Calculate the molarity of 1 L of water at 20 °C given a density of 0.9982 g/mL.

Answer:

365 mL

Explanation:

There are 1,000 mL per every 1 L. As such, to convert between the two measurements, you need to multiply the given volume (0.365 L) by the conversion. To allow for the cancellation of units (liters), liters should be in the denominator of the conversion.

1,000 mL = 1 L

 0.365 L            1,000 mL
----------------  x  -----------------  = 365 mL
                               1 L

Answer: cash?

Explanation: oh and it’s d

Answer:

2.49 M

Explanation:

Step 1: Given data

Step 2: Calculate the moles AlCl₃ (solute)

The molar mass of AlCl₃ is 133.34 g/mol.

150. g × 1 mol/133.34 g = 1.12 mol

Step 3: Calculate the molar concentration of AlCl₃

Molarity is equal to the moles of solute divided by the liters of solution.

M = 1.12 mol/0.450 L = 2.49 M

Answer:

1

Explanation:

Mass of

C

a

C

N

2

= 75.0 g

From the equation,

C

a

C

N

2

(

s

)

+

3

H

2

O

(

l

)

→

C

a

C

O

3

(

s

)

+

2

N

H

3

(

g

)

1 mol of

C

a

C

N

2

reacts with 3 moles of water to give calcium carbonate and ammonia.

Number of moles of

C

a

C

N

2

,

n

=

G

i

v

e

n

m

a

s

s

M

o

l

a

r

m

a

s

s

Molar mass of

C

a

C

N

2

= 92.11 g/mol

Therefore,

n

C

a

C

N

2

=

75

g

92

.11

g

/

m

o

l

=

0

.814

m

o

l

Moles of water =Therefore,

n

C

a

C

N

2

=

75

g

92

.11

g

/

m

o

l

=

0

.814

m

o

l

Moles of water =

3

×

0

.814

m

o

l

e

s

=

2

.442

m

o

l

e

s

Mass of water needed;

=

m

o

l

e

s

o

f

w

a

t

e

r

×

m

o

l

a

r

m

a

s

s

o

f

w

a

t

e

r

=

2

.442

m

o

l

×

18

g

/

m

o

l

=

43

.956

g

Thus, 43.96 g of water is needed to react with 75 g of

C

a

C

N

2

.

150 mole/g is the right response.

Use powers of 10 to multiply or divide. Because you multiply or divide by 10—sometimes more than once—to convert SI units is simple. Consider a staircase. Every time you ascend a stair, you multiply by 10, and every time you descend a flight, you divide by 10.

Data and content transformation services and products are offered by Data Conversion Laboratory (DCL). implementing the most recent developments in artificial intelligence, such as machine learning and natural language processing

Mole/kg*m=mole/1000g*\(10^{2}\)\(cm^{2}\)

solution is 150

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Answer:

i moles of copper has 6.022 multiplied by 10raseto 23

Explanation:

Answer:

Neutral solutions have an equal number of H+ ions and OH- ions. Acidic solutions have a higher H+ concentration. An acid is a substance that releases H+ when dissolved in water. Basic solutions have a low H+ concentration.

Answer:

Ans choise B

Explanation:

Increasing rates of reaction by catalysts always results because of decrease in activation energy occurs.

The electronic configuration 1s2,2s2,2p6,3s2  belongs to Magnesium.

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Answer:

C2H6N2O

Explanation:

Mass of carbon = 12g /44g/mol *  5.134 g = 1.4 g

Number of moles of carbon= 1.4 g/12g/mol = 0.12 moles

Mass of hydrogen = 2 g/18g/mol *  3.173 g = 0.35 g

Number of moles =  0.35 g/1 g/mol =  0.35

Mass of nitrogen= 37.82/100 * 4.319 g = 1.6 g

Number of moles = 1.6 g/14g/mol = 0.11

Mass of oxygen  = (4.319) - (1.4 + 0.35 + 1.635) = 0.934 g

Number of moles = 0.934 g/16 g/mol = 0.058 moles

The lowest ratio is 0.058

Dividing through;

C- 0.12/0.058 = 2

H - 0.35 / 0.058= 6

Nitrogen - 0.11/0.058 = 2

O- 0.058 moles/0.058 = 1

Hence he empirical formula is;

C2H6N2O

Answer:

D

Explanation:

The rest have characteristics of a plant cell

The number of moles of carbondioxide that will be produced in the combustion of methane is 3 moles (option D).

Stoichiometry refers to the study and calculation of quantitative (measurable) relationships of the reactants and products in chemical reactions (chemical equations).

According to this question, methane undergoes combustion in air to produce carbondioxide and water. Methane is the limiting reactant because the other reactant is oxygen of the air which is always present in excess.

Based on the chemical equation given above, 1 mole of methane produces 1 mole of carbondioxide.

This means that 3 moles of methane will produce 3 moles of carbondioxide.

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There are 0.2107 moles of KBr are dissolved in 60.2 mL of a 3.50 M solution.

The molarity of a substance is defined as the number of moles of solute present in 1 litre of a solution.

According to the given data, the molarity of the solution tells us that there are 3.50 moles of KBr in 1000mL of solution. But we only have 60.2mL of solution, so with a mathematical rule of three we can calculate the amount of moles in 60.2mL:

1000 ml - 3.50 moles

60.2 ml -x = 60.2 ml× 3.50 moles/1000 ml

x= 60.2 ml -0.2107 moles

So, there are 0.2107 moles of KBr.

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We are going to have the polynomial as;

\(4u^7 + 13 u^2 - 9\)

We know that when we talk about the Polynomial we are referring to the values in which one of the algebraic terms have been raised to a given power as we can see in the problem that we have in the statement that has been made here.

We have the polynomials as;

\((8u^7 + 5u^5 - 5) - (4u^7 - 8u^5 + 4)\)

When we open up the bracket;

\(8u^7 + 5u^5 - 5 -4u^7 + 8u^5 - 4\)

We then have;

\(8u^7 - 4u^7 + 5u^5 + 8u^5 - 5 - 4\\4u^7 + 13 u^2 - 9\)

Thus we have seen how the difference between the polynomials can be gotten for the problem that we have in this case here as shown by the problem that have been solved in the statements above us here.

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Answer:

Below

Explanation:

Density = mass / volume      the volume = the amountof water displaced

Density = 96 g /4 cc = 24 g/cc     ( cc and ml are the same )

Answer:

The correct answer to you your question is Potassium

Explanation:

Potassium is the most reactive

The electron configuration 1s22s22p6 corresponds to the noble gas neon (Ne), which has a completely filled valence shell.

What is Electric Configuration?

The placement of electrons around the nucleus of a specific atom or molecule is known as its electronic configuration.

Protons, neutrons, and electrons are the minuscule components that make up an atom. There are the same number of protons and electrons in a neutral atom. The quantity and location of an atom's electrons are revealed by its electronic configuration.

We say that electrons orbit the nucleus of an atom, like the rings of Saturn orbit the planet. Electrons move in orbitals that can accommodate a specific number of electrons as they circle the nucleus.

Four elements that may have ions with this electron configuration are:

Fluorine (F-) - gains one electron to achieve a noble gas configuration (1s22s22p6)

Oxygen (O2-) - gains two electrons to achieve a noble gas configuration (1s22s22p6)

Sodium (Na+) - loses one electron from the valence shell to achieve a noble gas configuration (1s22s22p6)

Magnesium (Mg2+) - loses two electrons from the valence shell to achieve a noble gas configuration (1s22s22p6)

Therefore, the symbols for these ions are:

Na+, Mg2+, F-, O2-.

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Answer:(−NH−CHR−CO−)n is a homopolymer. The reason is that it has a single monomer (NH2−CHR−COOH), α−amino acid.

If a polymer consists of only one kind of monomer then it is called a homopolymer, while a polymer that consists of more than one kind of monomer is called a copolymer

1.25 moles of \(CO_{2}\) are required to react with 2.50 moles of \(NH_{3}\).

What are the moles?

Moles are a unit of measurement used in chemistry to express the amount of a substance. One mole of a substance is equal to its molecular weight expressed in grams. In other words, one mole of a substance contains 6.022 x \(10^{23}\) individual particles (atoms, molecules, or ions). The number of moles of a substance can be calculated by dividing its mass in grams by its molecular weight or by using the ideal gas law PV=nRT, where n is the number of moles.

The balanced chemical equation is:

\(2NH_{3}\)(g) + \(CO_{2}\)(g) → \((NH_{2})_{2}CO\)(aq) + \(H_{2}O\)(l)

From the balanced equation, we can see that 1 mole of \(CO_{2}\) reacts with 2 moles of \(NH_{3}\).

Therefore, to determine the moles of \(CO_{2}\) required to react with 2.50 moles of \(NH_{3}\), we need to use the mole ratio from the balanced equation:

2 \(NH_{3}\) : 1 \(CO_{2}\)

2.50 moles \(NH_{3}\) * (1 mole \(CO_{2}\) / 2 moles \(NH_{3}\)) = 1.25 moles \(CO_{2}\)

Therefore, 1.25 moles of \(CO_{2}\) are required to react with 2.50 moles of \(NH_{3}\).

What is molecular weight ?

Molecular weight, also known as molar mass, is the mass of one mole of a substance. It is expressed in units of grams per mole (g/mol). The molecular weight of a compound is determined by adding up the atomic weights of all the atoms in the molecule.

What is substance?

In chemistry, a substance is a form of matter that has constant chemical composition and characteristic properties. It may be an element or a compound made up of two or more elements chemically combined in a fixed proportion. Examples of substances include pure water, carbon dioxide gas, and sodium chloride (table salt).

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The boundary conditions for a solid-liquid interface, interface of two immiscible liquids, and a liquid-gas interface in terms of Vgas, Vliquid, and Vsolid are Vliquid = Vsolid, Vliquid1n = Vliquid2n and τ1n = τ2n for the interface of two immiscible liquids, and Vliquid = Vsolid and τgas = 0 for the liquid-gas interface.

Solid-Liquid Interface:

At a solid-liquid interface, the boundary condition is given by the no-slip condition, which states that the velocity of the liquid at the interface is equal to the velocity of the solid surface. This can be expressed mathematically as, Vliquid = Vsolid.

Interface of Two Immiscible Liquids:

At the interface of two immiscible liquids, the boundary condition is given by the continuity of the normal component of velocity and the stress balance at the interface. This can be expressed mathematically as, Vliquid1n = Vliquid2n and τ1n = τ2n where Vliquid1n and Vliquid2n are the normal components of the velocities of the two liquids on either side of the interface, and τ1n and τ2n are the normal stress components on either side of the interface.

Liquid-Gas Interface:

At a liquid-gas interface, the boundary condition is given by the no-slip condition for the liquid and the zero-shear stress condition for the gas. This can be expressed mathematically as, Vliquid = Vsolid and τgas = 0 where Vliquid is the velocity of the liquid at the interface, Vgas is the velocity of the gas at the interface, and τgas is the shear stress on the gas side of the interface.

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The volume of the tank is approximately 130.75 m³.

To solve this problem, we need to use the concept of air and water vapor mixture. The given data includes the mass of dry air and water vapor, temperature, and total pressure. We can calculate the specific humidity, relative humidity, and volume of the tank using the following steps:

(a) Specific humidity:

The specific humidity (ω) is defined as the ratio of the mass of water vapor (m_w) to the total mass of the air-water vapor mixture (m_t):

ω = m_w / m_t

Given that the mass of water vapor is 0.17 kg and the total mass of the mixture is 15 kg + 0.17 kg = 15.17 kg, we can calculate the specific humidity:

ω = 0.17 kg / 15.17 kg ≈ 0.0112

So, the specific humidity is approximately 0.0112.

(b) Relative humidity:

Relative humidity (RH) is the ratio of the partial pressure of water vapor (P_w) to the saturation vapor pressure of water (P_ws) at the given temperature, multiplied by 100:

RH = (P_w / P_ws) * 100

To find the relative humidity, we need to determine the saturation vapor pressure at 30°C. Using a vapor pressure table or equation, we can find that the saturation vapor pressure at 30°C is approximately 4.246 kPa.

Given that the total pressure is 100 kPa, the partial pressure of water vapor is 0.17 kg / 15.17 kg * 100 kPa = 1.119 kPa.

Now we can calculate the relative humidity:

RH = (1.119 kPa / 4.246 kPa) * 100 ≈ 26.34%

So, the relative humidity is approximately 26.34%.

(c) Volume of the tank:

To find the volume of the tank, we can use the ideal gas law equation:

PV = nRT

Where P is the total pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

First, we need to calculate the number of moles of dry air and water vapor in the tank. The number of moles (n) can be obtained using the equation:

n = m / M

Where m is the mass and M is the molar mass.

The molar mass of dry air is approximately 28.97 g/mol, and the molar mass of water vapor is approximately 18.015 g/mol.

For dry air:

n_air = 15 kg / 0.02897 kg/mol ≈ 517.82 mol

For water vapor:

n_water = 0.17 kg / 0.018015 kg/mol ≈ 9.43 mol

Now we can calculate the volume using the ideal gas law:

V = (n_air + n_water) * R * T / P

Given that R is the gas constant (8.314 J/(mol·K)), T is the temperature in Kelvin (30°C + 273.15 = 303.15 K), and P is the total pressure (100 kPa), we can calculate the volume:

V = (517.82 mol + 9.43 Mol) * 8.314 J/(mol·K) * 303.15 K / (100,000 Pa) ≈ 130.75 m³

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Answer:

Example 1

palladium(II) nitrate,

Example 2

Metal catalysts such as Fe, Ni, Mo, and Co are routinely used in the manufacture of CNMs.

Explanation

The three metals used in catalytic converters — rhodium, platinum and palladium — are part of a category known as platinum group metals, or PGMs, which are known for their catalytic properties.

Answer: Neils Bohr

Explanation: Development of the Atomic Theory. In 1913, Neils Bohr, a student of Rutherford 's, developed a new model of the atom. He proposed that electrons are arranged in concentric circular orbits around the nucleus. This model is patterned on the solar system and is known as the planetary model.

Answer:

a but it might also be c

Explanation:

i d k what this is

Answer:

2V1

Explanation:

Answer:

The molarity of the solution is 0.99M.

Explanation:

The molaruty if a solution represents the amount of solute moles contained in 1 liter (1000ml) of a solution.

1st) In this case, we have 17.3g of KCl, so we have to use the KCl molar mass (74.5g/mol) to convert grams into moles:

Now we know that there are 0.23 moles of the solute KCl.

2nd) We have 0.23 moles of KCl contained in 231 mL of solution, so to calculate the molarity (moles of solute contained in 1000mL of solution), we can use a mathematical rule of three:

Finally, the molarity of the solution is 0.99M.

Answer:

homogenous mixture

Explanation: