an object have an acceleration of 8m/s/s. if the net force acting upon the object is decreased by a factor of 2 and the mass is increased by a factor of 4, then the new acceleration would be?​

A 150-lb man carries a 25-lb can of paint up a helical staircase that encircles a silo with radius 30 ft. If the silo is 120 ft high and the man makes exactly three complete revolutions, the work done by the man against gravity in climbing to the top is 48,832 ft-lb.

The work done by a person in lifting an object against gravity is given by the formula W = F × d where W is the work done, F is the force applied, and d is the distance moved in the direction of the force. Since the man is moving up the helical staircase, the distance moved by him is equal to the height of the silo, which is 120 ft. The force applied by the man is equal to the weight of the man and the can of paint. This is given by F = 150 + 25 = 175 lb. The man makes exactly three complete revolutions, which means that the vertical distance covered by him is three times the height of the silo. This is equal to 3 × 120 ft = 360 ft. However, the vertical component of this distance is equal to the height of the silo, which is 120 ft. This means that the man moves horizontally by a distance of 360 − 120 = 240 ft. This distance is covered by the man in moving around the silo. The circumference of the silo is given by 2πr, where r is the radius of the silo. Therefore, the circumference of the silo is given by 2π × 30 ft = 60π ft. The man makes three complete revolutions, which means that he moves a horizontal distance of 3 × 60π ft = 180π ft. Therefore, the total distance moved by the man is given by d = √(120² + 180π²) ft ≈ 372.77 ft. Now, substituting the values of F and d in the formula for work, we getW = F × d= 175 lb × 372.77 ft= 65,216.75 ft-lbHowever, the man is carrying the can of paint in one hand. This means that he is doing work against gravity not only for himself but also for the can of paint. Therefore, the work done against gravity by the man for himself is 65,216.75 ft-lb, and the work done against gravity for the can of paint isW = 25 lb × 120 ft= 3,000 ft-lbTherefore, the total work done against gravity is given by 65,216.75 ft-lb + 3,000 ft-lb = 68,216.75 ft-lb ≈ 48,832 ft-lb.

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Answer:

Rubbing his hand and ironing is Mechanical Energy being transformed into Thermal Energy.

Throwing a rock vertically in using Kinetic Energy, it then transforms into Gravitational Energy as the rock falls.

Explanation:

First, as Kwane rubbing his and and iron his clothes using the energy to create heat, that is thermal being transformed.

The rock being thrown uses kinetic energy and due to graviational force of the earth, it is being transformed into Potential Gravitational Energy.

Answer:  A hymn which accompanies religious observances and rituals.   And others like guitar, violin, flute, harp and the organ

Explanation: Gradually people instructed the natives not only in singing but also in playing various instruments like guitar, violin, flute, harp and later on, the organ.

The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

The cooling law is given by:

$$\frac{dQ}{dt}=-k(T-T_0)$$

where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.

We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.

Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.

Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:

dQ = - dQ where dQ is the heat energy gained by the environment.

We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.

We can rearrange the equation as follows:

$$-\frac{dQ}{dt}=k(T-T_0)$$

$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$

$$\frac{d}{dt}T=-k(T-T_0)$$

The differential equation above can be solved using separation of variables as follows:

$$\frac{d}{dt}\ln(T-T_0)=-k$$

$$\ln(T-T_0)=-kt+c_1$$

$$T-T_0=e^{-kt+c_1}$$

$$T=T_0+Ce^{-kt}$$

where C = e^(c1).

We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.

$$T=T_0+Ce^{-kt}$$

$$73=18+C\cdot e^{-0.09t}$$

$$55=C\cdot e^{-0.09t}$$

$$C=55e^{0.09t}$$

$$T=18+55e^{0.09t}$$

We can now solve for the value of t when T=93 as follows:

$$93=18+55e^{0.09t}$$

$$e^{0.09t}=\frac{93-18}{55}$$

$$e^{0.09t}=1.3636$$

$$t=\frac{\ln(1.3636)}{0.09}$$

Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

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In an open system, both energy and matter are exchanged with the surroundings.

In a closed system, only energy is exchanged with the surroundings.

In an isolated system, neither matter nor energy is exchanged with the surroundings.

In the greenhouse, only energy is exchanged with the surroundings.

Thus, the greenhouse is a closed system.

Answer:

A stretched spring : Elastic potential energy

Muscle of the athlete : Chemical energy

Explanation:

Elastic potential energy is the form of energy stored in an Elastic object(Can stretch and relax), when it is deformed from it's original shape.

\({ \purple{ \tt{Here \: is \: your \: answer...}}}\)

Umm it's quiet difficult to understand. But let us note down the given values.

\({ \green{ \tt{given : - }}}\)

\({ \red{ \tt{ λ = 5000 \times {10}^{ - 10} m}}}\)

\({ \red{ \tt{ λ = 5 \times {10}^{ - 7}m}}} \)

\({ \red{ \tt{ \beta = 0.6cm = 6 \times {10}^{ - 3} m}}}\)

\({ \red{ \tt{D' = \frac{D}{2}}}}\)

\({ \red{ \tt{ \beta' = 0.003m = 3 \times {10}^{ - 3}m}}}\)

Answer:

The amount of mechanical energy produced by the old lorry when 600 Joules of chemical energy have been used by the engine, M.E. is 120 Joules

Explanation:

The question is a word problem on the relationship between energy efficiency and energy consumption

The given parameters of the old lorry are;

The chemical energy to mechanical energy conversion efficiency of the old lorry = 20%

The amount of chemical energy used by the engine = 600 joules

Let 'M.E.' represent the amount of mechanical energy produced by the old lorry, we have;

\(Energy \ Efficiency = \dfrac{Energy \ produced }{Total \ Energy \ Taken \ In \ or \ Used} \times 100\)

Therefore, the for the old lorry, we have;

\(20\% = \dfrac{M.E. \ Produced}{600 \ Joules} \times 100\)

∴ M.E. Produced = 20/100 × 600 J = 120 J

The amount of mechanical energy produced by the old lorry when 600 Joules of chemical energy have been used by the engine, M.E. = 120 Joules

The acceleration of the bead in the viscous liquid at terminal speed is zero, from which the value of the constant b, can be determined.

Reasons:

The mass of the bead, m = 3.00 g

Time at which the mass is released, t = 0

Terminal velocity of \(v_T\) = 2.00 cm/s = 0.02 m/s

(a) The equation 6.2, obtained online is presented as follows;

\(\overrightarrow R = -b \cdot \overrightarrow v\)

Where;

\(\overrightarrow R\) = The resistive force = m·a

\(\overrightarrow v\) = The relative velocity of the object

a = The acceleration of the object

We get;

m·g - b·v = m·a

At the terminal velocity, \(v_T\), we have;

a = 0

Therefore;

m·g - b·\(v_T\) = m × a = 0

m·g = b·\(v_T\)

\(b= \dfrac{m \cdot g}{v_T}\)

Therefore;

\(b= \dfrac{0.003 \, kg \times 9.81 \, m/s^2}{0.02 \, m/s} = 1.4715 \, kg/s\)

b = 1.4715 kg/s.

(b) From, m·g - b·v = m·a, and \(a = \dfrac{dv}{dt}\), we have;

\(m \cdot \dfrac{dv}{dt}= m \cdot g - b\cdot v\)

Which gives;

\(\right. \dfrac{dv}{dt}= \mathbf{g - \dfrac{b}{m} \cdot v}\)

The expression for v obtained by differential equation is expressed as follows;

\(v = \dfrac{m \cdot g}{b} \cdot \left(1 - e^{-b \cdot t/m} \right)\)

Which gives;

\(v = \mathbf{v_T \cdot \left(1 - e^{-b \cdot t/m} \right)}\)

Therefore, when the bead reaches 0.632·\(v_T\), we get;

\(1 - e^{-b \cdot t/m}\) = 0.632

\(e^{-b \cdot t/m}\) = 1 - 0.632 = 0.368

\(t= \dfrac{ln(0.368)}{-\dfrac{1.4715}{0.003} } \approx 2.038 \times 10^{-3}\)

The time at which the bead reaches  0.632·\(v_T\), t ≈ 2.038 × 10⁻³ s.

(c) The value of the resistive force at terminal velocity, \(v_T\), is \(\overrightarrow F_R = -b \cdot v_T\)

Which gives;

\(\overrightarrow F_R\) = 1.4715 kg/s × 0.02 m/s = 0.02943 N.

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Answer:

\({ \rm{power, \: p = current \times p.d}} \\ { \rm{50 = 4.5 \times (current \times resistance)}} \\ { \rm{50 = 4.5 \times (4.5 \times r)}} \\ { \rm{resistance = \frac{50}{ {4.5}^{2} } }} \\ \\ { \rm{resistance = 2.5 \: ohms}}\)

The mass of the hummingbird is approximately 4.96 x 10^-37 ks (kilostones).

To find the mass of the hummingbird, we can use the equation relating momentum, mass, and velocity.

The momentum (p) of an object is given by the product of its mass (m) and velocity (v):

p = m * v

We are given the magnitude of the momentum (|p|) as 0.278 ems (electromagnetic units) and the velocity (v) as 50.0 km/h.

First, we need to convert the velocity from km/h to m/s:

50.0 km/h * (1000 m / 1 km) * (1 h / 3600 s) ≈ 13.89 m/s

Now, we can rearrange the equation to solve for the mass (m):

m = |p| / v

Substituting the given values:

m = 0.278 ems / 13.89 m/s

To convert the electromagnetic units (ems) to kilograms (kg), we need to use the conversion factor: 1 ems = 1.783 x 10^-36 kg.

m = (0.278 ems) * (1.783 x 10^-36 kg / 1 ems)

m ≈ 4.96 x 10^-37 kg

Finally, we can express the mass in units of kilograms (ks):

m ≈ 4.96 x 10^-37 ks

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Answer:

a

Explanation:

Answer:

You're best answer to your question would be C!!!

In A 2.0-kg block travels around a 0.50-m radius circle with an angular speed of 12 rad/s. The circle is parallel to the xy plane and is centered on the z axis, a distance of 0.75 m from the origin. The z component of the angular momentum around the origin is 6 kg·m^2/s.So option a is  correct.

The angular momentum (L) of a particle with respect to a point is given by the formula:

L = I * ω

Where:

L is the angular momentum

I is the moment of inertia

ω is the angular velocity

In this case, the block is traveling around a circle, so its motion can be considered as rotational. The moment of inertia for a particle rotating around a circle is given by

I = m * r^2

Where:

m is the mass of the particle

r is the radius of the circle

Given:

Mass of the block (m) = 2.0 kg

Radius of the circle (r) = 0.50 m

Angular speed (ω) = 12 rad/s

First, we calculate the moment of inertia (I):

I = m * r^2

= 2.0 kg * (0.50 m)^2

= 0.5 kg·m^2

Then, we calculate the angular momentum (L) around the origin:

L = I * ω

= 0.5 kg·m^2 * 12 rad/s

= 6 kg·m^2/s

The z component of the angular momentum around the origin is: 6 kg·m^2/s.Therefore option a is correct.

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Answer:

The big rip theory

Explanation:

      I believe what you are referring to is the big rip theory, in which the universe expands faster than the speed of light Kurzgesagt refers to it as a "horizon" but in reality it's a little more complicated than that. Eventually the expansion of the universe will accelerate far beyond the speed of light creating space between molecules until eventually all matter is fleeting and the entire universe is an endlessly vast cosmic void with not but the occasion molecule left from a time when things weren't so lonely.

The weight of the astronaut on Earth is 637 N. This means that the force with which the astronaut is being pulled towards the center of the Earth is 637 N.

The weight of an astronaut on Earth is determined by multiplying their mass by the gravitational field strength. In this case, the astronaut has a mass of 65 kg and the gravitational field strength on Earth is 9.8N/kg.

Therefore, the weight of the astronaut on Earth can be calculated by multiplying their mass by the gravitational field strength:
Weight = mass x gravitational field strength
Weight = 65 kg x 9.8 N/kg
Weight = 637 N
Therefore, the weight of the astronaut on Earth is 637 N. This means that the force with which the astronaut is being pulled towards the center of the Earth is 637 N.

However, it is important to note that weight is not the same as mass.

Mass is a measure of the amount of matter in an object, while weight is a measure of the force with which an object is being pulled towards the center of the Earth due to gravity.

This means that an astronaut would have the same mass on Earth as they would in space, but their weight would be different due to the varying gravitational field strength.

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The player's average power output on the way up is approximately 491.38 W.

The work done by the player on the stairs is given by the product of force and distance, which can be calculated as follows:

work = force × distance × cos θ

where θ is the angle of inclination and cos θ is the component of force in the direction of motion. The force can be calculated using Newton's second law:

force = mass × acceleration

where acceleration is the component of gravity along the inclined plane:

acceleration = g × sin θ

where g is the acceleration due to gravity.

Substituting these values and simplifying, we get:

work = (mass × g × sin θ) × distance × cos θ

= (91 kg × 9.81 m/\(s^2\) × sin 29°) × 83 m × cos 29°

= 34442.67 J

The average power output can be calculated as the work done divided by the time taken:

average power = work / time

= 34442.67 J / 70 s

= 491.38 W.

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The thermal conductivity of the metal is approximately B, 241 W/(m · K).

To find the thermal conductivity (k) of the metal, use the formula:

Q = k × A × (ΔT/Δx) × t

Where:

Q = Heat conducted by the rod (in Joules)

A = Cross-sectional area of the rod (in square meters)

ΔT = Temperature difference across the rod (in Kelvin)

Δx = Length of the rod (in meters)

t = Time (in seconds)

Given:

Q = 8.5 g of ice melted = 8.5 × Lf (latent heat of fusion of ice)

Lf = 3.34 × 10⁵ J/kg

Δx = 60 cm = 0.6 m

A = 1.25 cm² = 1.25 × 10⁻⁴ m²

t = 10 min = 600 seconds

ΔT = (100°C - 0°C) = 100 K

Substituting the given values into the formula:

8.5 × Lf = k × (1.25 × 10⁻⁴) × (100 K / 0.6 m) × 600 s

Simplifying the equation:

k = (8.5 × Lf) / [(1.25 × 10⁻⁴) × (100 K / 0.6 m) × 600 s]

Calculating the value:

k = (8.5 × 3.34 × 10⁵) / [(1.25 × 10⁻⁴) × (100 / 0.6) × 600]

k ≈ 241 W/(m · K)

Therefore, the thermal conductivity of the metal is approximately 241 W/(m · K).

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Answer:

The mass of the truck is 1500 Kg.

Explanation:

We know that,

F = mg

m = F/g

m = 15000/10

m = 1500 Kg

m = 1500 KgThus, The mass of the truck is 1500 Kg.

Answer:

In order to determine if the cathode ray consisted of charged particles, Thomson used magnets and charged plates to deflect the cathode ray. He observed that cathode rays were deflected by a magnetic field in the same manner as a wire carrying an electric current, which was known to be negatively charged.

Explanation:

According to the right-hand rule, the magnetic field causes the electrons to be refracted. Turn on the power strip to learn about the Cathode Ray (electron beam) Deflection by an Electric Field.

Magnetic forces can be seen in a magnetic field, an electric current, a changing electric field, or a vector field around a magnet. Magnetic compass needles and other permanent magnets align in the direction of magnetic fields like the one found on Earth. Electrically charged particles are forced to move in a circular or helical pattern by magnetic fields. The operation of electric motors is caused by this force, which is applied to electric currents in wires in a magnetic field.

The Lorentz Force, which is explained by the left-hand rule, has an impact on what happens inside the tube. In accordance with this law, an electron or other charged particle travelling in a magnetic field will be deflected by the field at a right angle to both the field's direction and the direction of the particle.

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a ) When they reach the ground, rock B has greater velocity.

b ) Both rocks have the same acceleration

c ) Rock A and Rock B arrives at the same time

According to law of conservation of energy,

1 / 2 m u² + m g hi = 1 / 2 m v² + m g hf

u = 0

hf = 0

m g hi = 1 / 2 m v²

v = √ ( 2 g / m ) √ hi

v ∝ √ hi

a ) hi of rock A will be higher because it reaches a certain height above the ground which will be considered as initial height for rock A. So, the final velocity of rock A is higher.

b ) Both the rock are affected by only the force of gravity. So they will have the same acceleration of 9.8 m / s²

c ) If air resistance is ignored,

s = u t + 1 / 2 at²

For an object that is dropped,

u = 0

a = g

s = at² / 2

t = √ ( 2 s / g )

It can clearly be seen that no matter what height an object might be dropped from, if air resistance is ignore they will fall at the same time.

Therefore,

a ) When they reach the ground, rock B has greater velocity.

b ) Both rocks have the same acceleration

c ) Rock A and Rock B arrives at the same time

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The net force on the object is the total force that is applied to some object.

The net force is the total force that is applied to some object, the force can be in a different direction and also can be in the same direction. For the different directions, we must subtract them.

We will use three force assumption because the question is incomplete,

So the net force is,

net force = first force + second force + third force

= 10 - 15 + 15

= 10 to the right

Your question is incomplete, but this is a general answer about net force

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Considering the coordinates of the radars as well as the direction of the object in order to determine the object's position in terms of distance and angle. Sincе thе radars arе situatеd at (0,0) and thе sеcond radar is on thе еast sidе of thе first onе, wе can assumе that thе first radar is locatеd on thе x-pivot and thе sеcond radar is locatеd on thе positivе y-hub.

Lеt's say thе objеct is dеtеctеd at coordinatеs (x, y). The objесt's y-coordinativity will be negative and its x-coordinativity positive as it approaches the southern direction in the first quadrant.

We can use the distancе formula to determine the object's diameter from its origin (0, 0):

Distancée = (x + y) 2 The angle can be calculated with trigonometry. The angle can be summarized as:

= arctan(y/x) ii) We must consider the circles of overlap for each radar in order to calculate the overlap from the radar signal intersection in the first quadrant.

Due to the fact that both radars have distinctive overlap and divide the covered area into circles, the overlapped area will be the intersection of these circles.

Thе ovеrlapping arеa can bе calculatеd by finding thе arеa of thе intеrsеction of two circlеs. The formula for the area of the intersection of two circles can be complex and depends on the specific radii and dimensions that exist between the circles' centers.

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Answer:

The derivation of the field intensity in the dipole at the point of equatorial plane is the result of the horizontal line.

Explanation:

The equatorial line of an axis on dipole is define as the line is perpendicular at the axial line and to pass from the mid way between the charges at both the poles.

The result of this intensity is the vector sum of the intensities with the PA and PB. The line EA and The line EB can be resolved into horizontal and the vertical components.

The vertical components of dipole cancel to each other because they both equally or opposite directed.

The horizontal line up gives the result of the dipole at the point of the equatorial.

A falling object will continue to accelerate to higher speeds until they encounter an amount of air resistance that is equal to their weight.

Hope this helps!

Explanation:

tan ● = opposite / adjacent

tan 31.5 = 19 / F

0.613 = 19 / F

0.613F = 19

F = 31

sin ● = opposite / hypotenuse

sin 31.5 = 19 / a

0.52 = 19 / a

0.52a = 19

a = 36. 36

Using trigonometry, the base of the triangle is approximately 33.476, and the hypotenuse of the triangle is approximately 38.118.

To find the base and hypotenuse of a right triangle with one angle of 31.5 degrees and a given height of 19:

Here,

Opposite side = height = 19 (given)

Adjacent side = base (unknown)

Hypotenuse = hypotenuse (unknown)

First, let's find the base (adjacent side):

tan(θ) = opposite ÷ adjacent

tan(31.5 degrees) = 19/base

To find the base, we can rearrange the equation:

base = opposite ÷ tan(θ)

base = 19 ÷ tan(31.5 degrees)

Calculating the value:

base ≈ 33.476

So, the base of the triangle is approximately 33.476.

Now, using the Pythagorean theorem, we can write:

hypotenuse² = base² + opposite²

hypotenuse² = (33.476)² + 19²

hypotenuse ≈ 38.118

Therefore, the hypotenuse of the triangle is approximately 38.118.

Thus, base is 33.476, and hypotenuse is 38.118.

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The “sum of forces” acting on a cart can be explained as the net force or resultant force acting on it. This term refers to the total amount of force acting on an object, considering both the direction and magnitude. The cart's acceleration is influenced by this force, which is critical in the laws of physics.

The following is a description of the “sum of forces” acting on a cart: The sum of forces can be calculated using the formula F = ma, where F is the force acting on the cart, m is the mass of the cart, and a is the acceleration produced by the force. If there is more than one force acting on the cart, it is necessary to calculate the net force, which is the sum of all the forces acting on the cart.
The sum of forces can be split into two components: internal and external forces. Internal forces are those generated within the object, whereas external forces are exerted by other objects. The frictional force between the wheels of the cart and the surface is an example of an internal force acting on the cart.
The gravitational force exerted by the Earth is an example of an external force acting on the cart. If there are more than two forces acting on the cart, vector addition must be used to determine the net force.
The sum of forces acting on the cart is critical in the laws of physics. If the sum of forces acting on the cart is zero, it implies that there is no net force acting on it, and it is either stationary or moving at a constant velocity. If the sum of forces is nonzero, it implies that there is a net force acting on the cart, and it is either accelerating or decelerating.

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Answer:  When we use an analogy that represents the expanding universe with the surface of an expanding balloon, what does the inside of the balloon represent? The inside of the balloon does not represent any part of our universe.

Answer:

a particular kind of matter with uniform properties.

Explanation:

A. True. Low-frequency surface waves will be amplified in tall buildings with low frequencies of vibration.

This is because tall buildings can act as a resonator, amplifying the vibration frequencies that match their natural frequency of oscillation. This phenomenon is known as resonance, and it can lead to increased vibrations and motion in the building, potentially causing discomfort for occupants and even structural damage in extreme cases.

This is why engineers and architects take resonance into account when designing tall buildings, to ensure that they are able to withstand the forces that can be generated by wind, earthquakes, and other external sources of vibration.

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