An object dropped from rest, its velocity be 294 m/s in downward direction after 30 s .
Kinematics is the study of the motion of mechanical points, bodies and systems without consideration of their associated physical properties and the forces acting on them.
initial velocity = u = 0
time = t = 30sec
g = acceleration due to gravity = 9.8 \(m/s^{2}\)
using equation of kinematics
v = u - g*t
v = 0 - 9.8 * 30
v = - 294 m/s
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Two children are standing on a 150-kg wagon that is at rest. The children jump off in opposite directions. The 40.-kg boy jumps off at +4.0 m/s and the 50.-kg girl jumps off at -2.0 m/s. What is the speed and direction of the wagon?
The speed and direction of the wagon of mass 150 kg is -0.4 m/s.
What is speed?Speed can be defined as the rate of change of distance.
To calculate the speed and direction of the wagon, we use the formula below.
Formula:
V = -(mv+m'v')/M................ Equation 1Where:
V = Speed of the wagonm = Mass of the boym' = Mass of the girlM = Mass of the wagonv = Final velocity of the boyv' = Final velocity of the girlFrom the question,
Given:
M = 150 kgm = 40 kgm' = 50 kgv = 4 m/sv' = -2 m/sSubstitute these values into equation 1
V = -[40×4+(-2×50)]/150V = -(160-100)/150V = -60/150V = - 0.4 m/sHence, the speed and direction of the wagon is -0.4 m/s.
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How many times larger is the mass of a proton compared to the mass of an electron?
Answer:
1.67262 × 10−27 kg, which is 1,836 times the mass of an electron.
Two objects are initially at the x = 0 meter mark at t=0 seconds. Object #1 has an initial velocity of 9.00 m/s i and undergoes a constant acceleration of 3.00 m/s2 i. Object #2 is initially at rest and undergoes a constant acceleration of 5.00 m/s2 i. a) What is the distance between the objects at t=4.00 seconds b) What is the distance between the objects when they have the same velocity?
a) We will determine the distance traveled by each object first, that is:
Object 1:
\(d_1=(9m/s)(4s)+\frac{1}{2}(3m/s^2)(4s)^2\Rightarrow d_1=60m\)Object 2:
\(d_2=(0m/s)(4s)+\frac{1}{2}(5m/s^2)(4s)^2\Rightarrow d_2=40m\)So, both objects are 20 meters apart after 4 seconds.
b) Now, we determine the distance when they have the same velocity, that is:
First, we determine the time it takes for them to have the same velocity:
\(\frac{1}{2}(5m/s^2)t^2=(9m/s)t+\frac{1}{2}(3m/s^2)t^2\Rightarrow(1m/s^2)t^2-(9m/s)t=0\)\(\Rightarrow t=\frac{-(-9)\pm\sqrt[]{(-9)^2-4(1)(0)}}{2(1)}\Rightarrow\begin{cases}t=9s \\ \\ t=0s\end{cases}\)So, after 9 seconds they will have the same velocity, now we determine the distance between them:
Object 1:
\(d_1=(9m/s)(9s)+\frac{1}{2}(3m/s^2)(9s)^2\Rightarrow d_1=202.5m\)Object 2:
\(d_2=(0m/s)(9s)+\frac{1}{2}(5m/s^2)(9s)^2\Rightarrow d_2=202.5m\)The distance between the two objects when they have the same velocity is 0 meters. They are in the same place.
for which of the following values of ""y"" does liam possess both a comparative advantage in mirror production and an absolute advantage in mirror production?
Liam possesses both a comparative advantage and an absolute advantage in mirror production for all values of "y".
When Liam has both a comparative advantage and an absolute advantage in mirror production, it means that he can produce mirrors more efficiently and at a lower opportunity cost compared to other individuals or countries. In this case, it is stated that Liam possesses these advantages for all values of "y", indicating that regardless of the specific circumstances or conditions, Liam is consistently more efficient and productive in mirror production.
The statement suggests that Liam has a significant advantage in mirror production, both in terms of absolute advantage and comparative advantage, regardless of any specific value of "y". This implies that Liam's skills, resources, or production capabilities are superior to others in the context of mirror production, allowing him to produce mirrors more efficiently and effectively.
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9. two solid spheres, both of radius 5 cm, carry identical total charges of 2 !c. sphere a is a good conductor. sphere b is an insulator, and its charge is distributed uniformly through- out its volume. (i) how do the magnitudes of the electric fields they separately create at a radial distance of 6 cm compare?(a)ea.eb 50(b)ea.eb.0(c)ea5eb.0 (d)0,ea,eb (e)05ea,eb (ii)howdothemagnitudes of the electric fields they separately create at radius 4 cm compare? choose from the same possibilities as in part (i).
(i) The magnitudes of the electric fields they separately create at a radial distance of 6 cm is \(E_{a}\)=\(E_b}\). and (ii) The magnitudes of the electric fields they separately create at radius 4 cm is \(E_{a} =E_{b}\), so the correct option is option b.
What do you mean by conductor?A conductor refers to a material that allows an electric current to flow through it with ease. In other words, it has a low electrical resistance. Conductors are materials that have a high number of free electrons that are able to move freely through the material. Examples of conductors include copper, aluminum, gold, and silver. These materials are commonly used in the electrical industry to make wires and other electrical components that need to conduct electricity. In addition to materials, a conductor can also refer to a person or an organization that is responsible for directing or leading an orchestra or a choir. In this context, a conductor is in charge of maintaining the ensemble's rhythm and intonation, and interpreting the score in a way that brings out the music's emotional content and intended meaning.
(i) The magnitude of the electric field created by a charged conductor is given by the formula E = \(\frac{kq}{r}\), where k is the Coulomb constant, q is the charge, and r is the distance from the center of the sphere.
For a good conductor, like sphere A, the charge will be distributed evenly on the surface of the sphere. So, the electric field at a radial distance of 6cm will be Eₐ = \(\frac{kq}{r^{2} }\) = \(k\frac{210^{-6} }{(619^{-2} )}^{2} =\frac{k}{72}\)
For an insulator, like sphere B, the charge is distributed uniformly throughout its volume. The electric field at a radial distance of 6cm will be \(E_{b}\)= \(\frac{kq}{r^{2} }=k\frac{210^{-6} }{(619^{-2} )}^{2} =\frac{k}{72}\)
As we can see, the magnitudes of the electric fields created by both spheres are equal, so the answer is (b) \(E_{a} =E_{b}\)
(ii) For the radius of 4cm, the electric field created by sphere A and sphere B will
\(E_{a} =\frac{kq}{r^{2} }=k\frac{210^{-6} }{(410^{-2} )^{2} } =\frac{k}{16}\\E_{b} =\frac{kq}{r^{2} }=k\frac{210^{-6} }{(410^{-2} )^{2} } =\frac{k}{16}\\\)
As we can see, the magnitudes of the electric fields created by both spheres are equal at a radius of 4cm, so the answer is (b) \(E_{a} =E_{b}\)
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Determine whether the series is convergent or divergent. 1 + 7n Σ 57 n = 1 convergent divergent If it is convergent, find its sum. (If the quantity diverges, enter DIVERGES.) 7 4
The given series, 1 + 7n Σ 57 n = 1, is divergent because the terms in the series continue to increase without bounds, the sum of the series also increases indefinitely.
To determine the convergence or divergence of the series, we can analyze its behaviour as n approaches infinity. The series can be written as Σ(1 + 7n*57) for n = 1 to infinity. By simplifying the expression, we have Σ(399n + 1) for n = 1 to infinity.
As n increases, the summand of the series grows linearly with a coefficient of 399. Since the coefficient is nonzero and positive, the series will diverge. This means that the sum of the series will not approach a finite value as n tends to infinity.
Therefore, the given series is divergent, and we cannot find its sum. It is important to note that a divergent series does not have a finite sum. Therefore, the sum of the given series is "DIVERGES."
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Write the complete decay equation for the given nuclide in the complete X notation. Refer to the periodic table for values of Z. (a) Write the complete decay equation for 239 Np. (Use B to signify the
The complete decay equation for 239Np is: ^{239}{93}Np -> ^{235}{92}U + ^{4}_{2}He . the superscripts indicate the atomic mass and the subscripts represent the atomic number of the respective nuclides.
The given nuclide is 239Np, where the superscripts represent the atomic mass and the subscripts represent the atomic number. Np stands for neptunium.
The decay process of 239Np involves the emission of an alpha particle, which consists of two protons and two neutrons. An alpha particle is represented by the symbol ^4_2He.
During the decay of 239Np, it transforms into a different nuclide. In this case, it decays into 235U, which is uranium. Uranium has an atomic number of 92, represented by the subscript 92.
Therefore, the complete decay equation for 239Np is:
^{239}{93}Np -> ^{235}{92}U + ^{4}_{2}He
The decay of 239Np results in the formation of 235U and the emission of an alpha particle (^4_2He). The complete decay equation is represented as ^{239}{93}Np -> ^{235}{92}U + ^{4}_{2}He, where the superscripts indicate the atomic mass and the subscripts represent the atomic number of the respective nuclides.
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2. A cat chases a mouse across a 1.0 m high table. The mouse steps out of the way, and the cat slides off the table at a
speed of 5.0 m/s.
a. How long will it take the cat to hit the floor?
b. How far from the base of the table will the cat land?
Answer:
Below
Explanation:
Here is what we are given in the problem :
dy = - 1.0 m (this is negative because the cat falls)
Vx = 5.0 m/s
We can use this equation to find the time that it will take the cat to fall :
t = √-2dy / g
t = √-2(-1.0) / 9.8
t = √0.20408
t = 0.45 (round this to 2 sig figs)
t = 0.5 seconds
Now we can find dx (distance in the x direction)
dx = vx (t)
dx = (5.0m/s)(0.45s)
dx = 2.258769 m
dx = 2.3 m
Hope this helps! Best of luck <3
the enthalpy of 36 g g of water vapor increases by 1830 j j when its temperature increases from 150∘c ∘ c to 175∘c ∘ c . assume that water vapor is an ideal gas.
The enthalpy of 36 g g of water vapor increases by 1830 j j when its temperature increases from 150∘c to 175∘c is 1830 J.
The enthalpy of 36 g of water vapor increases by 1830 J when its temperature increases from 150°C to 175°C. Assuming water vapor is an ideal gas, the change in enthalpy can be calculated using the following equation:
ΔH = Cp * m * ΔT
Where Cp is the specific heat capacity of the gas, m is the mass of the gas, and ΔT is the change in temperature. In this case, Cp = 1.88 J/g°C, m = 36 g, and ΔT = 25°C. Therefore, the change in enthalpy is:
ΔH = 1.88 * 36 * 25 = 1830 J.
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a 2.15-kg, 16.0-cm radius, high-end turntable is rotating freely at 33.3 rpm when a naughty child drops 11 g of chewing gum onto it 10.0 cm from the rotation axis.
The new angular speed of the turntable is approximately 2.91 rad/s.
What is meant by rotation?Circular movement of object around central axis or point is called rotation.
Moment of inertia of a solid disk is given by the equation: I = (1/2) * m * r²
I is moment of inertia, m is mass of the disk, and r is radius of the disk.
Initial moment of inertia of the turntable is: I₁ = (1/2) * m * r² = (1/2) * 2.15 kg * (0.16 m)² = 0.055 kg m²
Final moment of inertia of the turntable and the gum is: I₂ = I₁+ m_gum * r_gum²
m_gum is mass of gum and r_gum is distance of gum from rotation axis.
I₂ = 0.055 kg m² + 0.011 kg * (0.11 m)² = 0.066 kg m²
L₁ = I₁ * w₁
w1 is initial angular speed of turntable in radians per second.
w1 = (33.3 rpm) * (2π rad/rev) / (60 s/min) = 3.49 rad/s
Final angular momentum of the system (turntable and gum) is:
L₂ = I₂ * w₂
w₂ is final angular speed of turntable in radians per second.
As angular momentum is conserved : L₁ = L₂
I₂ * w₂ = I₂ * w₂
w₂ = (I₁ / I₂) * w₁ = (0.055 / 0.066 ) * 3.49 = 2.91 rad/s
Therefore, the new angular speed of the turntable is approximately 2.91 rad/s.
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Note: The question given on the portal is incomplete. Here is the complete question.
Question : A 2.15-kg, 16.0-cm radius, high-end turntable is rotating freely at 33.3 rpm when a naughty child drops 11 g of chewing gum onto it 11.0 cm from the rotation axis. Assuming that the gum sticks where it lands, and that the turntable can be modeled as a solid, uniform disk, what is the new angular speed of the turntable
Which two structures are not found in animal cells?
A) vacioles and ribosomes
B) chloroplasts and ribosomes
C) cell walls and chloroplasts
D) endoplasmic reticulum and cell walls
Answer:
C
Explanation:
So, lets start off by thinking about what we know is in both cells, and rule out from there.
There are just some basic things you need in eukaryotic cells, those include the following:
Nucleuscell membranemitochondriacytoplasm(dont get confused with chloroplast)Rough and smooth endoplasmic reticulumGolgi vescileGolci apparatusNucleolus(Dont get confused with nulceus)Here are jsut a few examples of what can be found in both plant and animal cells, however we can already rule out all of the following except for:
C
Because remember, c talks about the chlorplast, which is not the chlorplasm found in both plant anf animal cells, its just the chloroplast found in plant cells.
Although I gave the asnwer to you. Here are some things that are in plant cells that arent in animal cells:
Cell wallvaciolescentral vaciolechlroplastplastidsAnimal cells on the other hand, have a few things that plant cells do not as well:
LysomeCentrolsomeHope this helps! ;)
he cross-sectional area of the hose is m2 and the velocity at which the water leaves the hose is cm/s. if the velocity at which the water leaves the nozzle is m/s, what is the radius of the nozzle in meters?
Principle of conservation of mass and the formula for the cross-sectional area of a circle are used to find the radius of the nozzle in meters.
Given the cross-sectional area of the hose (A1) in m² and the velocity at which water leaves the hose (V1) in cm/s, and the velocity at which water leaves the nozzle (V2) in m/s, we will find the radius of the nozzle (r2).
Convert V1 to m/sBy following these steps, you can find the radius of the nozzle (r2) in meters using the given information about the cross-sectional area and velocities.
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The simple act of walking requires single leg
full body
and
a strong
and
full body
you are so wise how do you do it?
After the experiment, scientists organize and (blank) the data.
Does anyone know what goes in the blank? Im doing a crossword puzzle and I need help, please. (/w\)
Answer:
analyze
Explanation:
Given the equation describing the displacement of an object undergoing simple harmonic motion, Find the maximum acceleration of the object.
The maximum acceleration of the object is 10.94 x 10² m/s².
The equation of displacement is given as,
y(t) = 4.8 cos(15.1 t)
It is in the form, y(t) = A cos(ωt)
So, the amplitude of the SHM, A = 4.8 m
Angular frequency, ω = 15.1 s⁻¹
The maximum acceleration,
a(max) = -Aω²
the -ve sign indicates that the acceleration is acting towards the mean position.
a(max) = 4.8 x 15.1²
a(max) = 10.94 x 10² m/s²
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1. What are the two main gases responsible for lowering down the pH.
2. Can we control an acid rain? Why or Why not?
3. When pH changes from 6 to 3, how many times does acidity increase?
Answer:
1. The three main acidic gases responsible for lowering the pH of rainwater are non-metal oxides produced by the burning of fossil fuels like coal, oil and natural gas. Sulfur dioxide is produced when fossil fuels containing sulfur impurities are burned.
2. A great way to reduce acid rain is to produce energy without using fossil fuels. Instead, people can use renewable energy sources, such as solar and wind power. Renewable energy sources help reduce acid rain because they produce much less pollution.
3. The pH scale is logarithmic, meaning that an increase or decrease of an integer value changes the concentration by a tenfold. For example, a pH of 3 is ten times more acidic than a pH of 4.
A boulder sits atop a steep cliff and someone pushes it off the edge. If the cliff face is 45 meters
high, what is the speed of the boulder just before it hits the ground? (ignore air friction)
Answer:
See below
Explanation:
All of the PE (mgh) will be converted to KE (1/2 mv^2)
mgh = 1/2 m v^2
gh = 1/2 v^2
2 gh = v^2
v = sqrt (2gh) = sqrt ( 2 * 9.81 * 45) = 29.7 m/s
What goals do investigators have when examining a car accident? How do they know how fast a car that was involved in an accident was going?
Answer:
--->The goals of the investigators is to prevent tampering with evidence and reduce exposing workers to additional harm.
--> The investigators are able to find out how fast a car that was involved in an accident was going by measuring the length of skid marks.
Explanation:
Automobile or car accidents are incidents which when it occurs are generally fast, violent and confusing to both the people involved and the eyewitnesses. With the development in technology, investigators (usually known as forensic investigators) use a variety of tools and physical evidence to put together a clear picture of what happened during a car accident. With their discoveries, they would be able to to prevent tampering with evidence and reduce exposing workers to additional harm.
They can know how fast a car that was involved in an accident was going by:
--> Analysing a physical evidence such as measurement of the length of skid marks. When the skid distance (which is the drag factor due to road surface friction) and the braking efficiency are determined, the minimum speed of a car as it started skidding can be estimated. Even the appearance of the skid mark also tells investigators whether a car was braking, accelerating, or sliding.
Urgent Important!!
Many medications have a warning to avoid driving because.
A. they haven't been scientifically tested yet.
B. they have been proven to cause drowsiness.
C. they want to cover all their bases.
Answer:
B) they have been proven to cause drowsiness
Explanation:
B is the only answer that makes sense, as the other answers do not make sense. All medications are scientifically tested before they can be used by someone. Covering their bases would show negligence and is bad.
Hope this helps!
PS, this is biology or medical, not physics.
As fluids are transported over a long distance, what happens to the fluid pressure in the pipes? Why does this happen?
As fluids are transported over a long distance, the fluid pressure in the pipes tends to decrease. This occurs due to several factors, including friction, elevation changes, and pipe diameter variations.
1. Friction: As the fluid flows through the pipes, it encounters resistance from the pipe walls, which is known as friction. This friction causes the fluid to lose energy, resulting in a drop in pressure. The longer the distance, the more friction the fluid experiences, and the greater the pressure loss.
2. Elevation changes: When a fluid flows through pipes with elevation changes, the pressure can vary due to gravity. Fluids flowing uphill experience a decrease in pressure due to the energy required to move against gravity. Conversely, fluids flowing downhill may experience an increase in pressure as gravity aids in the movement.
3. Pipe diameter variations: If the pipe diameter changes along the path, it can also affect the fluid pressure. As the fluid moves from a larger diameter pipe to a smaller one, the flow velocity increases, resulting in a decrease in pressure according to Bernoulli's principle.
In summary, as fluids are transported over long distances, the fluid pressure in the pipes generally decreases due to factors such as friction, elevation changes, and pipe diameter variations. This happens because the fluid loses energy as it overcomes these obstacles during its flow, leading to a reduction in pressure.
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The moon completes one (circular) orbit of the earth in 23.7 days. The distance from the earth to the moon is 3.84×10^8m. Calculate the centripetal acceleration.
Given that distance of moon from the earth is, R= 3.84 x 10^8 m
Also, time taken to complete one revolution is, T= 23.7 days = 2047680 seconds
Mass of the moon is, m= 7.347 Kg
To find the centripetal acceleration,
\(a_c=\frac{m4\pi^2R}{T}\)Substituting the values, we get
\(undefined\)Two identical particles move toward each other, one twice as fast as the other. Just before they collide, one has a kinetic energy of 25 J and the other 100 J . At this instant their total kinetic energy is 75 J . 100 J . 25 J . 125 J . none of the above need more information
None of the above answer choices are correct. The total kinetic energy just before the collision is 25J.
We can use conservation of momentum and conservation of energy to solve this problem.
Let m be the mass of each particle, v1 be the velocity of the slower particle, and v2 be the velocity of the faster particle. We know that:
mv1 + mv2 = 0 (conservation of momentum)
and
(1/2)mv1^2 + (1/2)mv2^2 = 25 J + 100 J = 125 J (conservation of energy)
Simplifying the momentum equation, we get:
v2 = -2*v1
Substituting this into the energy equation and simplifying, we get:
5*v1^2 = 125 J
v1^2 = 25 J
v1 = ±5 m/s
Since the particles are moving towards each other, their relative velocity is the sum of their velocities, which is:
v_rel = v1 + v2 = v1 - 2*v1 = -v1
Therefore, the speed of the particles just before they collide is:
|v_rel| = |v1| = 5 m/s
The total kinetic energy just before the collision is:
(1/2)mv1^2 + (1/2)mv2^2 = (1/2)mv1^2 + (1/2)m(-2v1)^2 = 5/2m*v1^2 = 25J.
Therefore, the answer is 25J.
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A photon scatters in the backward direction from a free proton that is initially at rest. What must the wavelength of the incident photon be if it is to undergo a 10.0% change in wavelength as a result of the scattering
The wavelength of the incident photon must be 20 times the change in wavelength.
To determine the wavelength of the incident photon that undergoes a 10.0% change in wavelength as a result of scattering, we can use the principle of conservation of energy and momentum.
When a photon scatters off a particle, such as a proton, both energy and momentum must be conserved.
The energy of a photon is given by the equation:
E = hc / λ
Where:
E is the energy of the photon
h is the Planck's constant (approximately 6.626 x 10^-34 J·s)
c is the speed of light (approximately 3.00 x 10^8 m/s)
λ is the wavelength of the photon
Since the proton is initially at rest, its initial momentum is zero.
The momentum of a photon is given by the equation:
p = h / λ
Where:
p is the momentum of the photon
The change in wavelength (Δλ) is related to the initial and final wavelengths by the equation:
Δλ / λ = Δp / p
Where:
Δλ is the change in wavelength
λ is the initial wavelength
Δp is the change in momentum
p is the initial momentum
In this case, the scattering is in the backward direction, meaning the final momentum of the photon is equal in magnitude but opposite in direction to the initial momentum:
Δp = 2p
Substituting the expressions for momentum and the change in momentum:
Δλ / λ = Δp / p
Δλ / λ = 2p / p
Δλ / λ = 2
Given that the change in wavelength is 10.0% or 0.10, we can set up the equation:
0.10 = Δλ / λ
0.10 = 2
Solving for λ:
λ = Δλ / 0.10
λ = 2 / 0.10
λ = 20
Therefore, the wavelength of the incident photon must be 20 times the change in wavelength, which is equal to 20 times the initial wavelength.
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What element of medieval court culture is evident in the excerpt? the importance of christian practices the acts of warfare over land rights the proper conduct of knights the subjects’ loyalty to their lords
The element that is evident here is the importance of Christian practices. Option A
What is the evident?In the excerpt as we can see below, there is the depiction of the court life of the medieval era. In that era, there was quite a lot of tendency of the people to be very religious and the norms of the Christian faith was in the highest regard.
As such, in the medieval times, Christianity was a state religion in many cultures and its practices became an integral part of the national life of the people not only in England but across the world.
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Missing parts;
Read the excerpt from Sir Gawain and the Green Knight. When the King and his knights came into the hall, The chanting in the chapel had come to an end And a loud cry went up from the clerics and the others Proclaiming Noel once more, calling out the word again, And then the nobles ran and got the gifts ready . . . What element of medieval court culture is evident in the excerpt? the importance of Christian practices the acts of warfare over land rights the proper conduct of knights the subjects’ loyalty to their lords
Answer: a
Explanation: christian practices
Planet Force (N) Mass (kg)
A 8.0 0.50
B 30 3.0
C 45 3.0
D 60 6.0
The gravitational force acting on various masses is measured on different planets. Measured values for the forces acting on the corresponding masses are shown in the data table. Analyze the data and develop a method for comparing the gravitational field strengths on the different planets. Use your method to compare the gravitational field strengths, and report your conclusions.
From the analysis, it can be concluded that planet A has the strongest gravitational field, followed by planet C, and planets B and D have the same gravitational field strength.
The gravitational force acting on various masses is measured on different planets. The table shows the measured values for the forces acting on the corresponding masses:Planet Force (N) Mass (kg)A 8.0 0.50B 30 3.0C 45 3.0D 60 6.0
Method for comparing the gravitational field strengths on the different planets:First, we can use the formula for calculating gravitational force: \(`F = G (m_1m_2 / r^2)`\)where G is the universal gravitational constant `\(6.67 * 10^{-11 }Nm^2/kg^2\), m1 and m2 are the masses of the two objects in kg, and r is the distance between the centers of the objects in meters.
We know that the force is proportional to mass (F = ma). So we can calculate the acceleration due to gravity (g) on each planet by dividing the force by the mass. Therefore, we can use the formula: `g = F / m`.
Comparing the gravitational field strengths on the different planets:We will calculate the acceleration due to gravity (g) on each planet.
For planet A: `
g = F / m
= 8.0 N / 0.50 kg
= 16 \(m/s^2\)`
For planet B: `g = F / m
= 30 N / 3.0 kg
= 10 \(m/s^2\)
For planet C: `g = F / m
= 45 N / 3.0 kg
= 15 \(m/s^2\)
For planet D: `g = F / m
= 60 N / 6.0 kg
= 10 \(m/s^2\)
`So we see that planet A has the strongest gravitational field, followed by planet C, then planet B and planet D have the same gravitational field strength.
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What is the formula for acceleration? ( PLEASE HELP! ALSO IF YOU GET B IT'S WRONG BECAUSE I ALREADY PUT THAT AND IT WAS WRONG sorry caps)
A: Final speed-initial speed ________________________ time
B: Net force = Mass x acceleration
C: Mass x Velocity
D: Force a 5N Force B 10N Net force of forces A and B 15N
Answer:
option A is correct
Explanation:
acceleration the time rate of change of velocity or speed so
a=Δv/t
Δv=vf-vi
Δv= final speed-initial speed
now a=final speed-initial speed/time
Write a general formula to describe the variation The square of T varies directly with the cube of a and inversely with the square of d: T= 3 when a = 4 and d = 2
T^2 = (Use integers or fractions for any numbers in the expression.)
The value of k, we can write the general formula:
T^2 = (9/16) * (a^3 / d^2)
To write a general formula describing the variation, we can use the given information:
The square of T varies directly with the cube of a and inversely with the square of d. We can express this relationship as:
T^2 = k * (a^3 / d^2)
Here, k is the constant of variation. Now, we'll use the given values of T, a, and d to find the value of k:
3^2 = k * (4^3 / 2^2)
9 = k * (64 / 4)
9 = k * 16
k = 9 / 16
Now that we've found the value of k, we can write the general formula:
T^2 = (9/16) * (a^3 / d^2)
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Four identical electric bulbs are connected in series and then to a battery. the fifth identical bulb then is connected in parallel to the line of first four bulbs. this additional connection will:_________
The additional connection of the fifth identical bulb in parallel to the line of the first four bulbs will cause the fifth bulb to be brighter than the other four bulbs.
The total resistance in the circuit rises when bulbs are wired in series, which reduces the total current flowing through the bulbs. As a result, each individual bulb's brightness declines. The fifth bulb, when linked in parallel, creates a different path for current flow, effectively avoiding the other bulbs in the series. As a result, the circuit's overall current increases, increasing the brightness of all the bulbs—including the newly added bulb—in the circuit.
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Q- A body is acted upon by two forces 30N due east and 40N due North. Calculate
resultant and its direction.
Answer:
the following image will make you understand
Explanation:
Venus has an orbital period of 0.615 years and Mars has an orbital period of 1.88 years. How many orbits does Venus make for each Mars orbit?
Venus completes around 3 orbits for every orbit of Mars, given their respective orbital periods of 0.615 years and 1.88 years.
Venus and Mars have different orbital periods, with Venus completing one orbit around the Sun in approximately 0.615 years, while Mars takes about 1.88 years to complete its orbit. To determine the number of Venus orbits for each Mars orbit, we can divide the orbital period of Mars by that of Venus.
By dividing the orbital period of Mars (1.88 years) by the orbital period of Venus (0.615 years), we get approximately 3.06. This means that Venus completes about 3 orbits for each orbit of Mars.
Venus and Mars are both planets in our solar system, and each has its own unique orbital period, which is the time it takes for a planet to complete one orbit around the Sun. The orbital period of Venus is approximately 0.615 years, while the orbital period of Mars is about 1.88 years.
To determine the number of orbits Venus makes for each Mars orbit, we divide the orbital period of Mars by the orbital period of Venus. In this case, we divide 1.88 years (the orbital period of Mars) by 0.615 years (the orbital period of Venus).
The result of this division is approximately 3.06. This means that Venus completes approximately 3 orbits for every orbit that Mars completes. In other words, as Mars is completing one orbit around the Sun, Venus has already completed about 3 orbits.
This difference in orbital periods is due to the varying distances between the planets and the Sun. Venus orbits closer to the Sun than Mars, which results in a shorter orbital period for Venus compared to Mars.
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