Atom 1 has 19 electrons 19 protons and 20 neutrons atoms 2 has 19 electrons , 20 neutrons and 19 protons

Answers

Answer 1

Answer:

Atom 1: Potassium (K)

Atom 2: Same thing

Explanation:

Potassium has an atomic number of 19 and mass number of 39.0983.


Related Questions

Complete and balance the following nuclear transformation.

Flerovium--289 decays to form Gadolinium--160, 5 neutrons and what other isotope

Answers

Flerovium--289 decays to form Gadolinium--160, 5 neutrons, and Francium--124.

The given decay of Flerovium--289 can be represented as:

Flerovium--289 → Gadolinium--160 + X + 5n

Here, X represents the unknown isotope that is formed during the decay.

To balance this nuclear transformation, we need to ensure that the total atomic and mass numbers are equal on both sides of the equation.

Atomic number balance:

On the left-hand side, Flerovium has an atomic number of 114, so the sum of the atomic numbers on the right-hand side must also be 114. Gadolinium has an atomic number of 64, so the sum of the atomic numbers of X and the 5 neutrons must be 50. Since neutrons do not have an atomic number, X must have an atomic number of 50. Therefore, X is the element tin, which has the atomic number 50.

Mass number balance:

On the left-hand side, Flerovium--289 has a mass number of 289, so the sum of the mass numbers on the right-hand side must also be 289. Gadolinium--160 has a mass number of 160, and each neutron has a mass number of 1, so the sum of the mass numbers of X and the 5 neutrons must be 129. Francium--124 has a mass number of 124, so X must have a mass number of 5. Therefore, X is the isotope tin--125, which has a mass number of 125.

The balanced nuclear transformation is:

Flerovium--289 → Gadolinium--160 + Tin--125 + Francium--124 + 5n

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QUESTION 6 Consider the following reaction between the diatomic and monatomic forms of iodine: I2 (g) <-> 2I (g) When 0.095 M I2 is initially placed in a previously empty container and sealed, the system slowly reaches equilibrium. When equilibrium is reached, it is found that there is an equilibrium concentration of 0.0055 M of the monatomic form of iodine. Calculate the (unitless) equilibrium constant Kc. Round your answer to two sig figs, and express it in scientific notation.

Answers

Answer: The equilibrium constant is \(3.3\times 10^{-4}\)

Explanation:

Initial concentration of \(I_2\) = 0.095 M  

The given balanced equilibrium reaction is,

                            \(I_2(g)\rightleftharpoons 2I(g)\)

Initial conc.          0.095 M       0 M

At eqm. conc.     (0.095-x) M   (2x) M

Given : 2x = 0.0055

x = 0.00275

The expression for equilibrium constant for this reaction will be,

\(K_c=\frac{[l]^2}{[I_2]}\)  

Now put all the given values in this expression, we get :

\(K_c=\frac{(0.0055)^2}{(0.095-0.00275)}\)

\(K_c=\frac{(0.0055)^2}{0.09225}=0.00033\)

Thus the equilibrium constant is \(3.3\times 10^{-4}\)

what are the colors of a rainbow

Answers

The colors of a rainbow, in order, are: red, orange, yellow, green, blue, indigo, and violet
Red orange yellow green blue purple indigo

This force occurs when there is an attractive and repulsive force between two poles.

Answers

Answer:

Magnetic force

Explanation:


A solution is prepared by dissolving 0.131 g of a substance in 25.4 g of water. The molality of the solution is determined by freezing point
depression to be 0.056 m. What are the moles of the substance?

Answers

The mole of the substance, given the data from the question is 0.0014 mole

What is molality?

This is simply defined as the mole of solute per kilogram of water. Mathematically, it is expressed as

Molality = mole / mass (Kg) of water

How to determine the mole of the substanceMass of water = 25.4 g = 25.4 / 1000 = 0.0254 KgMolality = 0.056 mMole of substance =?

Mole = molality × mass of water

Mole of substance = 0.056 × 0.0254

Mole of substance = 0.0014 mole

Thus, the mole of the substance is 0.0014 mole

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A 5 kg ball is traveling at the same speed as a 10 kg ball. Compared to with 5 kg ball, the 10 kg ball has (2 points)

Answers

Answer: twice the momentum

Explanation:

If an athlete weighs 159 lb and has 15.0% % body fat by weight, how many pounds of fat does the athlete's body contain?

Answers

Answer:

23.85

Explanation:

is over of percent over 100

\(\frac{x}{159}\)x\(\frac{15}{100}\)

15 x 159 = 2385

2385 ÷ 100 = 23.85

If an athlete weighs 159 lb and has 15.0% % body fat by weight, the athlete's body contains approximately 23.84 pounds of fat.

To calculate the number of pounds of fat in the athlete's body, we can use the following steps:

Convert the athlete's weight from pounds to kilograms:

159 lb × 0.4536 kg/lb = 72.1224 kg

Calculate the weight of the athlete's body fat:

72.1224 kg × 0.150 = 10.81836 kg

Convert the weight of body fat from kilograms to pounds:

10.81836 kg × 2.2046 lb/kg = 23.8447 lb

Therefore, the athlete's body contains approximately 23.84 pounds of fat.

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How does charge change with dielectric?

Answers

On changing dielectric, charge changes directly. It is directly proportional to dielectric permittivity of free space.

In electromagnetism, a dielectric (or dielectric medium) is an electrical insulator that can be captivated by an applied electric field. At the point when a dielectric material is put in an electric field, electric charges don't course through the material as they do in an electrical conduit, since they have no inexactly bound, or free, electrons that might float through the material, however rather they shift, just somewhat, from their typical balance positions, causing dielectric polarization.

Due to dielectric polarization, positive charges are dislodged toward the field and negative charges change in the course inverse to the field (for instance, assuming that the field is moving lined up with the positive x hub, the negative charges will change in the negative x course). This makes an inside electric field that decreases the general field inside the actual dielectric. Assuming a dielectric is made out of pitifully reinforced particles, those atoms become energized.

We know that Q=CV where Q is charge, C is capacitance and V is the voltage of capacitor.

Since, capacitance is equal to= (∈A₀) /d  where ∈ is permittivity of free space or dielectric value.

If we increase dielectric value, capacitance will increase. When capacitance increase ,charge will also increase.

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A particular beer is 65.0% ethanol by volume . If a single bottle of beer contains a total of 750.0 mL of beer, what volume, in mL of ethanol (C₂H₆O), are present in the bottle?
SHOW CONVERSION

Answers

The volume in mL of ethanol (C₂H₆O) present in the bottle is 487.5L

HOW TO CALCULATE VOLUME OF ETHANOL:

According to this question, a particular beer is 65.0% ethanol by volume. This means that the beer contains 65/100 of ethanol.

If a single bottle of beer contains a total of 750.0 mL of beer, the volume of ethanol in the bottle is calculated as follows:

= 65/100 × 750

= 65 × 7.5

= 487.5mL

Therefore, volume in mL of ethanol (C₂H₆O) present in the bottle is 487.5L

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In the SI systems of unit the mole is one of the seven base units. It is frequently used in chemical calculations. However a mole of something is just a particular quantity of it. It is a not a unit of a measure in the way that meter seconds and kilograms are. Calculations performed with a number of moles of a sepsis could also be performed with the number of particles of a substance. Based on this information do you think that the mo should be considered a base unit in Si system? Explain why or why not.

In the SI systems of unit the mole is one of the seven base units. It is frequently used in chemical

Answers

answer

the mole should be considered as an SI unit because this quantity is used to determine many other units of measure such as Liters for volume, the pressure of a system in pascals. it is useful in all chemical studies

When a solution of sodium hydroxide is mixed with iron (II) chloride, a green precipitate is formed. What is the balanced equation for that reaction?

Answers

The balanced chemical equation for the reaction is:

2NaOH(aq) + FeCl₂(aq) --> 2NaCl(aq) + Fe(OH)₂(s)

What is a chemical equation?

Chemical equations are representations of chemical reactions using symbols and formula of the reactants and products.

The reactants are located on the left side while the products are located on the right side.

Reactants —> Products

The balancing of chemical equations follows the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.

How to write the balanced equation

Sodium hydroxide => NaOH

Iron (II) chloride => FeCl₂

2NaOH(aq) + FeCl₂(aq) --> 2NaCl(aq) + Fe(OH)₂(s)

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Determine the theoretical yield, limiting reactant when 0.50 g of Cr and 0.75 g of H3PO4 react according to the following chemical equation?

2Cr + 2 H3PO4 --> 2CrPO4 + 3H2

Answers

The theoretical yield of the reaction is 1.13 g. The acid is the limiting reactant.

What is the theoretical yield?

In a given chemical reaction, the theoretical yield can only be obtained from the balanced reaction equation. We have been given the balanced reaction equation in the question so we can work from there.

Number of moles of Cr =  0.50 g /52 g/mol = 9.6 * 10^-3 moles

Number of moles of acid =  0.75 g/98 g/mol = 7.7 * 10^-3 moles

Given that the reaction is 1:1, the limiting reactant would be the acid.

The theoretical yield is obtained from;

Number of moles of product * molar mass of product

We substitute to obtain;

7.7 * 10^-3 moles * 147 g/mole (since the reaction is 1:1)

= 1.13 g

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`Pb(NO3)2 (aq) + LiBr(aq) →

Answers

Answer:

PbBr2 + LiNO3

And goodluck

What are the properties of gas

Answers

Answer:

1) easy compressed

2) fills its container

3) far more space

Explanation:

Low Density. Gases contain scattered molecules that are dispersed across a given volume and are therefore less dense than in their solid or liquid states. ...
Indefinite Shape or Volume. Gases have no definite shape or volume. ...
Compressibility and Expandability. ...
Diffusivity. ...
Pressure.

A sample of nitrogen gas occupies a volume of 255 mL at 0.974 atm pressure. what volume will it occupy at 1.05 atm pressure?

Answers

The sample of nitrogen gas will occupy 236.54 mL of volume at 1.05 atm pressure.

Give a brief account on Boyle's Law.

Boyle's law is the ideal law that defines the relationship between pressure and volume of gases. A law is given if the temperature is kept constant. Pressure and volume exhibit an inverse relationship.

The Boyle's Law is given as:

P₁V₁ = P₂V₂

Given,

Initial pressure (P₁) = 0.974 atm

Initial volume (V₁) = 255 mL

Final pressure (P₂) = 1.05 atm

Final volume = V₂

The final volume at 1.05 atm is calculated by substituting values in Boyle's Law as:

P₁V₁ = P₂V₂

0.974 × 255 = 1.05 V₂

V₂ =  248.37 ÷ 1.05

= 236.54 mL

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A quantity of 1.922 g of methanol (CH3OH) was burned in a constant-volume bomb calorimeter. Consequently, the temperature of the water rose by 4.20 Ce … lsius. If the heat capacity of the bomb plus water was 10.4 kJ/degree Celsius, calculate the molar heat of combustion of methanol

Answers

The formula for calculating the amount of energy or heat released is:

ΔH = C ΔT

where ΔH is heat of combustion, C is heat capacity, while ΔT is change in temperature

ΔH = 8.69 kJ / °C * (5.14°C)

ΔH = 44.67 kJ

Then we calculate the moles of CH3OH which has molar mass of 32.04 g/mol:

moles = 1.922 / 32.04 = 0.05999 mol

SO the molar heat of combustion is:

ΔHm = 44.67 kJ / 0.0599875 mol

ΔHm = 744.60 kJ / mol

If I poured 1 mole of acetic acid into a pool, and 1 mole of acetic acid into a cup, would it take the same amount of drops of NaOH solution to neutralize both regardless?

Answers

Answer:

If you poured 1 mole of acetic acid into a pool and 1 mole of acetic acid into a cup, it would not take the same amount of drops of NaOH solution to neutralize both. This is because the concentration of acetic acid in the pool would be much lower than in the cup, and therefore more NaOH would be required to neutralize the cup.

To understand why this is the case, we need to look at the concept of molarity. Molarity is defined as the number of moles of solute per liter of solution. Therefore, if you have 1 mole of acetic acid in a cup with a volume of 0.1 L, the molarity of the solution would be 10 M (1 mole / 0.1 L). If you have 1 mole of acetic acid in a pool with a volume of 1000 L, the molarity of the solution would be 0.001 M (1 mole / 1000 L).

When you add NaOH to an acidic solution like acetic acid, a neutralization reaction occurs. The general equation for this reaction is:

acid + base → salt + water

In the case of acetic acid and NaOH, the specific equation is:

CH3COOH + NaOH → CH3COONa + H2O

This reaction shows that one mole of NaOH reacts with one mole of acetic acid to produce one mole of sodium acetate and one mole of water.

Therefore, if you add drops of NaOH to both the cup and the pool containing acetic acid, it will take more drops to neutralize the cup than it will to neutralize the pool. This is because there are more moles of acetic acid per liter in the cup than in the pool.

C3H8O dissolved in water

Answers

If C3H8O is dissolved in water, it would be expected to be a strong electrolyte.

What is a strong electrolyte?

A strong electrolyte is a solute or solution (already an electrolyte) that can completely dissociates in solution.

C3H8O is one of those compounds expected to be a strong electrolyte.

Thus, if C3H8O is dissolved in water, it would be expected to be a strong electrolyte.

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Problem 1. What masses of 15% and 20% solutions are needed to prepare 200 g of 17% solution?
Problem 2. What masses of 18% and 5% solutions are needed to prepare 300 g of 7% solution?
Problem 3. 200 g of 15% and 350 g of 20% solutions were mixed. Calculate mass percentage of final solution.
Problem 4. 300 g of 15% solution and 35 g of solute were mixed. Calculate mass percentage of final solution.
Problem 5. 400 g of 25% solution and 150 g of water were mixed. Calculate mass percentage of final solution.

Answers

Problem 1:

we need 80 g of the 15% solution and 120 g of the 20% solution.

Let x be the mass of the 15% solution needed and y be the mass of the 20% solution needed.

x + y = 200 (total mass of the two solutions)

0.15x + 0.2y = 0.17(200) (total amount of solute in the two solutions)

Solving these equations,  x = 80 g and y = 120 g.

Therefore, we need 80 g of the 15% solution and 120 g of the 20% solution.

Problem 2:

we need 120 g of the 18% solution and 180 g of the 5% solution.

Let x be the mass of the 18% solution needed and y be the mass of the 5% solution needed.

x + y = 300

0.18x + 0.05y = 0.07(300)

Solving these equations, x = 120 g and y = 180 g.

Therefore, we need 120 g of the 18% solution and 180 g of the 5% solution.

Problem 3:

The mass percentage of the final solution is 135 g/550 g × 100% = 24.55%.

The total mass of the final solution is 200 g + 350 g = 550 g.

The total amount of solute in the final solution is:

0.15(200 g) + 0.20(350 g) = 65 g + 70 g = 135 g.

Therefore, the mass percentage of the final solution is 135 g/550 g × 100% = 24.55%.

Problem 4:

The mass percentage of the final solution is 110 g/335 g × 100% = 32.84%.

The total mass of the final solution is 300 g + 35 g = 335 g.

The total amount of solute in the final solution is:

0.15(300 g) + 35 g = 75 g + 35 g = 110 g.

Therefore, the mass percentage of the final solution is 110 g/335 g × 100% = 32.84%.

Problem 5:

The mass percentage of the final solution is 18.18%.

Calculate the final mass of the solution:

Final mass = 400 g + 150 g = 550 g

Calculate the mass of solute in the 25% solution:

Mass of solute = 0.25 x 400 g = 100 g

Calculate the mass percentage of the final solution:

Mass percentage = (mass of solute ÷ final mass) x 100%

Mass percentage = (100 g ÷ 550 g) x 100%

Mass percentage = 18.18%

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List the 2 pKa's for H2SO4

Answers

No pKa1 because it is strong acid, pKa2 = 1.99

What is the definition of electron configuration. and thanks

Answers

Answer:

In atomic physics and quantum chemistry, the electron configuration is the distribution of electrons of an atom or molecule in atomic or molecular orbitals. For example, the electron configuration of the neon atom is 1s² 2s² 2p⁶, using the notation explained below

Explanation: welcome

please help

Why is there less air pressure at higher altitudes?

Air at higher altitudes is cooler and less turbulent.
Lighter air molecules float above heavier air molecules.
The warmer, lighter air rises, bringing cooler, heavier air to low altitudes.
Air at higher altitudes doesn't have as much air weighing down on it from above.

Answers

Answer:

The warmer, lighter air rises, bringing cooler, heavier air to low altitudes.

Air at higher altitudes doesn't have as much air weighing down on it from above.

Explanation:

In short - air pressure is the result of the cumulative force that air molecules act on objects below them due to Earth's gravity. The higher the altitude, the less air molecules there are to act a force below them, and therefore, there's less air pressure at higher altitudes.

Answer:

I believe it's the second option "Lighter air molecules float above heavier air molecules

Explanation:

I believe this because as altitude increases the amount of gas molecules decrease which makes the air less dense

5. Which element would form
covalent bond with Oxygen (0)
Sodium (Na)
Calcium (Ca)
Aluminum (AI)
Selenium (Se)

Answers

Na would be your answer

The period of a wave is directly proportional to the wavelength of the wave. True or False

Answers

The period of a wave is directly proportional to the wavelength of the wave. True

What is the relationship between a wave's wavelength and its period?

Period is the time it takes to complete one cycle of a wave, and wavelength is the distance between two identical locations in the neighbouring cycles of a wave. The number of cycles in a second is defined as frequency. In other terms, frequency = 1 / period.

An electromagnetic wave's wavelength is proportional to its frequency. Likewise, an electromagnetic wave's frequency is equal to the reciprocal of its period.

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A tapeworm living in the digestive system of a horse.

Answers

The tapeworm can cause inflammation and damage to the lining of the horse's intestines.

How does the tapeworm affect the horse in which it is living in?

A tapeworm living in the digestive system of a horse can impact the horse in a number of ways. The tapeworm can cause inflaming and impairment to the lining of the horse's intestines, leading to malabsorption of nutrients and potential weight loss. In severe cases, the tapeworm can also cause colic, which is a painful condition of the horse's gastrointestinal tract. Additionally, the tapeworm eggs can be shed in the horse's feces, which can contaminate pastures and potentially infect other horses or animals that graze in the same area.

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The entire question is:

How does A tapeworm living in the digestive system of a horse impact the horse? Also add a note on how other animals in the area might be infected because of this horse.

What trophic level has heterotrophs?
a only the second level
b all levels except the first
C only the first level
d only the last level

Answers

The answer should be letter B

A liquid ester used to flavour food is believed to be impure. What would be the best way of testing its purity?​

Answers

Answer:

Filter it

Explanation:

How many molecules are in 38.8g of C4H8O2?

Answers

Answer:

14

Explanation:

Convert 150 grams of NaOH to particles of NaOH

Answers

150 grams of NaOH is approximately equal to 2.256 x 10^24 particles of NaOH.

To convert grams of NaOH to particles of NaOH, we need to use the concept of molar mass and Avogadro's number. The molar mass of NaOH is calculated by adding the atomic masses of sodium (Na), oxygen (O), and hydrogen (H) together. It can be determined as follows:

Na: 22.99 g/mol

O: 16.00 g/mol

H: 1.01 g/mol

Molar mass of NaOH = (22.99 g/mol) + (16.00 g/mol) + (1.01 g/mol) = 40.00 g/mol

Now, we can use the molar mass to convert grams of NaOH to moles. Since 1 mole contains Avogadro's number (approximately 6.022 x 10^23) particles, we can determine the number of particles as follows:

150 g NaOH * (1 mol NaOH / 40.00 g NaOH) * (6.022 x 10^23 particles / 1 mol NaOH) ≈ 2.256 x 10^24 particles

It's important to note that this calculation assumes the substance is pure NaOH and that the molar mass and Avogadro's number are accurate.

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Changes in pressure can have a large effect on equilibrium systems containing gaseous components.

1. changing the concentration of gaseous components
2. adding an inert gas has no effect since the gas does not take part in the reaction, all partial pressures stay the same
3.changing the volume of the reaction vessel. This will cause a shift in the equilibrium position if the number of moles of gas is different on the reactant and product side (so Δn = n products - n reactants)

How would you change the volume for each of the following reactions to increase the yield of the product(s)?1. CaCO3(s) ⇋ CaO(s) + CO2(g) (increase, decrease, no change)2. S(s) + 3F2(g) ⇋ SF6(g) (increase, decrease, no change)3. Cl2(g) + I2(g) ⇋ 2ICl(g) (increase, decrease, no change)

Answers

Answer:

The correct option is 1, since by changing the partial pressures the gas pressures change, the gases go from the zones of higher partial pressure to the zones of lower partial pressure, an example of this is the homeostasis of the human pulmonary alveolus in gas exchange with CO2 and O2.

Explanation:

In the first it increases, in the second the volume is maintained, and in the third reaction it decreases.

Answer:

1. Increase volume.

2. No change.

3. No change.

Explanation:

Hello,

In this case, if we want to shift the reaction rightwards, based on the Le Chatelier's principle we would have to:

1. For this reaction:

\(CaCO_3(s) \rightleftharpoons CaO(s) + CO_2(g)\)

- Increase the volume or decrease the pressure, since there are more gaseous moles at the products.

2. For this reaction:

\(S(s) + 3F_2(g) \rightleftharpoons SF_6(g)\)

- Do nothing since it is not possible to achieve it as we have the same number of gaseous moles at both reactants and products.

3. For this reaction:

\(Cl_2(g) + I_2(g)\rightleftharpoons 2ICl(g)\)

- Do nothing since it is not possible to achieve it as we have the same number of gaseous moles at both reactants and products.

Regards.

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