An object of mass M suspended by a spring vibrates with period T. If this object is replaced by one of mass 4M, the new object vibrates with the period:
a) T
b) 2T
c) 4T
d) 16T

Explanation:

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Answer:

kinetic energy

Explanation:

Electrical energy is a type of kinetic energy caused by moving electric charges. The amount of energy depends on the speed of the charges – the faster they move, the more electrical energy they carry.

Answer:

el monitor,las impresoras y las memorias portátiles

Answer:

5 m/s²

Explanation:

Use the acceleration formula: \(a=\frac{v_f-v_i}{t}\)

Based on the information given to us by the prompt, we know:

Substitute these values for the variables to calculate the acceleration:

\(a=\frac{30-10}{4}\\\\a=\frac{20}{4}\\\\a=5\)

Therefore, the acceleration of the bus is 5 m/s².

The linear curve of the graphs shows an increase in distance of 5 m within 2 seconds. Then , the distance within 5 seconds will be 12.5m and the instantaneous speed is 2.5 m/s.

Instantaneous speed of an object is the speed at a particular instant. It describes how far an object travelled at a particular moment in time.

It is given that, the graph shows linearity in curve , where for each 2 second time interval the monkey climbs 5m. Then, for a time interval of 5 seconds, the monkey will climb 12.5 m in the tree.

Instantaneous speed = distance/time

t= 5 s

d = 12.5 m

then v = 12.5/5 = 2.5 m/s

Therefore, the instantaneous speed of the monkey within the given time will be 2.5 m/s.

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Given that both the chair and the person are affected by Earth's movement, we can deduct that both have inertia due to Earth's speed.

Answer:

F= 5000 N

Explanation:

This problem is related to force on a body, and to tackle it we need to apply newtons first law of motion which states that "a body will continue to be at rest or uniform motion except acted upon by an external force greater than the force keeping the body at rest or uniform motion"

given

mass m= 200kg

acceleration a= 25 m/s

we know that

F= ma

F= 200*25

F= 5000 N

Weight = (mass) x (gravitational acceleration where the mass is)

Weight = (1360 kg) x (9.8 m/s²)

Weight = 13,328  kg-m/s²

That's 13,328 Newtons

Given:-

To Find: Weight (W).

We know,

W = mg

where,

Thus,

W = (1360 kg)(9.8 m/s²)

→ W = 13,328 N (D)

In conclusion, the acceleration of the hollow spherical shell as it rolls down the slope is equal to the net force acting on it divided by its mass. The exact value of the acceleration depends on the radius of the shell, which is not provided in the problem.

To solve this problem, we can apply the principles of rotational motion and the concept of torque.

Given:

Mass of the hollow spherical shell (m) = 1.50 kg

Angle of the slope (θ) = 31.0°

We need to determine the acceleration of the shell as it rolls down the slope.

First, let's calculate the gravitational force acting on the shell. The gravitational force can be determined using the formula:

F_gravity = m * g

where g is the acceleration due to gravity, which is approximately 9.8 m/s^2.

F_gravity = 1.50 kg * \(9.8 m/s^2\) = 14.7 N

Next, let's analyze the forces acting on the shell as it rolls down the slope. There are two main forces involved: the gravitational force (F_gravity) acting vertically downward and the normal force (N) acting perpendicular to the surface of the slope.

The component of the gravitational force parallel to the slope can be calculated as:

F_parallel = F_gravity * sin(θ)

F_parallel = 14.7 N * sin(31.0°) = 7.73 N

Since the shell rolls without slipping, the friction force (f) can be calculated as:

f = μ * N

where μ is the coefficient of static friction. However, since the shell is rolling without slipping, the friction force is zero, as there is no relative motion between the surface and the shell.

Since there is no friction force, the net force acting on the shell is the parallel component of the gravitational force:

Net force (F_net) = F_parallel = 7.73 N

Finally, we can use Newton's second law for rotational motion to determine the angular acceleration (α) of the shell:

F_net = I * α

where I is the moment of inertia of the hollow spherical shell.

The moment of inertia of a hollow spherical shell can be calculated as:

I = (2/3) * m * R^2

where R is the radius of the shell.

Since the radius is not given in the problem, we cannot calculate the exact value of the angular acceleration. However, we can analyze the rotational motion of the shell.

As the shell rolls down the slope, it experiences a torque due to the net force acting on it. The torque can be calculated as:

τ = F_net * R

where R is the radius of the shell.

Since the shell rolls without slipping, the linear acceleration (a) can be related to the angular acceleration (α) as:

a = R * α

Combining these equations, we have:

τ = m * a * R

F_net * R = m * a * R

F_net = m * a

Therefore, the net force is equal to the mass of the shell times its linear acceleration.

In conclusion, the acceleration of the hollow spherical shell as it rolls down the slope is equal to the net force acting on it divided by its mass. The exact value of the acceleration depends on the radius of the shell, which is not provided in the problem.

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Answer:

La rapidez del móvil es 12 kilómetros por hora.

Explanation:

Asumamos que el móvil experimenta un movimiento rectilíneo uniforme, cuya ecuación cinemática es la siguiente:

\(v = \frac{x}{t}\) (1)

Where:

\(x\) - Distancia recorrida, en kilómetros.

\(t\) - Tiempo, en horas.

\(v\) - Rapidez, en kilómetros por hora.

Si tenemos que \(x = 6000\,m\) y \(t = 30\,min\), entonces la rapidez del móvil es:

\(v = \frac{6000\,m\times \frac{1}{1000}\,\frac{km}{m}}{30\,min \times \frac{1}{60}\,\frac{h}{min} }\)

\(v = 12\,\frac{km}{h}\)

La rapidez del móvil es 12 kilómetros por hora.

When we do, we make sure to measure our mass in kilograms. We determine that F is equal to 124.26 newtons by entering these numbers into our calculator.

That is the average magnitude of the force applied to the tennis ball.

The equation that Newton was referring to is shown by a serve. You can calculate the total force that was applied by the tennis racket to the ball by multiplying the weight of the racket by the speed at which the player swings their racquet.

An average 120-mph serve slows to 82 mph before the bounce, 65 mph after the bounce, and 55 mph at the opponent's racket, according to tennis instructor and analyst John Yandell.

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Infrared rays can be used to lower your monthly utility bills by using an infrared heater. The primary advantage of using an infrared heater is that it operates in a more targeted manner than a conventional heater.

It produces heat that is absorbed by the people and objects within its range, rather than the air. As a result, it requires less energy to warm up a room than a conventional heater.A heating system that uses infrared light waves can also save you money on your utility bills by reducing energy waste.

Traditional heating systems expend energy to heat large areas that aren't being used or are occupied by inanimate objects. In contrast, infrared heating panels, which provide heat directly to people and objects, do not heat the air unnecessarily. As a result, less energy is used, resulting in lower utility costs.

As a result, you may use infrared heaters to target heat where it is required in the house, reducing the need for an entire home heating system and saving money on your energy bills. Infrared heaters can be used in conjunction with a thermostat to regulate temperature and manage energy costs. In general, an infrared heater's lower energy consumption implies that it has a lower operating cost than a traditional heater.

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The battery would have approximately 4.68 x 10^20 electrons flow through it per minute when connected to a 1.20 ohm bulb.

To calculate the number of electrons that flow through the circuit per minute, we need to use the formula:
I = V/R
where I is the current, V is the voltage of the battery, and R is the resistance of the bulb.

In this case, the voltage of the battery is 1.5V, and the resistance of the bulb is 1.20 ohms. Plugging these values into the formula, we get:
I = 1.5V / 1.20 ohms
I = 1.25 amps

Now, we need to convert this current to the amount of electrons that flow through the circuit per minute. To do this, we need to use the formula:
n = I*t/q

where n is the number of electrons, I is the current, t is the time in seconds, and q is the charge of an electron (which is 1.602 x 10^-19 coulombs).

We can convert the time from minutes to seconds by multiplying by 60. So, if we assume that the battery is connected to the circuit for one minute, we can calculate the number of electrons as:
n = 1.25 amps * (60 seconds) / (1.602 x 10^-19 coulombs)
n = 4.68 x 10^20 electrons

Therefore, the battery would have approximately 4.68 x 10^20 electrons flow through it per minute when connected to a 1.20 ohm bulb.

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Answer:

yes

Explanation:

banked curve :

is a road that looks like the top part of a race track

its looks elevated

often seen in bicycle race track (velodrome)

Banking the curve can help keep cars from skidding. When the curve is banked, the centripetal force can be supplied by the horizontal component of the normal force.

sfuca

Given,

The mass of the object, m=2.1 kg

The speed of the object, v=25 m/s

Kinetic energy is the energy that an object possesses due to its motion. And potential energy is the energy that an object possesses due to its position.

The gravitational potential energy depends on the height of the object. As the change in the height of the object is not mentioned in the question, let us assume that there is no change in the potential energy.

The velocity of the object, however, changes. Thus the energy possessed by the object is the kinetic energy.

And the kinetic is given by

On substituting the known values,

Thus the kinetic energy of the ball is 656.25 J

Answer:

Charges B and C are negative

Explanation:

• We are certain of a law of magnetism that states "Field lines move from positive charge to negative charge"

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Answer:

B and C are negative.

Explanation:

This is because according to the law of charges in electric field line it says that the lines forming the electric field move from the positive terminal to the negative terminal,hence making B and C be negative as the lines are moving into them.

Answer:

1 m/s so number 2 is the right one

Explanation:

so when it is at rest it still has some of the left over energy so it would be at 1 m/s

If you are floating in the solar system at equal distances between Mars which has a small and Jupiter which has a larger mass than Jupiter, the planet has the largest gravitational pull. So the planet which has a larger mass will have a more gravitational pull.

The gravitationally bound system known as the Solar System is made up of the Sun and the asteroids that orbit it. It formed 4.6 billion years ago when a large interstellar molecular cloud gravitationally collapsed. Jupiter holds the lion's share of the system's remaining mass, with the Sun owning the vast majority of it.

Because Jupiter is the largest planet in our solar system, it has the strongest gravity. On Jupiter, you would weigh 2.5 times more than you would on Earth. Everything is drawn to the surface of the planet by the fundamental force of gravity.

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(a) The mechanical energy of the baseball of mass 0.45 kg at a height of 10m is  179.16 J (b) The mechanical energy of the baseball  at a height of 9 m is  174.75 J.

mechanical energy is sum of the kinetic energy, or energy of motion, and the potential of a body.

Formula:

Where:

(a) To calculate the mechanical energy of the baseball at an height of 10m, we use the formula above

Given:

Substitute these values into equation 1

(b) Similarly At a height of 9 m, we substitute into equation 1

From the answer, the height only affect the potential energy not the kinetic energy.

Hence, (a) The mechanical energy is  179.16 J (b) The mechanical energy at a height of 9 m is  174.75 J.

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(i)Therefore, it takes approximately 9.27 hours to reach its full power output.(ii)It is necessary to have quick-start power sources, this helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.(c)The Bremsstrahlung effect needs to be considered to ensure proper radiation protection.(d) The near-field region is characterized by strong electric and magnetic fields while the far-field region represents the radiation zone.

(i) To calculate the time it takes for the power station to reach its full power output, we can use the formula:

Energy = Power × Time

Given that the power station generates 6120 MWh of energy over a 10-hour period and the rated power at full capacity is 660 MW, we can rearrange the formula to solve for time:

Time = Energy ÷ Power

Converting the energy to watt-hours (Wh):

Energy = 6120 MWh × 1,000,000 Wh/MWh = 6,120,000,000 Wh

Converting the power to watt-hours (Wh):

Power = 660 MW × 1,000,000 Wh/MW = 660,000,000 Wh

Now we can calculate the time:

Time = 6,120,000,000 Wh ÷ 660,000,000 Wh ≈ 9.27 hours

Therefore, it takes approximately 9.27 hours (or 9 hours and 16 minutes) for the power station to reach its full power output.

(ii) The type of power station that can be started up fastest is a gas-fired power station. Gas-fired power stations can reach full power output relatively quickly because they use natural gas combustion to produce energy.

In contrast, other types of power stations, such as coal-fired or nuclear power stations, have longer start-up times. Coal-fired power stations require time to heat up the boiler and generate steam, while nuclear power stations need to go through a complex series of procedures to ensure safe and controlled nuclear reactions.

This is relevant to optimizing the usage of windfarms because wind power is intermittent and dependent on the availability of wind. This helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.

(c) The Bremsstrahlung effect is a phenomenon that occurs when charged particles, such as electrons, are decelerated or deflected by the electric fields of atomic nuclei or other charged particles. As a result, they emit electromagnetic radiation in the form of X-rays or gamma rays.

In shielding design, the Bremsstrahlung effect needs to be considered to ensure proper radiation protection. These materials effectively absorb and attenuate the emitted X-rays and gamma rays, reducing the exposure of individuals to harmful radiation.

(d) The electromagnetic field output from an antenna can be represented by two main regions:

Near-field region: This region is closest to the antenna and is also known as the reactive near-field. It extends from the antenna's surface up to a distance typically equal to one wavelength. In the near-field region, the electromagnetic field is characterized by strong electric and magnetic field components.

Far-field region: Also known as the radiating or the Fraunhofer region, this region extends beyond the near-field region.The electric and magnetic fields are perpendicular to each other and to the direction of propagation.  The far-field region is further divided into the "Fresnel region," which is closer to the antenna and has some characteristics of the near field, and the "Fraunhofer region," which is farther away and exhibits the properties of the far-field.

The transition between the near-field and the far-field regions is gradual and depends on the antenna's size and operating frequency. The size of the antenna and the distance from it determine the boundary between these regions.

In summary, the near-field region is characterized by strong electric and magnetic fields, while the far-field region represents the radiation zone where the energy is radiated away as electromagnetic waves.

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Answer:

7 hectometers is 7000 decimeters

The electric field strength across the membrane is approximately 8.612 × 10⁶ V/m, given a voltage of 77.7 mV and a membrane thickness of 9.02 nm.

To determine the electric field strength across a membrane, we can use the formula:

Electric field strength = Voltage / Distance

Given that the voltage across the membrane is 77.7 mV (millivolts) and the membrane thickness is 9.02 nm (nanometers), we need to convert the units to be consistent.

1 mV = 0.001 V (volts)

1 nm = 1e-9 m (meters)

Converting the units:

Voltage = 77.7 mV × 0.001 V/mV = 0.0777 V

Distance = 9.02 nm × 1e-9 m/nm = 9.02e-9 m

Plugging the values into the formula:

Electric field strength = 0.0777 V / 9.02e-9 m

Calculating the electric field strength:

Electric field strength = 8.612 × 10⁶ V/m

Therefore, the electric field strength across the membrane is approximately 8.612 × 10⁶ V/m.

In summary, the electric field strength across the membrane is approximately 8.612 × 10⁶ V/m when the voltage across the membrane is 77.7 mV and the membrane thickness is 9.02 nm.

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Given,

The mass of the car, m=1000 kg

The velocity of the car, v=20 m/s

The kinetic energy of an object is the energy of the body possessed due to its motion. The kinetic energy of a body is directly proportional to the square of the velocity of the object.

The kinetic energy of the car is given by,

On substituting the known values,

Thus the kinetic energy of the given car is 200 kJ.

The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)

The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.

To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).

The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).

In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).

Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.

If co > co_critical, the system is considered overdamped (Option E).

If co = co_critical, the system is considered critically damped (Option D).

If co < co_critical, the system is considered underdamped (Option C).

Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.

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Answer: A. They will be repelled because they are in each other's magnetic

field.

Explanation: Apex and gravity and electrical don't have effect on magnets magnetic field.

The statement that described the happening to the magnets should be that they will be attracted because they are in each other's magnetic.

Magnet refers to the  piece of iron or other material that comprise of the atoms also it inbuilt the magnetism properties like attraction of other type of iron objects. In the case when the two magnets shoud be placed near to each other also their north poles should be faced each other so it should be attracted since it is considered as the each other magnetic.

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When toggling between the runs of an oscillating system, a decrease in amplitude might occur. This is especially true when the system is left to oscillate on its own for an extended period of time. This decrease in amplitude is because the energy of the system is gradually lost due to friction between the oscillating mass and the surrounding medium.

There are several reasons why amplitude decreases over time in an oscillating system. One of the most significant reasons is friction. Friction forces in oscillating systems result in energy losses due to heat dissipation. These energy losses result in a decrease in amplitude over time. In the presence of damping, the decrease in amplitude will occur more rapidly. This is because the friction forces in damping systems will act as an additional force that opposes the motion of the oscillating mass and reduces its amplitude.

Another reason for a decrease in amplitude over time is the presence of external forces acting on the system. For instance, if a pendulum is oscillating in a gravitational field, its amplitude will decrease over time due to the loss of energy that occurs when the pendulum moves against the gravitational force acting on it.In conclusion, when left to oscillate, the amplitude of an oscillating system may slowly decrease over time due to frictional forces, damping, and external forces such as gravity acting on the system.

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Answer:

We can float in space.

Explanation:

We can float in space because of gravity. Gravity is the force that attracts anything towards the centre of earth. We can stand, walk because of gravity. Even if we jump, we return to the ground because of gravity. In space, there is no gravity. That's why, we can't walk in space and everything floats there.

if you take 6 liters of air from the surface to a depth of 20 meters/66 feet, the volume will decrease to approximately 2 liters.

When a given amount of air is taken from the surface to a certain depth underwater, the volume of the air will decrease due to the increase in pressure at greater depths.

Boyle's Law states that the volume of a gas is inversely proportional to its pressure when the temperature is held constant.

Boyle's Law can be expressed as:

P₁ × V₁ = P₂ × V₂

Where P₁ and V₁ represent the initial pressure and volume, and P₂ and V₂ represent the final pressure and volume.

let's assume the initial volume (V₁) is 6 liters and the initial pressure (P₁) is the atmospheric pressure at the surface.

Let's assume a typical approximation of the pressure at 20 meters/66 feet is roughly 3 times the atmospheric pressure.

Using Boyle's Law,

P₁ × V₁ = P₂ × V₂

1 atm × 6 L = (3 atm) × V₂

6 L = 3 atm × V₂

V₂ = 6 L / 3 atm

V₂ = 2 L

Therefore, the amount of air will drop to about 2 liters if you descend from the surface to a depth of 20 meters/66 feet.

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Answer:

The correct solution is "\(5\times 10^{-4}\) %".

Explanation:

The given values are:

Pressure,

\(\Delta P=7\times 10^5 \ N/m\)

for copper,

\(B=14\times 10^{10} \ N/m\)

As we know,

The Bulk Modulus (B) = \(\frac{\Delta P}{-\frac{\Delta V}{V} }\)

or,

The decrease in volume will be:

= \((\frac{\Delta V}{V})\times 100 \ percent\)

then,

= \(\frac{\Delta P}{B}\times 100 \ percent\)

On putting the values, we get

= \(\frac{7\times 10^5}{14\times 10^{10}}\times 100 \ percent\)

= \(5\times 10^{-4} \ percent\)