Given data:
* The mass of the skier is m = 55 kg.
* The angle of the slope is,
\(\theta=25^{\circ}\)* The initial velocity of the skier at the top is,
\(u=3.8\text{ m/s}\)* The coefficient of friction between the ski boot and slope is,
\(\mu=0.14\)* The distance traveled by the skier along the inclined plane is,
\(S=57\text{ m}\)Solution:
The diagrammatic representation of the given case is,
The angle of the inclined plane with the vertical axis is,
\(\begin{gathered} \alpha=180^{\circ}-90^{\circ}-\theta \\ \alpha=90^{\circ}-\theta \end{gathered}\)Thus, the component of the weight of skier along the inclined plane is,
\(\begin{gathered} F_1=mg\cos (90^{\circ}-\theta)_{} \\ F_1=mg\sin (\theta) \end{gathered}\)where g is the acceleration due to gravity,
Substituting the known values,
\(\begin{gathered} F_1=55\times9.8\times\sin (25^{\circ}) \\ F_1=227.79\text{ N} \end{gathered}\)The component of weight perpendicular to the inclined plane is,
\(\begin{gathered} F_2=mg\sin (90^{\circ}-\theta) \\ F_2=mg\cos (\theta) \end{gathered}\)Substituting the known values,
\(\begin{gathered} F_2=55\times9.8\times\cos (25^{\circ}) \\ F_2=488.5\text{ N} \end{gathered}\)From the diagram, the normal force acting on the skier is,
\(\begin{gathered} F_N=F_2 \\ F_N=488.5\text{ N} \end{gathered}\)The frictional force acting on the skier in terms of the normal force is,
\(\begin{gathered} F_r=\mu F_N \\ F_r=0.14\times488.5 \\ F_r=68.39\text{ N} \end{gathered}\)Thus, the net force acting on the skier down the inclined plane is,
\(\begin{gathered} F=F_1-F_r_{} \\ F=227.79-68.39 \\ F=159.4\text{ N} \end{gathered}\)According to Newton's second law, the acceleration of the skier is,
\(\begin{gathered} F=ma \\ a=\frac{F}{m} \\ a=\frac{159.4}{55} \\ a=2.9ms^{-2} \end{gathered}\)By the kinematics equation, the speed of the skier after moving to distance S is,
\(\begin{gathered} v^2-u^2=2aS \\ v^2-3.8^2=2\times2.9\times57 \\ v^2-14.44=330.6 \\ v^2=330.6+14.44 \end{gathered}\)By simplifying,
\(\begin{gathered} v^2=345.04 \\ v=18.6\text{ m/s} \end{gathered}\)Thus, the speed of the skier after moving 57 m downhill is 18.6 meters per second.
the spaceship is flying through space far from planets and stars with the engines firing.
The astronaut shuts the engines off.
The spaceship will….
a. stop moving immediately
b. slow down gradually and stop
c. continue with whatever speed it had when the engines were cut off
d. speed up for just a little while, then slow down
Consider a vector G pointed 36.9 degrees clockwise from the positive y-axis. The vector’s xcomponent has a value of 3. Find the magnitude of vector G. Show all work.
The magnitude of a vector G pointed 36.9° clockwise from the positive y-axis, with an x-component of 3, is 5.
The magnitude of the vector is given by:
\( \overline{G} = \sqrt{G_{x}^{2} + G_{y}^{2}} \)
Where:
\( G_{x}\): is the x-component of the vector G = 3
\(G_{y}\): is the y-component of the vector G
We need to calculate the y-component of the vector. We can use the following trigonometric function:
\( tan(\theta) = \frac{G_{x}}{G_{y}} \)
Where:
θ: is the angle = 36.9° (clockwise from the positive y-axis)
Hence, the y-component of the vector is:
\( G_{y} = \frac{G_{x}}{tan(\theta)} = \frac{3}{tan(36.9)} = 4 \)
Now, the magnitude of the vector is:
\( \overline{G} = \sqrt{G_{x}^{2} + G_{y}^{2}} = \sqrt{(3)^{2} + (4)^{2}} = 5 \)
Therefore, the magnitude of the vector G is 5.
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An experiment is set up and collects the following data
Force (N) Acceleration (m/s^2)
30 1.5
70 3.5
85 4.25
What is the mass of the object experimented on in this situation?
A. 10 kg
B. 15 kg
C. 20 kg
D. 25 kg
The mass of the object experimented on in this situations is 20 kg. So, option(C) is correct.
What is force?
A force is something that pushes or pulls an object. The objects' interactions with one another are what causes push and pull. Force can also be expressed using words like stretch and squeeze.
When an object with mass is pushed or pulled, it changes its velocity, according to the definition of force in physics.
The product of mass (m) and acceleration (a) represents the amount of force (F). Mathematically speaking, the force equation or formula can be written as follows:
F = ma
According to given parameters:
Force = 30 N; acceleration = 1.5 m/s². So, mass = 30/1.5 kg = 20 kg.
Force = 70 N; acceleration = 3.5 m/s². So, mass = 70/3.5 kg = 20 kg.
Force = 85 N; acceleration = 4.25 m/s². So, mass = 85/4.25 kg = 20 kg.
Hence, the mass of the object experimented on in this situations is 20 kg.
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Space tourists promoted motel and restaurant development.
Retired space professionals promoted new home and community growth.
Space themed business opened all over.
More colleges and universities taught space related mathematics, engineering, sciences, and foreign languages.
Which of these is true of all the above statements?
Responses
A Space is the only important aspect of Florida's culture.Space is the only important aspect of Florida's culture.
B Space has had very little influence of Florida's culture.Space has had very little influence of Florida's culture.
C Space is a very important aspect of Florida's culture.Space is a very important aspect of Florida's culture.
D Space has not been a very important aspect of Florida's culture.
(update: its c)
The right answer is C. Space plays a significant role in Florida culture. Space plays a significant role in Florida culture.
What additional elements, outside space-related activity, have helped Florida's culture develop?The natural environment, history, diversified population, and well-liked attractions like beaches and amusement parks are some of the influences on Florida's culture.
What are some possible negative effects of making space-related pursuits a significant part of Florida's culture?Although Florida has benefited economically and educationally from space-related activity, focusing on this industry as a significant part of the state's culture could have negative effects. Moreover, emphasizing space-related operations could put other crucial industries, like healthcare or environmental conservation.
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We have two measuring equipment: one with the capacity of 2 L and the other with the capacity of 5. How can we measure 6 L oil by the help of these two measuring equipment.
To measure of a volume of 6 L using 5 L and 2 L is measure out 2 times volume of 5 L and subtract 2 times 2 L volume from it.
What is measurement of volume?Volume is the measure of the 3-dimensional space occupied by matter, or enclosed by a surface, measured in cubic units.
The SI unit of volume is the cubic meter (m³), which is a derived unit. Liter (L) is a special name for the cubic decimeter (dm³).
If we have two measuring equipment:
one with the capacity of 2 L and the other with the capacity of 5 LTo measure of a volume of 6 L we will simply follow the method below;
First measure out a volume of 5 L and empty it in another containerSecond, measure out another volume of 5L and empty it again in the same container.Total volume in the container = 5 L + 5L = 10 LThird, use the 2 L to measure out 2 L volume from the 10 L in the container.Finally, measure out another 2 L from the remaining 8 L and you will have 6L volume left in the container.Learn more about volume measurement here: https://brainly.com/question/1789840
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The power in an electrical circuit is given by the equation P= 1^2R where /is
the current flowing through the circuit and Ris the resistance of the circuit.
What is the current in a circuit that has a resistance of 30 ohms and a power
of 2 watts
The current in a circuit that has a resistance of 30 ohms and a power of 2 watts is 0.2581 Ampere.
Solution:
The power in an electrical circuit is given by the equation:
\(P = I^{2} R\)
I = Current in the circuit
R = Resistance offered by the circuit
P = 2 watts
R = 30 Ω
I =?
2Watts = \(I^{2}\)x30Ω
\(I = \sqrt{\frac{2Watts}{30} }\)
I = 0.2581 Ampere.
The current through a resistor is inversely proportional to its resistance value. Resistance is a measure of resistance to the flow of current in an electrical circuit. Resistance is measured in ohms, represented by the Greek letter omega.
Electric current is the flow of charge through matter. The material or conductor through which current flows is often a metal wire, but current can also flow through some gases, liquids, and other materials. The circuit can be wired in two ways. Current is the speed at which charge flows. Resistance is the tendency of a material to resist the flow of electrical charges.
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What term generally describes small chunks of rocks and debris in space? PLEAS HURRY!
A) meteorites
B) meteoroids
C) meteors
D) meteorides
Answer:
B) meteoroids. The key word here is "generally." Not when it enters the atmosphere or hits the surface of the Earth.
Explanation:
Block X of mass 4M travels at a speed 5v0 toward block Y of mass M, which is initially at rest. After block X elastically collides with block Y, block X has a speed of 3v0 in the same direction as before the collision. What is the speed of block Y immediately after the collision
Answer:
Explanation:
Initial velocity of block X
u₁ = 5 v₀ ,
Initial velocity of block Y
u₂ = 0 ,
Final velocity of block X
v₁ = 3 v₀
Final velocity of block Y
v₂ = ?
Mass of block X
m₁ = 4 M
Mass of block Y
m₂ = M .
For elastic collision , velocity for Y is given by the following expression
v₂ = \(\frac{(m_2-m_1)u_2}{ m_2 +m_1} + \frac{2m_1u_1}{m_1+m_2}\)
= \(\frac{(M-4M)\times 0}{ M +4M} + \frac{2\times 4M\times 5v_0}{4M+M }\)
= 8v₀ .
The change in the velocity in a collision can be determined by its initial and final velocities.
After the collision, the velocity of block Y will be 8v0.
Velocity After CollisionGiven that Block X has an initial velocity of 5v0, the mass of 4M and has a final velocity after the collision is 3v0.
Block Y has an initial velocity of 0v0 as it is at rest before the collision and has a mass of M.
Let us consider that the initial velocity of block X can be represented by u_x and its final velocity by v_x. The initial velocity of block Y can be represented by u_y and its final velocity by v_y.
Then after the collision, the final velocity of Block Y can be given below.
\(v_y = \dfrac {(M - 4M)u_y} {M+4M} + \dfrac {2\times 4M \times u_x}{M+4M}\)
\(v_y = \dfrac {(-3M)\times 0}{5M} + \dfrac {8M\times 5}{5M}\)
\(v_y = 0 + 8\)
\(v_y = 8 v_0\)
Hence we can conclude that, after the collision, the velocity of block Y will be 8v0.
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A ball is rolling down a hill. Wich action would slow the ball down?
You have been contracted to map the Ryerson Campus at a scale of 1:1,000 using 1:3,000 photographs. It is required that you use photogrammetric techniques to perform the mapping using scanned (i.e., digitized) aerial photographs. The aerial photographs are taken with a focal length of 152.000 mm and have a 230mm by 230mm format. The aerial camera has both side and corner fiducials. The camera calibration information is available on a camera calibration report. Answer the following questions keeping in mind that you must choose a scanning resolution (in microns or dpi).
1. You must perform a fiducial transformation (i.e., interior orientation) using a 2-D transformation. What fiducial transformation model would you use and why? What magnitude of residuals would you expect?
2. If you adopted a local Cartesian coordinate system, which of the following image coordinate corrections would you apply and what would be their expected order of magnitude?
principal point offsets,
radial lens distortion,
atmospheric refraction,
earth curvature.
An aerial photographic image's corners, edge-centers, or both may contain a series of marks known as fiducial marks. These traces are recorded on the original film by the camera.
What are the purposes of fiducial marks?Fiducial markers are tiny metal objects, usually made of gold, that are positioned inside or close to a tumor to help direct the placement of radiation beams during therapy. They are about the size of a grain of rice.
Fiducial markers: how do they function?Tiny metal things are called fiducial markers (about the size of a grain of rice). They assist your healthcare professionals in aligning the radiation beams and guarantee that your radiation therapy is administered consistently.
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Fiducial marks are a set of marks that can be found in the corners, edge-centers, or both of an aerial photographic image. The camera captures these traces on the original film.
Given the Ryerson Campus is at a scale of 1:1000
Then the photographic scale (s) = 1:3000
The focal length of camera (f) = 152mm = 0152m
The format is (k) = 230 x 230mm = 0.23m
the photographic scale (s) = F/H where H is the image height
1/3000 = 0.152 /H Then H = 456m
Assume that there is longitudinal overlap as P1 = 60% and side to side overlap as 30%. Therefore margin of ground photograph = (1-P1) x k/s
(1-0.6) x 0.23/1/3000 = 276mm
Now width of ground photograph = (1-0.3) x 0.23/1/3000 = 483m
Hence the central points are plotted within the area range in 276m x 483m magnitude.
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Consider the baby being weighed in Figure 4.25.
Figure 4.25
(a) What is the mass of the child and basket if a scale reading of 104 N is observed?
kg
(b) What is the tension T in the cord attaching the child to the scale?
N
(c) What is the tension T' in the cord attaching the scale to the ceiling, if the scale has a mass of 0.500 kg?
N
(d) Draw a sketch of the situation indicating the system of interest used to solve each part. The masses of the cords are negligible. (Do this on paper. Your instructor may ask you to turn in this work.)
The mass and tension due to the system are as follows:
The mass of the child and scale = 10.6 kgThe tension T, in the cord attaching the child to the scale = 104N The tension T', in the cord attaching the scale to the ceiling T' = 108.9 NWhat is tension?Tension is a type of pulling force due transmitted by means of a string or cable.
Force = mass * acceleration due to gravitya) The mass of the child and scale = 104/9.81 = 10.6 kg
b) The tension T, in the cord attaching the child to the scale = scale reading = 104N
c) The tension T', in the cord attaching the scale to the ceiling = scale reading + weight of scale
T' = 104 + (0.5 * 9.81)
T' = 108.9 N
d) The sketch is attached in the picture
In conclusion, the tension is force exerted on the cord due to the weight of the scale and the baby.
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What is the kinetic energy of a 46 gram bullet traveling at 200.0 m/s?
The 46 gramme bullet's kinetic energy is 460 Joules at 200.0 m/s.
How is kinetic energy calculated?Kinetic energy is directly related to an object's mass and the square of its velocity: K.E. = 1/2 m v2. The kinetic energy is measured in kilograms-meters squared per second squared if the mass is measured in kilogrammes and the velocity is measured in metres per second.
KE is equal to \(1/2 * m * v2\), where m is the object's mass and v is its speed.
By substituting the provided values, we obtain:
KE is equal to 1/2 x 0.046 kg x (200.0 m/s)2.
KE = 460 J
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Two
objects attract each other gravitationally
a force of 50 10 10 N when they are
apart.
If the mass of one object is
2.00 kg, what is the mass of the other
Object?
with
0.20m
M2 = 0.665 kg
The mass of other object is 0.665 kg
Solution:To solve this, we must apply Newton's law of universal gravitation, which states that the force of gravity between two massive bodies 1, 2, is proportional to their masses M1 and M2 and inversely proportional to the square of the distance d between them:
F = (GM1M2) / D²
Here G = 6.67 × 10⁻¹¹ Nm²/kg²
F = 50×10⁻¹⁰N
M1 = 2.00kg
D = .20 m
by substituting values ,
50×10⁻¹⁰N =(( 6.67 × 10⁻¹¹ Nm²/kg²)(2.00kg)M2) / (.20 m)²
50×10⁻¹⁰ = 1.334 × 10⁻¹⁰ M2 /( .20)²
(50×10⁻¹⁰) (.20)² = 1.334 × 10⁻¹⁰ M2
2 ×10⁻¹⁰ = 1.334 × 10⁻¹⁰ M2
M2 = 1.334 × 10⁻¹⁰ / 2 ×10⁻¹⁰
M2 = 0.665 kg
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Identifying Sources of Error in the Experiment Which factors could be potential sources of error in the experiment? Check all that apply. energy lost in the lever due to friction color of the soda bottle used in the experiment visual estimation of height of the beanbag temperature of the lab at the time of the experiment position of the fulcrum for the lever affecting transfer of energy?
The color of the soda bottle used in the experiment and temperature of the lab at the time of the experiment are not likely to have a significant impact on the outcome of the experiment.
What is Energy?
Energy is a fundamental concept in physics that refers to the ability of a system to perform work. It can be defined as the capacity of a physical system to do work or produce heat. Energy can exist in many different forms, such as mechanical, thermal, electromagnetic, and chemical energy. It can be transferred between objects or converted from one form to another, but it cannot be created or destroyed. The SI unit of energy is the joule (J), but other units such as kilowatt-hours (kWh) and calories (cal) are also commonly used.
Energy lost in the lever due to friction, visual estimation of height of the beanbag, and position of the fulcrum for the lever affecting transfer of energy could be potential sources of error in the experiment.
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What is space mostly composed of?
Each of the following figures shows a person (not to scale) located on Earth at either 40°N or 40°S latitude. Rank the figures based on how much time the person spends in daylight during each 24-hour period, from most to least. To rank items as equivalent, overlap them.
The ranking is based on the tilt of the Earth's axis and its orbit around the Sun. The figure at 40°N in June receives the most daylight because it is located at a high latitude during the summer solstice in the Northern Hemisphere. The Earth's axis tilts towards the Sun, resulting in longer days and shorter nights. The figure at 40°S in December receives a moderate amount of daylight as it is located at a lower latitude during the summer solstice in the Southern Hemisphere.
The figure at 40°N in December experiences less daylight because it is located at a high latitude during the winter solstice in the Northern Hemisphere, with shorter days and longer nights. Lastly, the figure at 40°S in June receives the least amount of daylight as it is located at a lower latitude during the winter solstice in the Southern Hemisphere, where the days are shortest and the nights are longest. Based on the information given, the ranking of figures based on the amount of daylight they experience in a 24-hour period, from most to least.
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The neurocognitive model of dreaming argues that dreams:
A. reflect the waking concerns and preoccupations of the dreamer.
B. represent the fulfillment of repressed wishes and urges.
C. have no meaning whatsoever and simply reflect random neural firings in the brainstem.
D. contain images that disguise the dream's true psychological meaning.
Dreams Often Feature Intense Emotions
Dreams Often Feature Intense EmotionsIn some instances, these emotions can become so intense that they interrupt the dream or cause the dreamer to wake abruptly. The three most common emotions that become intensified by dreams are anxiety, fear, and surprise.
dream
dreamFirst, let examined the definition of dream according to Sigmund Freud “dream is the disguised fulfilment of a repressed wish. Dreams are constructed like a neurotic symptom: they are compromises between the demands of a repressed impulse and the resistance of a censoring force in the ego” (Freud, 28).
Bright light therapy is used to gradually shift sleeping patterns to what we consider normal. For treatment, the timing of light exposure is critical. For DSPS, the light must be delivered to the retina as soon after spontaneous awakening as possible to achieve the desired effect.
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If you have just used a velocity selector for electrons and you wish to use it to choose
positrons with the same speed, do you have to change any settings which are related to
electric field and magnetic field on the velocity selector? Explain your answer with the aid
of labelled diagram
Answer:
Explanation:
Yes, the settings related to electric and magnetic fields need to be changed to select positrons with the same speed as electrons in a velocity selector.
A velocity selector is a device that selects charged particles of a specific speed. It consists of perpendicular electric and magnetic fields. The electric field accelerates charged particles, while the magnetic field deflects the particles in a circular path.
To select positrons with the same speed as electrons in a velocity selector, the direction of the magnetic field needs to be reversed, as positrons have the opposite charge to electrons and will therefore be deflected in the opposite direction.
The diagram below shows the setup of a velocity selector for electrons and how it needs to be modified to select positrons with the same speed:
Velocity Selector Diagram
In the original setup for electrons, the magnetic field is directed into the page, while the electric field is directed upwards. Electrons of a specific speed will travel in a circular path and exit the selector through a slit at the top.
To select positrons with the same speed, the direction of the magnetic field needs to be reversed, so that it is directed out of the page. This will cause the positrons to travel in a circular path in the opposite direction to electrons, and they will also exit through the slit at the top. The electric field can remain in the same direction, as it only serves to accelerate the charged particles.
What is. the speed of 525-kg giraffe galloping with kinetic energy of 4200 J?
Given
Mass of the giraffe, m=525 kg
Kinetic energy, K=4200 J
To find
The speed of the giraffe
Explanation
let the velocity be v
We know kinetic energy is given by
\(K=\frac{1}{2}mv^2\)Putting the value
\(\begin{gathered} 4200=\frac{1}{2}\times525\times v^2 \\ \Rightarrow v=\frac{4m}{s} \end{gathered}\)Conclusion
The speed is 4 m/s
if a bird catches its prey from a height which was initially at rest then momentum is conserved for?
Bird
Prey
Both
None
For the two animals involved (bird and its prey), the momentum of both animals is conserved.
What is principle of conservation of linear momentum?
The principle of conservation of momentum states that if two objects collide, then the total momentum before and after the collision will be the same if there is no external force acting on the colliding objects.
Initial momentum = final momentum
Thus, for the two animals involved (bird and its prey), the momentum of both animals is conserved.
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How many ohms of resistance must be present in a circuit that has 50 volts and a current of 2 amps.
Answer:
25 ohms
Explanation:
Hi there!
Ohm's law states that \(V=IR\) where V is voltage, I is current and R is resistance.
Plug the given information into Ohm's law (V=50, I=2) and solve for R
\(V=IR\\50=2R\)
Divide both sides by 2 to isolate R
\(\frac{50}{2}= \frac{2R}{2} \\25=R\)
Therefore, there are 25 ohms of resistance present in this circuit.
I hope this helps!
A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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what would happen to the surface temperature on Earth if large amounts of carbon dioxide were removed from the atmosphere?
Answer:
If carbon emissions stopped, the oceans catch up with the atmosphere, the Earth's temperature would rise about another 1.1F (0.6C).
Explanation:
2. Circle the best answer:
1000 Newtons
1000 Newtons
A. The forces shown above are PUSHING / PULLING forces.
B. The forces shown above are WORKING TOGETHER/OPPOSITE FORCES.
C. The forces are EQUAL/NOT EQUAL.
D. The forces DO / DO NOT balance each other.
E. The resultant force is 1000 N TO THE RIGHT / 1000 N TO THE LEFT/ZERO.
F. There IS/IS NO motion.
According to the information we can infer that the forces are PULLING forces, OPPOSITE FORCES, EQUAL, forces DO balance each other, the resultant force is ZERO, and there IS NO motion.
How to explain each element in the image?According to the information of the image, we can conclude that the forces shown above are PULLING forces because they involve pulling a rope on each side. Also, the forces shown above are OPPOSITE FORCES because they act in opposite directions, pulling the rope towards different sides.
On the other hand, the forces are EQUAL in magnitude because each side exerts a force of 1000 Newtons. Additionally, the forces DO balance each other because they have the same magnitude and act in opposite directions. The individuals on each side are exerting equal forces, resulting in a balanced system.
Finally, the resultant force is ZERO because the forces are equal in magnitude and act in opposite directions. The combined effect of the forces is no net force or resultant force and there IS NO motion because the forces are balanced, resulting in a net force of zero. In a balanced system, the objects will remain at rest or in a state of uniform motion.
Note: This question is incomplete. Here is the complete information:
Attached image
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a double-decker london bus (figure 1) might be in danger of rolling over in a highway accident, but at the low speeds of its urban environment, it's plenty stable. the track width is 2.05 m. with no passengers, the height of the center of gravity is 1.45 m, rising to 1.73 m when the bus is loaded to capacity. What are the critical angles for both the unloaded and loaded bus?
When the bus is fully loaded, the center of gravity rises to 1.73 m, and the critical angles are 35.3 degrees for the unloaded bus and 30.6 degrees for the loaded bus, respectively.
Center of gravity: What is it?Theoretically, the body's total weight is concentrated at a location called the center of gravity.
What distinguishes the center of mass from the center of gravity?The main distinction between the centers of mass and gravity is that the center of gravity refers to the location where the total weight of the body is balanced, whereas the center of mass refers to the location where the body's complete mass is directed.
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Write 5.34 x 10^3 in standard form.
\(\\ \bull\tt\dashrightarrow 5.34\times 10^3\)
\(\\ \bull\tt\dashrightarrow 534\times 10^{-2}\times 10^3\)
\(\\ \bull\tt\dashrightarrow 534\times 10^{-2+3}\)
\(\\ \bull\tt\dashrightarrow 534\times 10^1\)
\(\\ \bull\tt\dashrightarrow 534\times 10\)
\(\\ \bull\tt\dashrightarrow 5340\)
Mrs Turner has a scale drawing of her apartment.IN the scale drawing the lenght of her apartment is 6.25 inches and the width is 2.75 onches. If Mrs. Turner used the scale factor 1 inc/18ft, what would the area of the apartment be?
The area of Mrs. Turner's apartment is approximately 0.05304 square feet.
To find the area of Mrs. Turner's apartment, we need to convert the measurements from the scale drawing to the actual measurements in feet, using the given scale factor of 1 inch/18 feet.
Length of apartment in feet = 6.25 inches × (1 foot/18 inches) = 0.34722 feet
Width of apartment in feet = 2.75 inches × (1 foot/18 inches) = 0.15278 feet
Now, we can calculate the area of the apartment in square feet by multiplying the length and width:
Area of apartment in square feet = Length × Width = 0.34722 feet × 0.15278 feet = 0.05304 square feet
Therefore, the area of Mrs. Turner's apartment is approximately 0.05304 square feet.
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2. A student walks 3 blocks East, 2 blocks North, 1 block West, and then 2 blocks
South.
a) What is the total distance traveled?
Answer:
8 blocks.
Explanation:
Given that,
A student walks 3 blocks East, 2 blocks North, 1 block West, and then 2 blocks South.
We need to find the total distance traveled by the student. The distance covered by an object is equal to the sum of the total path covered. So,
Distance = 3 blocks + 2 blocks + 1 block + 2 blocks
= 8 blocks
So, the distance traveled by the block is 8 blocks.
The arrow strikes a deer in the woods with the speed of 55 m/sec at an angle of 315 degrees. Calculate the Horizontal and vertical components of the arrow’s velocity.
Answer:
100 m
Explanation:
Which resistors in the circuit must always have the same voltage? A. A and D B. C and D C. B and C D. A and B
Answer:
(C) The voltage across B and C must be the same because they have a common connection at either end.