an object is placed at a distance of 27.0 cm away from a thin convex lens with a focal length of 9.00 cm. how far from the lens is the image located and what type of image is formed?

The minimum possible coefficient of static friction between the bike tires and the ground is approximately 0.025.

Fc = (mv^2) / r

where Fc is the centripetal force, m is the mass of the cyclist, v is the velocity, and r is the radius of the curve. fs = FcTo find the minimum coefficient of static friction (μs), we can set fs equal to the maximum

possible static friction force:

fs = μsN

where N is the normal force between the bike and the ground.

N = mg

Now we can substitute the equations and solve for μs:

fs = μsN

μsN = (mv^2) / r

μs(mg) = (mv^2) / r

μs = (v^2) / (rg)

Plugging in the given values v = 11 m/s

r = 22 m

μs = (11^2) / (22 * g)

The value of g is approximately 9.8 m/s^2.

μs = 5.5 / (22 * 9.8)

μs ≈ 0.025

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The magnitude of the load on the crane before the collapse was 7871.48 N, which is well below the maximum load rating of 500 kg.To determine the load on the crane, we need to use the principles of static equilibrium.

The crane is in equilibrium when the sum of the forces acting on it is zero and the sum of the torques is also zero.The forces acting on the crane are tension in the cable and the weight of the horizontal beam. the torque is due to the weight of the horizontal beam.First, calculate the weight of the horizontal beam:

W = mgL = 85.105.0009.810 = 4168.52 N, where m is the mass per meter of length, g is the acceleration due to gravity, and L is the length of the beam.Now calculating the torque due to the weight of the beam :

τ = W*(h/2) = 4168.52*(2.250/2) = 4686.03 Nm, where h is the height of the horizontal beam. since the  crane is equilibrium, the tension in the cable must balance the weight of the beam which is  T = W. now  substituting the values we get :

=>12040 N = 4168.52 N + L=> 12040 N - 4168.52 N = 7871.48 N

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The magnitude of the acceleration of the body is approximately 1.802 m/s^2 when forces of magnitude 5 Newton and 4 Newton act on a body of mass 4.0 kg at a right angle to each other.

To determine the magnitude of the acceleration of a body when two forces act on it at a right angle, we can use the Pythagorean theorem and Newton's second law of motion.Newton's second law states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma). In this case, the net force is the vector sum of the two forces acting on the body.Using the Pythagorean theorem, we can find the magnitude of the net force. Let's call the force with magnitude 5 Newton as F1 and the force with magnitude 4 Newton as F2. The net force (Fnet) can be calculated as the square root of the sum of the squares of the individual forces: Fnet = sqrt(F1^2 + F2^2).Now we can substitute the net force into Newton's second law to find the acceleration (a). Rearranging the formula, we have a = Fnet / m.Plugging in the values, Fnet = sqrt(5^2 + 4^2) = sqrt(25 + 16) = sqrt(41) Newtons. The mass (m) is given as 4.0 kg.

Finally, the magnitude of the acceleration of the body is calculated as a = Fnet / m = sqrt(41) / 4.0 ≈ 1.802 m/s^2.

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Answer:

radius=4.77cm

Explanation:

given

r=? ,h=14 , v=1000

then using the formula

\(r = \sqrt{ \frac{v}{\pi \: h} } \)

= √1000/π•14

=4.77cm

Answer:

Alloys are just mixtures of metal and metalloids are metallic substances with properties of metal.

Answer:

metalloids are chemical elements that form substances that have properties of metals and non metals while alloys is a mixture of metals

The diameter of the piston the student is standing on is 0.22 times greater than that of the piston the elephant is standing on.

Given parameters:

Mass of the student: m = 70 kg.

Mass of the elephant: M = 1200 kg.

Let the diameter of the piston the student is standing on is d.

and  the diameter of the piston the elephant is standing on is D.

Using Pascal's law,

Weight of the student ÷ area  of the piston the student is standing on = Weight of the elephant ÷ area  of the piston the elephant is standing on.

⇒ 70 kg × g / π d² = 1200 kg × g / π D²

⇒ 1400 d² = 70 D²

⇒ d= 0.22D.

Hence,  the diameter of the piston the student is standing on is 0.22 times greater than that of the piston the elephant is standing on.

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The theory astronomers use to rectify the apparent problem of insufficient time to form Jovian planets is the core-accretion model

Jovian planets are giant gas planets, such as Jupiter, Saturn, Uranus, and Neptune, that are thought to have formed far from the sun. The core accretion model is a widely accepted theory in astronomy that explains the formation of Jovian planets. This model proposes that the core of a Jovian planet forms first by the collision and accumulation of solid particles, followed by the accretion of gas onto the solid core.

The solid core acts as a seed for the gas to accumulate around, eventually forming the giant gas planet. The theory has been supported by observations of young stars that show evidence of disk structures around them, which is consistent with the core-accretion model. By using this theory, astronomers can explain the apparent problem of insufficient time to form Jovian planets in the universe. So therefore astronomers use the core-accretion model to rectify the apparent problem of insufficient time to form Jovian planets.

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The barometer reading at the top of the mountain is  98,737.6 Pa.

The barometer reading at the top of the mountain is calculated as follows;

Atmospheric pressure at base = ρgh

= 1.25 kg/m³ x 9.81 m/s² x 0.74 m

= 9.1 Pa

Pressure due to mercury column at base;

= 13,600 kg/m³ x 9.81 m/s² x 0.74 m

= 98,727.8 Pa

Total pressure at base = Atmospheric pressure + Pressure due to mercury column

= 9.1 Pa + 98,727.8 Pa

= 98,736.8 Pa

The total pressure at the top of the mountain can be calculated as follows;

Total pressure at top = Pressure due to mercury column + ρgh

98,736.8 Pa  = 101,325 Pa   + 1.25 kg/m³ x 9.81 m/s² x h

98,736.8 Pa = 101,325 Pa  + 12.263h

12.263h = -2,588.2

h = -211 m

Barometer reading at top;

= 101,325 Pa + 1.25 kg/m³ x 9.81 m/s² x (-211 m)

= 98,737.6 Pa

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a) Answer:

Momentum = 6 kgm/s

Explanation:

Momentum = mass × velocity

Given that,

Therefore, momentum = (0.02 × 300)kgm/s

Momentum = 6 kgm/s

b) Answer:

Momentum =80 kgm/s

Explanation:

Momentum = mass × velocity

Given that,

Therefore, momentum = (40 × 2)kgm/s

Momentum = 80 kgm/s

c) Answer:

Momentum = 800 kgm/s

Explanation:

Momentum = mass × velocity

Given that,

Therefore, momentum = (200 × 4)kgm/s

Momentum =800 kgm/s

Answer: Yes. Please find the answer in the explanation.

Explanation:

Yes. Since velocity is a vector quantity, that is, it has both magnitude and direction.

If the displacements covered are not of the same direction, the velocity will not also of the same direction.

Take for instance, if the velocity in a positive is 40 m/s and velocity in the opposite direction is - 20 m/s . Then, the resultant velocity will be 40 - 20 = 20 m/s

Therefore,  it is possible that at any time during their trip their velocity was -20 m/s.

Answer:

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The kinetic energy of the car is calculated using the formula KE = (1/2)mv^2. By plugging in the mass of the car (1489 kg) and the speed (95.4 km/h), we can calculate the kinetic energy in kilojoules.

The kinetic energy of a 1489 kg car traveling at a speed of 95.4 km/h can be calculated using the formula for kinetic energy, which is given by the equation KE = (1/2)mv^2. By converting the speed from km/h to m/s, the kinetic energy can be determined in joules and then converted to kilojoules.

First, we need to convert the speed from km/h to m/s. We know that 1 km/h is equal to 0.2778 m/s. Therefore, the speed of the car in m/s is 95.4 km/h * 0.2778 m/s = 26.5 m/s.

Next, we can plug the values into the formula for kinetic energy: KE = (1/2)mv^2. Using the given mass of the car (1489 kg) and the calculated speed (26.5 m/s), we have KE = (1/2) * 1489 kg * (26.5 m/s)^2.

Calculating this expression gives us the kinetic energy of the car in joules. To convert it to kilojoules, we divide the result by 1000. The final answer will be in kilojoules, representing the amount of energy possessed by the car due to its motion.

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The kinetic theory of gases is a model that explains the behavior of gases in terms of the motion of their constituent particles. According to this theory, gases are made up of tiny particles that are in constant random motion.
The correct answer is statement C

Statement A: "Gaseous particles are considered as point masses" is a correct statement in terms of the kinetic theory of gases. The particles of a gas are considered as point masses because their size is negligible compared to the distance between them.

Statement B: "The molecules are in random motion" is also a correct statement. The particles of a gas move randomly and in all directions with varying speeds.

Statement C: "When molecules collide, they lose energy" is not a correct statement. When gas molecules collide, they transfer energy between them. However, the total energy of the system is conserved.

Statement D: "When a gas is heated, the molecules move faster" is a correct statement. Heating a gas increases the kinetic energy of its particles, causing them to move faster.

In summary, , which is not correct in terms of the kinetic theory of gases. When gas molecules collide, they transfer energy between them, but the total energy of the system is conserved.

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The speed of the man with respect to a passenger sitting at rest in the train is 17 m/s in the opposite direction of the train's motion.

The speed of the man with respect to a passenger sitting at rest in the train can be calculated using the concept of relative velocity.

Relative velocity is the velocity of an object with respect to another object.

In this case, the velocity of the man with respect to the track is 14 m/s and the velocity of the train with respect to the track is 31 m/s.

To find the velocity of the man with respect to the passenger sitting at rest in the train, we can use the formula:

Where Vmp is the velocity of the man with respect to the passenger, Vmt is the velocity of the man with respect to the track, and Vpt is the velocity of the passenger with respect to the track.

Plugging in the given values, we get:

Vmp = 14 m/s - 31 m/s

Vmp = -17 m/s

Therefore, the speed of the man with respect to a passenger sitting at rest in the train is 17 m/s in the opposite direction of the train's motion.

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Answer: B Hope I helped ^^

Explanation:

The pith balls are having same charge and that is why they are held apart by the force of repulsion. When they both touched by the experimenter's finger they both gets attracted to the finger and comes in contact as in B.

Electrostatic force between two charges are arise when the charged bodies comes in contact. There are both force of attraction and repulsion. The electrostatic force of attraction results from the two unlike charges and the force of repulsion arise between two like charges.

Here, the pith balls are charged alike, hence they will get repelled. Ig they are negatively charged, the electrons will flow from them to the other body in touch.

When the experimenter touch his finger on the charged ball, the finger gets polarized and attracted to the ball , they gets in contact as in figure B.

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A Carbon atom (C) at the heart of the CO3(2-) Lewis structure is surrounded by three Oxygen atoms (O).

Between each Oxygen atom and the Carbon atom (C), there are two single bonds and one double bond (O). On an oxygen atom with a double bond, there are two lone pairs while on an atom with a single bond, there are three lone pairs (O). A polyatomic ion having the formula CO3 is called a carbonate ion (2-). NCI A carbon oxoanion is carbonate. It is a hydrogencarbonate's conjugate base. Negativity and the nature of bonds This indicates that the oxygen-carbon bond in the CO3(2-) ion is polar in nature, according to the Pauling scale.

The dipole moment along the three bonds in a molecule's trigonal planar form cancels each other out.

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Answer:

2 more neutrons

Explanation:

To obtain the answer to the question, let us calculate the number of neutrons in carbon–14 and standard carbon (i.e carbon–12). This can be obtained as follow:

For carbon–14:

Mass number = 14

Proton number = 6

Neutron number =?

Mass number = Proton + Neutron

14 = 6 + Neutron

Collect like terms

14 – 6 = Neutron

8 = Neutron

Neutron number = 8

For carbon–12:

Mass number = 12

Proton number = 6

Neutron number =?

Mass number = Proton + Neutron

12 = 6 + Neutron

Collect like terms

12 – 6 = Neutron

6 = Neutron

Neutron number = 6

SUMMARY:

Neutron number of carbon–14 = 8

Neutron number of carbon–12 = 6

Finally, we shall determine the difference in the neutron number. This can be obtained as follow:

Neutron number of carbon–14 = 8

Neutron number of carbon–12 = 6

Difference =?

Difference = (Neutron number of carbon–14) – (Neutron number of carbon–12)

Difference = 8 – 6

Difference = 2

Therefore, carbon–14 has 2 more neutrons than standard carbon (i.e carbon–12)

Warming the bed with water is far more efficient than warming the bed with an iron, the difference is the specific heat capacity of water and iron.

The specific heat capacity of a substance can be defined as the amount of the heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree).

q = m x C x AT

As the specific heat of water is 4.18 J/g°C and the specific heat of iron is 0.450 J/g°C. Since, the specific heat of water is greater than the specific heat of iron.

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The horizontal displacement of the cannonball  is  65.75 meter.

Speed is characterized as the rate at which an object's position changes in any direction. The distance travelled in relation to the time it took to travel that distance is how speed is defined. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

original speed: u= 35.9 m/s.

acceleration due to gravity: g = 9.8 m/s².

Initial height of the cannonball = 166 m.

Hence,  the horizontal displacement of the cannonball = u²/2g

= 35.9²/(2×9.8) meter

= 65.75 meter.

so, the displacement of the cannonball  is  65.75 meter.

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Answer:

C: Karl Schwarzschild correctly analyzed the relationship between the size of a black hole and its mass.

Explanation:

Karl Schwarzschild correctly analyzed the relationship between the size of a black hole and its mass. The correct option is C.

A black hole is an area of spacetime in which gravity is so powerful that nothing, not even light or other electromagnetic waves, can escape. According to general relativity theory, a sufficiently compact mass can bend spacetime to generate a black hole.

Karl Schwarzschild, a German physicist, was the first to "find" black holes. In 1915, he proposed a general relativity solution that was applicable to the simple (i.e., nonrotating, uncharged, and boring) example of a perfectly spherical object contained in otherwise empty space.

These suggestions are now known as the Schwarzschild radius and the singularity. Every item is allocated a Schwarzschild radius, which is determined by the object's mass. Gravity's behaviour begins to become strange within this radius.

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A collision that is fully elastic is one where there is no kinetic energy lost during the contact. In an inelastic collision, a proportion of the energy is converted into another kind of energy during the contact.

In elastic collisions, kinetic energy and momentum are both conserved. Consider two similar trolleys that are moving in the same direction at the same pace. With no loss of speed, they collide and bounce off one another. Since no power has been lost, this collision is fully elastic.

photo of A description of completely elastic collision

When a system's maximal quantity of kinetic energy is equal to zero, a relatively inelastic collision takes place.

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A collision that is fully elastic is one where there is no kinetic energy lost during the contact. In an inelastic collision, a proportion of the energy is converted into another kind of energy during the contact.

In elastic collisions, kinetic energy and momentum are both conserved. Consider two similar trolleys that are moving in the same direction at the same pace. With no loss of speed, they collide and bounce off one another. Since no power has been lost, this collision is fully elastic.

photo of A description of completely elastic collision

When a system's maximal quantity of kinetic energy is equal to zero, a relatively inelastic collision takes place.

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Answer:

Boyle's law, Charles's law, and Avogadro's law

Explanation:

9514 1404 393

Answer:

  63.4 °C

Explanation:

If we assume the "fixed points" are 0 °C and 100 °C, then the thermometer reading as a function of actual temperature can be described by a linear equation that must have (0, -0.5) and (100, 106) as solutions. We can use these points in the 2-point form of the equation for a line:

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

  y = (106 -(-0.5))/(100 -0)(x -0) -0.5

  y = 106.5x -0.5

Then, for x = 60, the thermometer reading is expected to be ...

  y = 106.5×60 -0.5 = 63.4 . . . °C

A bacteria (10^15 kg) weighs ten times as much as an ordinary cell (10^2 kg for a hummingbird and 10^12 cells for a bacterium). A essential quality of a body is its mass.

It was widely believed to be connected to the volume of matter in a physical body before to the atom's discovery and the development of particle physics. The mass of a unit cell is calculated as the product of the masses of each atom and the quantity of atoms in the unit cell. Mast cells are so-called because they can release protein-antibodies.

(Hummingbird Mass/Cell Mass) = 10^-2/10^-14 = 10^12 cells is the formula for estimating the number of cells.

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The complete question is -

Assuming the mass of an average cell is ten times the mass of a bacterium (which is 10⁻¹⁵ kg):Calculate the number of cells in a hummingbird, assuming it weighs 10⁻² kg.

These two forces are called action and reaction forces and are the subject of Newton's third law of motion.

Have a luvely day!

Answer:

V = -0.4 m/s

Explanation:

Given that,

Mass of cart 1, m₁ = 3 kg

Speed of cart 1, v₁ = 2 m/s

Mass of cart 2, m₂ = 2 kg

Speed of cart 2, v₂ = -4 m/s (left)

aWe need to find the velocity of the carts after the collision if they stick together. Let the common speed be V. Using the law of conservation of momentum to find it such that,

\(m_1v_1+m_2v_2=(m_1+m_2)V\\\\V=\dfrac{m_1v_1+m_2v_2}{(m_1+m_2)}\)

Put all the values,

\(V=\dfrac{3\times 2+2\times (-4)}{(3+2)}\\\\=-0.4\ m/s\)

So, the velocity of the carts after the collision is equal to 0.4 m/s to the left.