The energy required by the heating process is 0.042 candy bars.
We'll begin by calculating the mass of the water.
Thickness = 0.5 mm = 0.5 / 1000 = 5×10¯⁴ mArea = 1 m²Volume = Area × Thickness = 1 × 5×10¯⁴ = 5×10¯⁴ m³Density of water = 1000 Kg/m³Mass of water =?Mass = Density × Volume
Mass of water = 1000 × 5×10¯⁴
Mass of water = 0.5 Kg
Next, we shall determine the heat required
Mass of water (M) = 0.5 KgInitial temperature of water (T₁) = 10 °CFinal temperature (T₂) = 35 °CChange in temperature (ΔT) = T₂ – T₁ = 35 – 10 = 25 °CSpecific heat capacity of water (C) = 1 Kcal/KgºCHeat (Q) =?Q = MCΔT
Q = 0.5 × 1 × 25
Q = 12.5 KcalFinally, we shall convert 12.5 Kcal to candy bar.
300 Kcal = 1 candy bar
Therefore,
12.5 Kcal = 12.5/300
12.5 Kcal = 0.042 candy bars
Therefore, the energy required in candy bar is 0.042 candy bars
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Drag each tile to the correct box.
Arrange the events that are believed to have formed the hydrosphere in their order of occurrence.
1. bombardment of comets and meteorites 2. arrival of icy debris; 3. boiling of water due to Earth's enormous heat; 4. rising of water in the form of water vapor; 5. condensation of water vapor; 6. precipitation in the form of rainfall.
What is Hydrosphere?The millions of meteorites and comets that held the frozen particles that made up our planet's water brought it to us in the form of icy particles.
This frozen material was melting and boiling right away since the Earth was still incredibly hot. Water vapor increased in the Earth's atmosphere as more and more frozen particles arrived on our planet as a result of their boiling.
The water vapor began to condense as it rose higher into the atmosphere once there was enough of it present, which resulted in the formation of clouds. The first precipitation in the form of rainfall emerged from these early clouds.
Therefore, 1. bombardment of comets and meteorites 2. arrival of icy debris; 3. boiling of water due to Earth's enormous heat; 4. rising of water in the form of water vapor.
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The kinetic energy of a particle of mass 500g is 4.8j. Determine the velocity of the particle
Answer:
4.38 m/s
Explanation:
7. If a load of 300N is pulled along the inclined plane shown in the figure, answer the following. B 200 N 0.5m 2m 300 N А i. Calculate the VR and MA of the inclined plane. Calculate the input work and output work. ii.what efficiency of inclined plane?iv.what should be the length of inclined plane if same load has to be pulled with a50N effort for the same efficiency as above
Explanation:
700n I think friend .. if worng
Three 30 g metal balls, one of aluminum, copper and lead, are placed in a large beaker of hot water for a few minutes. [The specific heats of aluminum, copper, and lead are 903, 385, and 130 J / (kg ° C), respectively].
to. Which of the balls, if any, will reach the highest temperature? Explain.
b. Which of the balls, if any, will have the most heat energy? Explain.
Answer:
The answer is below
Explanation:
Specific heat capacity is an intensive property of a material. The specific heat of a material is the amount of energy required to raise the temperature of one unit mass m of material by one unit of temperature.
a) Temperature is inversely proportional to specific heat capacity. If the same amount of heat is applied to all three balls, the ball that will reach the highest temperature is the ball with the least specific heat capacity.
Hence lead will have the highest temperature since it has the least specific heat capacity.
b) The quantity of heat is directly proportional to the specific heat capacity. Hence if all balls experience the same temperature change, the ball that have the most energy will be that with the highest specific heat capacity.
Hence aluminum will have the most heat since it has the highest specific heat capacity.
What is true about the requirements of your academic care plan
Care plans are a technique to approach academic tasks strategically and make them run more quickly. They also make it possible for an academic team to communicate effectively.
A nursing care plan's goal is to list the patient's needs, preferences, and the nursing interventions (or implementations) that are planned to address those goals.
The care plan is intended to guarantee continuity of care and is kept as a part of the patient's medical file.
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Compare and contrast position graphs and velocity graphs.
Answer:
The difference between them is that the velocity-time graph reveals the speed of an object (and whether it is slowing down or speeding up), while the position-time graph describes the motion of an object over a period of time.
Explanation:
Two dogs are running a race of 100m. The green dog runs the 100m in 10s. The
red dog runs the first half of the race in 3s and then turns around and runs back
to the starting line in 5s. Describe what the velocity time graph would look like of
the race.
Answer: What type of dog is green and red?
Explanation:
How does Newtons second law of motion relate to Track and field (running sport)?
An airplane takes off at an acceleration of 2m/s2. If it continues accelerating at that rate what will the airplane change in velocity be, in m/s, 60 seconds after take off
The airplane change in velocity be 120 m/sec
What is acceleration?The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.
The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose strength or magnitude is determined by the norm and whose direction correlates with a plumb bob.
acceleration = velocity/time
Velocity = acceleration * time
Velocity = 60*2
Velocity = 120 m/sec
The airplane change in velocity be 120 m/sec
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a model rocket is launched straight upward at 58.8 m/s, how long does it take for the rocket to reach its peak height? What is the peak height of the rocket from the ground
The rocket takes 6s to reach peak height
The peak height of the rocket from the ground is 176.4m
The force that pulls objects toward the center of a planet or other body is known as gravity.
Given a model rocket is launched straight upward at 58.8 m/s,
The equation to be used to calculate the time it takes the rocket to reach peak height,
where v = final velocity
u = initial velocity = 58.8 m per sec
g = gravitational force = 9.8 m per sec²
t = duration of the flight
At the peak height,
v = 0
Therefore, 0 = 58.8 - (9.8)(t)
t = 58.8/9.8
= 6 seconds
The formula for calculating peak height is as follows:
h = ut – ½ gt2
h = 58.8 x 6 – ½ (9.8) (6)2
= 352.8 - 176.4
= 176.4 meters
Therefore
The rocket takes 6s to reach peak height
The peak height of the rocket from the ground is 176.4m
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With the maximum speed of 40 miles/hr (17.9 m/s) of your car, you can make a turn without slipping at one of the intersections near your home on a normal day. if it is raining, the road is wet and static friction is half of the normal static friction and the kinetic friction is 1/3 of normal kinetic friction. What is the maximum velocity you should have to avoid the slipping at the same intersection?
In the case of rain, the static friction is halved, meaning the new static friction coefficient is 0.5μs, while the kinetic friction is reduced to one-third, resulting in a new kinetic friction coefficient of (1/3)μk.
To determine the maximum velocity at which you can make a turn without slipping in the rain at the intersection, we need to consider the changes in friction.
Let's assume the normal static friction and normal kinetic friction are represented by μs and μk, respectively.
In the case of rain, the static friction is halved, meaning the new static friction coefficient is 0.5μs, while the kinetic friction is reduced to one-third, resulting in a new kinetic friction coefficient of (1/3)μk.
To avoid slipping during the turn, we need to ensure that the centripetal force required for the turn is less than or equal to the maximum frictional force available.
The centripetal force is given by the equation mv²/r, where m is the mass, v is the velocity, and r is the radius of the turn.
The maximum frictional force in the rain can be calculated as (0.5μs)mg, where g is the acceleration due to gravity.
Thus, to avoid slipping, we set the centripetal force equal to the maximum frictional force:
mv²/r = (0.5μs)mg
Simplifying the equation, we find:
v = √(0.5μsgr)
By plugging in the values for μs, g, and the radius of the turn, we can calculate the maximum velocity.
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Material aluminium density km-3 2-7x10² Relative density
The relative density of aluminum is 2.7. This means that aluminum is 2.7 times denser than water, which is the reference substance often used for comparing densities
The relative density (also known as specific gravity) of a material is the ratio of its density to the density of a reference substance. In this case, we are given the density of aluminum as 2.7 x 10^3 kg/m^3.
To find the relative density, we need to compare it to the density of the reference substance. The most commonly used reference substance for relative density is water, which has a density of 1000 kg/m^3.
Relative density = Density of the material / Density of the reference substance.Relative density = (2.7 x 10^3 kg/m^3) / (1000 kg/m^3)
Relative density = 2.7
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150 ml
Water at 22 °C
Iron at
125 °C
What is a possible
temperature of the
system after the iron
has been added to
the beaker?
A. 147 °C
B. 52°C
C. 125 °C
D. 19 °C
The possible temperature of the system after the iron has been added to the beaker is 52°C.
option B.
What is equilibrium temperature?A system is said to be in thermal equilibrium when there is no temperature difference between system and surroundings. Temperature, as you know, measures how hot or cold a body is with respect to a standard object.
When a system ( cold and hot body) reaches thermal equilibrium or equilibrium temperature, the heat lost by the hot body will be equal to the heat gained by the cold body.
heat gained by the water = heat lost by the iron
The equilibrium temperature will be greater than the initial temperature of the cold body but less than the final temperature of the hot.
Thus, the only possible answer for the equilibrium temperature of mixture is 52⁰C.
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What is the magnetic force on a 2.0-m length of (straight) wire carrying a current of 30 A in a region where a uniform magnetic field has a magnitude of 55 mT and is directed at an angle of 20° away from the wire?
To determine the magnetic force on a straight wire carrying a current in a uniform magnetic field, we can use the formula for the magnetic force:
F = I * L * B * sin(θ)
where:
F is the magnetic force,
I is the current in the wire,
L is the length of the wire,
B is the magnitude of the magnetic field, and
θ is the angle between the wire and the magnetic field.
In this case, the values are:
I = 30 A (current in the wire)
L = 2.0 m (length of the wire)
B = 55 mT = 0.055 T (magnitude of the magnetic field)
θ = 20° (angle between the wire and the magnetic field)
Substituting the values into the formula:
F = 30 A * 2.0 m * 0.055 T * sin(20°)
Calculating sin(20°):
F = 30 A * 2.0 m * 0.055 T * 0.3420
F ≈ 1.5714 N
Therefore, the magnetic force on the 2.0-meter length of wire carrying a current of 30 A in a region with a uniform magnetic field of magnitude 55 mT and at an angle of 20° away from the wire is approximately 1.5714 N.
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A ball is traveling at a constant speed of 4 m/s in a circle with a radius of 0.8 m. What is the centripetal acceleration of the ball?
According to the question the centripetal acceleration of the ball is 20 m/s².
What is centripetal acceleration?Centripetal acceleration is the acceleration that a body experiences when it is moving in a curved path. It is always directed towards the center of the curve, and its magnitude is equal to the square of the body's velocity divided by the radius of the curve. It is also known as the radial acceleration, since it is directed along the radius of the curve.
The centripetal acceleration of an object in a circular path is given by the equation:
\(a_c\) = v²/r
where a_c is the centripetal acceleration, v is the speed of the object, and r is the radius of the circular path.
In this case, the speed of the ball is 4 m/s, and the radius of the circular path is 0.8 m. Plugging these values into the equation, we get:
\(a_c\) = 4²/0.8 = 16/0.8 = 20 m/s²
Therefore, the centripetal acceleration of the ball is 20 m/s².
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Jack drops off 10m high red bridge into swimming waters below. Assuming acceleration to be 9.91 m/s^2
A. What Jack speed as he hits the water?
Jack speed as he hits the water is 14.13m/s
What is speed?
The speed of an object, also known as v in kinematics, is the size of the change in that object's position over time or the size of the change in that object's position per unit of time, making it a scalar quantity. The instantaneous speed is the upper limit of the average speed as the duration of the time interval approaches zero. The average speed of an item in a period of time is equal to the distance travelled by the object divided by the duration of the period. Velocity and speed are not the same thing.
The only force on Jack is gravity, which points straight down, and has an acceleration of 9.91m/s². Whether he's falling off a bridge or simply standing still on the surface of the earth, the acceleration due to gravity is the same.
If you're looking for the speed of Jack as he hits the water, you just need to solve for v in the equation\($v^2 = v_0^2 + 2ad$\).
Here,
v is Jack's speed as he hits the water,
\($v_0$\) is Jack's initial speed (which is zero since he's not moving when he jumps),
a is Jack's acceleration (which is 9.91m/s²), and
d is Jack's displacement (which is the height of the bridge, which you said is 10m).
This gives you an answer of \($v = \sqrt{2ad} = \sqrt{2(9.91)(10)} = 14.13 \ \mathrm{m/s}$\)
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The marble has its maximum gravitational potential energy when it is at the starting point: the
highest point on the roller coaster. How much of this potential energy is converted to the
marble's kinetic energy?
Answer:
Explanation:
This depends on the height.
Using the formula mgh + 1/2mv^2 = total mechanical energy, we can determine the amount of kinetic and potential energy. I'm assuming your talking about if the marble goes all the down, then all of the energy is converted.
We believe that chains of comet fragments like Comet Shoemaker-Levy 9’s have collided not only with the jovian planets, but occasionally with their moons. What sort of features would you look for on the outer planet moons to find evidence of such collisions?
For signs of such collisions on the moons of the outer planets, look for craters, ray systems, fissures and fractures, melted or evaporated material, and changes in the moon's surface composition.
What took place when comet shoemaker-Levy 9 hit Jupiter?Huge fragments of the newly discovered comet Shoemaker-Levy 9 (SL9) collided with Jupiter over a period of days from July 16 to 22, 1994, leaving vast, dark scars in the planet's atmosphere and lofting superheated plumes into its stratosphere.
Why did astronomers consider the Shoemaker 9 impact on Jupiter to be so significant?Dust was also left floating on top of Jupiter's clouds after the collision. The movement of the planet's dust allowed researchers to trace Jupiter's high-altitude winds for the first time.
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From what height must an oxygen molecule fall in a vacuum so that its kinetic energy at the bottom equals the average energy of an oxygen molecule at 300 K ?
Answer:
The value is \(h = 11930 \ m\)
Explanation:
From the question we are told that
The temperature is \(T = 300 \ K\)
Generally the root mean square speed of the oxygen molecules is mathematically represented as
\(v = \sqrt{\frac{3 * R * T }{M} } = \sqrt{ 2 * g * h }\)
Here R is the gas constant with a value \(R = 8.314 \ J\cdot K^{-1} \cdot \ mol^{-1}\)
M is the molar mass of oxygen molecule with value \(M = 0.032 \ kg /mol\)
So
\(\frac{3 * 8.314 * 300 }{0.032} = 2 * 9.8 * h\)
=> \(h = 11930 \ m\)
Question 5 0/1pts Scalar (dot) product: If=41-1+4k and B-xÎ +27-5X find x so B will be perpendicular to
the photoelectric
threshold
for an
unknown metal is 10
= 275 nm. calculate
the extraction work
for an electron from
this metal and the
maximum speed of
electrons extracted
by radiation with a
wavelength of λ =
180 nm.
As vₙ<v, no photoelectron is emitted, thus no extraction work is required.
The minimum frequency of incident radiation below which photoelectric emission or electron emission is not feasible is referred to as the threshold frequency.
The frequency of light at which an electron will be forced to leave a metal surface is referred to as the threshold frequency.
The wavelength of incident radiation is λ = 180nm = 1800A = 1800 * 10⁻¹⁰ m.
Therefore, the frequency of incident radiation is
v = c / λ
v = 3 * 10⁸ / 1800 * 10⁻¹⁰
v = 0.166 * 10¹⁶ Hz
Therefore, threshold frequency is
v₀ = c/λₙ
vₙ = 3 * 10⁸ / 275 * 10⁻¹⁰
vₙ = = 1.09 * 10¹⁶ Hz
As vₙ<v, no photoelectron is emitted.
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the surface of a mirror is flat.
Answer:
plane on edge
Explanation:
What precise meaning do you attach to the statement r = (24.0 ± 0.3) mm, where r is the radius of a tube.
The information provided above demonstrates that the range of the tube's radius within which we are certain is from 23.7 to 24.3.
Accurate findings are desired when any quantity is being measured. Closeness of the measurements to a particular value is referred to as accuracy (like the theoretical value). It is not insignificant that measurements can contain inaccuracies; as a result, the outcome frequently includes a margin error. The sentence above displays the radius's measured value along with its margin of error.
In other words, the aforementioned statement represents a quantity's numerical value along with its tolerance, or the only permissible (and conceivable) values to ensure that the measurement is accurate. The information provided above demonstrates that the range of the tube's radius within which we are certain is from 23.7 to 24.3.
These are all valid radius values, along with all others within this interval. By increasing the number of trials in a measurement, the value for the upper and lower bounds of the error can be decreased.
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The spring constant of Spring A is twice as great as the spring constant of Spring B. Both springs are stretched the same amount. How does the
force the Spring A applies compare to the force Spring B applies?
Answer:
FA = 2FB
Force on spring A is twice the Force on spring B
Explanation:
F = kx
FB = (kB)x
FA = (kA)x
FA= (2kB)x
FA = 2(kB)x
FA = 2FB
The force \(F_A\) needed to stretch spring A is going to be twice as much as the force \(F_B\) needed to stretch spring B.
Explanation:
We know that the spring constants are related as
\(k_A = 2k_B\)
The force \(F_A\) needed to stretch spring A is given by
\(F_A = -k_Ax\)
Also, the force \(F_B\) needed to stretch spring is
\(F_B = -k_Bx\)
Taking the ratio of the forces, we get
\(\dfrac{F_A}{F_B} = \dfrac{-k_Ax}{-k_Bx} = \dfrac{k_A}{k_B}\)
Since \(k_A = 2k_B,\) the equation above becomes
\(\dfrac{F_A}{F_B} = \dfrac{2k_B}{k_B} = 2\)
or
\(F_A = 2F_B\)
This shows that since the spring constant of spring A is twice as large as that of spring B, the force needed is going to be twice as large.
10 POINTS! SPACE QUESTION!!
A roller coaster has a vertical loop with radius 29.5 m.What is the minimum speed of the roller coaster car can have at the top of the loop if the passengers do not lose contact with the seats?
A) 10.0 m/s
B) 14.0 m/s
C) 17.0 m/s
D) 19.0 m/s
Answer:the Minimum speed , v of the roller coster = 17.0 m/s --c
Explanation:
According to Newton's First law of Motion which state that all object will remain at rest unless an external force is applied on the body to act otherwise.
Therefore the Force exerted/ acting on the surface of the roller coaster will be equal to 0,
Net Force = 0
Remember that , Force = mg = Mv ²/r = 0
Net Force =mv ² / r - mg = 0
mv²/ r - mg = 0
(diving through by m)
v²/r -g = 0
v² = gr
v= \(\sqrt{gr}\)
where g, acceleration due to gravity= 9.8m/s2 and radius, r = 29.5m
v= \(\sqrt{9.8m/s2 X 29.5m }\)
v =\(\sqrt{ 289}\)
v= 17.0 m/s
Therefore, the Minimum speed , v of the roller coaster = 17.0 m/s
A tire spinning at 5m/s uniformly accelerates to 10 m/s in five seconds. Its radius is 10 cm. Through what angle will pebble stuck in the tire revolve during this interval?
20 cm and 9 cm 30 cm is the distance for 5 mins so it will be 20 cm
A spring with spring constant 40 N/m is compressed .1m past it natural length. A mass of .5kg is attached to the spring. A. What is the elastic potential energy stored in the spring?B. The spring is released. What is the speed of the masses as it reaches the natural length of the spring?
Given data
*The given spring constant is k = 40 N/m
*The given compressed length is x = 0.1 m
*The given mass is m = 0.5 kg
(a)
The formula for the elastic potential energy stored in the spring is given as
\(U_p=\frac{1}{2}kx^2\)Substitute the values in the above expression as
\(\begin{gathered} U_p=\frac{1}{2}(40)(0.1)^2 \\ =0.2\text{ J} \end{gathered}\)Hence, the elastic potential energy stored in the spring is 0.2 J
(b)
The formula for the speed of the masses is given by the conservation of energy as
\(\begin{gathered} U_p=U_k \\ \frac{1}{2}kx^2=\frac{1}{2}mv^2 \\ v=x\sqrt[]{\frac{k}{m}} \end{gathered}\)Substitute the values in the above expression as
\(\begin{gathered} v=(0.1)\sqrt[]{\frac{40}{0.5}} \\ =0.89\text{ m/s} \end{gathered}\)Hence, the speed of the masses as it reaches the length of the spring is v = 0.89 m/s
A 16.0 kg canoe moving to the left at 12.5 m/s makes an elastic head-on collision with a 14.0 kg raft moving to the right at 16.0 m/s. After the collision, the raft moves to the left at 14.4 m/s. What is the velocity of the canoe after the collision?
According to the law of conservation of momentum, the velocity of the canoe after the collision will be 17.79 meters per second.
What is the law of conservation of momentum?The law of conservation of momentum states that the momentum of the system of objects remains constant before and after the collision unless an external force is applied.
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
where, m₁ is the mass of one object and m₂ is the mass of second object,
u₁ and u₂ are initial velocities of object one and two,
v₁ and v₂ are the final velocities of object one and two.
16 × 12.5 + 14 × 16 = 12.5 × v₁ + 14 × 14.4
200 + 224 = 12.5v₁ + 201.6
424 = 12.5v₁ + 201.6
424 - 201.6 = 12.5v₁
222.4 = 12.5v₁
v₁ = 222.4/ 12.5
v₁ = 17.79 m/s
Therefore, the velocity of the canoe after the collision will be 17.79 meters per second.
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Question 6 of 10
How would you change the distance between two charged particles to
increase the electric force between them by a factor of 16?
A. Reduce the distance by a factor of 4.
B. Increase the distance by a factor of 4.
C. Reduce the distance by a factor of 16.
D. Increase the distance by a factor of 16.
SUBMIT
Reduce the distance by a factor of 4 change the distance between two charged particles to increase the electric force between them by a factor of 16.
Thus, When charged things interact with other objects, there is an electric force present in the system.
The electric force between them is appealing because positive charges are attracted to negative charges. For two positive charges or two negative charges, the electric force is repellent.
A typical illustration of this is what happens when two balloons are rubbed on a blanket. When you rub the balloons against the blanket, electrons from the blanket transfer to the balloons, leaving the blanket positively charged and the balloons negatively charged.
Thus, Reduce the distance by a factor of 4 change the distance between two charged particles to increase the electric force between them by a factor of 16.
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