An olympic gold medalist from Moscow runs one time around the 400-meter track in 36seconds.What is her average speed?Answer:m/s

Answer:Aristotle believed that the Earth was orbited by the sun, moon, and the other planets which he referred to as Celestial Bodys

Explanation:please brainliest

The view supported by Aristotle is that the Sun and all the Planets revolve around Earth.

Aristotle who was a great philosopher, viewed the Earth as the center of the universe and that the Sun, Moon, Stars and other Planets revolved around it.

Most philosophers before Aristotle held similar view of Earth, they all believed that Earth was fixed while other planets, Sun and the Moon revolve round the Earth's orbit.

Thus, from the given options we can conclude that the view supported by Aristotle is that the Sun and all the Planets revolve around Earth.

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The air pressure that will produce a force of the given magnitude is 135 times the pressure transmitted by the liquid. The value of P2, the pressure transmitted by the liquid, is not given in the problem, so we cannot determine the exact value of P1.

The planet's gravitational pull on the gases above its surface produces atmospheric pressure, which depends on the planet's mass, the radius of its surface, the quantity, makeup, and vertical distribution of the gases in the atmosphere.

The following equations describe the force that compressed air exerts on a tiny piston:

F1 = P1 * A1

The larger piston, which has a larger area A2, receives the power via the liquid. The larger piston's power is determined by:

F2 = P2 * A2

Pascal's rule states that the larger piston receives the same amount of pressure P1 as the smaller piston, so we have:

P1 = P2

Since the forces F1 and F2 are equal, we have:

F1 = F2

Therefore:

P1 * A1 = P2 * A2

P1 * (pi * (5.00 cm)²) = P2 * (pi * (15.0 cm)²)

Simplifying and solving for P1, we get:

P1 = (P2 * A2 * (5.00 cm)²)/ (A1 * (15.0 cm)²)

Substituting A1 = pi * (5.00 cm)² and A2 = pi * (15.0 cm)², we get:

P1 = (P2 * 15.0²) / 5.00²

P1 = 135 * P2.

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Around 21.49% of the engine power, or 21.5% rounded to two significant figures, is being used to propel the aircraft upward.

There is always a change in the kinetic energy of an object when a net force acts on it. This happens as a result of the object experiencing an acceleration, which changes its velocity. As a result, we arrive at the work-energy theorem. The work-energy theorem is applicable to forces that are both constant and variable.

Power = (mass) x (gravity) x (vertical speed)

where the mass is 700 kg, gravity is 9.81 m/s², and the vertical speed is 2.5 m/s.

Power = (700 kg) x (9.81 m/s²) x (2.5 m/s)

Power = 17,192.5 W

To find the fraction of the engine power that is being used to make the airplane climb, we need to divide the power used for climbing by the total engine power, which is 80,000 W:

Fraction of engine power = (Power for climbing / Total engine power) x 100%

Fraction of engine power = (17,192.5 W / 80,000 W) x 100%

Fraction of engine power = 21.49%

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Explanation:

The WORK required to stop the truck is equal to the initial Kinetic Energy of the truck  ( 1/2 m v^2)

1/2 mv^2   = 1/2 * 2000 * 30^2  = 900 000 J

Distance travelled in 10 seconds is

  d = vot  - 1/2 at^2      where a = 30 m/s / 10 s = 3 m/s^2

     = 30 (10) - 1/2 ( 3)(10^2) = 150 meters

Work = F * d

900 000 = F * 150

   F = 6000 N

Answer:

D

Explanation:

because it doesn't agree with the law of definite proportion

and energy can niether be created nor destroyed but can be transformed from one form to another

The false statement will be, The total amount of energy changes upon an energy transformation.

The conservation of energy according to the first law of thermodynamics is that energy neither be created nor be destroyed, but can be transformed from one form to another form.

Now we can take many examples like if we are running a bicycle our efforts are converted to the rotation of the wheel and the rotation energy is converted to the linear energy of our motion.

But the necessary point is that from the second law of thermodynamics it states that the energy can not be completely converted to the other form but some part of it is losses in the environment.

Thus the false statement will be, The total amount of energy changes upon an energy transformation.

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The magnetic field vectors at points 2 through 5 due to the moving charge are B₂ = -1.3 x 10⁻⁹ T into the paper, B₃ = 0, B₄ = 0, and B₅ = 1.3 x 10⁻⁹ T out of the paper.

To determine the magnetic field vectors B₂ through B₅ at points 2 through 5 due to the moving charge, we need to use the Biot-Savart Law. The Biot-Savart Law gives the magnetic field at a point due to a current-carrying wire or a moving charge.

The Biot-Savart Law is given by:

dB = μ₀/4π (I x dℓ x ẑ) / r²

where;

Considering the velocity of the charge, the magnetic field at each point:

B₂ = μ₀/4π (q vᵧ / r²)sin(90°) = μ₀/4π(q vᵧ / r²)

B₃ = μ₀/4π (q vᵧ / r²)sin(180°) = 0

B₄ = μ₀/4π(q vᵧ / r²)sin(180°) = 0

B₅ = μ₀/4π(q vᵧ / r²)sin(90°) = μ₀/4π(q vᵧ / r²)

where;

Using the given distance of 1.0 mm, we can calculate the magnetic field magnitudes at each point:

B₂ = μ₀/4π(q vᵧ / r²)

The velocity of the charge is calculated as;

B₁ =  μ₀/4π(q vᵧ / r²)

1.3 x 10⁻⁹ = (1.26 x 10⁻⁶ Tm/A)/4π)(1.6 x 10⁻¹⁹ C)(v)/(0.001)²

v = 1.02 x 10⁵ m/s

B₂ = (1.26 x 10⁻⁶ Tm/A)/4π)(1.6 x 10⁻¹⁹ C)(1.02 x 10⁵ m/s) / (0.001 m)²

B₂  = 1.3 x 10⁻⁹ T

B₃ = 0 (since sin(180°) = 0)

B₄ = 0 (since sin(180°) = 0)

B₅ = μ₀/4π(q vᵧ / r²)

B₅ = (1.26 x 10⁻⁶ Tm/A)/4π)(1.6 x 10⁻¹⁹ C)(1.02 x 10⁵ m/s) / (0.001 m)²

B₅ = 1.3 x 10⁻⁹ T

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If the cells are in parallel, they form a battery of 1.5V with the ability to deliver 4 times as much current as one cell can.

If the cells are in series, they form a battery of 6.0V.

Answer: The egg will get sucked into the bottle. To get the egg out of the bottle, turn the bottle upside down and blow into it, so that the egg acts as a one-way valve. The increased air pressure in the bottle will cause the egg to pop back out.

Explanation:

Quickly place the egg over the mouth of the bottle. The egg will get sucked into the bottle. To get the egg out of the bottle, turn the bottle upside down and blow into it, so that the egg acts as a one-way valve. The increased air pressure in the bottle will cause the egg to pop back out.

Answer:a car with 1,000kg

Explanation: A car with a mass of 1,000kg has more inertia than 150 kg

Out of the two objects a 1000-kilogram car and a 150-kilogram golf cart, the 1000-kilogram cart will have more inertia as the inertia of any object is directly proportional to its mass.

According to Newton's first law, until pushed to alter its condition by the intervention of an external force, every object will continue to be at rest or in uniform motion along a single direction.

The larger the mass of the object, the greater would be the inertia of the object.

Thus, a 1000-kilogram automobile will have higher inertia than a 150-kilogram golf cart since any object's inertia is directly proportionate to its mass.

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Answer:

see below

Explanation:

a^3 = 125 m^3

b^2 = 8.41 s^2

c = 45 m/s           Plug these values into the equation

125 / ( 8.41 * 45)  = .33  m^2 / s

Answer:

Initial velocity = 0 × 5/18 = 0 m/s

Final Velocity = 100 × 5/18 = 27.77 m/s

Time = 6 sec

Acceleration

We know that

a = v - u/t

a = 27.77 - 0/6

a = 27.77/6

a = 4.6 m/s²

\( \\ \)

The average acceleration of the car is equal to 4.63 m/s².

The average acceleration is the change in velocity of an object divided by the elapsed time. Acceleration for an object can be described as the rate of change of velocity of the body.

The average acceleration for an interval is the change in velocity for that interval per time. So, the mathematical expression for the average acceleration can be written as:

Average acceleration (a) = △v/△t

If 'u' is the initial velocity and 'v' is the final velocity, and t is the time for the change of the velocity from u to v then a = v - u.

Given, the initial velocity of the car, u = 0

The final velocity of the car, v = 100 Km/hr = 27.77 m/s

The time is taken to change the velocity from 0 to 100 km/hr, t = 6 s

The average acceleration = (27.77 - 0)/6 = 4.63 m/s²

Therefore, the average acceleration of the car is equal to  4.63 m/s².

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3) unit of the following are :

a) force = Newton

b) distance = meter

c) work = Joule

4) 90 J work has been done by her

5) 51 J work was done

6) He have done  \(10^{4}\) J  of work

7) no work is done

8) no work is done

9) 700 J is the work done on the car

10) 10.68 N  force is applied

3 ) unit of the following are :

a) force = Newton

b) distance = meter

c) work = Joule

4 ) work done = force * displacement

                       = 75 * 1.2 = 90 J

5 )  work done = force * displacement  

                        = 15 * 3.4 = 51 J

6 ) work done = force * displacement  

                        = 100 * 100 = \(10^{4}\) J

7) no work is done because no displacement occurred

8)  no work is done because no displacement took place

9) work done = force * displacement

                        = 12.5 * 56 = 700 J

10)  force = work done / displacement

                = 142 / 13.3 = 10.68 N

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Answer:

A Tsunami would occur.

Answer:

Voltage

Explanation:

The term to describe pressure in electricity terms is 'voltage'. It's measured in volts using a voltmeter.

Answer:

x = 3472 [m]

Explanation:

To solve this problem we must use the following expression of kinematics:

\(v_{f}^{2}= v_{i}^{2}+(2*a*x)\\\)

where:

Vi = initial velocity = 0

Vf = final velocity = 300 [km/h]

a = acceleration = 1 [m/s^2]

x = takeoff distance [m]

Note: The initial velocity is equal to zero as avion starts its movement from rest.

Now we have to convert units of kilometers per hour to meters per second, the final velocity.

\(300 [\frac{km}{h}]*[\frac{1h}{3600s} ]*\frac{1000m}{1km} \\= 83.33 [\frac{m}{s} ]\)

(83.33)^2 = 0 + (2*1*x)

2*x = 6943.88

x = 3472 [m]

Although she wasn't truly listening to what was being said, she would occasionally say "Yeah" or "Okay" to appease her mother. This destructive listening behaviour is known as: Defensive listening, first

Interrupting, eavesdropping, being confrontational, egotistical, defensive, selective, insensitive, and pseudo-listening are some examples of these poor listening techniques.

Pseudolistening– having to pretend to pay any attention and did appear considerate but is not trying to listen to realise or translate the data (audience members may answer back with a smile, mouth, or even a verbal cues appreciation but are dismissing or not planning to attend).

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Answer:

16 m/s^2

Explanation:

acceleration tangential = (v^2)/r

a=400/25

a=16 m/s^2

Side note: next time, be more specific when asking about acceleration in circular motion. There's more than one type! Example:

angular acceleration=acceleration tangential/r

angular acc.=16/25

angular acc.=0.64 rad/s^2

We are given that a block is sliding up an incline. A diagram of the situation is given as follows:

To determine the acceleration we will add the forces parallel to the ramp, we will call this direction the x-direction:

Where:

Now we determine the x-component of the weight by using the trigonometric function sine:

Now we multiply both sides by "mg":

Now we substitute this value in the sum of forces:

Now, to determine the force of friction we will use the following formula:

Where:

To determine the normal force we add the forces in the direction perpendicular to the ramp, we will call this direction the y-direction:

Where:

Now, since there is no movement in the y-direction, the sum of forces is equal to zero:

Now we solve for the normal force:

Now we calculate the y-component of the weight using the trigonometric function cosine:

Now we substitute this value in the expression for the friction force:

Now we substitute this value in the sum of forces in the x-direction:

Now, since the sum of forces is equivalent to the product of the mass by the acceleration we have:

We can take "-mg" as a common factor on the left side:

We can cancel out the mass:

Now we substitue the values:

Now we solve the operations:

Therefore, the acceleration is -7.8 meters per second squared.

Answer:

60°

Explanation:

It will be equilateral triangle, you can prove with the cosine theorem.

1)P^2=P^2+P^2 - 2×P×P× cos A

2) cos A= P^2 / 2× P^2 = 1/2

cos A = 1/2

A = 60°

If you wrote this question right,it will be solved like this :)

Answer:

R = 19.36  ohms

Explanation:

Given that,

The power of an electric motor, P = 2500 Watts

The voltage of the circuit, V = 220 V

We need to find the resistance of the motor. We can find it as follows :

\(P=\dfrac{V^2}{R}\\\\R=\dfrac{V^2}{P}\\\\R=\dfrac{(220)^2}{2500}\\R=19.36\ \Omega\)

So, the resistance of the motor is 19.36  ohms.

The momentum carried by Santa of mass 120 kg is 48 kgm/s.

Momentum is the product of mass and acceleration.

To calculate the momentum carried by Santa, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the momentum is 48 kgm/s.

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The resultant force that water exerts on the overhang sea wall along abc is 179 kN.

Force is a physical quantity that describes the interaction between two objects, such as a push or a pull. It is defined as any influence that causes an object to undergo a change in motion or deformation. Force is a vector quantity, meaning that it has both magnitude (size or strength) and direction.

Component that is horizontal. Because AB is horizontal, there is no horizontal component. The horizontal component of BC's force is.

(Fbc)h =γwhˉA=(1000kg/m3)(9.81m/s2)(1.5m+21(2m))(2m(2m))=98.1(103)N.

Component that is vertical. The weight of the water contained in blocks Abefa and Bcdeb (shown shaded in Fig. a) is equal to the force on AB and the vertical component of the force on BC. Here,

Aabefa=1.5m(2.5m)=3.75m2and

2Abcdeb=(3.5m)(2m)–4π(2m)2=(7–p)m2. Then,

Fab=γwVabefa=(1000kg/m3)(9.81m/s2)[(3.75m2)(2m)] =73.575(103)N=73.6N (FBC)v=γwVbcdeb=(1000kg/m3)(9.81m/s2)[(7–π)m2(2m)] =75.702(103)N

Therefore,

Fbc=(Fbc)²h2+(Fbc)²v2=√[98.1(10³)N]²+[75.702(10³)N]²=123.91(10³)N=124KN

FR²   =(Fbc)²H2+[Fab+(Fbc)v]²

==[98.1(10³)N]² + [(73.6(10³)N)²+75.702(10³)N²]

=178.6(10³)N = 179 kN.

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If one ball is dropped at rest from a height of h = 65 m.  The acceleration of the two balls is: -9.8 m/s^2 for both balls.

Let's start by finding the time it takes for the two balls to meet. We know that the ball thrown upward starts from rest, so its initial velocity is 0 m/s. We can use the following kinematic equation:

y = v_i*t + (1/2)at^2

where y is the displacement (in this case, it is the distance between the two balls), v_i is the initial velocity, a is the acceleration, and t is the time. We can set y equal to the initial height of the dropped ball, which is h = 65 m. For the ball thrown upward, the initial position is y = 0.

For the dropped ball:

y = h = 65 m

v_i = 0 m/s

For the ball thrown upward:

y = 0

v_i = 0 m/s

Using the given information, we can solve for t:

h = (1/2)at^2

65 m = (1/2)*(-9.8 m/s^2)t^2

t = sqrt(65 m / (1/2(-9.8 m/s^2))) ≈ 3.64 s

So it takes about 3.64 seconds for the two balls to meet.

Now, we can find the acceleration of the two balls. For the dropped ball, the acceleration is simply the acceleration due to gravity, which is -9.8 m/s^2. For the ball thrown upward, the acceleration is also the acceleration due to gravity, but with a negative sign since it is moving in the opposite direction of gravity. Therefore, the acceleration of the two balls is:

a = -9.8 m/s^2 for both balls

This means that both balls experience the same acceleration due to gravity, regardless of their initial velocities.

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Use the kinetic energy formula:

KE = 1/2 m v^2

m= mass = 49 kg

v = speed

and the potential energy formula:

PE = m g h

g = 9.8 N

h= height = 6 m

PE = 49 x 9.8 x 6 = 2,881.2 J

Since PE = KE

2,881.2 J = KE

2,881.2 = 1/2 x 49 x v^2

2,881.2 = 24.5 x v^2

2,881.2 / 24.5 = v^2

117.6 = v^2

√117.6 = v

v= 10.84 m/s

Answer:

1.75 m/s

Explanation:

k = Spring constant = 490 N/m

m = Mass of object = 5.8 kg

x = Displacement of spring = 0.19 m

v = Speed of object at the equilibrium position

The potential energy of the spring will balance the kinetic energy of the mass

\(\dfrac{1}{2}kx^2=\dfrac{1}{2}mv^2\\\Rightarrow v=\sqrt{\dfrac{kx^2}{m}}\\\Rightarrow v=\sqrt{\dfrac{490\times 0.19^2}{5.8}}\\\Rightarrow v=1.74637\ \text{m/s}\)

The speed of the mass as it returns to the equilibrium position is 1.75 m/s.

Answer: A literature review consists of an overview, a summary, and an evaluation (“critique”) of the current state of knowledge about a specific area of research.

Explanation: