By what percentage does the drag force on a car increase as it goes from 61 km/h to 113 km/h?

Answers

Answer 1

Given,

The initial speed of the car, u=61 km/h

The final speed of the car, v=113 km/h

The drag force on an object is given by,

\(F=\frac{1}{2}\rho v^2C_DA\)

Where:

• ρ is the density of the air.

,

• v is the speed of the object.

,

• C_D is the drag coefficient.

,

• A is the area of cross-section of the object.

In the given problem, only the speed of the car changes. And density of the air, drag coefficient, and area of the cross section remains the same.

Thus, the initial drag force on the car is

\(F_i=\frac{1}{2}\rho u^2C_DA\)

The final drag force is given by,

\(F_f=\frac{1}{2}\rho v^2C_DA\)

The percentage increase in the drag force is given by,

\(P=\frac{F_f-F_i}{F_i}_{}\times100\)

On substituting,

\(\begin{gathered} P=\frac{\frac{1}{2}\rho v^2C_DA-\frac{1}{2}\rho u^2C_DA}{\frac{1}{2}\rho u^2C_DA}\times100 \\ =\frac{\frac{1}{2}\rho C_DA(v^2-u^2)}{\frac{1}{2}\rho u^2C_DA}\times100 \\ =\frac{v^2-u^2}{u^2}\times100 \end{gathered}\)

On substituting the values of v and u,

\(\begin{gathered} P=\frac{113^2-61^2}{61^2}\times100 \\ =243\% \end{gathered}\)

Thus, the percentage increase in the drag force is 243%


Related Questions

4x The law of conservation of matter states that during a chemical reaction, the amount of matter
A
B
C
D
decreases.
stays the same.
disappears.
increases.o

Answers

The law of conservation of matter stated that during a chemical reaction, the amount of matter stays the same. Thus, option B is correct.

Matter can be changed into other forms either by physical or chemical changes. But through any of these changes matter remains constant. The amount of matter present before the chemical reaction will remain the same after the chemical reaction. Thus, the matter can neither be created nor destroyed.

The law of conservation of matter is defined as the law of conservation of mass. Hence, in a system, the mass or matter remains conserved, before and after the chemical reaction and it was given by Antonie Lavoisier.

The law of conservation of matter states that during a chemical reaction, the amount of matter remains the same. Thus, the ideal solution is option B.

To learn more about the Law of conservation of matter:

https://brainly.com/question/12733091

#SPJ1


Man-made climate change is an example
of...

Answers

Humans are increasingly influencing the climate and the earth's temperature by burning fossil fuels, cutting down forests and farming livestock. This adds enormous amounts of greenhouse gases to those naturally occurring in the atmosphere, increasing the greenhouse effect and global warming.

I got this from a book please do not copy it will be plagiarism. If helped mark me the brainiest!!!

Two particles of a gas collide. Why is this considered an elastic collision? (1 point)
O They bounce off each other, conserving momentum only.
O They stick together, conserving momentum.
O They bounce off each other, conserving energy only.
O They bounce off each other, conserving energy and momentum.

Answers

They bounce off each other, conserving energy and momentum.

This is considered an elastic collision because they bounce off each other, conserving energy only.

Gas is the state of matter that is made up of particles which freely move about its container and they bounce off each other.

As the particles move over each other they collide without exerting any force in each other. This is known as elastic collision.

Kinetic energy is conserved in elastic collisions which occurs between gas molecules.

While in inelastic collision, momentum is conserved and kinetic energy is not.

Because the gas particles do not stick together as they collide, no force is exerted and kinetic energy is therefore conserved.

Learn more here:

https://brainly.com/question/24478517

An orbit is equivalent to being in permanent free fall around a mass center (planet, star etc.).
O True
O False

Answers

Answer:

false

Explanation: because an orbit is not equal to being in a permanent free fall because if it is not equal the orbit is not correct

Which of the following is the only group in mission control that gets to communicate with the astronauts in space?


Flight Director


CAPCOM


Senior Flight Controller


Lead Ground Astronaut

Answers

Capsule communicator or Capcom  is the only group in mission control that gets to communicate with the astronauts in space. Hence, option (B) is correct.

What is capsule communicator or Capcom?

The capsule communicator, or Capcom, was the only voice that spoke to the astronauts during their trip to avoid any mistake. To ensure that the men in the capsule always had a familiar individual who understood their situation and could provide the information they required, Capcom was always manned by astronauts.

Both the technical control team on the ground and the astronauts in space are represented by Capcom.

Learn more about Capcom here:

https://brainly.com/question/27805681

#SPJ1

Stationary waves are
A) transverse waves
B) longitudinal waves
C) mechanical waves

Answers

Answer:

stationary waves are transverse waves

3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?​

Answers

The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

Know more about   kinetic energy  here:

https://brainly.com/question/8101588

#SPJ8

Which digits in a measurement are always significant? Check all that apply.
zeros to the left of the decimal point
zeros between nonzero numbers
zeros to the right of the decimal point
nonzero numbers
zeros to the right of both the decimal point and a nonzero number
O zeros to the left of both the decimal point and a nonzero number

Answers

Answer:

zeros between nonzero numbers

nonzero numbers

zeros to the right of both the decimal point and a nonzero number

Explanation: edge 2020

A car has 10,800 kg m/s of momentum as it collides with a trash dumpster AT REST.
How much TOTAL MOMENTUM will the car and dumpster have after collision?

Answers

Answer:

10800 kg m/s

Explanation:

Since the dumpster was initially at rest, its momentum before collision equal to zero. So that the total momentum of the car and dumpster before collision is 10800 kg m/s.

The principle of conservation of linear momentum states that: in a system of colliding bodies, total momentum is conserved. Therefore, the total momentum of the car and dumpster after collision is 10800 kg m/s.

Mary throws a baseball straight upward. We can ignore air resistance.

Answers

Answer:

Acceleration Remains Constant and Velocity decreases.

Explanation:

a space traveller whose mass is 115kg leaves earth. what are his weight and mass;
a) On earth
b) Interplanetary space where there are no nearby planetary objects?​

Answers

Answer:

On Earth: mass = 115 kg; weight = 1127 N

Interspace:  mass = 115 kg; weight = 0 N

Explanation:

On Earth, his mass is 115 kg, and his weight is 115 kg * 9.8 m/s^2 = 1127 N.

On interspace , his mass is still 115 kg,  and his weight is Zero Newtons = 0 N

(a) The mass of space traveler on Earth is 115 kg and its weight is 1127 N.

(b)  The mass of traveler at interplanetary space is 115 kg and its weight is 0 N.

Given data:

The mass of space traveler outside the Earth is, m = 115 kg.

(a)

Since, the mass of any object is always remains constant. In other words, there is no way to destroy mass and hence mass of traveler on Earth will be same as 115 kg.

While the weight will be,

W = mg

W = 115(9.8)

W = 1127 N

Thus, we can conclude that the mass of space traveler on Earth is 115 kg and its weight is 1127 N.

(b)

On interspace , his mass is still 115 kg,  and his weight is Zero Newtons. This is because the gravity at interplanetary space is zero.

That is,

W = mg

W = 115 (0)

W = 0 N

Thus, we can conclude that the mass of traveler at interplanetary space is 115 kg and its weight is 0 N.

Learn more about the gravity here:

https://brainly.com/question/12008506

A ball is attached to one end of a wire, the other end being fastened to the ceiling. The wire is held horizontal, and the ball is released from rest (see the drawing). It swings downward and strikes a block initially at rest on a horizontal frictionless surface. Air resistance is negligible, and the collision is elastic. The masses of the ball and block are, respectively, 1.70 kg and 2.50 kg, and the length of the wire is 1.21 m. Find the velocity (magnitude and direction) of the ball (a) just before the collision, and (b) just after the collision.

Answers

Just before the collision, the ball has a velocity of 9.3 m/s, downward. After the collision, the ball has a velocity of 6.2 m/s, upward.

To solve this problem, we can analyze the motion of the ball and block before and after the collision using the principles of conservation of energy and momentum. Since the collision is elastic, the total kinetic energy of the system is conserved. The ball has gravitational potential energy before the collision, which is converted to kinetic energy as it falls.

The block has no kinetic energy before the collision, but gains some after the collision due to the transfer of momentum from the ball. By equating the total kinetic energy before and after the collision and using the principle of conservation of momentum, we can solve for the velocities of the ball and block.

Learn more about  kinetic energy here:

https://brainly.com/question/8101588

#SPJ4

Directions: One of the biggest myths in weight management is that a short-term fad diet will help you lose weight and keep it off. Below is a list of current fad diets. Read the short description of each, and answer the questions based on your knowledge of healthy eating.

Directions: One of the biggest myths in weight management is that a short-term fad diet will help you
Directions: One of the biggest myths in weight management is that a short-term fad diet will help you
Directions: One of the biggest myths in weight management is that a short-term fad diet will help you
Directions: One of the biggest myths in weight management is that a short-term fad diet will help you

Answers

1. Completely cutting out food groups, such as grains, fruits, and vegetables, can have negative health implications as each food group provides essential nutrients.

2. Is this eating a sustainable one

This eating pattern of high meat and protein intake while restricting grains, fruits, and vegetables may not be sustainable over a lifetime, as it lacks balance and variety.

3. Three healthy foods that would be restricted in this diet are grains, fruits, and vegetables. These foods are important as they provide essential nutrients, antioxidants, and dietary fiber, supporting overall health, digestion, and reducing the risk of chronic diseases. Restricting these foods can lead to nutrient deficiencies and negatively impact well-being.

Read more on healthy foods here:https://brainly.com/question/30784972

#SPJ1

The centripetal acceleration of a point on a wheel is 72 m/s2. The wheel is spinning with a
tangential velocity of 4.3 m/s. What is the radius of the wheel?

Answers

The radius of the wheel with a tangential velocity of 4.3 m/s and centripetal acceleration of 72 m/s² is 0.25 meter.

What is centripetal acceleration ?

The acceleration of an object ,moving through a  circular path is called the centripetal acceleration. It is related to the velocity and radius of curvature of the circular path as follows:

a = v²/r.

The tangential velocity or angular velocity is the rotational analogue of the linear velocity.

given that, tangential velocity v = 4.3 m/s

centripetal acceleration a = 72  m/s²

Then, radius of the wheel is calculated as follows:

r = v²/a

r = (4.3 m/s × 4.3 m/s)72 m/s²

 = 0.25 meter.

Therefore, the radius of the rotating wheel is 0.25 meter.

Find more on centripetal acceleration:

https://brainly.com/question/29197591

#SPJ9

help!!!
middle school physics ​also please explain :)

help!!!middle school physics also please explain :)

Answers

Answer:

hope its helps

good luck

help!!!middle school physics also please explain :)

Answer:

0.1 cm/s

Explanation:

16 min 40 second = 1000 sec

1m = 100cm

100/1000 = 0.1   (speed = distance/time)

a ballon is filled with air. what forces are acting on the ballon and the air?

Answers

Answer: Three forces act significantly on a freely floating helium-

filled balloon: gravity, air resistance (or drag force), and a

buoyant force.

Explanation:

The air pressure on the bottom of the balloon is slightly higher than the air pressure on the top of the balloon (because of the altitude difference). This difference gives rise to the bouyant force. This force competes with gravity as the two main forces acting on the balloon. Every time your feet hit the ground when you are running, the ground hits your feet with an equal and opposite force. Newton’s third law explains how balloons and rocket engines work. When the neck of an inflated balloon is released, the stretched rubber material pushes against the air in the balloon. The air rushes out of the neck of the balloon.

a force is something that ___ an object to ____

Answers

Answer:

which can cause an object with mass to change its volocity

how far will a rolling wheel travel if it completed 32 revolutions with a radius of 0.8 meters?

Answers

Answer: The wheel will travel 102.72 meters if it completes 32 revolutions with a radius of 0.8 meters. ✅

Explanation:

A rolling wheel will travel a certain distance when it completes a certain number of revolutions. To calculate the distance, you need to know the number of revolutions and the radius of the wheel.

In this case, the wheel completed 32 revolutions and the radius is 0.8 meters. To calculate the distance, we will use the formula:

Distance = 2 * pi * radius * number of revolutions

So the distance this wheel will travel is:

Distance = 2 * 3.14 * 0.8 * 32

Distance = 102.72 meters

So the wheel will travel 102.72 meters if it completes 32 revolutions with a radius of 0.8 meters.

what is the average number of electrons per second that flow past a fixed reference cross section that is perpendicular to the direction of flow

Answers

The complete question is;

In electronic circuits it is not unusual to encounter currents in the microampere range. Assume a 35 μA current, due to the flow of electrons. What is the average number of electrons per second that flow past a fixed reference cross section that is perpendicular to the direction of flow?

Answer:

2.185 × 10^(14) electrons/seconds

Explanation:

We are given current as 35 μA = 35 × 10^(-6) Amperes

The value of the charge on one electron is; e = 1.602 × 10^(-19) coulombs

Now, from conversions;

One ampere = one coulomb/second =

Then, 35 × 10^(-6) Ampere's would give;

35 × 10^(-6) Coulombs/sec

Now,

1.602 × 10^(-19) coulombs = 1 electron

Thus;

35 × 10^(-6) Coulombs/sec gives;

(35 × 10^(-6))/(1.602 × 10^(-19)) = 2.185 × 10^(14) electrons /sec

The average number of electrons per second that flow past a fixed reference cross-section perpendicular to the direction of flow is 2.185 × 10⁻¹⁴ electrons /sec

The flow of charge:

The question is as given below:

In electronic circuits, it is not unusual to encounter currents in the microampere range. Assume a 35 μA current, due to the flow of electrons. What is the average number of electrons per second that flow past a fixed reference cross-section that is perpendicular to the direction of flow?

Given information:

Current I = 35 μA = 35 × 10⁻⁶ A

charge on electron e = 1.602 × 10⁻¹⁹C

We know that:

I = de/dt, rate of flow of charge.

1A = 1C/s

Thus,

35 × 10⁻⁶ A = 35 × 10⁻⁶ C/s

Now, one electron has a charge of  1.602 × 10⁻¹⁹C

So, the number of electrons for a current of 35 × 10⁻⁶ C/s will be:

n = (35 × 10⁻⁶ C/s) ÷ (1.602 × 10⁻¹⁹C)

n = 2.185 × 10⁻¹⁴ electrons /sec

Learn more about current and charge:

https://brainly.com/question/1345174?referrer=searchResults

In 7.5 s, 4200 waves pass a given point. What is the frequency of the waves?

Answers

In 7.5 s, 4200 waves will pass a given point. Then, the frequency of the waves is 560 Hz.

Frequency is the number of cycles or oscillations of a wave that occur in one second, measured in Hertz (Hz). It is the rate at which a wave completes a full cycle, which is usually measured as the number of wavelengths that pass a fixed point in a unit of time.

The formula for frequency is;

frequency = waves/time

Where "waves" is the number of waves that pass a given point and "time" is the time it takes for those waves to pass.

In this case, we know that 4200 waves pass a given point in 7.5 seconds, so we can plug those values into the formula;

frequency = 4200/7.5

Simplifying;

frequency = 560

Therefore, the frequency of the waves is 560 Hz.

To know more about frequency here

https://brainly.com/question/14316711

#SPJ1

Work and Kinetic Energy
1. A car starts at rest and ends up with 1500 j of K E. How much work was done on it?
2. A motorcycle at rest has 550 J of work done on it what is its final K E
3. A runner has 250 J of K E. A short time later, he has 350 J of K E how much work was done on him?
4. A runner has 250 J of K E. A short time later, he has 150 J of K E. How much work was done on him?
5. A 0.150 kg baseball is moving 30.0 m/s How much K E does it have?
6. A 0.150 kg baseball is moving 20.0m/s a bat hits it doing 15.0j of work on it what is the final K E of the ball?
7. A block is at rest a 40.0 N force directed 38.0 above horizontal pulls the block 8.00m across flat ground how much work was done on the block? what is its final K E
8. A block is moving with 52.0 J of K E A 12.0 N force pulls the block straight forward for 3.00 m How much work was done on the block? what is its final K E?
9. A block is moving with 52.0 J of K E A 12.0 N force pulls the block straight back against the motion for 3.00m how much work was done on the block what is its final K E
10. A 5.00 kg block is moving 6.00 m/s a short time later it is moving at 8.00 m/s what was the starting K E? what was the final K E? how much work was done on the block?

Answers

1. The work done on the car is equal to its change in kinetic energy, is 1500 J.

2. The work done on the motorcycle is equal to its change in kinetic energy, is 550 J.

3. The work done on the runner is equal to his change in kinetic energy, is  100 J.

4. The work done is equal to the negative of his change in kinetic energy, is 100 J.

5. The kinetic energy of the baseball is 67.5 J.

What is the work done?

The definition of work done includes both the forces applied to the body and the total displacement of the body. A constant force F is present before to this block. The goal of this force is to move the body d meters in a straight line in the force's direction.

The work done on the car is equal to its change in kinetic energy, so W = ΔKE = 1500 J.

The work done on the motorcycle is equal to its change in kinetic energy, so W = ΔKE = 550 J. Since the motorcycle was initially at rest, its final kinetic energy is equal to the work done on it, so KEf = W = 550 J.

The work done on the runner is equal to his change in kinetic energy, so W = ΔKE = 350 J - 250 J = 100 J.

Since the runner's kinetic energy has decreased, negative work must have been done on him. The work done is equal to the negative of his change in kinetic energy, so W = -ΔKE = -150 J + 250 J = 100 J.

The kinetic energy of the baseball is given by KE = 1/2 mv^2, where m is its mass and v is its velocity. Plugging in the given values, we get KE = 1/2 (0.150 kg) (30.0 m/s)^2 = 67.5 J.

Learn more about work done on:

https://brainly.com/question/8119756

#SPJ1

A 12.0kg object is pushed with a horizontal force of 6.0N East across a table. If the force of
friction is 2.0N, what is the acceleration of the object?

Answers

Answer:

0.33m/\(s^{2}\) East.

Hope this helps you. Do mark me as brainliest.

2. If an em' of Hg weighs 13.6 g, what is the mass of a cylinder of: Sem and height 20 Cm

Answers

Answer:

Let the mass of mercury  m= 13.6 gm and volume be V=1cm3.

Now change in volume when it is heated upto 50oC,

ΔV=VαΔT

ΔV=1×1.82×10−4×50

ΔV=91×10−4cm3 

New volume V1=V+ΔV=1.0091cm3

New density ρ=V1m=1.009113.6=13.48gcm−3

Explanation:

Mark me as a brainliest please

A hockey puck attached to a horizontal spring oscillates on a
frictionless, horizontal surface. The spring has force constant 4.50 N/m and the oscillation period is 1.20 s. (a) What is the mass of the puck? (b) During an oscillation, the acceleration of the puck has maximum magnitude 1.20 m/s^2. What is the amplitude of the oscillation?
Answers:
(a) 0.164 kg
(b) 0.0438 m = 4.38 cm

Answers

(a) The mass of the puck is 0.16 kg

(b)  The amplitude of the oscillation is 4.3 cm.

What is the mass of the puck?

The mass of the puck is calculated by applying the formula for the period of the oscillation.

T = 2π √ ( m /k )

T / 2π = √ ( m /k )

T² / 4π² = m/k

m = k ( T² / 4π² )

where;

k is the spring constantT is the period of oscillationm is mass of the puck

The mass of the puck is calculated as;

m = 4.5 ( 1.2² / 4π²)

m = 0.16 kg

The amplitude of the oscillation is calculated as follows;

a = ω²A

where;

ω is the angular frequencyA is the amplitude a is the maximum acceleration

ω = √ ( k /m )

ω² = k / m

from this equation "a = ω²A" make amplitude "A" the subject of the formula.

A = a / ω²

A = (a) / (k / m)

A = ( 1.2 ) / ( 4.5 / 0.16)

A = (1.2) / ( 0.03556)

A = 0.043 m = 4.3 cm

Learn more about amplitude here: https://brainly.com/question/3613222

#SPJ1

A detailed graph of angular velocity versus time is shown. What is the angular displacement, in radians, during the time interval from 0.75 s to 14.2 s?

Answers

0.116 rad/s is the angular speed in radians, during the time interval from 0.75 s to 14.2 s

ω=Δθ/Δt

Δθ= 90° = 1.571rad

Δt=13.45

ω=1.571/13.45

ω=0.116 rad/s

The rate of change of angular displacement, or the angle a body travels along a circular path, is the definition of angular speed. Calculating angular speed involves dividing the quantity of rotations or revolutions made by a body by the amount of time required. Omega is a Greek letter that represents angular speed. The SI's angular speed unit is rad/s.

As is well known, angular speed is determined by dividing the rate of displacement change by the time. As a result, the angular speed equation is = /t. Despite the procedure stated above, a different and more well-liked formula is used to determine angular speed in competitive testing. As ω = θ/t

To know more about angular speed visit : brainly.com/question/16407861

#SPJ9

the spaceship is flying through space far from planets and stars with the engines firing.
The astronaut shuts the engines off.

The spaceship will….

a. stop moving immediately

b. slow down gradually and stop

c. continue with whatever speed it had when the engines were cut off

d. speed up for just a little while, then slow down

Answers

c. continue with whatever speed it had when the engines were cut off

Which vector is the sum of vectors à and b?

Answers

The vectors addition permits locating the perfect result for the sum of the two vectors in option B).  See attached and the vector is directed to the right and up.

Vector addition is the operation of adding or extra vectors together into a vector sum. The so-known as parallelogram regulation gives the rule for vector addition of or greater vectors. for two vectors and, the vector sum is received via placing them head to tail and drawing the vector from the loose tail to the unfastened head.

A vector is an amount or phenomenon that has impartial residences: importance and direction. The time period also denotes the mathematical or geometrical representation of the sort of quantity. Examples of vectors in nature are velocity, momentum, force, electromagnetic fields, and weight.

Vectors are used in technological know-how to describe something that has a direction and a magnitude. they're commonly drawn as pointed arrows, the length of which represents the vector's importance

Disclaimer: your question is incomplete, please see below for the complete question.

The image shows the complete question.

Which vector is the sum of vectors à and b?

Learn more about vectors here:- https://brainly.com/question/25705666

#SPJ9

Which vector is the sum of vectors and b?

18] (b) The diagram below shows a uniform beam pivoted at P. The force of gravity on the beam is 425 N. 23" 3.4 m -8.4 m 720 N Determine the magnitude of the reaction force at the point. [12]

Answers

We have that  the magnitude of the reaction force at the point. is

Pv=3832N

From the question we are told

18] (b) The diagram below shows a uniform beam pivoted at P. The force of gravity on the beam is 425 N. 23" 3.4 m -8.4 m 720 N Determine the magnitude of the reaction force at the point.

Generally the equation for the Resolutions  is mathematically given as

\(\sum y=0\\\\Where\\\\Pv+Tsin23=720\\\\Pv=720-Tsin23\)

\(\sum x=0\\\\720*8.4=Tsin23 *3.4\\\\6048=3.4Tsin23\\\\T=4553N\)

Therefore

the magnitude of the reaction force at the point. is

Pv=3832N

For more information on this visit

https://brainly.com/question/12319416

18] (b) The diagram below shows a uniform beam pivoted at P. The force of gravity on the beam is 425

A smooth circular cylinder of radius 1.5m in a triangular grove, one side of which makes 15 °angle and the other 40° angle with the horizontal · Find the reaction. at the surface of contact, if there. is no fiction and the cylinder weigh 100N ​

Answers

Answer:

46.5 N

Explanation:

attached is explanation

A toy car on a string is pulled across a table horizontally. The string is at an
angle of 30°. Which is the correct free-body diagram for this situation?
EN
w
w
w
w
А
B
с
D
A. A
ОВ. В
ОО Ο Ο
O C. C
D. D

A toy car on a string is pulled across a table horizontally. The string is at anangle of 30. Which is

Answers

(C)

...........................

Answer:

Hope this helps!

Explanation:

A toy car on a string is pulled across a table horizontally. The string is at anangle of 30. Which is
Other Questions
Cage 1 1. What is the expected ratio of black to brown mice in Cage 1? BB BBit's not really math it's science The basic principle of activity based costing is a(n) On a spinner with two equal sections labeled 2 and 3 comma Josie determines that the probabilities of landing on 2 or 3 are equally likely. Which shows the probability of landing on a 2 ?. Civil Rights Activist began be portrayed in the media as ___________. 1 1/4 times 5 3/5 whats the answer in fractions Consider a monopoly that sales 500 units of a product each month. Buyers of this product paid $12 for each unit. The monopoly firm faces a constant marginal cost of $10. In addition, the firm's average fixed costs are $2 each month. The monopoly firms monthly economic profit equals $__________. Please input a numerical value without the $ sign your answer. If the answer is $30, please input 30. Parallel lines x and w are cut by transversals z and y and form 4 angles at each intersection. Where line x intersects with line z, labeled clockwise, from the uppercase left, the angles are: 1, 4, 3, 2. Where line w intersects with line z, the angles are: 5, 75 degrees, 7, 6. Where line x intersects with line x, the angles are: 13, 16, 15, 14. Where line w intersects line y, the angles are: 9, 12, 11, 10. What is m2? What is m1? can someone help me answer this Rewrite the equation 2y4x=10 in function notation where f(x)=y. At first, aids within the united states seemed to be confined principally to three groups: gay men, haitians, and people with Laser printers work with the use of heat and positive and negative charges. The laser etches a negative charge on spots of the printer drum in the form of text or images. The plastic ink dust is attracted to the places on the drum with this negative charge. What is the charge of the plastic ink dots themselves Question 2. Evaluate the principal value of the integral 00 dx L x2 + 2. + 2 Suppose that a duck is swimming in the circle x = cos(7t), y = sin(7t) and that the water temperature is given by the formula dT T = 2x e) 3xy4. Find the rate of change in temperature the duck might feel. dt (Use symbolic notation and fractions where needed.) Word of caution: this problem is lengthy because of the number of terms. Be careful when entering your answer. dT dt 8 = 28 sin(7t) cos(7t) e sin (7t) +21 sin (71) + 14 cos (71)eS 7t sin (7t) e 84 cos? (7t) sin(7t) - Incorrect PLS HELP ITS ABOUT PLANETS THSNKS a(x+2y)+(x+2y)^2please solving How is a Hypothesis different from a Theory? Solve the problem.The formula P = 14.7e-0.21x gives the average atmospheric pressure, P, in pounds per square inch, at an altitude x, in miles above sea level. Find the average atmospheric pressure for an altitude of 2.3 miles. Round your answer to the nearest tenth.A) 9.1 lb/in.B) 8.4 lb/in.C) 11.0 lb/in.D) 7.8 lb/in. The Net new borrowings of Maria's Tennis 5 hop, Ine 5,5300,000, The 2009 income statement showed an interest expense of 5170,000 . What was the thrm's cash flow to creditors during 2009? a. $300,000 b. $130,000 c. None of the above d. $470,000 A cone has a circular base with a diameter of 18 inches. The height of the cone is 40 inches. What is the approximate lateral area of the cone? Use 3. 14 for and round to the nearest whole number. 565 square inches 580 square inches 1,131 square inches 1,159 square inches. Noemy had homework three days of the school week. What is the ratio of days with homework to days without homework? Which of the following has the largest atomic radius? oxygen boron neon lilthium