Here we see that purchasing the computer is a better choice since the total cost of ownership over 15 years is less than the present value of leasing for the same period.
To determine the best option, we need to compare the present value of the cost of leasing with the present value of the cost of purchasing.
Option 1: Lease
Cost per day = $50
Number of days in a year = 365
Annual cost of leasing = $50/day × 365 = $18,250
Present value of annual leasing cost over 15 years at 9% interest rate:
PV(Lease) = $18,250 × [(1 - (1 + 0.09)^-15) / 0.09] = $173,186.76
Option 2: Purchase
Cost of computer = $25,000
Salvage value at the end of 15 years = $4,000
Annual maintenance cost = $2,800
Total cost of ownership over 15 years:
Total Cost = Cost of computer + Present value of annual maintenance cost over 15 years + (Cost - Salvage value) / Present value factor for 15 years
Total Cost = $25,000 + [$2,800 × ((1 - (1 + 0.09)^-15) / 0.09)] + [($25,000 - $4,000) / (1 + 0.09)^15]
Total Cost = $67,739.12
Comparing the two options, we see that purchasing the computer is a better choice since the total cost of ownership over 15 years is less than the present value of leasing for the same period. Therefore, management should choose to purchase the computer.
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While drilling, the mud is being circulated at 2.5 bbls/minute. The surface pressure seen at the pumps is 2,500 psi.
(2 pts) Assuming the well is 7,375 ft deep, estimate is the bottomhole pressure (at 7,375 ft) under these conditions, assuming the mud weight is 11 ppg? (the bottomhole pressure is the sum of a) the surface pressure and b) the pressure caused by the column of mud in the wellbore)
The bottomhole pressure (BHP) at a given depth in a wellbore can be calculated as the sum of the hydrostatic pressure of the mud column and the surface pressure.
The hydrostatic pressure of the mud column can be calculated as:
P_hydrostatic = mud_weight * 0.052 * depth
where mud_weight is the density of the mud in pounds per gallon (ppg), 0.052 is a conversion factor to convert the mud density to psi/ft, and depth is the vertical depth of the well in feet.
In this case, the mud weight is given as 11 ppg and the well depth is 7,375 ft. Therefore, the hydrostatic pressure of the mud column is:
P_hydrostatic = 11 * 0.052 * 7375 = 4,045 psi
The surface pressure is given as 2,500 psi.
Therefore, the bottomhole pressure can be estimated as:
BHP = P_hydrostatic + surface pressure
BHP = 4,045 + 2,500 = 6,545 psi
So the estimated bottomhole pressure at 7,375 ft depth is 6,545 psi.
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What is the difference between digital instruments and decimal scaled instruments to measure
Answer Digital measuring instruments are self-contained devices that automatically present the value of the measured quantity on a digital display. And Decimal Scaled Instruments: Record all digits that you can certainly determine from the scale markings and estimate one more digit. I hope this Helped I´m new to this.
Explanation:
A contractor estimates maintenance costs for a new piece of equipment to be $275 for the first month with a monthly increase of 0.5%. At i = 0.75% per month, what is the present cost of maintenance for the new equipment across 4 years?
The present cost of maintenance for the new equipment across 4 years is $12,266.01.
What is the formula for calculating a growing annuity?The formula for calculating a growing annuity is as follows:
\(\frac{M}{r-g}\) \((1- (\frac{1+g}{1+r} )^N).\)where M = the first payment, g = the growth rate, r = the discount rate, and N = the number of payments.
According to the question,
The first payment is = 275
The growth rate is = 0.5%.
The discount rate is = 0.75%.
The number of payments in 4 years = 4*12 = 48.
Now, put all values in the above equation:
\(\frac{275}{0.75 - 0.5}\) \((1- (\frac{1+0.5}{1+0.75} )^4^8)\) = 12.366.01.
Therefore, the present cost of maintenance for the new equipment across 4 years is $12,266.01.
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What is computer programming
Answer:
Computer programming is where you learn and see how computers work. People do this for a living as a job, if you get really good at it you will soon be able to program/ create a computer.
Explanation:
Hope dis helps! :)
Knowing that the central portion of the link BD has a uniform cross-sectional area of 800 2, determine the magnitude of the load P for which the normal stress in that portion of BD is 50 .
Answer: 50
Explanation:
Q.13 In order to produce maximum starting torque in a split-phase motor, how many degrees out of phase should the start- and run-winding currents be with each other?
Select one:
A. 180°
B. 0°
C. 120°
D. 90°
Answer:
D. 90 degrees.
Explanation:
Torque is a rotational force which moves an object in other direction. There should be 90 degrees out of phase to start, run winding currents with each other. Torque is produced by the rotational motion of an object. The angle of the object must be 90 degrees set in order to create torque.
when analyzing transients in dc-powered circuits, an uncharged capacitor is replaced with [ select ] in the initial stages and with [ select ] in the dc steady-state
When analyzing transients in DC-powered circuits, an uncharged capacitor is replaced with a short circuit in the initial stages and with an open circuit in the DC steady-state.
When analyzing transient behavior in DC-powered circuits, capacitors are often treated as either short circuits or open circuits depending on the stage of the circuit's operation.
Initially, an uncharged capacitor is treated as a short circuit because it presents low impedance to the incoming DC voltage, allowing current to flow and quickly charge up the capacitor to the source voltage.
As the capacitor charges, its impedance decreases, behaving like a short circuit. However, once the capacitor reaches its maximum charge in the steady-state, it behaves as an open circuit, blocking any further DC current from passing through.
Treating the capacitor as an open circuit in the steady-state simplifies the circuit analysis, as it effectively isolates the DC source from the rest of the circuit.
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A quantity of gas occupied a volume of 0. 3m cube at a pressure of 300KN/m square and a temperature of 20 degree Celsius the gas compressed isothermally to a pressure of of 800KN/m square and then expanded adiabatically to it's initial volume
Therefore, the final pressure of the gas is 1.52 MPa (megaPascals).
We can use the ideal gas law to solve this problem:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
First, we need to find the initial number of moles of gas:
n1 = (P1 V1)/(R T1)
= (300 x 10^3 Pa) x (0.3 m^3)/(8.31 J/(mol K) x (20 + 273) K)
= 4.97 mol
where R = 8.31 J/(mol K) is the gas constant.
Next, we can use the fact that the process is isothermal (i.e., at constant temperature) to find the final volume of the gas after it is compressed to a pressure of 800 kN/m^2:
P1 V1 = P2 V2
V2 = (P1 V1)/P2
= (300 x 10^3 Pa) x (0.3 m^3)/(800 x 10^3 Pa)
= 0.1125 m^3
Now we can use the fact that the process is adiabatic (i.e., no heat is exchanged with the surroundings) and that the initial and final volumes are the same to find the final pressure of the gas:
P1 V1^γ = P2 V2^γ
where γ is the adiabatic index (a property of the gas), which depends on the specific gas. For simplicity, we will assume that γ = 1.4, which is a reasonable value for diatomic gases such as nitrogen and oxygen.
P2 = P1 (V1/V2)^γ
= (300 x 10^3 Pa) x (0.3 m^3/0.1125 m^3)^1.4
= 1.52 x 10^6 Pa
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The I26 profile beam is supported and loaded as in the figure. It is required to calculate the vertical movement of the free end and the rotation of the free end.
 
                                                Answer:
...
Explanation:
...
 
What is the impedance of an ideal parallel resonant circuit (no resistance in either branch)?
Answer:
infinite
Explanation:
The impedance of an ideal parallel resonant circuit is infinite at the resonant frequency. The sum of the admittances of the branches of the circuit is zero.
What is usually the strongest part of a unibody
The cost function of Taccol Engineering Limited is given by TC=4Q^3-90Q^2+1000Q+500, where Q measures the number of kilometers of road constructed by the company per year . Suppose tge company is awarded a contract to construct 10000 kilometers of roads in 2022. Show how Taccol Engineering Limited would achieve this target whilst remaining profitable
Taccol Engineering Limited can achieve the target of constructing 10000 kilometers of roads in 2022 by producing at an output level of 125 km per year, which would ensure profitability.
What is the explanation for the above response?To achieve the target of constructing 10000 kilometers of roads in 2022, Taccol Engineering Limited would need to determine the optimal level of output that would ensure profitability. This can be done by finding the level of output where the marginal cost (MC) equals the marginal revenue (MR).
The marginal cost is the derivative of the total cost function with respect to Q. Thus, MC = d(TC)/dQ = 12Q^2 - 180Q + 1000.
The marginal revenue can be approximated as the market price for the construction of a kilometer of road. Assuming a market price of $50, the marginal revenue would be constant at MR = $50.
To maximize profits, Taccol Engineering Limited would need to produce output where MC = MR. Thus, 12Q^2 - 180Q + 1000 = 50, which gives Q = 125 km.
Therefore, Taccol Engineering Limited can achieve the target of constructing 10000 kilometers of roads in 2022 by producing at an output level of 125 km per year, which would ensure profitability.
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I need to solve for d
 
                                                Answer:
it's not included
Explanation:
plz exact ur explain
Answer:
si amor
Explanation:
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when a dielectric is added between two parallel plates, does the capacitance increase, decrease, or remain the same?
The capacitance of two parallel plates increases when a dielectric material is added between them. This is due to the dielectric material's ability to store electric charge and create an electric field between the plates.
The dielectric increases the capacitance because it decreases the electric field, thus allowing more charge to be stored on the plates. The amount of charge stored on the plates is directly proportional to the capacitance of the circuit. Therefore, when a dielectric material is added, the capacitance increases.
To summarise, when a dielectric is added between two parallel plates, the capacitance increases. This is because the dielectric material can store electric charge and decreases the electric field between the plates, thus allowing more charge to be stored and increasing the capacitance of the circuit.
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A horizontal curve of a two-lane undivided highway (12-foot lanes) has a radius of 678 feet to the center line of the roadway. An old building (sight obstruction) is located 30 feet from the edge of the innermost lane. The road is level and the superelevation is 0.06. Please determine the maximum speed for safe vehicle operation on this horizontal curve.
Answer:
maximum speed for safe vehicle operation = 55mph
Explanation:
Given data :
radius ( R ) = 678 ft
old building located ( m )= 30 ft
super elevation = 0.06
Determine the maximum speed for safe vehicle operation
firstly calculate the stopping sight distance
m = R ( 1 - cos \(\frac{28.655*S}{R}\) ) ---- ( 1 )
R = 678
m ( horizontal sightline ) = 30 ft
back to equation 1
30 = 678 ( 1 - cos (28.655 *s / 678 ) )
( 1 - cos (28.655 *s / 678 ) ) = 30 / 678 = 0.044
cos \(\frac{28.65 *s }{678}\) = 1.044
hence ; 28.65 * s = 678 * 0.2956
s = 6.99 ≈ 7 ft
next we will calculate the design speed ( u ) using the formula below
S = 1.47 ut + \(\frac{u^2}{30(\frac{a}{3.2} )-G1}\) ---- ( 2 )
t = reaction time, a = vehicle acceleration, G1 = grade percentage
assuming ; t = 2.5 sec , a = 11.2 ft/sec^2, G1 = 0
back to equation 2
6.99 = 1.47 * u * 2.5 + \(\frac{u^2}{30[(11.2/32.2)-0 ]}\)
3.675 u + 0.0958 u^2 - 6.99 = 0
u ( 3.675 + 0.0958 u ) = 6.99
what's mutual inductance
For one-family dwellings, the service disconnecting means must have a rating of at least ___ amperes, 3-wire.
The rating of the service disconnecting means for a single-family home must be at least 100 amperes, 3-wire.Therefore, 100 amperes is the required minimum rating of service size for a one-family home.
What is the service's required minimum ampere rating?
NEC 230.79 (C) states that the rating of the service disconnecting mechanism for a one-family residence must not be less than 100 amperes, 3-wire.Therefore, 100 amperes is the required minimum rating of service size for a one-family home. In one enclosure, six switches or circuit breakers.Since the 1937 edition of the NEC, the number of switches or sets of circuit breakers that can be utilized as the service disconnecting mechanism to separate a building's premises wiring from the utility provider's conductors can range from one to six. The combined ratings of the circuit breakers, if the disconnecting method consists of more than one switch or circuit breaker, must not be less than the calculated load as established by Art. The 98 amp load for the single-family home will be supplied by a 100 amp electrical service.100 x 83 percent equals 83 amps.The bare minimum service conductor is this one. A revision made to the 2020 NEC mandates that an emergency disconnect be used in accordance with section 230.85.This disconnect is meant to allow emergency personnel to turn off the electricity to the entire house before entering to deal with the situation. Any combination of the following is authorized for the two to six service disconnecting means:separate enclosures, each with a method to disconnect the main service.a main service disconnecting mechanism built inside each panel board enclosure. All primary conductors of transformers that are not grounded must be disconnected using a disconnect.Unless the location of the disconnect is clearly written on the transformer and the disconnect is lockable, as is depicted in the Figure, it must be placed within sight of the transformer.To learn more about ampere rating refer
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Hey everyone!
This question is hard.
What specific fluid goes in the windshield wipers? (I never drove a car before)
And how much to put in fluid ounces? (So you don't blow a car up)
Answer:
What specific fluid goes in the windshield wipers.
Distilled water
How much to put in fluid ounces?
There should be a tiny bit more than 3/4 of the way full.
2 A SQUARE GIVEN
 LENGTH OF DIAGONAL = 70 mm
Answer:
Area of square = 2,450 mm²
Explanation:
Given:
Length of diagonal = 70 mm
Find:
Area of square
Computation:
Area of square = diagonal² / 2
Area of square = 70² / 2
Area of square = 4900 / 2
Area of square = 2,450 mm²
What can firefighters do to reduce the risk to people living in Skyview?
Answer:
The City can grant higher budgets to emergency services like the Fire Department, so a higher budget will allow engineers & scientists to innovate new technology and add more fire stations across the city.
Explanation:
for a brick veneer that bears on the foundation and continues to the top of the building without any intermediate bearing support, the maximum veneer height is limited to
For a brick veneer that bears on the foundation and continues to the top of the building without any intermediate bearing support, the maximum veneer height is limited to 30 ft.
Veneer (English for Furnier) or Verblendschale is a thin, light-transmitting ceramic covering for the teeth that is applied to the dental surface, particularly on front teeth, using specialty adhesive. The use of ceramic veneers often has no health risks, save from rare allergic reactions to the befestification material, as the ceramic material has a very high biocompatibility. Problems only arise with extensively fluoridated dental paste. Additionally, the necessary integration measures raise the possibility of chronic pulmonitis (Zahnmarkentzündung), which the doctor must disclose. Veneers can be used to fix minor dental issues such gaps in the teeth, discoloured teeth, and localized blemishes. Veneers provide teeth's visible surfaces with an improved appearance. Usually, when they are used, old plastic fillers or corner builders are removed.
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Is a dry park check a good way to check ball joints and control arm bushings for looseness? Yes or No?
Answer:yes
Explanation:
Because the
what type of device is used on a distribution transformer to protect the transformer from voltage spikes
Medium Voltage Circuit Breaker
Usually, medium voltage circuit breaker is to protect the transformer from voltage spikes on a distribution transformer.
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abdulla hired granite construction to build an addition onto his home. granite construction dug the foundation but then abandoned the project. granite construction has substantially performed as they started the job, and is entitled to receive the full contract price minus the value of the defects.
The provided case is false since abdulla did not commission Granite Construction to build an addition to his house. Rock Construction dug the structure, but later abandoned the project. With the exception of the estimated defects, Stone Construction is eligible to receive the full contract amount.
What is full contract amount?The total sum that is obligated under this Agreement for any payments made by the State to the Contractor for the completion of the Work in accordance with the Contract Documents is referred to as the "Contract Amount." The lifetime worth of a contract is referred to by the term total contract value, which is also known as contract value. TCV gives organisations the ability to accurately assess the annual contract value (your company's annual contract value) and the cost of your customer acquisition initiatives. Knowing the worth of your contract gives you the ability to create a successful plan that will ultimately help your business. In this article, we'll explain what TCV is, how to calculate it, and other helpful hints and suggestions for using it.
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Anyone help me please ?
 
                                                Answer:
I can help but I need to know what it looking for
Find the first five terms of the sequence defined by an=6an-1
Answer:
The first five terms of the given geometric sequence are
8,40,200,1000,5000
Explanation:
:)
. explain the effect of increasing the right flow tube radius on the flow rate, resistance, and pump rate.
Answer:
Increasing the flow tube radius caused flow rate to increase and resistance to decrease. To maintain the same pressure, the pump rate had to increase as well.
Which of the following are the key
aspects a technical engineer will be
asked to do?
A. Build and put together
B. Design and structure
C. Deconstruct and analyze
Answer: A ,build and put together. engineer build things.
as the angle of the ramp is increased the force parallel increases /decreases / remains the same
As the angle of the ramp is increased, the force parallel increases. Hence, option (a) can be considered as the correct answer.
When the angle of a ramp is increased, the force parallel to the ramp, also known as the parallel component of the gravitational force, does increase. This is because the component of gravity acting parallel to the ramp increases with the angle. However, it's important to note that the total gravitational force acting on an object remains constant regardless of the angle of the ramp.As the angle of the ramp increases, the force required to push or pull an object up the ramp against gravity increases. This is due to the increase in the vertical component of the gravitational force, which opposes the motion up the ramp. The parallel force required to overcome this increased vertical force also increases.
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list five pieces of personal safety equipment which must be in everyday use in the workshop
Answer:
safety glasses, hearing protection, respirator, work gloves, and work boots.
Explanation:
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