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Answer:

it is false john deere invented the self-scouring steel plow

Explanation:

Using the modulus of elasticity, the approximate elongation of the steel alloy specimen when a load of 61,141 N is applied is approximately 0.51788 mm.

To determine the approximate elongation of the steel alloy specimen, we need to know the modulus of elasticity (E) for the material.

Assuming the steel alloy follows Hooke's law and has a constant modulus of elasticity throughout the given load range, we can use the equation:

ε = σ / E

where:

ε = Strain (elongation as a fraction of the original length)

σ = Stress (force applied per unit area)

E = Modulus of elasticity

Given:

Diameter of the specimen = 8.3 mm

Radius (r) of the specimen = 8.3 mm / 2 = 4.15 mm = 0.00415 m

Length of the specimen = 91 mm = 0.091 m

Load applied (P) = 61,141 N

We need the modulus of elasticity (E) for the specific steel alloy. The modulus of elasticity varies for different steel alloys and can typically range from 190 to 210 GPa (Gigapascals).

Let's assume a modulus of elasticity of E = 200 GPa = 200 × 10⁹ Pa.

To calculate the stress (σ), we need the cross-sectional area (A) of the specimen:

A = π * r²

A = π * (0.00415 m)²

A ≈ 5.3809 × 10⁻⁵ m²

Now we can calculate the stress (σ):

σ = P / A

σ = 61,141 N / 5.3809 × 10⁻⁵ m²

σ ≈ 1.136 × 10⁹ Pa

Now we can calculate the strain (ε):

ε = σ / E

ε ≈ (1.136 × 10⁹ Pa) / (200 × 10⁹ Pa)

ε ≈ 0.00568

Finally, we can determine the approximate elongation:

Elongation = ε * L

Elongation ≈ 0.00568 * 0.091 m

Elongation ≈ 0.00051788 m ≈ 0.51788 mm

Therefore, the approximate elongation of the steel alloy specimen when a load of 61,141 N is applied is approximately 0.51788 mm.

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Answer:

24 i believe

Explanation:

This question is incomplete, the complete question is;

For a steel alloy it has been determined that a carburizing heat treatment of 11.3 h duration at Temperature T1 will raise the carbon concentration to 0.44 wt% at a point 1.8 mm from the surface. A separate experiment is performed at T2 that doubles the diffusion coefficient for carbon in steel.

Estimate the time necessary to achieve the same concentration at a 4.9 mm position for an identical steel and at the same carburizing temperature T2.

Answer:

the required time to achieve the same concentration at a 4.9 is 83.733 hrs

Explanation:

Given the data in the question;

treatment time t₁ = 11.3 hours

Carbon concentration = 0.444 wt%

thickness at surface x₁ = 1.8 mm = 0.0018 m

thickness at identical steel x₂ = 4.9 mm = 0.0049 m

Now, Using Fick's second law inform of diffusion

\(x^2\) / Dt = constant

where D is constant

then

\(x^2\) / t = constant

\(x^2_1\) / t₁ = \(x^2_2\) / t₂

\(x^2_1\) t₂ = t₁\(x^2_2\)

t₂ = t₁\(x^2_2\) / \(x^2_1\)

t₂ = (\(x^2_2\) / \(x^2_1\))t₁

t₂ = \((\) \(x_2\) / \(x_1\) \()^2\) × t₁

so we substitute

t₂ = \((\) 0.0049  / 0.0018  \()^2\) × 11.3 hrs

t₂ = 7.41 × 11.3 hrs

t₂ = 83.733 hrs

Therefore, the required time to achieve the same concentration at a 4.9 is 83.733 hrs

Answer:

SECTION LEARNING OBJECTIVES

By the end of this section, you will be able to do the following:

Distinguish between static friction and kinetic friction

Solve problems involving inclined planes

Section Key Terms

kinetic friction static friction

Static Friction and Kinetic Friction

Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.

There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.

Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.

Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.

The correct statements are 2, 3 and 5. Elastic deformation is a temporary deformation of a material. When a force is applied to a material, it will deform, and the amount of deformation will be proportional to the force applied.

Elastic deformation refers to the reversible deformation of a material when a force is applied and it is released. When the load is removed, the material will return to its original shape. Elastic deformation is characterized by its capability to withstand stress without causing any permanent change in the shape of the material or its molecular structure. The following are the correct statements regarding elastic deformation: Stress and strain are proportional; hence, when stress is applied, the deformation or strain is proportional to the stress. Isostatic uplift following deglaciation represents elastic deformation. This statement is correct. Fold structures are the result of elastic deformation. This statement is correct.

Therefore, If the force is removed, the material will return to its original state. The explanation for elastic deformation is that the stress and strain are proportional, and the deformation will not cause any permanent change in the shape or molecular structure of the material.

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The corresponding minimum and maximum velocities that the rocket experiences are 23.195m/s and 37.249m/s.

The minimum value will be:

V(t) = 3t³ + (-24)t² + 54t

V(3.721) = 3(3.721)³ - 24(3.721)² + 54(3.721)

= 23.195m/s.

The maximum value will be:

V(.1613) = 3(1.613)³ - 24(1.613)² + 54(1.613)

= 37.249m/s

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Explanation:

the resultant force =

\( \sqrt{} {x}^{2} + {y}^{2} \)

A resultant force is the single force and corresponding torque that are produced when adding vectors to a system of forces and torques acting on a rigid body.

R = A + B. Instance 2 To create the resulting vector, two vectors facing the opposite direction are subtracted from one another. Here, the vector B is pointing in the opposite direction of the vector A, and the resulting vector is called R.

A force system is a group of forces that interact at specific locations (may also include couples). Therefore, the collection of forces shown on any free body diagram is a force system. A group of forces is simply referred to as a force system.

Therefore, When an item is under the influence of two or more forces, the combined force can be calculated by adding up the separate forces.

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Answer:

When possible, use public transportation, walk, or ride a bike

Explanation:

Answer:

water; water; Oxygen enters the waterways and causes an imbalance of plant life to animal life.

Explanation:

Your Answer would be A I believe.

Answer: It is very important that the orifices and passages be kept clean and free of burrs to permit free gas flow and to form a well-shaped flame.

Explanation:

The law that requires federal agencies to develop security policies for computer systems that process confidential information is the Federal Information Security Modernization Act (FISMA).

FISMA is a United States federal law passed in 2002 as a portion of the E-Government Act of 2002, which mandates federal agencies to maintain information security programs that include annual reviews of information security practices and procedures, training of personnel, and the creation and maintenance of a risk management framework.

In addition, the law mandates the development of annual reports on the state of computer systems security for each agency. Furthermore, it required the Director of the Office of Management and Budget (OMB) to provide guidance to ensure consistent and effective information security protections across the federal government.

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The given code is an implementation of a Python function that converts a height given in feet and inches to meters. The function takes two parameters, `feet` and `inches`.

The first step in the function is to convert the height into inches, which is done by multiplying the number of feet by 12 and then adding the number of inches. This is assigned to the variable `height_inches`.

Next, the height in inches is converted to meters by multiplying with the conversion factor 0.0254. The result is stored in the variable `height_meters`.

Finally, the function returns the height in meters using the `return` statement.

To test the function, it is called three times with different sets of feet and inches using the `print` statement. The output shows the corresponding height in meters for each set of feet and inches provided.

It is worth noting that the function assumes that the input values are valid and do not contain any errors.

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Technicians A and B have correctly identified the benefits of a Continuously Variable Transmission (CVT) over an automatic transmission.

By allowing engines to operate at their most efficient RPM range, a CVT can help improve fuel economy whilst avoiding gear shifting issues or delays that traditional automatic transmissions may face, as mentioned by Technician B which can also provide riders with heightened comfort throughout the journey.

Consequently, both technicians are correct in recognizing various advantages linked with this type of transmission system.

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Answer:

False

I hope this helps...

Please mark me Brainliest.

Have a nice day! <3

Answer:

False

Explanation:

There are many benefits in creating organizers to help find your tools. The most helpful part of doing this is finding your tools quickly which makes the project you're working on go faster and more enjoyably.

Answer:

mechanical engineer is the best answer

Answer:

What’s the most important reason we should need a mask?

we were because it protects us from germs and viruses.

Is the ban on removal of the mask requirement being implemented too fast in an area without general consensus (moral, political, cultural, technological)?

Face coverings limit the volume and travel distance of expiratory droplets dispersed when talking, breathing, and coughing.

The solution of given relations are σ = 1.897 ksi (using the kilo- prefix), σ = 0.397 ksi (using the kilo- prefix).

To solve the given relations and apply the rules for rounding and prefix selection, we'll follow the steps for each relation:

(a)

Given:

σ = M/Z

σ = 1770 lbf⋅in / 0.934 in^3

M = 1770 lbf⋅in

Z = 0.934 in^3

To round the result to three digits and choose prefixes, we'll divide the values by appropriate factors until we have no more than four digits to the left of the decimal point:

σ = (1770 / 0.934) lbf⋅in / \(in^3\)

σ = 1896.99 \(lbf/in^2\)

σ = 1.897 ksi (using the kilo- prefix)

(b)

Given:

σ = F/A

σ = 9440 lbf / 23.8 \(in^2\)

F = 9440 lbf

A = 23.8 \(in^2\)

σ = (9440 / 23.8) lbf / \(in^2\)

σ = 396.64 lbf/\(in^2\)

σ = 0.397 ksi (using the kilo- prefix)

(c)

Given:

σ = F *l^3 / 3EI

σ = (270 lbf) * (31.5 in)^3 / (3 * 30 Mpsi * 0.154 in^4)

F = 270 lbf

l = 31.5 in

E = 30 Mpsi

I = 0.154 in^4

σ = (270 * \(31.5^3\)) / (3 * 30 * 0.154) psi

σ = 34682.86 psi

σ = 34.7 ksi (using the kilo- prefix)

(d)

Given:

θ = T*l / GJ

θ = (9740 lbf⋅in) * (9.85 in) / (11.3 Mpsi * 1.00 in)

T = 9740 lbf⋅in

l = 9.85 in

G = 11.3 Mpsi

J = 1.00 in

θ = (9740 * 9.85) / (11.3 * 1.00) rad

θ = 8507.82 rad

θ = 8508 rad (rounding to three digits)

Thus, (a) σ = 1.897 ksi, (b) σ = 0.397 ksi, (c) σ = 34.7 ksi, (d) θ = 8508 rad.

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The should be no concerns about the space immediately below the tanks because there will be no damage to anything if any peril causes the tank to falls.

Potential hazards refers to the active source for potential damage on a building, structure etc

It is important we know that the storage tanks are placed on a platform next to the building at the second-floor level but nothing beneath the tanks stands.

Hence, there should be no concerns about the space immediately below the tanks because there will be no damage to anything if any peril causes the tank to falls.

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According to Tech A, many wheels have a tapered hole that centers the wheel on the wheel flange and matches the lug nut's tapered end. Tech A has it right.

The brake line needs to be replaced if it is leaking. A closed hydraulic system is the only one that works well. Fluid or air leaks from the system can limit its capabilities, resulting in soft brakes or none at all.

Like removing a bolt from a nut, removing a brake line is simple. However, just because it's easy doesn't mean it's easy. Road debris and corrosion caused by salt, water, and galvanic reactions can harm brake fittings. Although anodized to prevent rust and corrosion, the majority of fittings are steel and can and do corrode.

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Answer:

A) F = 0.011 N

B) ΔP = 5.6 N/m²

Explanation:

We are given;

surface tension coefficient; S = 0.07 N/m

Radius; r = 2.5 mm = 0.025 m

A) Formula to find the surface tension force(F) is given by;

F = SL

Where L is effective length = 2πr

F = 0.07 × 2π × 0.025

F = 0.011 N

B) Formula for difference in pressure droplet is;

ΔP = 2S/r

Thus;

ΔP = (2 × 0.07)/0.025

ΔP = 5.6 N/m²

Answer:

The state you live in

Computer professionals need to have a moral code specific to their profession as technology has created a different set of moral values.

This is because more than 100 years of technology and innovation have created an entirely new set of ethical concerns for computer professionals. The reason why computer professionals require a moral code is that their work often entails access to sensitive information and computing systems that, if exploited, could result in significant harm to individuals and organizations.

Technology has created a different set of moral values because it has brought about new ethical challenges that were previously unheard of. For example, online privacy, cyberbullying, identity theft, and hacking are all ethical issues that have arisen due to technology advancements.

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The family should accept a minimum of Kshs.42,250,000.00 to avoid incurring a loss.

To obtain the total cost, the expenses for the land, trees and upkeep are summed up and subsequently reduced by 6. 5% using a discount rate.

Hence, it can be seen that a forced acquisition appraisal primarily focuses on three key factors: the land's market value, the expenses involved in replacing the property, and the potential harm caused to the owner's belongings.

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Given that,

Mass of the object 1, m = 107.01 grams

To find,

Force on the object.

Solution,

The force acting on the object is gravitational force. The force is given by the formula as follow :

F = mg

g is acceleration due to gravity

F = 0.10701 kg × 9.8 m/s²

F = 1.048 N

So, the force acting on object 1 is 1.048 N.

The following parts describe the idea about sine functions is derived:

Part A: The maximum amplitude of the voltage is 30 V.
Part B: The frequency in hertz is given by f = ω/2π, where ω is the angular frequency. From the given expression, we see that ω = 400π rad/s. Therefore, f = (400π)/(2π) = 200 Hz.
Part C: The frequency in radians per second is simply ω = 400π rad/s.
Part D: The phase angle in radians is 60π/180 = π/3 radians.
Part E: The phase angle in degrees is 60 degrees.
Part F: The period is given by T = 1/f, where f is the frequency in hertz. From part B, we know that f = 200 Hz. Therefore, T = 1/200 = 0.005 seconds.

Thus, overall, the answers are:
Part A: 30 V

Part B: 200 Hz

Part C: 400π rad/s

Part D: π/3 radians

Part E: 60 degrees

Part F: 0.005 seconds

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The probability that one telephone call passes through the switchboard in three minutes is 1.49%.

Using the Poisson probability formula, we can calculate the probability of exactly one call passing through the switchboard in 3 minutes as follows:

P(X = 1) = (e^(-6) * 6^1) / 1!

Where

6 = 2 per minute * 3 minute

X is the number of calls passing through the switchboard in 3 minutes.

So, we have

P(X = 1) = (e^(-6) * 6^1) / 1!

= (0.00248 * 6) / 1

= 0.0149

Therefore, the probability that one telephone call passes through is approximately 0.0149, or about 1.49%.

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