3 conditions that may be
required for a chemical reaction to occur.

Answer:

Density= 2.78 g/cm³

Relative density=2.8

Explanation:

To calculate the density of the cube we have to use the formula ρ=mass/volume

ρ stands for density.

So now we don't have the volume of the cube and to find the volume of the cube we have to use the formula a³

3³= 9 cm³

Now plug in the values. ρ= 25 g/9 cm³

ρ= 2.78 g/cm³

To find the relative density, we have to use the formula ρsample/ρH20

The sample means the density of the substance earlier. We do not know the density of water but it is constant at 997 kg/m³.

Now we have to make the units same so you change the unit of the density of cube to kg/m³

So, 25/1000= 0.025 kg

9/100×100×100 (because cm³ which means that there should be 3 meters to change the unit and to conver cm to meter we need to divide by 100 so 9cm/100, 9cm²/100×100, 9cm³/100×100×100)

=0.000009 m³

The new density= 0.025 kg/ 0.000009 m³

= 2777.78 kg/m³

Now plug the values into the formula:

relative density= 2.777.78 kg/m³ / 997 kg/m³

=2.8

There is no unit since kg/m³ and kg/m³ cancels

The object with the highest mass is the one on planet D. This is because mass is a measure of the amount of matter an object contains, and is not affected by gravity. Therefore, although the weight of the object on planet D is lower than that of the other planets, its mass remains the same.

Weight, on the other hand, is a measure of the gravitational force acting on an object. Therefore, the weight of an object will vary on different planets due to different gravitational forces. As shown in the drawings, the object on planet A has the greatest weight, but nevertheless the greatest mass.

In summary, the object with the greatest mass is on planet D, while the object with the greatest weight is on planet A.

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A component that is used on the higher temperature evaporators to prevent their pressures from dropping below the desired setting is known as temperature evaporators.

A refrigerant controller is employed on the higher-temperature evaporators to keep their pressures from falling below the target pressure. The refrigerant controller has a temperature probe that senses the evaporator's temperature and adjusts a mechanical valve's opening to maintain the desired pressure in the evaporator.

The valve is connected to the controller by a tube, which transmits the controller's pressure signal to the valve.  The evaporator pressure controls regulate refrigerant flow into the evaporator and keep the evaporator pressure constant. When refrigeration systems have many evaporators operating at various temperatures, various evaporator pressure controllers will keep the evaporator pressure constant. To keep the evaporator pressure at the proper level, the controller injects more refrigerant or allows less to enter.

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The dark absorption lines on the continous spectrum represents absoprtion of some of the light before the observation of the spectrum.

The continous spectrum of helium represents the star is made up of helium.

The dark absorption lines superimposed on the sontinous spectrum represents the light from the star has passed through a cloud of helium in which helium atoms absorbs the emitted helium light from the star.

Hence, option D is a correct answer.

The cohesive forces between liquid molecules generate the surface tension phenomena.

In physics, cohesion is defined as the intermolecular attractive force operating between two adjacent sections of a material, most notably a solid or liquid. This is the force that keeps stuff together. Intermolecular forces also exist between two distinct substances that come into contact, a process known as adhesion. Water characteristics cohesion and adhesion explain how water molecules interact with one another. as well as how water molecules interact with other substances such as leaves or even you. Water tends to stick to itself, which is what cohesion means. Water tends to attach to other things, which is what adhesion means. Cohesion is the act of sticking together. If your group of pals goes to the lunchroom as a unit and sits together, you're displaying good cohesiveness.

Here,

The phenomenon known as surface tension is caused by the cohesive forces between liquid molecules.

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Microcomputer words typically have a length of 8 to 32 bits.

Microcomputers are compact, reasonably priced computers. The central processing unit (CPU), input unit, output unit, and storage unit are all components of these computers. The CPU is housed on a single semiconductor chip in microcomputers. Microcomputers are multipurpose computers made for people.

Nowadays, 32-bit (x86) and 64-bit CPU architectures are the two most common types (x86-64, IA64, and AMD64). The CPU can operate with different datapath widths, integer sizes, and memory address widths depending on the architecture.

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Answer:

vaporation

Explanation:

latent heat also called the heat of vaporization is the amount of energy necessary to change a liquid to a vapour at constant temperature and pressure.

The acceleration of the object is 2.0 m/s². This means that for every second the object is in motion, its velocity will increase by 2.0 meters per second.

The given information is the net force (N) = 5.0 and the mass (kg) = 2.5. We need to determine the acceleration.


Acceleration is the rate at which an object's velocity changes over time.

It is directly proportional to the net force applied to the object and inversely proportional to its mass.

The formula to calculate acceleration is:

Acceleration = Net Force / Mass

Now, let's substitute the given values into the formula:

Acceleration = 5.0 N / 2.5 kg

Simplifying the equation:

Acceleration = 2.0 m/s²

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A 750 g aluminum pan is removed from the stove and plunged into a sink filled with 10 kg of water at 200c. The temperature quickly rises to 240c. 100 c the initial temperature of the pan.

The physical concept of temperature indicates in numerical form how hot or cold something is. Temperature is measured with a thermometer. Different temperature scales, which traditionally established various reference points and thermometric materials, are used to calibrate thermometers. The most widely used scales are the Kelvin scale (K), which is mostly used in science, the Fahrenheit scale (°F), and the Celsius scale, also referred to as centigrade and denoted by the unit symbol °C. The kelvin is one of the seven base units in the International System of Units (SI). On the thermodynamic temperature scale, absolute zero, also known as 0 kelvin, or 273.15 °C, is the lowest temperature. The third law of thermodynamics recognizes that it can only be very nearly attained experimentally and that it cannot actually be reached. It would be challenging for a body to produce heat at such temperature. Temperature is a crucial factor in all branches of natural science, including physics, chemistry, Earth science, astronomy, biology, ecology, material science, metallurgy, mechanical engineering, geography, and the majority of aspects of daily living. These fields cover the majority of the scientific disciplines, including biology, medicine, and ecology.

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Answer:

cm and cm²

Explanation:

volume is three dimensional

cm² is in relation to area and cm is in relation to the length of the object... to find the volume getting a base area times the length gives you volume of the object

(cm²×cm=cm³)... attempted illustration

Answer:

m³, cm³, km³

Explanation:

Answer: 1/10th of its weight on Earth.

Explanation: Let's assume that the weight of the object on Earth is W, and the gravitational acceleration on Earth is g. We know that weight is given by the formula:

W = m * g where m is the mass

If the gravitational attraction on another planet is 1/10th of Earth's pull, then the gravitational acceleration on that planet will be:

g' = g/10

Using the same formula for weight, the weight of the object on the new planet will be:

W' = m * g'

Substituting the value of g' in the equation above, we get:

W' = m * (g/10)

W' = (m/10) * g

Therefore, the weight of the object on the new planet will be 1/10th of its weight on Earth.

W' = (100/10) N = 10 N

So, the weight of the same object on a planet where the gravitational attraction has been reduced to 1/10th of Earth's pull would be 1/10th of its weight on Earth.

If an object was 1 mm across and it was magnified 10 times, it would be 10 mm across. Magnifying an object is essentially enlarging the object to make it appear bigger than it actually is.

The process of magnification is done by using a magnifying glass, microscope or telescope to focus the rays of light on the object. Magnification is used for various purposes such as reading, science, and even for entertainment.

For example, a magnifying glass can be used to closely observe the details of a small object, while a microscope can be used to study the structure of a cell. Similarly, a telescope is used to observe distant objects in the night sky. Magnification can also be used to create a magnified image of an object which can be viewed on a computer screen.

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The new collision frequency of the hypothetical hard-sphere gas, after being heated isochorically from 228.8 K to 478.4 K, is X GHz/L.

The collision frequency of a gas is related to its temperature and is a measure of how frequently gas particles collide with each other. In this scenario, the initial collision frequency per unit volume (Z₁) is given as 1.09 GHz/L at a temperature of 228.8 K. To determine the new collision frequency after heating the gas to 478.4 K, we can use the relationship between collision frequency and temperature.

The collision frequency (Z₂) is directly proportional to the square root of the absolute temperature. Therefore, we can calculate the ratio of the square roots of the temperatures (T₂/T₁) to find the change in collision frequency. By multiplying this ratio with the initial collision frequency (Z₁), we can determine the new collision frequency (Z₂).

Plugging in the given temperatures and the initial collision frequency into the equation and solving for Z₂ will give us the desired new collision frequency in GHz/L.

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A halo around the sun or moon is often an indication that cirrostratus clouds are present.

Cirrostratus clouds are high-level clouds that form above 20,000 feet (6,000 meters). They are composed of ice crystals and have a thin, often transparent appearance. When these clouds are present, they can create a halo effect around the sun or moon.

The halo is formed when light from the sun or moon is refracted, or bent, as it passes through the ice crystals in the cirrostratus clouds. This refraction causes the light to spread out and create a ring or halo-like appearance around the sun or moon.

The presence of a halo is often an indication of thin, high-level cloud cover, typically preceding an approaching warm front or an area of moisture. It can also be a sign of changing weather conditions.

It is worth noting that halos can also be formed by other cloud types, such as altostratus or thin, wispy cirrus clouds, depending on the specific atmospheric conditions.

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Input and output voltage circuit topologies that can be utilized to connect this battery with a 36 v (constant) load. 3V battery energy source.

Line voltage, often known as the supply power input or power supply, is what powers a device like such a washing machine. The input voltage is 220 volts AC with an active neutral and ground.

The output of a lead-acid automobile battery is 12V. 3V is the output of a lithium coin cell battery. The operative word here is "nominal," as a battery's actual measured voltage will drop as it empties. A LiPo battery will produce roughly 4.23V when fully charged, whereas its voltage may be closer to 2.7V when totally depleted.

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So the speed remains same 0.25m/s.

Answer:

33.333 ohms

Explanation:

voltage = power / current

3 / 0.3 = 10

resistance = voltage / current

10 / 0.3 = 33.33333

Answer:

Option D. 5.45 Ω

Explanation:

From the question given above, the following data were obtained:

Resistance 1 (R₁) = 10 Ω

Resistance 2 (R₂) = 20 Ω

Resistance 3 (R₃) = 30 Ω

Voltage (V) = 120 V

Equivalent resistance (R) =?

The equivalent resistance can be obtained as follow:

1/R = 1/R₁ + 1/R₂ + 1/R₃

1/R = 1/10 + 1/20 + 1/30

Find the least common multiple (lcm) of 10, 20 and 30. The result is 60

Divide 60 by each of the denominators and multiply by their numerators respectively. We have:

1/R = (6 + 3 + 2)/60

1/R = 11/60

Invert

R = 60/11

R = 5.45 Ω

Thus, the equivalent resistance in the circuit is 5.45 Ω

The total momentum is Mv and the total kinetic energy is ½ Mv². Therefore, option E is correct.

In an elastic collision, the total momentum and the total kinetic energy are conserved.

Before the collision:

After the collision, since the collision is elastic:

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Answer:

but for which activity donu need the answer and mention the question clearly

Explanation:

5vfvnuj6ynjtntjunjtu

In enzyme catalysis, binding energy is essential. Proteins known as enzymes serve as catalysts for chemical reactions by reducing the activation energy necessary for the reaction to take place.

Binding energy is the amount of power needed to separate two or more particles held together by an external force, such as the strong nuclear force or the electrostatic force. It is a crucial idea in physics and chemistry that aids in the explanation of a variety of events, including the structure of atomic nuclei and the creation of chemical bonds between atoms. Binding energy is essential in biological systems as well because it is essential for DNA replication, protein folding, and enzyme catalysis. The specificity and effectiveness of these biological processes are determined by the strength of the binding energy between a ligand and its target molecule, and even tiny changes in the binding energy can have a big impact on the system's overall performance.

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Explanation:

divide the distance by the time it takes to travel that same distance, then add your direction to it.

Or change in displacement divided by change in time.

answer:

click on the picture, hope it helps

The magnitude of the electric field at that location is is 40  N.C⁻¹.

The force per unit charge exerted on a positive test charge that is at rest at a given position is the force per unit charge that is used to define the electric field analytically.

Electric charge or magnetic fields with variable amplitudes can produce an electric field.

Given parameters:

Charge of the positive test charge, q =  5.0x10⁻⁶ C.

Electric force exerted by the electric field, F = 2.0x10⁻⁴ N.

Then, electric field at the position, E = F/q

= 2.0x10⁻⁴ / 5.0x10⁻⁶ N.C⁻¹.

= 40  N.C⁻¹.

Hence,  the magnitude of the electric field at the location of the test charge is 40  N.C⁻¹.

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The final angular speed (ωf) is equal to the initial rotational inertia (Ii) multiplied by the initial angular speed (ωi) divided by the final rotational inertia (If).

According to the conservation of angular momentum, the initial angular momentum of the ice skater must be equal to the final angular momentum after extending her arms outward.

The angular momentum (L) is given by the equation:

L = I * ω

where I represents the rotational inertia and ω represents the angular speed.

Given:

Initial rotational inertia (Ii) = Ii

Initial angular speed (ωi) = ωi

Final rotational inertia (If) = If

Using the conservation of angular momentum, we can write:

Ii * ωi = If * ωf

Rearranging the equation to solve for the final angular speed (ωf), we have:

ωf = (Ii * ωi) / If

Therefore, the final angular speed (ωf) is equal to the initial rotational inertia (Ii) multiplied by the initial angular speed (ωi) divided by the final rotational inertia (If).

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The force felt by the larger test charge would be twice as large as the force felt by the original test charge.

This is because the force felt by a test charge in an electric field is directly proportional to the magnitude of the test charge. The electric field is a vector field and the force experienced by a test charge is given by the product of the charge of the test particle and the electric field at that point.

So, when the magnitude of the test charge is doubled, the force experienced is also doubled. Therefore, if a test charge of magnitude twice as large as the original test charge were placed at point a, it would feel twice the force that the original test charge felt when it was placed at that same point.

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Answer:

True

Explanation: