(A)
Gravitational force
This law states that every massive particle in the universe attracts every other massive particle with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
The correct option is the direction marked as C, which indicates the direction of gravitational force on the object, represented by the black dot
(B)
Centripetal Force:
The centripetal force can be defined as the force exerted by the object when it is moving in a circular or curved path. Its direction is always towards the center of the circle, perpendicular to the tangent velocity. The diagram shows 4 possible options for the centripetal force acting on the object represented as a black dot.
The correct option is the direction marked as C, since it points inwards and ties the object to its circular motion.
If a ball leaves the ground with a velocity of 4.67 m/s,
how high does the ball travel?
Answer:
\(Vf^2=Vo^2+2aS\\(0m/s)^2=(4.67m/s)^2+(2*-10m/s^2)S\\-(4.67)^2 m^2/s^2=-20m/s^2*S\\S=(21.8089/20) m\\S=1.090445 m\\\)
When a skater pulls her arms in, it
reduces her moment of inertia from
2.12 kg m² to 0.699 kg-m². If she was
initially spinning 3.25 rad/s, what is
her final angular velocity?
The skater's final angular velocity is approximately 9.86 rad/s.
The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:
L = Iω
where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.
Initially, the skater has an angular momentum of:
L_initial = I_initial * ω_initial
Substituting the given values:
L_initial = 2.12 kg m² * 3.25 rad/s
The skater's final angular momentum remains the same, as angular momentum is conserved:
L_final = L_initial
The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:
L_final = I_final * ω_final
0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s
Solving for ω_final:
ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²
Hence, the skater's final angular velocity is approximately 9.86 rad/s.
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I’m testing if this app works.What is gravity?
Answer:
Gravity, or gravitation, is a natural phenomenon by which all things with mass or energy—including planets, stars, galaxies, and even light—are brought toward one another. On Earth, gravity gives weight to physical objects, and the Moon's gravity causes the ocean tides.
What does the measurement unit N stand for?
Explanation:
The newton (symbol: N) is the International System of Units (SI) derived unit of force.
Answer:
The newton is the SI unit of force, and is the force which will accelerate one kilogram one metre per second squared. The symbol of the newton in SI is N. The newton is also the unit of weight
Explanation:
I hope it helps
The word acid comes from the Latin word
Which of the following elements has properties different than the rest?
H
K
N
O
Answer:
I think K . If it not, then sorry.Hope I helped you.
Answer: The answer [b] or also known as k
Explanation:
PLEASE HELP I WILL MARK BRAINLYIST!!!!!!!!!
All of the matter in the universe formed after the big bang. Scientists
predicted that hydrogen and helium would be the most abundant elements.
What did scientists discover?
A. The universe has 73% hydrogen and 25% helium, which does not
support the big bang theory
B. Planets are made mostly of other elements, which does not
support the big bang theory
C. Stars are made mostly of other elements, which supports the big
bang theory
D. The universe has 74% hydrogen and 24% helium, which supports
the big bang theory.
Answer:
The answer is D. Here is proof . Plz mark brainliest
Explanation:
What is the wavelength of an FM radio
signal if the number on the dial reads 88.6
MHz? The speed of light is 3 x 108 m/s.
Answer in units of m.
V = 3.0 x 10⁸ m/s (This is the same for all types of electromagnetic waves)
f = 88.6 MHz = 8.86 x 10⁷ Hz
λ = ?
V = fλ
λ = V/f = (3 x 10⁸)/(8.86 x 10⁷)
= 3.4 m [Ans]
Hope this helps!
Light in the air is incident at an angle to the surface of (12.0 A) degrees on a piece of glass with an index of refraction of (1.10 (B/100)). What is the angle between the surface and the light ray once in the glass
The question is incomplete. You dis not provide values for A and B. Here is the complete question
Light in the air is incident at an angle to a surface of (12.0 + A) degrees on a piece of glass with an index of refraction of (1.10 + (B/100)). What is the angle between the surface and the light ray once in the glass? Give your answer in degrees and rounded to three significant figures.
A = 12
B = 18
Answer:
18.5⁰
Explanation:
Angle of incidence i = 12.0 + A
A = 12
= 12.0 + 12
= 14
Refractive index u = 1.10 + B/100
= 1.10 + 18/100
= 1.10 + 0.18
= 1.28
We then find the angle of refraction index u
u = sine i / sin r
u = sine24/sinr
1.28 = sine 24 / sine r
1.28Sine r = sin24
1.28 sine r = 0.4067
Sine r = 0.4067/1.28
r = sine^-1(0.317)
r = 18.481
= 18.5⁰
Derrick crawls 4 feet south, and then turns east and crawls 6 feet.
What distance did he cover?
What was his displacement?
Displacement is a vector quantity. The distance and displacement of the given object are 10 ft and 7.07 ft respectively.
Distance:
It can be defined as the change in position of the object. It is a scalar quantity.
Displacement = 4+6
Displacement = 10 ft
Displacement:It can be defined as the vector change in position overall change in position.It is a vector quantityVector quantity is the quantities that have both magnitude and direction.\(\rm Dislacement =\sqrt { 4^2 +6^2}\\\\ \rm Dislacement = 7.07 ft\)
Therefore, the distance and displacement of the given object are 10 ft and 7.07 ft respectively.
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What essential nutrient is so important and makes up approximately 80% of the body.
Protein
it's the main component of muscles, bones, organs ext.
An iron wire has a length of 1.50 m and a cross sectional area of 0.290 mm2. If the resistivity of iron is 10.0 ✕ 10−8 Ω · m and a potential difference of 0.700 V is maintained across its length, determine the current in the wire (in A).
Answer:
1.35 A
Explanation:
Applying,
V = IR
I = V/R..................... Equation 1
I = Current, V = Voltage, R = Resistance.
But,
R = Lρ/A............... Equation 2
Where L = Length of the wire, ρ = resistivity, A = Cross-sectional area of the wire.
Sustitute equation 2 into equation 1
V = AV/Lρ............... Equation 3
From the question,
Given: V = 0.7 V, A = 0.290 mm² = 2.9×10⁻⁷ m², L = 1.5 m, ρ = 10×10⁻⁸ Ω.m
Substitute these values into equation 3
I = (0.7× 2.9×10⁻⁷)/(1.5× 10×10⁻⁸ )
I = (2.03×10⁻⁷)/(15×10⁻⁸)
I = 1.35 A
During the earthquake, what we need to do to be safe,write steps.
(i) When you are in the classroom.
(ii) When you are out of danger
During an earthquake, it is important to take appropriate steps to ensure safety
Steps you can follow in two different scenarios(i) When you are in the classroom
Drop, Cover, and Hold On: Quickly drop to the ground, take cover under a sturdy desk or table, and hold on to it to protect yourself from falling objects and potential structural collapse.
Protect Your Head: If possible, use your arms to cover your head and neck to provide additional protection.
Stay Indoors: Remain inside the classroom until the shaking stops and it is safe to exit. Be prepared for aftershocks, which are smaller tremors that may occur after the main earthquake.
(ii) When you are out of danger:
Evacuate to Open Space: If you are no longer in immediate danger, move quickly to an open space away from buildings, trees, streetlights, and utility wires that may pose a risk of falling or collapsing.
Watch for Falling Debris: Be aware of your surroundings and watch out for any hazards such as falling debris, broken glass, or damaged infrastructure.
Stay Clear of Buildings: Avoid entering damaged buildings or structures as they may be unstable. Keep a safe distance until authorities confirm it is safe to enter.
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10 pointsWhat is the electric force between a 3.7 x 10^-6 C charge and a 4.9 x10^-6 C charge that are separated by a distance of .33 m?(Don't forget your units and whether the force is attractive or repulsive!!)Your answer
The electric force = 1.498N
It is an attractive force
Explanations:The force between two charges q₁ and q₂ separated by a distance r is calculated using the coulomb's law equation
\(F\text{ = }\frac{Kq_1q_2}{r^2}\)\(\begin{gathered} q_1\text{ = 3.7 }\times10^{-6}C \\ q_2\text{ = 4.9 }\times10^{-6}C \end{gathered}\)The distance r = 0.33 m
\(k\text{ = }9\text{ }\times10^9Nm^2/C^2\)Substituting these values into the formula above:
\(F\text{ = }\frac{9\text{ }\times10^9\times3.7\times10^{-6}\times4.9\times10^{-6}}{0.33^2}\)\(\begin{gathered} F\text{ = }\frac{163.17\times10^{-3}}{0.1089} \\ F\text{ = }1498.35\text{ }\times10^{-3} \\ F\text{ = }1.498N \end{gathered}\)Since the Force gotten is positive, it is an attractive force
& Linear exponsion & A metal scale is graduated at 0°c. bathat would be the time benyth of an objedt whit when measured with the scale at 25°C, reads som 9 For metal is 18x15 4/² C. in It t
The given information is insufficient to determine the change in length of the object at 25°C using the metal scale graduated at 0°C.
To solve this problem, we need to consider the concept of linear expansion. Most materials, including metals, expand when heated and contract when cooled. The amount of expansion or contraction depends on the coefficient of linear expansion (α) of the material.
The formula for linear expansion is:
ΔL = α * L * ΔT
where ΔL is the change in length, α is the coefficient of linear expansion, L is the original length, and ΔT is the change in temperature.
Given:
Coefficient of linear expansion for the metal scale (α) = 18 × 10^(-4) °C^(-1) (assuming it's the same as the metal of the object)
Temperature difference (ΔT) = 25°C - 0°C = 25°C
Original length (L) = unknown
We are asked to find the change in length (ΔL) of the object when measured at 25°C compared to its measurement at 0°C. Let's assume the object's original length at 0°C is L0.
ΔL = α * L * ΔT
ΔL = 18 × 10^(-4) °C^(-1) * L0 * 25°C
However, the given information is incomplete. The specific value of L0 or any other details about the object are not provided. Without knowing the original length of the object or any other relevant information, it is not possible to calculate the change in length or answer the question accurately.
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two particles with equal charge experiences a force of 12 nN where they are 30 cm apart. what is the magnitude of the charge on each particle
Considering the Coulomb's Law, the magnitude of the charge on each particle is 4.2426 C.
Definition of Coulomb's LawCoulomb's law or law of electrostatics is the relationship between the interactions of electric charges, that is, it explains the force experienced by two electric charges at rest.
This law says that the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them, expressed mathematically as:
\(F=k\frac{Qq}{d^{2} }\)
where:
F is the electrical force of attraction or repulsion. It is measured in Newtons (N).Q and q are the values of the two point charges. They are measured in Coulombs (C).d is the value of the distance that separates them. It is measured in meters (m).k is a constant of proportionality called the Coulomb's law constant. It depends on the medium in which the charges are located. Specifically for vacuum k is approximately 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\).The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.
Magnitude of the charge on each particleIn this case, you know that:
F= 12 nN= 1.8×10⁻⁸ N (being 1 nN= 1×10⁻⁹ N)k= 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\)Q= qd= 30 cm= 0.3 m (being 100 cm= 1 m)Replacing in the Coulomb's Law:
\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{Qq}{(0.3 m)^{2} }\)
Being Q=q:
\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{q^{2} }{(0.3 m)^{2} }\)
Solving:
1.8×10⁻⁸ N÷ 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\)= q²÷ (0.3 m)²
2×10⁻¹⁸ C²/m²= q²÷ (0.3 m)²
2×10⁻¹⁸ C²/m²= q²÷ 0.09 m²
2×10⁻¹⁸ C²/m² ×0.09 m²= q²
1.8×10⁻¹⁹ C²= q²
√1.8×10⁻¹⁹ C²= q
4.2426 C= q= Q
Finally, each charge has a value of 4.2426 C.
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If a 40 N block is resting on a rough horizontal table with a coefficient of static friction
If a 40 N block is resting on a rough horizontal table with a coefficient of static friction is 12 N.
What is static friction?Static friction is a force that resists the motion of two objects that are in contact with each other. It is caused by the forces of attraction between the two objects and is usually greater than the force of kinetic friction. The forces of static friction oppose the movement of the two objects and can be overcome by applying a force greater than the static friction.
The maximum force the block can withstand before it starts to move is 40 N multiplied by the coefficient of static friction.
The coefficient of static friction between the block and the table is determined by the materials of the block and the table and the surface roughness of the table.
If the coefficient of static friction is 0.3, then the maximum force the block can withstand before it starts to move is 40 N × 0.3 = 12 N.
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The two objects shown are both positively charged. Which position could possibly have zero electric field?
- A
- B
- C
- D
- They could all have zero electric field
The position they could possibly have zero electric field is C.
What is electric field?An electric field is a physical field that exists in the space surrounding electrically charged particles or objects. It is a vector field, meaning that it has both magnitude and direction.
When a charged particle is present in a space, it creates an electric field that exerts a force on any other charged particles in the vicinity.
The strength of the electric field at any given point is defined as the force per unit charge that a small test charge would experience if placed at that point.
The magnitude and direction of the electric field depend on the distance between the charges and their magnitudes. The electric field is stronger when the charges are closer together and weaker when they are farther apart.
So position they could experience zero electric field is C, assuming point C if very far from the two charges.
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4. Answer the following questions in terms of a wave's frequency, wavelength, amplitude, and
energy.
a. Describe the characteristics of a high pitch wave.
b. Describe the characteristics of a high-volume wave.
a. A high-pitch wave is characterized by a high frequency and a short wavelength. The frequency determines the pitch of the sound, with higher frequencies corresponding to higher pitches.
The wavelength is the distance between two consecutive peaks or troughs of the wave and is inversely proportional to the frequency. Therefore, a high-pitch wave has a shorter wavelength.
The amplitude of the wave, which is the height of the peak or the depth of the trough, is not directly related to the pitch of the sound, but it does determine the volume or intensity of the sound.
b. A high-volume wave is characterized by a high amplitude and a relatively long wavelength. The amplitude determines the volume or intensity of the sound, with higher amplitudes corresponding to louder sounds.
The wavelength of the wave does not directly affect the volume of the sound, but it can affect how the sound is perceived in different environments.
In general, longer wavelengths are more effective at traveling through obstacles such as walls and are better at penetrating long distances, whereas shorter wavelengths are more easily scattered and attenuated in the atmosphere.
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A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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Mrs. Tate travels in her car. She goes from mile marker 15 to 125 in 2.75 hours. What is her average speed?
Answer:
Explanation:
Step 1: Subtract 15 from 125
\(125-15=110\)
She traveled 110 miles in 2.75. We need to find her avg. speed.
Step 2: Divide 110 by 2.75
\(110/2.75=40\)
The answer is: Her average speed is 40 miles per hour.
Hope this helped!
In the sport of billiards, event organizers often remove one of the rails on a pool table to allow players to measure the speed of their break shots (the opening shot of a game in which the player strikes a ball with his pool cue).
The top of a pool table is a height ℎ=2.75 ft from the floor. If a player's ball lands a distance =16.50 ft from the table edge, what is her break shot speed 0?
The break shot speed of the player is determined as 96.5 ft/s.
Time of motion of the playeruse the following kinematic equation to determine the time of motion of the player.
h = vt + ¹/₂gt²
h = 0 + ¹/₂gt²
h = ¹/₂gt²
t = √(2h/g)
t = √(2 x 2.75/32.17)
t = 0.171 s
break shot speedvx = x/t
vx = 16.5 ft / 0.171 s
vx = 96.5 ft/s
Thus, the break shot speed of the player is determined as 96.5 ft/s.
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A runner traveled 20.0 km east then back tracked 12 km before stopping .the displacement from the original position is?
The displacement of the runner from the original position is determined as 8 km.
What is displacement?
The displacement of an object is the change in the position of an object. The displacement of an object describes the shortest distance between the initial position and final position of an object.
For a runner that traveled 20.0 km east then back tracked 12 km before stopping, the displacement of the runner is calculated as follows;
Δx = x₂ - x₁
where;
x₂ is the final positionx₁ is the initial positionΔx = 20 km - 12 km
Δx = 8 km
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Which fundamental force increases with the mass of an object?A. Weak nuclearB. GravitationalC. Electromagnetic. D. Strong nuclear
We know that all fundamental forces have a fundamental charge and that each of them is responsible for some fundamental phenomenon. In the case of the gravitational force, we know that it is responsible of all gravitational interactions and that its magnitude is proportional to the mass.
Therefore, gravitational force increases with the mass of an object and the answer is B.
A FBD of a rocket launching into space should include:
Answer:
Explanation:
the force of the rocket engine pushing it up, the force of gravity pulling it down, maybe some force of air resistance as the rocket goes fast, hmmm Free Body Diagrams (FBD) should have any and all forces on the model, unless they are negligible . or so slight they really make little difference in the total outcome.
A net force of 500 newtons causes
an object to accelerate at a rate of
5.0 m/s2. What is the mass of the
object?
A - 100 kg
B - .20kg
C - 600 kg
D - 2500 kg
Answer:
The answer is option AExplanation:
To find the mass of an object given it's acceleration and the force acting on it we use the formula
\(mass = \frac{force}{acceleration} \\ \)
From the question
force = 500 N
acceleration = 5.0 m/s²
We have
\(mass = \frac{500}{5} \\ \)
We have the final answer as
100 kgHope this helps you
Please help I need help with these 2 questions
Two students (90.0 kg and 60.0 kg) on roller skates face-to-face push against each other. The 90.0 kg student moves at 5.0 m/s just after their hands lose contact. What is the velocity of the other student?
Given that,
Mass of student 1, m₁ = 90 kg
Mass of student 2, m₂ = 60 kg
Speed of student 1, v₁ = 5 m/s
To find,
The velocity of the other student.
Solution,
Using the conservation of momentum to find the velocity of the other student. Let it is v₂.
\(m_1v_1=m_2v_2\\\\v_2=\dfrac{m_1v_1}{m_2}\\\\v_2=\dfrac{90\times 5}{60}\\\\=7.5\ m/s\)
So, the velocity of the other student is 7.5 m/s.
What is a therapuetic modality in psychology?
Answer:
There are several modalities, or methods, of treatment: individual therapy, group therapy, couples therapy, and family therapy
Explanation:
Answer:
Modalities are therapeutic tools that we use to help our patients recover from surgery, injury or a condition that causes pain and dysfunction, so they can get back to the activities they enjoy.
Protons and ____ have electric charge?