An unidentified gas a density of 2. 40 g/L when measured at 45°C and 820 torr pressure. Calculate

the molar mass of this gas

The d-block elements are transition metals. They still exhibit the properties expected of metals just like the main group elements  even though they are not as reactive as the main group metals.

The periodic table is divided into blocks; s- block, p- block, d - block and f - block.

The s - block and p - block elements are called the main group elements. The elements of the d - block has some unique properties due to the presence of partially filled d - orbitals.

However, the d - block elements are metals and also undergo many of the reactions expected of metals. They still displace hydrogen from dilute acid and react with water(just a few of them) under appropriate conditions to liberate hydrogen gas etc.

However, the first row transition elements are more reactive than the second and third row which tends to be more noble.

Generally, the d - block elements are far less reactive than s - block and p - block metals.

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Answer:

The d-block elements are transition metals. They still exhibit the expected properties of metals but aren't as reactive .

The d-block is not part of the main group elements: s and p blocks. The d-block has unique properties due to the presence of partially filled d-orbitals.

Answer:

Explanation:

I don't know how you want the conversion done. I use dimensional analysis.

Jane

12 miles / hour [1.6 km/1 mile][1000 m/1 km][1 hour / 3600 sec]

12 * [1.6 * 3600 / 1000  m/s] = 69.12 m/s

5.33 m/s      This answer is a bit shorter than using 5280 feet.

Using 5280 feet

12 miles / hour [5280 ft/1 mile] [1 m/3.281 feet] * [1 hr/3600 sec]

12 * 5280 / (3.281 * 3600)

12 *. 4470

5.36

Jack

330 feet / minute [ 1 meter / 3.281 feet] [1 minute / 60 seconds]

330 * 1/(3.281 * 60)

330 * 1/(196.86)

1.676 m/s

She's going faster than he is, no matter which method is used to do the calculation

As a result, 0.231liters of the 0.150M potassium iodide solution would be required to thoroughly react with the supplied lead(II) nitrate solution.

When a solution of potassium iodide is introduced to a solution of lead nitrate in a test tube, a yellowish solid precipitates.

Lead iodide is a whitish solid. Along with lead iodide, potassium nitrate is generated. This is a reaction with two displacements.

The reaction between lead nitrate [Pb(NO3)2] and potassium iodide (Kl) results in the creation of potassium nitrate (KNO3) and a yellow precipitate of lead iodide (PbI2).

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The law of diminishing marginal rate of substitution indicates that the rate at which one input can be substituted for another decreases as the quantity of one input increases, leading to isoquants being bent toward the origin.

In other words, as the quantity of one good increases, the individual is willing to sacrifice fewer units of the other good to obtain an additional unit of the first good. This reflects a diminishing rate of substitution between the two goods.

The reason why the law of diminishing marginal rate of substitution suggests that isoquants must be bent toward the origin is rooted in the concept of diminishing marginal utility. As more units of a particular input (e.g., labor or capital) are added while holding other inputs constant, the additional output gained from each additional unit of the input will decrease. This diminishing marginal productivity leads to a decreasing MRS.

When isoquants (which represent different combinations of inputs that produce the same level of output) are bent toward the origin, it reflects the fact that as more of one input is used, the amount of the other input that needs to be substituted decreases. This bending signifies the diminishing MRS and captures the idea that a larger quantity of one input can be substituted for a smaller quantity of the other input to maintain the same level of output.

Overall, the law of diminishing marginal rate of substitution indicates that the rate at which one input can be substituted for another decreases as the quantity of one input increases, leading to isoquants being bent toward the origin.

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Answer:

\(\frac{140}{57}La -------->\frac{140}{58} Ce +\frac{0}{-1} \beta\)

Explanation:

Beta emission occurs when a neutron is converted to a proton, an electron and a neutrino. This phenomenon reduces the neutron-proton ratio(N/P).

When a beta emission occurs, the mass number of the daughter nucleus is the same as that of the parent nucleus while the atomic number of the daughter nucleus increases by one unit.

We can see this explanation above in the reaction described in the answer section.

Explanation:

1L is 1.3 g so 600L is 780 g

1kg= 1000g so

780 g = 0.78kg

I GUESS

Mass in kilograms of liquid air required = 0.78 kg

Given that

1 Litre of liquid air contains 1.3 grams of oxygen ( air )

Determine the amount of liquid air in Kg

volume of air given = 600 L

mass of liquid air required = x

1 litre = 1.3 grams

600 L =  x

∴ x ( mass of liquid air ) = 1.3 * 600

                                       = 780 g  = 0.78 kg

Hence we can conclude that Mass in kilograms of liquid air required = 0.78 kg

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The treatment for magnesium poisoning involves slowly injecting 10mL of calcium gluconate (2.2mmol of calcium in a 10mL vial; formerly known as 10% solution) into the vein over the course of 10 minutes.

What are the symptoms and treatment for magnesium sulfate toxicity?

Early symptoms of magnesium toxicity include nausea, feeling heated, flushing, somnolence, double vision, slurred speech, and weakness. The first sign of magnesium toxicity is typically the loss of patellar reflexes, which happens with serum magnesium levels of 9 mg/dl to 12 mg/dl.

What symptoms indicate toxicity from magnesium sulfate?

Keep an eye out for the warning signs and symptoms of magnesium sulfate toxicity, such as hypotension, areflexia (loss of DTRs), respiratory depression and arrest, oliguria, shortness of breath, chest pains, slurred speech, hypothermia, confusion, and circulatory collapse.

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The gold-colored ring has a mass of 18.9 grams and a volume of 1.12mL. Is not the ring pure gold as its density is 16.87 centimeter cube.

The density of any object is defined as the total amount of volume occupied by the mass of an object and the unit is centimeter cube.

             Density = mass of substance / volume of substance

Substituting the value in formula

           Density = 18.9 /  1.12mL

                        =  16.87 centimeter cube.

The density of pure gold must be 19  centimeter cube.

Therefore , The gold-colored ring Is not the ring pure gold as its density is 16.87 centimeter cube.

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Lead exposure can cause all of the following except for A. Skin burns. Hence option A. is the correct answer.

Lead poisoning happens when lead builds up in the body over some months or years. Small amounts of lead also can cause serious health problems. Children younger than 6 years are vulnerable to lead poisoning, which affect mental and physical development.

Lead can damage the central nervous system, cardiovascular system, reproductive system, hematological system, and also kidneys. When it is  absorbed into the body in high enough doses, lead can be toxic. In addition to this , workers' lead exposure can harm their children's development.

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Note: The question given on the portal is incomplete. Here is the complete question.

Question: Lead exposure can cause all of the following except:

A. Skin burns

B. Kidney damage

C. Brain damage

D. Sterility

Answer:

"it can help us explain the universe" or "it can help us study how cells in the body function"

Explanation:

you choose which one you want but their still both technicly right

Answer:

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Answer:

No Se Espanol

Explanation:

When a sample of 89.56 g  NH4NO3 dissolves in 42.05 g of water, the temperature changes from 28.69 c to 7.8 c, the heat flow (q) in this case is approximately -11,165 Joules.

To calculate the heat flow (q) in this case, we can use the equation:

q = m × C × ΔT

where:

q is the heat flow

m is the mass of the solution (water + NH4NO3)

C is the specific heat capacity of the solution

ΔT is the change in temperature of the solution

First, we need to find the mass of the solution by adding the mass of the water and the mass of NH4NO3:

Mass of solution = Mass of water + Mass of NH4NO3

= 42.05 g + 89.56 g

= 131.61 g

Next, we calculate the change in temperature:

ΔT = Final temperature - Initial temperature

= 7.8°C - 28.69°C

= -20.89°C

Now, we need to determine the specific heat capacity of the solution. Since the specific heat capacity of water is commonly used, we can assume it is approximately 4.18 J/g·°C.

Plugging the values into the equation, we can calculate the heat flow (q):

q = 131.61 g × 4.18 J/g·°C × (-20.89°C)

≈ -11,165 J

Therefore, the heat flow (q) in this case is approximately -11,165 Joules.

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Answer:

covalent

Explanation:

Explanation:

Calamine solution contains zinc carbonate and is basic in nature. When applied in the skin, it reacts with the acid, and neutralizes its effect, thus giving relief.

If \(HA^{0}\) for a particular reaction is positive, it indicates that the reaction is endothermic, meaning that heat energy is absorbed from the surroundings. This leads to a net increase in the enthalpy of the system.

This can also be understood in terms of bond strength - if the bonds formed in the product(s) were weaker than the bonds broken in the starting material, energy would be released, and \(HA^{0}\) would be negative. However, since the bonds formed in the product(s) are stronger than the bonds broken in the starting material, more energy is required to break these bonds and form the new product(s). Therefore, statements a) and b) are correct, while c) and d) are incorrect in this context.

In other words, if ΔH° for a particular reaction is positive, the correct statements that describe the reaction are: a) The reaction is endothermic. A positive ΔH° value indicates that the reaction absorbs energy from its surroundings, making it an endothermic reaction. b) There is a net increase in the enthalpy of the system. A positive ΔH° means that the enthalpy of the products is greater than the enthalpy of the reactants, resulting in a net increase in the system's enthalpy. c) More energy is needed to break bonds than is released by forming bonds. In a reaction with a positive ΔH°, the energy required to break the bonds in the reactants is higher than the energy released when new bonds are formed in the products. This leads to an overall energy absorption in the reaction.

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The correct definition of oxidation in terms of oxygen, electron and hydrogen is added, lost , lost, (Row B).

An oxidation reaction is a reaction in which the oxidation number if the reacting species increases in a positive direction.

Therefore, the correct definition of oxidation in terms of oxygen, electron and hydrogen is added, lost , lost, (Row B).

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Answer:

The combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy

Explanation:

Given;

CH₄ + 2O₂ → CO₂ + 2H₂O, ΔH = -890 kJ/mol

From the combustion reaction above, it can be observed that;

1 mole of methane (CH₄) released 890 kilojoules of energy.

Now, we convert 59.7 grams of methane to moles

CH₄ = 12 + (1x4) = 16 g/mol

59.7 g of CH₄ \(= \frac{59.7}{16} = 3.73125 \ moles\)

1 mole of methane (CH₄) released 890 kilojoules of energy

3.73125 moles of methane (CH₄) will release ?

= 3.73125 moles x  -890 kJ/mol

= -3320.81 kJ

Therefore, the combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy

Answer:

The combustion will release -3,321 KJ/mol of energy

Explanation:

Answer:

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Answer:

1.23 x 10²⁴ formula units K₂S

Explanation:

To find the amount of formula units in potassium sulfide, you need to (1) convert grams to moles (via the molar mass) and then (2) convert moles to formula units (via Avogadro's number). The conversions/ratios need to be arranged in a particular way that allows for the cancellation of units. Units are cancelled when then are located both in the numerator and denominator somewhere in the math. The final answer should have 3 sig figs because the given value (225 grams) has 3 sig figs.

Avogadro's number:

6.02 x 10²³ formula units = 1 mole

Molar Mass of K₂S:

110.26 g/mol

225 g K₂S           1 mole              6.02 x 10²³ units
----------------  x  -----------------  x  ----------------------------  = 1.23 x 10²⁴ formula units
                           110.26 g                    1 mole

Answer:

6.022 x \(10^{22}\) molecules

Explanation:

One mole of any substance has 6.022x \(10^{23}\) particles.

Mr of water: 16 + 2 = 18 g

moles of water given: 1.8/18 = 0.1 moles

Using ratio:

moles   :   molecules

   1        :    6.022x \(10^{23}\)

 0.1      :          X

X = 0.1 x (6.022x \(10^{23}\) )

X = 6.022 x \(10^{22}\)

Answer:

Explanation:

4,5 diethyl-2 fluoro-3-methylheptanal

Answer: Each element on the periodic table is listed in a box with its atomic symbol and atomic number. The element's full name and atomic mass is also sometimes indicated. The image below shows a typical entry for the element calcium. The number above the atomic symbol represents the atomic number.

Answer:

f. nanogram

b. microgram

d. milligram

a. centigram

c. kilogram

e. megagram

Explanation:

f. nanogram = 10^-9

b. microgram = 10^-6

d. milligram = 10^-3

a. centigram = 10^-2

c. kilogram = 10^3

e. megagram = 10^6

The order of the units from smallest to largest.

f. nanogram

b. microgram

d. milligram

a. centigram

c. kilogram

SI units are those units that are used to measure different measurements. The SI units mean the Internation system of measurement.

A nanogram is the smallest unit of measurement. It is used to measure a very minuter amount of an object. Its value is 10⁻⁹. After this, there is a microgram, which is sued to measure micro things. Its value is 10⁻₆

Milligram, then centigram, and then there is the kilogram. The kilogram is the largest unit of measurement in the SI unit. These units are used to measure the mass of a substance.

Thus, the correct order is

f. nanogram

b. microgram

d. milligram

a. centigram

c. kilogram

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Answer:

Two moles.

Explanation:

Sulphuric (sulfuric) acid \(\rm H_2SO_4\) is a diprotic acid. When one mole of \(\rm H_2SO_4\) molecules dissolve in water, two moles of \(\rm H^{+}\) ions would be produced.

\(\rm H_2SO_4 \to 2\, H^{+} + {SO_4}^{2-}\).

On the other hand, sodium hydroxide \(\rm NaOH\) is a monoprotic base. When one mole of \(\rm NaOH\) formula units dissolve in water, only one mole of hydroxide ions \(\rm OH^{-}\) would be produced.

\(\rm NaOH \to Na^{+} + OH^{-}\).

Note that \(\rm H^{+}\) and \(\rm OH^{-}\) react at a one-to-one ratio:

\(\rm H^{+} + OH^{-} \to H_2O\).

As a result, it would take \(2\; \rm mol\) of \(\rm OH^{-}\) to react with the \(\rm 2\; mol\) of \(\rm H^{+}\) that was released when \(1\; \rm mol\) of \(\rm H_2SO_4\) is dissolved in water. Since one mole of \(\rm NaOH\) formula units could produce only one mole of \(\rm OH^{-}\), it would take \(\rm 2\; mol\) of \(\rm NaOH\) formula units to produce that \(2\; \rm mol\) of \(\rm OH^{-}\) for reacting with \(1\; \rm mol\) of \(\rm H_2SO_4\).

The amount of heat created or absorbed during a reaction that takes place under a constant amount of pressure is measured by the enthalpy change.

The change in enthalpy that occurs as one mole of a compound is created from its component parts is known as the "heat of formation." The total amount of energy that should be added to or released during a chemical reaction is known as the heat of reaction.

By deducting the total of the standard enthalpies of formation of the reactants from the sum of the standard enthalpies of formation of the reactants and products, one can determine the standard enthalpy change of formation.

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Answer:

Explanation:

Molecular weight of Al: 27

Molecular weight of O: 16

Percentage composition of Al by weight in Al2O3

= (27*2) / (27*2 + 16*3)

= 0.5294

In 200 grams of Al2O3, there are

= 200*0.5294

= 105.88 grams of Al

77.18 grams of Al was produced in the experiment.

Percent yield for the experiment

= product mass / reactant mass * 100%

= 77.18 / 105.88 * 100%

= 72.89%

To find the molecular formula of this compound, what we're going to do is to follow up the steps:

Step 1: Pass all the percentages to grams. This is, just to change the unit:

Step 2: Divide each mass by respective molar mass to obtain the moles of each element:

Step 3: Divide all the amounts in moles through by smaller value obtained:

These are the subscripts for C and H respectively. Thus our empirical formula is CH2. We're asked to find the molecular formula so, we could use the fact that the compound has a molecular weight of 112 g/mol. If we analyze, CH2 has a molecular weight of 14g/mol, so:

Step 4: We're going to divide the molecular weight of the compound with molecular formula through by the molecular weight of the compound with empirical formula:

This means that our molecular formula will be eight times the subscripts of the empirical formula. Therefore, the answer is:

Answer:

The reducing agent donates electron to the oxidizing agent and gets oxidized itself

Explanation:

In an oxidation-reduction reaction, also known as REDOX reaction, one of the reactants is called OXIDIZING AGENT while the other is called REDUCING AGENT. The reducing agent is called so because it reduces another substance in the reaction.

It reduces another atom/ion by donating electrons to that atom, hence, getting oxidized itself in the process. For example, in the following reaction:

H2 + F2 → 2HF

Fluorine is getting oxidized from -2 to 0 by donating electrons to H and reducing it from +2 to 0.

Answer:

Reduces another atom

Explanation:

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Answer:

500/100=5m

W=F*D

W=20*5=100Nm

Explanation:

The work done in Nm on the object is 100 Nm

Since A force of 20N acts on an object. It causes a displacement of 500 cm in the direction of the force.

Since the displacement is in cm

So, in meters, it should be like

= 500 / 100

= 5 m

Now we know that

Work done = force * displacement

= 20N * 5

= 100 Nm

hence, The work done in Nm on the object is 100 Nm

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