If Aston pays $75 each month for 23 months, the total amount he would have paid after 23 months, is:
\(75\times23=1725\)Since the cost of the motorcycle is $9200, substract $1725 from $9200 to find the amount that is to be paid to cover the balance in full:
\(9200-1725=7475\)Since $7475 are yet to be paid, Aston must pay that amount the last month if he wants to avoid interest charges.
Therefore, the answer is:
Aston should pay $7475 the last month.
Two wires made of the same material have the same length but different diameters. They are connected in series to a battery. The quantity that is the same for the wires is
Answer:
Two wires made of the same material have the same length but different diameters. They are connected in series to a battery. The quantity that is the same for the wires is The current
Mantle fluid that is heating up will become ________ and move _________.
A. less dense, upwards
B. denser, upwards
C. less dense, downwards
D. denser, downwards
Cobalt-60 (Co) is often used as a radiation source in medicine. It has a half-life of 5.25 years. 4.1. Explain what is meant by the underlined sections in the statement above. [5] Using her knowledge and understanding of nuclear physics, a student was asked to answer the following problem about cobalt-60: How long after a new sample is delivered will its activity have decreased (a) to about one-eighth its original value? (b) to about one-third its original value? Give your answers to two significant figures. The student was also provided with the following information: The activity is proportional to the number of undecayed atoms (AN/At = AN) 4.2. Explain what is meant by the information above provided to the student. [5]
From the question;
1) It takes 15.75 years to decrease to 1/8
2) It takes 8.36 years to decrease to 1/3
What is half life?
Half-life is the length of time it takes for a chemical to degrade or go through a particular process. It frequently refers to the length of time it takes for half of a radioactive substance to decay into a stable form in the context of radioactive decay.
We know that;
\(N/No = (1/2)^t/t1/2\)
No = initial amount
N = amount at time t
t = Time taken
t1/2 = half life
\(1/8 = (1/2)^t/5.252^-3 = 2^-t/5.25\)
t = 15.75 years
Again;
\(1/3 = (1/2)^t/5.25\)
ln0.33 = t/5.25ln0.5
t = ln0.33/ln0.5 * 5.25
t = 8.36 years
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A pipe of length 10.0 m increases in length by 1.5 cm when its temperature is increased by 90°F. What is its coefficient of linear expansion?
The coefficient of linear expansion, given that the length of the pipe increased by 1.5 cm is 1.67×10¯⁵ /°F
How to determine the coefficient of linear expansionFrom the question given above, the following data were obtained
Original diameter (L₁) = 10 mChange in length (∆L) = 1.5 cm = 1.5 / 100 = 0.015 mChange in temperature (∆T) = 90 °FCoefficient of linear expansion (α) =?The coefficient of linear expansion can be obtained as illustrated below:
α = ∆L / L₁∆T
α = 0.015 / (10 × 90)
α = 0.015 / 900
α = 1.67×10¯⁵ /°F
Thus, we can conclude that the coefficient of linear expansion is 1.67×10¯⁵ /°F
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Can you list the offensive position on a flag football team?
Answer:
yes u can flag football has everything that pad football has so you can enlist on being offensive position but you have to play like you want that position
Explanation:
If the coefficient of kinetic friction is 0.43 for a box sliding across your lab table and the
box weighs 7.4 N, what is the force of kinetic friction?
Answer:
3.2N
Explanation:
Given parameters:
Coefficient of kinetic friction = 0.43
Weight of box = 7.4N
Unknown:
Force of kinetic friction = ?
Solution:
The force of kinetic friction is given as:
Force of kinetic friction = UN
U is the coefficient of friction
N is the weight
Force of kinetic friction = 0.43 x 7.4 = 3.2N
a person dives off the edge of aa cliff 33m above the surface of the sea. assuming that air resistance is negligible, how long does the dive last and with what speed does the person enter the water
Answer:
The time is \(t = 2.595 \ s\)
The speed is \(v = 25.43 \ m/s\)
Explanation:
From the question we are told that
The height of the cliff is \(h = 33 \ m\)
Generally from kinematic equation we have that
\(h = ut + \frac{1}{2} gt^2\)
before the jump the persons initial velocity is u = 0 m/s
So
\(33 = 0 * t + \frac{1}{2} 9.8 * t^2\)
=> \(t = 2.595 \ s\)
Generally from kinematic equation
\(v= u + gt\)
=> \(v= 0 + 9.8 * 2.595\)
=> \(v = 25.43 \ m/s\)
An objects motion changes
Answer:
uh finish the question please lol.
Two particles with charges +2e and -4e are initially very far apart (effectively an infinite distance apart). They are then fixed at positions that are 6.09 x 10-12 m apart. What is EPEfinal - EPEinitial, which is the change in the electric potential energy?
Answer:
-2-2×6.09
-4×6.04
-24.04 answer
A bike accelerates from 0 m/s to 15 m/s over the span of 5 seconds. How fast is the bike
traveling after 2.5 seconds?
The bike is travelling at 22.5 m/s after 2.5 s
What is acceleration?This is defined as the rate of change of velocity which time. It is expressed as
a = (v – u) / t
Where
a is the acceleration v is the final velocity u is the initial velocity t is the time How to determine the acceleration Initial velocity (u) = 0 m/sFinal velocity (v) = 15 m/sTime (t) = 5 sAcceleration (a) =?a = (v – u) / t
a = (15 – 0) / 5
a = 3 m/s²
How to determine the final velocity in the first 2.5 s Initial velocity (u) = 15 m/sAcceleration (a) = 3 m/s²Time (t) = 2.5 s Final velocity (v) = ?a = (v – u) / t
3 = (v – 15) / 2.5
Cross multiply
v – 15 = 3 × 2.5
v – 15 = 7.5
Collect like terms
v = 7.5 + 15
v = 22.5 m/s
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If a 93000 kg truck collides with a 60 kg car
are recent changes in solar radiation strongly correlated with earth's temperature? group of answer choices
No, recent changes in solar radiation are not correlated with the earth's temperature.
Seasonal temperatures of sites at various latitudes are influenced by the angle of incoming solar radiation. The incoming solar energy is more direct (almost perpendicular or closer to a 90° angle) when the sun's rays hit the surface of the Earth close to the equator. Warmer temperatures result from solar radiation being concentrated over a smaller surface area.
Higher latitudes have narrower solar radiation angles, which spread energy across a broader region of the surface and result in cooler temperatures. Surface temperatures are typically warmer at lower latitudes and cooler at higher latitudes because the angle of radiation varies with latitude (even though higher latitudes have more hours of daylight during the summer months).
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10. Luther is designing a roller coaster for an amusement park. At one point, the roller coaster will enter a horizontal loop at the speed of 31.8 m/s. If Luther does not want to centripetal acceleration to exceed 29.0 m/s^2, what is the minimum radius of the horizontal loop?
16. When a certain roller coaster is at the top of a 61 m hill, it has no velocity. As the coaster descends the hill, it gains speed. What is the roller coasters speed when the it has a height of 34 m above the ground?
Please answer both of you can!!
Answer:
centripital acceleration= v^2/r
r = v^2/a
r=31.8×31.8/29
r=34.8703m
Explanation:
the maximum acceleration is obtained with minimum radius.
to be safe during a lightning storm, it is best to be to be safe during a lightning storm, it is best to be inside a wooden building without any grounding. inside a metal car. on a metal observation tower. next to a tall tree in a forest. in the middle of a grassy meadow.
To be safe during a lightning storm, it is best to be to be safe during a lightning storm, it is best to be inside a metal car.
As the car is made up of metal, it acts as a good conductor and conducts energy from the lightning to the grounded rubber tires.
Being inside a wooden building is not good as wood is a bad conductor.
Staying on metal observation tower is bad as the charges on the tower are attracted to the clouds and lightning strikes you.
It is not safe to stay under tall trees as the charge may jump from trees to you as wood is a bad conductor.
In the middle of grassy meadows is bad as you are taller than surrounding and your are a good conductor.
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the drawing shows a uniform electric field that points in the negative y direction; the magnitude of the field is 3230 n/c. determine the electric potential difference the following points.
These locations, where the potential difference between Vab and Vcb is 0 and 258v, respectively, have a uniform electric field with a magnitude of 3230 n/c.
The potential difference, also referred to as voltage, is equal to the amount of current multiplied by the resistance. One Joule of energy is consumed by a charge when it moves between two points in a circuit at a potential difference of one Volt. respectively, have a uniform electric field with a magnitude of 3230 n/c. An electric field is a type of physical field that exists around electrically charged particles and which influences the behaviour of all other charged particles nearby (or E-field).
whereas Vcb = E/d = 3230*0.08 = 258v, Vba = E/d = 0
Vba = E/d = 0
Vcb = E/d = 3230*0.08 = 258v
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Suppose a shrimp has been put on the ground that has just been taken out of water.Now touch the shrimp from a distance by a stick.The shrimp will jump straight upward.Will the shrimp do any work in this case?
Answer:
yes
Explanation:
I would say yes because it's exerting some type of force as it reacts to the stick to make it jump straight in an upwards direction
Answer correctly ill give brainliest!! Describe how carbon was formed and eventually end up in your body. Your description needs to explain how a star was once born and eventually produced the carbon. Then you are to explain how that carbon end up in our planet and eventually ended up in your body. You need to be very specific and clear in your explanation. You will need more than one sentence to answer this question. Bonus if you incorporate the carbon cycle in your answer
Answer: Carbon is the chemical backbone of life on Earth. Carbon compounds regulate the Earth’s temperature, make up the food that sustains us, and provide energy that fuels our global economy.
A diagram of the carbon cycle with arrows showing the movement of carbon through a landscape with plants and animals, mountains and a volcano, a river leading to the ocean, and an industrial area. Carbon moves in and out of our atmosphere, ocean, waterways, and soil through burning fossil fuels, precipitation, fires, vegetation, volcanoes, and organic processes.
The carbon cycle. (Image credit: NOAA)
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Most of Earth’s carbon is stored in rocks and sediments. The rest is located in the ocean, atmosphere, and in living organisms. These are the reservoirs through which carbon cycles.
This graph shows the monthly mean carbon dioxide measured at Mauna Loa Observatory, Hawaii, the longest record of direct measurements of CO2 in the atmosphere.
Climate change: Atmospheric carbon dioxide
Carbon dioxide concentrations are rising mostly because of the fossil fuels that people are burning for energy.
Carbon storage and exchange
Carbon moves from one storage reservoir to another through a variety of mechanisms. For example, in the food chain, plants move carbon from the atmosphere into the biosphere through photosynthesis. They use energy from the sun to chemically combine carbon dioxide with hydrogen and oxygen from water to create sugar molecules. Animals that eat plants digest the sugar molecules to get energy for their bodies. Respiration, excretion, and decomposition release the carbon back into the atmosphere or soil, continuing the cycle.
The ocean plays a critical role in carbon storage, as it holds about 50 times more carbon than the atmosphere. Two-way carbon exchange can occur quickly between the ocean’s surface waters and the atmosphere, but carbon may be stored for centuries at the deepest ocean depths.
Rocks like limestone and fossil fuels like coal and oil are storage reservoirs that contain carbon from plants and animals that lived millions of years ago. When these organisms died, slow geologic processes trapped their carbon and transformed it into these natural resources. Processes such as erosion release this carbon back into the atmosphere very slowly, while volcanic activity can release it very quickly. Burning fossil fuels in cars or power plants is another way this carbon can be released into the atmospheric reservoir quickly.
A research vessel ploughs through the waves, braving the strong westerly winds of the Roaring Forties in the Southern Ocean, in order to measure levels of dissolved carbon dioxide in the surface of the ocean.
Southern Ocean confirmed as strong carbon dioxide sink
New research utilizes airborne measurements of carbon dioxide to estimate ocean uptake.
Changes to the carbon cycle
Human activities have a tremendous impact on the carbon cycle. Burning fossil fuels, changing land use, and using limestone to make concrete all transfer significant quantities of carbon into the atmosphere. As a result, the amount of carbon dioxide in the atmosphere is rapidly rising; it is already greater than at any time in the last 3.6 million years. The ocean absorbs much of the carbon dioxide that is released from burning fossil fuels. This extra carbon dioxide is lowering the ocean’s pH, through a process called ocean acidification. Ocean acidification interferes with the ability of marine organisms (including corals, Dungeness crabs, and snails) to build their shells and skeletons.
An aerial view of Century City section of Los Angeles, California.
Atmospheric carbon dioxide rebounds as global pollution rates approach pre-Covid levels
Global carbon emissions are projected to bounce back to after an unprecedented drop caused by the response to the coronavirus pandemic, according to an annual report by the Global Carbon Project.
EDUCATION CONNECTION
Take a bite of dinner, breathe in air, or a drive in a car — you are part of the carbon cycle. The resources in this collection provide real world examples of the changes occurring in the cycle. There is much to learn about this essential topic, and some of the resources highlight exciting career opportunities in this field of study.
Explanation: learn from a middle schooler like me smart
Carbon was formed in stars through nuclear fusion and scattered into space when the star died. Carbon was incorporated into organic molecules through photosynthesis and eventually became part of animals' bodies. The carbon cycle involves the uptake of carbon dioxide by plants, transfer to animals, and release back into the atmosphere through respiration and decomposition, and human activities have disrupted this cycle.
Carbon was formed in the universe through nuclear fusion reactions that took place in the cores of stars. These reactions fused lighter elements into heavier ones, including carbon. When the star eventually died in a supernova explosion, the carbon and other elements were scattered into space.
The carbon, along with other elements, eventually formed clouds of gas and dust that coalesced to form new stars and planets. On our planet, carbon was incorporated into organic molecules through photosynthesis by plants and other photosynthetic organisms. These organic molecules were then consumed by animals, which allowed the carbon to become part of their bodies.
The carbon cycle is the process by which carbon moves through the Earth's atmosphere, oceans, and biosphere. This cycle involves the uptake of carbon dioxide by plants through photosynthesis, the transfer of carbon from plants to animals through the food chain, and the release of carbon back into the atmosphere through respiration and decomposition. Human activities, such as the burning of fossil fuels, have disrupted this cycle, leading to increased levels of carbon dioxide in the atmosphere and contributing to climate change.
Therefore, Nuclear fusion in stars produces carbon, which is then released into space when the star dies. By photosynthesis, carbon was added to organic molecules, eventually becoming a component of animal bodies. Human activities have interrupted the carbon cycle, which involves the intake of carbon dioxide by plants, its transport to animals, and its release back into the atmosphere through respiration and decomposition.
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Explain the function of the “Amygdala” in emotional experience?
Answer:
Emotions. The amygdala is part of the limbic system of the brain, which is involved with emotions and other reactions to stimuli. The amygdala is a processing center that is hooked up to receive incoming messages from our senses and our internal organs. It is highly involved with different emotional responses
Explanation:
A 2.0 g metal cube and a 4.0 g metal cube are 6.0 cm apart, measured between their centers, on a horizontal surface. For both, the coefficient of static friction is 0.65. Both cubes, initially neutral, are charged at a rate of 7.0 nC/s .
(a) Which cube moves first?
(b) How long after charging begins does one cube begin to slide away?
Draw a Sketch of the Problem and Create a "Parameter Panel" for the Problem.
Cube moves first, that the cube which is neutral in nature. Hence, the cube which is neutral will move.
To solve this problem, we need to calculate the electrostatic force between the two charged cubes and compare it with the force of static friction between the cubes and the surface. The cube with the smaller force of friction will begin to move first. The parameter panel and sketch of the problem are shown below:
Parameter Panel:
Mass of cube 1 (m1) = 2.0 g = 0.002 kg
Mass of cube 2 (m2) = 4.0 g = 0.004 kg
Distance between the centers of the cubes (d) = 6.0 cm = 0.06 m
Charge rate of each cube (q) = 7.0 nC/s
Coefficient of static friction (μ) = 0.65
Sketch:
|-----------| |-----------|
| 2 | | 1 |
|-----------| |-----------|
| |
d=6.0 cm d=6.0 cm
| |
|-----------------|
(a) To determine which cube moves first, we need to calculate the electrostatic force between the charged cubes and compare it with the force of static friction between the cubes and the surface. The electrostatic force between two charged objects is given by Coulomb's law:
F = (k * q1 * q2) / d^2
where k is the Coulomb constant (9.0 x 10^9 N m^2/C^2), q1 and q2 are the charges on the cubes, and d is the distance between them. For each cube, the charge is increasing at a rate of 7.0 nC/s, so the charge at any time t is given by:
q = 7.0 x 10^-9 C/s * t
At t = 0, the cubes are neutral and have no charge. At some later time t, the charges on the cubes are:
q1 = 7.0 x 10^-9 C/s * t
q2 = 7.0 x 10^-9 C/s * t
The electrostatic force between the cubes is then:
F = (9.0 x 10^9 N m^2/C^2) * (q1 * q2) / d^2
= (9.0 x 10^9 N m^2/C^2) * [(7.0 x 10^-9 C/s * t)^2 / (0.06 m)^2]
The force of static friction between each cube and the surface is:
Ff = μ * N
= μ * m * g
where N is the normal force, m is the mass of the cube, μ is the coefficient of static friction, and g is the acceleration due to gravity (9.81 m/s^2).
The normal force N is the force exerted by the surface on the cube, and is equal in magnitude to the weight of the cube:
N = m * g
Plugging in the values for each cube, we get:
Ff1 = μ * m1 * g
= 0.65 * 0.002 kg * 9.81 m/s^2
= 0.0127 N
Ff2 = μ * m2 * g
= 0.65 * 0.004 kg * 9.81 m/s^2
= 0.0254 N
Comparing the electrostatic force between the cubes and the force of static friction, we find:
F - Ff1 = (9.0 x 10^9 N)
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A student heats the same amount of two different liquids over Bunsen burners. Each liquid is at room temperature when the student begins. If Liquid 1 has a higher specific heat than Liquid 2, then Liquid 1 will
Answer: Liquid 1 heats more slowly than 2
Explanation:
Liquid 1 heats more slowly than 2 because it has a higher specific heat.
(Hope this helps!)
How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.A cylindrical solenoid with radius 1.00 cm
and length 10.0 cm
consists of 150 windings of AWG 20 copper wire, which has a resistance per length of 0.0333 Ω/m
. This solenoid is connected in series with a 10.0 μF
capacitor, which is initially uncharged. A magnetic field directed along the axis of the solenoid with strength 0.160 T
is switched on abruptly.
How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.
The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.
The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.
Initially, the capacitor is uncharged, so the second term is zero.
Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.
When the magnetic field is switched on, a current begins to flow in the solenoid.
This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.
Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.
The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.
Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.
This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.
The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)
The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)
The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)
This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.
The solution is t = 1.74 ms.
The units are in seconds.
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A runner starts from rest and accelerates at a rate of 1.5 m/s2 and covers 375 m. How long did it take the runner to cover this distance?
Answer:
it takes him 22.36 seconds to cover that distance
Explanation:
We can solve this problem using the kinematic equation for uniformly accelerated motion:
\(x_f-x_i=v_0*t\,+\,\frac{1}{2} a\,*\,t^2\)
which replacing the values given for our case becomes:
\(375=0*t\,+\,\frac{1}{2} (1.5)\,t^2\\375=\frac{1}{2} (1.5)\,t^2\)
and which solving for t gives:
\(375=\frac{1}{2} (1.5)\,t^2\\t^2=2*375/1.5\\t^2=500\\t=\sqrt{500} \\t \approx 22.36\,\,sec\)
If the frequency of a FM wave is 8.85 × 107 hertz, what is the period of the FM wave?
Answer:
1.1299 x 10^-8 second
Explanation:
Period = 1 / f = 1 / (8.85 * 10^7) = 1.1299 x 01^-8 sec
NO LINKS Select the choice that shows the helping verb followed by the main verb. I am writing this sentence. I am writing this sentence. I am writing this sentence. I am writing this sentence
The helping verb in the sentence; "I am writing this sentence" is the verb "am".
Helping verbs are verbs that occur in sentences or clauses whose function is to express tense, form negations or form a question. Examples of helping verbs include; Am, is, are, was and were, being, been, and be, Have, has, had, do, does, did, will, would, shall and should, may, might, must, can, could.
In this sentence; "I am writing this sentence", the helping verb is "am". It helps to express the tense of the action that is being carried out.
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How much time does it take a dropped object to fall 180 m on Earth?
18 s
36 S
10 s
6s
Answer:
6s
Explanation:
Assume it is dropped from rest and the gravitational acceleration is 10
By the equation of motion under constant acceleration:
\(s=ut+\frac{1}{2} at^2\)
180 = (0)t+10(t^2)/2
t = 6 or -6 (rejected)
t = 6 s
7. A particle of mass 3 kg is held in equilibrium by two light unextensible strings. One string is horizontal, as shown in Figure 7.30. The tension in the horizontal string is PN and the tension in the other string is N. Find a) the value of 0 b) the value of P.
The tension in the strings are 31.47 and 19.25 N respectively.
Mass of the block, m = 3 kg
From the figure, consider the vertical components,
T₁ sin45° + T₂ sin30° = mg
(T₁/√2) + (T₂/2) = 3 x 9.8 = 29.4
Also, consider the horizontal components,
T₁ cos45° = T₂ cos30°
T₁/√2 = T₂ x√3/2
T₁ = T₂ x √3/2 x √2
So,
T₁ = 0.612T₂
Applying in the first equation,
(T₁/√2) + (T₂/2) = 29.4
(0.612T₂/1.414) + 0.5T₂ = 29.4
0.434 T₂ + 0.5 T₂ = 29.4
0.934 T₂ = 29.4
Therefore, the tension,
T₂ = 29.4/0.934
T₂ = 31.47 N
So, the tension,
T₁ = 0.612 T₂
T₁ = 0.612 x 31.47
T₁ = 19.25 N
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A sodium ion, Na+ , has a positive charge because it
A. gained an electron.
B. lost a proton.
C. gained a neutron.
D. lost an electron.
D. lost an electron
because they have free electron in the outermost shell which they will like to denote, in order to attain stable configuration
1.How are elements arranged on the periodic table in terms of valence electrons?
2. Show some evidence using data tables
3. Explain how the evidence supports your claim. Explain how the evidence from your data table shows the trends for valence electrons for both groups and periods on the periodic table.
Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration.
1. Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration. The valence electrons are the outermost electrons in an atom's electron shell, and they are crucial in determining the chemical properties and reactivity of elements.
2. Evidence from data tables can be shown by examining the electron configuration and the group and period numbers of various elements on the periodic table. Here is a simplified example:
Element | Electron Configuration | Group | Period |
--------------------------------------------
Hydrogen | 1s^1 | 1 | 1 |
Lithium | [He] 2s^1 | 1 | 2 |
Carbon | [He] 2s^2 2p^2 | 14 | 2 |
Oxygen | [He] 2s^2 2p^4 | 16 | 2 |
Neon | [He] 2s^2 2p^6 | 18 | 2 |
--------------------------------------------
3. The evidence from the data table supports the claim that the arrangement of elements on the periodic table is based on valence electrons.
- Group Trend: Elements within the same group (vertical columns) share the same number of valence electrons. In the example table, Hydrogen, Lithium, and Neon are all in Group 1, indicating they have 1 valence electron.
- Period Trend: Elements within the same period (horizontal rows) have the same number of electron shells. In the example table, Hydrogen and Lithium are in Period 1, indicating they have their valence electron in the first energy level. Carbon, Oxygen, and Neon are in Period 2, indicating they have their valence electrons in the second energy level.
By examining the electron configurations, group numbers, and period numbers, we can clearly see the trends and patterns in the number of valence electrons for both groups and periods on the periodic table. This evidence supports the claim that the arrangement of elements on the periodic table is based on their valence electrons, which play a crucial role in determining their chemical behavior and properties.
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Two students are sitting 1.50 m apart. One student has a mass of 70.0 kg and
the other has a mass of 52.0 kg. What is the gravitational force between them?
A. 8.01 x 10-9
B. 1.08 x 10-2
C. 2.28 x 10-8
Answer:
B
Explanation:
Since the bullets also have zero velocity, a more exact description of the bullet's state would be _____.
Answer:
Static equilibrium.
Explanation: