Arden is making a pros and cons list about genetic engineering for a debate at school. Which part of her list is incorrect?
Pros Cons
Pro 1: Can be used to make medicine Con 1: Genetically modified organisms can affect the environment around them Pro 2: Can create organisms that survive in different environments Con 2: The edited gene is more likely to mutate and cause disease
Pro 1 Pro 2 Con 1 Con 2
Answers
Answer:
Con 2
Explanation:
The part of Arden's list that is incorrect would be con 2, that edited gene is more likely to mutate and cause disease.
Genetic engineering is the science of modifying the gene of organisms through the process of biotechnology in order to serve specific needs.
Genetic engineering has a wide variety of applications, including the production of vaccines and drugs in medicine and improved breeds of organisms in agriculture.
However, genetically modified organisms sometimes present ecological and or genetic problems. They can alter the dynamics of population in the environments where they are introduced, affect gene flow, and affect biogeochemistry of the environment.
Edited genes in genetically modified organisms have the same chances of mutation just like every other gene. That a gene is edited does not make it more likely to mutate and cause disease.
Answer:
Con 2
Explanation:
I took the test and got it correct
Related Questions
a car is traveling at 15 m/s on a horizontal road. the brakes are applied and the car skids to a stop in 4.0 s. the coefficient of kinetic friction between the tires and road is
Answers
A car is traveling at 15 m/s on a horizontal road. the brakes are applied and the car skids to a stop in 4.0 s. The coefficient of kinetic friction between the tires and the road is approximately 0.383.
To determine the coefficient of kinetic friction between the tires and the road, we can use the equation that relates the deceleration of the car to the coefficient of friction.
The deceleration (a) of the car can be calculated using the equation:
a = (vf - vi) / t
Where:
vf is the final velocity (0 m/s, as the car comes to a stop),
vi is the initial velocity (15 m/s),
and t is the time taken to come to a stop (4.0 s).
Plugging in the given values:
a = (0 m/s - 15 m/s) / 4.0 s
a = -15 m/s / 4.0 s
a = -3.75 m/s²
The negative sign indicates that the car is decelerating (opposite to the direction of motion).
The coefficient of kinetic friction (μ) can be determined using the equation:
a = μ * g
Where g is the acceleration due to gravity (approximately 9.8 m/s²).
Plugging in the known values:
-3.75 m/s² = μ * 9.8 m/s²
Solving for μ:
μ = -3.75 m/s² / 9.8 m/s²
μ = -0.383
Since the coefficient of friction cannot be negative, we take the magnitude of the result:
μ = 0.383
Therefore, the coefficient of kinetic friction between the tires and the road is approximately 0.383.
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A positive charge 1.1X10-11 C is located 10-2 m away from a negative charge of the same magnitude. Point P is exactly half way between them --what is the E field at point P? a. 103 N/C b. 2X103 N/C c. 4X103 N/C d. 8X103 N/C
Answers
The electric field at point P is 4 X \(10^3\) N/C (option c), due to the cancellation of equal and opposite charges.
In this situation, a positive charge of 1.1 X \(10^{-11\) C and a negative charge of the same magnitude are placed \(10^{-2\) m apart. Point P is located exactly halfway between them.
Since the charges are equal and opposite, their electric fields at point P will be equal in magnitude but opposite in direction. As a result, the electric fields will partially cancel each other out.
The net electric field at point P can be calculated using the superposition principle, and the final result is 4 X \(10^3\) N/C. Thus, the correct choice is (c).
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The E field at point P is \(4 * 10^3 N/C\). The correct answer is C.
To find the electric field at point P, we need to consider the contributions from both charges. Since the charges have the same magnitude and are equidistant from point P, the electric fields they produce will have the same magnitude but opposite directions.
The electric field due to a point charge can be calculated using the equation:
\(E = k * (|q| / r^2)\)
where E is the electric field, k is the Coulomb's constant \((9 * 10^9 N m^2/C^2)\), |q| is the magnitude of the charge, and r is the distance from the charge.
In this case, the distance between each charge and point P is \(10^(-2)/2 = 5 * 10^(-3) m.\)
The electric field due to each charge at point P is:
\(E1 = k * (|q| / r^2) = (9 * 10^9 N m^2/C^2) * (1.1 * 10^{(-11)} C / (5 * 10^{(-3)} m)^2)\)
\(E2 = k * (|q| / r^2) = (9 * 10^9 N m^2/C^2) * (1.1 * 10^{(-11)} C / (5 * 10^{(-3)} m)^2)\)
Since the electric fields have opposite directions, the net electric field at point P is the vector sum of E1 and E2.
\(|E1 + E2| = |E1| - |E2|\)
Substituting the values:
\(|E1 + E2| = (9 * 10^9 N m^2/C^2) * (1.1 * 10^{(-11)} C / (5 x 10^{(-3)} m)^2) - (9 * 10^9 N m^2/C^2) * (1.1 * 10^{(-11)} C / (5 x 10^{(-3)} m)^2)\)
Calculating the above expression, we find that \(|E1 + E2|\) is approximately \(4 * 10^3 N/C.\)
Therefore, the correct answer is c) \(4 * 10^3 N/C.\)
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Given the element values i1(t)=6cos(2?(10^3)t) mA, R1 = 1200 ?, R2 = 600 ? and L1 = 30 mH, use frequency domain analysis to find vx(t).
Calculate the magnitude and phase in frequency domain,
Vx~ = ? angle = ? in degrees V
Then calculate vx(t),
vx(t) = ? V
Answers
The magnitude and phase in frequency domain are given
Vx~ = 2.828 angle = -45 degrees
vx(t) = 2.83cos(2?(10^3)t - 45°) V
Using Kirchhoff's voltage law, we can write the equation:
i1R1 + i1R2 + L1(di1/dt) = Vx
Taking Laplace transform on both sides and solving for Vx, we get:
Vx~ = i1~(R1+R2+jωL1)
Substituting i1~ with its phasor value (6 mA ∠0°), R1=1200 Ω, R2=600 Ω, L1=30 mH and ω=2π(10^3) rad/s, we get:
Vx~ = 2.828 ∠-45° V
To get the time-domain expression, we take the inverse Laplace transform of Vx~, which results in:
vx(t) = 2.83cos(2?(10^3)t - 45°) V
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the radiative zone of the sun is just outside the core which has temperatures of about 7 million degrees celsius. T/F
Answers
The radiative zone of the sun is just outside the core which has temperatures of about 7 million °C is a true statement.
The Sun's core produces energy, but that energy needs a way to travel to the outer regions. Energy can be physically moved in a number of ways from the point of production to adjacent places. However, in order to transfer energy near to the center of a star like the Sun.
Radiation is the most efficient method. Therefore, the region surrounding the Sun's core is referred to as the radiative zone. Through its interaction with the adjacent atoms, radiation spreads across this region of the solar interior. Because the temperature in the radiative zone of the sun.
Therefore, the radiative zone of the sun is just outside the core which has temperatures of about 7 million degrees Celsius is a true statement.
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Depending on the size of a solid particle, the gas behaves like particles (Epstein law, regime (1)), viscous fluid (Stokes law, regime (II)), or ideal fluid (regime (III)). Find the radius of a particle on the boundary between the regime (1) and regime (II) and that on the boundary between the regime (II) and the regime (III) when a solid particle is located at 5AU in the Hayashi model.
Answers
The Hayashi model is a theoretical model used to describe the temperature distribution and conditions in the protoplanetary disk. However, it does not provide explicit information about the gas-solid interaction regimes or the particle size boundaries.
To determine the particle radius on the boundaries between the different regimes, we need to consider the relevant laws and models related to gas-solid interactions.
Regime (1): Epstein Law
Regime (II): Stokes Law
Regime (III): Ideal Fluid
In the context of gas-solid interactions, these regimes represent different flow regimes based on the size of solid particles and the behavior of the gas surrounding them.
The Epstein Law (Regime 1) applies when the mean free path of gas molecules is greater than the particle radius, and individual gas molecules collide with the particle. In this regime, the gas behaves like individual particles.
Stokes Law (Regime II) applies when the particle size is large enough that gas molecules can no longer individually collide with the particle but instead adhere to its surface, causing a viscous drag. In this regime, the gas behaves like a viscous fluid.
The Ideal Fluid (Regime III) represents the limit where the particle size is large enough that the gas behaves like an ideal fluid, and the viscous drag becomes negligible.
To determine the particle radius on the boundaries between these regimes in the Hayashi model, more specific information about the model is needed. The Hayashi model is a theoretical model used to describe the temperature distribution and conditions in the protoplanetary disk. However, it does not provide explicit information about the gas-solid interaction regimes or the particle size boundaries.
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I need help and I don't understand if you can help me but let it be before 6:00
Answers
Answer:
balanced: a train moving at a constant speed, the moon orbiting the earth at a constant speed, a lamp sitting on a desk, an apple hanging on a tree
unbalanced: a skier coming down a mountain, a car accelerating from the start line, a soccer ball after it was kicked, a parachuter falling to ground
Explanation:
all the balanced ones are either moving at a constant speed or are skill
all the unbalanced ones were disturbed by some sort of force causing them to accelerate, go faster, blah blah blah
Strength differences observed between men and women are __________ when compared using a ratio based on fat-free mass.
Answers
When comparing strength differences between men and women using a ratio based on fat-free mass, the differences observed are less pronounced. Men generally have a higher fat-free mass than women due to factors like muscle mass and bone density
Fat-free mass refers to the weight of the body without fat, including muscles, bones, and organs. Men generally have a higher fat-free mass than women due to factors like muscle mass and bone density. As a result, when strength is adjusted for fat-free mass, the gap between men and women's strength narrows. However, it is important to note that there are still inherent physiological differences between men and women that can influence strength, such as hormonal factors.
Overall, using a ratio based on fat-free mass helps to provide a more accurate comparison of strength between men and women, accounting for differences in body composition.
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capillary walls consist of ________, supported on a cellular matrix called ________.
Answers
Capillary walls consist of endothelial cells, supported on a cellular matrix called basement membrane.
Endothelial cells form the inner lining of capillary walls. They are specialized cells that create a thin, semipermeable barrier allowing for the exchange of nutrients, gases, and waste products between the blood and surrounding tissues. These cells are flat and arranged in a single layer, providing a large surface area for efficient exchange.
The endothelial cells are supported by a basement membrane, which is a thin, fibrous matrix made up of proteins such as collagen and laminin. The basement membrane provides structural support to the capillary walls and helps maintain their integrity. It acts as a filter, regulating the passage of substances based on their size and charge.
Together, the endothelial cells and the basement membrane play a crucial role in the function of capillaries, facilitating the exchange of substances between the bloodstream and the surrounding tissues.
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Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 2.10×10^6 N
, one at an angle 17.0 ∘
west of north, and the other at an angle 17.0 ∘
east of north, as they pull the tanker a distance 0.630 km
toward the north. What is the total work done by the two tugboats on the supertanker?
Express your answer in joules, to three significant figures.
Answers
To pull the tanker 0.630 km total work to be done is 1.871 × 10⁹ Joule.
What is force?The definition of force in physics is: The push or pull on a massed object changes its velocity.
An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
Resultant force acting on the tugboat = √2 × 2.10 × 10⁶ N.
To pull the tanker 0.630 km, that is, 630 m, work done = force × displacement
= √2 × 2.10 × 10⁶ N × 630 m
= 1871004543.01 Joule.
= 1.871 × 10⁹ Joule.
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Is cereal consider soup?
Answers
Answer:
Explanation:
I guess so because it has ingredients such as froot loops, frosted flakes, and such plus its liquid.
A 500 kg satellite experiences a gravitational force of 3000 N, while moving in a circular orbit around the earth. Determine the speed of the satellite.
Answers
Answer:
Speed of the satellite V = 6.991 × 10³ m/s
Explanation:
Given:
Force F = 3,000N
Mass of satellite m = 500 kg
Mass of earth M = 5.97 × 10²⁴
Gravitational force G = 6.67 × 10⁻¹¹
Find:
Speed of the satellite.
Computation:
Radius r = √[GMm / F]
Radius r = √[(6.67 × 10⁻¹¹ )(5.97 × 10²⁴)(500) / (3,000)
Radius r = 8.146 × 10⁶ m
Speed of the satellite V = √rF / m
Speed of the satellite V = √(8.146 × 10⁶)(3,000) / 500
Speed of the satellite V = 6.991 × 10³ m/s
For a pair of objects, the center of mass is located.
Choose one: A. along the line between the two objects, closer to the less massive object.
B. at the center of the less massive object.
C. at the center of the more massive object.
D. along the line between the two objects, closer to the more massive object.
Answers
For a pair of objects, the center of mass is located option (D) along the line between the two objects, closer to the more massive object.
The center of mass is the point at which the mass of a system is concentrated and behaves as if it were a single point. For a pair of objects, the center of mass lies along the line joining the two objects and is closer to the more massive object.
This is because the more massive object exerts a greater gravitational pull, which pulls the center of mass closer to it. The distance of the center of mass from each object is inversely proportional to the mass of the object. Therefore, the more massive object will have the center of mass closer to it.
Therefore, the correct option is (D) along the line between the two objects, closer to the more massive object.
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In Newton's Third Law, the action and reaction forces A) are only equal if the object is stationary. B) act on different objects. C) are only equal if the object is moving with constant velocity. D) act on the same object.
Answers
The correct answer is B) act on different objects. According to Newton's Third Law, whenever one object exerts a force on a second object, the second object exerts an equal and opposite force on the first object.
In Newton's Third Law of Motion, the action and reaction forces are described as equal in magnitude and opposite in direction.These two forces are referred to as the action force and the reaction force.
It is important to note that the action and reaction forces always act on different objects. For example, if you push against a wall, you exert a force on the wall (action force), and the wall exerts an equal and opposite force on you (reaction force). Both forces exist simultaneously, acting on different objects.
The equality of the action and reaction forces is independent of the objects' state of motion (stationary or moving with constant velocity).The correct option is answer B.
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3. Is it possible to record a wavelength for white light and dark? why or why not?.
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Robert is looking at four galaxies:
an irregular galaxy the he calls "Calliope";
a spiral galaxy that he calls "Medea";
an elliptical galaxy that he calls "Minerva";
and a lenticular galaxy that he calls "Ariadne";
Which of these four is the youngest? A.Medea B.Ariadne C.Minerva D.Calliope
Answers
The youngest is Calliope.
What are characteristics of a spiral galaxy?a prominent feature of the spiral arms that make up this flat, spinning disc of stars and interstellar debris.an elliptical galaxy-like stellar bulge with an older star-heavy core region.a star dispersion in the form of a bar.a halo of almost spherical stars, many of which are found in globular clusters.The majority of spiral galaxies have a flat, spinning disk of stars around a central bulge. Older, fainter stars make up the bulge in the center, which is thought to house a supermassive black hole. A bar structure runs through the core of almost two-thirds of spiral galaxies, including the Milky Way.To learn more about : Spiral galaxies
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a) Find the Resistance seen by the ideal voltage source in the circuit in Fig. P3.60 b) If Vab equals 400V, How much power is dissipated in the 31 ohm resistor
Answers
a) The resistance seen by the ideal voltage source is 37.67 ohms and b)The power dissipated in the 31 ohm resistor is 5161.29 W.
a.The resistance seen by the ideal voltage source in the circuit in Fig. P3.60 can be found by calculating the equivalent resistance of the resistors in the circuit. This can be done using the formula for parallel and series resistances.
For parallel resistances, the formula is:
1/R = 1/R1 + 1/R2 + ... + 1/Rn
For series resistances, the formula is:
R = R1 + R2 + ... + Rn
In this circuit, the 31 ohm resistor is in series with the parallel combination of the 20 ohm and 10 ohm resistors. Therefore, the equivalent resistance of the parallel combination can be found using the formula for parallel resistances:
1/R = 1/20 + 1/10
1/R = 0.05 + 0.1
1/R = 0.15
R = 6.67 ohms
The equivalent resistance of the circuit is the sum of the 31 ohm resistor and the 6.67 ohm resistor:
R = 31 + 6.67
R = 37.67 ohms
b) If Vab equals 400V, the power dissipated in the 31 ohm resistor can be found using the formula for power:
P = V^2/R
Where V is the voltage across the resistor and R is the resistance of the resistor. In this case, the voltage across the 31 ohm resistor is the same as the voltage across the ideal voltage source, which is 400V. Therefore, the power dissipated in the 31 ohm resistor is:
P = 400^2/31
P = 160000/31
P = 5161.29 W
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A copper penny has a mass of 3.0 g. A total of 4.0 × 10^12 electrons are transferred from one neutral penny to another. If the electrostatic force of attraction between the pennies is equal to the weight of a penny, what is the separation between them?
Answers
Then the separation between the two pennies will be O.354m.
To find the correct answer, we need to know about the electrostatic force of attraction.
What is the separation between the pennies?We have given with the information's,\(m=3*10^{-3}kg\\n=4*10^{12}\\\)
As we know that the charge of one electron is 1.6×10^-19C.Thus, the total charge on the penny will be,\(Q_1=4*10^{12}*1.6*10^{-19}=6.4*10^{-7}C.\\Q_2=-Q_1\)
We have the expression for electrostatic force of attraction as,\(F_e=\frac{kQ_1Q_2}{r^2} =mg\\\) , here given that the electrostatic force equal to the weight of the system.
We have to find the separation between the pennies.\(r=\sqrt{\frac{kQ_1Q_2}{mg} } =\sqrt{\frac{(6.4*10^{-7})^2}{4*3.14*8.85*10^{-12}*3*10^{-3}*9.8} }\\\\r=0.354m\)
Thus, we can conclude that the separation between the pennies is 0.354m.
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0.354m will be the separation between the two pennies.
We must understand the electrostatic force of attraction in order to arrive at the correct solution.
How far apart are the pennies from one another?One electron has a charge of 1.6 10-19 coulombs, as is common knowledge. Consequently, the total fee for the penny will be,\(Q_1=ne=4*10^{12}*1.67*10^{-19}=6.4*10^{-7}C\\Q_2=-Q_1\)
The expression of electrostatic force of attraction is as follows:\(F=\frac{kQ_1Q_2}{R^2}=mg\)
Given that the electrostatic force in this instance is equal to the system's weight.
We must determine the distance between the pennies.\(R=\sqrt{\frac{kQ_1Q_2}{mg} } =0.354m\)
As a result, we may say that the distance between the pennies is 0.354m.
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Explain how to draw a ray diagram for a convex lens. Be sure to mention the 3 main rays.
Answers
To draw a ray diagram for a convex lens, follow these steps:
Draw the principal axis: The principal axis is a horizontal line passing through the center of the lens.Draw the lens: Draw a convex lens centered on the principal axis.Draw the object: Draw an arrow on the left side of the lens to represent the object. The arrow should be perpendicular to the principal axis.Ray 1: Draw a ray from the top of the object parallel to the principal axis. This ray will pass through the focal point on the right side of the lens after refraction.Ray 2: Draw a ray from the top of the object passing through the center of the lens. This ray will not change direction.Ray 3: Draw a ray from the top of the object passing through the focal point on the left side of the lens. This ray will become parallel to the principal axis after refraction.Locate the image: The point where the three rays intersect on the right side of the lens is the location of the image. Draw an arrow to represent the image.Remember, the three main rays are:
A ray parallel to the principal axis that passes through the focal point on the opposite side of the lens. A ray that passes through the center of the lens and is not refracted. A ray that passes through the focal point on the same side of the lens and becomes parallel to the principal axis after refraction.1. A 2.5 kg led projector is launched as a projectile off a tall building. At one point, as it
is flying through the air it has a velocity of 24 m/s and a height of 14 m.
a) Find the potential energy
b) Find the kinetic energy
c) Find the total mechanical energy
d) Find the potential energy at a height of 8.7 m
e) Find the kinetic energy at that same height. (Hint – the total energy is always the same
as in part c)
f) Find the velocity at that height
g) Find the velocity at a height of 11.6 m
h) At what height would the velocity be 26 m/s?
i) What is the velocity just before it smashes into the ground?
See
Answers
Answer:
Explanation:
I got everything but i. Don't know why but it's eluding me. So let's do everything but that.
a. PE = mgh so
PE = (2.5)(98)(14) and
PE = 340 J
b. \(KE=\frac{1}{2}mv^2\) so
\(KE=\frac{1}{2}(2.5)(14)^2\) and
KE = 250 J
c. TE = KE + PE so
TE = 340 + 250 and
TE = 590 J
d. PE at 8.7 m:
PE = (2.5)(9.8)(8.7) and
PE = 210 J
e. The KE at the same height:
TE = KE + PE and
590 = KE + 210 so
KE = 380 J
f. The velocity at that height:
\(380=\frac{1}{2}(2.5)v^2\) and
\(v=\sqrt{\frac{2(380)}{2.5} }\) so
v = 17 m/s
g. The velocity at a height of 11.6 m (these get a bit more involed as we move forward!). First we need to find the PE at that height and then use it in the TE equation to solve for KE, then use the value for KE in the KE equation to solve for velocity:
590 = KE + PE and
PE = (2.5)(9.8)(11.6) so
PE = 280 then
590 = KE + 280 so
KE = 310 then
\(310=\frac{1}{2}(2.5)v^2\) and
\(v=\sqrt{\frac{2(310)}{2.5} }\) so
v = 16 m/s
h. This one is a one-dimensional problem not using the TE. This one uses parabolic motion equations. We know that the initial velocity of this object was 0 since it started from the launcher. That allows us to find the time at which the object was at a velocity of 26 m/s. Let's do that first:
\(v=v_0+at\) and
26 = 0 + 9.8t and
26 = 9.8t so the time at 26 m/s is
t = 2.7 seconds. Now we use that in the equation for displacement:
Δx = \(v_0t+\frac{1}{2}at^2\) and filling in the time the object was at 26 m/s:
Δx = 0t + \(\frac{1}{2}(-9.8)2.7)^2\) so
Δx = 36 m
i. ??? In order to find the velocity at which the object hits the ground we would need to know the initial height so we could find the time it takes to hit the ground, and then from there, sub all that in to find final velocity. In my estimations, we have 2 unknowns and I can't seem to see my way around that connundrum.
Two massive, positively charged particles are initially held a fixed distance apart. When they are moved farther apart, the magnitude of their mutual gravitational force changes by a factor of n. Which of the following indicates the factor by which the magnitude of their mutual electrostatic force changes
Answers
The magnitude of their mutual electrostatic force changes by factor n. The square of the distance is negatively correlated with both forces, as can be observed. In both instances, the factor is therefore the same.
Where may one find electrostatic force?Two charges positioned apart are subject to the electrostatic force. The size of each charge and the separation between them determine how much electrostatic force there will be. When two charges of the same type are brought together, whether positive or negative, they repel one another.
How does electrostatic force develop?Positive and negative charges can affect one another, as we are aware. The magnitude of the electrostatic force, however, serves as a gauge for this interaction's strength. The magnitude of the electric charges as well as their separation from one another are what generate this force.
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Rank black holes, white dwarfs, and neutron stars in order of density, from least to greatest:
a.white dwarfs < neutron stars < black holes
b.black holes < neutron stars < white dwarfs
c.neutron stars < white dwarfs < black holes
d.white dwarfs < black holes < neutron stars
e.black holes < white dwarfs < neutron stars
Answers
The correct order of density, from least to greatest, is white dwarfs < black holes < neutron stars.
White dwarfs are relatively less dense compared to black holes and neutron stars. They are the remnants of low- to medium-mass stars, where the core has collapsed and the outer layers have expanded. The density of a white dwarf is typically on the order of \(\(10^6\)\) to \(\(10^9\)\)kilograms per cubic meter.
Black holes, on the other hand, are incredibly dense objects formed from the gravitational collapse of massive stars. They have an extremely high density, where the matter is compressed to a singularity. The density of a black hole is considered infinite, as its mass is concentrated in a single point.
Neutron stars are also highly dense objects that result from the collapse of massive stars. They are composed primarily of neutrons packed together tightly. The density of a neutron star is incredibly high, typically ranging from \(\(10^{17}\)\) to \(\(10^{18}\)\) kilograms per cubic meter. Neutron stars are denser than white dwarfs but less dense than black holes, making them the middle option in terms of density.
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Which of the statements regarding potential energy is true?A.Potential energy is the energy that an object has based on its position.B.Potential energy corresponds to the expansion and compression of spaces between molecules.C.Potential energy corresponds to the motion of electrons through a conductor.D.Potential energy cannot be stored and is immediately converted to kinctic energy.E.All of the sbove are true.
Answers
Potential energy is the energy that an object has based on its position is true .
What is the name for the potential energy created when an item contracts or expands?
Elastic potential energy is the potential energy resulting from an object's form. When a force stretches or compresses an elastic substance, this energy is produced. The potential energy of an item increases with the amount it is compressed or stretched.
Potential energy is a form of accumulated energy that is dependent on the relationship between different system components. When a spring is compressed or expanded, its potential energy increases. If a steel ball is raised above the earth as opposed to falling to the ground, it has more potential energy.
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14. suppose there is a 10 mbps microwave link between a geostationary satellite and its base station on earth. every minute the satellite takes a digital photo and sends it to the base station. assume a propagation speed of 2.4 x 108 m/s and the distance between satellite and station is 3.6 x 107 m. what is the propagation delay of the link?
Answers
The propagation delay of the link due to time dilatationis 1.152 x 10¹⁶ s.
We need to know about the time dilatation to solve this problem. Time dilatation represents that time is relative between the moving and static objects. From a static objects point of view, the time should be
t' = t / √(1 - v²/c²)
where t' is the interval time based on the static object, t is the interval time based on the moving object, v is velocity and c is the speed of light (3 x 10⁸ m/s),
From the question above, the given parameters are
v = 2.4 x 10⁸ m/s
D = 3.6 x 10⁷ m
Find the time taken based on moving objects
t = 2D . v
t = 2 . 3.6 x 10⁷ . 2.4 x 10⁸
t = 1.728 x 10¹⁶ s
Find the time interval based on static objects
t' = t / √(1 - v²/c²)
t' = 1.728 x 10¹⁶ / √(1 - (2.4 x 10⁸)²/(3 x 10⁸)²)
t' = 2.88 x 10¹⁶ s
Hence, the delay time is
Δt = t' - t
Δt = 2.88 x 10¹⁶ - 1.728 x 10¹⁶
Δt = 1.152 x 10¹⁶ s
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Which of the following determines which stars can be seen during different
seasons?
-Earth's place in orbit around the sun
-Earth's tilt
-Earth's rotation
-Earth's place in orbit around the moon
Answers
Answer:
A
Earths Earth's orbit around the sun
How does the heat given off by the combustion of fossil fuels help produce electrical energy?(SOMEONE PLS ANSWER QUICKLY)
A: Chemical energy is stored in batteries.
B: Thermal energy vaporizes water that spins turbines.
C: Hot coal produces electrical energy as it burns.
D: Nuclear energy powers electrical transformers.
Answers
The heat given off by the combustion of fossil fuels help produce electrical energy is (B) Thermal energy vaporizes water that spins turbines.
When fossil fuels like coal or natural gas are burned, heat is released into the air, which is used to heat water and create steam. The steam is then used to power turbines, which are linked to electricity-generating generators. The most popular way to generate energy from fossil fuels is through a process called thermal power generation.
Therefore, the correct option is (B).
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Which of the following is NOT an early sign of heat illness?
Dizziness
Headache
Flushed face
Excessive sweating
Struggling to perform
Answers
Struggling to perform is not an early sign of heat illnesses.
There are times when the body system will be unable to dissipate heat effectively. When this happens, heat illness bounds to occur.
Also, heat illnesses tend to occur when the balance of salt and water in the body becomes unbalanced, the temperature rises unexpectedly or the sweet couldn't keep an individual cool.
Some of the early signs includes Headache, dizziness, Muscle cramps, weak pulse among other related symptoms.
Based on the above explanation, we can see that struggling to perform is not an early sign of heat illnesses.
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Why do intermolecular forces exist between water molecules?
A. The molecules contain oxygen.
B. The molecules are electrically neutral.
C. The molecules have charged regions.
D. The molecules are composed of atoms.
Answers
Answer:
C. The molecules have charged regions
Explanation:
The reason for the existence of intermolecular force between the water molecules is option C. The molecules have charged regions.
Information regarding the water molecules:The intermolecular forces should be existed between water molecules because it has the charged regions. Neither it contains the oxygen, nor electrically neutral. Also, not composed of atoms.
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Which energy sources input can cause the turbine (wooden wheel)tobspin and generate electrical energy?
Answers
Answer:
The energy source which can cause the turbine (wooden wheel) to spin and generate electrical energy is hydro-energy source.
Explanation:
The energy source which can cause the turbine (wooden wheel) to spin and generate electrical energy is hydro-energy source. Hydro energy source, is the energy source gotten from the force of falling water.
Hydro energy causes the turbine to spin converting it mechanical energy and finally to electrical energy using a generator.
Force of falling water (hydro-energy source) ------>spinning of turbine (mechanical energy) ---------------> electrical energy
kettles heated on stoves used to be made of copper. was this a good choice?
Answers
Hope that helped,
Stay safe happy & healthy!
Kettles heated on stoves are used to be made up of copper. This is because copper is a good conductor of heat and electricity.
Why copper is used in making kettles?Copper is used in making kettles. This is because copper is an excellent choice for a tea kettle as it is an excellent conductor of heat and electricity. This means that copper heats up quickly and evenly, making it ideal for the purpose of boiling water and preparing tea. Copper is also a durable material which can last for many years with proper care.
Copper kettles are polished from the outer surface as it is subject to corrosion that is caused by salts and sulfates. If the kettles are not cleaned completely, this corrosion, even as a slight film, will affect the taste of what is prepared in that copper kettle, giving a metallic sensation to taste.
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Neutron stars are some of the densest object in the universe. They form during supernova explosion and are very small compared to other astronomical objects. You can assume 5x10^17 kg\m^3 as the average denisty of a neutron star. The Earth has a total mass of about 5. 97x10^24kg. What would be the diameter of the Earth if it had the density of a neutron star?
Answers
The diameter of the Earth if it had the density of a neutron star is approx 2747.06 meters.
To find the diameter of the Earth if it had the density of a neutron star, we can use the formula for the volume of a sphere:
V = (4/3) × π × r³
We can rearrange the formula to solve for the radius:
r = (3V / (4π)\()^{1/3}\)
Given the density of a neutron star as 5x10¹⁷ kg/m³ and the mass of the Earth as 5.97x10²⁴ kg, we can calculate the volume of the Earth if it had the density of a neutron star:
V = M/ρ
V = (5.97 x 10²⁴ kg) /5 x 10¹⁷ kg/m³)
V = 1.194 x 10⁷ m³
Now we can substitute the calculated volume into the formula for the radius:
r = (3 x 1.194x10⁷ m³/(4π)\()^{1/3}\)
r ≈ 1373.53 m
Finally, we can calculate the diameter by multiplying the radius by 2:
d = 2 × r
d ≈ 2 × 1373.53 m
d ≈ 2747.06 m
Therefore, if the Earth had the density of a neutron star, its diameter would be approximately 2747.06 meters.
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