||
Find the volume of this cylinder. Use 3 for T.
5 cm
V = πr²h
V ≈ [?]cm³
9 cm
Enter P

The correct answer is C. Airport S has 100 on-time flights, and Airport T has 200 on-time flights. Since 100 is one-half of 200, Airport S has one-half the number of on-time flights that Airport T has.

Given that,

The number of flights that were either on time or delayed at three separate airports on a given day is depicted in the segmented bar chart below.

Which of the following statements is the bar chart evidence for?

The options are : In comparison to the other two airports, A Airport T has the highest proportion of on-time flights.

In comparison to the other two airports, B Airport R has the lowest percentage of on-time flights.

C The proportion of on-time flights at Airport S is less than half that at Airport T.

D The proportion of on-time flights at Airport R is lower than that at Airport S.

E There are exactly as many flights at Airport T as there are at Airports R and S put together.

As the number of flights that were either on time or delayed at three different airports on one day can be exactly represented by

The correct answer is less than half as many flights arrive on time at Airport S than at Airport T.

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The Complete Question is :

Which of the following statements is the bar chart evidence for the number of flights that were either on time or delayed at three different airports on one day.?

Answer:

p=-3

Step-by-step explanation:

Answer:

-4/2=2p

Step-by-step explanation:

5p - 8/2 = 7p +4/2

-5p           -5p

        -8/2 = 2p + 4/2

        -4/2            -4/2

Keep in mind that without the population standard deviation, it is impossible to provide an exact sample size. However, this formula will give you a good starting point.

To find the sample size needed for a 99.5% confidence interval with a margin of error of 1.5, we can use the formula:

n = (Z * σ / E)^2

where n is the sample size, Z is the Z-score corresponding to the desired confidence level, σ is the population standard deviation, and E is the margin of error.

For a 99.5% confidence interval, the Z-score is approximately 2.807 (from a standard normal distribution table). Since we do not have the population standard deviation (σ), we will need to estimate it using a sample standard deviation or use a conservative approach by assuming the maximum possible value. For now, let's assume we have an estimated standard deviation.

n = (2.807 * σ / 1.5)^2

Solve for n by plugging in the estimated standard deviation (σ) and then round up to the nearest whole number, as you cannot have a fraction of a sample.
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Answer:

b

Step-by-step explanation:

It is true, Mai can conclude that the diagonal WY bisects the angles ZWX and ZYX

Since Mai has proven triangles WYZ and WYX to be congruent by the SSS triangle Congruence Theorem, she can conclude that:

Diagonal WY bisects angles ZWX and ZYX because:

all corresponding parts of both triangles are congruent. (Option A).

If two triangles are proven to be congruent to each other, it means that all three pairs of corresponding sides and angles of both triangles are congruent and equal to each other.

Thus, since Mai has proven triangles WYZ and WYX to be congruent by the SSS Triangle Congruence Theorem, therefore, all corresponding parts of both triangles are congruent.

If this is so, then Mai can conclude that angles ZWX and ZYX are bisected by diagonal WY. (Option A is correct).

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Answer:

Its either A or B I believe it's A srry if im wrong.

Answer:

(x+1)(x+2)(x-3)

x³-7x-6

Step-by-step explanation:

We are looking for an equation where we have a degree of 3 and where we can plug in -1, -2, or 3 for x and have it equal 0

the first one is definetly correct

To see if there's another answer let's mulitply it out

(x+1)(x+2)(x-3)= (x-3)(x²+3x+2)= x³-7x-6 which is equal to the third one

The constant differences between the consecutive terms are 2 (a); 2 (b), -3 (c), 7 (d), 1(e), and 6(f).

In math, the constant difference can be defined as the number that defines the pattern of a sequence of numbers. This means that number that should be added or subtracted to continue with the sequence.

Due to this, to determine the constant difference it is important to observe the pattern and find out the number that should be added. For example, if the sequence is 2, 4, 6, 8, there is a difference of 2 between each of the numbers and this is the constant difference.

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Answer:

H0 is rejected and Ha is accepted that the students show a higher population mean math score on the SAT if their parents attained a higher level of education.

Step-by-step explanation:

Part a:

The null and alternate hypothesis can be formulated as

H0 : u1 ≤ u2 the two means ( of students whose parents did or did not attain a higher level of education) are equal .

against the claim

Ha: u1 > u2 the students show a higher population mean math score on the SAT if their parents attained a higher level of education.

Part b:

The point estimate of the difference between the means for the two populations is the difference of sample means

x1`- x2`

525- 487= 38

Student’s Parents

College Grads

x                                            x²

485      487               235,225         237,169

534      533                  285,156        284,089

650     526                 422,500         267,676

554       410                   306,916          168,100

550      515                   302,500        265,225

572      578                      327,184        334,084

497      448                     247,009        200,704

592     469                  350,464         219,961          

∑xi = 8400                      ∑xi ²= 4,462,962          

x1`= ∑ xi/n1= 8400/16= 525

Using statistic calculator Using formula :  σ(n-1)

s1= 59.4205

High School Grads

x                                          x²

442          492                   195,364            242,064

580          478                    336,400            228,484

479           425                      229,441             180,625

486            485                     236,196            235,225

528            390                     278,784           152,100

524             535                     274,576           286,225        

∑xi = 5844                                 ∑xi ²= 2,875,484                

x2`= ∑ xi/n2= 5844/12= 487

Using statistic calculator Using formula :  σ(n-1)

s2= 51.7476

x1`- x2`= 525- 487= 38

The test statistic is

t= (x1`- x2`) / √ s1²/n1+ s2²/n2

t= 38/ √(59.4205)²/16 + (51.7476)²/12

t=38 / √3530.7958/16 + 2677.8141/12

t= 1.804

and the degrees of freedom is

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= [3530.7958/16 + (2677.8141/12) ]²/ (3530.7958/16)²/15 +(2677.8141/12)²/11

≈ 25

The degrees of freedom is always rounded in this calculation

From the table t∝ = 1.708

Hence critical value is t ≥ t∝

Reject H0:

Part C.

The p-value is 0.041647.

The result is less than  0.05.

Result:

H0 is rejected and Ha is accepted that the students show a higher population mean math score on the SAT if their parents attained a higher level of education.

Answer:

Step-by-step explanation:

The area of Mrs Brown’s classroom is

63 m2

. The area of Mr Black’s

classroom is 64 m2

. Mr Black’s

classroom is bigger.

The shape is a depiction of how the diagonals of a rectangle have the same length and bisect each other.

In a rectangle, the diagonals are perpendicular bisectors of each other, which means that they intersect each other at their midpoints and divide each other into two equal parts. Moreover, since a rectangle has congruent opposite sides, the two diagonals are also congruent to each other.

We can see this with the diagonals, EG and DF as they bisect each other and intercept at the halfway point of H.

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The question is:

How does the figure prove the following statement:

The diagonals of a rectangle have the same length and bisect each other.

Step-by-step explanation:

To eliminate x in the system of equations:

1. Multiply Equation 1 by 9 and multiply Equation 2 by -4, this gives:

Equation 1: 36x -54y = 90

Equation 2: -36x - 8y = -28

2. Add the two equations together to eliminate x:

(36x - 54y) + (-36x - 8y) = 90 - 28

Simplifying, we get:

-62y = 62

3. Solve for y:

y = -1

4. Substitute y = -1 into one of the original equations, say Equation 1:

4x - 6(-1) = 10

Simplifying, we get:

4x + 6 = 10

5. Solve for x:

4x = 4

x = 1

Therefore, the solution to the system of equations is x = 1 and y = -1. We can check that these values are correct by substituting them back into the original equations and verifying that they satisfy both equations.

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See this attachment

Answer: 2y = 24

Step-by-step explanation:

h: The domain

-5 ≤ x ≤ 5

Answer:

B. √3 inches

Step-by-step explanation:

Apply trigonometry ratio to solve for AB

AB = DC (opposite sides of a rectangle are equal)

Given,

reference angle (θ) = 30°

Hypotenuse = BD = 2

Adjacent = DC = ?

Apply CAH, which is:

Cos θ = Adj/Hyp

Substitute

Cos 30° = DC/2

2*Cos 30° = DC

2*√3/2 = DC (Cos 30° = √3/2)

DC = √3 in.

AB = DC. Therefore,

AB = √3 inches

M = 270,000 * (0.5833% * (1 + 0.5833%)^240) / ((1 + 0.5833%)^240 - 1).  Calculating this equation will give us the monthly mortgage payment for Abigail and Curtis Siebert.

Abigail and Curtis Siebert have a $270,000 mortgage at an interest rate of 7% for a term of 20 years.

To calculate the monthly mortgage payment, we can use the formula for an amortizing mortgage:

M = P * (r * (1 + r)^n) / ((1 + r)^n - 1),

where M is the monthly mortgage payment, P is the principal amount (loan amount), r is the monthly interest rate, and n is the total number of monthly payments.

First, we need to convert the annual interest rate to a monthly interest rate. Since there are 12 months in a year, the monthly interest rate is 7% divided by 12, which is approximately 0.5833%.

The total number of monthly payments is the term of the mortgage multiplied by 12. In this case, it's 20 years * 12 months, which equals 240 months.

Now, we can substitute the values into the formula:

M = 270,000 * (0.5833% * (1 + 0.5833%)^240) / ((1 + 0.5833%)^240 - 1).

Calculating this equation will give us the monthly mortgage payment for Abigail and Curtis Siebert.

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Answer:

a) 0.125 = 12.5% probability that it’s not raining and there is heavy traffic and I am not late.

b) 0.2292 = 22.92% probability that I am late.

c) 0.5454 = 54.54% probability that it rained that day.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

\(P(B|A) = \frac{P(A \cap B)}{P(A)}\)

In which

P(B|A) is the probability of event B happening, given that A happened.

\(P(A \cap B)\) is the probability of both A and B happening.

P(A) is the probability of A happening.

Question a:

2/3 probability of not raining.

If not raining, 1/4 probability of heavy traffic.

1 - 0.25 = 0.75 = 3/4 probability of not late.

So

\(p = \frac{2}{3} \times \frac{1}{4} \times \frac{3}{4} = \frac{2}{16} = 0.125\)

0.125 = 12.5% probability that it’s not raining and there is heavy traffic and I am not late.

b. What is the probability that I am late?

0.5 of (1/3)*(1/2) = 1/6(rainy and heavy traffic).

0.25 of (1/3)*(1/2) = 1/6(rainy and no traffic).

1/8 = 0.125 of (2/3)*(3/4) = 1/2(not rainy and no traffic).

0.25 of (2/3)*(1/4) = 1/6(not rainy and traffic). So

\(P(A) = 0.5\frac{1}{6} + 0.25\frac{1}{6} + 0.125\frac{3}{6} + 0.25\frac{1}{6} = \frac{0.5 + 0.25 + 3*0.125 + 0.25}{6} = 0.2292\)

0.2292 = 22.92% probability that I am late.

c. Given that I arrived late at work, what is the probability that it rained that day?

Event A: Late

Event B: Rained

0.2292 = 22.92% probability that I am late.

This means that \(P(A) = 0.2292\)

Probability of late and rain:

0.5 of 1/6(rain and heavy traffic).

0.25 of 1/6(rain and no traffic). So

\(P(A \cap B) = 0.5\frac{1}{6} + 0.25\frac{1}{6} = \frac{0.5 + 0.25}{6} = \frac{0.75}{6} = 0.125\)

Probability:

\(P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.125}{0.2292} = 0.5454\)

0.5454 = 54.54% probability that it rained that day.

\(~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ G(\stackrel{x_1}{5}~,~\stackrel{y_1}{-4})\qquad H(\stackrel{x_2}{11}~,~\stackrel{y_2}{0}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ 11 +5}{2}~~~ ,~~~ \cfrac{ 0 -4}{2} \right) \implies \left(\cfrac{ 16 }{2}~~~ ,~~~ \cfrac{ -4 }{2} \right)\implies (8~~,~~-2)\)

Answer:

Step-by-step explanation:

Year 1: $850 * 0.91 = $773.50

Year 2: $773.50 * 0.91 = $704.69

Year 3: $704.69 * 0.91 = $641.95

...

Year 34: (continue the pattern)

We can continue this calculation for each year, but to save time, we can use an exponential decay formula:

Remaining Amount = Initial Amount * (1 - rate)^years

Substituting the values:

Remaining Amount = $850 * (1 - 0.09)^34

Calculating this expression:

Remaining Amount ≈ $850 * (0.91)^34 ≈ $255.88

After 34 years, approximately $255.88 will be left with Sally.

Company should provide insurance policies to employees because the employees are assets to them.

An insurance policy is a contract between the insurance company and the person getting the insurance.

Employees are assets of a company.

Companies should look after by insuring this asset like any other asset.

Although it is not the only factor for an employee to stick to a company, it is also one of the contributing factor for the employees to stick to a company longer.

It is a very good benefit for the employee since the premium is paid by the employer for the employee.

Hence companies should provide insurance policies to employees.

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The expression that shows the total oranges amir got in total is x-12 = 4. And amir got 16 oranges in all

A linear expression is an algebraic statement where each term is either a constant or a variable raised to the first power. In other words, none of the exponents can be greater than 1. For example, x² is a variable raised to the second power, but x is a variable raised to the first power.

example of linear expression is 2x+2y = 5. This is a linear expression with two variables x and y.

Let's represent the total no of oranges by x.

Therefore ,

2 bags of oranges with 6 in each bag will amount to 2×6 = 12 oranges.

an addition of 4 loose oranges . Therefore the total number of oranges = 12+4 = x

x = 12+4 or x-12 = 4

= 16

therefore amir got 16 oranges in all

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Answer:

LEavel ^ 9-8=1

Step-by-step explanation:

Answer:-4 + -6 = -10

Step-by-step explanation:

    Equivalent fractions are those that, despite their visual differences, reflect the same value. For instance, if you take a cake and cut it into two equal pieces, you will have consumed half of the cake.

          When two fractions are expressed in their simplest form, they are said to be equivalent. When broken down into its simplest components, the fraction 26/28 equals 13/14. You only need to multiply the numerator and denominator of the reduced fraction (13/14) by the same natural number, i.e., multiply by 2, 3, 4, 5, 6 to get analogous fractions.

    In decimal form, 13/14 is 0.92857142857143.

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The probability of getting a black card and a numbered card is 9/26.

To calculate the probability of getting a black card (E1), we need to determine the number of black cards in a standard deck of 52 cards.

There are 26 black cards in total, which consist of 13 spades (black) and 13 clubs (black).

Therefore, the probability of drawing a black card (P(E1)) is:

P(E1) = Number of favorable outcomes / Total number of possible outcomes

P(E1) = 26 / 52

Simplifying this fraction, we get:

P(E1) = 1/2

So the probability of drawing a black card is 1/2.

To calculate the probability of drawing a numbered card (E2), we need to determine the number of numbered cards (2 through 10) in a standard deck.

Each suit (spades, hearts, diamonds, clubs) contains one card for each numbered value from 2 to 10, totaling 9 numbered cards per suit.

Therefore, the probability of drawing a numbered card (P(E2)) is:

P(E2) = Number of favorable outcomes / Total number of possible outcomes

P(E2) = 36 / 52

Simplifying this fraction, we get:

P(E2) = 9/13

So the probability of drawing a numbered card is 9/13.

To calculate the probability of both events occurring together (getting a black card and a numbered card), we multiply the individual probabilities:

P(E1 ∩ E2) = P(E1) × P(E2)

P(E1 ∩ E2) = (1/2) × (9/13)

Simplifying this fraction, we get:

P(E1 ∩ E2) = 9/26

Therefore, the probability of getting a black card and a numbered card is 9/26.

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To obtain the distributed Expression

A.

4(x + 3)

We will expand by multiplying each term in the bracket by 4

=> 4 X x + 4 X 3

=> 4x + 12

B.

5 (2 + 10m + 4)

WE will also multiply each term by 5

=> 5 X 2 + 5 X 10m + 5 X 4

=> 10 + 50 M + 20

Upon collecting like terms to simplify the expression

=> 50M + 30

C.

a (8 + a) + 3a

We then Re-arrange by collecting like terms

The statement that must be true is (c) If a quadrilateral has opposite sides that are both congruent and parallel, then it is a parallelogram.

A parallelogram has parallel and congruent opposite sides.

However, the following are true about parallelograms at:

Hence, the true statement is (c)

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Answer:

5,000

Step-by-step explanation:

=10÷2[500÷5{6+4}

=10÷2[500÷5×10]

=10÷2[100×10]

=10÷2×1000

=5×1000

=5000