gap region between the diver's skin and her
wetsuit, forming a water layer about 0.5 mm thick.
Assume that the total surface area of the wetsuit
covering the diver is about 1.0 mº, and that the
water enters the suit at 10 °C and is warmed by
the diver to skin temperature of 35°C. The specific
heat of water is 1.00 kcal/kg - Cº.
Estimate how much energy (in
units of candy bars = 300 kcal)
is required by this heating
process.
Express your answer using
two significant figures.

Answers

Answer 1

The energy required by the heating process is 0.042 candy bars.

We'll begin by calculating the mass of the water.

Thickness = 0.5 mm = 0.5 / 1000 = 5×10¯⁴ mArea = 1 m²Volume = Area × Thickness = 1 × 5×10¯⁴ = 5×10¯⁴ m³Density of water = 1000 Kg/m³Mass of water =?

Mass = Density × Volume

Mass of water = 1000 × 5×10¯⁴

Mass of water = 0.5 Kg

Next, we shall determine the heat required

Mass of water (M) = 0.5 KgInitial temperature of water (T₁) = 10 °CFinal temperature (T₂) = 35 °CChange in temperature (ΔT) = T₂ – T₁ = 35 – 10 = 25 °CSpecific heat capacity of water (C) = 1 Kcal/KgºCHeat (Q) =?

Q = MCΔT

Q = 0.5 × 1 × 25

Q = 12.5 Kcal

Finally, we shall convert 12.5 Kcal to candy bar.

300 Kcal = 1 candy bar

Therefore,

12.5 Kcal = 12.5/300

12.5 Kcal = 0.042 candy bars

Therefore, the energy required in candy bar is 0.042 candy bars

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Related Questions

Drag each tile to the correct box.
Arrange the events that are believed to have formed the hydrosphere in their order of occurrence.

Drag each tile to the correct box.Arrange the events that are believed to have formed the hydrosphere

Answers

1.  bombardment of comets and meteorites 2. arrival of icy debris; 3. boiling of water due to Earth's enormous heat; 4. rising of water in the form of water vapor; 5. condensation of water vapor; 6. precipitation in the form of rainfall.

What is Hydrosphere?

The millions of meteorites and comets that held the frozen particles that made up our planet's water brought it to us in the form of icy particles.

This frozen material was melting and boiling right away since the Earth was still incredibly hot. Water vapor increased in the Earth's atmosphere as more and more frozen particles arrived on our planet as a result of their boiling.

The water vapor began to condense as it rose higher into the atmosphere once there was enough of it present, which resulted in the formation of clouds. The first precipitation in the form of rainfall emerged from these early clouds.

Therefore, 1.  bombardment of comets and meteorites 2. arrival of icy debris; 3. boiling of water due to Earth's enormous heat; 4. rising of water in the form of water vapor.

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The kinetic energy of a particle of mass 500g is 4.8j. Determine the velocity of the particle

Answers

Answer:

4.38 m/s

Explanation:

The kinetic energy of a particle of mass 500g is 4.8j. Determine the velocity of the particle
The answer is 4.38 m/s
The kinetic energy of a particle of mass 500g is 4.8j. Determine the velocity of the particle

7. If a load of 300N is pulled along the inclined plane shown in the figure, answer the following. B 200 N 0.5m 2m 300 N А i. Calculate the VR and MA of the inclined plane. Calculate the input work and output work. ii.what efficiency of inclined plane?iv.what should be the length of inclined plane if same load has to be pulled with a50N effort for the same efficiency as above​

Answers

Explanation:

700n I think friend .. if worng

Three 30 g metal balls, one of aluminum, copper and lead, are placed in a large beaker of hot water for a few minutes. [The specific heats of aluminum, copper, and lead are 903, 385, and 130 J / (kg ° C), respectively].
to. Which of the balls, if any, will reach the highest temperature? Explain.
b. Which of the balls, if any, will have the most heat energy? Explain.

Answers

Answer:

The answer is below

Explanation:

Specific heat capacity is an intensive property of a material. The specific heat of a material is the amount of energy required to raise the temperature of one unit mass m of material by one unit of temperature.

a) Temperature is inversely proportional to specific heat capacity. If the same amount of heat is applied to all three balls, the ball that will reach the highest temperature is the ball with the least specific heat capacity.

Hence lead will have the highest temperature since it has the least specific heat capacity.

b) The quantity of heat is directly proportional to the specific heat capacity. Hence if all balls experience the same temperature change, the ball that have the most energy will be that with the highest specific heat capacity.

Hence aluminum will have the most heat since it has the highest specific heat capacity.

What is true about the requirements of your academic care plan

Answers

Care plans are a technique to approach academic tasks strategically and make them run more quickly. They also make it possible for an academic team to communicate effectively.

A nursing care plan's goal is to list the patient's needs, preferences, and the nursing interventions (or implementations) that are planned to address those goals.

The care plan is intended to guarantee continuity of care and is kept as a part of the patient's medical file.

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Compare and contrast position graphs and velocity graphs.

Answers

Answer:

The difference between them is that the velocity-time graph reveals the speed of an object (and whether it is slowing down or speeding up), while the position-time graph describes the motion of an object over a period of time.

Explanation:

Two dogs are running a race of 100m. The green dog runs the 100m in 10s. The
red dog runs the first half of the race in 3s and then turns around and runs back
to the starting line in 5s. Describe what the velocity time graph would look like of
the race.

Answers

Answer: What type of dog is green and red?

Explanation:

How does Newtons second law of motion relate to Track and field (running sport)?

Answers

Newton's second law also helps to explain what happens every time an athlete lands during running. When the foot hits the track, it will decelerate to a stop before leaving the track again. The faster the deceleration, the greater the force of impact on the foot.

An airplane takes off at an acceleration of 2m/s2. If it continues accelerating at that rate what will the airplane change in velocity be, in m/s, 60 seconds after take off

Answers

The airplane change in velocity be 120 m/sec

What is acceleration?

The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.

The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose strength or magnitude is determined by the norm and whose direction correlates with a plumb bob.

acceleration = velocity/time

Velocity = acceleration * time

Velocity = 60*2

Velocity = 120 m/sec

The airplane change in velocity be 120 m/sec

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a model rocket is launched straight upward at 58.8 m/s, how long does it take for the rocket to reach its peak height? What is the peak height of the rocket from the ground

Answers

The rocket takes 6s to reach peak height

The peak height of the rocket from the ground is 176.4m

The force that pulls objects toward the center of a planet or other body is known as gravity.  

Given a model rocket is launched straight upward at 58.8 m/s,

The equation to be used to calculate the time it takes the rocket to reach peak height,

where v = final velocity

u = initial velocity = 58.8 m per sec

g = gravitational force = 9.8 m per sec²

t = duration of the flight

At the peak height,

v = 0

Therefore, 0 = 58.8 - (9.8)(t)

t = 58.8/9.8

= 6 seconds

The formula for calculating peak height is as follows:

h = ut – ½ gt2

h = 58.8 x 6 – ½ (9.8) (6)2

= 352.8 - 176.4

= 176.4 meters

Therefore

The rocket takes 6s to reach peak height

The peak height of the rocket from the ground is 176.4m

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With the maximum speed of 40 miles/hr (17.9 m/s) of your car, you can make a turn without slipping at one of the intersections near your home on a normal day. if it is raining, the road is wet and static friction is half of the normal static friction and the kinetic friction is 1/3 of normal kinetic friction. What is the maximum velocity you should have to avoid the slipping at the same intersection?

Answers

In the case of rain, the static friction is halved, meaning the new static friction coefficient is 0.5μs, while the kinetic friction is reduced to one-third, resulting in a new kinetic friction coefficient of (1/3)μk.

To determine the maximum velocity at which you can make a turn without slipping in the rain at the intersection, we need to consider the changes in friction.

Let's assume the normal static friction and normal kinetic friction are represented by μs and μk, respectively.

In the case of rain, the static friction is halved, meaning the new static friction coefficient is 0.5μs, while the kinetic friction is reduced to one-third, resulting in a new kinetic friction coefficient of (1/3)μk.

To avoid slipping during the turn, we need to ensure that the centripetal force required for the turn is less than or equal to the maximum frictional force available.

The centripetal force is given by the equation mv²/r, where m is the mass, v is the velocity, and r is the radius of the turn.

The maximum frictional force in the rain can be calculated as (0.5μs)mg, where g is the acceleration due to gravity.

Thus, to avoid slipping, we set the centripetal force equal to the maximum frictional force:

mv²/r = (0.5μs)mg

Simplifying the equation, we find:

v = √(0.5μsgr)

By plugging in the values for μs, g, and the radius of the turn, we can calculate the maximum velocity.

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Material aluminium density km-3 2-7x10² Relative density​

Answers

The relative density of aluminum is 2.7. This means that aluminum is 2.7 times denser than water, which is the reference substance often used for comparing densities

The relative density (also known as specific gravity) of a material is the ratio of its density to the density of a reference substance. In this case, we are given the density of aluminum as 2.7 x 10^3 kg/m^3.

To find the relative density, we need to compare it to the density of the reference substance. The most commonly used reference substance for relative density is water, which has a density of 1000 kg/m^3.

Relative density = Density of the material / Density of the reference substance.Relative density = (2.7 x 10^3 kg/m^3) / (1000 kg/m^3)

Relative density = 2.7

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150 ml
Water at 22 °C
Iron at
125 °C

What is a possible
temperature of the
system after the iron
has been added to
the beaker?
A. 147 °C
B. 52°C
C. 125 °C
D. 19 °C

Answers

The possible temperature of the system after the iron has been added to the beaker is 52°C.

option B.

What is equilibrium temperature?

A system is said to be in thermal equilibrium when there is no temperature difference between system and surroundings. Temperature, as you know, measures how hot or cold a body is with respect to a standard object.

When a system ( cold and hot body) reaches thermal equilibrium or equilibrium temperature, the heat lost by the hot body will be equal to the heat gained by the cold body.

heat gained by the water = heat lost by the iron

The equilibrium temperature will be greater than the initial temperature of the cold body but less than the final temperature of the hot.

Thus, the only possible answer for the equilibrium temperature of mixture is 52⁰C.

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What is the magnetic force on a 2.0-m length of (straight) wire carrying a current of 30 A in a region where a uniform magnetic field has a magnitude of 55 mT and is directed at an angle of 20° away from the wire?

Answers

To determine the magnetic force on a straight wire carrying a current in a uniform magnetic field, we can use the formula for the magnetic force:

F = I * L * B * sin(θ)

where:

F is the magnetic force,

I is the current in the wire,

L is the length of the wire,

B is the magnitude of the magnetic field, and

θ is the angle between the wire and the magnetic field.

In this case, the values are:

I = 30 A (current in the wire)

L = 2.0 m (length of the wire)

B = 55 mT = 0.055 T (magnitude of the magnetic field)

θ = 20° (angle between the wire and the magnetic field)

Substituting the values into the formula:

F = 30 A * 2.0 m * 0.055 T * sin(20°)

Calculating sin(20°):

F = 30 A * 2.0 m * 0.055 T * 0.3420

F ≈ 1.5714 N

Therefore, the magnetic force on the 2.0-meter length of wire carrying a current of 30 A in a region with a uniform magnetic field of magnitude 55 mT and at an angle of 20° away from the wire is approximately 1.5714 N.

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A ball is traveling at a constant speed of 4 m/s in a circle with a radius of 0.8 m. What is the centripetal acceleration of the ball?

Answers

According to the question the centripetal acceleration of the ball is 20 m/s².

What is centripetal acceleration?

Centripetal acceleration is the acceleration that a body experiences when it is moving in a curved path. It is always directed towards the center of the curve, and its magnitude is equal to the square of the body's velocity divided by the radius of the curve. It is also known as the radial acceleration, since it is directed along the radius of the curve.

The centripetal acceleration of an object in a circular path is given by the equation:

\(a_c\) = v²/r
where a_c is the centripetal acceleration, v is the speed of the object, and r is the radius of the circular path.
In this case, the speed of the ball is 4 m/s, and the radius of the circular path is 0.8 m. Plugging these values into the equation, we get:

\(a_c\) = 4²/0.8 = 16/0.8 = 20 m/s²
Therefore, the centripetal acceleration of the ball is 20 m/s².

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Jack drops off 10m high red bridge into swimming waters below. Assuming acceleration to be 9.91 m/s^2

A. What Jack speed as he hits the water?

Answers

Jack speed as he hits the water is 14.13m/s

What is speed?
The speed of an object, also known as v in kinematics, is the size of the change in that object's position over time or the size of the change in that object's position per unit of time, making it a scalar quantity. The instantaneous speed is the upper limit of the average speed as the duration of the time interval approaches zero. The average speed of an item in a period of time is equal to the distance travelled by the object divided by the duration of the period. Velocity and speed are not the same thing.

The only force on Jack is gravity, which points straight down, and has an acceleration of 9.91m/s².  Whether he's falling off a bridge or simply standing still on the surface of the earth, the acceleration due to gravity is the same.

If you're looking for the speed of Jack as he hits the water, you just need to solve for v in the equation\($v^2 = v_0^2 + 2ad$\).  
Here,
v is Jack's speed as he hits the water,
\($v_0$\) is Jack's initial speed (which is zero since he's not moving when he jumps),
a is Jack's acceleration (which is 9.91m/s²), and
d is Jack's displacement (which is the height of the bridge, which you said is 10m).  
This gives you an answer of \($v = \sqrt{2ad} = \sqrt{2(9.91)(10)} = 14.13 \ \mathrm{m/s}$\)

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The marble has its maximum gravitational potential energy when it is at the starting point: the
highest point on the roller coaster. How much of this potential energy is converted to the
marble's kinetic energy?

Answers

Answer:

Explanation:

This depends on the height.

Using the formula mgh + 1/2mv^2 = total mechanical energy, we can determine the amount of kinetic and potential energy. I'm assuming your talking about if the marble goes all the down, then all of the energy is converted.

We believe that chains of comet fragments like Comet Shoemaker-Levy 9’s have collided not only with the jovian planets, but occasionally with their moons. What sort of features would you look for on the outer planet moons to find evidence of such collisions?

Answers

For signs of such collisions on the moons of the outer planets, look for craters, ray systems, fissures and fractures, melted or evaporated material, and changes in the moon's surface composition.

What took place when comet shoemaker-Levy 9 hit Jupiter?

Huge fragments of the newly discovered comet Shoemaker-Levy 9 (SL9) collided with Jupiter over a period of days from July 16 to 22, 1994, leaving vast, dark scars in the planet's atmosphere and lofting superheated plumes into its stratosphere.

Why did astronomers consider the Shoemaker 9 impact on Jupiter to be so significant?

Dust was also left floating on top of Jupiter's clouds after the collision. The movement of the planet's dust allowed researchers to trace Jupiter's high-altitude winds for the first time.

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From what height must an oxygen molecule fall in a vacuum so that its kinetic energy at the bottom equals the average energy of an oxygen molecule at 300 K ?

Answers

Answer:

The  value is  \(h = 11930 \ m\)

Explanation:

From the question we are told that

    The  temperature is  \(T = 300 \ K\)

     

Generally the root mean square speed of the  oxygen molecules is mathematically represented as

        \(v = \sqrt{\frac{3 * R * T }{M} } = \sqrt{ 2 * g * h }\)

Here  R is the gas constant with a value  \(R = 8.314 \ J\cdot K^{-1} \cdot \ mol^{-1}\)

    M  is the molar mass of oxygen molecule with value \(M = 0.032 \ kg /mol\)

So  

     \(\frac{3 * 8.314 * 300 }{0.032} = 2 * 9.8 * h\)

=>    \(h = 11930 \ m\)

   

Question 5 0/1pts Scalar (dot) product: If=41-1+4k and B-xÎ +27-5X find x so B will be perpendicular to​

Answers

Refer to the photo taken.
Question 5 0/1pts Scalar (dot) product: If=41-1+4k and B-x +27-5X find x so B will be perpendicular to

the photoelectric
threshold
for an
unknown metal is 10
= 275 nm. calculate
the extraction work
for an electron from
this metal and the
maximum speed of
electrons extracted
by radiation with a
wavelength of λ =
180 nm.

Answers

As vₙ<v, no photoelectron is emitted, thus no extraction work is required.

The minimum frequency of incident radiation below which photoelectric emission or electron emission is not feasible is referred to as the threshold frequency.

The frequency of light at which an electron will be forced to leave a metal surface is referred to as the threshold frequency.

The wavelength of incident radiation is λ = 180nm = 1800A = 1800 * 10⁻¹⁰ m.

Therefore, the frequency of incident radiation is

v = c / λ

v = 3 * 10⁸ / 1800 * 10⁻¹⁰

v = 0.166 * 10¹⁶ Hz

Therefore, threshold frequency is

v₀ = c/λₙ

vₙ = 3 * 10⁸ / 275 * 10⁻¹⁰

vₙ = = 1.09 * 10¹⁶ Hz

As vₙ<v, no photoelectron is emitted.

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the surface of a mirror is flat.

Answers

Answer:

plane on edge

Explanation:

What precise meaning do you attach to the statement r = (24.0 ± 0.3) mm, where r is the radius of a tube.

Answers

The information provided above demonstrates that the range of the tube's radius within which we are certain is from 23.7 to 24.3.

Accurate findings are desired when any quantity is being measured. Closeness of the measurements to a particular value is referred to as accuracy (like the theoretical value). It is not insignificant that measurements can contain inaccuracies; as a result, the outcome frequently includes a margin error. The sentence above displays the radius's measured value along with its margin of error.

In other words, the aforementioned statement represents a quantity's numerical value along with its tolerance, or the only permissible (and conceivable) values to ensure that the measurement is accurate. The information provided above demonstrates that the range of the tube's radius within which we are certain is from 23.7 to 24.3.

These are all valid radius values, along with all others within this interval. By increasing the number of trials in a measurement, the value for the upper and lower bounds of the error can be decreased.

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The spring constant of Spring A is twice as great as the spring constant of Spring B. Both springs are stretched the same amount. How does the
force the Spring A applies compare to the force Spring B applies?

Answers

Answer:

FA = 2FB

Force on spring A is twice the Force on spring B

Explanation:

F = kx

FB = (kB)x

FA = (kA)x

FA= (2kB)x

FA = 2(kB)x

FA = 2FB

The force \(F_A\) needed to stretch spring A is going to be twice as much as the force \(F_B\) needed to stretch spring B.

Explanation:

We know that the spring constants are related as

\(k_A = 2k_B\)

The force \(F_A\) needed to stretch spring A is given by

\(F_A = -k_Ax\)

Also, the force \(F_B\) needed to stretch spring is

\(F_B = -k_Bx\)

Taking the ratio of the forces, we get

\(\dfrac{F_A}{F_B} = \dfrac{-k_Ax}{-k_Bx} = \dfrac{k_A}{k_B}\)

Since \(k_A = 2k_B,\) the equation above becomes

\(\dfrac{F_A}{F_B} = \dfrac{2k_B}{k_B} = 2\)

or

\(F_A = 2F_B\)

This shows that since the spring constant of spring A is twice as large as that of spring B, the force needed is going to be twice as large.

10 POINTS! SPACE QUESTION!!

Answers

Is there a p,if of the question?
Hdbsnanndmdndnsnvdmsksv fndksndndndndb Dbd be did d djbd f be d Dbd d f

A roller coaster has a vertical loop with radius 29.5 m.What is the minimum speed of the roller coaster car can have at the top of the loop if the passengers do not lose contact with the seats?
A) 10.0 m/s
B) 14.0 m/s
C) 17.0 m/s
D) 19.0 m/s

Answers

Answer:the  Minimum speed , v of the roller coster = 17.0 m/s --c

Explanation:

According to Newton's First law  of Motion which state that all object will remain at rest unless an external force is applied on the body to act otherwise.

Therefore the   Force exerted/ acting  on the surface of  the roller coaster will be equal to 0,

Net Force = 0

Remember that , Force = mg = Mv ²/r = 0

 Net Force =mv ² / r - mg = 0

mv²/ r - mg = 0

(diving through by m)

v²/r -g = 0

v² = gr

v= \(\sqrt{gr}\)

where g, acceleration due to gravity= 9.8m/s2 and radius, r = 29.5m

v=  \(\sqrt{9.8m/s2 X 29.5m }\)

v =\(\sqrt{ 289}\)

v=  17.0 m/s

Therefore, the  Minimum speed , v of the roller coaster = 17.0 m/s

A tire spinning at 5m/s uniformly accelerates to 10 m/s in five seconds. Its radius is 10 cm. Through what angle will pebble stuck in the tire revolve during this interval?

Answers

20 cm and 9 cm 30 cm is the distance for 5 mins so it will be 20 cm

A spring with spring constant 40 N/m is compressed .1m past it natural length. A mass of .5kg is attached to the spring. A. What is the elastic potential energy stored in the spring?B. The spring is released. What is the speed of the masses as it reaches the natural length of the spring?

Answers

Given data

*The given spring constant is k = 40 N/m

*The given compressed length is x = 0.1 m

*The given mass is m = 0.5 kg

(a)

The formula for the elastic potential energy stored in the spring is given as

\(U_p=\frac{1}{2}kx^2\)

Substitute the values in the above expression as

\(\begin{gathered} U_p=\frac{1}{2}(40)(0.1)^2 \\ =0.2\text{ J} \end{gathered}\)

Hence, the elastic potential energy stored in the spring is 0.2 J

(b)

The formula for the speed of the masses is given by the conservation of energy as

\(\begin{gathered} U_p=U_k \\ \frac{1}{2}kx^2=\frac{1}{2}mv^2 \\ v=x\sqrt[]{\frac{k}{m}} \end{gathered}\)

Substitute the values in the above expression as

\(\begin{gathered} v=(0.1)\sqrt[]{\frac{40}{0.5}} \\ =0.89\text{ m/s} \end{gathered}\)

Hence, the speed of the masses as it reaches the length of the spring is v = 0.89 m/s

A 16.0 kg canoe moving to the left at 12.5 m/s makes an elastic head-on collision with a 14.0 kg raft moving to the right at 16.0 m/s. After the collision, the raft moves to the left at 14.4 m/s. What is the velocity of the canoe after the collision?​

Answers

According to the law of conservation of momentum, the velocity of the canoe after the collision will be 17.79 meters per second.

What is the law of conservation of momentum?

The law of conservation of momentum states that the momentum of the system of objects remains constant before and after the collision unless an external force is applied.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

where, m₁ is the mass of one object and m₂ is the mass of second object,

u₁ and u₂ are initial velocities of object one and two,

v₁ and v₂ are the final velocities of object one and two.

16 × 12.5 + 14 × 16 = 12.5 × v₁ + 14 × 14.4

200 + 224 = 12.5v₁ + 201.6

424 = 12.5v₁ + 201.6

424 - 201.6 = 12.5v₁

222.4 = 12.5v₁

v₁ = 222.4/ 12.5

v₁ = 17.79 m/s

Therefore, the velocity of the canoe after the collision will be 17.79 meters per second.

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Question 6 of 10
How would you change the distance between two charged particles to
increase the electric force between them by a factor of 16?
A. Reduce the distance by a factor of 4.
B. Increase the distance by a factor of 4.
C. Reduce the distance by a factor of 16.
D. Increase the distance by a factor of 16.
SUBMIT

Answers

Reduce the distance by a factor of 4 change the distance between two charged particles to increase the electric force between them by a factor of 16.

Thus, When charged things interact with other objects, there is an electric force present in the system.

The electric force between them is appealing because positive charges are attracted to negative charges. For two positive charges or two negative charges, the electric force is repellent.

A typical illustration of this is what happens when two balloons are rubbed on a blanket. When you rub the balloons against the blanket, electrons from the blanket transfer to the balloons, leaving the blanket positively charged and the balloons negatively charged.

Thus, Reduce the distance by a factor of 4 change the distance between two charged particles to increase the electric force between them by a factor of 16.

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approximately how far ahead would one need to plan for the following types of facilities? a. restaurant b. hospital c. oil refinery d. toy factory e. electric power plant f. public school g. private school Determine whether the statements regarding gametophytes and sporophytes pertain to nonvascular plants, seedless vascular plants, or seedbearing vascular plants. how was the antebellum (pre civil war) republican party different from democrats Date: December 12, 2021Merry Christmas, everyone! Since Christmas Vacation is around the corner, I think everyone deserves a break. So here are some Xmas Trivia questions to get you all in the holiday spirit! 1: Buddy the Elf sticks to the four main food groups; candy, candy canes, candy corns, and ____? 2: In the song "Winter Wonderland", what do we call the snowman? 3: Which Hollywood actor played six roles in the movie "The Polar Express"? high school class rank is highly correlated with college gpa. this is an example of what type of validity? group of answer choices construct validity predictive validity concurrent validity content validity Describe laws related to employment, in particular with regardto EmploymentRelations Act 2004 and what these legislations means with regardsto termination ofemployment The residence of a city voted on whether to raise property taxes the ratio of yes votes to know votes was 5 to 6 if there was 5844 Novos what was the total number of votes What critereia does your compass need to meet for it to work as a magnetometer? I need help finding area of this shape Suppose you have $1600 in your savings account at the end of a certain period of time. You invested $1500at a 6.49% simple annual interest rate. How long, in years, was your money invested? 2. What is the basic difference between cardinal and ordinal approaches of utility? 3. Elaborate the justifications for the negative slope and convexity of indifference curve. 4. Standard indifference curves cannot intersect each other. Why? 5. Does the change in income affect the slope of the budget line? Explain. Name the earth system that contains the lithosphere. a. Atmosphere b. Cryosphere c. Hydrogen d. Geosphere Does GDP increase when inflation increases? QuestionAlthough the javelina resembles a pig in appearance, but has a more complex digestive system than a pigO but hasO but havingO it havingO it has Can someone plz help me SUMMARISE (30 PTS)Global Climate Change may be responsible in part for some trends in natural disasters such as extreme weather.Based on future projections of climate change, the IPCC (International Panel on Climate Control) report makes a number of predictions. It is predicted that over most land areas, the frequency of warm spells or heat waves will very likely increase. It is likely that:Increased areas will be affected by droughtThere will be increased intense tropical cyclone activityThere will be increased incidences of extreme high sea level (excluding tsunamis)Storm strength leading to extreme weather is increasing, such as the power dissipation index of hurricane intensity. Kerry Emanuel writes that hurricane power dissipation is highly correlated with temperature, reflecting global Climate change. However, a further study by Emanuel using current model output concluded that the increase in power dissipation in recent decades cannot be completely attributed to global Climate change. Hurricane modeling has produced similar results, finding that hurricanes, simulated under warmer, high-CO2 conditions, are more intense, however, hurricane frequency will be reduced.] Worldwide, the proportion of hurricanes reaching categories 4 or 5 with wind speeds above 56 meters per second has risen from 20% in the 1970s to 35% in the 1990s. Precipitation hitting the US from hurricanes has increased by 7% over the twentieth century. The extent to which this is due to global Climate change as opposed to the Atlantic Multidecadal Oscillation is unclear. Some studies have found that the increase in sea surface temperature may be offset by an increase in wind shear, leading to little or no change in hurricane activity. Hoyos et al. (2006) have linked the increasing trend in number of category 4 and 5 hurricanes for the period 19702004 directly to the trend in sea surface temperatures. Increases in catastrophes resulting from extreme weather are mainly caused by increasing population densities, and anticipated future increases are similarly dominated by societal change rather than climate change. The World Meteorological Organization explains that though there is evidence both for and against the existence of a detectable anthropogenic signal in the tropical cyclone climate record to date, no firm conclusion can be made on this point. They also clarified that no individual tropical cyclone can be directly attributed to climate change.Thomas Knutson and Robert E. Tuleya of NOAA stated in 2004 that climate change induced by greenhouse gas may lead to increasing occurrence of highly destructive category-5 storms. In 2008, Knutson et al. found that Atlantic hurricane and tropical storm frequencies could reduce under future greenhouse-gas-induced climate change. Vecchi and Soden find that wind shear, the increase of which acts to inhibit tropical cyclones, also changes in model-projections of global climate change. There are projected increases of wind shear in the tropical Atlantic and East Pacific associated with the deceleration of the Walker circulation, as well as decreases of wind shear in the western and central Pacific. The study does not make claims about the net effect on Atlantic and East Pacific hurricanes of the climate change and moistening atmospheres, and the model-projected increases in Atlantic wind shear. A substantially higher risk of extreme weather does not necessarily mean a noticeably greater risk of slightly-above-average weather. However, the evidence is clear that severe weather and moderate rainfall are also increasing. Increases in temperature are expected to produce more intense convection over land and a higher frequency of the most severe storms. IS UVW =XYZ ? IF SO NAME THE POSULATE THAT APPLIES help meeeeeeeeeeeeeee pleaseee s = 70 + 14t+ 0.08 where s is in meters and t is in seconds. Find the acceleration of the particle when t = 2. m/sec how to shape the front's armhole for a knitted vest so that the fabric does not bunch up at the armhole