assuming that the brakes are lifted with constant speed what is the minimum power the motor must produce?

The weight of the human body is distributed across a wider region due to an opposing force acting in opposition to it.

In science, the word "force" has a precise definition. At this level, the phrases "push" and "pull" are entirely suitable to describe forces. A force is not something that exists inside or within an object. A force acts on the first thing from another. A force can be thought of as consisting of both living and non-living things.

The term "force" refers to the tendency of a body to modify to change its state as a result of an outside factor. Additionally, a force applied to the body might cause it to alter in size, shape, and direction. Like kicking a ball, opening and closing doors, or kneading dough, for instance.

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Below are the required answers and explanations for each of the scenarios listed.

1. A machine that pulls all thermal energy out of a refrigerated space: This violates the second law of thermodynamics. This is because the second law of thermodynamics states that no heat engine can have an efficiency of 100 percent, and no heat transfer can occur from a colder to a warmer object without external work being done.

2. A machine that can pull 1000J of heat out of a refrigerated space and into a warmer space without external work: This violates the second law of thermodynamics. The second law of thermodynamics states that no heat transfer can occur from a colder to a warmer object without external work being done.

3. A machine that can turn 1000J of heat directly into 1000J of electricity: This does not violate any of the laws of thermodynamics.

4. A machine that can create 1000J of heat from 100J of electricity: This does not violate any of the laws of thermodynamics.

5. A machine that can pull 1000J of heat out of a refrigerated space and put 1500J of heat into a warmer space if it uses 500J of external work: This does not violate any of the laws of thermodynamics.

a) Option 2 is correct answer.

b) Option  2 is correct answer.

c) Option 4 is correct answer.

d) Option 4 is correct answer

e) Option 4 is correct answer.

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Answer:

I would say pushing it from the top because when you push anything from the top it basically flips over. You can go ahead and try to push anything forward from the top and starts tipping forward. I think the reason would be because you're putting weight only on the top of the tv and that is what would cause it to topple

Explanation: Hope this helps:)

Answer:

B. It increases

Explanation:

Im sure

Answer:

F = G M m / R^2         a = G M / R^2

aS / aE = (MS / RS^2) / (ME / RE^2)

aS / aE = 329390 * RE^2 / RS^2) = 1    If acceleration due gravity equal

RE^2 = 1 / 329290 * (6.96E8)^2

RE^2 = 1.471 E12

RE = 1.213E6 m

actual RE = 6.38E6 m      (average density of sun < that of earth)

The ray does not bend when it enters the semi circular glass block - Light ray incident on semicircular block at 90 degrees, therefore there is no change in the direction of ray at P.

Electromagnetic radiation that falls within the region of the electromagnetic spectrum that the human eye can see is known as light or visible light.

Light is electromagnetic radiation that the human eye can perceive. From radio waves with wavelengths measured in meters to gamma rays with wavelengths shorter than around 1 1011 meters, electromagnetic radiation occurs throughout an incredibly broad range of wavelengths.

Light governs our sleep-wake cycle and is crucial to our health and wellbeing. In actuality, "light" that is visible is a type of radiation, which is just energy that moves in the form of electromagnetic waves. It can alternatively be explained as a flow of "wave-packets," or particles, known as photons.

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While it is true that sound travels through metal at about 6 kilometers per second, phone conversations between New York City and LA do not rely on the physical transmission of sound waves through a metal wire.

Instead, phone calls are sent as electrical signals across a network of microwave towers, satellites, and fiber-optic cables that is connected to each other. The speed of sound through metal is substantially slower than the speed of electrical impulses, which move at the speed of light.

Due to the fact that electrical impulses can travel far quicker than sound through metal, residents in these cities are able to hold a regular conversation over the phone.

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In your business plan, the target market section should clearly identify both your primary and secondary market(s). The market analysis is basically the target market section of your business plan. It is a thorough examination of the ideal people to whom you intend to sell your products or services.

In order to covnert the given quantities, use the correct covnersion factor, as follow:

g) 0.35 oz to mg

h) 75 mL to gal

i) 54 mi to km

j) 1789 ft to km

A photon is a tiny energy packet of electromagnetic radiation, also referred to as a light quantum.

1) Ultraviolet radiation is commonly used in sanitizing hospitals because, viruses, methicillin-resistant Staphylococcus aureus, and vancomycin-resistant enterococci are all susceptible to the germicidal effects of UV-C.

2) According to the photon theory, electrons that have been stimulated return to the ground state to create atomic emission spectra. Light or the photon is the energy that is released when electrons drop to a lower energy level.

3) To characterise the atomic characteristics of light, Albert Einstein used Planck's quantum theory.

Planck's hypothesis is supported by Einstein's demonstration that electromagnetic radiation, such as light, has both wave-like and particle-like properties.

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Answer:

coefficient of friction (μ) and normal force (N)

Answer: How hard the surfaces push together and the types of surfaces involved

Explanation:

According to collision theory, the quantity of reactant molecule collisions determines how quickly a chemical reaction proceeds. The pace of reaction increases with the frequency of reactant-molecule collisions.

The average pace of particles increases with temperature, which increases the rate of particle collisions. The average kinetic power of collisions increases with temperature, increasing the proportion of collisions that require the least amount of energy to react.

Reactant particles need to have a certain minimum energy in order to make an efficient collision. The activation energy is the energy that starts the reaction.

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Answer:

Volume, velocity and variety.

Answer:

  T₀ = 2π \(\sqrt{\frac{m}{k} }\)           T = \(\sqrt{\frac{5}{6} }\) T₀

Explanation:

When the block is oscillating it forms a simple harmonic motion, which in the case of a spring and a mass has an angular velocity

        w = \(\sqrt{k/m}\)

To apply this formula to our case, let's look for the equivalent constant of the springs.

Let's start with the springs in parallels.

* the three springs in the upper part, when stretched, lengthen the same distance, therefore the total force is

       F_total = F₁ + F₂ + F₃

the springs fulfill Hooke's law and indicate that the spring constant is the same for all three,

       F_total = - k x - k x - kx = -3k x

therefore the equivalent constant for the combination of the springs at the top is

      k₁ = 3 k

* the two springs at the bottom

following the same reasoning the force at the bottom is

        F_total2 = - 2 k x

the equivalent constant at the bottom is

         k₂ = 2 k

now let's work the two springs are equivalent that are in series

the top spring is stretched by an amount x₁ and the bottom spring is stretched x₂

            x₂ = x -x₁

            x₂ + x₁ = x

if we consider that the springs have no masses we can use Hooke's law

            \(-\frac{F_{1} }{k_{1} } - \frac{F_{2}}{k_{2} } = \frac{F}{k_{eq} }\)

therefore the equivalent constant is the series combination is

             \(\frac{1}{k_{eq} } = \frac{1}{k_{1} } + \frac{1}{k_{2} }\)

we substitute the values

             \frac{1}{k_{eq} }  = \frac{1}{3k } + \frac{1}{2k }  

             \frac{1}{k_{eq} }  = \frac{5}{6k} }  

              k_eq = \(\frac{6k}{5}\)  

therefore the angular velocity is

             w = \(\sqrt{\frac{6k}{5m} }\)  

angular velocity, frequency, and period are related

           w = 2π f = 2π / T

           T = 2π / w

            T = 2π \(\sqrt{\frac{5m}{6k} }\)

           T₀ = 2π \(\sqrt{\frac{m}{k} }\)

           T = \(\sqrt{\frac{5}{6} }\) T₀

This question is incomplete, the complete question is;

An air-filled capacitor stores a potential energy of 6.00 mJ due to its charge. It is accidentally filled with water in such a way as not to discharge its plates. How much energy does it continue to store after it is filled?

(The dielectric constant for water is 78 and for air it is 1.0006.)

Answer: it continue to store 0.07692 mJ after it was filled

Explanation:

Given that;

stored potential energy = 6.00 mJ = 0.006 J

dielectric constant for water K = 78

Energy stored  U = Q² / 2C = 0.006 J

C = ∈₀A/d { Air}

C = K∈₀A/d  { Water, k = 78 }

so

U = 0.006 / 78

U = 7.6723 × 10⁻⁵J

U = 0.07692 mJ

Therefore it continue to store 0.07692 mJ after it was filled

The size of the angle θ of a point object moving from point A to point B along a circular path is 2πR / L.

To understand this, consider a simple example. Suppose that a point object that moves from point A to point B along a circular path with a radius of 1 meter. The distance between points A and B is also 1 meter. Therefore, the size of the angle θ is equal to 2π × 1 / 1 = 2π radians.

In general, the size of the angle θ = ratio of the circumference of the circle to the distance between points A and B. The circumference of the circle is equal to 2πR, where R = radius of the circle. Therefore, the size of the angle θ is equal to 2πR / L.

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Complete question:

A point object moves from point A to point B along a circular path with a radius R. What is the size of the angle θ?

Answer:

A) M

Explanation:

The three blocks are set in series on a horizontal frictionless surface, whose mutual contact accelerates all system to the same value due to internal forces as response to external force exerted on the box of mass M (Newton's Third Law). Let be F the external force, and F' and F'' the internal forces between boxes of masses M and 2M, as well as between boxes of masses 2M and 3M. The equations of equilibrium of each box are described below:

Box with mass M

\(\Sigma F = F - F' = M\cdot a\)

Box with mass 2M

\(\Sigma F = F' - F'' = 2\cdot M \cdot a\)

Box with mass 3M

\(\Sigma F = F'' = 3\cdot M \cdot a\)

On the third equation, acceleration can be modelled in terms of F'':

\(a = \frac{F''}{3\cdot M}\)

An expression for F' can be deducted from the second equation by replacing F'' and clearing the respective variable.

\(F' = 2\cdot M \cdot a + F''\)

\(F' = 2\cdot M \cdot \left(\frac{F''}{3\cdot M} \right) + F''\)

\(F' = \frac{5}{3}\cdot F''\)

Finally, F'' can be calculated in terms of the external force by replacing F' on the first equation:

\(F - \frac{5}{3}\cdot F'' = M \cdot \left(\frac{F''}{3\cdot M} \right)\)

\(F = \frac{5}{3} \cdot F'' + \frac{1}{3}\cdot F''\)

\(F = 2\cdot F''\)

\(F'' = \frac{1}{2}\cdot F\)

Afterwards, F' as function of the external force can be obtained by direct substitution:

\(F' = \frac{5}{6}\cdot F\)

The net forces of each block are now calculated:

Box with mass M

\(M\cdot a = F - \frac{5}{6}\cdot F\)

\(M\cdot a = \frac{1}{6}\cdot F\)

Box with mass 2M

\(2\cdot M\cdot a = \frac{5}{6}\cdot F - \frac{1}{2}\cdot F\)

\(2\cdot M \cdot a = \frac{1}{3}\cdot F\)

Box with mass 3M

\(3\cdot M \cdot a = \frac{1}{2}\cdot F\)

As a conclusion, the box with mass M experiments the smallest net force acting on it, which corresponds with answer A.

The reading on a vernier caliper can be represented as 45.75mm.

1. Understand the components of a vernier caliper: A vernier caliper consists of two main scales - the main scale and the vernier scale. The main scale is typically graduated in millimeters, while the vernier scale is a smaller scale that slides along the main scale.

2. Locate the main scale: Identify the main scale on the vernier caliper. The main scale is usually marked on the fixed jaw of the caliper and extends in a linear fashion.

3. Identify the vernier scale: The vernier scale is attached to the movable jaw of the caliper. It slides along the main scale and consists of smaller divisions.

4. Align the zero marks: Close the jaws of the caliper and ensure that the zero marks on both the main and vernier scales are aligned.

5. Determine the main scale reading: Read the main scale value that aligns with the zero mark on the vernier scale. In this case, the main scale reading will be 45mm.

6. Locate the vernier scale reading: Examine the vernier scale and identify the division on the vernier scale that lines up perfectly with a division on the main scale. This will give you the additional measurement beyond the main scale reading.

7. Determine the vernier scale reading: Find the division on the vernier scale that aligns with a division on the main scale. The value of this vernier division corresponds to the additional measurement. In this case, the vernier scale reading will be 0.75mm.

8. Add the main scale and vernier scale readings: Combine the main scale reading and the vernier scale reading to get the final measurement. In this case, the final reading will be 45.75mm.

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The net force on q₂ will be  1.07 x 10⁻² N, pointing to the left.

To find the net force on particle q₂, we need to calculate the force due to q₁  and q₃ individually and then add them up vectorially. We can use Coulomb's law to calculate the force between two point charges:

F = k × (q₁ × q₂) / r²

where F is the magnitude of the force, k is Coulomb's constant (k = 8.99 x 10⁹ Nm²/C²), q1 and q2 are the charges of the two particles, and r is the distance between them.

The force due to q₁ on q₂ can be calculated as:

F₁ = k × (q₁ × q₂) / r₁²

where r1 is the distance between q₁ and q₂ (r₁ = 0.180 m).

Similarly, the force due to q₃ on q₂ can be calculated as:

F₂ = k × (q₃ × q₂) / r₃²

where r₃ is the distance between q₂ and q₃ (r₃= 0.230 m).

The direction of each force can be determined by the direction of the electric field due to each charge. Since q₁ and q₃ have opposite signs, their electric fields point in opposite directions. Therefore, the force due to q₁ points to the left and the force due to q₃ points to the right.

To find the net force, we need to add up the forces vectorially. Since the forces due to q₁ and q₃ are in opposite directions, we can subtract the magnitude of the force due to q₃ from the magnitude of the force due to q₁ to get the net force on q₂:

Fnet = F₁ - F₃

Substituting the values we get:

Fnet = k × (q₁ × q₂) / r₁² - k × (q₃ × q₂) / r₃²

Plugging in the values we get:

Fnet = (8.99 x 10⁹ Nm²/C²) × [(9.33 x 10⁻⁶ C) × (4.22 x 10⁻⁶ C) / (0.180 m)² - (-8.42 x 10⁻⁶ C) × (4.22 x 10⁻⁶ C) / (0.230 m)²]

Fnet = 1.07 x 10⁻² N

Therefore, the net force on q₂ is 1.07 x 10⁻² N, pointing to the left.

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At the point indicated by the dot, the electric field vector would be at an angle of 45 degrees measured clockwise from the positive x-axis, since the x and y components of the electric field are equal at that point.

Assuming that the two charges are of equal magnitude and opposite sign and that the distance between them is d, the electric field at the point indicated by the dot can be found using Coulomb's law:

\(E = kq/r^2\)

where k is Coulomb's constant (\(8.99 *10^9 N m^2/C^2\)), q is the magnitude of the charge, and r is the distance between the charges.

Since the charges are of equal magnitude, the net charge at the point indicated by the dot is zero, so we only need to consider the electric field due to one of the charges. Let's assume that we want to find the electric field due to the positive charge.

The distance between the positive charge and the point indicated by the dot is r = d/2. Therefore, the electric field at that point is:

\(E = kq/(d/2)^2 = 4kq/d^2\)

The direction of the electric field is radial, pointing away from the positive charge and toward the negative charge. At the point indicated by the dot, the electric field vector would be at an angle of 45 degrees measured clockwise from the positive x-axis, since the x and y components of the electric field are equal at that point.

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If the cloud is transparent, milky, thin layers, rain within the next 2 hours, then the cloud you are seeing is most likely a type of altocumulus cloud.

Altocumulus clouds are generally characterized by their white or gray color, and can sometimes appear milky or translucent. They often form in layers, and can be thin or thick depending on the conditions.

Altocumulus clouds are typically found at medium altitudes, between 6,500 and 20,000 feet and are often associated with unsettled weather conditions.

While they don't necessarily indicate that rain is imminent, altocumulus clouds can be a sign that a change in the weather is on the way.

Thus, if it is likely to rain in the next 2 hours, then the cloud must be altocumulus clouds.

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Answer:

HEYO BRO! (my bad for da caps)

Explanation:

Evidence-based practice (EBP) is the idea that occupational practices ought to be based on scientific evidence. That at first sight may seem to be obviously desirable, but the proposal has been controversial.

Happy to Help From, Adam

Answer:

Her computer is producing thermal energy, not heat.

Explanation:

Answer:

Her computer is producing thermal energy,not heat

Explanation:

Work is done when you lift an object to a certain height. If the force exerted is greater than the weight of the object, input work is greater than the output work. Then the extra energy goes in overcoming the gravitational acceleration and heating up of body etc

Answer:

I have no clue what this means or what the answer is i am just trying to get my points up so i can ask questions

Explanation:

i am going to put something here so it looks like an explanation so yeah this has no meaning whatsoever i am very sorry that i am not able to give you the answer try looking the answer up im very very very very sorry :(

The figure below shows the trajectory of a particle with mass m bound to (orbiting) an object of mass M by the Newtonian gravitational force therefore the location which equation Fnet = mv²/r applies is at B.

This is referred to as any force which causes a change in direction of velocity toward the center of the circular motion and the formula is  mv²/r .

For an object moving in a circular path, the centripetal force acts on it towards the centre of the path and in this scenario, location B is closest to the centre and the force which makes it remain on that same path which is why it was chosen as the correct choice.

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Answer:

which on a is the question

Answer:

A

Explanation:

A vector quantity is when the unit has magnitude (#) and direction and velocity is speed in a given direction.

A particular small car, with a mass of 920 kg , can accelerate on a level road from rest to 21 m/s (75 km/h ) in 12.0 s. The maximum steepness of a hill is  9.87 degrees.

The term acceleration is defined as any process where the velocity changes. Therefore,velocity is a speed and a direction, there are only two ways for you to accelerate are change your speed or change your direction or change both.

First, find the force pushing the car up a hill as follows:

Force = mass × acceleration

F = ma

Where,

a = change of velocity / change of time

F = mΔv / Δt

F = (920)(21 - 0)/(12.5 - 0)

F = 1545.6 N

By equating this value to the car's y-component:

mg sin (x) = 1545.6

Where,

x = angle of inclination

g = gravity = 9.8 m/s^2

m = mass = 920 kg

(920)(9.8)sin(x) = 1545.6

x = 9.87 degrees.

Thus, the maximum steepness of a hill is 9.87 degrees.

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Your question is incomplete, most probably your question was

a city planner is working on the redesign of a hilly portion of a city. an important consideration is how steep the roads can be so that even low-powered cars can get up the hills without slowing down. a particular small car, with a mass of 920 kg, can accelerate on a level road from rest to 21 m/s (75 km/h) in 12.5 s. using these data, calculate the maximum steepness of a hill.