At 30 mph, it takes approximately 100 feet to react to something you see and to bring your car to a complete stop. This is because the average reaction time for a driver is about 1.5 seconds, during which time the vehicle continues to travel forward at full speed.
Speed is a measure of how fast an object moves relative to a reference point. It is typically expressed in terms of distance traveled per unit of time, such as meters per second or miles per hour. Speed can be a scalar quantity, which only specifies how fast an object is moving, or it can be a vector quantity, which also includes the direction of motion.
Speed is an important concept in physics and is used to describe the motion of objects in many different contexts, from the speed of a car on a highway to the speed of light in a vacuum. It is also an important consideration in everyday life, where we often need to estimate how long it will take to travel a certain distance.
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briefly explain why the magnitude of the absorption coefficient a depends on the radiationwavelength.
It is important to understand what the absorption coefficient (a) represents.
This coefficient is a measure of the amount of energy that is absorbed by a material per unit of distance traveled by the radiation through the material. In other words, it represents the ability of a material to absorb electromagnetic radiation. The magnitude of this coefficient can vary depending on a number of different factors, one of which is the wavelength of the radiation.
Lastly, it is important to note that the magnitude of the absorption coefficient is not the only factor that determines how much radiation is absorbed by a material. Other factors such as the thickness of the material, the temperature of the material, and the intensity of the radiation all play a role in determining the amount of energy that is absorbed.
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Which are properties of both a gas and a plasma? Check all that apply.
A. Can change shape to conform to a container
B. Has a rigid shape that does not change easily
C. Is made up of free-moving ions and electrons
D. Is compressed more easily than other states
E. Has particles that move freely from place to place
F. Will expand to completely fill a closed container
Answer:
D, E, and F
Explanation:
Like a gas, plasma lacks a fixed volume and shape. Unlike a gas, plasma can conduct electricity and respond to magnetism. That's because plasma contains charged particles called ions. The particles that make up matter are also constantly moving.
The properties of both a gas and a plasma are:
Is compressed more easily than other states.Has particles that move freely from place to place.Will expand to completely fill a closed container.What are the properties of gas and plasma?A gas lacks both a fixed volume and a fixed shape. While certain gases are palpable to humans and can be seen and felt, others are not. The gases oxygen, helium, and air are a few examples. N2, O2, and CO2 are among the gases that make up the Earth's atmosphere.
Both the volume and shape of plasma are illusive. Ionized gases frequently contain plasma, yet plasma differs from a gas in that it has special characteristics. The plasma is electrically conductive because it contains free electrical charges that aren't attached to atoms or ions. A gas can be heated and ionized to create plasma. Stars, lightning, fluorescent lights, and neon signs are a few examples of plasma.
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You can make a smoothie in a blender with a power of 400 watts and an efficiency of 85 percent. How much energy is actually being used to make the smoothie in 30 seconds?
A) 8600 J
B) 3000 J
C) 6580 J
D) 10,200 J
Answer:
Its D
Explanation:
I got help from another user lol
Answer:
D!!!
Explanation:
I had this question on my assignment and got it right!
what fraction of the mass needed to halt expansion is known to exist in the form of visible mass in the universe?
The fraction of the mass needed to halt expansion is known to exist in the form of visible mass in the universe is 1 percent
What is meant by visible mass in the universe ?
Baryons, a general term for subatomic particles including protons, neutrons, and electrons, make up visible matter, also known as baryonic matter. What dark matter is constituted of is a topic of conjecture among scientists.
A mysterious, invisible substance called dark matter (25%) and a force that defies gravity called dark energy appear to make up the rest of the universe.
It is estimated that dark energy is responsible for 73% of the universe's total mass and energy. Dark matter makes up another 23% of the universe, leaving only 4% of it to be made up of ordinary matter like stars, planets, and people.
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State government approves a series of grants to fund job training. Which of the following is a negative externality? (5 points
Businesses would not necessarily increase hiring rates.
Economic recession would result in a backlog of applicants.
Money for conservation efforts would be eliminated.
The state would have to provide child care for parents in training.
None of the options listed is a negative externality. A negative externality is an unintended consequence of an economic activity that affects a third party who is not directly involved in the activity.
If I were to choose: Businesses would not necessarily increase hiring rates.
This could be considered a negative externality because the grant funding is intended to fund job training in order to increase employment opportunities, but if businesses do not increase their hiring rates despite having a pool of trained workers, then the intended benefit of the grant may not be fully realized. This could result in a loss of resources and a missed opportunity to address unemployment in the community.
please help, 1 question, brainliest if you get it right! please only answer if you know.
thanks!
Answer:
the answer is b
Explanation:
the answer is b.
Answer:
b is the answer........*-*
The figure shows a rod with two weights on the sides. You are going to rotate the rod at the center of the rod. If the mass of the rod is 30 g, each weight is 50 g, calculate the following.
a. Rotational inertia of the rod.
b. Rotational inertia of a weight (as a hoop).
c. Total rotational inertia.
a. The rotational inertia of the rod is 0.0004 kgm²
b. The rotational inertia of a weight is 0.0009025 kgm²
c. The total rotational inertia is 0.002205 kgm²
What is rotational inertia?Rotational inertia is a property of an object which shows its aboility to rotate about an axis.
a. What is the Rotational inertia of the rod?The rotational inertia of a rod is given by I = 1/12ML² where
M = mass of rod and L = length of rod.Given that
M = 30 g = 0.030 kg and L = 40 cm = 0.40 mSo, substituting the values of the variables into the equation, we have that
I = 1/12ML²
= 1/12 × 0.030 g × (0.40 cm)²
= 1/12 × 0.030 kg × 0.1600 m²
= 1/12 × 0.0048 kgm²
= 0.0004 kgm²
So, the rotational inertia of the rod is 0.0004 kgm²
b. What is the Rotational inertia of a weight (as a hoop).?The rotational inertia of the weight (as a hoop) is given by I' = 1/2mL' where
m = mass of weight and L' = distance of COM of weight from axisGiven that
m = 50 g = 0.050 kg and L = 19 cm = 0.19 mSo, substituting the values of the variables into the equation, we have that
I' = 1/2mL'²
= 1/2 × 0.050 g × (0.19 cm)²
= 0.025 kg × 0.0361 m²
= 0.0009025 kgm²
So, the rotational inertia of a weight is 0.0009025 kgm²
c. What is the Total rotational inertia?The total rotational inertia, I" = rotational inertia of rod + rotational inertia of both weights.
So, I" = I + 2I'
= 0.0004 kgm² + 2 × 0.0009025 kgm²
= 0.0004 kgm² + 0.001805 kgm²
= 0.002205 kgm²
So, the total rotational inertia is 0.002205 kgm²
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When preparing a wet mount specimen for viewing, it should be covered with ______. A) clear paper. B) another glass slide. C) a coverslip
When preparing a wet mount specimen for viewing, it should be covered with a coverslip.
A coverslip is a thin, flat piece of glass or plastic that is placed over the specimen on the slide. It is used to protect the specimen from being compressed or damaged, and to prevent evaporation of the liquid medium that the specimen is suspended in. The coverslip also helps to keep the specimen in focus and allows the viewer to observe the specimen clearly under a microscope.
To prepare a wet mount, a small amount of the specimen is placed on a microscope slide and a drop of liquid medium (such as water, saline, or stain) is added. The coverslip is then placed over the specimen at a slight angle and carefully lowered onto the slide to avoid trapping air bubbles. The coverslip should be pressed down gently to flatten the specimen and remove any excess liquid, but not so hard as to crush the specimen.
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Find the mass of the mystery box D
Please show all work, thxs
The mass of box D, given that a 20 Kg block and two girls each of 20 Kg and 30 Kg sits on the sea-saw is 10 Kg
How do i determine the mass of box D?The mass of box D can be obtained as illustrated below:
Clockwise moment = (0.5 × box D) + (1.5 × 30)Anti-clockwise moment = (2 × 20) + (0.5 × 20)Mass of box D =?Clockwise moment = Anti-clockwise moment
(0.5 × box D) + (1.5 × 30) = (2 × 20) + (0.5 × 20)
0.5 × box D + 45 = 40 + 10
0.5 × box D + 45 = 50
Collect like terms
0.5 × box D = 50 - 45
0.5 × box D = 5
Divide both sides by 0.5
Box D = 5 / 0.5
Box D = 10 Kg
Thus, we can conclude that the mass of box D is 10 Kg
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What do Rachel's actions reveal about her
Three point particles, with masses 5.00 kg, 4.00 kg and 7.00 kg are located along a straight line at 4.00 m, 6.00 m and x m, respectively, in a uniform gravitational field such that the center of gravity is located at the origin. Determine the value of x.
The value of x = -6.29 m
The center of gravity of the three particles X = m₁x₁ + m₂x₂ + m₃x₃/(m₁ + m₂ + m₃)
Given that the center of gravity is located at the origin, X = 0 m and m₁ = 5.00 kg, m₂ = 4.00 kg , m₃ = 7.00 kg, x₁ = 4.00 m, x₂ = 6.00 m, and x₃ = x m
Substituting the values of the variables into the equation, we have
X = m₁x₁ + m₂x₂ + m₃x₃/(m₁ + m₂ + m₃)
0 = 5.00 kg × 4.00 m + 4.00 kg × 6.00 m + 7.00 kg × x/(5.00 kg + 4.00 kg + 7.00 kg)
0 = 20.00 kgm + 24.00 kgm + 7.00x kgm/16.00 kg
Cross-multiplying, we have
20.00 kgm + 24.00 kgm + 7.00x kgm = 0
44.00 kgm + 7.00x kgm = 0
44.00 kgm = -7.00x kgm
Divide through by -7.00 kg, we have
x = 44.00 kgm/-7.00 kg
x = -6.29 m
So, the value of x = -6.29 m
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a simple pendulum consisting of a bob of mass m attached to a string of length l swings with a period t.
The new period of oscillation if the mass of the bob is reduced by half is \(\frac{T}{\sqrt{2}}\) or T/√2.
Look at the attachment for a complete question. The period of oscillation of the simple pendulum
\(T \:=\: 2 \pi \sqrt{\frac{m}{k}}\)\(T \:=\: 2 \pi \sqrt{\frac{L}{g}}\)where
π = 3.14m = the mass of the bob (kg)k = the rope constant (N/m)L = the length of the swing (m)g = the acceleration due to gravity (m/s²)If we change the mass of the bob and didn't change the rope, the period also will change but the rope constant will not. The ratio of the period between the two condition
m₁ = mT₁ = Tm₂ = 0.50 mT² = 4π²m/k
T₁²: T₂² = m₁ : m₂
T²: T₂² = m : 0.50 m
T²: T₂² = 1 : 0.5
T₂² = 0.5T²
\(T_2 \:=\: \sqrt{0.5T}\)
\(T_2 \:=\: \sqrt{\frac{T}{2}}\)
T₂ = T/√2
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Will mark as BRAINLIEST......
A balloon is ascending at the rate of 4.9 m/s. A packet is dropped from from the balloon when situated at a height of 100m.
How long does it take the packet to reach the ground ?
What is it's final velocity ?
Answer:
t = 5.04secsv = -44.49m/sExplanation:
Given parameters
initial velocity u = 4.9m/s
height of drop H = 100m
acceleration due to gravity g = -9.8m/s²(since the body is ascending i.e moving against gravity)
Required
time taken by the packet to reach the ground 't'
Using the equation of motion
S = ut+1/2gt²
0-100 = 4.9t+1/2(-9.8)t²
-100 = 4.9t-1/2(9.8)t²
-100 = 4.9t-4.9t²
4.9t-4.9t² +100 = 0
4.9t²-4.9t² -100 = 0
Multiplying through by 10
49t²-49t-1000 = 0
Using the general equation t = (-b±√b²-4ac)/2a
t = -(-49)±√(-49)²-4(49)(-1000)/2(49)
t = 49±√(2401+196000)/2(49)
t = 49±√(198401)/98
t = 49±√(198401)/98
t = 49±449.42/98
t = (49+449.42)/98
t = 494.42/98
t = 5.04secs
Hence, it took the packet 5.04secs to reach the ground
The final velocity is calculated using the formula v = u + at
v = u-gt
v = 4.9-(9.8)(5.04)
v = 4.9-49.392
v = -44.492m/s
This shows that the final velocity is 44.49m/s(moving downwards)
PLEASE HELPPP
Force: Adding vectors (find resultant force)
50N north plus 50N west Plus 50N north west
inertia is directly related to which quantities
Inertia is directly related to the mass of an object.
Inertia is the tendency of an object to resist a change in its motion. The more mass an object has, the more inertia it has, and the harder it is to change its motion. This is why it is harder to push a heavy object than a light one.
The relationship between inertia and mass can be seen in Newton's Second Law of Motion, which states that the acceleration of an object is equal to the force applied to it divided by its mass. This means that the more mass an object has, the less it will accelerate when a force is applied to it. In conclusion, inertia is directly related to the mass of an object. The more mass an object has, the more inertia it has, and the harder it is to change its motion.
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When a guitar string is plucked, sound waves, which are mechanical waves, transmit sound to your ears. What is the primary medium through which the sound waves travel?
The primary medium through which the sound waves travel is
Air.
What is a Wave?A wave is defined as a disturbance that travels through a
medium which transports energy from one place to another in
the process.
In a guitar, the vibration of the string sets the surrounding air
molecules into vibrational motion which thereby produces
sound heard.
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Use dimensional analysis to determine how many centimeters are in 15 kilometers.A. 15,000 cmB. 1,500 cmC. 1,500,000 cmD. 150 cm
In order to find how many centimeters are in 15 kilometers, we can use the following conversion rate:
1 km = 100,000 cm.
So, for 15 kilometers, we have:
\(15\text{ km}=15\cdot(100,000\text{ cm})=(15\cdot100,000)\text{ cm}=1,500,000\text{ cm}\)Therefore the correct option is C.
What was the initial speed of a car if its speed is 40 m/s after 5 seconds of accelerating at -4 m/s2?
Answer:
60m/s
Explanation:
We are given that
Speed of car after 5 sec, v=40m/s
Acceleration ,a=\(-4m/s^2\)
We have to find the initial speed of car.
We know that
Acceleration, a=\(\frac{v-u}{t}\)
Where v=Final speed
u=Initial speed
Using the formula
\(-4=\frac{40-u}{5}\)
\(-4\times 5=40-u\)
\(-20=40-u\)
\(u=40+20\)
\(u=60\)
Hence, initial speed of car=60m/s
What is the smallest, most basic level of organization in an animal or
plant?
Answer:
hhmmmmmhmmmm hmhmmmm hmmm yeah i got nothing
Explanation:
PLEASE HELP: A car is traveling at 72.0 km/h, when the driver notices an overturned truck blocking the road 95.0 m ahead. The car travels at 72.0 km/h for 0.50 s before the driver applies the brakes. (Please show work).
(a) How far does the car travel in that 0.50 s?
(b) If the car has an acceleration of -2.50 m/s², will it be able to stop before reaching the truck? If not, how fast is the car traveling when it collides with the truck?
Answer:
10 m
Yes, the car will be able to stop before it reaches the truck.
Explanation:
\(u=\text{Initial velocity of the car}=\dfrac{72}{3.6}=20\ \text{m/s}\)
\(t=\text{Time}=0.5\ \text{s}\)
\(s=\text{Displacement}\)
From the laws of motion we have
\(s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=20\times 0.5+0\\\Rightarrow s=10\ \text{m}\)
The car will travel 10 m in 0.5 seconds
\(a=\text{Acceleration}=-2.5\ \text{m/s}^2\)
\(v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-20^2}{2\times -2.5}\\\Rightarrow s=80\ \text{m}\)
Total distance required for the car to stop is 10+80 = 90 m. So, the car will be able to stop before it reaches the truck.
Hellpppppp
1.39 A of current flow across a
144 Ohm resistor. How much
voltage is being applied?
V = 200.16 volts
Explanation:
V= IR
= (1.39 A)(144 ohm)
= 200.16 volts
Answer:
200.16
Explanation:
acellus
12) Two-point charges each have a value of 3.0 C and 5.0 C and are separated by a distance of 6.0 m. What is the electric field at a point midway between the two charges?
Answer:
The electric field at a point midway between the two charges is 2 x 10⁹ N/C.
Explanation:
Given;
first point charge, Q₁ = 3.0 C
second point charge, Q₂ = 5.0 C
distance between the two point charges, R = 6.0 m
The mid-point between the two charges, r = R/2 = 3.0 m
3.0 C <-------------------->3.0m<----------------------->5.0 C
The forces are acting in opposite direction, the electric field strength of each charge is calculated as;
\(E_1 = \frac{kQ_1}{r^2} (-\bar x)\\\\E_1 = \frac{9\times 10^9 \times 3}{3^2}(-\bar x)\)
\(E_2 = \frac{kQ_1}{r^2} (+\bar x)\\\\E_2 = \frac{9\times 10^9 \times 5}{3^2} (+\bar x)\\\\\)
The net electric field is calculated as;
\(E_{net} = \frac{9\times 10^9 \times 5}{3^2} \ - \ \frac{9\times 10^9 \times 3}{3^2}\\\\E_{net} = \frac{9\times 10^9 }{3^2} (5-3)\\\\E_{net} = 2 \times 10^9 \ N/C\)
Therefore, the electric field at a point midway between the two charges is 2 x 10⁹ N/C.
If the mass of the sun is 3x, at least one planet will fall into the habitable zone if I place a planet in orbits___, ____, ____, and ____, and all planets will orbit the sun successfully.
When Earth is closer to the sun, there will be hotter climate. A little movement that takes one closer to the sun could lead to a huge impact.
Impact of the distance of the sun
If I put a planet in orbits 2, 6, and 75, all planets will orbit the sun successfully if the sun's mass is 1x, and at least one planet will fall inside the habitable zone.
If I put a planet in orbits 84, 1, and 5, at least one of them will fall into the habitable zone if the sun's mass is 2x, and all planets will orbit the sun successfully.
If I put a planet in orbits 672 and 7, at least one of them will fall into the habitable zone if the sun's mass is 3x, and all planets will orbit the sun successfully.
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A 6.1 kg echidna is moving to the right. It has a momentum of 29.3 kgm/s right. What is the velocity of the echidna? show work
The velocity of the echidna is 4.8033 m/s to the right.
To find the Momentum:
p = m * v
where
p = Momentum
m = mass
v= velocity
Given that the momentum of the echidna is 29.3 kgm/s to the right and its mass is 6.1 kg, we can rearrange the formula to solve for velocity:
v = p / m
Substituting the given values:
v = 29.3 kgm/s / 6.1 kg
v ≈ 4.8033 m/s
Therefore, the velocity of the echidna is approximately 4.8033 m/s to the right.
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Please send the correct and detailed s olution. Send
it in 45mins please, i will defina
tely upvote you
In the Newton's ring experiment, the diameter of 4 and 10% dark ring are 0.30 cm and 0.62 cm, respectively. a) What is the diameter of 15th dark ring? b) Calculate the wavelength of the light, if the
Answer: In the Newton's ring experiment, the diameter of the 4th dark ring is 0.30 cm and the diameter of the 10th dark ring is 0.62 cm. We can use this information to find the diameter of the 15th dark ring and calculate the wavelength of the light.
Explanation:
In the Newton's ring experiment, the diameter of the 4th dark ring is 0.30 cm and the diameter of the 10th dark ring is 0.62 cm. We can use this information to find the diameter of the 15th dark ring and calculate the wavelength of the light.
a) To find the diameter of the 15th dark ring, we can use the formula for the diameter of the nth dark ring:
d_n = sqrt(n * λ * R)
where d_n is the diameter of the nth dark ring, n is the order of the ring, λ is the wavelength of the light, and R is the radius of curvature of the lens.
Since we want to find the diameter of the 15th dark ring, we can substitute n = 15 into the formula and solve for d_15:
d_15 = sqrt(15 * λ * R)
b) To calculate the wavelength of the light, we can use the formula:
λ = (\(d_10^2 - d_4^2\)) / (\(10^2 - 4^2\))
where d_10 is the diameter of the 10th dark ring and d_4 is the diameter of the 4th dark ring.
Substituting the given values, we have:
λ = (\(0.62^2 - 0.30^2\)) / (\(10^2 - 4^2\))
Simplifying this expression will give us the value of the wavelength of the light used in the experiment.
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HELPPP IM DESPERATE
the first one cuz I know
3) An astronaut in an inertial reference frame measures a time interval Δt between her heartbeats. What will observers in all other inertial reference frames measure for the time interval between her heartbeats? A) Δt B) more than Δt C) less than Δt D) The answer depends on whether they are moving toward her or away from her.
The correct answer to this question is A) Δt. This is because time intervals are invariant in all inertial reference frames, meaning they are the same no matter how fast an observer is moving.
This is a fundamental principle of special relativity. Therefore, an observer in any other inertial reference frame will measure the same time interval Δt between the astronaut's heartbeats as she does. This is true regardless of whether the observer is moving towards or away from the astronaut, as the relative motion between them does not affect the measurement of time intervals. This concept is crucial in space travel and exploration, as astronauts must account for the invariant nature of time when making calculations and measurements. Overall, the time interval between an astronaut's heartbeats is a reference frame-independent quantity that is consistent across all inertial frames of reference.
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HELPPPPPPP PLEASE! ASAPPPPPP
Answer:
Answer:
Debt payments to income ratio = 22.74%
Explanation:
Debts payment to Income ratio is calculated as follows:
= \frac{Total\ debt\ payment}{Total\ Income}
Total Income
Total debt payment
We have total debts payment = auto loan payment 685 + student loan payment685+studentloanpayment375 + credit card payment 125 =125=1,185
Total Income = $5,210
Note: Credit card is also a kind of debt as firstly all the expenses are met during the period and then the payment is made at the end of the period, therefore, there is a loan in the period. Therefore, it will be considered for payment of debt.
Debt payments to income ratio = \frac{1,185}{5,210} = 22.74
5,210
1,185
=22.74
That means the debts are 22.74% of income.
magnitudes cuantitativas
ejemplos
consider the same balloon as in part d. based on what you learned in the video and your answer to part d, if you assume that your balloon began very tiny and has been expanding at a constant rate, what can you conclude about how long your balloon has been expanding?
Answer:
Your balloon has been expanding for 5 hours.
Explanation:
Your balloon has been expanding for 5 hours.