An underwater sound source emits waves of frequency 30 kHz in all directions. How does the intensity of the waves (in Watts/m2) vary with distance r from the source?


a) 1/r^3
b) 1/r^2
c) 1/r
d) None of above

Answer:

hiii

Explanation:

but u have already given the answer along with the question

Answer:

Gravity is a contact force between objects in the universe

Explanation:

Gravity doesn't repel objects, it pulls them closer.

Answer:

m = 27752.7 [kg]

Explanation:

To solve this problem we must first use the following equation of kinematics.

\(v_{f}=v_{o}+a*t\)

where:

Vf = final velocity = 240 [km/h]

Vo =  initial velocity = 0

a = acceleration [m/s²]

t = time = 2 [s]

But first we must convert the speed from kilometers per hour to meters per second.

\(240[\frac{km}{h} ]*(\frac{1h}{3600s} )*(\frac{1000m}{1km} )=66.67[m/s]\)

Now replacing:

\(66.67 = 0 +a*2\\a = 33.33 [m/s^{2} ]\)

Now using Newton's second law which is defined as the product of mass by acceleration we can determine the mass of the jet.

∑F = m*a

\(925000=m*33.33\\m = 925000/33.33\\m = 27752.7 [kg]\)

Answer:

The elevator is stationary

The volume of the vegetable oil is  0.00003998 m³.

The density of vegetable oil,

ρ = 913 kg/m³

The mass of vegetable oil,

m = 0.0365 kg

To find: The volume of the vegetable oil, V Solution: The density of any substance is defined as the mass of the substance per unit volume.

The formula for density is:

ρ = m/V

where, ρ is the density of the substancem is the mass of the substance V is the volume of the substance We can rearrange the above formula to find the volume of the substance:

V = m/ρSubstituting the given values of mass and density in the above formula,

We get:

V = 0.0365 kg / 913 kg/m³ = 0.00003998 m³ (approx)

Therefore, the volume of the vegetable oil is approximately 0.00003998 m³.

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Answer:

9000m

Explanation:

Given parameters:

Time  = 30s

Acceleration  = 20m/s²  

Unknown:

Distance traveled  = ?

Solution:

To solve this problem, we use one of the kinematics equation.

     S  = ut + \(\frac{1}{2}\)at²  

u is the initial velocity = 0m/s

t is the time taken

a is the acceleration

           S  = (0 x 30) + ( \(\frac{1}{2}\) x 20 x 30² ) = 9000m

The trip takes 48 minutes longer in heavy traffic than it does under normal conditions.

The distance between San Diego and Los Angeles is the same regardless of the speed you are traveling. Let's convert the average speed to the same units:

105 km/h = 65 mi/h

73.0 km/h = 45 mi/h

The time it takes to drive from San Diego to Los Angeles at the normal speed is:

t₁ = 1 hour + 50 minutes = 1.83 hours

The time it takes to drive from San Diego to Los Angeles in heavy traffic is: t₂ = d/v₂  

where d is the distance and v₂ is the speed in heavy traffic. Since the distance is the same, we can set t₁ equal to t₂:

t₂ = d/v₂ = t₁

Solving for d, we get:

d = v₁t₁ = (105 km/h)(1.83 h) = 191.85 km

Now we can find the time it takes to drive the same distance at a speed of 73.0 km/h:

t₃ = d/v₃ = (191.85 km)/(73.0 km/h) = 2.63 hours

The difference in time between the two trips is:

Δt = t₃ - t₁ = 2.63 h - 1.83 h = 0.80 h = 48 minutes

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--The given question is incorrect, the correct question is

"You normally drive on the freeway between San Diego and Los Angeles at an average speed of 105 km/h (65 mi/h), and the trip takes 1 h and 50 min. On a Friday afternoon, however, heavy traffic slows you down and you drive the same distance at an average speed of only 73.0 km/h (45 mi/h ). How much longer does the trip take?"

Answer:

\(\huge\boxed{25.5mi}\)

Explanation:

Simply multiply the rate by the time

17 * 1.5 = 25.5 mi

Hope it helps :) and let me know if you want me to elaborate.

Answer:

\(a=4.8m/s^2\)

Explanation:

Hello,

In this case, since the acceleration in terms of position is defined as its second derivative:

\(a=\frac{d^2x(t)}{dt^2}=\frac{d^2}{dt^2}(2.9+8.8t+2.4t^2)\)

The purpose here is derive x(t) twice as follows:

\(a=\frac{d^2x(t)}{dt^2}=\frac{d}{dt}(8.8+2*2.4*t)\\ \\a=4.8m/s^2\)

Thus, the acceleration turns out 4.8 meters per squared seconds.

Best regards.

Explanation:

Weight of an object is shows the force of gravity acting on it. It is calculated mass times acceleration due to gravity.

lb is the unit of avoirdupois weight. It means that 12 lb shows weight.

gram, kg is the unit of mass. It means 0.34 g and 120 kg shows mass of an object.

m and cm are the units of length. It means 0.34 m and 411 cm shows the length of the object.

N is the unit of weight.

Hence, 12.0 lb and 1600 kN are acceptable representations of weight.

Answer:

a) 8 m/s²

b) 100 m

Explanation:

The acceleration of the train can be calculated as

Where vf is the final velocity, vi is the initial velocity, and t is the time. Replacing vf = 10 m/s, vi = 0 m/s, and t = 5 s, we get:

Then, the distance traveled can be calculated using the following equation

Replacing vi = 0 m/s, t = 5 s, and a = 8 m/s², we get

Therefore, the distance traveled by train was 100 m.

Answer:

\(39000\ \text{kg m/s}\)

West

Explanation:

m = Mass of car = \(1.3\times 10^{3}\ \text{kg}\)

t = Time = 9 seconds

u = Initial velocity = 30 m/s

v = Final velocity = 0

Impulse is given by

\(J=m(v-u)\\\Rightarrow J=1.3\times 10^3(0-30)\\\Rightarrow J=-39000\ \text{kg m/s}\)

The magnitude of the total impulse applied to the car to bring it to rest is \(39000\ \text{kg m/s}\).

The direction is towards west as the sign is negative.

Answer:

the net electric charge of the iron atom is 2.24 × 10⁻¹⁸ C

Explanation:

Given the data in the question;

we know that neural iron atoms should have same number of protons and electrons i.e 26 and 26 but in the sun's atmosphere, many of their electrons stripped away.

so; we have 26 protons and 12 electrons, meaning ( 26-12=14) 14 electrons have been stripped away.

when we loss electron, we gain positive charge

so, the Net charge of the iron atom of with 26 protons and 12 electrons will be;

q = 26 ( proton charge) + 12( electron charge )

we know that; a singular proton has a charge of 1.6×10⁻¹⁹ C

protons carry negative charge while electrons carry negative

we substitute

q = 26 ( 1.6×10⁻¹⁹ ) + 12( -1.6×10⁻¹⁹  )

q = 2.24 × 10⁻¹⁸ C

Therefore, the net electric charge of the iron atom is 2.24 × 10⁻¹⁸ C

Given what we know, we can confirm that the bands indicate that the canyon was carved due to erosion caused by moving water.

The bands are the result of sediments being deposited as the canyon was being formed. These sediments are deposited by the running water that carves the canyon. This results in horizontal bands that can tell us much about the history of the canyon as well as the river that formed it.

Therefore, we can confirm that the bands indicate that the canyon was carved due to erosion caused by moving water.

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Answer: Static electricity is the build up of an electrical charge on the surface of an object. It's called "static" because the charges remain in one area rather than moving or "flowing" to another area.

Explanation:

hi brainly user! ૮₍ ˃ ⤙ ˂ ₎ა

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\(\large \bold {ANSWER}\)

Explanation: ΔL = τ(average) * Δt
Change in angular momentum = average torque * change in time

solve for average torque for each objects
τ(average) = ΔL / Δt

Object y average torque
τy = ΔLy / Δt = 20 / 5 = 4
τy = 4

Object x average torque
τx = ΔLx / Δt = 10 / 5 = 2
τx = 2

Relates τy and τx
2τx = τy

Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey.

The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. The precise relation between torquey and torquex is torquey = 2 * torquex.

To relate torquey to torquex, we are able to use the concept of angular momentum and torque. Angular momentum is described because the manufactured from the moment of inertia and angular velocity:

L = I * ω

Differentiating this equation with an appreciation of time, we get:

dL/dt = d(I * ω)/dt

Using the product rule of differentiation, we've got:

dL/dt = I * dω/dt + ω * dI/dt

Now, we realize that torque (τ) is described because of the charge of the exchange of angular momentum:

τ = dL/dt

Substituting the expression for dL/dt in terms of angular velocity and second of inertia:

τ = I * dω/dt + ω * dI/dt

Let's denote the common price of torque for item X as torquex. Since object X has a moment of inertia I0, we can write:

torquex = I0 * dω/dt + ω * dI0/dt

Now, let's consider item Y. It has a moment of inertia 2I0. Using the identical expression, we will write:

torquey = (2I0) * dω/dt + ω * d(2I0)/dt

torquey = 2I0 * dω/dt + ω * (2 * dI0/dt)

torquey = 2I0 * dω/dt + 2ω * dI0/dt

Comparing the expressions for torquex and torquey, we will see that:

torquey = 2 * torquex

Therefore, the precise relation between torquey and torquex is;

torquey = 2 * torquex.

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The correct question is;

"Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey. The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. Which of the following expressions correctly relates torquey to torquex?"

False. A Method for Calculating the Spring Constant of Atomic Force Microscopy Cantilevers with a Nonrectangular Cross Section is not a valid statement.

This is because the spring constant is not affected by the shape of the cantilever, but is instead determined by the material used in its construction, the number of coils in its spring, the wire diameter of its spring, and the amount of tension placed on the spring. Therefore, the statement is incorrect and cannot be used to calculate the spring constant of atomic force microscopy cantilevers with a nonrectangular cross section.

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The kinetic energy of particle B at the instant when the particles are 3.0 m apart is 4.32 J.

The total energy of the system is conserved. The initial energy of the system is the electrostatic potential energy, which is given by:

U = k × (Q₁ × Q₂) / r

where:

U = potential energy in joules

k = Coulomb's constant (8.988 x 10⁹ N m²/C²)

Q₁ and Q₂ = charges in coulombs

r = distance between the charges in meters

In this case:

U = 8.988 x 10⁹ N m²/C² × (12 C × 5 Q) / (1.0 m) = 5.375 x 10⁻⁷ J

The final energy of the system is the kinetic energy of particle B. The kinetic energy is given by:

KE = 1/2 × m × v²

where:

KE = kinetic energy in joules

m = mass in kilograms

v = velocity in meters per second

Solve for the velocity of particle B using the conservation of energy equation:

KE = U

Substituting the expressions for KE and U gives:

1/2 × m × v² = 5.375 x 10⁻⁷ J

Solving for v gives:

v = √(2 × 5.375 x 10⁻⁷ J / m)

= 1.53 m/s

The kinetic energy of particle B is then:

KE = 1/2 × m × v²

= 1/2 × m × (1.53 m/s)²

= 4.32 J

Therefore, the kinetic energy of particle B at the instant when the particles are 3.0 m apart is 4.32 J.

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when Force (N) is 10.0 Length (m) is 0.60

when Force (N) is 8.0 Length (m) is 0.40

when Force (N) is 4.0 Length (m) is 0.20

when Force (N) is 4.0 Length (m) is 0.20

when Force (N) is 2.0 Length (m) is 0.10

chatgpt

49. To find the length of a pendulum that has a period of 2.3 seconds on the Moon, where the gravitational acceleration (g) is 1.6 N/kg, we can use the formula:

Period (T) = 2π√(Length (L) / g)

Substituting the given values:

2.3 = 2π√(L / 1.6)

To solve for L, we can rearrange the formula:

L = (2.3 / (2π))^2 * 1.6

L ≈ 0.781 meters (or 78.1 centimeters)

So, the pendulum must be approximately 0.781 meters (or 78.1 centimeters) long to have a period of 2.3 seconds on the Moon.

50. Ranking Task:

To rank the pendulums according to their periods, we need to consider both the length and mass of each pendulum.

Ranking from least to greatest period:

1. A: 10 cm long, mass = 0.25 kg

2. C: 20 cm long, mass = 0.25 kg

3. B: 10 cm long, mass = 0.35 kg

There is a tie between pendulums A and C, as they have the same length but different masses.

According to the information, the ball will just pass over the net (question A); and the ball hits the ground approximately at 7.04 meters from the player and after a time of flight of approximately 1.31 seconds (question B).

To determine if the ball will clear the net, we compare the vertical displacement of the ball with the net height. The ball's initial height is 1.1 meters, and it reaches its highest point during flight. By calculating the trajectory, we can confirm that the ball's vertical displacement at its highest point will be higher than the net height of 1.81 meters, ensuring it clears the net.

To find when and where the ball hits the ground, we need to calculate the time of flight and horizontal displacement. Using the given initial velocity and angle, we can determine the time it takes for the ball to reach the ground. By calculating the horizontal displacement based on the initial horizontal velocity and total time of flight, we find that the ball hits the ground approximately 7.04 meters from the player. The time of flight is approximately 1.31 seconds. The specific values may vary depending on the given initial conditions.

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Answer:

W = 12 J

Explanation:

Given that,

Force, F = 4 N

The object moves in rightward direction for a distance of 3 m.

Work done on the object is given by :

\(W=F\times d\\\\=4\ N\times 3\ m\\\\=12\ J\)

So, the work done on the object is 12 J.

Answer:

I'm not sure but I think its aluminum

Answer:

a) a = 3.09 m/s²

b) aₓ = 2.60 m/s²

Explanation:

a) The magnitude of her acceleration can be calculated using the following equation:

\( V_{f}^{2} = V_{0}^{2} + 2ad \)

Where:

\(V_{f}\): is the final speed = 8.89 m/s

\(V_{0}\): is the initial speed = 0 (since she starts from rest)

a: is the acceleration

d: is the distance = 12.8 m    

\( a = \frac{V_{f}^{2}}{2d} = \frac{(8.89 m/s)^{2}}{2*12.8 m} = 3.09 m/s^{2} \)

Therefore, the magnitude of her acceleration is 3.09 m/s².              

b) The component of her acceleration that is parallel to the ground is given by:

\( a_{x} = a*cos(\theta) \)

Where:

θ: is the angle respect to the ground = 32.6 °

\( a_{x} = 3.09 m/s^{2}*cos(32.6) = 2.60 m/s^{2} \)

Hence, the component of her acceleration that is parallel to the ground is 2.60 m/s².

I hope it helps you!

A skateboarder, starting from rest, rolls down a 12.8-m ramp the magnitude of the skateboarder's acceleration is approximately 3.07 \(m/s^2\), the component of her acceleration that is parallel to the ground is approximately 1.66 \(m/s^2\).

(a) The following kinematic equation can be used to calculate the skateboarder's acceleration:

\(v^2 = u^2 + 2as\)

\((8.89)^2 = (0)^2 + 2a(12.8)\)

78.72 = 25.6a

a = 78.72 / 25.6

a = 3.07 \(m/s^2\)

(b) Trigonometry can be used to calculate the part of her acceleration that is parallel to the ground. We are aware that the ramp's angle with the ground is 32.6°.

\(a_{parallel }= a * sin(\theta)\)

Plugging in the values:

\(a_{parallel\) = 3.07  \(m/s^2\)* sin(32.6°)

\(a_{parallel\)≈ 1.66  \(m/s^2\)

Therefore, the component of her acceleration that is parallel to the ground is approximately 1.66  \(m/s^2\).

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According to the information we can infer that the forces are PULLING forces, OPPOSITE FORCES, EQUAL, forces DO balance each other, the resultant force is ZERO, and there IS NO motion.

According to the information of the image, we can conclude that the forces shown above are PULLING forces because they involve pulling a rope on each side. Also, the forces shown above are OPPOSITE FORCES because they act in opposite directions, pulling the rope towards different sides.

On the other hand, the forces are EQUAL in magnitude because each side exerts a force of 1000 Newtons. Additionally, the forces DO balance each other because they have the same magnitude and act in opposite directions. The individuals on each side are exerting equal forces, resulting in a balanced system.

Finally, the resultant force is ZERO because the forces are equal in magnitude and act in opposite directions. The combined effect of the forces is no net force or resultant force and there IS NO motion because the forces are balanced, resulting in a net force of zero. In a balanced system, the objects will remain at rest or in a state of uniform motion.

Note: This question is incomplete. Here is the complete information:
Attached image

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Answer:

29

Explanation:

You can put 29 signifigant figures into a value

(hope it was helpful)

Given

mass (m) = 1 kg

velocity (v) = 10 m/s

kinetic energy ( ke) = ?

,we know

K.E =1/2 m v²

= 1/2 * 1 * 10²

= 100/2

=50 joule

hope it helps :)

The kinetic energy of a 1 kg pie if it is thrown at 10 m/s is 50 joule.

Energy due to motion of the body  is kinetic energy. Whether an object is moving vertically or horizontally, it contains kinetic energy.

Kinetic energy can take many different forms, including vibrational (the energy resulting from vibrational motion), rotational (the energy resulting from rotational motion), and translational energy (the energy due to motion from one location to another). To keep things straight-forward, we'll concentrate on translational kinetic energy.

An object's mass (m) and speed (v) are two factors that affect how much translational kinetic energy it has (from this point on, the term "kinetic energy" will refer to translational kinetic energy). The kinetic energy (K.E) of an object is denoted by the equation below.

K.E = (1÷2)×m×v²

where m = mass of object

v = speed of object

Given that in question  1 kg pie is thrown at  the velocity of 10 m/s,

K.E = (1÷2)×1×(10)²

K.E = 50 joule

So the kinetic energy of the pie is 50 joule.

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Answer:

200j

Explanation:

see in the figure

the answer is in the figure and above