At perihelion a planet in another solar system is 175 x 106 km from its sun at traveling at 40 km/s. At aphelion it is 250 x 106 km distant. What is its speed at aphelion

Answers

Answer 1

The speed at aphelion is mathematically given as

v2 = 21.43 km/s

What is its speed at aphelion?

Question Parameter(s):

At perihelion a planet in another solar system is 175 x 106 km from its sun at traveling at 40 km/s.

At aphelion it is 250 x 106 km distant.

Generally, the equation for the angular momentum conservation is mathematically given as

I1*w1 = I2*w2

Therefore

(0.5*m*R1^2)*v1/R1 = (0.5*m*R2^2)*v2/R2

Where

v1*R1 = v2*R2

v2 = v1*(R1/R2) = (30*10^3)*(2.50*10^11)/(3.50*10^11)

v2 = 2.1428*10^4 m/s

v2 = 21.43 km/s

In conclusion, speed is

v2 = 21.43 km/s

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Related Questions

g a 62 cm guitar string produces a sound wave with a fundamental frequency of 160 hz the speed of sound in air is 339 m/s determine the ratio of the wavelength of the waves that travel on the string to the wavelength of the generated sound wave

Answers

Answer:

The ratio of the wavelength of the waves that travel on the string to the wavelength of the generated sound wave is 0.585

Explanation:

Given;

length of the guitar string, L = 62 cm = 0.62 m

fundamental frequency of the sound, f = 160 Hz

speed of sound in air, v = 339 m/s

The wavelength of the sound that travels on the string is calculated as follows;

for fundamental frequency; Length of the string = Node ------->  Node

Length of string, L = λ/2

λ₁ = 2 x L

λ₁ = 2 x 0.62 m

λ₁ = 1.24 m

The wavelength of the generated sound wave that travels in the air is calculated as follows;

λ₂ = v / f

λ₂ =  339 / 160

λ₂ = 2.12 m

The ratio of the two wavelengths is calculated as;

\(\frac{\lambda _1}{\lambda_2} = \frac{1.24}{2.12} = 0.585\)

What is also know When you know both the speed and direction of an objects motion.

Answers

Answer:

When you know both the speed and direction of an object's motion, you know the velocity of the object.

1.) There was an earthquake in Salt Lake City, Utah, on March 18, 2020, in the morning at  9 hours, 9 minutes, and 45 seconds Mountain Standard Time (9:9:45 MST).  If the velocity of the p-wave is 7.3 km/sec and the velocity of the s-wave is 5.1 km/sec and the s-p time lag is 16 seconds, what is the distance in kilometers from Salt Lake City to the focus of the earthquake?  Explain how you calculated the answer.


Answers

Answer:

7 because salt lake and Southis weat

A sprinter starting from rest on a straight and level track is able to achieve a speed of 14 m/s in a time of 6.7 s. What is the sprinter's average acceleration?answer:___ m/s2

Answers

ANSWER:

2.09 m/s²

STEP-BY-STEP EXPLANATION:

Given:

Initial speed = 0 m/s

Final speed = 14 m/s

Time = 6.7 s

We can determine the acceleration by the following formula:

\(\begin{gathered} a=\frac{\Delta v}{\Delta t} \\ \\ \text{ We replacing:} \\ \\ a=\frac{14-0}{6.7-0} \\ \\ a=2.09\text{ m/s}^2 \end{gathered}\)

The acceleration is equal to 2.09 m/s²

A 1,000 kg truck initially had a velocity of 9 m/s. A force acts on it for a duration of time. After that force, the truck now has a velocity of 17 m/s. What is the impulse that the truck experienced?

Answers

Answer:

8000Ns

Explanation:

Given parameters:

Mass of the truck  = 1000kg

Initial velocity  = 9m/s

Final velocity  = 17m/s

Unknown:

Impulse  = ?

Solution:

The impulse experienced by the truck is the the change in momentum of the body.

  Impulse  = Ft

        Momentum  = m(v  - u)

        Ft  = m( v - u )

 F is the force

 t is the time

 m is the mass

  v is the final velocity

 u is the initial velocity

     Impulse  = 1000(17 - 9) = 8000Ns

The earth has a radius of 6.38×10^6 meters. Assume a perfectly smooth spherical earth. Calculate the minimum horizontal velocity required for an object to orbit the earth just above the surface

The earth has a radius of 6.3810^6 meters. Assume a perfectly smooth spherical earth. Calculate the minimum

Answers

The minimum horizontal velocity required for an object to orbit the earth just above the surface is 5.04 x 10¹⁰ m/s.

What is orbital speed of earth?

The orbital speed of Earth or a natural satellite is the speed at which it orbits around the center of the system.

The minimum orbital speed of the Earth is calculated as follows;

V(min) = √GMR

where;

G is universal gravitation constant = 6.67 x 10⁻¹¹Nm²/kg²M is mass of earth = 5.97 x 10²⁴ kgR is the radius of the earth = 6.38 x 10⁶ m

Substitute the given parameters and solve for the minimum orbital speed of the earth.

V(min) = √(6.67 x 10⁻¹¹ x 5.97 x 10²⁴ x 6.38 x 10⁶)

V(min) = 5.04 x 10¹⁰ m/s

Thus, the minimum horizontal velocity required for an object to orbit the earth just above the surface is 5.04 x 10¹⁰ m/s.

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Why is DNA a useful evolutionary clock?

Answers

Because analyzing DNA from present-day and ancient genomes provides a complementary approach for dating evolutionary events. Because certain genetic changes occur at a steady rate per generation, they provide an estimate of the time elapsed.

A wooden block is dragged along a smooth surface with a rope parallel to the floor attached to it.If the force on the string is 30n and the mass of the work is 3.2kg.What is the value of the coefficient of the limiting friction

Answers

Answer:

  0.957

Explanation:

Assuming the surface is parallel to the floor and the block is not accelerating, the coefficient of friction will be the ratio of the horizontal force to the normal force. The normal force will be the force due to gravity:

  F = Ma = (3.2 kg)(9.8 m/s²) = 31.36 N

Then the ratio of the forces is ...

  μ = horizontal force/vertical force = (30 N)/(31.36 N)

  μ ≈ 0.956633

The coefficient of friction is about 0.957.

Physics Question!!!!!

Physics Question!!!!!

Answers

Answer:

bbibinononobyvtcrxrxextcyvubuvububububububbu

Answer:

im just gettin these points babbbyyyyyy

Explanation:

Objects 1 and 2 attract eachother with a gravitational force

Objects 1 and 2 attract eachother with a gravitational force

Answers

Given,

The force between object 1 and object 2, F₁=72.0 units

From Newton's law of gravitation, the gravitational force between two objects is directly proportional to the product of the masses of the two objects and inversely proportional to the square of the distance between them.

Let us assume that initially, the distance between object 1 and object 2 was 'r'.

From Newton's law of gravitation,

\(F_1\propto\frac{1}{r^2}\)

After tripling the distance between the objects, the separation is 3r.

Again, from Newton's law of gravitation,

\(\begin{gathered} F_2\propto\frac{1}{(3r)^2} \\ \Rightarrow F_2\propto\frac{1}{9r^2} \end{gathered}\)

On dividing the two forces,

\(\begin{gathered} \frac{F_2}{F_1}=\frac{\frac{1}{9r^2}}{\frac{1}{r^2}} \\ =\frac{r^2}{9r^2} \\ \Rightarrow F_2=\frac{F_1}{9} \end{gathered}\)

On substituting the values of F₁,

\(\begin{gathered} F_2=\frac{72.0}{9} \\ =8.0\text{ units.} \end{gathered}\)

Thus after tripling the distance between object 1 and object 2, the new gravitational force is 8.0 units.

What happened to the pod during those seconds when communication was lost?

Answers

Answer:

Explanation:

From our investigation of what forces are like in a collision, we learned that when two

objects collide, a force is exerted on each object. The two forces are in opposite

directions but the same strength. This allowed us to infer that an equal strength force

was exerted on the space station and the pod, but in opposite directions.

As a result, the space station and the pod are moving in opposite directions. We need to

learn more about the effects of collisions on each object’s motion so we can report back

to Dr. Gonzales at the space agency.

You will use physical materials to gather data about

forces in a collision. You will also notice how objects

are affected by collisions. Students will use their

data to infer the force direction for objects in a

collision.

Based on the velocity change of each object,

what did you infer about the direction of forces

during a collision?

• We observed that the velocity of each object changed during a collision, so we can infer

that a force had to be exerted on each object. However, the motion of the objects

changed in different ways.

• The object that was moving forward slowed down, so I can infer that the force must have

pushed backward on this object.

• The other object started moving forward, so the force must have pushed forward on that

object. If one force was backward and one force was forward, then the forces pushed

the objects in opposite directions.

Write an experiment to show motion of particles in the matter

Answers

The experiment to show the random motion of the particles is the movement of particles in a solution is the simplest representation of motion of particles.

What is the experiment to show the motion of particle in a matter?

Pick up two glass beakers. Fill one beaker with hot water and the second one with cold water. Add KMnO4 crystals in very small quantities to both. We thus see that KMnO4 particles move faster in hot water than in cold water.

What is the experiment to show evidence for attraction between the particles:

Pick up some iron and  a piece of chalk. We learn that it's quite difficult to work with iron. This leads us to believe that the Forces can affect matter particles. among them. The pressure kept between  particles and the power of the attraction in materials is at its strongest between particles the least in gases.

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M1 is a spherical mass (25.0 kg) at the origin. M2 is also a spherical mass (10.6 kg) and is located on the x-axis at x = 94.8 m. At what value of x would a third mass with a 19.0 kg mass experience no net gravitational force due to M1 and M2?

Answers

The point where m3 experiences a zero net gravitational force due to M1 and m2 is 57.42 m.

Position of the third mass

m1<------(x)------> m3 <-----------(94.8 m - x)-------->m2

a point, x, where m3 experiences a zero net gravitational force due to M1 and m2;

Force on m3 due to m1 = Force on m3 due to m2

Gm1m3/d² = Gm2m3/r²

m1/d² = m2/r²

where;

d is the distance between m1 and m3 = xr is the distance between m3 and m2 = 94.8 - x

m1/(x²) = m2/(94.8 - x)²

m1(94.8 - x)² = m2x²

(94.8 - x)² = (m2/m1)x²

(94.8 - x)² = (10.6/25)x²

(94.8 - x)² = 0.424x²

(94.8 - x)² = (0.651)²x²

94.8 - x = 0.651x

94.8 = 1.651x

x = 94.8/1.651

x = 57.42 m

Thus, the point where m3 experiences a zero net gravitational force due to M1 and m2 is 57.42 m.

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)Which will likely produce a greater amount of static charge: a wool sweater worn under a cotton jacket, or a wool sweater worn under a rubber rain coat? Why?

Answers

A wool sweater worn under a cotton jacket produces more static charges.

What is static charge?

Static charge is an imbalance of electric charges within or on the surface of a material or between materials.

Static charges can be produced by two materials together (friction method).

A wool sweater worn under a cotton jacket (in the absence of lubricant like water) creates friction which enables more static charge to be produced.

Thus, a wool sweater worn under a cotton jacket produces more static charges.

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What is the economic term for the act of sacrificing one good or service to purchase or produce another?

Answers

Answer:

Trade-off. sacrificing one good or service to purchase or produce another.

A roller coaster has a mass of 450 kgIt sits at the top of a hill with height 49 m. If it drops from this hill, how fast is it going when it reaches the bottom? Assume there is no air resistance or friction.)

Answers

The speed of the roller coater at the bottom of the hill is 31 m/s.

Speed of the roller coater at the bottom of the hill

Apply the principle of conservation of mechanical energy as follows;

K.E(bottom) = P.E(top)

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

v is the speed of the coater at bottom hillh is the height of the hillg is acceleration due to gravity

v = √(2 x 9.8 x 49)

v = 31 m/s

Thus, the speed of the roller coater at the bottom of the hill is 31 m/s.

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27/13 AL + 4/2 He -> ? + 1/On
Please help!!!!!! What’s the missing species???

Answers

The missing species of the nuclear reaction obtained is ³⁰₁₅P

How do i determine the missing species?

The missing species of the equation can be obtain as follow:

Let the missing species be ʸₓZ

Now, we can obtain the value of x, y and Z as follow:

²⁷₁₃Al + ⁴₂He -> ʸₓZ + ¹₀n

For x

13 + 2 = x + 0

15 = x

x = 15

For y

27 + 4 = y + 1

31 = y + 1

Collect like terms

y = 31 - 1

y = 30

For Z

ʸₓZ => ³⁰₁₅Z

From the period table, the element with atomic number of 15 is phosphorus, P. Thus, we have

ʸₓZ => ³⁰₁₅Z => ³⁰₁₅P

Therefore, we can write the complete equation as:

²⁷₁₃Al + ⁴₂He -> ³⁰₁₅P + ¹₀n

Thus, the missing species is ³⁰₁₅P

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What color(s) of visible light will cyan ( bluish green) pair of sunglasses
A. Transmit

B. Absorb or block

Answers

A pair of cyan sunglasses will absorb or block light in the blue-green range and transmit light in the red-orange and yellow-green range.

What is Light?

Light is a form of electromagnetic radiation that is visible to the human eye. It is a type of energy that travels through space as waves and is characterized by its wavelength and frequency. Light can be produced by a variety of sources, including the sun, light bulbs, and electronic devices. It can also be manipulated through lenses, mirrors, and other optical devices to create different effects, such as magnification or dispersion.

Cyan (bluish-green) sunglasses will transmit or allow the passage of wavelengths of light that appear bluish-green to our eyes. This means that the lenses of these sunglasses are designed to absorb or block other wavelengths of visible light that correspond to other colors. The specific wavelengths of visible light that are absorbed or blocked by cyan sunglasses will depend on the exact properties of the dye or pigment used to color the lenses.

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how can you find the reading of main scale and vernier scale​

Answers

Answer:

this pdf should help you out

Explanation:

You perform an experiment to test how far a cannon will shoot a performer at
different angles. The data are shown below.
Angle
Distance (feet)
110
32°
36°
120
40°
128
440
133
48°
127
52
119
56°
109
60°
100
64°
91
68°
77
72°
63
At which angle will the performer travel the longest distance?

You perform an experiment to test how far a cannon will shoot a performer atdifferent angles. The data

Answers

Answer:

44°

Explanation:

Look for the longest distance under the 'Distance ' column....look to the left to find the corresponding angle

  Table clearly shows that the longest distance (133 ft) occurs at angle of 44°

the orbit of an object is caused by what two factors *
1. The initial force of motion and an inward-acting force
2. 2 unbalanced forces
3, A push or pull on an object

Answers

The initial force of motion and inward acting force

PLEASE HELP!!!!



Do you think we will ever be able to get rid of our dependency on fossil fuels? Why or why not?

Answers

Answer:Probably because we've been so dependent on them,and we took to long to find new reusable resources.

Explanation:

The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?

Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.

Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!

Answers

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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a steam engine works on its vicinity and 285 k heat is released with the help of 225 degree centigrade energy absorbed to the system. what is the efficiency of steam engine

Answers

The efficiency of the steam engine is 78.9%.

What is the efficiency of a machine?

The efficiency of a machine is a measure of the useful work done by the machine as against the work input into the machine.

Efficiency of a machine = work output/work input × 100%

Work output of the steam engine = 225 K

Work input of the steam engine = 285 K

The efficiency of the machine = 225/275 × 100% = 78.9%

Therefore, the efficiency of the steam engine is 78.9%.

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What does it mean ' a source of energy is nonrenewable?(1 point)

Answers

In our lives or possibly in countless lifetimes, non-renewable energy sources will deplete or cease to exist. Coal, petroleum, & natural gas make up the majority of non-renewable energy sources.

In what ways are non-renewable energies harmful?

By most standards, biofuels, oil, and natural gas—cause significantly more damage than renewable energy sources, including air pollution, ill effects on human health, habitat loss for species, water use, land use, the global warming emissions.

What is the main drawback of non-renewable energy?

Coal, nat gas, oil, & nuclear energy are examples of nonrenewable energy sources. Since we now depend on these resources for the majority of our energy, once they are depleted, they could be replaced, which poses a serious issue for humanity.

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Help me in PE plzzzzzz

Help me in PE plzzzzzz

Answers

Answer:

Balance. Eyes. Elbow. Follow-Through

Explanation:

Answer:

you have to take 4 to 5 steps to do the step

Explanation:

An object is moving with constant speed in a
circular path. The object's centripetal
acceleration remains constant in
(1) magnitude, only
(2) direction, only
(3) both magnitude and direction
(4) neither magnitude nor direction

Answers

Answer:

both magnitude and direction

Explanation:

When an object moves in a circular path, its motion is called uniform circular motion. In this motion, the force acting on it is centripetal force and it is moving under centripetal acceleration. This type of force acts towards the centre of the circle.

In this type of motion, the speed remains constant while the velocity keeps on changing. The object's centripetal  acceleration remains constant in magnitude as well as direction.

Hence, the correct option is (3).

If an object is moving with constant speed in the circular path the object's centripetal  acceleration remains constant in both magnitude and direction

The formula for calculating the centripetal acceleration of an object is expressed as:

\(a =\frac{v^2}{r}\)

v is the speed of the objectr is the radius of the circular path

If the speed of the object is constant, the acceleration is of the body is also constant.

Hence if an object is moving with constant speed in the circular path the object's centripetal  acceleration remains constant in both magnitude and direction

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The magnitude of the electric field due to a point charge object at a distance 4.0 m is 9 N/C. From the same
charged object the electric field of magnitude, 16 N/C will be at a distance of

Answers

The electric field of magnitude 16 N/C will be at a distance of 6.0 meters from the charged object.

The magnitude of the electric field due to a point charge object follows the inverse square law, which states that the magnitude of the electric field is inversely proportional to the square of the distance from the charged object. Mathematically, this is expressed as:

\(E = k*q/r^2\)

where E is the electric field, k is Coulomb's constant (\(k = 9 x 10^9 N*m^2/C^2\)), q is the charge of the object, and r is the distance from the object.

We can use this formula to find the distance at which the electric field has a magnitude of 16 N/C. Let's call this distance x:

16 = \(k*q/x^2\)

We can rearrange this equation to solve for x:

x = \(\sqrt(k*q/16)\)

To find q, we need another piece of information. We know that the electric field has a magnitude of 9 N/C at a distance of 4.0 m. Using the same formula as before, we can solve for q:

9 = \(k*q/4^2\)

q = \(9*4^2/k\)

Now we can substitute this value for q into the equation for x:

x =\(\sqrt(k*(9*4^2/k)/16)\)

x =\(\sqrt(9*4^2/16)\)

x = \(\sqrt(36)\)

x = 6.0 meters

Therefore, the electric field of magnitude 16 N/C will be at a distance of 6.0 meters from the charged object.

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A standing wave of the third overtone is induced in a stopped pipe, 3 m long. The speed of sound is 340 m/s. The number of antinodes in the standing wave pattern is:

Answers

Answer:

overtone- one over the first

n skips by twos

4 antinodes

500 Hz

Explanation: Hope this helps :)

Which type of material uses the subtractive coloring process?

a. light

b. math

c. opaque

d. pigments

e. none of these

Answers

I think that the answer is A
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