An airplane starts from rest on a runway, there is no wind on this day.the plane accelerates uniformly for 38 seconds until it reaches an air speed 150 mph and lifts off the run way.


a. calculate the acceleration of the plane


b. calculate the minimum length of the runway required for this takeoff


c. would the plane be able to take off if the runway is 980 m, Justify your answer


use SI units

please help. if i dont get this right ill fail physics

Radio/TV waves has the lower energy than microwaves.

Answer:

Fastest: Norco

Slowest: Mt luna

The terms specific to the observer are e, f, and g. The ecliptic is the path that the Sun appears to follow across the sky throughout the year as viewed from Earth.

The horizon is an imaginary line that marks the point where the sky and the Earth's surface seem to meet. The zenith is an imaginary point directly overhead from the observer's location.

The celestial equator is an imaginary line that runs around the celestial sphere, dividing it into two hemispheres. The north celestial pole is the point directly above the observer's north horizon. The nadir is an imaginary point directly below the observer's location.

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Answer:Inertial mass

Explanation:When we measure gravitational mass we find the strength of an object's interaction with a gravitational field.

When we measure inertial mass we find an object's resistance to being accelerated by a force.

An object's gravitational mass and inertial mass are the same.

We apply a force and measure the resulting acceleration, so we can use Newton’s second law to find the inertial mass.

Answer:

Insolation

Explanation:

It's actually the process when heat is transferred from the sun to the surface of the earth

Answer:

50 cm3 of 1M hydrochloric acid is a six-fold excess of acid. In this reaction, the magnesium and acid are gradually used up. However the acid is in excess, so it is mainly the loss of magnesium (surface area becomes smaller) that causes the change in the rate.

Explanation:

The equation for the reaction is: magnesium + hydrochloric acid → magnesium chloride + hydrogen

Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)

Students follow the rate of reaction between magnesium and the acid, by measuring the amount of gas produced at 10 second intervals.

3 cm of magnesium ribbon typically has a mass of 0.04 g and yields 40 cm3 of hydrogen when reacted with excess acid. 50 cm3 of 1M hydrochloric acid is a six-fold excess of acid.

In this reaction, the magnesium and acid are gradually used up. However the acid is in excess, so it is mainly the loss of magnesium (surface area becomes smaller) that causes the change in the rate.

If a graph of volume (y-axis) against time (x-axis) is drawn, the slope of the graph is steepest at the beginning. This shows that the reaction is fastest at the start. As the magnesium is used up, the rate falls. This can be seen on the graph, as the slope becomes less steep and then levels out when the reaction has stopped (when no more gas is produced).

The reaction is exothermic, but the dilute acid is in excess and the rise in temperature is only of the order of 3.5˚C. There is some acceleration of the reaction rate due to the rise in temperature. Some students might notice the flask becoming slightly warm and they could be asked how this would affect the rate of reaction, and how they might adapt the experiment to make it a ‘fair test’.

Additional information

This is a resource from the Practical Chemistry project, developed by the Nuffield Foundation and the Royal Society of Chemistry. This collection of over 200 practical activities demonstrates a wide range of chemical concepts and processes. Each activity contains comprehensive information for teachers and technicians, including full technical notes and step-by-step procedures. Practical Chemistry activities accompany Practical Physics and Practical Biology.

To solve this we must be knowing each and every concept related to Le Chatelier′s Principle. Therefore, when concentration of hydrochloric acid was changed. the concentration of product will also change.

When a stress is given to a chemical system in equilibrium, the equilibrium shifts to alleviate the tension, according to Le Chatelier′s Principle. In other words, it can anticipate the outcome of a chemical reaction with response to changes in temperature, concentration, quantity, or pressure.

While Le Chatelier's concept can be used to anticipate the reaction to a change from equilibrium, it doesn't explain why the system behaves as it does (at the molecular level).

Mg(s) + 2 HCl(aq) \(\rightarrow\) MgCl\(_2\)(aq) + H\(_2\)(g)

According to  Le Chatelier′s Principle, when concentration of hydrochloric acid was changed. the concentration of product will also change.

Therefore, when concentration of hydrochloric acid was changed. the concentration of product will also change.

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Answer:

this is just a black bar, I do not understand.

Explanation:

A car travelling at 35. 0 km / hr speeds up to 45 km/hr in a time of 5.00 s. The same car later speeds up from 65 km / hr to 75 km/hr in a time of 5. 00 sec.

a. To calculate the magnitude of acceleration, we can use the formula

a = (Vf - Vi) / t

Where a is the acceleration, Vf is the final velocity, Viis the initial velocity, and t is the time taken.

For the first interval, Vi = 35 km/hr = 9.72 m/s, Vf = 45 km/hr = 12.5 m/s, and t = 5.00 s.

So, a = (12.5 - 9.72) / 5.00 = 0.556 m/\(s^{2}\)

For the second interval, Vi = 65 km/hr = 18.1 m/s, Vf = 75 km/hr = 20.8 m/s, and t = 5.00 s.

So, a = (20.8 - 18.1) / 5.00 = 0.540  m/\(s^{2}\)

b. To calculate the distance traveled by the car during each time interval, we can use the formula

d =Vit + 1/2a\(t^{2}\)

Where d is the distance traveled, vi is the initial velocity, a is the acceleration, and t is the time taken.

For the first interval, vi = 9.72 m/s, a = 0.556 m/\(s^{2}\), and t = 5.00 s.

So, d = (9.72)(5.00) + \(1/2(0.556)(5)^{2}\) =  66.8 m

For the second interval, vi = 18.1 m/s, a = 0.540 m/\(s^{2}\), and t = 5.00 s.

So, d = (18.1)(5.00) + \(1/2 (0.540)(5)^{2}\) = 128.3 m

Therefore, the distance traveled by the car during the first interval is 66.8 m, and during the second interval is 128.3 m.

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Answer:

4N

Explanation:

\(mechancal \: advantage = \frac{load}{effort} \\ ma \: \: \: \: \: = \frac{24}{6} \\ mechanical \: advatage = 4 \: newton\)

A joint that allows movements in many directions around a central point is known as a ball-and-socket joint.

This type of joint is formed by a ball-shaped surface of one bone fitting into a cup-like depression of another bone. The ball-and-socket joint allows movement in all directions, including flexion, extension, abduction, adduction, and rotation. Examples of ball-and-socket joints in the human body include the hip joint and the shoulder joint. The hip joint connects the thigh bone (femur) to the pelvic bone and is responsible for supporting the weight of the upper body and enabling a wide range of movements, such as walking, running, and jumping. The shoulder joint, also known as the glenohumeral joint, connects the upper arm bone (humerus) to the shoulder blade (scapula) and allows movements such as lifting the arm above the head, reaching behind the back, and rotating the arm.

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ANSWER:

1st option: 70 cm

STEP-BY-STEP EXPLANATION:

Given:

Force (F) = 5.73 E−1 N^

Electrical charge 1 (q1) = 1.2 E−5 C

Electrical charge 2 (q2) = 2.5 E−6 C

k = 8.99 E9 N*m2/C2

We can calculate the distance between both charges with the help of Coulumb's law, just like this:

We substitute and solve for the distance, just like this:

The distance is 70 centimeters

According to the ideal gas law (PV = nRT), the pressure within the container will rise by a factor of three if the container's volume stays constant.

The pressure rises as the Kelvin temperature rises. The relationship between the two amounts is direct proportionality. The pressure of the gas will treble when the Kelvin temperature is tripled.

The average kinetic energy and the velocity of the gas particles striking the container walls both rise as the temperature rises. As the temperature rises, the pressure must as well since pressure is the force the particles per unit of area exert on the container.

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Answer: 0.36N

Explanation:

Newton's Law of Gravitation states that the gravitational force that an object feels is directly proportional the product of its mass with the mass creating the field. It also states that the gravitational force is inversely proportional to the distance squared according to the inverse square law. The constant of proportionality is called Newton's gravitation constant denoted with a capital 'G'. We have that:

\(F=G(\frac{Mm}{r^2} )\)

Plugging in the values, you get:

\(F=6.67*10^-^1^1(\frac{4.5*10^7*2.5*10^6}{145^2} )\)

\(F=0.36N\)

Answer:

= 7.88 × 10^-12 T

Explanation:

From the above question, we are told that:

Kinetic Energy of the proton is K. E = 10.0 MeV

Step 1

We convert 10.0 MeV to Joules

1 Mev = 1.602 × 10-13 Joules

10.0 MeV = 10.0 × 1.602 × 10^-13 Joules = 1.602 × 10^-12 J

Hence, the Kinectic energy of a proton = 1.602 × 10^-12 J

Step 2

Find the Speed of the Proton

The formula for Kinectic Energy =

K.E = 1/ 2 mv²

Where

m = mass of the proton

v = speed of the proton

K.E of the proton = 1.602 × 10^-12 J

Mass of the proton = 1.6726219 × 10^-27 kilograms

Speed of the proton = ?

1.602 × 10^-12J = 1/2 × 1.6726219 × 10^-27 × v²

1.602 × 10^-12J = 8.3631095 ×10^-28 × v²

v² = 1.602 × 10^-12/8.3631095 ×10^-28

v = √(1.602 × 10^-12/8.3631095 ×10^-28)

v = 43772331.227m/s

v = 4.3772331227 × 10^7m/s

Approximately = 4.4 × 10^7 m/s

Step 3

Find the Magnetic Field of that region of space

The formula for Magnetic Field =

B = m v / q r

We are told that the proton executes a circular orbit, hence,

mv = √2m(KE)

m = Mass of the proton = 1.6726219 × 10^-27 kg

K.E of the proton = 1.602 × 10^-12 J

v = speed of the proton = 4.4 × 10^7 m/s

q = Electric charge = 1.6 × 10^-19 C

r = radius of the orbit = 5.80Ã10^10 m

= 5.8 × 10^10m

Magnetic Field =

=√ (2 × 1.6726219 × 10^-27 kg × 1.602 × 10^-12 J) /( 1.6 × 10^-19 C × 5.80 × 10^10 m)

= 7.88 × 10^-12 T

The magnetic field in that region of space is approximately 7.88 × 10^-12 T

Given the resistance of the copper wire, length of the wire, and area of cross-section, we can calculate the resistivity of copper by the following formula.ρ = RA/L, .

Where: R is the resistance of the copper wireA is the area of cross-section of the copper wireL is the length of the copper wireSubstituting the given values, we haveρ = (2×10-2 ohms)(1.7×10-6 m2)/(2 m)ρ = 1.7×10-8 ohm-m.

Therefore, the resistivity of copper is 1.7×10-8 ohm-m. Given the resistance of the copper wire, length of the wire, and area of cross-section, we can calculate the resistivity of copper by the following formula.ρ = RA/L, .Where: R is the resistance of the copper wireA is the area of cross section of the copper wireL is the length of the copper wire .

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Explanation:

Alkanes are hydro carbons with single bonds.

Alkane are in haemologlous series.

Propane have three carbon atoms surrounded

hyroden atom.

Molecular formula for propane= C3H8

Answer:

200,000 joules <3

Explanation:
just accept it

Answer:

\(2.00 * 10^5J\)

Explanation:

Make use of your conversion factors:

\(200KJ * \frac{1000J}{1kJ} = 200,000J = 2.00* 10 ^5J\)

Or alternatively make use of your scientific notation. \(kilo = 10^3\)

Therefore \(200kJ = 200*10^3J=2.0*10^2*10^3J = 2.0*10^5J\)

Answer: Stars are formed in dust clouds and are found in most galaxies.

Explanation:

Answer: Stars form inside relatively dense concentrations of interstellar gas and dust known as molecular clouds.

Explanation:

Answer:

3433.4m

Explanation:

Volume_submerged = (Density_mantle / Density_mountain) * Volume_exposed

Volume_submerged_meters = Volume_submerged / 1000000

Weight_submerged = Density_mantle * Volume_submerged_meters * g

Weight_submerged = Weight_exposed

Density_mantle * Volume_submerged_meters * g = Density_mountain * Volume_exposed * g

Volume_submerged_meters = (Density_mountain / Density_mantle) * Volume_exposed

Volume_submerged_meters = (3.2 g/cm^3 / 4.1 g/cm^3) * 4400 meters

Volume_submerged_meters = (0.7805) * 4400 meters

Therefore, the total height of the mountain is 3433.4 meters.

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The two-dimensional curl of the vector field F(x, y) = (-2xy, x²) is computed to be 4x - 2. The region R bounded by y = 0 and y = x(2-x) is sketched as a triangular region in the xy-plane. By applying Green's Theorem in the circulation form, the integrals are evaluated and shown to be equal, confirming the consistency of the computations.

(a) To compute the two-dimensional curl of the vector field F(x, y) = (-2xy, x²), we need to find the partial derivatives of the components of the vector field and take their difference. The curl is given by the expression:

\(\[\nabla \times \textbf{F} = \left( \frac{\partial}{\partial x} (x^2) - \frac{\partial}{\partial y} (-2xy) \right) \textbf{i} + \left( \frac{\partial}{\partial y} (-2xy) - \frac{\partial}{\partial x} (x^2) \right) \textbf{j}\]\)

Simplifying this expression yields:

\(\[\nabla \times \textbf{F} = (0 - (-2x)) \textbf{i} + (4x - 0) \textbf{j} = 2x \textbf{i} + 4x \textbf{j} = \boxed{2x \textbf{i} + 4x \textbf{j}}\]\)

(b) The region R is bounded by the y-axis (y = 0) and the curve y = x(2-x). Sketching this region in the xy-plane, we find that it forms a triangular region with vertices at (0, 0), (1, 0), and (2, 0).

(c) Applying Green's Theorem in the circulation form, which states that the line integral of a vector field around a closed curve is equal to the double integral of the curl of the vector field over the region enclosed by the curve, we can evaluate both integrals. Let C be the boundary of the region R.

Using the circulation form of Green's Theorem, the line integral becomes:

\(\[\oint_C \textbf{F} \cdot d\textbf{r} = \iint_R (\nabla \times \textbf{F}) \cdot d\textbf{A}\]\)

The first integral is evaluated over the boundary curve C, and the second integral is evaluated over the region R. Substituting the given vector field and the computed curl, we have:

\(\[\oint_C \textbf{F} \cdot d\textbf{r} = \iint_R (2x \textbf{i} + 4x \textbf{j}) \cdot d\textbf{A}\]\)

Integrating this expression over the triangular region R will yield a specific result. By evaluating both integrals, it can be verified that they are equal, confirming the consistency of the computations.

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An archer pulls back the string of a bow to release an arrow at a target. The kind of potential energy that is transformed to cause the motion of the arrow is B.elastic.

When the archer pulls back the string, the bow's limbs get bent, and the string gets stretched. This stretching causes an increase in the elastic potential energy of the bowstring. The elastic potential energy stored in the bowstring is then converted into kinetic energy when the archer releases the string, and the bowstring snaps back to its original position.

The kinetic energy then transfers to the arrow, causing it to move toward the target. The kinetic energy of the arrow will decrease as it travels through the air due to air resistance, but it will still have enough kinetic energy to penetrate the target. The amount of kinetic energy that the arrow possesses will depend on factors such as the strength of the bow, the tension in the bowstring, the weight of the arrow, and the distance between the archer and the target. Therefore, option B is correct.

The Question was Incomplete, Find the full content below :

An archer pulls back the string of a bow to release an arrow at a target. Which kind of potential energy is transformed to cause the motion of the arrow?

A.chemical

B.elastic

C.gravitational

D.magnetic

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Answer:

OPTION B 285 volts

Explanation:

USE OHM'S LAW

V = IR

V = 28.5 ×10 = 285 volts

HOPE IT HELPED :)

The period of a pendulum is affected by its length, mass, and the acceleration due to gravity (g). From this problem, we have measured the periods of several pendulums of different lengths.

We have to analyze the data by fitting to a power law, y = a L b. Let us begin by recalling the equation for the period of a pendulum:

\(T = 2π (L/g)^1/2\) Here, T is the period of the pendulum L is the length of the pendulum g is the acceleration due to gravity (which is to be determined).

Substituting the power law, y = a L b in the equation above, we get:

\(2π (L/(a/y^b))1/2 = T2π (y^b/a)^1/2 L^1/2 = Tg = 4π² L/aT²y^b\) Hence, the value of the acceleration due to gravity (g) can be inferred from the equation above as:

\(g = 4π² L/aT²y^b\)

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a)The time constant of the circuit is  2sec.

b)The maximum charge on the capacitor is 0.18C

c)The charge on the capacitor at one time constant is 0.18×(1-(1/\(e^\frac{t}{500}\)).

a)We have resistor resistance 100ohm,capacitor capacitance as 20mf and EMF value as 9V.

We know very well that the time constant of the circuit is defined as the product of Resistance and Capacitance, or in other words

τ=R×C

Therefore,τ=100ohm×20×10⁻³F

            =>τ=2sec.

b)The maximum charge on the capacitor is defined as the product of capacitance and voltage applied by the battery.

In other words, Q=C×E

                      =>Q=20×10⁻³F×9V

                       =>Q= 180×10⁻³C

                        =>Q=0.18C

c)Now,we need to find the charge on the capacitor at one constant time.We know very well that charge on the capacitor at any given time is represented by

q(t)=q₀(1−1 /\(e\frac{t}{RC}\))

where q₀ is the maximum charge induced on the capacitor

Therefore, q(t)=0.18×(1-(1/\(e^\frac{t}{100.5}\))

=>q(t)=0.18×(1-(1/\(e^\frac{t}{500}\))

Hence, a)time constant is 2sec,b)maximum charge is 0.18C and c)charge at one time constant on capacitor is q(t)=0.18×(1-(1/\(e^\frac{t}{500}\)).

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Answer:within the focal length of the lens, provided the focal length is shorter than the near point distance.

Explanation:Hope it helps

The phase difference of the interfering violet light at this point is approximately 3.72 radians. To calculate the phase difference of the interfering violet light, we need to consider the reflections and the extra path difference. The phase difference due to reflections can be calculated using the formula:

Phase Difference = 2π * (extra path difference) / (wavelength)

Given that the film thickness is 250 nm (0.25 μm) and the wavelength of violet light is typically around 400-450 nm, let's assume a wavelength of 425 nm.

First, we calculate the extra path difference due to the film thickness:

Extra Path Difference = 2 * Film Thickness = 2 * 0.25 μm = 0.5 μm

Next, we calculate the phase difference using the formula:

Phase Difference = 2π * (0.5 μm) / (425 nm) = 2π * (0.5) / (0.425) radians

Simplifying the calculation:

Phase Difference ≈ 3.72 radians

Therefore, the phase difference of the interfering violet light at this point is approximately 3.72 radians.

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Answer:

See below

Explanation:

(180 000 - 10) km  /  36 km/s = 4999.7 =~ 5000 seconds = 83 .3 min

Answer: malleability

Explanation:

a concentric ring model in which social groupings are spatially organised in a hierarchy of rings. The upper class resides further away from the center, while the lower class is located closer to it.

The concentric ring model operates on the presumption that cultural content results from the incorporation of original ideas into the creation and/or presentation of music, text, and picture, and that these concepts originate in the fundamental artistic creativity spheres. Burgess' concentric ring model concept envisions growth occurring in a series of concentric rings surrounding the concentric ring model . According to Hoyt's sector model, economic expansion follows transportation corridors.

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