Atrap and Bracken are two rival insurance companies. Atrap and Bracken have premiums of $150 and $100 and deductibles of $2,500 and $3,500 respectively. The average expense of surgery is $25,000.If after 1 year, 5 of the 1,000 people registered with Atrap have gone through surgery, where does Atrap stand in terms of gains or losses?

Answers

Answer 1

The premiums are the prices people pay to have the insurance coverage. The deductible is the amount one pays if he or she needs to use the insurance, in this case, if someone needs a surgery.

If 1,000 people register for Atrap, it's $150*1,000 = $150,000.

If 5 people need surgery, it's 5*25,000 = $125,000 in expenses.

Antrap has 2,500*5 = $12,500 in deductibles. That makes the expenses $112,500.

So, $150,000-112,500 = $37,500

Answer: Atrap has $37,500 gains.


Related Questions

How do you do this question?

How do you do this question?

Answers

Step-by-step explanation:

K is an upper bound for│f"(x)│on the interval [0, 1], so x ≤ 1.

Sine and cosine have maximums of 1, so an upper bound of │f"(x)│is:

│f"(x)│≤ (76 · 1 + 152 · 1 · 1)

│f"(x)│≤ 228

Joshua invested $750 in an account paying an interest rate of
3 1/4% compounded quarterly. Josiah invested $750 in an account paying an interest rate of 2 5/8 % compounded annually. After 18 years, how much more money would Joshua have in his account than Josiah, to the nearest dollar?

Answers

Due to the difference in the interest rate and the quarterly compounding, Joshua will have $212.24 more than Josiah.
Step-by-step explanation:
Giving the following information:
Joshua:
Initial investment (PV)= $750
Interest rate (i)= 0.0341/4= 0.008525
Number of periods (n)= 18*4= 72 quarters
Josiah:
Initial investment (PV)= $750
Interest rate (i)= 0.0285
Number of periods (n)= 18 years
To calculate the future value of each one, we need to use the following formula:
FV= PV*(1 + i)^n
Joshua:
FV= 750*(1.008525^72)
FV= $1,381.98
Josiah:
FV= 750*(1.0285^18)
FV= $1,169.74
Due to the difference in the interest rate and the quarterly compounding, Joshua will have $212.24 more than Josiah.

what would be the answers for these ????

what would be the answers for these ????

Answers

Answer:

Step-by-step explanation: the y would be 50

Please help this is due today!

Do not answer this with one answer ,blank, or a ridiculous answer.... this is serious please.

Please help this is due today! Do not answer this with one answer ,blank, or a ridiculous answer....

Answers

Answer:

perdita is correct

Step-by-step explanation:

perdita is correct because A isoceles triangle has two of the same. The triangle will just be very very thin

I need help plz....zzzzz

I need help plz....zzzzz
I need help plz....zzzzz

Answers

Problem 1

Answer:  Choice C) -511

---------------------------------------

Work Shown:

a1 = 9 = first termd = -7 = common difference

We decrease by 7 each time we need a new term

an = nth term

an = a1+d(n-1)

an = 9+(-7)(n-1)

an = 9-7n+7

an = -7n+16

a14 = -7*14+16

a14 = -82

Sn = sum of the first n terms of an arithmetic sequence

Sn = (n/2)*(a1+an)

S14 = (14/2)*(9+(-82))

S14 = -511  

================================================

Problem 2

Answer: Choice C)  \(a_n = -6(a_{n-1}), \ a_1 = -2.5\)

--------------------------------------

Explanation:

The nth term of a geometric sequence is a*r^(n-1)

a = first termr = common ratio

We're given that

a2 = 15 = second terma5 = -3240 = fifth term

Those two facts lead us to these two equations

a*r = 15a*r^4 = -3240

Divide the second equation over the first equation

The left hand sides would divide to r^3

The right hand sides divide to -216

Solving r^3 = -216 leads to r = -6

This leads to...

a*r = 15

a*(-6) = 15

a = 15/(-6)

a = -2.5

This points us at choice C as the answer. Choice C says that the nth term is found by multiplying the previous term by -6, which is tied directly to the common ratio.

My teacher gave me an extra credit assignment with 25 minutes left of class. It is extra credit, not a timed assessment. need done asap

My teacher gave me an extra credit assignment with 25 minutes left of class. It is extra credit, not

Answers

The answer is 19. JM and ML are equal to each other

Jo has a 10 GB monthly cell phone plan. Jo has used 8 GB in the first 10 days of the month. At that rate, how many GB will Jo use after a month of 30 days?

Answers

Answer:

Step-by-step explanation:

1st 10 days - 8 GB

2nd 10 days - 8 GB

3rd 10 days - 8 GB

________________

30 days    -  24 GB

Plz help 100 points
A soccer team scores an average of 11 goals per season. A double number line is drawn to figure out the average number of goals the team scores in 6 seasons. Which of the following statements is true about the diagram?

Both number lines increase by 6.
One number line increases by 1, and the other increases by 6.
One number line increases by 11, and the other increases by 1.
One number line increases by 11, and the other increases by 6.

Answers

Answer:

the answer is one line is increased by 1, and the other increased by 6

hope this helped :))

Answer:

the answer is one line is increased by 1, and the other increased by 6

Step-by-step explanation:

A Eurasian tree sparrow weighs 0.17 pounds. How many pounds are 4 eurasian tree sparrows and a 2-pound nest?

Answers

4 x (weight of sparrow) + 2lb nest = ?
4(0.17) + 2
= 0.68 + 2
= 2.68 pounds

Which decimal is equivalent to 201%?
210
2.01
2.10
0.201

Answers

Answer: 2.01

Step-by-step explanation:

A percentage is equal to x/100.

For example, 5% would be equal to 5/100.

5/100 = 0.05

So 201% = 201/100.

201/100 = 2.01

what is (9x+8)^2-54x+48y

Answers

Answer:

81x² + 90x + 48y + 64

Step-by-step explanation:

(9x+8)² = (9x+8)(9x+8) = 9x*9x + 9x*8 + 8*9x + 8*8 = 81x² + 72x + 72x + 64

             = 81x² + 144x + 64

then:

(9x+8)² -54x+48y = (81x² + 144x + 64) -54x + 48y = 81x² + 90x + 48y + 64

What should you substitute for x in the second equation (bottom equation) in order to solve the system by the substitution method?

What should you substitute for x in the second equation (bottom equation) in order to solve the system

Answers

We substitute -1+1/6y for x in the second equation (bottom equation) in order to solve the system by the substitution method.

The given system of equations are 2x-1/3y = -2...(1)

3x+y=1...(2)

We solve this system of equations by using substitution method.

Let us solve for x in equation to substitute it in equation (2).

2x=-2+1/3y

Divide both sides of equation by 2.

x=-1+1/6y

Now plug in the value of x in equation 2.

Hence, we substitute -1+1/6y for x in the second equation (bottom equation) in order to solve the system by the substitution method.

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Suma40grados 35 con
60grados7
er
ор
q' w
a' rty u
a s d f g h j k l ñ en español​

Answers

Answer:

Je ne sais pas sur quoi vous avez besoin d'aide, pourriez-vous préciser pour que je puisse vous aider ??

Step-by-step explanation:

HELP PLS !% POINTS!!

HELP PLS !% POINTS!!

Answers

Answer:

149 sq. ft

Step-by-step explanation:

For the triangle:

Base = 16-9 = 7 ft

Area of Triangle = 1/2 of  b.h

= 1/2 of 7 * 6

= 21 sq. ft

Area of Rectangle = l.b

= 5 * 16

= 128 sq. ft

Total Area = 149 sq. ft

Running at an average rate of 10 m/s, a sprinter ran to the end of a track and then jogged back to the starting point at an average of 5 m/s. The sprinter took 60 s to run to the end of the track and jog back. Find the length of the track.

d=300md is equal to 300 m

d=200md is equal to 200 m

d=600md is equal to 600 m

d=150md is equal to 150 m

Answers

9514 1404 393

Answer:

  200 m

Step-by-step explanation:

Let d represent the length of the track in meters. The relation of interest is ...

  time = distance/speed

Then the total time to run and walk back is ...

  60 = d/10 + d/5

  600 = d + 2d

  200 = d . . . . . . . divide by 3

The length of the track is 200 meters.

_____

200 m in 20 seconds is a world-record time for a woman; a very good time for a man.

√√96
√8
Ο 213
Ο 4
Ο 222
D. 12

968 213 4 222D. 12

Answers

Answer:

2sqr3, the first option

Step-by-step explanation:

divide the polynomials x^2-10,000/x-100

Answers

Answer:

x+100

Step-by-step explanation:

x^2-10,000/x-100

x^2-10000 is a difference in squares and can be factored.

x^2-10000 = (x+100)(×-100).

(x+100)(x-100)/(x-100)

(x-100) cancel each other.

x+100 remains.

the unit rate for each option. 9. Option A: $15.40 for 3.5 lbs of gummy bears ​

Answers

The unit rate for Option A is $4.4 per pound of gummy bears.

The unit rate for each option is a mathematical expression that compares two quantities of different measures by dividing one quantity by the other.

The unit rate is used to determine how much an item costs per unit of measure.

To find the unit rate for each option, we can use the following formula: Unit rate = price ÷ weight Option A: $15.40 for 3.5 lbs of gummy bears Unit rate = 15.40 ÷ 3.5Unit rate = $4.4 per pound of gummy bears.

Therefore, the unit rate for Option A is $4.4 per pound of gummy bears.

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Here is the complete question given below:

The unit rate for each option. 9. Option A: $15.40 for 3.5 lbs of gummy bears. $7.65 for 1.8 Ibs of gummy bears.

I need help ASAP, this is with khan academy.

I need help ASAP, this is with khan academy.

Answers

Answer:

◉ No

Step-by-step explanation:

   a vertical line is not a function because it will not survive the vertical line test, VLT.

the VLT is a vertical line that touches functions, if it touches it twice or more, then it's not a function

=======================================

\(\textcopyright ELIZA \bullet22/09/'22\)

\(\#CARRYONLEARNING :)\)

what is the property of 3x(5x7)=(3x5)7

Answers

The property you are referring to is called the associative property of multiplication. According to this property, when multiplying three numbers, the grouping of the numbers does not affect the result. In other words, you can change the grouping of the factors without changing the product.

In the equation you provided: 3x(5x7) = (3x5)7

The associative property allows us to group the factors in different ways without changing the result. So, whether we multiply 5 and 7 first, or multiply 3 and 5 first, the final product will be the same.

NO LINKS!!! URGENT HELP PLEASE!!!!
Please help me with 23 and 25

Part 2: Using the information given in each diagram below, decide if any triangles are congruent, similar but not congruent, or not similar. If you claim the triangles are congruent or similar, create a flowchart justifying your answer

NO LINKS!!! URGENT HELP PLEASE!!!!Please help me with 23 and 25Part 2: Using the information given in

Answers

Answer:

23. Similar as well as congruent triangle

25. Conguent triangle

Step-by-step explanation:

NO LINKS!!! URGENT HELP PLEASE!!!!Please help me with 23 and 25Part 2: Using the information given in

Answers:

23. Not enough information

25. Congruent (by the HL theorem)

HL = hypotenuse leg

=============================================

Explanation for problem 23.

Check out figure 1 shown below.

I have marked the given diagram with light blue and light pink to show which angles are congruent.

Because lines UN and TC are parallel, we know the following alternate interior pairs are congruent.

angle UNC = angle TCN (light blue)angle UNL = angle TCH (light pink)

Therefore, we can establish one link of paired congruent angles of the triangles LNU and TCH. However, we cannot determine any other angle pairings. Why not? Because we don't know if segment UL is parallel to segment TH. If they were parallel, then we could establish something like angle LUN = angle CHT as one alternate interior pairing.

But again, we don't know if UL is parallel to TH. The arrow markers aren't shown for these segments.

Therefore, we simply don't have enough information to determine if the triangles are similar or congruent.

----------------------------------------

Explanation for problem 25.

Luckily this problem will provide sufficient info to prove the triangles KSR and ISR are congruent.

We start with the given info that KR = SI due to the identical tickmarks. This represents one node in the flowchart (see figure 2).

Another node is angle RKS = angle RIS because both are right angles, aka 90 degree angles.

A third node is SR = SR because of the reflexive property.

Those three nodes then feed into the final conclusion node that triangle KSR = triangle ISR. The reasoning is "HL theorem" where HL = hypotenuse leg. This theorem works for right triangles only.

Take note how I structured the proof so that it flows from top to bottom. The three nodes side by side are related so they share the same row.

There are many other ways to make the flowchart, so don't feel obligated to use this format. Use whatever works best for you.

NO LINKS!!! URGENT HELP PLEASE!!!!Please help me with 23 and 25Part 2: Using the information given in
NO LINKS!!! URGENT HELP PLEASE!!!!Please help me with 23 and 25Part 2: Using the information given in

Help

Identify the equation that represents a quadratic relationship
y =4x^2
y =4x^4
y =4x^3
y =4

Answers

The equation that represents a quadratic relationship is y = 4x^2. Option A.

A quadratic relationship is a mathematical relationship where the variable y is a function of the variable x raised to the power of 2. In other words, it is an equation in which the highest power of the variable is 2.

Let's analyze the given equations:

1. y = 4x^2: This equation represents a quadratic relationship because the variable x is raised to the power of 2. The term 4x^2 indicates that the relationship between x and y is quadratic.

2. y = 4x^4: This equation represents a quartic relationship, not a quadratic relationship. The variable x is raised to the power of 4, which indicates a higher degree relationship than quadratic.

3. y = 4x^3: This equation represents a cubic relationship, not a quadratic relationship. The variable x is raised to the power of 3, indicating a higher degree relationship.

4. y = 4: This equation represents a linear relationship, not a quadratic relationship. It is a constant equation where y is always equal to 4, regardless of the value of x. In a quadratic relationship, the variable x should have a power of 2. Option A.

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What is the value of 8x-25 when x is equal to 12?

Answers

Answer:

71

Step-by-step explanation:

Evaluate for x=12

(8)(12)−25

(8)(12)−25

=71

Answer:

71

Step-by-step explanation:

To evaluate \(8x - 25\) when \(x = 12\), we have to replace x with 12 in the expression:

\(8x - 25\)

⇒ \(8(12) -25\)

⇒ \(96 - 25\)

⇒ \(\bf 71\)

What is the product?
(-2x-9y²)(-4x-3)
O-8x²-6x-36xy²-27y²
O-14x²-36xy2 +27y²
O 8x2 +6x+36xy2 +27y²
O 14x²+36xy² +27y²

Answers

The value of the product expression (-2x-9y²)(-4x-3) is 8x² + 6x + 27y² + 36xy²

How to evaluate the product?

The expression is given as:

(-2x-9y²)(-4x-3)

Expand the expression

8x² + 6x + 27y² + 36xy²

Hence, the value of the product expression (-2x-9y²)(-4x-3) is 8x² + 6x + 27y² + 36xy²

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Can anyone help???????

Can anyone help???????

Answers

Answer:

80

Step-by-step explanation:

For every additional 10 hrs, you get 200 more dollars.

\(\bold{Heya...}\)

\(\sf{6 \: - \: (1 \: x \: 4) \: - \: 2}\)

Explain into your own words.

Thanks~

Answers

Answer:

 0

Explanation:

Given expression:

\(\sf 6 - (1 \times 4) -2\)

Use BODMAS method:

brackets, order, division, multiplication, addition, subtraction

First simplify variables inside brackets

\(\sf 6 - (4) -2\)

Then simply use subtract integers

\(\sf 0\)

\({ \qquad\qquad\huge\underline{{\sf Answer}}} \)

Let's get it done using Bodmas Rule ~

\(\qquad \sf  \dashrightarrow \: 6 - (1 \times 4) - 2\)

\(\qquad \sf  \dashrightarrow \: 6 - (4) - 2\)

\(\qquad \sf  \dashrightarrow \: 6 - ( 4 + 2)\)

\(\qquad \sf  \dashrightarrow \: 6 - 6\)

\(\qquad \sf  \dashrightarrow \: 0\)

We will get the end result 0, on simplification ~

Please help I’ll mark you as brainliest if correct!

Please help Ill mark you as brainliest if correct!

Answers

Step-by-step explanation:

x = number of quarters.

y = number of dimes.

z = number of pennies.

0.25x + 0.1y + 0.01× = 1.05

but it is not possible to find a combination of a subset of the coins to create exactly 1 (= the change for $1).

like to have only 3 quarters and 3 dimes (and no pennies). that makes $1.05, and no combination can create exactly $1.

as a consequence

x < 4 (because 4 quarters is $1, and more than 4 quarters is already more than $1.05).

z < 5 (because with 5 or more pennies, since the total sum is $1.05, if I simply remove 5 pennies, I get $1 with the other coins, no matter what combination they are).

with 1 or 2 or 3 or 4 pennies I cannot build a total sum of $1.05, as the other coins will can only build a sum that ends in 0 or in 5.

so, the sum of these other coins and 1, 2, 3, 4 pennies can never end in 5.

that means, we have 0 pennies.

that rules out to have 0 or 2 quarters, because then together with the dimes the sum can only end in 0 (and actually also give change for $1).

so, we can have only 1 or 3 quarters.

that means the solutions are

1 quarters and 8 dimes

or

3 quarters and 3 dimes.

1 quarter and 8 dimes (and 0 pennies) is the desired solution, because it contains more coins.

for the maximum amount of money built by coins not providing change for $1 we need to remember :

4 quarters are $1 (and would provide change for $1). so, we always need less than 4 quarters. but also at least 1 quarter to keep the sum from ending with a 0 (which would allow again to build $1).

10 dimes are $1 (and provide change for $1). we always need less than 10 dimes.

5 or more pennies would always allow to take away or fill up to create a sum that ends in 0 and therefore build $1. so, we always need less than 5 pennies.

that means again

1 or 3 quarters

max. 9 dimes

4 pennies.

if the the maximum possible sum would be higher than 1.19, then we could only increase in steps of 0.10 (dimes) : 1.29, 1.39, ...

if the sum is 1.29, I could remove 1 quarter and 4 pennies to make $1.

if it is 1.39, I could remove 1 quarter, 1 dime and 4 pennies to make $1.

and so on.

any sum >= 1 created incl. 4 or more quarters or 10 or more dimes or 5 and more pennies can always be reduced to a full $1.

$1.19 can only be built by 1 quarter and 9 dimes and 4 pennies, so that we cannot build $1 out of a subset, or by 3 quarters, 4 dimes and 4 pennies.

and 1 quarter, 9 dimes and 4 pennies has more coins.

(Need Help please and thank you!)

(Need Help please and thank you!)

Answers

The equation of the graph is

d. y = sqrt(x) + 2

How to complete the table

The table is completed by substituting the x to the function y = sqrt(x) + 2

When x = 0:

y = sqrt(0) + 2

y = 0 + 2

y = 2

When x = 1:

y = sqrt(1) + 2

y = 1 + 2

y = 3

When x = 4:

y = sqrt(4) + 2

y = 2 + 2

y = 4

When x = 9:

y = sqrt(9) + 2

y = 3 + 2

y = 5

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Convert
431 base 10 divided by 112base 10​

Answers

Answer:

543 i think?

Step-by-step explanation:

The lunch special at Omar's Restaurant is a sandwich, a drink and a dessert. There are 2 sandwiches, 2 drinks, and 2 desserts to choose from. How many lunch specials are possible?

Answers

Answer:

The number of lunch specials possible is 8.

Step-by-step explanation:

• If there are 2 sandwiches, 2 drinks, and 2 desserts to choose from and the lunch special is a sandwich, drink, and dessert:

• To find out the answer, we are going to say that we have sandwich a & sandwich b, drink a & drink b, and dessert a & dessert b:

1.) Sandwich a:

drink adessert a

2.) Sandwich a:

drink adessert

3.) Sandwich a:

drink bdessert b

4.) Sandwich a:

drink bdessert a

5.) Sandwich b:

drink adessert a

6.) Sandwich b:

drink a dessert b

7.) Sandwich b:

drink bdessert b

8.) Sandwich b:

drink bdessert a

Please mark me the Brainliest!?!

The number of lunch specials possible is 8.

What is the combination in maths?

Combinations are mathematical operations that count the number of potential configurations for a set of elements when the order of the selection is irrelevant. You can choose the components of combos in any order.

If there are 2 sandwiches, 2 drinks, and 2 desserts to choose from and the lunch special is a sandwich, drink, and dessert.

The total choices are 3 in that 2 options for every choice are available.

Thus total combination can be made = 2³

total combination can be made = 8

Therefore, the total number of possible lunch specials is 8.

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