Answers
Answer:
Explanation:
The energy of a quantum of light with frequency v is given by
\(E=hv\)where h = planck's constant = 6.63 *10^-34 and v = frequency of light.
Now in our case, we are told that
\(v=4.21\times10^{11}\times10^3Hz\)The extra 10^3 comes from the fact that we were given kilohertz (and not simply hertz).
Substituting the value of the given frequency and the Planck's constant into the above equation gives
\(E=(6.63\times10^{-34})\times(4.21\times10^{11}\times10^3)\)which upon evaluating gives
\(\boxed{E=2.79\times10^{-19}J}\)Hence, the energy of our quantum of light is 2.79*10^-19 Joules!
Related Questions
It takes tiffany 0. 25 hours to get to school in the mornings. She lives 4. 5 miles away from the school. At what speed (in miles per hour) is she traveling to get there?.
Answers
If It takes Tiffany zero.25 hours to get to school in the mornings. She lives 4.5 miles far away from the faculty, then the speed of traveling off the Tiffany would be 28.96 kilometers per hour.
velocity of touring = general distance traveled by means of the Tiffany / general time
velocity of touring = 4.5 × 1.609 / 0.25
= 28.96 kilometers per hour
Speed in physics is a scalar quantity that refers to the rate at which an object moves, usually expressed in units of meters per second (m/s) or kilometers per hour (km/h). It is defined as the distance an object travels per unit of time, which means that it only takes into account the magnitude of the object's motion and not its direction.
Instantaneous speed refers to the speed of an object at any given moment, while average speed is calculated over a period of time. The speed of an object can be influenced by several factors, such as the forces acting upon it and the medium through which it is moving.
In addition to speed, there are other related concepts in physics, such as velocity, which includes both the speed and direction of an object's motion, and acceleration, which describes the fee at which an item's speed modifications over time.
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A 2.5 m ramp is used to load a truck 1.0 m off of the ground. A man uses 600 N of force to load a box weighing 1200 N. What is the efficiency of the ramp? What is the mechanical advantage of the ramp?
Answers
The efficiency of the ramp is 80% and the mechanical advantage is 2.
What is the efficiency of the ramp?
To solve this problem, we can use the formulas for efficiency and mechanical advantage:
Efficiency = (output work / input work) x 100%
Mechanical Advantage = output force / input force
First, we need to find the output force and output work of the ramp.
The output force is the weight of the box, which is 1200 N.
The output work is the force applied by the output force over the distance it moves. Since the box moves a distance of 1.0 m up the ramp,
the output work is:
Output work = output force x output distance
Output work = 1200 N x 1.0 m
Output work = 1200 J
Next, we need to find the input force and input work of the ramp.
The input force is the force applied by the man, which is 600 N.
The input work is the force applied by the input force over the distance it moves. Since the man moves a distance of 2.5 m along the ramp,
the input work is:
Input work = input force x input distance
Input work = 600 N x 2.5 m
Input work = 1500 J
Now we can calculate the efficiency and mechanical advantage:
Efficiency = (output work / input work) x 100%
Efficiency = (1200 J / 1500 J) x 100%
Efficiency = 80%
Mechanical Advantage = output force / input force
Mechanical Advantage = 1200 N / 600 N
Mechanical Advantage = 2
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What factor that influence science research?
Answers
Answer:
The general norms of science;
The nature of particular scientific disciplines and the traditions of organizing a specific body of scientific knowledge;
The Role of Individual Scientists and Research Teams
institutional Policies
Social Attitudes and Expectations
Explanation:
How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.A cylindrical solenoid with radius 1.00 cm
and length 10.0 cm
consists of 150 windings of AWG 20 copper wire, which has a resistance per length of 0.0333 Ω/m
. This solenoid is connected in series with a 10.0 μF
capacitor, which is initially uncharged. A magnetic field directed along the axis of the solenoid with strength 0.160 T
is switched on abruptly.
How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.
Answers
The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.
The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.
Initially, the capacitor is uncharged, so the second term is zero.
Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.
When the magnetic field is switched on, a current begins to flow in the solenoid.
This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.
Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.
The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.
Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.
This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.
The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)
The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)
The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)
This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.
The solution is t = 1.74 ms.
The units are in seconds.
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5. Hilda is trying to move a 40 kg couch across a level floor and pushes with a horizontal force of
150 N, but the couch does not move. What is the minimum coefficient of static friction with the
floor? Assume the acceleration due to gravity is g = 9.8 m/s2
Answers
The minimum coefficient of static friction with the floor is 0.3846.
To find the minimum coefficient of static friction with the floor, we need to consider the forces acting on the couch. In this case, the force of gravity is pulling the couch downward with a magnitude of mg, where m is the mass of the couch (40 kg) and g is the acceleration due to gravity (9.8 m/s²).
Since the couch does not move, the force of static friction between the couch and the floor must be equal in magnitude but opposite in direction to the horizontal pushing force of 150 N.
Therefore, we have the equation F_friction = F_push, where F_friction is the force of static friction.
The force of static friction can be calculated using the formula F_friction = μ_s * N, where μ_s is the coefficient of static friction and N is the normal force.
Since the couch is on a level floor and is not accelerating vertically, the normal force N is equal in magnitude but opposite in direction to the force of gravity, which is mg.
Substituting the values into the equation, we have μs * mg = 150 N.
Solving for μs, we get μs = 150 N / (mg).
Substituting the given values, we have μ_s = 150 N / (40 kg * 9.8 m/s²).
Simplifying, we find that μs = 0.3846.
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Two long, straight wires are separated by a distance of 32.2 cm. One wire carries a current of 2.75 A, the other carries a current of 4.33 A. (a) Find the force per meter exerted on the 2.75-A wire. (b) Is the force per meter exerted on the 4.33-A wire greater than, less than, or the same as the force per meter exerted on the 2.75-A wire
Answers
Answer:
a)\(\frac{F_1}{L}=1.95*10^-^5N\)
b)\(\frac{F_2}{L}=1.95*10^-^5N\)
Explanation:
From the question we are told that:
Distance between wires \(d=32.2\)
Wire 1 current \(I_1=2.75\)
Wire 2 current \(I_2=4.33\)
a)
Generally the equation for Force on \(l_1\) due to \(I_2\) is mathematically given by
\(F_1=I_1B_2L\)
Where
B_2=Magnetic field current by \(I_2\)
\(B_2=\frac{\mu *i_2}{2\pi d}\)
Therefore
\(F_1=I_1B_2L\)
\(F_1=I_1(\frac{\mu *i_2*l_1}{2\pi d})L\)
\(\frac{F_1}{L} =\frac{4*\pi*10^{-7}*2.75*4.33*100 }{2*\pi*12.2 }\)
\(\frac{F_1}{L}=1.95*10^-^5N\)
b)
Generally the equation for Force on \(I_2\) due to \(I_1\) is mathematically given by
\(F_2=I_2B_1L\)
Where
B_1=Magnetic field current by \(I_2\)
\(B_1=\frac{\mu *I_1}{2\pi d}\)
Therefore
\(\frac{F_2}{L} =I_2(\frac{\mu *I_1*I_2}{2\pi d})\)
\(\frac{F_2}{L}=1.95*10^-^5N\)
Explain in two or three sentences how we can know what an object is made out of by looking at the light it gives off?
Answers
Answer:
The act of 'seeing' an object is the result of light from any luminous source e.g. the Sun, a glowing candle or a torch, radiating outwardly from the source until it strikes the object and is reflected to travel to the observer's eyes where if it retains sufficient intensity it will form an image on the retina. i hope this helps
Which of the following best describes an inverse-square relationship?(A) Daylight on Mars is dimmer than daylight on Earth.(B) A camera flashbulb produces a sudden burst of light.(C) When you blow out a candle, the room darkens.(D) Installing compact fluorescent bulbs reduces your electric bill.
Answers
The inverse-square relationship states:
The intensity of the light to an observer from a source is inversely proportional to the square of the distance from the observer to the source. According to this, we can describe this mathematically as follows:
\(\frac{I1}{I2}=\frac{d1^2}{d2^2}\)In this sense:
Let:
I1 = Intensity of light in earth
I2 = Intensity of light in mars
d1 = distance from sun to the earth
d2 = distance from sun to mars
If the light on mars is dimmer:
I2besides:
d2>d1
So, we can conclude that the most accurate statement is:
(A) Daylight on Mars is dimmer than daylight on Earth.
Calculate the energy stored in the stretched wire. With an extension of 0.30mm a steel wire with a length of 4.0m and a cross sectional area of 2.0x 10^6m*
Answers
Given data,
Change in length,
\(\Delta L=0.\text{30 mm}\)Length of the steel wire,
\(L=4.0\text{ m}\)Area,
\(A=2.0\times10^{-6}m^2\)Young modulus,
\(\text{young modulus=2}.1\times10^{11}\text{ pa}\)Calculate the strain in the wire,
\(\begin{gathered} \text{Strain}=\frac{\Delta L}{L} \\ Strain=\frac{0.30\times10^{-3}^{}\text{ m}}{\text{4.}0\text{ m}} \\ Strain=0.075\times10^{-3}\text{ m} \end{gathered}\)Calculate the stress in the wire,
\(\begin{gathered} \text{Stress}=young\text{ modulus}\times strain \\ \text{Stress}=2.1\times10^{11}\times0.075\times10^{-3} \\ \text{Stress}=0.1575\times10^8Nm^{-2} \end{gathered}\)Calculate the volume of the wire,
\(\begin{gathered} V=2\times10^{-6}\times4 \\ V=8\times10^{-6}m^3 \end{gathered}\)Calculate the elastic potential energy stored.
\(\begin{gathered} U=\frac{1}{2}\times stress\times strain\times\text{volume} \\ U=\frac{1}{2}\times0.1575\times10^{8\times}0.075\times10^{-3}\times\text{8}\times10^{-6} \\ U=0.004725\text{ J} \end{gathered}\)Part-II Work out Step by step clearly (6%) 5. A 5kg mass starts from rest at xo = -1 and moves under the action of a variable force F(x) = √1-x² to point xf = 1. Calculate the total work done by the force? (1%)
Answers
If a 5kg mass starts from rest at xo = -1 and moves under the action of a variable force F(x) = √1-x² to point xf = 1. Then the total work done by the force is equal to π/2 + 1.
To calculate the total work done by the force in this scenario, we can use the formula for work:
Work = ∫F(x) dx
where F(x) is the force as a function of position and dx represents an infinitesimal displacement.
In this case, the force is given by F(x) = √(1 - x²), and we need to find the total work done as the object moves from xo = -1 to xf = 1.
Let's break down the calculation step by step:
Write the integral for work:
Work = ∫F(x) dx
Substitute the given force:
Work = ∫√(1 - x²) dx
Integrate with respect to x:
To integrate the square root of (1 - x²), we use the trigonometric substitution. Let's substitute x = sin(θ) and dx = cos(θ) dθ.
Work = ∫√(1 - sin²(θ)) cos(θ) dθ
Simplify the integrand:
Using the trigonometric identity sin²(θ) + cos²(θ) = 1, we can rewrite the integrand as cos²(θ).
Work = ∫cos²(θ) dθ
Apply the power-reducing formula:
The power-reducing formula states that cos²(θ) = (1 + cos(2θ)) / 2. We can use this formula to simplify the integrand further.
Work = ∫(1 + cos(2θ))/2 dθ
Integrate the terms separately:
Work = (1/2) ∫dθ + (1/2) ∫cos(2θ) dθ
The first integral, ∫dθ, is simply θ, and the second integral, ∫cos(2θ) dθ, can be calculated as sin(2θ)/2.
Work = (1/2) θ + (1/2) (sin(2θ)/2) + C
Evaluate the integral limits:
To find the total work done, we need to evaluate the integral at the upper and lower limits of integration.
At xf = 1, the angle θ is π/2, and at xo = -1, the angle θ is -π/2.
Work = (1/2) (π/2) + (1/2) (sin(2(π/2))/2) - [(1/2) (-π/2) + (1/2) (sin(2(-π/2))/2)]
Simplifying further:
Work = π/4 + (1/2) - (-π/4 + (1/2))
Work = π/4 + 1/2 + π/4 + 1/2
Work = π/2 + 1
Therefore, the total work done by the force is equal to π/2 + 1.
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A 50.0-kg wagon is pulled with a constant force of 380 N. Neglecting friction, the wagon's acceleration will be
Answers
A 50.0-kg wagon is pulled with a constant force of 380 N. Neglecting friction, the wagon's acceleration will be 7.6 m/s².
When a constant force acts on a wagon, it causes the wagon to accelerate We can calculate the wagon's acceleration using Newton's second law, which states that the force acting on an object is directly proportional to its acceleration, and the acceleration is inversely proportional to the mass of the object.A = F/mHere,A = AccelerationF = Force acting on the wagon m = mass of the wagon Substituting the given values, we getA = 380 N/50.0 kgA = 7.6 m/s²Therefore, the acceleration of the wagon is 7.6 m/s² when it is pulled with a constant force of 380 N, neglecting friction.For such more question on Newton's second law
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When it comes to fitness, at the end of the day the most important thing is
Answers
Answer:
Getting a good rest
Explanation:
can someone help me pleaseenkwnsn
Answers
If a third resistor is added in SERIES, what changes happens to the....
a. Total Voltage - stay the same b. Total Current - decrease c. Total Resistance - increase d. Voltage through resistor 1 - decrease e. Current through resistor 1 - decreaseWhat happens in a circuit?When you add a third resistor in series, the total resistance of the circuit increases. This is because the current has to flow through all three resistors, so it has to overcome more resistance. The total voltage across the circuit stays the same, because the voltage of the battery is constant. However, the current decreases, because the same amount of current is now flowing through a larger resistance.
The voltage across each resistor also decreases, because the total voltage is divided among the three resistors. The current through each resistor also decreases, because the same current is now flowing through a larger resistance.
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An object has no speed. Which of the following correctly describes the object’s motion?
Answers
Answer:
Potential Energy
Explanation:
Potential energy is the energy an object has before it starts moving.
Answer:
u788i
Explanation:
A ceramic tile measuring 50 cm x50cm has been designed to bear a pressure of 40 N/in . Will it with stand a force of 5 N?
Answers
Answer:
Yes the tile can withstand a force 5 N
Explanation:
We'll begin by converting the dimensions from cm to in. This can be obtained as follow:
Dimension = 50 cm x 50cm
Recall
2.54 cm = 1 in
Therefore,
50 cm = 50 cm × 1 in / 2.54 cm
50 cm = 19.685 in
Thus, the dimension becomes:
Dimension = 19.685 in × 19.685 in
Next, we shall determine the area. This can be obtained as follow:
Dimension = 19.685 in × 19.685 in
Area = 19.685 in × 19.685 in
Area = 387.5 in²
Next, we shall determine the force to which the tile can withstand. This can be obtained as follow:
Pressure (P) = 40 N/in²
Area (A) = 387.5 in²
Force (F) =?
P = F/A
40 = F/387.5
Cross multiply
F = 40 × 387.5
F = 15500 N
Thus, the tile can withstand a force up to 15500 N.
Therefore, the answer to the question is:
Yes the tile can withstand a force 5 N
WHAT IS THE MASS OF A PURE PLATINUM DISK
Answers
The mass of a pure platinum disc can be gotten by multiplying the density with the volume.
Therefore the mass is 2418.2 grams or 2.4182 kilograms.
What is mass?A body's mass is an inherent quality. Prior to the discovery of the atom and particle physics, it was widely considered to be tied to the amount of matter in a physical body.
The kilogram is the primary mass unit in the SI.
The resistance of the body to acceleration in the presence of a net force can be measured as mass.
Due to the lower gravity on the Moon, an object would weigh less than it does on Earth while maintaining the same mass. This is due to the fact that mass, coupled with gravity, determines the strength of weight, which is a force.
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What is the mass of a pure platinum disk with a volume of 113 cm3? The density of platinum is 21.4 g/cm3.
Give your answer in grams and kilograms.
The rotational inertia of a collapsing spinning star changes to 1/6 its initial value. What is the ratio of the new rotational kinetic energy to the initial rotational kinetic energy
Answers
Answer:
Explanation:
Let the initial rotational inertia be I and final rotational inertia be I / 6 .
Let the initial angular velocity be ω₁ and final angular velocity be ω₂.
Applying conservation of angular momentum law
I x ω₁ = I / 6 x ω₂
6 ω₁ = ω₂
initial rotational kinetic energy = 1/2 I x ω₁ ²
Final rotational kinetic energy = 1/2 ( I / 6 ) x ω₂ ²
Final rotational kinetic energy / initial rotational kinetic energy
= ( 1 / 6 ) x ω₂ ² / ω₁ ²
= ω₂ ² / 6ω₁ ²
= 36 ω₁ ² / 6ω₁ ²
= 6 .
The ratio will be "6". A further solution is below.
Let,
The initial rotational inertia,
\(\omega_1 = 1\)The final rotational inertia,
\(\omega_2 = \frac{1}{6}\)By applying the conservation of angular momentum law, we get
→ \(1\times \omega_1 = \frac{1}{6}\times \omega_2\)
→ \(6 \ \omega_1 = \omega_2\)
Now,
Initial rotational K.E = \(\frac{1}{2}1\times \omega_1^2\)
Final rotational K.E = \(\frac{1}{2} (\frac{1}{6} )\times \omega_2^2\)
hence,
→ \(\frac{Final \ rotational \ K.E}{Initial \ rotational \ K.E} = \frac{(\frac{1}{6} )\times \omega_2^2}{\omega_1^2}\)
\(= \frac{\omega_2^2}{6 \omega_1^2}\)
\(= 6\)
Thus the answer above is right.
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Show all work. Write the equation, plug in numbers, and get answer with unit.
9. A child sits on a dock and notices that 8 wavelengths pass the end of the dock in 4 seconds. What is
the frequency of the waves passing the dock? What is the period of the waves?
10. A pendulum oscillates 12 times in 4 seconds.
a. What is the frequency of the pendulum's oscillations?
b. What is the period of the pendulum's oscillations?
11. water wave has a frequency of 2 Hz, and there are 3 meters between each crest on the wave. How
fast is the wave moving?
12. Sound waves travel at roughly 340 m/s at room temperature. The minimum hearing range of a
human is 20 Hz. What is the wavelength of this wave?
I
Answers
The frequency is the inverse of time period of a wave and the time period of a wave is the time taken divided by number of cycles or wave.
What is Frequency and period of a wave?A wave is a propagating dynamic disturbance of different quantities. Frequency is the number of waves which are passing by a specific point of time per second. And, time period is the time which the wave takes for one wave cycle to complete.
Frequency of a wave can be calculated by reciprocal of time taken.
Frequency of a wave = 1/ Time period
The time period is the time in which one wave.
9. The time period of the wave = Time taken/ Number of waves or cycles
Time period = 4/ 8
Time period = 1/2 or 0.5 sec
Frequency of a wave = 1/ T
Frequency of a wave = 1/ 0.5 = 2⁻¹
10. The time period of the pendulum's oscillations = 4/ 12 = 1/3 = 0.33 sec
The frequency of the pendulum's oscillations = 3.03 sec⁻¹
11. Speed of a wave = wavelength of a wave × frequency of the wave
Speed of a wave = 3 × 2
Speed of a wave = 6 meters per second
12. Wavelength of the wave will be the ratio of speed of the wave and frequency of the wave.
Wavelength (λ) = Speed of the wave (v)/ frequency of the wave (f)
Wavelength = 340/ 20
Wavelength = 170 meters
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Hello I want to ask questions about physics
Answers
Answer:
okay then
Explanation:
When 1.5 kg of mass turns into energy, how much energy is released? Find the equation, substitution, and number with units.
Answers
Explanation:
\(from \: einstein \: equation : \\ E = m {c}^{2} \\ E = 1.5 \times {(3 \times {10}^{8} )}^{2} \\ E = 1.35 \times {10}^{17} \: joules\)
How are u? I hope u doing well ااااااااااااااااا
Answers
Answer:
Hey
I'm alright and you
I also hope you're doing well
Which is an example of a non-contact force?
A. A woman pulls open a door.
B. A magnet pulls an item toward it.
C. A student pushes his chair in at his desk.
D. A rolling ball slows down from friction
! Will give brainliest if you help !
Answers
Answer:
B - magnet pulls an item toward it.
Explanation:
It's the answer trust bro
Answer:
B.
Explanation:
Because your not physically touching the item getting pulled towards the magnet. hope this helps
A wire loop is suspended from a string that is attached to point P in the drawing. When released, the loop swings downward, from left to right, through a uniform magnetic field, with the plane of the loop remaining perpendicular to the plane of the paper at all times. Determine the direction of the current induced in the loop as it swings past the locations labeled (a) I and (b) II. Specify the direction of the current in terms of the points x, y, and z on the loop (e.g., x→y→z or z→y→x). The points x, y, and z lie behind the plane of the paper. What is the direction of the induced current at the locations (c) I and (d) II when the loop swings back, from right to left?
Answers
Complete Question
The complete question iws shown on the first uploaded image
Answer:
a
\(y \to z \to x\)
b
\(x \to z \to y\)
Explanation:
Now looking at the diagram let take that the magnetic field is moving in the x-axis
Now the magnetic force is mathematically represented as
\(F = I L\) x B
Note (The x is showing cross product )
Note the force(y-axis) is perpendicular to the field direction (x-axis)
Now when the loop is swinging forward
The motion of the loop is from y to z to to x to y
Now since the force is perpendicular to the motion(velocity) of the loop
Hence the force would be from z to y and back to z
and from lenze law the induce current opposes the force so the direction will be from y to z to x
Now when the loop is swinging backward
The motion of the induced current will now be x to z to y
11.1. Is ammeter A1 connected in series or in parallel in this diagram?
Answers
Ammeter is always connected in series with the circuit in which the current is to be measured.
An ammeter is connected, to gauge the current flowing through a part or circuit. Since current in a series connection stays constant and an ammeter's resistance is relatively low, the current being measured is unaffected. For the purpose of measuring current, an ammeter is linked in series.
A shunt running parallel to the metre carries the majority of the current at high current values, hence an ammeter can measure a wide range of current values. An ammeter is represented by a circle with a capital A inside it on circuit diagrams.
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A car with a mass of 1200kg is traveling west at 25 m/s collides head on with highway barrier. The car comes to rest in 0.35 seconds . What is the magnitude of the force and the impulse applied to the car
Answers
The magnitude of the force and the impulse applied to the car are 85714 N and 30000 N-s respectively.
What is force?
The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
The magnitude of the force applied to the car = change in momentum/time interval
= (1200 kg × 25 m/s - 1200 kg×0)/0.35 second
= 85714 N.
The impulse applied to the car = change in momentum
= (1200 kg × 25 m/s - 1200 kg×0)
= 30000 N-s.
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A wildebeest and a chicken participate in a race over a 2.10 km long course. The wildebeest travels at a speed of 19.0 m/s and the chicken can do 3.30 m/s. The wildebeest runs for 1.680 km and then stops to tease the slow-moving chicken, which eventually passes by. The wildebeest waits for a while after the chicken passes and then runs toward the finish line. Both animals cross the finish line at the exact same instant. Assume both animals, when moving, move steadily at their respective speeds.
(a) how far (in m) is the chicken from the Finish Line when the wildebeest resume the race?
(b) for how long in time (in s) was the wildebeest stationary?
Answers
Answer:
Explanation:
2.1 km = 2100 m
1.68 km = 1680 m
a ) Time taken by wild beast to travel 1680 m
= 1680 / 19 = 88.42 s
Time taken by wild beast to travel 2100 m
2100 / 19 = 110.52 s
distance travelled by chicken in 88.42 s
= 88.42 x 3.3 = 291.78 s
Its distance from the end point
= 2100 - 291.78 = 1808.22m
b ) Time taken by chicken to travel 2100 m
= 2100 / 3.3 = 636.36 s
Both reach simultaneously so , time of resting by wild beast
= 636.36 - 110.52 = 525.84 s .
what happens to the thermal conductivity of the wall if it's thickness is doubled ?
Answers
If the material's physical characteristics and other factors are constant, doubling the wall's thickness will reduce its thermal conductivity by a factor of two.
What is Thermal conductivity ?The capacity of a material to conduct heat is known as thermal conductivity.
When a wall's thickness doubles, there is now a twofold increase in the amount of material that heat must pass through to move from one side to the other of the wall. This denotes a reduction in thermal conductivity due to a slowing of heat transfer.
Therefore, If the material's physical characteristics and other factors are constant, doubling the wall's thickness will reduce its thermal conductivity by a factor of two.
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A 5.8 kg mass is attached to a spring with a stiffness of 490 N/m and is allowed to move along a friction-less horizontal surface. The mass is pulled back so that the spring is stretched 0.19 m from its equilibrium position. What will be the speed of the mass in m/s as it returns to the equilibrium position?
Answers
Answer:
1.75 m/s
Explanation:
k = Spring constant = 490 N/m
m = Mass of object = 5.8 kg
x = Displacement of spring = 0.19 m
v = Speed of object at the equilibrium position
The potential energy of the spring will balance the kinetic energy of the mass
\(\dfrac{1}{2}kx^2=\dfrac{1}{2}mv^2\\\Rightarrow v=\sqrt{\dfrac{kx^2}{m}}\\\Rightarrow v=\sqrt{\dfrac{490\times 0.19^2}{5.8}}\\\Rightarrow v=1.74637\ \text{m/s}\)
The speed of the mass as it returns to the equilibrium position is 1.75 m/s.
an object has the mass of 5.7kg what is the force of gravity acting on the object on earth
Answers
Answer:
55.68
Explanation:
Which type of wave displaces the particles of the medium parallel to the direction on which the wave travels?
Answers
Longitudinal waves
In a longitudinal wave the particles are displaced parallel to the direction the wave travels.