Answer:
doubled
Explanation:
F=ma1----------(1)
2F = ma2-------(2)
Divide 2nd equation by 1st one
we get a1×2=a2
2. doubled
What is Force?A force can cause an object with mass to change its velocity, i.e., to accelerate.
\(F=m*a\)
Given:
\(F=m*a_1\)..............(i)
\(2F = m*a_2\)...........(ii)
On dividing equation (ii) by (i)
\(\frac{2F}{F} =\frac{m*a_2}{m*a_1} \\\\2=\frac{a_2}{a_1} \\\\a_1=2*a_2\)
Thus, the magnitude of the acceleration of the object is doubled. Therefore, correct option is 2.
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what part of an experiment is not being tested but is used for comparison
Answer:
The part of an experiment that is not being tested but is used for comparison is the controls or the controlled variables.
What is the net force in this image?
a
8000 N right
b
5000 N right
c
4000 N right
d
4000 N left
e
5000 N left
f
8000 N left
Answer:
4000N left
Explanation:
6000N-1000N-1000N
6000N-2000N
8000N
how does this experiment help us understand their behavior? stanford prison experiment
This experiment help us understand their behavior as well as how the people will cop up with the rules and regulation the society wants to apply on them
What is Stanford prison experiment ?In a two-week simulation of a prison setting, the Stanford prison experiment was meant to look at the impact of situational factors on participants' responses and behaviors.
Hence, this experiment allows us to better understand their behavior, as well as how individuals will respond to the laws and regulations imposed by society.
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photoelectron energy Radiation with an energy of 4.2 eV strikes a photocell. If the work function of the photocell is 2.31 eV, what is the energy of the ejected photoelectron?
Equation Sheet:
E = nhf
E = hf
KE= -eΔVo
h = 6.62607004 x 10^-34 m^2 kg/s
E = hc / λ = 1240 eV . nm/λ
KE = hf - hf0
Electron (mc) 9.109 xx 10^-33 kg
e = 1.60 x 10^-19 C
p = hf/c = h/ λ
λ = h/p = h/mv
The energy of the ejected photoelectron is 1.89 eV.
Energy of radiation, E = 4.2 eV Work function of photocell, φ = 2.31 eV
Energy of ejected photoelectron is given by the difference of the energy of incident radiation and the work function of the metal. That is, KE = hυ - φ where, h is Planck's constant, υ is the frequency of radiation, c = λυ is the speed of lightλ is the wavelength of radiation and c is the speed of light.
From the energy formula of radiation, E = hυE = hc / λ, by substituting h and c values
KE = hc / λ - φ
Given, h = 6.626 x 10^-34 J-s, c = 3 x 10^8 m/s
λ = hc / E
= (6.626 x 10^-34 J-s x 3 x 10^8 m/s) / (4.2 eV x 1.6 x 10^-19 J/eV)
= 4.93 x 10^-7 m
KE = hc / λ - φ
= (6.626 x 10^-34 J-s x 3 x 10^8 m/s) / (4.93 x 10^-7 m) - (2.31 eV x 1.6 x 10^-19 J/eV)
= 1.89 eV
Therefore, the energy of the ejected photoelectron is 1.89 eV.
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An NFL wide receiver prospect runs 40 m in 4.5 seconds. What is the average speed of the wide receiver (m/s)?
Answer:
8.89 m/s
Explanation:
rate = distance/time
40m/4.5 sec = 8.8888889 m/s
a person runs 1 km. how does his speed affect the total energy needed to cover this distance?
For a person running 1 km, faster speed requires more total energy.
What does kinetic energy mean?
Kinetic energy is the energy possessed by an object caused by the force of motion. Therefore, an object moving at a certain speed must have kinetic energy, while an object that is not moving does not have kinetic energy.
According to the given question:
Total energy comprises of kinetic energy and potential.
Since in running potential energy is zero, only kinetic energy is at play.
Kinetic energy is also called motion energy, where the movement of an object can produce other energy.
Hence, faster the speed of the object, more energy required in the form of Kinetic Energy.
Complete question:
A person runs 1 km. How does his speed affect the total energy needed to cover this distance?
A. A faster speed requires less total energy.
B. A faster speed requires more total energy.
C. The total energy is about the same for a fast speed and a slow speed.
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A dockhand rolls a barrel up a plank 6.40 m long. the barrel weighs 425 n and is displaced a height of 1.28 m. the dockhand exerts a constant force of 95.0 n parallel to the plank. a. what work is needed to overcome friction? (64.0 j) b. what is the efficiency of the person?
Work done required to overcome friction is 696.96 J. Efficiency of work is 95.5 %.
Work is done when a force does displacement in an object in the direction of the force. The energy required to do work translates into work. Its converse is also true. Work done gets stored in the form of potential energy.
Work = Force × displacement in the direction of the force
Work is a scalar quantity even though it is the dot product of two vector quantities - force and displacement.
Total distance to be displaced = 6.40m + 1.28m
= 7.68m
Net force acting on the barrel = 95-4.25 N
= 90.75 N
So, W = F × S
= 90.75 ×7.68 J
= 696.96 J
Efficiency of work = (output/ input ) × 100
If there would be no weight force and no friction, then amount of work would be = 95 × 7.68 J
= 729.6 J
So, efficiency of work = (696.96 / 729.6 ) × 100
= 95.5%
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A woman drives a golf ball off the tee to a speed of 28 m/s. The mass of the ball is 45 g and tIf the angle of the flight was initially 20ofrom the horizontal, how far would the ball go before it landed? (51 m) he time of contact was 6.0 ms.
Answer:
456
Explanation:
impulse = Force x (time of contact)
this isn't really much information but hope this helps !: )
The energy generated by the sun travels to Earth as electromagnetic waves of varying lengths. Which statement describes an electromagnetic wave with a long wavelength?
А
It has a high frequency and low energy.
B. It has a high frequency and high energy.
C. It has a low frequency and can travel through a vacuum.
It has a low frequency and needs a medium to travel through
Pls help quick!!!!
Answer:
It has low frequency and can travel through a vacuum
Explanation:
C.
A machine gun with a mass of 5kg fires a 50g bullet at a speed of 100m/s. what Is the recoil of the machine gun
Explanation:
Using conservation of momentum
the bullets momentum must equal the rifle's momnetum
5 000 gm * v = 50 gm * 100 m/s
v = 1 m/s
A car start from rest and reached with a speed of 20m/s in 9seconds calculate the acceleration of the car and calculate the displacement covered in this time
Hi there!
Acceleration:
a = Δv / Δt, so:
a = 20/9 ≈ 2.22 m/s²
Displacement:
We can use the equation Δd = v₀t + 1/2at² to solve. (Initial velocity is 0).
Δd = 1/2at²
Plug in the acceleration and time:
Δd = 1/2(2.22)(9)² ≈ 89.91 m
A 15 kg flywheel has all its mass around its outer rim. A string is wrapped around it and a m = 3.7 kg weight is hanging on the string. The flywheel has radius R = 0.25 m.
a) When the 3.7 kg weight is dropping with a speed of 1.7 m/s, what is the angular velocity of the flywheel?
w = ?? rad/s
b) When the 3.7 kg weight is moving with a speed of 1.7 m/s, what is the kinetic energy of the entire system?
K.E. = ?? J
c) If the system started from rest, how far has the weight fallen?
hfall = ?? m
d) What is the angular acceleration at this point?
a = ?? rad/s2
A 15 kg flywheel has all its mass around its outer rim. A string is wrapped around it and a m = 3.7 kg weight is hanging on the string. The flywheel has radius R = 0.25 m.
a) When the 3.7 kg weight is dropping with a speed of 1.7 m/s, the angular velocity of the flywheel 6.8 rad/s.
b) When the 3.7 kg weight is moving with a speed of 1.7 m/s, the kinetic energy of the entire system is 22.5 J.
c) If the system started from rest, the height weight fallen is 0.719 m
d) the angular acceleration at this point is 39.2 rad/s².
a) Angular velocity of the flywheel is given by :
w = v / r
Where, w = angular velocity of flywheel v = velocity of weight R = radius of flywheel
Therefore,w = v / r = 1.7 m/s / 0.25 m = 6.8 rad/s
Therefore, the angular velocity of the flywheel is 6.8 rad/s.
b) Kinetic energy of the entire system is given by :
K.E. = 1/2 * I * w²
Where, I = moment of inertia = mass of the flywheel * radius²
Thus,I = 15 kg * (0.25 m)²I = 0.9375 kg.m²
Therefore, K.E. = 1/2 * I * w²= 1/2 * 0.9375 kg.m² * (6.8 rad/s)²= 22.5 J
Therefore, the kinetic energy of the entire system is 22.5 J.
c) Potential energy of the weight at the top of the wheel is given by:
U = mgh
Where, m = mass of the weight = 3.7 kg g = acceleration due to gravity = 9.8 m/s² h = height fallen
Thus,U = 3.7 kg * 9.8 m/s² * h
Therefore, h = U / (mg) = (1.7 * 3.7 * 9.8) / (15 * 9.8)= 0.719 m
Therefore, the height fallen by the weight is 0.719 m
d) At this point, angular acceleration is given by:
a = alpha * r
Where, alpha = angular acceleration of flywheel
Therefore, alpha = a / r = g / r= 9.8 m/s² / 0.25 m= 39.2 rad/s²
Therefore, the angular acceleration at this point is 39.2 rad/s².
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what will happen to the gravition force between two bodies if the distance between them is halved keeping their masses constant
Answer:
The new force will be 4times the original
A current of 11.37 A passes through a wire. How many electrons pass through the wire in 18.19 seconds ?
Explanation
An Ampere is in the SI base unit of electric current equal to one coulomb per second.
\(\text{ 1 Ampere=}\frac{1\text{ C}}{s}\)and remember that the charge of an electron is
\(Q_e=-1.6*10^{-19\text{ }}C\)Step 1
a) let
\(\begin{gathered} I=11.37\text{ Amperes} \\ I=11.37\text{ A}*(\frac{\frac{1C}{s}}{A})=11.37\frac{C}{s} \\ also \\ time\text{ =}18.9\text{ s} \end{gathered}\)so
\(\begin{gathered} I=\frac{Q}{time} \\ replace \\ 11.37A=\frac{Q}{18.19} \\ multiply\text{ both sides by 18.19} \\ 11.37A*18.19=\frac{Q}{18.19}*18.19 \\ 206.8206\text{ C}=Q \end{gathered}\)b) now , to find the number o f electrons , divide the total a}charge by the charge of an electron
\(Number\text{ of electrons=}\frac{206.8206C}{\lvert{-1.6*10^{-19\text{ }}C}\rvert}=1.29*10^{21}\text{ electrons}\)therefore, the answer is
\(\begin{equation*} =1.29*10^{21}\text{ electrons} \end{equation*}\)I hope this helps you
Inside a radiation therapy device, an electron is in the presence of a uniform electric field with a magnitude of 305 N/C.
(a) What is the magnitude of the acceleration of the electron (in m/s2)
(b) The electron is initially at rest. What is its speed (in m/s) after 7.50 ✕ 10−9 s?
The magnitude of the acceleration of the electron is 3.34797e+32 m/s².
The speed of the electron after 7.50 ✕ 10−9 s is 2.24097e+31 m/s.
(a) The magnitude of the acceleration of the electron is:
a = E / m = 305 N/C / 9.11e-31 kg
a = 3.34797e+32 m/s²
where:
a is the acceleration of the electron (m/s²)
E is the magnitude of the electric field (N/C)
m is the mass of the electron (kg)
(b) The electron's speed after 7.50 ✕ 10−9 s is:
v = at = 3.34797e+32 m/s² * 7.50e-9 s
v = 2.24097e+31 m/s
where:
v is the speed of the electron (m/s)
a is the acceleration of the electron (m/s²)
t is the time (s)
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when heated the temperature of a water sample increased from 15°C to 39°C. Is absorbed 41840 joules of heat. what is the mass of the sample
Answer:
Mass of water: 43 g
Explanation
hope it helps
What is the speed of a donut rolling across the floor if it takes 2.5 seconds to travel across a 10 meter floor?
Answer:
4 m/s
Explanation:
10/2.5= 4 m/s
A small bar magnet pulls on a larger one with a force of 79 Newtons.
What is the magnitude of the force the larger one exerts on the smaller one?
Answer in units of N.
Answer:
79 N ( the same)
Explanation:
an automotive clutch spring is a mechanism that pushes two circular, rotating plates (the clutch and the flywheel) together with the purpose of keeping them locked together and rotating at the same angular velocity. assume a maximum force of static friction exerted of about 6000 n between the clutch and flywheel and a coefficient of friction of 0.25 and a compression of the spring of 0.4 meters, what is the spring constant of the clutch spring? a
Spring constant of the clutch spring is 60000 N/m.
We know maximum force of static friction between the clutch and flywheel is 6000 N and the coefficient of friction is 0.25. Therefore, the maximum force that can be exerted by the spring is:
F = μsN
where μs is the coefficient of static friction and N is the normal force.
N = Fspring
where Fspring is the force exerted by the spring.
Substituting these values into the equation we have:
F = μsFspring
Fspring = F/μs = \(6000 N / 0.25 = 24000 N\)
Now we can use the formula for spring constant to find k:
\(k = Fspring / x = 24000 N / 0.4 m = 60000 N/m\)
Therefore, the spring constant of the clutch spring is 60000 N/m.
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a battery is connected to two capacitors shown below. the capacitors have air between the plates. capacitor 1 has a plate area of 1.5cm2 and an electric field between its plates of 2000v/m. capacitor 2 has a plate area of 0.7 cm2 and an electric field of 1500v/m. what is the total charge coming out of the power supply?
A battery is connected to two capacitors shown below. the capacitors have air between the plates. The total charge coming out of the power supply: 8.16 × 10⁻⁹ C.
Capacitor 1 has a plate area of 1.5 cm² and an electric field between its plates of 2000 V/m and Capacitor 2 has a plate area of 0.7 cm² and an electric field of 1500 V/m.
Therefore, the total charge coming out of the power supply can be calculated by using the following formula:
Q = C × V,
where Q is the total charge coming out of the power supply.
C is the capacitance of the capacitors.
V is the voltage of the capacitors.
The capacitance of a parallel plate capacitor can be calculated by using the following formula:
C = εA/d,
where C is the capacitance of the capacitor.
ε is the permittivity of air.
A is the area of the capacitor plates.
d is the distance between the plates of the capacitor.
let's calculate the capacitance of the capacitors:
For capacitor 1:
ε = ε₀ = 8.85 × 10⁻¹² F/m²
A = 1.5 cm² = 1.5 × 10⁻⁴ m²d = ?
E = 2000 V/mQ = CV
C = εA/dC₁ = ε₀A/d
C₁ = ε₀A/E₁
C₁ = ε₀A/(V/d)
C₁ = (ε₀A/d) × V⁻¹
C₁ = ε₀A₁/E₁
C₁ = (8.85 × 10⁻¹² F/m²)(1.5 × 10⁻⁴ m²)/(2000 V/m)
C₁ = 6.63 × 10⁻¹⁰ F
For capacitor 2:
ε = ε₀ = 8.85 × 10⁻¹² F/m²
A = 0.7 cm² = 0.7 × 10⁻⁴ m²
d = E = 1500 V/m
Q = CV
C = εA/d
C₂ = ε₀A/d
C₂ = ε₀A/E₂
C₂ = (8.85 × 10⁻¹² F/m²)(0.7 × 10⁻⁴ m²)/(1500 V/m)
C₂ = 3.95 × 10⁻¹¹ F
Total charge coming out of the power supply: Q = C₁V + C₂VQ = (6.63 × 10⁻¹⁰ F)(12 V) + (3.95 × 10⁻¹¹ F)(12 V)Q = 8.16 × 10⁻⁹ C. Therefore, the total charge coming out of the power supply is 8.16 × 10⁻⁹ C.
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Is there gravitational force between two students sitting in a classroom?
If so, explain why you don't observe any effects of this force.
Answer:
Yes.
Explanation: the magnitude of the force is extremely small because the masses of the students are small relative to Earth's mass.
The gravitational force between two students sitting in classroom exists but its effect are not visible because the distance between these students is very very very small.
We have two students sitting in a classroom.
We have to investigate whether or not there is gravitational force between these two students.
State Newtons law of Gravitation.Newton's law of universal gravitation states that every particle attracts every other particle in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. Mathematically -
\($F=\frac{GMm}{r^{2} }\)
According to the question, we have - Two students sitting in a classroom.
Take a close look and you will identify that the distance between any two students in classroom is very small. Gravitational force is also the weakest force since the value of Universal gravitation constant (G) = 6.674 x \(10^{-11}\) \(m^{3}kg^{-1}s^{-2}\) is very small. Moreover, the force of gravitation is inversely proportional to square of distance between two bodies -
\($F \alpha \frac{1}{r^{2} }\)
This will make the gravitational force even more weak. This is the main reason why you don't observe any effects of this force. The gravitational force exists between any two bodies that have mass and energy, but its magnitude might depend upon other factors to.
Hence, the gravitational force between two students sitting in classroom exists but its effect are not visible because the distance between these students is very very very small.
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an electron travels at a speed of 8.60 x 10^7 m/s. what is its total energy
The total energy of an electron traveling at a speed of 8.60 x 10^7 m/s is (3.68 x 10^-15) J.
The total energy of an electron can be calculated by the formula E=0.5mv², where E is the total energy, m is the mass of the electron and v is the velocity of the electron. We know that the speed of the electron is 8.60 x 10^7 m/s. The mass of an electron is 9.109 x 10^-31 kg.Using the formula, we can calculate the total energy as follows:E = 0.5 x (9.109 x 10^-31 kg) x (8.60 x 10^7 m/s)²E = 3.68 x 10^-15 JTherefore, the total energy of an electron traveling at a speed of 8.60 x 10^7 m/s is (3.68 x 10^-15) J. The total energy is dependent on the velocity of the electron and the mass of the electron.
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the momentum of an object is increased by a factor of 4 in magnitude. by what factor is its kinetic energy changed? (assume no change in the mass of the object.)
When the momentum of an object is increased by a factor of 4 in magnitude, the kinetic energy of the object is changed by a factor of 16. Here option A is the correct answer.
The kinetic energy of an object is given by the equation KE = (1/2)mv², where m represents the mass of the object and v represents its velocity.
The momentum of an object is defined as p = mv, where p represents the momentum, m is the mass, and v is the velocity.
If the momentum of an object is increased by a factor of 4 in magnitude, it means the new momentum is 4 times larger than the original momentum. Mathematically, we can write this as p' = 4p, where p' is the new momentum and p is the original momentum.
Since p = mv, we can substitute this into the equation above to obtain p' = 4mv.
Now, let's consider the kinetic energy. The original kinetic energy is KE = (1/2)mv², and the new kinetic energy is KE' = (1/2)m(v')², where v' is the new velocity.
We know that p' = 4mv, so we can rewrite it as 4mv = m(v').
Dividing both sides of the equation by m, we get 4v = v'.
Now, substituting this into the equation for kinetic energy, we have KE' = (1/2)m(4v)².
Simplifying the equation, we have KE' = (1/2)m(16v²).
Notice that v² appears in both the original and new kinetic energy equations. Since the mass (m) is the same for both cases, we can cancel it out.
Therefore, the ratio of the new kinetic energy to the original kinetic energy is (1/2)(16v²)/(1/2)(v²) = 16.
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Complete question:
The momentum of an object is increased by a factor of 4 in magnitude. By what factor is its kinetic energy changed?(a) 16 (b) 8 (c) 4 (d) 2(e) 1
Nuclei decay from a more stable form to a less stable form.Question 9 options:TrueFalse
ANSWER
False.
EXPLANATION
In radioactive decay (or nuclei decay), an unstable nucleus emits radiation into a nucleus that is table and has less energy and a lower mass.
Therefore, nuclei decay from a less stable form to a more stable form.
The answer is false.
Which velocity time graph represents the motion of an object moving with constant acceleration
Answer:
A
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shoes of football players have studs
Answer:
The football shoes have spikes or studs because the studs or spikes provides larger frictional force than normal shoes while running on the grass. The studs prevents player from slipping on the grass and help to run faster and change direction quickly without slipping.
Un hombre parado en el techo de un edificio, tira una bola verticalmente hacia arriba con una velocidad de 12m/s, la bola llega al suelo en 4s. ¿que altura tiene el edificio ?
Respuesta:
24m
Explicación:
Según la ecuación de movimiento
v = u + en
Dado
Velocidad final v = 12 m / s
velocidad inicial u = 0 m / s
tiempo t = 4s
Sustituir
12 = 0 + 4a
a = 12/4
a = 3 m / s²
Lo siguiente es obtener la distancia;
S = ut + 1 / 2at²
S = 0 (4) + 1/2 (3) (4) ²
S = 3 * 16/2
S = 48/2
S = 24 m
Por lo tanto, la distancia requerida es de 24 m.
Compare and contrast fluorescent and incandescent light bulbs.
Answer:
The biggest difference between the two is in how they produce light. Incandescent bulbs produce light by a heating a metallic filament until it starts to radiate light. On the other hand, fluorescent lamps produce light by exciting a gas and causing it to glow.
Explanation:
an empty bottle has a mass of 15g when full of alcohol of density 0.8g/cm3 it's mass is 47g . Calculate? 1) the volume of the bottle (2) it's mass when full of water (3) it's mass when full of mercury of density 13.6g/cm3
To calculate the volume of the bottle, we can use the fact that the difference in mass when the bottle is empty and full of alcohol is equal to the mass of the alcohol it contains. So:
Mass of alcohol = 47 g - 15 g = 32 g
We know that the density of alcohol is 0.8 g/cm³, so:
Density = Mass / Volume
0.8 g/cm³ = 32 g / V
Solving for V, we get:
V = 32 g / 0.8 g/cm³ = 40 cm³
To find the mass of the bottle when full of water, we need to know the volume of water that the bottle can hold. Since we know the volume of the bottle, we can directly calculate the mass of the water using its density (which is 1 g/cm³):Volume of water = 40 cm³
Mass of water = Density x Volume
Mass of water = 1 g/cm³ x 40 cm³ = 40 g
To find the mass of the bottle when full of mercury, we can use the same approach as above, but this time using the density of mercury (which is 13.6 g/cm³):Volume of mercury = 40 cm³
Mass of mercury = Density x Volume
Mass of mercury = 13.6 g/cm³ x 40 cm³ = 544 g
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What are the main 7 forms of energy?
Mechanical, chemical, electrical, electromagnetic, thermal, acoustic, and radioactive energy are examples of different types of energy.
What transpires to the energy when a person passes away?To avoid energetic connection with other individuals, there may be some compacting—holding back—of energy in the heart centre, and the energy field begins to divide during the early stages of death. The bottom three bodies (energy field layers) separate and disintegrate.
According to experts, energy conservation does not equate to energy savings. Energy is neither generated nor destroyed, according to the rule of conservation of energy. Energy doesn't evaporate when it is used by people. Energy may transform from one kind of energy into another.
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Forms of energy include mechanical, chemical, electrical, electromagnetic, thermal, sound, and nuclear energy.
Chemical energy is the power stored in the bonds between atoms and molecules. Things like batteries, biomass, oil, natural gas, and coal all contain chemical energy. Chemical energy is converted into thermal energy, for example, when people burn wood in a fireplace or gasoline in a car's engine.
Tension in objects is a form of mechanical energy. Rubber bands that have been stretched and compressed are two examples of mechanical energy that has been stored.
The energy that an atom's nucleus stores and uses to preserve its structural integrity is known as nuclear energy. Significant amounts of energy may be released during the joining or splitting of the nuclei.
Electrical energy is produced by tiny charged particles called electrons, which typically move along a wire. a specific instance of electrical energy in nature is lightning.
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