in the photosynthesis the energy starts as ___ energy and ends up as___energy

light heat
chemical: chemical
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The number of moles of the gas by the ideal gas law is 0.18 moles.

The behavior of an ideal gas, a hypothetical gas made up of randomly moving particles with little volume and no intermolecular interactions, is described by the ideal gas law.

Although intermolecular interactions and non-zero particle volume prevent gases from always behaving in an ideal manner, the ideal gas law is nevertheless a good approximation for many gases under some circumstances.

We know that;

PV = nRT

We have ;

P = 1.2 atm

V = 3.4 L

T = 10 + 273 = 283 K

n = ?

n = PV/RT

n = 1.2 * 3.4/0.082 * 283

n =4.08 /23.2

n = 0.18 moles

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Answer:

Number of moles=Given mass/Molar mass =567/123.55=4.55

Explanation:

Given mass in grams= 567g

Formula mass/Molar mass of CuCO3= 123.55g/mol

The equilibrium constant for the system at this temperature is\(1.17 × 10^-31 mol^2/L^2\).

For the chemical equation:

N2(g) + O2(g) ⇌ 2NO(g)

The equilibrium mixture at a temperature of 1500 K is determined to contain 6.4 × 10^-3 mol/L of N2,\(1.7 × 10^-3\)mol/L of O2 and 1.1 × 10^-5 mol/L of NO.  First, we need to calculate the concentration of N2 and O2 required to produce

1.1 × 10^-5 mol/L of NO:

2NO(g) = N2(g) + O2(g)

Given that there are 1.1 × 10^-5 mol/L of NO, the number of moles of N2 and O2 are equal since the stoichiometric ratio is 1:1. Therefore:

\(1.1 × 10^-5 mol/L\) = [N2][O2]Kc = \(([NO]^2)/([N2][O2])Kc\)= \((1.1 × 10^-5 mol/L)^2/(6.4 × 10^-3 mol/L)(1.7 × 10^-3 mol/L)Kc\) =

1.17 × 10^-31 mol^2/L^2.

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At pOH value  of 6.0 the pH value of the following solution is 8.0 and the concentration of [\(H^{+}\) ] ion is \(10^{-8}\)

In this question we will apply the formula

      pH +pOH = 14 . . . . . . . . . . . . .(1)

where pH = concentration of [\(H^{+}\) ] ion

pOH = concentration of [\(OH^{-}\) ] ion

As per the question

pOH =6.0

Putting the value of pOH in equation (1) we get the value of pH

              pH + 6.0 =14

             pH = 14 -6.0

             pH  = 8.0

 The value of pH if the pOH value is 6.0 is 8.0

To find the concentration of \(H^{+}\) ion we will use the following formula

This is calculated by the formula

                                 [\(H^{+}\)} = \(10^{-pH}\)

where we will write the values of pH

Hence the concentration of [\(H^{+}\)} ion is \(10^{-8}\)

Therefore at  pOH of 6.0 the pH value of the following solution is 8.0 and the concentration of [\(H^{+}\) ] ion is \(10^{-8}\)

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The complete question is -

What is the pH value and concentration of [\(H^{+}\) ] ion of the following if the pOH value of the solution is 6.0 ?

Answer:

A. Water

Explanation:

Virtually every known substance can be referred to as MATTER, as long as it has weight and occupies space. Matter can exists in three different forms namely: solid, liquid and gaseous states.

However, each state of matter has its own unique property that characterizes it. WATER is the only matter that can exists in the three different states as follows:

- LIQUID - WATER

- SOLID - ICE

- GASEOUS - STEAM OR VAPOUR.

Answer:

\(55.2gH_2O\)

Explanation:

Hello!

In this case, since the reaction between hydrogen and oxygen to produce water is:

\(2H_2+O_2\rightarrow 2H_2O\)

When equal masses of each reactant go in contact to carry out the reaction, we can identify the maximum mass of yielded water as the fewest mass yielded by each reactant, just as shown below:

\(m_{water}^{by\ H_2}=49.0gH_2*\frac{1molH_2}{2.02gH_2}*\frac{2molH_2O}{2molH_2}*\frac{18.02gH_2O}{1molH_2O} =170gH_2O\\\\m_{water}^{by\ O_2}=49.0gO_2*\frac{1molO_2}{32.0gO_2}*\frac{2molH_2O}{1molO_2}*\frac{18.02gH_2O}{1molH_2O} =55.2gH_2O\)

Thus, since hydrogen yields more water than real, we limit the maximum mass of water to those 55.2 g yielded by oxygen as hydrogen would be in excess.

Best regards!

The mass percent of oxygen in Nickel(\(III\))sulfate is \(23.68\) percent.

At first, we look up the atomic masses for the element from the periodic table.

The atomic masses are found to be:

Next, we determine how many grams of each element are present in one mole of \(Ni_{2}(SO_{4})_{3}\)

The mass of one mole  \(Ni_{2}(SO_{4})_{3}\) is:

\(117.4g+96g+192g=405.4g\)

So, The mass percent of oxygen \(=(96g/405.4)*100=0.2368*100%\\\)

                                                    \(=23.68 %\) percent.

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Taking into account the definition of pH and pOH, [H₃O⁺] will be 1×10⁻³ M.

pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.

The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or H₃O⁺:

pH= - log [H⁺]= - log [H₃O⁺]

Similarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

The following relationship can be established between pH and pOH:

pOH + pH= 14

In this case, you know that [OH⁻]= 1×10⁻¹¹ M.

Replacing in the definition of pOH, it is calculated as:

pOH= - log (1×10⁻¹¹ M)

Solving;

pOH= 11

Replacing in the relationship established between pH and pOH, the pH can be calculated as:

pH + 11= 14

Solving:

pH= 14 - 11

pOH= 3

Replacing in the definition of pH the concentration of H₃O⁺ ions is obtained:

- log [H₃O⁺]= 3

Solving:

[H₃O⁺]= 10⁻³

[H₃O⁺]= 1×10⁻³ M

In summary, [H₃O⁺] will be 1×10⁻³ M.

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Answer:

Wind

Explanation:

It's impossible for them to travel in a wave.

Answer:

D

Explanation:

When the pressure and temperature are raised high enough a substance is said to be a supercritical fluid,

Supercritical fluids exist in a state where a distinct gas and liquid phase are not present

Answer:

D0wnload Phot0Math......................

Explanation:

Answer:

2.954grams of pottasium for that week

Explanation:

According to this question, a medium-sized that weighs 118grams contains 422 milligrams (mg) of potassium nutrient.

If someone eats a medium-sized banana each day for a week, this means that the person has consumed 422mg of pottasium that day.

Since there are 7days in a week, the person will consume 422 × 7 = 2954 mg of pottasium that week.

The question asks for the total pottasium intake in grams for that week, hence, we need to convert 2954 milligrams to grams.

1000mg = 1 g

Hence, 2954mg will be 2954/1000

= 2.954grams

Therefore, 2.954grams of pottasium are ingested by that person that week.

The volume of the solution is 24.8 milliliters (mL).

To solve this problem, we can use the formula:

Molarity (M) = moles of solute / liters of solution

We are given the mass of CuNO3 and the molarity of the solution, so we can first calculate the number of moles of CuNO3:

moles of CuNO3 = mass / molar mass

molar mass of CuNO3 = 63.55 + 14.01 + 3(16.00) = 187.56 g/mol (using atomic weights from the periodic table)

moles of CuNO3 = 3.90 g / 187.56 g/mol = 0.0208 mol

Next, we can rearrange the formula for molarity to solve for the volume of the solution:

liters of solution = moles of solute / Molarity

liters of solution = 0.0208 mol / 0.840 M = 0.0248 L

Finally, we can convert liters to milliliters:

volume of solution = 0.0248 L x 1000 mL/L = 24.8 mL

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The reaction is endothermic since the energy level of the products have are higher than that of the reactants.

The activation energy (AE) is the energy difference between the reactants and the transition state.

The change in energy E and the energy difference between the reactants and the products

The data given is as follows:

Reactants: 0 kJ/mol

AE forward 125 kJ/mol

AE reverse: 86 kJ/mol

Products: 39 kJ/mol

The values of ΔE forward and ΔE reverse are as follows:

ΔE forward = (39 - 0) kJ/mol

ΔE forward = +39 kJ/mol

ΔE reverse = (0 - 39) kJ/mol

ΔE reverse =  -39 kJ/mol

3. Given that Ea = 154 kJ/mol and ΔE = 136 kJ/mol

AE reverse = ΔE - AE forward

E = 136 kJ/mol - 154 kJ/mol

E = -18 kJ/mol

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The equilibrium constant (Kc) for the given reaction is approximately 16.448. The value of Kc indicates the relative concentrations of reactants and products at equilibrium. In this case, a Kc greater than 1 suggests that the products (H2 and P4) are favored at equilibrium, indicating that the forward reaction is more favorable.

To determine the equilibrium constant (Kc) for the given reaction:

4PH3(g) ↔ 6H2(g) + P4(g)

We can write the equilibrium constant expression based on the stoichiometric coefficients:

Kc = ([H2]^6 * [P4]) / ([PH3]^4)

Substituting the given equilibrium concentrations:

[PH3] = 0.250 M

[H2] = 0.580 M

[P4] = 0.750 M

We can plug in these values into the equilibrium constant expression:

Kc = ([0.580]^6 * [0.750]) / ([0.250]^4)

Kc = (0.0860128 * 0.750) / (0.00390625)

Kc = 16.448

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Answer:

89.0493

Explanation:

Add the numbers(line up the decimals)

4.337 + 84.7123

Than you should get

89.0493

Answer:

5. 56.5217

Explanation:

Calculate percent yield by (actual yield / theoretical yield) times 100

(13/23) x 100 = 56.52173913

A methane molecule (CH4) is considered symmetrical because it possesses a symmetric structure and exhibits symmetry operations.

Symmetry refers to a balanced arrangement of elements that can be divided into equal parts by a plane, axis, or center. In the case of methane, it exhibits several symmetrical characteristics.

Firstly, methane has a tetrahedral molecular geometry, with the carbon atom at the center and four hydrogen atoms positioned around it. This geometry ensures that the molecule is symmetrical in terms of its spatial arrangement.

Each hydrogen atom is located at one of the vertices of the tetrahedron, forming equal angles and distances with respect to the central carbon atom. This symmetry is maintained regardless of the orientation of the molecule.

Additionally, methane possesses rotational symmetry. It can be rotated around any of the carbon-hydrogen bonds, and the molecule will retain its overall appearance.

The symmetry of methane arises from its molecular structure and the equal distribution of electron density around the central carbon atom. The four hydrogen atoms are bonded to the carbon through sigma bonds, which have a cylindrical symmetry. This balanced arrangement of the atoms contributes to the overall symmetry of the molecule.

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Answer:

D) Fe³⁺, O²⁻; Fe₂O₃

Explanation:

Option D shows correctly an ion pair and the correct formula for the ionic compound the two ions form.

Ion pairs of iron and oxygen react to form iron (III) oxide. The iron (III) oxide is one of the oxides of iron. The compound is usually attacked by acids and it is often called rust. It is used in the feedstock of the steel and iron industries. This means that the compound is used in the production of iron, steel, and many alloys.

Below are some equations:

4 Fe + 3 O₂→ 2 Fe₂O₃

Fe⁰ + 3O₂⁰ →  Fe³⁺O₃²⁻

The energy of a photon is hv. Where h is plank's constant and v be the frequency. The frequency of a photon with an energy of 3.75 × 10⁻²¹ J is 5.66 × 10¹² Hz.

Frequency of a wave is the number of wave cycles per unit time. It is the inverse of the time period. Thus, has a unit of s⁻¹ which is equivalent to Hz.

Frequency of a wave is directly proportional to the energy.

The energy of a photon = hv

h is the planck constant = 6.62 × 10⁻34 J.s

Given the energy of a photon = 3.75 × 10⁻²¹ J

Thus, frequency = energy/planck's constant

= 3.75 × 10⁻²¹ J/ 6.62 × 10⁻34 J.s

= 5.66 × 10¹² Hz.

Therefore, the frequency of the photon is 5.66 × 10¹² Hz.

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Answer:

Citric Acid is a weak acid with a chemical formula C6H8O7.

...

Properties of Citric Acid – C6H8O7.

C6H8O7 Citric Acid

Molecular Weight/ Molar Mass 192.124 g/mol

Density 1.66 g/cm³

Boiling Point 310 °C

Melting Point 153 °C

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Answer:

Al + S -> Al2S3

Al and S are the reactants, Al2S3 is the product

Explanation:

It's important to note that equilibrium is a dynamic state, meaning that while the conditions mentioned above are true, there may still be continuous microscopic fluctuations or changes within the system, but the macroscopic properties remain constant.

What is Equilibrium?

Equilibrium refers to a state of balance or stability in a system where there is no net change or overall tendency for change to occur. In various scientific disciplines, including physics, chemistry, and biology, equilibrium is a fundamental concept that describes the balance between opposing forces or processes.

Balance of forces: The net force acting on the system is zero. This means that the forces acting in opposite directions are balanced, and there is no overall acceleration of the system.

Balance of torques: The net torque (or moment) acting on the system is zero. This means that the torques acting in opposite directions are balanced, and there is no rotational acceleration of the system.

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The enthalpy change of the reaction C(diamond) → C(graphite) is -2.9 kJ.

The given information is ΔHrxn for the reaction C(diamond) → C(graphite) can be calculated with the given equations:Equations:  C(diamond) + O2(g) → CO2(g) ΔH = −395.4 kJ  2 CO2(g) → 2 CO(g) + O2(g) ΔH = 566.0 kJ  C(graphite) + O2(g) → CO2(g) ΔH = −393.5 kJ  2 CO(g) → C(graphite) + CO2(g) ΔH = −172.5 kJThe required reaction can be obtained by adding the equations (1) and (4), as follows:C(diamond) + O2(g) + 2CO(g) → C(graphite) + 3CO2(g)Addition of the two equations (1) and (4) results in a reaction whose products are C(graphite) and CO2.

To get the final equation that involves only the required reactants and products, the equation (2) should be added, which consumes CO2 and produces O2, as shown below:C(diamond) + O2(g) → CO2(g)  ΔH = −395.4 kJ [eq. (1)]  2 CO(g) → C(graphite) + CO2(g)  ΔH = −172.5 kJ [eq. (4)]  2 CO2(g) → 2 CO(g) + O2(g)  ΔH = 566.0 kJ [eq. (2)]  C(diamond) + O2(g) + 2CO(g) → C(graphite) + 3CO2(g)  ΔHrxn=ΣΔHf(products)−ΣΔHf(reactants)  ΔHrxn=[(3 mol CO2)(-393.5 kJ/mol) + (1 mol C(graphite))(0 kJ/mol)] − [(1 mol C(diamond))(0 kJ/mol) + (1 mol O2)(0 kJ/mol) + (2 mol CO(g))(−172.5 kJ/mol)] − [(2 mol CO2)(566.0 kJ/mol)]  ΔHrxn=−2.9 kJ.

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Answer:

I don’t have any specific examples of wet labs that study the effects of human activity on wetlands. However, some common human activities that can affect wetlands include the construction of buildings and roads, agricultural land use, and overfishing. Wet labs can be used to study the impact of these activities on the physical, chemical, and biological processes in wetland ecosystems.