An object in motion stays in motion and an object at rest stays at rest until ?

The isomerization of cyclopropane to propylene is a first-order process with a half-life of 19 minutes at 500oc. The time it takes for the partial pressure of cyclopropane to decrease from 1. 0 atmosphere to 0. 125 atmosphere at 500oc is closest to 57 minutes.

First, we must get the rate constant.

k= 0.693/ 19 = 0.0365 min⁻¹

Now we need to figure out how long decay takes.

First order kinetics' expression for the rate law is provided by:

t= (2.303/k) log a/(a-x)

where,

Rate constant = k

t = time it took for decay to occur.

Initial reactant pressure equals 1.0 atm, or a.

After the process of decay, a - x equals 0.125 atm of pressure.

After entering all the values into the equation above, we get

t= (2.303/0.0365) log 1/(1-0.125)

t = 57 min

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Answer:

B

Explanation:

The warmer the water, the more space it takes up, and the lower its density.

Answer:

The density decreases

Explanation:

The colder the water the closer the particles move together making it denser. The hotter the water the more the particles slow down and move away from each other making the water less dense.

The aim of heating \(KMnO_4\) during its preparation step is to increase its solubility in water and to convert the brown manganese dioxide \(MnO_{2}\)\(MnO_2\) to purple potassium permanganate   \(KMnO_4\).

Potassium permanganate  \(KMnO_4\) is a powerful oxidizing agent and disinfectant that is commonly used in water treatment plants and for sterilizing wounds. It is prepared by heating manganese dioxide \(MnO_2\)  with a solution of potassium hydroxide (KOH) in a reactor.

The heat helps to dissolve the \(MnO_2\)  in the solution and triggers a redox reaction where the \(MnO_2\)  is oxidized to  \(KMnO_4\) and the KOH is reduced to potassium hydroxide \(K_2O\). The reaction can be represented by the following equation:

2KOH +\(MnO_2\)  ->  \(KMnO_4\) + \(H_2O\)

During the preparation of  \(KMnO_4\), heating is also used to remove impurities and to control the reaction rate, ensuring that the final product is of the desired quality and concentration. The reaction is exothermic and releases heat, so the reactor must be cooled to prevent overheating and to ensure that the reaction proceeds at a controlled rate.

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Answer  b

Explanation:

Answer: B. Isotopes of the same element have the same number of neutrons and a different number of protons.

Explanation: Founders Educere answer.

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Answer:

Precipitates Form

Explanation:

I apologize if I am wrong

In general, the arming time of a munition refers to the time required for the munition's fuse to become active and enable the explosive charge to detonate. The arming time can vary depending on several factors, including the type of fuse used, the specific munition model.

Tail fuzes like the M905 tail fuze are designed to be used with certain types of munitions, such as bombs, and are typically armed by the motion or rotation of the munition during its descent or trajectory. The arming time of a tail fuze can depend on several factors, including the munition's velocity, the altitude of the munition, and the specific settings on the fuze.

It's important to note that discussing specific arming times of military munitions is not recommended, as it can be considered sensitive information that should only be handled by authorized personnel with the proper clearance and training to ensure public safety and security.

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The pH change is comes out to - 0.237 pH units, which is shown in the below section.

In the initial buffer,

[CH3COOH] + [CH3COO-] = 0.100 mol/l  and their quantity is

0.100 mol/L x 0.200 L = 0.0200 mol

Calculate the ratio [CH3COO-]/[CH3COOH] using the buffer formula:

 log ([CH3COO-]/[CH3COOH]) = pH – pKa = 5.000 – 4.740 = 0.260

         [CH3COO-]/[CH3COOH] = 100.260= 1.820 = 1.820:1

0.0200 mol x 1.820/(1.820 + 1) = 0.0129 mol CH3COO-

0.0200 mol x 1 /(1.820 + 1) = 0.0071 mol CH3COOH

In the initial buffer.

The quantity of HCl added is

0.00660 L x 0.400 mol/L = 0.00264 mol

After neutralization, the buffer composition is:

0.0129 mol - 0.00264  = 0.01026 M CH3COO-

0.0071 mol + 0.00264 = 0.00974 M CH3COOH

The new pH is

pH = pKa + log([CH3COO-]/[CH3COOH])

     = 4.740 + log(0.01026 M/0.00974 M)=

     = 4.740 + 0.0226 = 4.763

The pH change is 4.763 – 5.000 = - 0.237 pH units.

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(a) All the bonds present in urea are polar.

(b) The oxygen atom will carry the partial negative charge at the end of the bond dipole, thus C=O is the most polar bond.

When atoms share their electrons inequitably, polar covalent bonds are formed, whereas non-polar covalent connections are formed when atoms divide their electrons more evenly.The uneven electron sharing is caused by discrepancies in the electronegativities of the two atoms sharing the electrons

(a) All of the bonds in a urea molecule are polar. The compound's formula is [(NH₂)₂CO]. The bonds (C=O, N-H, and C-N) are all polar because to large variances in electronegativities. O has a higher electronegative potential than C, and N has a higher electronegative potential than C and H.

(b) All the bonds present in urea are polar, however, the most polar bond is the connection between carbon and oxygen due to its greater electronegativity than a nitrogen atom (N), thus C=O is the most polar bond.

As the atom that will attracts the electrons due to its electronegative nature, the oxygen atom will carry the partial negative charge at the end of the bond dipole.

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The process of cooling a food until the first ice crystals form is referred to as supercooling. Supercooling occurs when a substance is cooled below its freezing point without undergoing solidification.

This phenomenon is commonly observed in liquids that are pure and free from impurities. Supercooling allows the formation of ice crystals to be delayed until a nucleation site is present or an external disturbance occurs.

Supercooling refers to the state where a substance remains in a liquid phase below its freezing point. When a food is rapidly cooled, it can reach a temperature below the freezing point without solidifying. This occurs because the process of nucleation, which initiates the formation of ice crystals, is hindered. In the absence of nucleation sites or external disturbances, the food remains in a supercooled state.

However, as soon as a nucleation site is introduced or an external disturbance occurs, the supercooled food rapidly crystallizes and forms ice. This process is commonly observed when touching an already supercooled liquid, causing it to freeze instantly. Supercooling can be utilized in various applications, such as in the production of supercooled drinks or in cryopreservation techniques.

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Answer:

a is C2H2

and c6h6

Explanation:

The balanced equation for the double-replacement neutralization reaction described is:

H2S(aq) + 2KOH(aq) → 2H2O(l) + K2S(aq)

In the double-replacement reactions, two elements from two different compounds replace each other because of the greater reactivity of the first two and the greater stability of the latter two.

In the neutralization reactions, one of the products needs to be water (H2O).

Therefore, the balanced equation for the double-replacement neutralization reaction between hydrosulfuric acid (H2S) and potassium hydroxide (KOH) is as follows:

H2S(aq) + 2 KOH(aq) → K2S(aq) + 2 H2O(l)

In this reaction, the hydrosulfuric acid (H2S) reacts with potassium hydroxide (KOH) to form water (H2O) and potassium sulfide (K2S).

The coefficients in the equation represent the smallest possible integers, and an excess base is assumed.

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Answer:

A 3s orbital is at a greater average distance from the nucleus than a 2s orbital

Explanation:

As the principal quantum number n increases, the distance of the orbital from the nucleus increases. Hence if we consider the 2s and 3s orbitals, it is easy to see that the 3s orbital is at a greater distance from the nucleus than the 2s orbitals.

This is clearly seen when we plot the radial distribution against the distance from the nucleus. This enables us to visualize the region in space in which an electron may be found.

Answer:

70°C,130.9 ................,...

The density of the substance having a mass of 2.0 g is 0.4 g/mL (Option D)

First, we shall obtain the volume of the substance. This can be obtained as follow:

Volume of substance = (Volume of water + substance) - (Volume of water)

Volume of substance = 75 - 70

Volume of substance = 5 mL

Finally, we shall determine the density of the substance. This is illustrated below:

Density = mass / volume

Density of substance = 2 / 5

Density of substance = 0.4 g/mL

Thus, the density is 0.4 g/mL (Option D)

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Heat absorbed by water is calculated as follows: 34.3 g x 5.4 oC x 1.00 calorie/g oC = 185.22 cal ( 0.18522 Kcals) Kcal/gram of potato chips = 0.18522/2.4 g, or 0.077 Kcal/g, is the unit of measurement for the caloric content of potato chips.

The self-repellent fluid known as caloric, which moves from hotter to colder bodies, is the basis of the debunked scientific hypothesis known as the caloric theory of heat. In addition, it was believed that caloric could enter and exit liquids and solids by way of their pores.

Supplement. Foods abundant in protein, carbohydrate, fat, vitamins, and minerals make up the high-calorie diet kind of diet. There might be between 4,000 and 5,000 calories consumed daily on this kind of diet.

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Answer:

Heat energy required (Q) = 10.736 KJ

Explanation:

Given:

Specific heat of ethanol (C) = 2.44 J/g °C

Mass of ethanol (M) = 50 gram

Initial temperature (T1) = -20°C

Final temperature (T1) = 68°C

Find:

Heat energy required (Q) = ?

Computation:

Change in temperature (ΔT) = 68°C - (-20°C)

Change in temperature (ΔT) = 88°C

Heat energy required (Q) = mC(ΔT)

Heat energy required (Q) = (50)(2.44)(88)

Heat energy required (Q) = 10,736 J

Heat energy required (Q) = 10.736 KJ

The cation formed when a sodium atom loses an electron is called the sodium ion, which is represented by the symbol Na+.

This ion is commonly found in many chemical compounds and is important for various biological processes. When sodium atoms react with nonmetals, such as halogens, they form ionic compounds called sodium halides.

The loss of an electron by sodium creates a positively charged ion, which is attracted to negatively charged ions or molecules.

This attraction forms strong ionic bonds that hold the compound together. The correct answer to the given question is option d.

It is important to note that the terms "sodate ion", "sodide ion", and "soda ion" are not used to describe the cation formed by the loss of an electron from a sodium atom.

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See the attached image.

The technique for the separation, purification, and testing of compound is called Chromatography and the resultant data is read in form of a chromatogram. Depending on the retention of the compound, retention factor or RF value is calculated.  

Based on the chromatogram obtained with hexanes/ethyl acetate 95:5, it appears that compounds X and Y are very close in Rf value and may even be overlapping, while compound Z is more separated from them.

To achieve better separation of all three compounds, it may be beneficial to try a different eluting solvent system with a different polarity.

One possible option could be to increase the polarity of the eluting solvent by increasing the proportion of ethyl acetate, such as using hexanes/ethyl acetate 90:10 or 85:15.

Another option could be to switch to a completely different solvent system, such as using a mixture of dichloromethane and methanol or a mixture of toluene and ethyl acetate. Experimentation with different solvent systems and ratios would be necessary to determine the best option for separating these specific compounds.

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Answer:

Helium

Explanation:

You can take physics as a hobby and also it is great that you like both maths and physics as well and also want to be an computer science engineer because physics and math

the gas sample contains roughly 0.000968 mol of moles. Together with solids, liquids, and plasmas, gases are among the four basic states of matter.

The number of moles in the gas sample can be determined using the ideal gas law:

PV = nRT

where R is the gas constant, n is the number of moles, P is the pressure, V is the volume, and T is  temperature in Kelvin.

First, we must change the temperature from Celsius to Kelvin and the volume from dm3 to m3:

T = 10°C + 273.15 = 283.15 K V = 5.0 dm3 = 0.005 m3

We can now enter the given values into the equation as follows:

PV/RT is equal to n = (2 atm)(0.005 m3)/(0.082 L atm/mol K) (283.15 K)

If we condense this phrase, we get:

n = 0.000968 mol

As a result, the gas sample contains roughly 0.000968 mol of moles.

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The concentration of the nitric acid solution is 0.0862 mol/\(dm^3\) and the concentration of the nitric acid in g/\(dm^3\) is 5.431 g/\(dm^3\).

A titration is a technique where a solution of known concentration is used to determine the concentration of an unknown solution.

According to the neutralization law,

\(n_1M_1V_1 = n_2M_2V_2\)

\(n_1\)is the basicity of \(HNO_3\) =1

\(M_1\) is the molarity of \(HNO_3\) =0.05 mol/\(dm^3\)

\(V_1\) is the volume of \(HNO_3\) solution = 25\(cm^3\)

\(n_2\) is the acidity of NaOH =1

\(M_2\) is the molarity of NaOH =?

\(V_2\) is the volume of NaOH solution =14.5\(cm^3\)

Putting in the values we get:

\(n_1M_1V_1 = n_2M_2V_2\)

1 x 0.05 mol/\(dm^3\) x 25cm^3 = 1 x \(M_2\) x 14.5\(cm^3\)

\(M_2\) = 0.0862 mol/\(dm^3\)

Hence. the concentration of the nitric acid solution in  0.0862 mol/\(dm^3\) and the concentration of the nitric acid in g/dm3 is 0.0862 x63.01 g/\(dm^3\)= 5.431 g/\(dm^3\).

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The initial amount of moles of HNO₃ in the solution was 2.505 x 10⁻⁴ mol.

The initial amount of moles of HNO₃ in the solution can be calculated using the pH and the formula for calculating the concentration of hydrogen ions (H⁺) in a solution.

pH = -log[H⁺]

Rearranging the formula:

[H⁺] = 10⁻ᵖʰ

[H⁺] = 10⁻³.³⁰

[H⁺] = 5.01 x 10⁻⁴ mol/L

Since HNO₃ is a strong acid, it dissociates completely in water to form H⁺ and NO₃⁻ ions. This means that the initial amount of moles of HNO₃ is equal to the amount of H⁺ ions in the solution.

Therefore, the initial amount of moles of HNO₃ in 0.50 L of the solution is:

moles of HNO₃ = [H⁺] x volume of solution

moles of HNO₃ = 5.01 x 10⁻⁴ mol/L x 0.50 L

moles of HNO₃ = 2.505 x 10⁻⁴ mol

This was calculated using the pH of the solution and the formula for calculating the concentration of hydrogen ions in a solution.

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Answer:

false

Explanation:

Answer:

True

Explanation:

Kinetic energy is a form of energy that an object or a particle has by reason of its motion. If work, which transfers energy, is done on an object by applying a net force, the object speeds up and thereby gains kinetic energy.

The positive iodoform test indicates the presence of a methyl ketone or a compound that can undergo oxidation to form a methyl ketone. In the case of C5H8O, two geometric isomers that can give a positive iodoform test are trans-2-pentene-1-ol and cis-3-penten-2-ol. Here are their structures:

Trans-2-pentene-1-ol:

    H

    |

H - C = C - C - C - OH

    |    |

    H    H

Cis-3-penten-2-ol:

    H

    |

H - C = C - C - OH

    |    |

    H    H

Both of these isomers have the empirical formula C5H8O and can undergo oxidation to form a methyl ketone, which will react with iodine and hydroxide ions to produce a yellow precipitate of iodoform.

It's important to note that the structures provided are examples of geometric isomers that fit the given empirical formula and can give a positive iodoform test. The actual arrangement of atoms in space may vary depending on the specific isomer.

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Answer:

125 lbs would round to C. 56.8kg

Answer:

it is very easy why you can't know it

Material's ability to move through a medium is referred to as its diffusion coefficient. It is determined by the nature of  medium, ion's size, and charge. Cl- ion has greater diffusion coefficient than Fe(CN)₆_₃ ion, which explains why Cl- ion moves faster than Fe(CN)₆_₃ ion.

The migration of ions in a solid is described by the diffusion of ions. It is a slower process that depends on the ion's charge, radius, mobility, and diffusion coefficient. The diffusion of ions is related to the Brownian motion of ions caused by their thermal energy. The smaller ions move quicker and cover a greater distance over time than larger ones, as a result of Brownian motion.

During the diffusion in a solid experiment, Cl ion moved faster and further than Fe(CN)₆ because of the following reasons: The diffusion rate is determined by the ion's charge and size. The rate of diffusion of an ion is directly proportional to the size and inversely proportional to the ion's charge. The Cl ion has a smaller size and a greater charge than the Fe(CN)6 ion.

The diffusion of Cl ion is therefore faster and covers a greater distance than the diffusion of Fe(CN)₆. Cl- ion has a greater diffusion coefficient than Fe(CN)₆_₃ion. A material's ability to move through a medium is referred to as its diffusion coefficient. It is determined by the nature of medium, the ion's size and charge. Cl- ion has greater diffusion coefficient than Fe(CN)₆_₃ ion, which explains why Cl- ion moves faster than Fe(CN)₆_₃ ion.

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