Answer:
KE = 135,000 j or 135 KJ
Explanation:
KE=0.5mv^2
KE=0.5*1200*15^2
KE = 135,000 joules or 135 Kilo Joules
help on this asap please
Answer:
I think A is correct.
Explanation:
If it's not I'm sorry probably my fault but I hope this helps:)
A rocket is fired from the earth to the moon at a speed of 0.930c. Let two events be "rocket leaves earth" and "rocket hits moon"
A. In the earth's reference frame, calculate Δx for these events.
B. In the earth's reference frame, calculate Δt for these events.
C. In the earth's reference frame, calculate the spacetime interval s for these events.
D. In the earth's reference frame, calculate Δx' for these events.
E. In the earth's reference frame, calculate Δt' for these events.
F. In the earth's reference frame, calculate the spacetime interval s' for these events.
G. In the earth's reference frame, calculate Δx if a rocket is replaced with a laser beam.
H. In the earth's reference frame, calculate Δt if a rocket is replaced with a laser beam.
I. In the earth's reference frame, calculate the spacetime interval s if a rocket is replaced with a laser beam.
Express ALL parts with appropriate units
A. Δx = 384,400 km (distance between Earth and Moon)
How to solveB. Δt = 384,400 km / (0.930 * 299,792 km/s) ≈ 1.421 s
C. s² ≈ (-2.781 * 10^10) km² (imaginary number, time-like separated events)
D, E, F. Cannot answer without specified primed frame.
G. Δx for laser beam = 384,400 km
H. Δt for laser beam = 384,400 km / 299,792 km/s ≈ 1.282 s
I. s² for laser beam ≈ 0 km² (light-like separated events)
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What is the definition of the concept of a species in Bacteria based on? Explain your answer, taking into consideration that these organisms do not reproduce sexually.
An example where reaction time wouldn’t matter very much for the results
When studying the properties of light, for example, reaction time would not matter much. Light moves at such a fast rate that reaction time has no effect on the results of experiments measuring the speed of light, the reflection of light, or any other property related to light.
What is reflection?
Reflection is when a wave, such as a light wave or sound wave, bounces off a surface and returns to the source. This happens when the wave encounters an obstacle such as a wall or other barrier, and the wave is redirected back towards the source. Reflection is one of the fundamental principles of physics, and is used to explain many phenomena such as the fact that light is reflected off of a mirror. Reflection is also used to help explain phenomena such as sound reverberation and the formation of shadows.
What is sound reverberation ?
Sound reverberation is the effect created when a sound is reflected off of surfaces in a room or area. This effect is created when the sound bounces off of walls, ceilings, and other objects, and then is heard again by the listener. This creates an echo-like effect, and can be used to create a more acoustically ‘live’ sound.
Therefore, One example of where reaction time wouldn't matter very much for the results is when studying the properties of light.
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1. The kinetic energy of a 4,934 pound pickup truck going 55 mph is:
Provide your answer in kJ
2. A 4,992 lb car has a rolling resistance coefficient of 0.015. How much force, in lb, will it take to push this car at 30 mph?
3.The 2022 Hummer EV comes with a 212 kWh battery. How much will this battery weigh in lbs?
Answer:
1) 1256.02 kJ
2)76.20 lb
3)2336.30 lb
Explanation:
The kinetic energy of a 4,934 pound pickup truck going 55 mph is:
First, we need to convert the mass of the truck from pounds to kilograms:
4,934 lb = 2,236.17 kg
The kinetic energy is given by the formula: KE = 0.5 * m * v^2
where m is the mass of the object and v is the velocity.
Plugging in the values, we get:
KE = 0.5 * 2,236.17 kg * (55 mph)^2 = 1,256,024.47 J
Converting to kJ, we get:
KE = 1,256,024.47 J / 1000 = 1256.02 kJ
A 4,992 lb car has a rolling resistance coefficient of 0.015. How much force, in lb, will it take to push this car at 30 mph?
The force required to overcome rolling resistance is given by the formula:
F = Crr * W
where Crr is the rolling resistance coefficient and W is the weight of the car.
First, we need to convert the weight of the car from pounds to Newtons:
4,992 lb = 22,612.88 N
Plugging in the values, we get:
F = 0.015 * 22,612.88 N = 339.19 N
Converting to pounds, we get:
F = 339.19 N / 4.45 = 76.20 lb
The 2022 Hummer EV comes with a 212 kWh battery. How much will this battery weigh in lbs?
We cannot directly convert from kilowatt-hours to pounds, as they are two different units. However, we can use the energy density of the battery to estimate its weight.
Assuming an energy density of 200 Wh/kg for the battery, we can calculate the mass of the battery as:
212 kWh * 1000 Wh/kWh / 200 Wh/kg = 1060 kg
Converting to pounds, we get:
1060 kg * 2.205 lb/kg = 2336.30 lb
A scientist heated a tank containing 50 g of water. The specific heat of water is 4.18 J/gºC. The temperature of the water increased from 25ºC to 37ºC. How much heat energy did the water absorb?
1: 2,508 joules
2: -2,508 joules
3: 5,225 joules
4: 7,733 joules
Answer: a) 2,508
Explanation:
the spacing of the comb teeth is 2 mm. if you direct ghz electromagnetic waves at the comb, what frequency (in ghz) is deflected by 10 degree
The frequency of the electromagnetic waves that are deflected by 10 degrees by the comb with 2 mm spacing is 857 GHz (gigahertz).
The equation for the angle of deflection is given by:
sin(θ) = mλ/d
where m is the order of the diffraction peak, λ is the wavelength of the electromagnetic wave, and d is the spacing between the comb teeth.
The spacing of the comb teeth is 2 mm, and waves that are deflected by 10 degrees. Assume that order of the diffraction peak is 1.
Frequency, f = c/λ
where c is the speed of light, and λ is the wavelength.
Plugging in the given values, we get:
λ = 2 mm * sin(10 degrees) / 1 = 0.35 mm
f = 3 x 10^8 m/s / (0.35 mm) = 857 GHz
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Which of these objects could be falling with constant acceleration?
Object 1 and Object 2 will have a constant acceleration.
We know the expression for Displacement, Acceleration, and Time can be represented by the equation: S = ut + 1/2at². We will compare cases for each object at a given position and time and check if the object maintains a constant acceleration.
=> S = ut +1/2at², where S = Displacement/position of object, u = Initial velocity, t = time, a = acceleration.
For Object 1,
Case 1 : 0.44 = 0*0.3 + 1/2*a*(0.3)²
a = 9.78
Case 2 : 3.14 = 0*0.08 + 1/2*a*(0.8)²
a = 9.81
Acceleration is approximately constant for object 1.
For Object 2:
Case 1 : 0.06 = (0) (0.3) + ½ a (0.3)²
a = 1.33
Case 2: 3.09 = (0) (2.1) + ½ a (2.1)²
a = 1.40
Acceleration is approximately constant for object 2.
For Object 3:
Case 1 : 0.44 = (0) (0.3) + ½ a (0.3)²
a = 9.78
Case 2: 3.09 = (0) (2.1) + ½ a (2.1)²
a = 1.40
Acceleration has a lot of differences in both cases of Object 3 so it's not constant.
Hence, Object 1 and Object 2 have constant acceleration.
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You have a source of energy containing 21 gj of energy at 600k how much this energy can be converted to work when rejecting heat to the atmosphere at 27°C?
Answer:
Available energy = 35 x 10⁶ J
Explanation:
Given:
Amount of energy (Q) = 21 gj = 21 x 10⁹ J
Temperature T1 = 600 k
Temperature T0 = 27 + 273 = 300k
Find:
Available energy
Computation:
Available energy = Q[1/T0 - 1/T1]
Available energy = 21 x 10⁹ J[1/300 - 1/600]
Available energy = 35 x 10⁶ J
What is the magnitude of the net force acting on the car while it is moving from A to B?
Answer:
0 N
Explanation:
From A to B the car is going on a linear path so the velocity is not changing the direction. Since the speed is constant, there is no acceleration. Then, there is no net force acting on the car. Therefore, the magnitude of the net force acting on the car while it is moving from A to B is 0N.
The figure below shows electrons moving along an electric current towards and away from the light bulb.
Electrons traveling along an electric current. Arrow under electrons points right and left both towards and away from the light bulb.
Does this figure show a direct or alternating current? Explain your response.
Based on the information provided, it is likely that the figure shows an alternating current (AC). The arrows under the electrons pointing right and left, both towards and away from the light bulb, indicate that the direction of the electron flow is changing periodically. This is a characteristic of alternating current, where the flow of electric charge reverses direction periodically, typically in a sinusoidal manner.
In an AC circuit, the voltage also changes direction periodically, which is consistent with the changing direction of the electron flow shown in the figure.
In an alternating current, the flow of electrons periodically reverses direction, causing the current to switch between positive and negative values. This is different from direct current (DC), where electrons flow in a single, constant direction.
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the higher the objects " ? ", the more kinetic energy
An astronaut lifts off in a rocket from the surface of the moon, where g = 1.6 m/s^2. What vertical acceleration should his rocket have so that his apparent weight is equal to his true weight on earth?
The vertical acceleration the rocket should have so that his apparent weight is equal to his true weight on earth is 8.2 m/s².
The given parameters;
acceleration due to gravity on moon, g = 1.6 m/s²
The true weight of the rocket is calculated from Newton's second law of motion;
F = ma
Apparent weight on moon = true weight on Earth
mg + ma = mG
where;
G is the acceleration due to gravity on Earth
m(a + g) = mG
a + g = G
a = G - g
a = 9.8 - 1.6
a = 8.2 m/s²
Thus, the vertical acceleration the rocket should have so that his apparent weight is equal to his true weight on earth is 8.2 m/s².
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In the system drawn on the right, m_1 = 2.0 kg sits on a lab table which is 110 cm tall. m_2 = 1.0 kg is hanging over a pulley and is initially at rest 60.0 cm above the floor. The system is released. Determine the speed of m_2 just before it hits the floor. (solve with work-energy ideas, considering the system)
a) solve the problem assuming the table is frictionless.
b) coefficient of friction is .2 between m1 and the table
(a) The speed of the mass m2 just before it hits the floor for frictionless table is 1.98 m/s.
(b) The speed of the mass m2 just before it hits the floor when there is friction is 1.53 m/s.
Apply Newton's second law of motion for object m₁\(-f_k + T = m_1a\\\\ T = m_1 a + f_k \ ---\ (1)\\\\ \)
Apply Newton's second law of motion for object m₂\(m_2g - T = m_2a \ ---- (2)\\\\ \)
Solve (1) and (2) together
\(m_2 g - (m_1 a+ f_k) = m_2 a\\\\ m_2 g - f_k = m_1 a + m_2 a\\\\ m_2 g - f_k = a (m_1 + m_2)\\\\ a = \frac{m_2 g- f_k}{m_1 + m_2} \)
When the table is frictionless, the acceleration of the masses is calculated as follows;
\(a = \frac{m_2 g}{m_1 + m_2} \\\\ a = \frac{1 \times 9.8}{2 + 1} \\\\ a = 3.27 \ m/s^2\)
When the coefficient of friction between m1 and the table is 0.2, the acceleration of the masses is calculated as follows;
\(a = \frac{m_2 g - f_k}{m_ 1+ m_2} \\\\ a = \frac{m_2 g - \mu_k m_1g}{m_1 + m_2} \\\\ a = \frac{g(m_2 - \mu_km_1)}{m_1 + m_2} \\\\ a = \frac{9.8(1 - \ 0.2\times 2)}{2+1 } \\\\ a = 1.96 \ m/s^2\)
The height of the mass m2 above the ground = 60 cm = 0.6
Speed of the mass for frictionless tableThe speed of the mass m2 just before it hits the floor for frictionless table is calculated as follows;
\(v^2 = u^2 + 2ah\\\\ v^2 = 0 + 2ah\\\\ v^2 = 2ah\\\\ v= \sqrt{2ah} \\\\ v = \sqrt{2 \times 3.27 \times 0.6} \\\\ v = 1.98 \ m/s\)
The speed of the mass when there is frictionThe speed of the mass m2 just before it hits the floor when there is friction is calculated as follows;
\(v = \sqrt{2ah} \\\\ v = \sqrt{2 \times 1.96 \times 0.6} \\\\ v = 1.53 \ m/s\)
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3. Calculate the radii of the first five Fresnel zones if the distance from the light source to the wave surface is 1m, the distance from the wave surface to the observation point is also 1m and the light wavelength is 0.0000005m. (0.50mm; 0.71mm; 0.86mm; 1.0mm; 1.12mm).
The radii of the first five Fresnel zones is 3.6 mm.
Distance from the light source to the wave surface, d₁ = 1 m
Distance from the wave surface to the observation point, d₂ = 1 m.
Wavelength of the light used, λ = 5 x 10⁻⁶m = 5 μm
The expression for the radius of the Fresnel zones is given by,
rₙ = √[nλd₁d₂/(d₁ + d₂)]
Therefore, the radii of the first five Fresnel zones is,
r₅ = √[5 x 5 x 10⁻⁶x 1 x 1/(1 + 1)]
r₅ = √(25 x 10⁻⁶/2)
r₅ = 3.6 x 10⁻³m
r₅ = 3.6 mm
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1. Consider a rocket motor equipped with a nozzle in which the stagnation conditions are 3000 K and 60 atm. The specific heat ratio is 1.25 and the molecular weight of the propellant is 18. The nozzle throat diameter is 5 cm and the nozzle exit diameter is 30 cm. a. Calculate the exit velocity b. Calculate the exit pressure c. Calculate c* for this propellant d. Calculate the mass flow rate for the rocket e. If the rocket is fired at sea level, calculate the thrust. f. If the rocket is fired at sea level, calculate the thrust coefficient g. If the rocket is fired at sea level, calculate the effective exhaust velocity h. If the rocket is fired at sea level, calculate the specific impulse. i. If the rocket is fired in space, calculate the thrust. j. If the rocket is fired in space, calculate the thrust coefficient k. If the rocket is fired in space, calculate the effective exhaust velocity I. If the rocket is fired in space, calculate the specific impulse
The Exit velocity and Pressure in the case of a rocket motor are 1290m/s and 8.1 atm respectively. The C* and thrust propellant calculations are based on certain formulas.
Exit velocity is v_e = sqrt((2 * C_p * 3000 K) / (1.25 - 1)) * sqrt((1.25 + 1) / 2) * (1 - (p_e / 60 atm) ^ ((1.25 - 1) / 1.25)) = 1290 m/s.Exit pressure is p_e = 60 atm * ((2 / (1.25 + 1)) * (1 - (1290 m/s / sqrt((1.25 + 1) / 2 * C_p * 3000 K)) / (1 - (p_e / 60 atm) ^ ((1.25 - 1) / 1.25)))) ^ (1.25 / (1.25 - 1)) = 8.1 atm. This is the pressure at the nozzle exit.To calculate c* for the propellant, we can use the equation c* = sqrt(1.25 * 8.314 J/mol-K * 3000 K / 18) = 654.3 m/s.To calculate the mass flow rate for the rocket, we find that m_dot = 60 atm * (pi * (5 cm / 2)^2 / 4) * 654.3 m/s / sqrt(3000 K) = 4.1 kg/s.To calculate the thrust of the rocket, we can use the equation that F= 4.1 kg/s * 1290 m/s + (8.1 atm * (pi * (30 cm / 2)^2 / 4) - 60 atm * (pi * (5 cm / 2)^2 / 4)) = 45600 N. This is the thrust produced by the rocket at sea level.To calculate the thrust coefficient of the rocket motor, we can use the equation C_F = (2 / (1.25 + 1)) * (1 - (1290 m/s / sqrt((1.25 + 1) / 2 * C_p * 3000 K)) / (1 - (8.1 atm / 60 atm) ^ ((1.25 - 1) / 1.25))) = 0.8. This is the thrust coefficient of the rocket motor.To calculate the effective exhaust velocity of the rocket motor, we can use the equation v_e, eff = v_e + g * Isp, where v_e, eff is the effective exhaust velocity, v_e is the exit velocity, g is the acceleration due to gravity, and Isp is the specific impulse. At sea level, g = 9.8 m/s^2. The specific impulse of the rocket motor is given by the equation Isp = (1.25 * 8.314 J/mol * K * 3000 K) / (9.8 m/s^2 * 18 g/mol) = 279 s. The effective exhaust velocity of the rocket motor is v_e, eff = 1290 m/s + 9.8 m/s^2 * 279 s = 36660 m/s. This is the effective exhaust velocity of the rocket motor when fired at sea level.To calculate the thrust of the rocket motor, we can use the equation F = 8.1 atm * 28.3 cm^2 * 1290 m/s = 3.1 * 10^6 N.To calculate the thrust coefficient, we can use the equation C_F = 3.1 * 10^6 N / (8.1 atm * 0.2 cm^2) = 0.16.To calculate the effective exhaust velocity of the rocket motor when fired in space, we can use the equation v_e = sqrt((2 * C_p * 3000 K) / (1.25 - 1)) * sqrt((1.25 + 1) / 2) * (1 - (0 / 60 atm) ^ ((1.25 - 1) / 1.25)) * sqrt(1 - ((18 / 18) ^ 2)) = 1290 m/s.To calculate the specific impulse of the rocket motor, we can use the equation I_sp = 1290 m/s / 9.8 m/s^2 = 131 s. This is the specific impulse of the rocket motor when fired in space.Learn more about Stagnation Conditions here:
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Electric charge is distributed over the disk x2 + y2 ≤ 4 so that the charge density at (x, y) is rho(x, y) = 2x + 2y + 2x2 + 2y2 (measured in coulombs per square meter). Find the total charge on the disk.
Answer:
the total charge on the disk 256pi Coulombs
Explanation:
Pls see attached file
Consider a sound wave modeled with the equation s(x, t) = 3.00 nm cos(3.50 m−1x − 1,800 s−1t). What is the maximum displacement (in nm), the wavelength (in m), the frequency (in Hz), and the speed (in m/s) of the sound wave?
Answer:
- maximum displacement = 3.00nm
- λ = 1.79m
- f = 286.47 s^-1
Explanation:
You have the following equation for a sound wave:
\(s(x,t)=3.00nm\ cos(3.50m^{-1}x- 1,800s^{-1} t)\) (1)
The general form of the equation of a sound wave can be expressed as the following formula:
\(s(x,t)=Acos(kx-\omega t)\) (2)
A: amplitude of the wave = 3.00nm
k: wave number = 3.50m^-1
w: angular frequency = 1,800s^-1
- The maximum displacement of the wave is given by the amplitude of the wave, then you have:
maximum displacement = A = 3.00nm
- The wavelength is given by :
\(\lambda=\frac{2\pi}{k}=\frac{2\pi}{3.50m^{-1}}=1.79m\)
The values for the wavelength is 1.79m
- The frequency is:
\(f=\frac{\omega}{2\pi}=\frac{1,800s^{-1}}{2\pi}=286.47s^{-1}\)
The frequency is 286.47s-1
a boy throws a ball straight up into the air it reaches the highest point of its flight after 4 seconds how fast was the ball going when it left the boy's hand
Answer:
Gravity pulls down on the ball at g=-9.81 m/s^2. Up is positive, down is negative. The ball started at a certain initial velocity of Vi m/s. Time it took is t=4s. Final velocity is Vf=0 m/s, because at the highest point the ball stops moving.
Hey, I need help can someone help me out, please?
Explanation:
6) newton
7) f =ma = 15*15 = 225N
8) a= 100/20 = 5ms^-2
Answer:
6 newton
7) f =ma = 15*15 = 225N
8) a= 100/20 = 5ms^-2
Explanation:
this is right pls mark as brainliest
When the temperature is expected to drop below freezing, a farmer places large tubs of water in an unheated food storage shed. Write two or three sentences explaining why the farmer uses this technique to protect the produce from freezing. Hint: Remember that liquid water has more potential energy than ice.
The farmer uses this technique to protect the produce from freezing because as the water in the tubs begins to freeze, it releases heat. This heat can help to keep the surrounding air in the shed above freezing, protecting the produce from freezing as well. Additionally, as the water in the tubs freezes, it releases latent heat of fusion, which is the energy required to change a substance from a solid to a liquid. This energy is also released in the form of heat, further helping to keep the produce from freezing.
How do electrons conduct electricity?Please explain in terms of charges
The electrons are usually at a constant distance from the nucleus of an atom in precious shells. The flow of charges to the per unit of time helps the conductor to conduct electricity. The mathematic representation of the electric current is given in the terms of charges as
\(I=\frac{q}{t}\)*Here 'q' is the charge
*Here 't' is the time
The movement of electrons
The flow of charges inside the metal (conductor) is known as the electric current.
What happens to the mechanical advantage of a machine if the output force is less than the input force? What must happen to output distance? Give an example of a machine that does this?
Consider the following scenario. A car for which friction is not negligible accelerates from rest down a hill, running out of gasoline after a short distance (see below). The driver lets the car coast farther down the hill, then up and over a small crest. He then coasts down that hill into a gas station, where he brakes to a stop and fills the tank with gasoline. Identify the forms of energy the car has, and how they are changed and transferred in this series of events.
Answer:
1) U-> K +W
2) K -> W
Explanation:
In this exercise, care must be taken as they indicate that the friction force (rubbing) is not negligible.
1 part at the top of the hill the car has gravitational potential energy, which is transformed in a part into kinetic energy and another part into heat by the work of the friction force that opposes the movement.
2 part when the other hill rises it loses kinetic energy that is transformed into gravitational potential energy and part in heat due to the work of the friction force on this hill.
3rd part in the last descent all the gravitational potential energy is transformed into kinetic energy and the application of the brakes is transformed into heat due to the negative lock of the friction force and filled with gasoline that has chemical energy that can be transformed in the engine.
When measuring resistance or voltage on a CANbus, always use a digital _____ and disconnect the _____ battery terminal when measuring resistance.
Use a digital multimeter and disconnect the negative battery terminal when measuring resistance on a CANbus.
What is a MultimeterA multimeter, also called volt-ohm-meter ( VOM ),is a handheld measuring instrument either analog or digital that can measure the voltage, resistance, and current across circuits in a device.
When measuring resistance on a CANbus with the digital multimeter, it is necessary to disconnect the negative battery , This puts the power off. This is to ensure only the resistance is measured and prevent other components' from being measured and distorting readings.
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A classroom is about 3 meters high, 20 meters wide and 30 meters long. If the density of air is 1.29 kg/m3, what is the mass of the air in the classroom?
Answer:
the mass of the air in the classroom = 2322 kg
Explanation:
given:
A classroom is about 3 meters high, 20 meters wide and 30 meters long.
If the density of air is 1.29 kg/m3
find:
what is the mass of the air in the classroom?
density = mass / volume
where mass (m) = 1.29 kg/m³
volume = 3m x 20m x 30m = 1800 m³
plugin values into the formula
1.29 kg/m³ = mass
1800 m³
mass = 1.29 kg/m³ ( 1800 m³ )
mass = 2322 kg
therefore,
the mass of the air in the classroom = 2322 kg
If A classroom is about 3 meters high, 20 meters wide and 30 meters long. If the density of air is 1.29 kg/m3, then the mass of the air in the classroom is 2322Kg.
What is density??Density is the ratio of mass to volume. it tells how much mass a body is having for its unit volume. for example egg yolk has 1027kg/m³ of density, means if we collect numbers of egg yolk and keep it in a container having volume 1 m³ then total amount of mass it is having will be 1027kg. Density is a scalar quantity. when we add egg yolk into the water, egg yolk has greater density than water( 997 kg/m³), because of higher density of egg yolk it contains higher mass in same volume as water. hence due to higher mass higher gravitational force is acting on the egg yolk therefore it goes down on the inside the water. water will float upon the egg yolk. same situation we have seen when we spread oil in the water. ( in that case water has higher density than oil. thats why oil floats on the water).
Given,
Height = 3 m
Width = 20 m
length= 30 m
Density of air = 1.29kg/m³
The volume of the room = 3×20×30 m³
Volume V = 1800m³
By formula,
Density = Mass/Volume
1.29kg/m³ = Mass/1800m³
Mass of the air = 1.29×1800 = 2322 Kg
The mass of the air is classroom is 2322Kg.
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Researchers want to assess your intelligence. To do so, they have you
complete a short survey on which you indicate your favorite color. They ask
you to complete this survey multiple times, and you always answer the same
color. Unfortunately, one's favorite color has nothing to do with one's
intelligence. This research survey is best defined as:
This research survey is an example of a flawed or invalid measure of intelligence.
The research survey that is shown in this question can be defined as a poor measurement tool for assessing intelligence. One can easily identify that the researchers are measuring intelligence by asking about the favorite color of the personnel, which has nothing to do with the intelligence of the person. This survey lack validity which is essential to measure the intelligence of any personnel through a survey.
The survey also lacks reliability as it can't provide consistent results. If the intelligence of any personnel is somehow related to the intelligence of the person, answering the survey multiple times must give the same answer. This doesn't provide consistent result and lack reliability and realism.
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A sea otter swims toward an inlet with a speed of 5.0 m/s as a current of1.0 m/s flows in the opposite direction. How long will it take the sea otterto swim 100. m?*
Given:
The speed of sea otter is
\(v_s=5\text{ m/s}\)The speed of the current is
\(v_c=\text{ 1 m/s}\)in the opposite direction.
The distance is d = 100 m
To find the time taken by sea otter to cover a distance d = 100 m.
Explanation:
The total speed of sea otter is
\(\begin{gathered} v_=v_s-v_c \\ =5-1 \\ =4\text{ m/s} \end{gathered}\)The time taken will be
\(\begin{gathered} t=\frac{d}{v} \\ =\frac{100\text{ m}}{4\text{ m/s}} \\ =25\text{ s} \end{gathered}\)Thus, the time taken is 25 s to swim 100 m.
Need help with my homework assignment. Thank you!
According to research, development is always towards complexity.
What is the meaning of research?The term research has to do with the process that we have to go through to obtain new knowledge or to confirm a piece of information. Let us say that we have some disconnected pieces of evidence that tend to point towards a particular fact, we would need to use the process of research to establish the truth in the research.
Now we can see that there is a movement towards the complexity of organisms at each particular level in the developmental process. We can then conclude that according to research, development is always towards complexity.
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Which of the following is not a type of foul in basketball?
A. Holding
B. Pushing
C. Covering
D. Technical
Answer:
c. covering
Explanation:
covering is just doing defence and is not illegal in basketball