An object moving at a constant velocity of 5.4 m/s travels for 12 s. How far will it move during that time?x = xo + vo t + ½ a t 2 g = 9.8 m/s2 (downward)

Answer:

C6H12O6 is the final product of Calvin cycle light independent reactions

Explanation:

* steps in Calvin cycle

: carbon fixation

: reduction

: regeneration

for C6H12O6 it requires 2 molecules of PGAL or G3P

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If a light bulb is placed at d and b is closed, the light bulb will be on.

A light bulb is a device that produces light from electricity.

A light bulb circuit works when the electric current flowing through the light bulb combines with the current flowing in the battery or power source.

Since bulb is connected in the closed circuit at the position of D, also switch B is closed, in this situation, current will flow through the bulb and bulb will glow

So the most appropriate correct option will be

D. The light bulb will be on

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The front of the truck is designed to crumple during a collision to absorb the impact energy, slow down the collision, and protect the well-being of the passengers. This design feature helps increase the collision time, reduce the forces acting on the passengers, and minimize the risk of severe injuries.

Danica observes a collision between two vehicles. She sees a large truck driving down the road. It strikes a small car parked at the side of the road. On colliding, the truck applies a force on the stationary car, and the stationary car applies an opposite force on the truck. The front of the truck is designed to crumple in order to absorb the impact energy and slow down the collision , which protects the well-being of the passengers.

During a collision, the principle of Newton's third law of motion comes into play. According to this law, for every action, there is an equal and opposite reaction. In the case of the collision between the truck and the car, the truck exerts a force on the car, pushing it forward, while simultaneously experiencing an equal and opposite force from the car.

The purpose of designing the front of the truck to crumple is to increase the collision time and absorb the kinetic energy. When the truck collides with the stationary car, the front of the truck deforms, crumples, and absorbs a significant amount of the impact energy. This process increases the time over which the collision occurs, reducing the forces acting on the passengers and minimizing the risk of severe injuries.

By allowing the truck to crumple, the kinetic energy of the collision is transformed into other forms, such as deformation energy and heat. This energy transformation helps protect the passengers by reducing the deceleration forces acting on them. It also helps prevent the transfer of excessive forces to the car's occupants and reduces the likelihood of severe injuries.

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Answer:

N = 2mg

Explanation:

Assuming the surface is horizontal

The surface must provide enough normal force to prevent the masses from accelerating in the vertical direction.

(a) The normal force exerted by the surface on the bottom block is N1 = 2mg.

Given that,

Based on the above information, we can say that the N1 is 2mg.

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y= 6.26 lb.

Check attached image 1.

Using the trigonometric functions, we need to find a function that relates the angle, opposite side and adjacent side of the drawn triangle. The function that does this is the tangent.

Let theta (θ) be the angle given by the problem.

Let "y" be the missing y component.

Tangent (θ) = Opposite side (y) / Adjacent side (x)

\(Tan(tetha)=\frac{y}{x}\)

\(Tan(tetha)*x=y\)

\(Tan(51.8)*(4.93)=y\\ \\y=6.26\)

5. Express the result.

y= 6.26 lb.

Forklift attachments are not integral parts of the forklift equipment but are used to hold a load or loads. Examples of forklift attachments include fork extensions, side shifters, clamps, rotators, and pallet handlers.

A forklift is a piece of heavy equipment that is primarily used to lift and move materials over short distances. It typically consists of a power-operated platform, called a pallet, that can be raised and lowered using hydraulic cylinders. The pallet is attached to a set of forks that can slide under a load, allowing it to be lifted and moved.

Forklifts are commonly used in warehouses, manufacturing facilities, and construction sites, where they can quickly and efficiently move heavy materials from one location to another. They are also used to load and unload trucks and shipping containers. Forklifts come in a variety of sizes and configurations, ranging from small, electric-powered models for indoor use, to large, diesel-powered models for outdoor applications.

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Answer: The capacitor is fully charged when the voltage of the power supply is equal to that at the capacitor terminals. This is called capacitor charging; and the charging phase is over when current stops flowing through the electrical circuit.

(a) The magnitude and direction of the net force on the crate while it is on the rough surface is 34.7 N in opposite direction.

(b) The net work done on the crate while it is on the rough surface is -22.6 J.

(c) The speed of the crate when it reaches the end is 0.5 m/s.

The magnitude and direction of the net force on the crate while it is on the rough surface is calculated as follows;

F (net) = F - Ff

where;

F (net) = F - μmg

where;

F (net) = 289 N  -   (0.359 x 92 X 9.8)

F (net) = -34.7 N

The negative sign indicates opposite direction to the applied force.

The net work done on the crate while it is on the rough surface is calculated as follows;

W = F(net) x L

where;

W = -34.7 x 0.65

W = -22.6 J

The speed of the crate when it reaches the end is calculated as follows;

acceleration of the crate = F(net) / m

a = -34.7 N / 92 kg

a = -0.377 m/s²

v² = u² + 2aL

v² = ( 0.855)²  +  ( 2 x -0.377 x 0.65)

v² = ( 0.855)²   - ( 2 x 0.377 x 0.65)

v² = 0.24

v = √ 0.24

v = 0.5 m/s

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Answer:

look for the "W" in the North. Remember that, the "W" may be on its side or inverted to form an "M." If you can recognize the Big Dipper (Ursa Major), the two stars at the edge of the Dipper point toward the North Star (Polaris)

Explanation:

Answer: I'm pretty sure the answer is B

Explanation: I'll check after the test

:Okay yes the answer is 100% B

The direction of the magnetic field shown by the magnetic field lines around a magnet is from north to its south pole of magnet. Option B is correct.

Magnetic Field Lines:

These are the imaginary lines that are used to represent the strength of the magnetic field.

Therefore, the direction of the magnetic field shown by the magnetic field lines around a magnet is from north to its south pole of magnet.

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If the initial speed of the ball was increased the horizontal distance traveled by the ball would increase.

Speed in physics is the change in distance over time, and is the distance traveled divided by the time traveled. Speed is a scalar quantity so it only has magnitude and has no direction. Because speed has no direction, it is always positive.

Italian physicist Galileo Galilei was the first scientist to measure speed by measuring the distance traveled and the time needed to travel that distance.

Galileo defined speed as distance per unit time. The equation is as follows: v = d/t , where v is speed, d is distance, and t is time. For example; a person on a bicycle covers a distance of 30 meters in 2 seconds then has a speed of 15 meters per second.

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The average speed of the whole journey is 54 mph.

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Answer:

Explanation:

vapour pressure at 70⁰F = .36 psi

pressure of 6.5 inch water column

6.5 inch = 6.5 x 2.54 cm =.165 m

pressure = .165 x 10³ x 9.8 = 1617 Pa

= 1617 x .000145 psi

= .23 psi

28.35 inch = 28.35 x 2.54 cm = .72 m

pressure = .72 x 13.6 x 10³ x 9.8

= 95961.6 Pa

= 95961.6 x .000145 psi

= 13.91 psi

a ) Barometric pressure at  70⁰F

=  pressure due to mercury column of 28.35 inch + water column of 6.5 inch + vapour pressure at 70⁰F

= 13.91 + .23 + .36 psi

= 14.5 psi

b )

If pressure is measured at 85⁰F

vapour pressure will be increased and pressure of dry gas will also be increased . This pressure will force down the column of mercury . So column of mercury will go down .

Answer:

F = 15 N

Explanation:

Given:

m = 3.0 kg

μ = 0.50

__________

F - ?

Friction force:

F = μ·m·g

F = 0.50·3.0·9.8 ≈ 15 N

Explanation:

Increasing the rpm results in an increase of terminal voltage and an increase in frequency and magnetic field

The direction in which the 25 kg mass will move is to the Left. The correct option is A.

This is because the force pulling to the left is greater than that to the right.

The velocity of the mass after 1 second will be 0.4 m/s

The velocity of the mass after 2 seconds will be 0.8 m/s

The net force o the mass of 25 kg is given below:

Net force = 20 N - 10 N

Net force = 10 N

The velocity of the mass is given by the formula below:

Velocity = net force * time / mass

velocity after 1 second = 10 * 1 / 25

velocity after 1 second = 0.4 m/s

velocity after 2 seconds = 10 * 2 / 25

velocity after 2 seconds = 0.8 m/s

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Answer:

Target must be placed 1.42 meters from the table

Explanation:

Answer:

The rate of change of velocity is acceleration. Like velocity, acceleration is a vector and has both magnitude and direction. For example, a car in straight-line motion is said to have forward (positive) acceleration if it is speeding up and rearward (negative) acceleration if it is slowing down.

Explanation:

Hope it is helpful....

Answer:

All objects free fall at the same rate of acceleration regardless of their mass. But, if you were to increase the force on the object then the acceleration will increase while the mass decreases. Therefore, the greater force on more massive objects is offset by greater mass.

the force the woman exerts to do a push-up at constant speed is 333 N.

the work the woman does is 152 J.

her useful power output is 76 W.

(a) To calculate the force the woman exerts to do a push-up, we need to use torque methods. The woman is doing a push-up at constant speed, which means that the net torque on her body is zero. The only torque acting on her body is due to her weight W, which acts at the center of mass of her body. The distance between her center of mass and her hands is 0.76 m, and the angle between her body and the horizontal is 45 degrees.

The torque due to her weight about her hands is given by:

τ = r x W = (0.76 m) x (cos 45°)(W)

where r is the distance between her hands and her center of mass and cos 45° is the component of the distance perpendicular to the weight vector. Since the woman is at constant speed, the torque she exerts about her hands must be equal and opposite to the torque due to her weight. Therefore:

τ = (0.76 m)(cos 45°)(W) = (1/2)(W)(0.76 m)

Solving for W, we get:

W = 2(τ/0.76 m) = 2[(0.5)(mg)(0.76 m)/(0.76 m cos 45°)] = 333 N

Therefore, the force the woman exerts to do a push-up at constant speed is 333 N.

(b) The work the woman does is equal to the change in her potential energy as her center of mass rises. The woman's mass is not given, so we will assume a value of 60 kg. The gravitational potential energy of the woman is given by:

U = mgh

where m is the mass of the woman, g is the acceleration due to gravity (9.81 m/s^2), and h is the height her center of mass rises (0.26 m). Therefore:

U = (60 kg)(9.81 m/s^2)(0.26 m) = 152 J

Therefore, the work the woman does is 152 J.

(c) The useful power output of the woman is the work she does per unit time, taking into account the work done in lowering her body. Each push-up involves two phases: lifting her body and lowering her body. When she lowers her body, the work done is negative, as the force she exerts is in the opposite direction to the displacement. The work done in lowering her body is equal to the work done in lifting her body, so the total work done in one push-up is zero.

The woman does 30 push-ups in 1 minute, which means she does one push-up every 2 seconds. Therefore, the useful power output of the woman is:

P = (152 J)/(2 s) = 76 W

Therefore, her useful power output is 76 W.

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The time taken is approximately 2.08 seconds for the bag of sand to reach the ground from the moment of its release.

To determine the time it takes for the bag of sand to reach the ground, we can use the kinematic equation for vertical motion. The equation is given as:

h = ut + (1/2)gt^2

Where:

h = height (37.8 m)

u = initial velocity (0 m/s)

g = acceleration due to gravity (-9.81 m/s^2, considering downward motion)

t = time

Since the balloon is ascending with a constant upward velocity of 2.95 m/s, the initial velocity of the bag is also 2.95 m/s in the upward direction. Therefore, we need to consider the initial velocity as negative.

Substituting the known values into the equation, we have:

37.8 = (-2.95)t + (1/2)(-9.81)t^2

Simplifying the equation further, we get:

-4.905t^2 - 2.95t + 37.8 = 0

Solving this quadratic equation for time, we find two solutions: t = 2.08 s and t = -3.61 s. Since time cannot be negative, we discard the negative value.

Therefore, it takes approximately 2.08 seconds for the bag of sand to reach the ground from the moment of its release.

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The relative density of aluminum is 2.7. This means that aluminum is 2.7 times denser than water, which is the reference substance often used for comparing densities

The relative density (also known as specific gravity) of a material is the ratio of its density to the density of a reference substance. In this case, we are given the density of aluminum as 2.7 x 10^3 kg/m^3.

To find the relative density, we need to compare it to the density of the reference substance. The most commonly used reference substance for relative density is water, which has a density of 1000 kg/m^3.

Relative density = Density of the material / Density of the reference substance.Relative density = (2.7 x 10^3 kg/m^3) / (1000 kg/m^3)

Relative density = 2.7

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The airplane will strike the ground at a horizontal distance of 490 meters.

To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.

The horizontal distance traveled by an object can be calculated using the formula:

Distance = Speed × Time

In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.

Distance = 100 m/s × t

Now, to find the value of time, we can rearrange the equation as follows:

t = Distance / Speed

t = 490 m / 100 m/s

t = 4.9 seconds

Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.

Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:

Distance = Speed × Time

Distance = 100 m/s × 4.9 s

Distance = 490 meters

It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.

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When a block is launched with initial speed 2.2 m/s up a 35° frictionless ramp then ramp slides up to 0.43m.

The work-energy theorem explains that net work done by the forces on an object is equal to change in its kinetic energy.

We can also say that work done on a body is equal to the net change in its energy.

Given angle = 35°

initial speed = 2.2m/s

Applying work - energy theorem,

Wgravity = KE

-m *g *sin ∅ * S =1/2* (0- 2.2²)

-9.81*sin 35° *S= 1/2 *(0- 2.2² )

S= 0.43m

Ramp slides up to 0.43m.

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