Are there differences in how the size/radius changes over time, when you compare stars with different initial masses?

The resultant displacement of the bullet is  1,418.6 m.

The resultant displacement of the bullet is the total displacement of the bullet obtained by resolving the displacement into x and y component.

the horizontal component of the displacement (x)  = d cosθ

the vertical component of the displacement (y) = d sinθ

where;

For the first displacement;

x = 850 m x cos(0) = 850 m

y = 850 m x sin(0) = 0

For the second displacement;

x = 640 m  x   cos(36) = 517.8 m

y = 640 m  x  sin(36) = 376.2 m

Net horizontal and vertical displacement;

∑x = 850 m  +   517.8 m   = 1,367.8 m

∑y = 376.2 m + 0 = 376.2 m

The resultant displacement of the bullet is calculated as;

d = √(∑x² + ∑y²)

d = √(1,367.8²   +    376.2²)

d = 1,418.6 m

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Answer:

The quantization of energy refers to the fact that at subatomic levels, energy is best thought of as occuring in discreet "packets" called photons. The red and blue photons are therefore "quantized" just as dollar bill denominations are "quantized". Each photon contains a unique amount of discreet energy.

Both statements A and E are true concerning sign conventions for image formation.

A) When the center of curvature of a spherical mirror is on the same side as the reflected light, the radius of curvature is positive; otherwise, it is negative.

E) When the object is on the same side of the reflecting or refracting surface as the incoming light, the object distance is positive; otherwise, it is negative.

A) This sign convention helps distinguish between concave and convex mirrors based on the sign of their radius of curvature. A positive radius of curvature indicates a concave mirror, while a negative radius of curvature indicates a convex mirror.

E)This sign convention is used to determine the sign of the object distance in the equations related to image formation. If the object is on the same side as the incoming light, the object distance is positive. If the object is on the opposite side, the object distance is negative.

The second statement mentioned in the question (regarding magnification) is not correct. The sign of the magnification depends on whether the image is upright or inverted, not the other way around. For an upright image, the magnification is positive, and for an inverted image, the magnification is negative.

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As stars get bigger and brighter, the closer they are to their end of life.

Because they have already used all the elements they can in nuclear fusion. Iron cannot be fused, its too heavy.

The most accurate graph here would be the third one.

Answer:

\(\boxed {\boxed {\sf C. \ 5.0 \ m/s}}\)

Explanation:

Momentum is the product of mass and velocity. The formula is:

\(p=mv\)

The mass of the cart is 2.0 kilograms. The momentum is 10.0 kg m/s. The velocity is unknown.

\(m= 2.0 \ kg \\p= 10.0 \ kg \ m/s\)

Substitute the values into the formula.

\(10.0 \ kg \ m/s= (2.0 \ kg ) v\)

We want to solve for the velocity (v). Therefore we must isolate the variable. It is being multiplied and the inverse of multiplication is division. Divide both sides of the equation by 2.0 kg.

\(\frac { 10.0 \ kg \ m/s}{2.0 \ kg}=\frac{(2.0 \ kg )v}{2.0 \ kg}\)

The kilograms will cancel each other out.

\(\frac { 10.0 \ m/s}{2.0}=v\)

\(5.0 \ m/s=v\)

The velocity is 5 meters per second.

Answer:

Option A nuclear

Explanation:

The rate of electricity production in nuclear power plant is much higher as compared to the rate of electricity generation in gas, wind and solar power plants.

Thus, in case where large amount of electricity is to be produced in a short period then one must rely on nuclear power plants.

Therefore, option A is correct

Answer: Option A- Nuclear power station

Explanation: During a sudden increase in demand, Nuclear power stations can be used easily to supply the needed energy as they have an extremely short start up time. This means that the energy can be supplied in a short period of time.

Answer:

200,000 joules <3

Explanation:
just accept it

Answer:

\(2.00 * 10^5J\)

Explanation:

Make use of your conversion factors:

\(200KJ * \frac{1000J}{1kJ} = 200,000J = 2.00* 10 ^5J\)

Or alternatively make use of your scientific notation. \(kilo = 10^3\)

Therefore \(200kJ = 200*10^3J=2.0*10^2*10^3J = 2.0*10^5J\)

Explanation

23.6/100= 0.236

The soldier's speed initially increases as she falls due to the force of gravity. The speed-time graph for the whole journey will have a positive slope in the beginning, followed by a negative slope, and finally a horizontal line.

However, once the parachute is opened, the air resistance increases and slows down her speed. The final speed at which she lands depends on various factors such as the size and shape of the parachute, the weight of the soldier, and the air resistance. The second stage is when the parachute is opened. During this stage, the soldier's speed decreases gradually due to air resistance. Therefore, the speed-time graph for this stage will be a curved line with a negative slope. The final stage is when the soldier lands on the ground.

To plot a speed-time graph for the whole journey, we need to break down the journey into different stages. The first stage is the free fall without the parachute. During this stage, the soldier's speed increases at a constant rate due to gravity. Therefore, the speed-time graph for this stage will be a straight line with a positive slope.

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The impact parameter (1.67 x \(10^{-14\)m) is greater than the sum οf the radii (9.8 x \(10^{-15\) m), the twο gοld nuclei will nοt cοllide. The distance οf clοsest apprοach that they will reach is the impact parameter, which is apprοximately 1.67 x \(10^{-14\) m.

Tο determine if the twο gοld nuclei will cοllide, we need tο calculate the distance οf clοsest apprοach (alsο knοwn as the impact parameter) and cοmpare it tο the sum οf their radii. If the distance οf clοsest apprοach is less than the sum οf their radii, they will cοllide.

The impact parameter (b) can be calculated using the fοrmula:

b = (Z1 * Z2 * e²) / (4πε₀ * m * v²)

Where:

Z1 and Z2 are the charges οf the twο gοld nuclei (since they are fully iοnized, Z1 = Z2 = 79).

e is the elementary charge (1.602 x \(10^{-19\) C).

ε₀ is the permittivity οf free space (8.854 x \(10^{-12\) C²/Nm²).

m is the mass οf each gοld nucleus (3.27 x \(10^{-25\) kg).

v is the relative velοcity οf the twο nuclei (2 x \(10^7\) m/s).

Plugging in the values, we can calculate the impact parameter:

b = (79 * 79 * (1.602 x \(10^{-19\) C)²) / (4π * 8.854 x \(10^{-12\) C²/Nm² * 3.27 x \(10^{-25\) kg * (2 x \(10^7\) m/s)² )

b ≈ 1.67 x\(10^{-14\) m

The sum οf the radii οf the gοld nuclei is 2 * 4.9 fm = 9.8 fm = 9.8 x \(10^{-15\)m.

Since the impact parameter (1.67 x \(10^{-14\)m) is greater than the sum οf the radii (9.8 x \(10^{-15\) m), the twο gοld nuclei will nοt cοllide. The distance οf clοsest apprοach that they will reach is the impact parameter, which is apprοximately 1.67 x \(10^{-14\) m.

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The option There is a warm layer of air and a cold layer of air closer to the ground. is the correct answer

Answer:

\(force = mass \times acceleration \\ 100 = m \times 5 \\ m = \frac{100}{5} \\ m = 20 \: kg\)

Answer:

??????

Explanation:

Answer:

A gas usually has much lower density than a solid or liquid. ... The molecules or atoms in a gas are much further apart than in a solid or a liquid. Gas molecules or atoms are usually flying around at very high speeds, occasionally bouncing off each other or the walls of the container the gas is in.

Answer:

i) 20-30 kg

Explanation:

The child with the smallest mass range of 20-30 kg will require the smallest force to move his skate board because he/she has a smaller inertia force to overcome. The mass of a body is the measure of the inertia forces of the body. The inertia force makes it difficult for a body at rest to start moving, and a body already in motion to stop moving.

When the children try to move the skateboard, they exert a force that is proportional to the product of their mass and the acceleration with which they start moving. This force must exceed their body's inertia force before they would start moving.

from

F = ma

where F is the force required

m is the mass

a is the acceleration

We can see that for the given mass ranges, the children with the larger mass range will require more force in order to move their skateboard. Consequently, the child with the smallest mass range will require the smallest pushing force to move his skate board.

Given,

The force applied by each person who is pushing the object, F=50 N

The frictional force, f=20 N

The frictional force is the force that opposes the motion of the object. As the people are pushing the object to the right, the frictional force will be directed to the left. And as the force with which people are pushing is greater than the frictional force, the net force will also be directed towards the right.

The net force is given by,

On substituting the known values,

Therefore the net force on the object is 80 N to the right.

Thus the correct answer is option 4.

Answer:

The correct answer is C. Heat always moves from warm to cool, and cold can not move.

Explanation:

Unintentional injuries caused by accidents are the number one killer of children and teenagers.

What causes the majority of adolescent deaths?

A little over half of all adolescent fatalities are caused by accidents. Over one-third of all fatal accidents fall under the category of motor vehicle fatalities, which is the top cause of death for teens. Non-Hispanic black male teens have the highest death rate.

The top causes of mortality for children under 5 years old continue to be congenital anomalies, pre-term birth complications, birth asphyxia, and other infectious diseases like pneumonia, diarrhea, and malaria. According to a recent study, homicide is the top cause of death for children in the United States, and the total rate has grown by 4.3% annually on average.

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Answer:

true

Explanation:

hope it helps

Answer:

Explanation: Thermal energy is transferred through water by conduction, convection, and radiation. Conduction occurs when heat is transferred through direct contact between water molecules with different thermal energy. Convection occurs when warmer water rises to the top and cooler water sinks to the bottom, creating a circular motion that distributes heat. Radiation is the transfer of energy through electromagnetic waves, but it is not significant in water due to poor conduction. The specific mechanism that dominates heat transfer depends on various factors such as temperature gradient, depth, and presence of other materials.

If a charge of 8.15 mC is placed at each corner of a square 0.170 m on a side then the magnitude of Force = 3.48 N. The direction of the force on Charge is along the line between the charge and the center of the square, outward of the center. (option B) is correct.

To determine the magnitude and direction of the force on each charge in the given configuration, we can use Coulomb's law.

Coulomb's law states that the force between two charged objects is given by:

F = k * |q1 * q2| / r^2

where:

F is the magnitude of the force,

k is the Coulomb's constant (k = 8.99 x 10^9 N m^2/C^2),

q1 and q2 are the magnitudes of the charges,

and r is the distance between the charges.

In this case, each charge is 8.15 mC (milliCoulombs), and the distance between them is the side length of the square, which is 0.170 m.

Part A: Magnitude of the force on each charge (F)

Using Coulomb's law:

F = k * |q1 * q2| / r^2

= (8.99 x 10^9 N m^2/C^2) * (8.15 x 10^-3 C)^2 / (0.170 m)^2

Calculating this, we get:

F ≈ 3.48 N

Therefore, the magnitude of the force on each charge is approximately 3.48 N.

Part B: Direction of the force on a charge

The force between two positive charges is repulsive, meaning the charges will push away from each other. Since all charges in this square are positive, the force on each charge will be outward, along the line between the charge and the center of the square, toward the center.

So, the correct option is:

b. along the line between the charge and the center of the square, outward of the center.

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Answer:On a bicycle trail, the city is painting arrows like the one shown below:

Explanation:Upper pointing arrow with height of 11 and length of 9. Rectangular base of arrow has length of 7 and height of 8. All units are in centimeters.

Answer:

C and D

Explanation:

A: is a simple composition

B: is a single replacement

C: C is a double displacement

D: is a double replacement

Answer:

The answers are C abd D.

Explanation:

Here,

A no. Is a combination or analysis chemical reaction.

B no.is a single displacement reaction as cl2 goes to zn.

C no. Is double displacement reaction.

D no. Is a double displacement reaction.

Hope it helps.....

Answer:

the attraction between N and S poles

The resistance of the discman is approximately 45.113 ohms.

To calculate the resistance of the discman, we can use Ohm's Law, which states that resistance (R) is equal to the voltage (V) divided by the current (I). Thus, putting it into application.

According to the question, it's given that:

Current (I) = 0.133 amperes

Voltage (V) = 6 volts

Using Ohm's Law:

R = V / I

Substituting the given values:

R = 6 volts / 0.133 amperes

Calculating the resistance:

R ≈ 45.113 ohms

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Quantization of electron energy states in an atom is a fundamental concept in atomic physics and quantum mechanics. It refers to the discrete and distinct energy levels that an electron can occupy in an atom.

This quantization is better understood in terms of the electron's wave-like nature. The electron behaves like a wave, and its energy is related to the wavelength and frequency of the wave.
The wave-like behavior of the electron was first proposed by Louis de Broglie in 1924, and it was later confirmed by experiments. According to de Broglie's theory, electrons have wave-particle duality, meaning that they can exhibit both wave-like and particle-like behavior. When an electron is confined to an atom, its wave-like behavior leads to the quantization of energy levels.
The quantization of energy levels in an atom arises from the fact that electrons can only occupy specific orbitals around the nucleus. These orbitals have specific energies associated with them, and the electron can only exist in one of these energy levels. When an electron absorbs or emits energy, it must do so in discrete packets or quanta, which correspond to the energy difference between the energy levels.
In summary, the quantization of electron energy states in an atom is a consequence of the wave-like nature of the electron. It arises from the fact that electrons can only occupy specific orbitals around the nucleus, and their energies are quantized in these orbitals. This concept is fundamental to our understanding of atomic structure and has important implications for a wide range of fields, including chemistry, materials science, and electronics.

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To calculate the theoretical steady-state levels of the quantities i1, i2, i3, i4, v1, v2, v3, and v4, we would need the circuit diagram or the specific configuration of the circuit, including the values of the resistors and capacitors involved. Without this information, it is not possible to provide a specific answer.

However, in general, in a circuit containing ideal capacitors and resistors, the steady-state levels of currents and voltages can be determined using Kirchhoff's laws and the equations governing the behavior of capacitors and resistors in the circuit. These equations involve solving systems of linear equations and can vary depending on the circuit's topology and the arrangement of the components.

To calculate the theoretical steady-state levels, one needs to analyze the circuit using the relevant equations and principles of circuit analysis, taking into account the values of the resistors, capacitors, and any applied voltage or current sources in the circuit.

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Answer:

It depends upon SAE No. of oil. (SAE means Society of Automotive Engineers). However, it usually does protect against friction.

Explanation:

If we use very viscous oil, it does not reach all the parts. Very thin oil will flows away easily and gets wasted. Grease is used in such cases. It is generally used around ball-bearing. Normal grease or oil is never used where there is high pressure, high temperature and high speed. Special lubricants are used in such cases. In cold season the oil becomes thick and in hot season it becomes thin. Therefore selection of lubrication also depends on the season. It is always advisable to refer operating manual of the equipment before selecting the lubricant.

The intensity of friction depends on following factors:

i) The area involved in friction.

ii) The pressure applied on the surfaces.

Force = Pressure ´ Area Frictional force will increase, if the area of contact will increase or if pressure applied on the surface increased.

Answer:

The value is  \(a = 20.4 \%\)  

Explanation:

From the question we are told that

    The  acceleration due to gravity of the planet is  \(a = 5.40 \ m/s^ 2\)

     The  percentage  volume of the apparatus submerged in the ocean on earth is \(k = 25.0 \%\)

  Generally the buoyant force acting on the apparatus  is equal to the weight of the apparatus

i.e

     \(\rho_s * V_s * g = m * g\)

Hence the mass of the apparatus  is mathematically represented as

           \(m_s = \rho_s * V_s\)

Here  \(\rho_s\) is the  density of the sea water with a value of  \(\rho_s = 1030 \ kg/m^3\)

        \(V_s\) is the volume of the apparatus submerged

So  

          \(m_s = 1030 * 0.25 V\)  

Here V  is the total  volume of the apparatus

=>        \(m_s = 257.5 V \ kg\)  

  Generally at the new planet the mass of the apparatus is mathematically represented as

      \(m_c = \rho_c * V_c\)

Here  \(\rho_c\) is the  density of the glycerin with a value of  \(\rho_c = 1260 \ kg/m^3\)

Gnerally  \(m_s = m_c\)  

So

         \(257.5 V = 1260 * V_c\)

=>      \(V_c = \frac{257.5V }{ 1260 }\)  

=>      \(V_c = 0.204 \ V\)

Hence the percentage volume of the apparatus which is submerged in glycerin at the new planet is  

           \(a = 0.204 * 100 = 20.4 \%\)  

To know which the following compounds has signals in its 13c nmr spectrum at 25.9 ppm (ch 3), 51.1 ppm (ch), 125.9 ppm (ch), 126.6 ppm (ch), 128.3 ppm (ch), and 148.5 ppm (c) is as follow:

The given carbon NMR spectrum consists of six signals, at the following chemical shifts: 25.9 ppm (CH3), 51.1 ppm (CH), 125.9 ppm (CH), 126.6 ppm (CH), 128.3 ppm (CH), and 148.5 ppm (C).

The possible organic compound that fits with these chemical shifts in carbon NMR spectrum is 2-chloro-4-methylpentane.

This is due to the protons, which are connected to sp3 carbons, have values between 20 and 50 ppm. 2-chloro-4-methylpentane has the following structure:

CH3- 25.9 ppm

CH- 51.1 ppm

CH2- 125.9 ppm

CH- 126.6 ppm

CH- 128.3 ppm

C- 148.5 ppm

Thus, 2-chloro-4-methylpentane has signals in its 13C NMR spectrum at 25.9 ppm (CH3), 51.1 ppm (CH), 125.9 ppm (CH), 126.6 ppm (CH), 128.3 ppm (CH), and 148.5 ppm (C).

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