Assume you have 5. 0g of mg(s) reactant. calculate how much hcl(aq) you would need to use in order to ensure that hcl is not the limiting reactant. your final answer should be in ml of hcl.


a. 82ml hcl


b. 41ml hcl


c. 410ml hcl


d. 205ml hcl






assume you have 5. 0g of mgo(s) reactant. calculate how much hcl(aq) you would need to use in order to ensure that hcl is not the limiting reactant. your final answer should be in ml of hcl.


a. 50. ml hcl


b. 25ml hcl


c. 250ml hcl


d. 125 ml hcl

The coefficient in front of H₂O(ℓ) is 4, and it is a product.

To balance the redox reaction in a basic solution, we start by balancing the atoms other than hydrogen and oxygen. In this reaction, there is one Mn atom on both sides, so we proceed to balance the oxygen atoms.

On the reactant side, there are four oxygen atoms from MnO₄⁻ and two oxygen atoms from NO, totaling six oxygen atoms. On the product side, there are two oxygen atoms from MnO₂ and two oxygen atoms from NO₂, also totaling six oxygen atoms.

Next, we balance the hydrogen atoms by adding H₂O molecules. In a basic solution, we need to add OH⁻ ions to neutralize the excess H⁺ ions. The number of OH⁻ ions needed is equal to the number of H⁺ ions.

To balance the hydrogen atoms, we add 4 H₂O molecules on the reactant side, which introduces 8 hydrogen atoms. To balance the hydroxide ions, we add 4 OH⁻ ions on the reactant side as well.

The balanced equation becomes:

MnO₄⁻ + 4H⁺ + NO → MnO₂ + NO₂ + 2H₂O

Thus, the coefficient for the liquid water (H₂O(ℓ)) is 4, indicating that it is one of the products.

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The correct answer is:E. 10, product

To balance the given redox reaction, MnO4⁻ (aq) + NO (g) → MnO2 (s) + NO2 (g), in a basic solution, you need to follow these steps:

1. Split the reaction into two half-reactions: oxidation and reduction.

2. Balance the atoms other than hydrogen (H) and oxygen (O) in each half-reaction.

3. Balance the oxygen atoms by adding H2O molecules to the side deficient in oxygen.

4. Balance the hydrogen atoms by adding H+ ions to the side deficient in hydrogen.

5. Balance the charges by adding electrons (e⁻) to the appropriate side of each half-reaction.

6. Multiply the half-reactions by appropriate coefficients to equalize the number of electrons transferred in both half-reactions.

7. Add the half-reactions together and cancel out any common species on both sides of the equation.

Let's go through the steps to balance the given redox reaction in a basic solution:

Half-reaction 1: Reduction (Mn reduction)

MnO4^- → MnO2

Balance Mn: Add 4 H2O molecules to the reactant side:

MnO4^- + 4H2O → MnO2

Half-reaction 2: Oxidation (NO oxidation)

NO → NO2

Balance O: Add 1 H2O molecule to the product side:

NO → NO2 + H2O

Now, we need to balance the hydrogen atoms:

Balance H: Add 2 H+ ions to the product side:

NO + 2H2O → NO2 + H2O + 2H+

Next, we need to balance the charges:

Balance charge: Add 3 electrons (e^-) to the product side:

NO + 2H2O → NO2 + H2O + 2H+ + 3e^-

Now, we can multiply the half-reactions to equalize the number of electrons transferred:

3(NO + 2H2O → NO2 + H2O + 2H+ + 3e^-)

2(MnO4^- + 4H2O → MnO2)

Adding the half-reactions together gives us the balanced overall reaction in basic solution:

2MnO4^- + 8H2O + 6NO → 2MnO2 + 6NO2 + 10H2O

From the balanced equation, we can see that there are 10 H2O molecules as products. Therefore, the coefficient in front of H2O is 10, and it is a product (not a reactant).

The correct answer is:

E. 10, product

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when ammonia is then added, the precipitate dissolves and the solution turns a deep navy blue. The net chemical equation for the dissolution of the precipitate is

Cu²⁺ (aq) + 4NH₃(aq)→ Cu(NH₃)₄²⁺(aq)

When we have a reaction that involves two solutions we can say that such a reaction is rightly classed to be an aqueous phase reaction. The reactants are all in solution. It is however possible that this reaction that involves species that are in solution would produce a product that is a solid and would separate from the system .The reaction is shown below

Cu²⁺ (aq)+ 2NaOH (aq) → Cu(OH)₂(s) + Na₂SO₄(aq)

This now implies that we can write the net ionic reaction and eliminate the spectator ions from this net reaction;

Cu²⁺ (aq)+ 2OH⁻(aq)  → Cu(OH)₂(s)

Now, if we do add the ammonia compound there would be a reaction in which an ammine complex is formed as follows;

Cu²⁺ (aq)+ 4NH₃(aq)→ Cu(NH₃)₄²⁺(aq)

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Answer:

We need the picture to answer the question

Explanation:

but i did do this test and number 4 was biotic and number 5 was abotic hope this helped

Answer:

59.92 × 10²³ atoms are in 9.95 moles of iron

1.8 ×10²² molecules are in 0.03 moles of Carbon dioxide

1.19 moles are found in 7.20 x 10^23 atoms of platinum

Answer:

I was traveling on a train where I fell asleep. someone stole my luggage in which I had money and other essentials. when the ticket checker arrived a lady paid my fine. she helped me a lot. when I told her about being robbed she helped me and took me to the police station and I found my bag. I insisted she take the money she paid for my fine but she said that in return you too help someone."I have never found such a kind person ever since.".....

Explanation: I think this is what you are looking for. Hope this helps.

The **receiving clerk** should prepare the debit memo to adjust for the difference between the quantity ordered and received.

A **debit memo** is a document that records a financial transaction, specifically an adjustment made to an account. In this case, the receiving clerk needs to create a debit memo to account for the discrepancy between the 10 units received and the 12 units specified in the purchase order. This ensures accurate financial records and alerts the necessary parties to the missing items. The receiving clerk is responsible for verifying the quantity and quality of goods received, so they are the appropriate person to prepare this document. By doing so, they help maintain proper inventory management and facilitate communication between the company and its suppliers.

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Answer:

8893.092J

Explanation:

energy= mass × specific heat capacity of water × change in temperature

=32.7×4.184×(77-12)

=8893.092J

Explanation:

the equation must be

4NH3 + 5O2–> 4NO + 6H2O

Answer: The liquid oxygen machine is producing less liquid oxygen than normal because there's a low attraction between the molecules.

It should be noted that oxygen in its liquid state will take up less space. It can also be stored at a lower pressure than when it's in its gaseous state.

Explanation:

From the complete question, the liquid oxygen evaporates at a slightly higher The reason for this is due to the fact that they have similarly low attraction between molecules.

The half life is the time taken for only one of the half  of the radioactive substance to remain.

The half life is the time taken for only one of the half  of the radioactive substance to remain. We can see the half life by looking at the graph and observing the point at which the sample decreases to half its original number.

Since the half life of carbon-14 is 5700 years, after ten half lives, almost 60000 years has elapsed thus there is little or no carbon-14 left. As a result of this carbon-14 can not be used if the sample is over 60000 years old.

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Answer:

D. 25 amu

Explanation:

Answer:

D

Expla

14 NHÂN 1 + 11 NHÂN 1 = 25 AMU

The empirical formula for the compound that contains 0.126 mol of Cl and 0.44 mol of O is \(\(\text{Cl}_2\text{O}_7\)\).

The empirical formula of a compound represents the simplest whole-number ratio of atoms present in the compound. To determine the empirical formula, we need to find the ratio of the number of moles of each element in the compound.

Given that there are 0.126 mol of Cl and 0.44 mol of O, we can start by dividing both values by the smallest number of moles, which is 0.126 mol in this case.

\(\(\frac{0.126 \text{ mol}}{0.126 \text{ mol}} = 1\) and \(\frac{0.44 \text{ mol}}{0.126 \text{ mol}} \approx 3.49\)\)

Rounding the ratio to the nearest whole number, we get 1:3. Therefore, the empirical formula is \(\(\text{Cl}_1\text{O}_3\)\).

However, empirical formulas are usually expressed using the simplest whole-number ratio. Since we cannot have fractional subscripts, we multiply the subscripts by 2 to get the final empirical formula:\(\(\text{Cl}_2\text{O}_6\)\).

Hence, the empirical formula for the compound is \(\(\text{Cl}_2\text{O}_7\)\).

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Answer:

See explanation

Explanation:

The can chiller has a cooling system which expels heat around the immediate vicinity of the can chiller.

Let us remember that convection is a mode of heat transfer that occurs as a result of the actual movement of the particles of a substance. In this case, we are going to consider the movement of air molecules.

As the can chiller expels heat, the air molecules around the can chiller become heated and less dense and begin to move away from the can chiller. They are quickly replaced by cold denser air.

This process of cycling of hot/cold air molecules is known as a convection current. It is set up as a result of the working of the can chiller.

The pressure exerted by 200 g of Ar in a rigid 4.50 L container at 21.0 ˚ C would be 19.6 atm.

To calculate the pressure exerted by the Argon gas, we can use the ideal gas law:

PV = nRT

where

First, we need to determine the number of moles of Argon gas present:

Next, we convert the volume and temperature:

Now we can substitute the values into the ideal gas law and solve for P:

In other words, the pressure exerted by 200 g of Argon gas in a 4.50 L container at 21.0 ˚C is 19.6 atm.

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Answer: Answer

Iron is a chemical element with symbol Fe and atomic number 26. It is a metal that belongs to the first transition series and group 8 of the periodic table. It is, by mass, the most common element on Earth, right in front of oxygen, forming much of Earth's outer and inner core. It is the fourth most common element in the Earth's crust.

Explanation:

Hope this helps!

Answer:

iron:

group 8

4 orbitals

electrons per shell:2,8,14,2

26 electrons

8 valence electrons.

Explanation:

iron is in the 8th group in the periodic table because it is a transition metal and their valence shells have 8 electrons.

It has 4 electron shells because the first one can hold two electrons, the second has 8 and so on.

The total number of electrons is 26, which is equal to number of protons.

Valence electrons are in the outermost shell.

Answer:free shampoo Here In Seconds! Easy to Use. Immediate Response - 24/7. Fast & Free. Highest Standards. Guaranteed Satisfaction. Serving You Better. Results in 5 Sec. or Less. Highly Qualified Search. 1,000,000 Unique Results. Immediate Results. Services: Search Services, Web Results, Result Pages.

Explanation:

Answer:

134.397 Joules

Explanation:

Using the formula:

E = C × m × Δθ (where E is Energy, C is specific heat capacity and Δθ is change in temperature)

So E = 0.45×5.45×(79.8-25)

So E = 134.397 Joules

The heat required to raise the temperature of 5.45g of iron is equal to 134.4 J.

The specific heat capacity is described as the quantity of heat required to raise the temperature of one unit of substance by one-degree Celsius. The specific heat capacity of the substance depends upon the nature of the substance, not its quantity.

The mathematical formula can be used to determine the specific heat is equal to:

Q = m×C×ΔT

Given, the mass of the sample of iron, m = 5.45 g

The initial temperature of the sample, T₁ = 25°C

The final temperature of the sample, T₂ = 79.8°C

The specific heat capacity of iron, C =  0.450 J/g.°C

The heat required for the sample of iron will be:

Q = 5.45 × (0.450) × (79.8 -25)

Q = 134.4 J

Therefore, the heat required to raise the temperature of a 5.45g sample of iron is 134.4 J.

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Answer:

26. Hemoglobin is a tetramer that consists of four polypeptide chains. Each monomer contains a heme group in which an iron ion is bound to oxygen.

Explanation:

Answer:

26. (I think.)

Answer:

B. Electrons have the most mass of the

subatomic particles

Compared to the mass of neutron and proton, mass of electron is negligible.

Answer:

B

Explanation:

when creating a Bohr model, you will usually mark protons + or P and neutrons are usually 0 or N.

Electrons are on the rings surrounding the nucleus, but everything else is inside.

Electrons are typically represented by - or E

The probability that the shipment came from Ghana is approximately 48.78%.

To calculate the probability that the shipment came from Ghana, we can use Bayes' theorem. Let's denote the event that the shipment came from Ghana as G and the event that the shipment came from a neighboring country as N. We want to find P(G|I), the probability that the shipment came from Ghana given that one vial is ineffective.

Calculate the probability of selecting an ineffective vial from Ghana's shipments.

P(I|G) = 0.10 (10% of the vials from Ghana are ineffective)

Calculate the probability of selecting an ineffective vial from neighboring countries' shipments.

P(I|N) = 0.02 (2% of the vials from neighboring countries are ineffective)

Calculate the probability that a shipment came from Ghana, given that one vial is ineffective.

P(G|I) = (P(I|G) * P(G)) / [(P(I|G) * P(G)) + (P(I|N) * P(N))]

        = (0.10 * 0.20) / [(0.10 * 0.20) + (0.02 * 0.80)]

        ≈ 0.0488

Therefore, the probability that the shipment came from Ghana is approximately 48.78%.

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Answer:

75% will have long legs and 25% will have short legs

Explanation:

Examples of herbivores are buffalo, elk, some bird species, mice, squirrels, rabbits, and many more.

To solve this, we must know each and every concept behind herbivores and  carnivores. Therefore, herbivores include cows, goats, giraffes, sheep, and zebras etc.

Herbivores, often known as herbivorous animals, are creatures that eat plants, leaves, fruits, and other plant-based foods for nourishment. They are classified as primary eaters and are found at levels 2 or above in the food supply chain.

Herbivores include cows, goats, giraffes, sheep, and zebras. Interestingly, there really are herbivores who specialize in eating on specific parts of the plant; for example, frugivores are herbivores that graze on fruits, whereas folivores are herbivore that eat on leaves.

Therefore, herbivores include cows, goats, giraffes, sheep, and zebras etc.

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Answer:

7.5X1000

scientific notation

The concentration of the 26 mL HCl solution needed to neutralize 30 mL of the 0.0100 M solution of Ba(OH)₂ is 0.023 M

The concentration of the HCl solution needed for the neutralization of the 30 mL of the 0.0100 M solution of Ba(OH)₂ can be obtained as follow:

Balanced equation:  

2HCl + Ba(OH)₂ —> BaCl₂ + 2H₂O

CaVa / CbVb = nA / nB

(Ca × 26) / (0.01 × 30) = 2

(Ca × 26) / 0.3  = 2

Cross multiply

Ca × 26 = 0.3 × 2

Ca × 26 = 0.6

Divide both side by 26

Ca = 0.6 / 26

Ca = 0.023 M

Thus, the concentration of the HCl solution needed is 0.023 M

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The concentrations of H₃O⁺ and OH⁻ in pure water at 25°C are both 1.0 x 10⁻⁷ M.

In pure water at 25°C, the concentration of H₃O⁺ and OH⁻ ions are equal and can be calculated using the self-ionization constant of water (Kw).

The Kw of water at 25°C is 1.0 x 10⁻¹⁴ mol²/L².

Since the concentration of H₃O⁺ and OH⁻ ions are equal, we can represent them with the same variable, x.

Then, applying the equation for Kw we have;

Kw = [H₃O⁺][OH⁻]

1.0 x 10⁻¹⁴ mol²/L² = x²

Taking square root on both sides, we have;

x = [H₃O⁺] = [OH⁻] = 1.0 x 10⁻⁷ M

Therefore, the concentrations of H₃O⁺ and OH⁻ in pure water is  1.0 x 10⁻⁷ M.

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The given statement "The molar enthalpy of sublimation of a given substance can be determined if its enthalpies of fusion and vaporization are known" is true.

The molar enthalpy of sublimation of a substance can be determined if its enthalpies of fusion (melting) and vaporization (boiling) are known. The enthalpy of sublimation refers to the energy required to change a substance from the solid phase directly to the gaseous phase, bypassing the liquid phase.

The enthalpy change during sublimation can be calculated by considering the enthalpies of fusion and vaporization. When a substance undergoes sublimation, it first requires energy to melt from the solid phase to the liquid phase (enthalpy of fusion) and then additional energy to vaporize from the liquid phase to the gaseous phase (enthalpy of vaporization). The sum of these two enthalpies represents the overall energy change during sublimation.

Therefore, by adding the enthalpy of fusion and the enthalpy of vaporization, one can determine the molar enthalpy of sublimation for a given substance.

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When acid is added to the slime, the crosslinking is broken, resulting in a liquid with lesser viscosity. When alkali is added, the process is reversed, and the slime needs to be regenerated.

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The 14 points mean when it says reduction of armaments to the lowest point of consistent with domestic safety is colonial claims for the benefit of indigenous peoples and the environment. President Woodrow Wilson has also created a proposal that will ensure the preservation of the world in the future.

President Woodrow Wilson directly addressed the causes of World War I in his speech, calling for the abolition of secret treaties, a reduction in armaments, an adjustment in colonial claims in the interests of both native peoples and colonists, and freedom of the seas. Wilson also made proposals to ensure future world peace. He proposed, for example, the removal of economic barriers between nations, the promise of "self-determination" for oppressed minorities, and a world organization that would provide a system of collective security for all nations. Wilson's 14 Points were intended to undermine the Central Powers' will to continue and to inspire the Allies to victory.

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To calculate the actual yield of magnesium nitrate, you need to know the theoretical yield and then compare it to the actual yield. The theoretical yield is calculated based on the balanced chemical equation for the reaction between magnesium and copper(ii) nitrate. The actual yield is the amount of magnesium nitrate that was actually produced during the reaction.

Magnesium nitrate refers to the inorganic compound with the formula Mg(NO₃)₂ₓ, where x = 6, 2, and 0. These are all white solids. The anhydrous material is hygroscopic, quickly forming hexahydrate when in air. All salts are highly soluble in water and ethanol.

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