Calculate the binding energy, and the binding energy per nucleon, for a nucleus of the 16O isotope. Express your answers in units of megaelectronvolts (MeV).

Answer:

13636.36 Hz or 1.36*10^(4) Hz

Explanation:

We know as an equation for velocity (v) = wavelength (lambda) * frequency (f)

re write the equation to solve for f to get

f= v / lambda

f= 300.0 (m/s) / .022(m)

f= 13636.36 (1/s)

Hz shows up as 1/s because it is a special unit.

a)1060 kg/m2.

b) 525

What exactly is inertia?

a quality of matter that allows it to remain in its current state of rest or uniform motion in a straight line until modified by an external force.

What is the definition of moment of inertia?

In physics, a moment of inertia is a quantitative measure of a body's rotational inertia—that is, the resistance that the body shows to having its speed of rotation along an axis altered by the application of a torque (turning force). The axis might be internal or exterior, and it can be fixed or not.

A rigid body's moment of inertia, also known as its mass moment of inertia, angular mass, second moment of mass, or, more precisely, rotational inertia, is a quantity that determines the torque required for a desired angular acceleration about a rotational axis, similarly to how mass determines the force required for a desired acceleration. A typical mechanical quantity is the moment of inertia.

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Inertia is a property of matter that causes it to resist changes in velocity (speed and/or direction). According to Newton's first law of motion, an object with a given velocity maintains that velocity unless acted on by an external force. Inertia is the property of matter that makes this law hold true.

What exactly is inertia?

A quality of matter that allows it to remain in its current state of rest or uniform motion in a straight line until modified by an external force.

What is the definition of moment of inertia?

In physics, a moment of inertia is a quantitative measure of a body's rotational inertia—that is, the resistance that the body shows to having its speed of rotation along an axis altered by the application of a torque (turning force). The axis might be internal or exterior, and it can be fixed or not.

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Pressing a lever in the box's corner is the sole method to get rid of the shocks. The rat picks up pressing the lever quite quickly. This is an illustration of negative reinforcement.

The technique of negative reinforcement can be applied to aid in teaching particular actions.

When something unpleasant or uncomfortable is taken away in response to a stimulus, this is known as negative reinforcement.

Target behavior should gradually grow better with the hope that the unpleasant item will go away.

A rat is placed in an environment where the floor gives the rat small electric shocks. The only way to get rid of the shocks is to press a lever in the corner of the box.

The rat quickly learns to press the lever. This is an example of  negative reinforcement

Hence the given condition is an example of negative reinforcement.

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Answer:

C. observations

Explanation:

a scientist have to observe somethng to find the answers or solve problems

The hydraulic radius is the same for both pipes, the velocity of the water in the circular pipe must be the same as the velocity of the water in the square pipe, i.e., v1.

The cross-sectional area of a pipe and its hydraulic radius, which is the ratio of the cross-sectional area to the wetted perimeter, determine the velocity of water flowing through it.

The equation v = s/t denotes the vector quantity velocity (v), which quantifies displacement (or change in location, s), over change in time (t).

Given that the cross-sectional area of the circular pipe is\(a^2\) and the wetted perimeter is 2a the hydraulic radius is a.

The hydraulic radius is a for the square pipe because its cross-sectional area is\(2 a^ 2\) and wetted perimeter is 4 a.

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1 ) Acceleration of the ball just before it strikes the ground = 10.67 m/s²

2 ) The initial speed of the ball = 1.15 m / s

3 ) The initial speed of the ball if the ball lands at 5.0 m/s = 3.2 m / s

v² = u² + 2 a s

v = Final velocity

u = Initial velocity

a = Acceleration

s = Displacement

1 ) In vertical motion,

v = 4 m / s

s = 0.75 m

u = 0

4² = 0 + ( 2 * a * 0.75 )

a = 16 / 1.5

a = 10.67 m / s²

2 ) The initial speed of the ball,

Resolving the velocity into its horizontal and vertical components,

\(V_{y}\)² = \(U_{y}\)² + 2 a s

\(V_{y}\)² = 0 + ( 2 * 9.8 * 0.75 )

\(V_{y}\) = 3.83 m / s²

V² = \(V_{x}\)² + \(V_{y}\)²

4² = \(V_{x}\)² + 3.83²

\(V_{x}\) = √ 16 - 14.67

\(V_{x}\) = 1.15 m / s

\(V_{x}\) = \(U_{x}\) = 1.15 m / s

3 ) If the ball lands with a speed of 5.0 m/s,

V² = \(V_{x}\)² + \(V_{y}\)²

5² = \(V_{x}\)² + 3.83²

\(V_{x}\) = √ 25 - 14.67

\(V_{x}\) = 3.2 m / s

\(V_{x}\) = \(U_{x}\) = 3.2 m / s

Therefore,

1 ) Acceleration of the ball just before it strikes the ground = 10.67 m/s²

2 ) The initial speed of the ball = 1.15 m / s

3 ) The initial speed of the ball if the ball lands at 5.0 m/s = 3.2 m / s

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To find the time it took for the car to accelerate, you can use the formula:

t = (v - u) / a

where t is the time, v is the final velocity, u is the initial velocity, and a is the acceleration.

Plugging in the given values, you get:

t = (26 m/s - 19 m/s) / (205 m / t^2)

You can then rearrange the equation to solve for t:

t = sqrt(205 m / (26 m/s - 19 m/s))

Solving for t, you get:

t = sqrt(205 m / 7 m/s) = sqrt(29.3 s^2) = 5.4 s

So it took the car approximately 5.4 seconds to accelerate from 19 m/s to 26 m/s.

Answer:

mars is to hot

Explanation:

The experimental determination of the centripetal force when employing F = ma depends on the centripetal force parameters for an item in uniform circular motion.

A parameter "beside, subsidiary" is, in general, any attribute that helps define or categorize a particular system. To put it another way, a parameter is a system component that is essential or helpful for identifying the system or evaluating its operation, status, or other properties. The term "parameter" has more specific definitions in several disciplines, including mathematics, computer programming, engineering, statistics, logic, linguistics, and electronic music production. In addition to its technical uses, it also has broader implications, especially outside of the realm of science, where it is employed to indicate defining characteristics or restrictions, as in the expressions "test parameters" or "game play parameters."

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Answer:

laa a

Explanation:poque usairea  ye aire tienfe luza preopia mkr

Answer:

Solar Panels

Explanation:

Answer:

\(0.25\ cm^3\)

Explanation:

Data provided in the question

Number of drops fell from a burret = 60

The first reading is 28 cm^3

And, the final reading is 43 cm^3

Based on the above information, the average volume of one drop is

\(= \frac{Final\ readings - first\ readings}{number\ of\ drops}\)

\(= \frac{43\ cm^3 - 28\ cm^3}{60 \ drops}\)

\(= 0.25\ cm^3\)

Basically we applies the above formula by applying the three items given in the question so that the average volume of one drop could come

Answer:

0.25\ cm^30.25 cm

3

Explanation:

Data provided in the question

Number of drops fell from a burret = 60

The first reading is 28 cm^3

And, the final reading is 43 cm^3

Based on the above information, the average volume of one drop is

= \frac{Final\ readings - first\ readings}{number\ of\ drops}=

number of drops

Final readings−first readings

= \frac{43\ cm^3 - 28\ cm^3}{60 \ drops}=

60 drops

43 cm

3

−28 cm

3

= 0.25\ cm^3=0.25 cm

3

Answer:

Which month has the longest daytime? shortest daytime?

Explanation:

Answer: 700 kg/m³

Explanation: Check the solutions , 3 ways :-

The density of cube  will be 700 kg/m^3.

What is the density of cube.

Length of cube(l) =15 cm =0.15m

Volume of cube (\(V_{c}\)) = l^3=(0.15 m)^3

Volume of water displaced (\(V_{w}\)) = Volume of cube inside water

\(V_{w}\) =0.15*0.15*0.105 m^3

we know that,

Density of water (\(D_{w}\)) =1000 kg/m^3

from law of floatation ,

Weight of floating body= Weight of displaced liquid

\(V_{c}\)\(D_{c}\)g = \(V_{w}\)\(D_{w}\)g

\(V_{c}\)\(D_{c}\)=\(V_{w}\)\(D_{w}\)

0.15*0.15*0.15*\(D_{c}\)=0.15*0.15*0.105*1000

\(D_{c}\)=0.105*1000/0.15

\(D_{c}\) =700

Hence, The density of cube  will be 700 kg/m^3.

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Answer:

The first reactant is methane, the next is oxygen, the first product is carbon dioxide and the second product is water.

The word equation is:

methane + oxygen → carbon dioxide + water

The balanced symbol equation is:

CH₄ + 2O₂ → CO₂ + 2H₂O

Explanation:

In any combustion reaction, fuel is burned in the presence of oxygen to produce carbon dioxide and water.

An equation is balanced when there are the same number of atoms of each element on both sides of the arrow.

Hope this helps!

Answer:

Longitudinal waves

Explanation:

With sound waves, the energy travels along in the same direction as the particles vibrate. This type of wave is known as a longitudinal wave , so named because the energy travels along the direction of vibration of the particles.

Explanation:

the tune of neptune is better thatbany other tune

hope it helps

The total number of lamps is mathematically given as

N=24

Question Parameters:

How many 60-watt lamps could be connected in parallel on a 15-amp, 120-volt

Generally, the equation for the Power  is mathematically given as

P=IV

Therefore

I=P/v

I=60/120

I=0.5A

Since the system does not exceed 80% of the rating

NI=I'(0.8)

N=15*0.8/0.5

N=24

In conclusion, the total number of lamps is

N=24

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Answer:

the answer is 352.8m

Explanation:

Since the gravitational constant is denoted as g

\(g = 9.8 \: \frac{m}{ {s}^{2} }\)

and the ball needed 6 seconds to land, so we can calculate the height of the building as:

\(h = 9.8 \: \frac{m}{ {s}^{2} } \times {(6s)}^{2} = 9.8 \: \frac{m}{ {s}^{2} } \times 36 {s}^{2} = 352.8m\)

Answer:

the mass of the car is very big

Explanation:

its heavy

The coefficient of friction can be calculated by dividing a distance by a distance, which results in a dimensionless quantity.

The coefficient of friction is a dimensionless quantity, so it does not have any SI units. It represents the ratio of the force required to overcome the frictional force between two surfaces in contact, and it is expressed as a pure number without units.

In the given equation, the height of the meter stick is measured in meters (m) and the base of the meter stick is also measured in meters (m). Therefore, the coefficient of friction can be calculated by dividing a distance by a distance, which results in a dimensionless quantity.

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The beam is compressed approximately 2677.9 micrometers along its length due to the loading.

To calculate the distance that the aluminum beam is compressed along its length, we need to use Hooke's Law, which states that the deformation of an elastic material is directly proportional to the applied force.

The formula for calculating the compression of a beam is:

Compression = (Force × Length) / (Elastic modulus × Cross-sectional area)

In this case, the force applied to the beam is 48549 N, the unloaded length of the beam is 2.7 m, and the cross-sectional area is 0.0007 m^2.

We need to determine the elastic modulus of aluminum. The elastic modulus for aluminum is approximately 70 GPa (gigapascals) or 70 × 10^9 N/m^2.

Using these values, we can substitute them into the formula:

Compression = (48549 N × 2.7 m) / (70 × 10^9 N/m^2 × 0.0007 m^2)

Simplifying the calculation:

Compression = (131169.3 N·m) / (49 × 10^6 N/m^2)

Compression ≈ 2.6779 × 10^-3 m

To convert this value to micrometers (µm), we multiply it by 10^6:

Compression ≈ 2.6779 × 10^-3 m × 10^6 µm/m

Compression ≈ 2677.9 µm

Therefore, the beam is compressed approximately 2677.9 micrometers along its length due to the loading.

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Explanation:

The formula for finding distance is: speed × time

We must multiply:

200Km/h × 2.5 hours

This gives you 500 Km.

Remember: the formula to work out the distance -  speed x time.

If the train speed is 200 km/h, it travels 200 km/h.

Now, we must multiply 200 by 2.5:

200 x 2.5 = 500

Our answer is 500 Kilometers.

Answer:

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Explanation:

You know where this comes from, right thoughtqueztionz?

Answer:

Typical golf caddie responsibilities include carrying clubs, cleaning balls,

calculating distances and scores, and even replacing the divots - pieces of

grass and dirt that have been cut loose by the swift, forceful strikes of golf

clubs.

Answer:

1. C. can be affected

2. B. in the opposite direction as the electric field

3. C. the charge's velocity and the magnetic field

4. I am sorry I have no answer for this one :(

Explanation:

1. Yes they actually can be affected because they are interacting with another magnectic field

2. The force exerted on a negatively charged particle by the electric field is always in " the direction opposite that of the electric field itself. "

3. In the context of the electric field as the set of almost all electric field vectors in a region of space, the most simplest kind of an electric field is a uniform electric field

Equal but in opposing directions, forces of the car and the force of the bus.

Given that both objects are moving, you can be sure that the collision is elastic and that the forces involved in the collision between the bus and the car will be equal.

Without force, objects cannot be moved, stopped, or changed direction. Force can be defined as the pushing or pulling of any object as a result of the object's interaction or movement. In nature, there are various types of forces that interact quantitatively between two physical bodies, such as an object and its surroundings. If an object is in motion or in a static state, the position of the object can only be changed by an external force—referred to as force—pushing or pulling against it. The various types of contact force include spring force, applied force, air resistance force, normal force, tension force, friction force, and others that are generated when we exert some effort on an object. Non-contact forces, which include electromagnetic, gravitational, and nuclear forces, are another category of forces that exist at a distance.

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Using a saltwater aquarium to model the ocean has limitations, such as showing only a small part of the actual ocean and being unable to replicate the vastness and complexity of the ocean ecosystem.

One limitation of using a saltwater aquarium to model the ocean is that it can only show a small part of the actual ocean. Since an aquarium is confined and limited in size, it cannot realistically replicate the vastness and complexity of the ocean ecosystem. For example, it may not have the space to accommodate large marine animals like whales or the turbulent currents that exist in the open ocean. Therefore, it is important to recognize that while a saltwater aquarium can provide some insights into the ocean, it cannot fully capture the dynamic nature and diverse interactions found within the entire ocean ecosystem.

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Answer:

Speed = 4 m/sec

Explanation:

Speed = Distance / Time

Where Distance = 7200 m and Time = 1800 s

Speed = 7200 m / 1800 sec

Speed = 4 m/sec