An object of 1 kpc across subtends an angle of 1 arc second at a distance of 187,514.5 Mpc and a redshift of 0.1.
To determine the distance and redshift for an object of 1 kpc across subtending an angle of 1 arc second, we can use the formula:
θ = 206,265 × D / (d × (1+z))
where θ is the angle in arc seconds, D is the physical size of the object in kpc, d is the distance to the object in Mpc, and z is the redshift.
Substituting the given values of D = 1 kpc, θ = 1 arc second, and solving for d and z, we get:
d = 206,265 × D / (θ × (1+z)) = 206,265 × 1 / (1 × (1+z)) = 206,265 / (1+z) Mpc
Solving for z, we get:
z = (206,265 / d) - 1 = (206,265 / (206,265 / (1+z))) - 1 = (1+z) - 1 = z
Thus, we can set z equal to the redshift, and solve for d using the formula above.
Substituting the given values of D = 1 kpc and θ = 1 arc second, we get:
d = 206,265 × 1 / (1 × (1+z)) = 206,265 / (1+z) Mpc
To find the redshift, we need to know the spectral lines of the object. If we assume that the object has a spectral line at a rest wavelength of 500 nm (which corresponds to a green color), and the observed wavelength is shifted to 550 nm (which corresponds to a yellow-green color), then we can use the formula for redshift:
z = Δλ / λrest = (λobserved - λrest) / λrest = (550 - 500) / 500 = 0.1
Substituting z = 0.1 into the formula for distance, we get:
d = 206,265 / (1+0.1) Mpc = 187,514.5 Mpc
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You and a friend go to a nearby rifle range in order to practice your marksman skills. You are standing 20.3 m behind your friend when she fires her rifle horizontally. If the air temperature at the range is 22°C and her rifle has a muzzle velocity of 891.6 m/s, determine how far the bullet travels before you hear the report of the rifle.
The bullet travels approximately 20.3 m before you hear the report of the rifle.
To determine the distance the bullet travels before you hear the report of the rifle, we need to calculate the time it takes for the sound to reach you.
First, let's calculate the time it takes for the bullet to reach you. Since the bullet is fired horizontally, it only experiences horizontal motion. The horizontal distance it travels is the distance between you and your friend, which is 20.3 m.
Using the equation:
distance = velocity × time
We can rearrange the equation to solve for time:
time = distance / velocity
time = 20.3 m / 891.6 m/s
time ≈ 0.0228 s
Now, let's calculate the distance the sound travels in 0.0228 seconds. The speed of sound in air at 22°C is approximately 343 m/s.
distance = velocity × time
distance = 343 m/s × 0.0228 s
distance ≈ 7.82 m
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a sealed bottle of water was taken from a refrigerator and left in a warm kitchen. explain in the terms of its molecules what happened to the thermal energy and temperature of the water in a few minutes
Answer:
Explanation:
The sealed bottle serves as an open system for the water molecules, thus heat energy can be exchanged with its surroundings. When the bottle is placed in a warm environment, there would be a gradual increase in the thermal energy of the molecules of water due to a change in the temperature of its surroundings.
Thus, the molecules of water closer to the boundary of the bottle absorbs heat, becomes lighter and changes position. This gradual process continues until all molecules attains an average temperature which equals that of the surroundings of the bottle.
Therefore, both the thermal energy and temperature of the water increases.
A student writes: “When I rub my dry hands together on a cold morning, they warm up. However, when I repeat this with soapy water my hands don’t warm up as much.” Explain these observations by considering the energy stores and transfers involved.
Answer:
Its not getting as hot because water and soap can act as a lubricant and it would not heat up easily because of the soapy water.
Answer:
there is less friction when your hands are soapy
Explanation:
During a magic trick, a magician twirled a ball on a string horizontally at a constant rate. He then doubled the length of the string but maintained the rate at which the ball rotated. Which of the following factors remained constant? A angular velocity B centripetal acceleration с centripetal force
Correct option is C, Centripetal force remains constant.
Centripetal Force -
Any force that changes the direction of motion toward the center of a circular motion is known as a centripetal force. The part of the force that produces the centripetal force is the part that is perpendicular to the velocity.
A net force that keeps an object moving in a circular motion is known as a centripetal force.
Centripetal force has the formula =mv2r. The newton or kgms2 is the measure of force.
A centripetal force is applied to any item travelling in a circle (or along a circular path). In other words, the object is being physically pushed or pulled in the direction of the circle's center. This is the necessary centripetal force.
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A rifle bullet is going 2760 ft/s and hits a tree. It slows to 0 ft/s in 0.13sec. What was its
acceleration?
The initial velocity of the rifle bullet is 2760 ft/s. It comes to rest after hitting the tree in 0.13 seconds.
We are supposed to find the acceleration of the rifle bullet given the initial velocity and time taken to come to rest.
Therefore, we can use the formula to calculate acceleration (a) from the given values of velocity (v) and time taken (t) which is given as follows:
a = (v - u) / t
Where,u = Initial Velocity
v = Final Velocity
a = acceleration
t = time taken
Now, substituting the given values of u, v, and t in the above formula, we get:
a = (v - u) / ta
= (0 - 2760) / 0.13
We get the acceleration of the rifle bullet as - 21230.76923076923 ft/s² (Rounding to 2 decimal places, it is -21230.77 ft/s²).
The acceleration of the rifle bullet is negative because it's coming to rest, indicating a deceleration.
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The forearm bone is part of the elbow joint. The bicep muscle in the forearm bends it against the weight of the forearm
and a weight that the hand is holding. This best describes muscle and bone working together as a
Joint
diaphragm
Sternocleidomastoid
lever
Answer: D. Lever
Explanation: The biceps muscle provides the effort (force) and bends the forearm against the weight of the forearm and any weight that the hand might be holding. Many muscle and bone combinations in our bodies are of the Class 3 lever type.
Pamela produced an electromagnet by wrapping a copper wire around an iron nail. When she connected the wire ends to a battery, she was able to lift 4 paper clips with her electromagnet. She decided that she wanted to modify the electromagnet so that it would lift 7 paper clips. She modified the electromagnet by removing the iron nail and replacing it with an aluminum nail. However, when she modified the electromagnet, it would not lift any paper clips.
Explain why Pamela's modification caused the electromagnet to lose its magnetic properties.
how many washers or paper clips can be picked up by each magnet. The one which picks up the most is the strongest.
-Slowly bring each magnet close to a magnetic material (such as an iron pin). The one which attracts the pin from the farthest distance is the strongest.
-Construct a device such as in class (place a tongue depressor between two plastic cups, place each magnet on top of the tongue depressor, and then suspend a paperclip beneath it to see how many washers each magnet can hold
In which part of the EM spectrum do you see the colors red, orange, yellow, green, blue, indigo, and violet (ROYGBIV);
gamma rays
ultraviolet rays
microwaves
visible light
Answer:
gamma rays
Explanation:
hope it helps
Calculate the buoyant force on a 2.00-L helium balloon. (b) Given the mass of the rubber in the balloon is 1.50 g, what is the net vertical force on the balloon if it is let go
Answer:
Following are the solution to the given points:
Explanation:
In this question, some of the values are missing, that's why its solution can be defined as follows:
In point a:
Density of air \(\rho_{air} =1.29 \frac{kg}{m^3}\\\\\)
Density of helium \(\rho_{helium} =0.178 \frac{kg}{m^3} \\\\\)
The volume of the helium balloon \(V= 2L\)
\(\to V= 2 \times 10^{-3}\)
Formula:
\(F_B = e_a V g\\\\\)
\(= 1.29 \times 2 \times 10^{-3} \times 9.81\\\\ = 0.0253098 \ N\)
where g is the acceleration due to gravity
In point b:
\(m_g= 1.5 \ g\)
Formula:
\(F_{net}=F_B - (m_r + \rho_h \ v )g\)
\(= 0.0253098 - (1.5 \times 10^{-3} + 0.178 \times 2 \times 10^{-3} \times 9.81)\\\\= 7.10244 \times 10^{-3} \ N\)
3. A bicycle accelerates from rest to 6m/s in a distance of 50m, calculate the acceleration. a 4. A person who is initially stationary is eventually walking at a speed of 1.5m/s after an acceleration of 0.5 m/s², calculate the distance it takes them to reach this speed. S V² √²+20S 1.5=²== 0+2x0.5x5 2.2508 = 2.25m/s 5. A car reaches a speed of 15m/s after an acceleration of 2m/s² over a distance of 44m, calculate the initial speed.
3. The acceleration of the bicycle is 0.36 m/s²
4. The distance traveled by the person is 2.25 m
5. The initial speed of the car is 7 m/s
3. How do i determine the acceleration of the bicycle?The acceleration of the bicycle can be obtained as follow:
Initial velocity (u) = 0 m/sFinal velocity (v) = 6 m/sDistance (s) = 50Acceleration (a) = ?v² = u² + 2as
Inputting the given parameters, we have:
6² = 0² + (2 × a × 50)
36 = 0 + 100a
36 = 100a
Divide both side by 100
a = 36 / 100
a = 0.36 m/s²
Thus, the acceleration is 0.36 m/s²
4. How do i determine the distance?The distance traveled by the person can be obtain as follow:
Initial speed (u) = 0 m/sFinal speed (v) = 1.5 m/s Acceleration(a) = 0.5 m/s²Distance (s) =?v² = u² + 2as
1.5² = 0² + (2 × 0.5 × s)
2.25 = 0 + s
s = 2.25 m
Thus, we can conclude that the distance is 2.25 m
5. How do i determine the initial speed?The initial speed of the car can be obtain as follow:
Final speed (v) = 15 m/sAcceleration (a) = 2 m/s²Distance (s) = 44 mInitial speed (u) = ?v² = u² + 2as
15² = u² + (2 × 2 × 44)
0 = u² + 176
Collect like terms
u² = 225 - 176
u² = 49
Take the square root of both sides
u = √49
u = 7 m/s
Thus, the initial speed of the car is 7 m/s
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An object moves from point A to B to C to D and finally to A
along the circle shown in the figure below.
a) Find the distance covered by the moving object.
b) Find the magnitude of the displacement of the object.
Answer:
a) The distance covered by the moving object is approximately 18.85 km
b) The magnitude of the displacement of the object is 0 (no displacement)
Explanation:
From the drawing, we have;
The sale of the drawing is 1 unit = 1 km
The radius of the circle in the drawing along which the object moves = 3 units
Therefore;
The radius of the circle along which the object moves, r = 1 km/unit × 3 units = 3 km
a) The distance covered by the object that moves from point A to B to C to D and finally to A is equal to the circumference of the circle
Therefore;
The distance covered by the moving object, d = 2·π·r
By pugging the value for r = 3 km
d = 2 × π × 3 km = 6·π km ≈ 18.85 km
The distance covered by the moving object, d ≈ 18.85 km
b) The displacement = The object's change in position
The initial position of the object = Point A
The final position of the object = Point A
Therefore, the displacement of the object, A = No displacement = 0 (No difference between the initial and final location of the object
A wire that is cold has less resistance than a wire that is hot
True
False
What is a food chain? (site 1)
Answer:
food chain is a process of how food is transported to the plant and then to the animal that eats the animal. there are primary, secondary, and tertiary and then decompose.
Explanation:
plz mark my answer as the brainliest
Answer:
A hierarchical series of organisms each dependent on the next as a source of food.
Explanation:
Hope this helps!! plz mark brainliest-Lily ^_^ ( food chain also known as the Circle Of Life)
When a 65 kg skydiver jumps from a plane, her speed steadily increases until air
resistance provides a force that balances the force due to free fall. How fast is the
skydiver falling if her kinetic energy at the moment is 704 x 10- J?
Correct value of kinetic energy is 704 × 10³ J
Answer:
v = 147.18 m/s
Explanation:
At any point/moment during the fall, the sky diver will possess kinetic energy with the formula;
KE = ½mv²
Where;
m is mass
v is velocity
We are given;
m = 65 kg
KE = 704 × 10³ J
Thus;
704 × 10³ = ½ × 65 × v²
v² = (2 × 704 × 10³)/65
v² = 21661.53846153846
v = √21661.53846
v = 147.18 m/s
what do you mean by solar energy?
Answer:
Solar energy is radiant light and heat from the Sun that is harnessed using a range of technologies such as solar power to generate electricity, solar thermal energy including solar water heating, and solar architecture.
A football player threw a football with a velocity of (3.0 m/s x + 5.0m/s y). How far did it travel horizontally?
The horizontal distance travelled by the football is 3.1 m.
What is the angle of projection of the ball?
The angle of projection of the football is calculated as follows;
tan ( θ ) = Vy / Vx
where;
Vy is the velocity of the ball in the vertical directionVx is the velocity of the ball in the horizontal directiontan ( θ ) = 5 / 3
tan ( θ ) = 1.667
θ = arc tan (1.667)
θ = 59⁰
The resultant velocity of the ball is calculated as follows;
v = √ (Vx² + Vy²)
v = √ (3² + 5²)
v = 5.83 m/s
The horizontal distance travelled by the football is calculated as follows;
x = v² sin(2θ) /g
where;
v is the resultant velocityg is acceleration due to gravityθ is the angle of projection of the ballx = [ (5.83)² sin(2 x 59) /9.8 ]
x = 3.1 m
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suppose water is raised by capillary action to a height of 8.95 cm in a glass tube. refer to the angle values given in the table to answer the questions. enter a positive number for height if the water is raised above the surrounding water level and a negative number if it is pushed below. what height will water reach in a paraffin tube of the same radius? paraffin tube: cm what height will water reach in a silver tube of the same radius? silver tube: cm question credit: openstax college physics
Water will rise by 1.47 cm in a silver tube of the same radius.
Capillary action is the phenomenon of a liquid rising in a narrow tube due to the combination of adhesive and cohesive forces. The height to which the liquid rises depends on the radius of the tube and the surface tension of the liquid.
In this problem, water is raised by capillary action to a height of 8.95 cm in a glass tube.
To determine the height to which the water will rise in a paraffin tube or a silver tube of the same radius, we need to use the angle of contact between the liquid and the solid surface.
The angle of contact is the angle at which the liquid meets the solid surface.
It depends on the nature of the liquid and the solid. If the angle of contact is less than 90 degrees, the liquid will wet the surface and rise in the tube.
If the angle of contact is greater than 90 degrees, the liquid will not wet the surface and will be pushed down.
The table given in the problem provides the angle of contact for water with glass, paraffin, and silver. We can use these angles to calculate the height to which water will rise in tubes of the same radius.
For a paraffin tube, the angle of contact between water and paraffin is 106 degrees. Since this angle is greater than 90 degrees, water will be pushed down in a paraffin tube.
The height to which water will be pushed down can be calculated using the formula:
h = (2T cos θ) / (ρgr)
where T is the surface tension of water, θ is the angle of contact, ρ is the density of water, g is the acceleration due to gravity, and r is the radius of the tube.
Substituting the values, we get:
h = (2 x 0.0728 N/m x cos 106°) / (1000 kg/m³ x 9.81 m/s² x 0.5 x 10⁻² m) = -0.51 cm
Therefore, water will be pushed down by 0.51 cm in a paraffin tube of the same radius.
For a silver tube, the angle of contact between water and silver is 90 degrees. Since this angle is less than 90 degrees, water will wet the surface and rise in a silver tube. The height to which water will rise can be calculated using the same formula:
h = (2T cos θ) / (ρgr)
Substituting the values, we get:
h = (2 x 0.0728 N/m x cos 90°) / (1000 kg/m³ x 9.81 m/s² x 0.5 x 10⁻² m) = 1.47 cm
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You would like to confirm Netwon's second law by running an experiment. You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude?
Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.
There is some other force present. This additional force is different for the two objects and accounts for the fact that the objects land at different times.
Newton's second law is not relevant in determining when an object will land on the ground.
One object must be heavier than the other and must therefore experience a greater gravitational acceleration.
Answer:
You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude? Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.
Explanation:
You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude? Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.
You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude? Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.
For a certain 12- v car battery ( e = 12.6 v ), the terminal voltage drops to 8.34 v when the starter draws 86.2 a . what is the internal resistance of the battery?
The internal resistance of the battery is 0.049 \(\ohm\)Ω
How can we calculate the value of the internal resistance?To calculate the internal resistance we are using the formula,
E = V + Ir
where,
E = Emf of the car battery.
V = The terminal voltage drops of the car battery.
I = The current floes through the battery.
Here,
E = 12.6 V.
V = 8.34 V.
I = 86.2 A.
We have to calculate the value of internal resistance = r
Now we put the known values in the above equation we get,
E = V+Ir
Or, Ir= E-V
Or, r= \(\frac{E-V}{I}\)
Or, r= \(\frac{12.6-8.34}{86.2}\)
Or, r = 0.049 \(\ohm\)Ω
So from the above calculation we can conclude that the internal resistance of the battery is \(\ohm\)0.049Ω
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Explain how each of the following factors affects resistance through a wire:
•Conductivity
•thickness
•length
•temperature
Resistance through a wire is affected by several factors including conductivity, thickness, length, and temperature.
Conductivity refers to the ability of a material to conduct electricity. The higher the conductivity of a wire, the lower its resistance. This is because a highly conductive wire allows for a larger flow of electrons, making it easier for electricity to pass through.
Thickness also affects resistance. A thicker wire has a lower resistance compared to a thinner wire because it has more surface area for the electrons to flow through. This results in less resistance as the electrons do not have to struggle to pass through a narrow space.
The length of a wire also plays a role in resistance. A longer wire has a higher resistance compared to a shorter wire because the electrons have to travel a longer distance, which results in more collisions with atoms and ions in the wire, thereby impeding the flow of electricity.
Temperature can also affect resistance. Generally, as the temperature of a wire increases, its resistance increases too. This is because the atoms and ions in the wire gain more energy when heated, which results in more collisions with electrons, making it more difficult for them to pass through the wire. However, there are some materials that exhibit a decrease in resistance with an increase in temperature, such as superconductors.
In summary, conductivity, thickness, length, and temperature all affect resistance through a wire. A wire with high conductivity, thickness, and short length, and a low temperature will have low resistance.
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How many stars in the star rating label of an electrical appliance should be used? Explain your answer.
Answer:
5 Stars
Explanation:
Because every Star from 1 to 5 vary energy consumption of the electrical device...So 5 star product uses a very less energy compared to 1 star product...
Hope it is helpful
There are 0 to 5 star are used in the star rating label of electrical appliance.
What is stars label in electrical appliance?The appliance is more energy efficient if it has more stars on the Energy Rating Label. To perform at the same level as comparable models of the same size or capacity, efficient appliances require less electricity. A model will use less energy and cost you less to run if it is more energy efficient.
Example a 3-star refrigerator saves a lot more energy compared to a 2 star.
Number of stars in the star rating label of an electrical appliance should be used is five for most efficient electrical device.
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2. A motorcycle starts at rest and moves a distance of 350 m. If it has a constant acceleration of 4.55m/s2, what is
its final velocity?
Answer:
Vf = ≈56.436 m/s
Explanation:
We'll need to use the equation:
Vf^2 = Vi^2 + 2aΔx
Plugging in what we know, we get:
Vf^2 = (0)^2 + 2(4.55)(350)
Finally, some algebra:
Vf^2 = 3185
Vf = ≈56.436
a farsighted woman has a near point of 70.0 cm. what power contact lens (when on the eye) will allow her to see objects 27.3 cm away clearly?
A contact lens with a +3.014 diopters power will enable a farsighted woman with a near point of 70.0 cm to see objects clearly at a distance of 27.3 cm.
We have do = 23cm and di = -75cm
So 1/f = 1/do + 1/di = 1/23 + 1/(-75) = .03014
So f = 1/.03014=33.17
So power = 1/0.3317 = +3.014Diopters (converging lens)
In optics, a diopter represents the magnifying power of a lens or lens system. The power of a lens is proportional to unity (one) divided by the focal length (see lens), so the power of a lens in diopters is mathematically equal to 1 meter is divided by the focal length. A healthy human eye can concentrate on an object or picture that is 1/40 of a meter away with an optical power of roughly 40 diopters. A average young person's eye has an additional 20 diopters of adjustment.
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when a knowledgeable amateur astronomer tells you that she has a 14-inch telescope, what does the number 14 refer to?
When a knowledgeable amateur astronomer tells you that she has a 14-inch telescope, the number 14 refers to the diameter of the telescope’s objective lens.
A telescope is a device used to view distant objects by utilizing electromagnetic radiation to either magnify their apparent size or gather more light than the human eye can. Telescopes are used for scientific, commercial, and amateur purposes. The telescope comprises an objective lens or mirror and an eyepiece to magnify the images created by the objective. Most telescopes have a viewfinder to make it simpler to aim the telescope precisely at the object of interest. They may also have a motorized mount to track celestial objects as they move across the sky.
Telescopes come in a variety of sizes, designs, and shapes and they range from large observatory telescopes to handheld amateur models. They are often classified into two types, reflecting and refracting telescopes and the size of a telescope is determined by the diameter of its objective lens or mirror. The bigger the diameter, the more light the telescope can collect, and the clearer the image. The diameter of the objective is the most significant aspect of a telescope when it comes to observing the heavens. For instance, a 14-inch telescope has an objective lens with a diameter of 14 inches, this large lens is capable of collecting a lot of light and providing clear images, making it a perfect tool for viewing the night sky.
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do you add the initial position and final position to get distance?
Does red or green light have more energy.
Answer: Green Light
Explanation:
The color green has a higher frequency than the color red and the higher the frequency the more energy. If you looks at a rainbow you'll see red on one end and violet on the other. Red has the least energy Violet has the most.
(b) if one micrometeorite (a sphere with a diameter of 1.30 10-6 m) strikes each square meter of the moon each second, how many years would it take to cover the moon to a depth of 1.20 m? (hint: consider a box on the moon 1.00 m on a side and 1.20 m deep, and find how long it will take to fill the box.)
The time required to cover the Moon to a depth of 1.20 meters with micrometeorites.
To find out how long it would take to cover the Moon to a depth of 1.20 meters with micrometeorites, we can calculate the volume of the Moon and then divide it by the volume of one micrometeorite. Let's break down the calculation step by step:
Calculate the volume of the Moon:
The average radius of the Moon is approximately 1.737 ×10⁶ meters. Using the formula for the volume of a sphere, V = (4÷3)πr³, we can calculate the volume of the Moon.
\(V_{moon}\) = (4÷3)π(1.737 × 10⁶)³
Calculate the volume of one micrometeorite:
The diameter of the micrometeorite is given as 1.30 ×10⁽⁻⁶⁾ meters, which means the radius is half of that.
\(r_{meteorite}\) = (1.30 × 10⁽⁻⁶⁾)÷2
Using the formula for the volume of a sphere, V = (4÷3)πr₃, we can calculate the volume of one micrometeorite.
\(V_{meteorite}\) = (4÷3)π((1.30 × 10⁽⁻⁶⁾)÷2)³
Calculate the number of micrometeorites needed to fill the Moon:
To find the number of micrometeorites required to fill the Moon, we divide the volume of the Moon by the volume of one micrometeorite.
\(N_{meteorites}\) = \(V_{moon}\) ÷ \(V_{meteorite}\)
Calculate the time to fill the Moon:
Since one micrometeorite strikes each square meter of the Moon each second, we can equate the number of micrometeorites needed to fill the Moon to the number of seconds it would take.
Time = \(N_{meteorites}\) ÷ (1 m²/s)
Convert seconds to years:
Finally, we convert the time in seconds to years by dividing by the number of seconds in a year (assuming 365.25 days in a year and 24 hours in a day).
\(Time_{years}\) = Time ÷ (365.25 days/year × 24 hours/day × 3600 seconds/hour)
Performing these calculations will give us the time required to cover the Moon to a depth of 1.20 meters with micrometeorites.
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Using a cable with a tension of 1350 N , a tow truck pulls a car 5.00 km alond a horizontal roadway. (a) how much work does the cable do on the car if it puls horizontally ? if it pulls at 35.0 degrees above the horizontal ? (b) how much work does the cable do on the tow truck in both cases of part (a)? (c) how much work does gravity do on the car in part (a)?
Using a cable with a tension of 1350 N , a tow truck pulls a car 5.00 km alone a horizontal roadway. Therefore,
(a) Cable work: 6,750,000 J horizontally.
(b) Cable work: 6,308,250 J at 35.0° above horizontal.
(c) No work by gravity.
To calculate the work done by the cable in each scenario, we need to consider the angle between the direction of the force applied and the displacement.
(a) If the cable pulls horizontally (0° above the horizontal):
In this case, the angle between the force and the displacement is 0 degrees, so the work done can be calculated as:
Work = Force * Displacement * cos(Ф)
Work = 1350 N * 5000 m * cos(0°)
Work = 1350 N * 5000 m * 1
Work = 6,750,000 J
The cable does 6,750,000 Joules of work on the car when it pulls horizontally.
(b) If the cable pulls at 35.0 degrees above the horizontal:
In this case, the angle between the force and the displacement is 35.0 degrees, so the work done can be calculated as:
Work = Force * Displacement * cos(Ф)
Work = 1350 N * 5000 m * cos(35.0°)
Work = 1350 N * 5000 m * 0.819
Work = 6,308,250 J
The cable does approximately 6,308,250 Joules of work on the car when it pulls at 35.0 degrees above the horizontal.
(c) The work done by gravity on the car is zero because gravity acts vertically downward, perpendicular to the displacement along the horizontal roadway. Therefore, the gravitational force does not contribute to the work done on the car in this scenario.
In both cases (a) and (b), the cable does the same amount of work on the tow truck as on the car since they are connected by the cable. So the work done by the cable on the tow truck would be equal to the values calculated above: 6,750,000 J in case (a) and 6,308,250 J in case (b).
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Label each of the following photons as ones that can or cannot be absorbed by this atom. The value stated is the energy of the photon.
2.00x10-19)
1.00x 10-19
8.00 x 10-19
7.00x 10-19)
9.00x10-19
Using the Bohr model, we can calculate what photons were absorbed giving transitions in the Hydrogen atom; the correct answer is
The photon to be absorbed are: 2.00 10⁻¹⁹ J, Balmer serie in the visible
1.00 10⁻¹⁹ J, Paschem serie in infrared
The other photons cannot be absorbed
The energy of the photons is given by the PlanK equation
E = h f
where h is Plank's constant and f is the frequency of the photons
For the absorption by an atom, the photons must have an energy equal to greater than the difference in energy of the levels involved, in case the energy of the detachment of an electron must be greater than or equal to the ionization energy.
In this exercise it is not indicated which specific atom is being analyzed, but the most common of them is Hydrogen.
The ionization energy of hydrogen is
E = 13.6 eV (1.6 10-19 J / 1 eV) = 21.76 10-9 J
in atomic transitions it is ususal to work in units of lectronVolts and if necessary reduce to Joule.
when checking the given values none of these photons can ionize the hydrogen atom.
The energy of the atomic levels is given by the Bohr model for the hydrogen atom
E = \(- \ \frac{13.606}{n^2}\) [eV]
where n is a number in between and the amount in brackets are units , therefore the transition between two levels is given by
ΔE = 13.606 ( \(\frac{1}{n_o^2} - \frac{1}{n_f^2}\) ) [eV]
where n₀ and n_f are integers corresponding to the initial and final states of the transition, in the table we see the values for several transitions
n₀ n_f ΔE [eV] ΔE [10⁻¹⁹ J]
1 2 10.2 16.3
2 3 1.89 3.0
3 4 0.66 1.1
let's compare these results with the energies of the incident photons
a) the photon of 2.00 10⁻¹⁹ j
can give transition between the state n = 2 and n = 3 that corresponds to the Balmer series, in the visible of the electromagnetic spectrum
b) the photon of 1.00 10⁻¹⁹ J
It is absorbed giving transitions between levels n = 3 to n = 4 which corresponds to a Paschem series in the infrared of the electromagnetic spectrum
c) photons 8 10-19, 7 10-19 and 9 10-19 J
they cannot be absorbed by the hydrogen atom and they do not correspond to any permitted transition according to the Bohr model.
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The action spectrum is broader than the absorption spectrum because:_________
The action spectrum is broader than the absorption spectrum because the action spectrum represents the overall efficiency of photosynthesis, while the absorption spectrum only shows the wavelengths of light absorbed by pigments.
In the action spectrum, a wider range of wavelengths contributes to photosynthesis, as it takes into account the energy conversion process and the involvement of accessory pigments that can absorb different wavelengths and transfer energy to the main photosynthetic pigments.
This results in a broader action spectrum compared to the absorption spectrum.
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