Calculate the power output exerted by a boy of a mass 92 kg who runs up a staircase to a floor 8m higher in 9s.

Answers

Answer 1

Given:

The mass of the boy, m=92 kg

The height of the floor, h=8 m

The time it takes for the boy to climb up the stairs, t=9 s

To find:

The power exerted by the boy.

Explanation:

The power exerted is the time rate of transfer of energy. Thus the power is caculated as the ratio of the work done to the time.

Thus the power exerted by the boy is given by,

\(P=\frac{W}{t}=\frac{mgh}{t}\)

Where h is the height of the stairs.

On substituting the known values,

\(\begin{gathered} P=\frac{92\times9.8\times8}{9} \\ =801.4\text{ W} \end{gathered}\)

Final answer:

The power exerted by the boy is 801.4 W


Related Questions

How are work and power different

Answers

Work is defined as the process of energy transfer to the motion of an object through the application of force. Power is defined as the amount of energy transferred in unit time.

what is the specific function of the respiratory system?

Answers

Answer:

Your respiratory system is the network of organs and tissues that help you breathe. This system helps your body absorb oxygen from the air so your organs can work. It also cleans waste gases, such as carbon dioxide, from your blood. Common problems include allergies, diseases or infections.

Explanation:

have an awesome day! :3

If the 4th harmonic in the diagram has a wavelength = 10 m,
find the wavelengths of the other three harmonics

If the 4th harmonic in the diagram has a wavelength = 10 m,find the wavelengths of the other three harmonics

Answers

The wavelengths are given as

firsts harmonic = 40 m

second harmonic = 20 m  

third harmonic = 13.33 m

What is wavelengths

Wavelength refers to the distance between two consecutive points of a wave that are in phase, or the distance it takes for a wave to complete one full cycle. It is commonly denoted by the Greek letter lambda (λ).

Using the wavelength of the fourth harmonics as reference, we have that the full scale is 20 m

firsts harmonic = 40 m (double of the full scale)

second harmonic = 20 m (covers the full scale)

third harmonic = 20 m * 2/3 = 13.33 m (covers 2/3 of the full scale)

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use equivalent ratios in higher terms to eliminate decimals from the following ratio 3.04 to 6 and ratio is ?​

Answers

The equivalent ratio in higher terms to eliminate decimals from the ratio 3.04 to 6 is 76 to 150.

To eliminate decimals from the ratio 3.04 to 6, we can multiply both terms of the ratio by a common factor that will result in whole numbers.

First, let's convert 3.04 to a fraction:

3.04 = 3 + 0.04 = 3 + 4/100 = 3 + 1/25 = 75/25 + 4/100 = 76/25

Now, the ratio 3.04 to 6 can be written as:

3.04/6 = 76/25 / 6

To eliminate the decimal, we can multiply both the numerator and denominator by 25:

(76/25) * 25 / (6 * 25) = 76 / 150

Therefore, the equivalent ratio in higher terms to eliminate decimals from the ratio 3.04 to 6 is 76 to 150.

By multiplying both terms by 25, we effectively scale up the ratio to eliminate the decimal and create whole numbers. This allows us to express the ratio in higher terms without decimals. The final ratio 76 to 150 represents the same relationship as the original ratio 3.04 to 6, but in whole number form.

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Write a hypothesis about how the mass of the cylinder affects the temperature of the water. Use the "if . . . then . . . because . . .” format and be sure to answer the lesson question: "How is potential energy converted to thermal energy in a system?”

Answers

Hypothesis, If the mass of the cylinder increases, then the temperature of the water will also increase because an increase in mass leads to greater potential energy, which is converted to thermal energy in the system.

According to the principle of conservation of energy, energy cannot be created or destroyed but can be transformed from one form to another. In this case, potential energy from the mass of the cylinder can be converted into thermal energy in the system. When the cylinder is lifted and submerged in the water, it possesses gravitational potential energy due to its elevated position.

As the cylinder is released and descends into the water, this potential energy is converted into kinetic energy, causing the water molecules to move and collide with higher energy. These collisions generate heat and increase the overall temperature of the water. By increasing the mass of the cylinder, more potential energy is stored.

As a result, there is a greater amount of energy available to be converted into thermal energy when the cylinder is released into the water. Thus, the temperature of the water is expected to increase as the mass of the cylinder increases.

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plzzz help will give brainlist

Below are views related to education.

---------------------------

Civics should be taught in public schools.
Good citizenship is learned in communities.
---------------------------

Which conclusion can be drawn from these views?

A. Civic involvement is important to building strong societies.

B. Civic participation should be learned at home.

C. Political conflict is a threat to strong societies.

D. Political conflict should be reduced through legislation.

Answers

Answer:

A.

Explanation:

this would make sense but it seems to be more like they both sound different

Calculate the force between charges of 55 × 108 C and 1 × 107C if they are 5

cm apart.?​

Answers

First:

5 cm = 0,05 m

Now, the formula:

F = k * (qq') / r²

Replacing:

F = 9x10⁹ * (55x10⁸ * 1x10⁷) / 0,05²

F = 9x10⁹ * (5,5x10¹⁶ / 2,5x10⁻³)

F = 9x10⁹ * 2,2x10¹⁹

F = 1,98x10²⁹

The force between the charges is 1,98x10²⁹ Newtons.

Catastrophes, significant life changes and sleep were the three examples provided in
the video that lead to stress?
True
False

Answers

The statement is False that Catastrophes, significant life changes and sleep were the three examples provided in the video that lead to stress.

What does catastrophe stress look like?

disastrous stress .Serious sickness in the child or a family member, natural disasters, and child maltreatment are a few instances of this level of stress. The child's risk is at its maximum at this level.

What three stages of the body's reaction to stress are there?

The alarm reaction stage, the resistance stage, and the weariness stage are the several phases of this illness. The "fight or flight" response and the body's earliest signs of acute stress are referred to as the alarm reaction stage.

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2. The following diagram shows a metal ball and ring apparatus. The ring and ball are both made of brass. At room temperature, the ball is just the right size to pass through the ring. When the ball is heated, it is unable to pass through the ring. Which of the following is NOT true? A The volume of the ball increased. B The mass of the ball increased. C. The speed at which the particles move increased. D The spaces between the particles increased. Not True

Answers

The statement that is NOT true is "the spaces between the particles increased.

option D.

What is effect of temperature on volume?

If we consider the solids and liquids, when the temperature increases the molecules gain energy and start moving in all directions. This expands the substance and the volume of the substance increases.

Similar, when the ball is heated, the volume of the ball increases due to thermal expansion.

As the temperature increases, the average kinetic energy of the particles within the ball also increases, causing them to move faster.

However, the spaces between the particles do not necessarily increase. In fact, the expansion of the ball occurs due to the particles themselves moving farther apart, but the intermolecular spacing within the ball remains relatively constant.

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How long has tension been building in the cascadia fault zone

Answers

Answer:

The Cascadia Subduction Zone has not produced an earthquake since 1700 and is building up pressure where the Juan de Fuca Plate is subsiding underneath the North American plate.

Explanation:

At depths shallower than 30 km (19 mi) or so, the Cascadia zone is locked by friction while stress slowly builds up as the subduction forces act, until the fault's frictional strength is exceeded and the rocks slip past each other along the fault in a megathrust earthquake. Below 30 km (19 mi) the plate interface exhibits episodic tremor and slip .

1. A) If the radius of a cylinder increases by a factor of 2.73, by what factor does the volume change? Assume that the height of the cylinder stays the same.​

Answers

The new volume of the cylinder will increase by a factor of 7.453.

What is the volume of a cylinder?

The volume of a cylinder is calculated by applying the following equation as shown below.

V  = πr²h

where;

r is the radius of the cylinderh is the height of the cylinder

when the radius increases by a factor of 2.73, the new volume will become;

V = π(2.73r)²h

V = 7.453 πr²h

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The bond order for a single covalent bond is.
A. two
B. four
C. one
D. three

Answers

Answer:

I think it should be C, which is one

You are working as an electrical technician. One day, out in CR the field, you need an inductor but cannot find one. Look- ing in your wire supply cabinet, you find a cardboard tube with single-conductor wire wrapped uniformly around it to form a solenoid. You carefully count the turns of wire and find that there are 580 turns. The diameter of the tube is 8.00 cm, and the length of the wire-wrapped portion is 36.0 cm. You pull out your calculator to determine (a) the inductance of the coil and (b) the emf generated in it if the current in the wire increases at the rate of 4.00 A/s.

Answers

Answer:

a. 5.901x10⁻³H

b. 2.36x10⁻²V

Explanation:

a. inductance of coil

we calculate the inductance of coil using this formula

L = N²μπA/λ

= [N²μπd²/4]/λ

we substitute values

L = 580² x 4πx10⁻⁷ x π(8x10⁻²)²/ 4x0.36

L = 336400 x 0.000001257 x 0,020096/1.44

L = 0.005901

= 5.901x10⁻³H

b. EMF

|e| = Ldi/dt

= 0.005901 * 4.00

= 0.023604

= 2.36x10⁻²V

17 points
A cannon fires a cannonball as shown in the diagram. Calculate the
velocity of the cannonball. *
M=500 kg
V=-3 m/s
m=10kg
v=?
A. 0.06 m/s
B. 150 m/s
C. 300 m/s
D. 1667 m/s

Answers

The velocity of the cannonball is 150 m/s,  the right option is B. 150 m/s.

The question can be solved, using Newton's second law of motion.

Note: Momentum of the cannon = momentum of the cannonball.

Formula:MV = mv................. Equation 1

Where:M = mass of the cannonm = mass of the cannonballV = velocity of the cannonv = velocity of the cannonball

Make v the subject of the equation.

v = MV/m................ Equation 2

From the question,

Given: M = 500 kgV = 3 m/sm = 10 kg.

Substitute these values into equation 2.

v = (500×3)/10v = 150 m/s.

 

Hence, The velocity of the cannonball is 150 m/s,  the right option is B. 150 m/s.

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A penny sinks to the bottom of a wishing well
What type of frictional force is that?

Answers

The frictional force involved when a penny sinks to the bottom of a wishing well is primarily due to viscous drag or fluid friction. As the penny moves through the water, it experiences resistance from the surrounding fluid. This resistance is caused by the frictional forces between the water molecules and the penny's surface.

A man whose mass is 69 kg and a woman whose mass is 52 kg sit at opposite ends of a canoe 5 m long, whose mass is 20 kg. Suppose that the man moves quickly to the center of the canoe and sits down there. How far does the canoe move in the water

Answers

Answer:

the canoe moved 1.2234 m in the water

Explanation:

Given that;

A man whose mass = 69 kg

A woman whose mass = 52 kg

at opposite ends of a canoe 5 m long, whose mass is 20 kg

now let;

x1 = position of the man

x2 = position of canoe

x3 = position of the woman

Now,

Centre of mass = [m1x1 + m2x2 + m3x3] / m1 + m2 + m3

= ( 69×0 ) + ( 52×5) + ( 20× 5/2) / 69 + 52 + 20

= (0 + 260 + 50 ) / ( 141 )

= 310 / 141

= 2.19858 m

Centre of mass is 2.19858 m

Now, New center of mass will be;

52 × 2.5 / ( 69 + 52 + 20 )

= 130 / 141

= 0.9219858 m  { away from the man }

To get how far, the canoe moved;

⇒ 2.5 + 0.9219858 - 2.19858

= 1.2234 m

Therefore, the canoe moved 1.2234 m in the water

The canoe move in the water will be 1.2234 m. The canoe move depending on the center of mass of the bodies.

What is the center of mass?

The center of mass of an item or set of objects is a place specified relative to it. It's the average location of all the system's components, weighted by their mass.

The centroid is the location of the center of mass for simple rigid objects with homogeneous density. The center of mass of a uniform disc shape, for example, would be at its center.

The given data in the problem is;

m₁ is the mass of man = 69 kg

m₂ is the mass of woman whose= 52 kg

m₃ is the mass  of  canoe =  20 kg

L is the length of canoe = 5 m

x₁ is the position of the man

x₂ is the position of the canoe

x₃ is the position of the woman

The center of mass will be;

\(\rm COM= \frac{[m_1x_1 + m_2x_2 + m_3x_3]}{ m1 + m2 + m3} \\\\ \rm COM= \frac{[69 \times 0 +52 \times 5 + 20 \times 2.5]}{ 69+ 52 + 20} \\\\ \rm COM= (0 + 260 + 50 ) / ( 141 )\\\\ \rm COM = 310 / 141 \\\\ \rm COM = 2.19858 m\)

The new center of mass is;

\(\rm COM= \frac{52 \times 2.5 }{69+52+20} \\\\ \rm COM=\frac{130}{141} \\\\ \rm COM= 0.9219 m\)

The distance to find how the canoe moved will be found by;

\(\rm x= 2.5+0.9219-2.1985 = 1.2234\)

Hence the canoe move in the water will be 1.2234 m.

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Three identical 6.39 x 10-4 Ccharges are on the corners ofan equilateral triangle of side3.35 m. Find the magnitude ofthe net force on 93.9291(Make sure you know the direction of each force!Remember, equilateral triangles have 60 degree interiorangles.)93

Three identical 6.39 x 10-4 Ccharges are on the corners ofan equilateral triangle of side3.35 m. Find

Answers

Given:

• Number of identical charges = 3

,

• Charge, q1 = q2 = q3 = 6.39 x 10⁻⁴ C.

,

• Length of each side of the triangle, d = 3.35 m

,

• θ = 60 degrees

Let's find the magnitude of the net force on q3.

For forces acting on q3 due to q1 and q2, apply the formula:

\(\begin{gathered} F=\frac{kq_1q_2}{d^2} \\ \\ F=\frac{9\times10^9*(6.39\times10^{-4})*(6.39\times10^{-4})}{3.35^2} \\ \\ F=\frac{3674.889}{11.2225} \\ \\ F=327.46\text{ N} \end{gathered}\)

The magnitude of net force on all 3 charges will also be equal.

Now, to find the magnitude of the net force acting on q3, apply the formula:

\(\begin{gathered} F_{net}=\sqrt{F^2+F^2+2F^2cos\theta} \\ \\ F_{net}=\sqrt{2F^2+2F^2cos\theta} \end{gathered}\)

Thus, we have:

\(\begin{gathered} F_{net}=\sqrt{2(327.46)^2+2(327.46)^2cos60} \\ \\ F_{net}=\sqrt{214460.1032+214460.1032(0.5)} \\ \\ F_{net}=\sqrt{214460.1032+107230.0516} \\ \\ F_{net}=\sqrt{321690.1548} \\ \\ F_{net}=567.18\text{ N} \end{gathered}\)

Therefore, the magnitude of net force acting on charge 3 is 567.18 N.

• ANSWER:

567.18 N

A circuit with 220 voltage is supplied with a fuse of 10 ampere.How many bulbs of 100 watt can be safely used in the circuit​

Answers

11 !

Explained below

let the number of bulbs-n

power=potential difference* current

n * 100 = 220* 5

n = 220*5/100 = 11

11 bulbs can safely used with 5 Ampere fuse.

What do you think the flat fee amount is? Explain how you decided your answer.

Answers

Answer:

I think that a flat fee amount is an amount that is charged or paid that does not change according to the amount of work done, or the number of times something is used

Explanation:

i could be wrong and if i am , i am truly sorry :(

Suppose a 0.3-kg mass on a spring that has been compressed 0.10 m has elastic potential energy of 1 J. What is the spring constant?
a. 10 N/m
b. 20 N/m
c. 200 N/m
d. 300 N/m

Answers

The spring constant of the spring is 200 N/m.

option C.

What is the spring constant of the spring?

The spring constant of the spring is calculated  by applying the following formula as shown below;

.

Mathematically, the formula for energy stored in a spring is given as;

U = ¹/₂kx²

where;

k is the spring constantx is the extension of the spring

k = ( 2U ) / ( x² )

k = ( 2 x 1 J ) / ( 0.1 m )²

k = 200 N/m

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A 0.0400 kg meter stick is placed on a thin rod at the 30.0 cm mark. What is the minimum mass required to be placed on the 0.00 cm mark on the stick to maintain equilibrium?

Answer in kg

Answers

The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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What is the total current in a parallel circuit containing a 12-V battery, a 2 Ω resistor, and a 4 Ω resistor?

Answers

Answer:

V=IR

since the circuit is parallel both resistor have same voltage and different current value according to OHMs law.

total resistance in parallel=

1/R=1/R1+1/R2+...+1/Rn

since we have two resistor in parallel

Rt=R1R2/R1+R2

2*4/2+4=4/3 ohms

I=V/R

12/4/3=36/4=9Amp

OR

I=12/2=6amp

I=12/4=3amp

total current

I=6+3

9amp

D
5. Mariam driving at a speed of 20.0 m/s applies
brakes close to a signal and travels a distance of
200 m before coming to rest. What was her
acceleration?
A. -0.50 m/s2
B. -0.70 m/s2
C. -1.00 m/s2
D. -2.00 m/s2
6. A trollen at rest is nushed to accelerate at a

Answers

Answer:

maibi.... D

Explanation:

I think is D

Please can someone help?​

Please can someone help?

Answers

first part.)

The anomalous result is likely the resistance of 50.0 cm of wire, which is significantly higher than the adjacent values.

second part.)

The most likely cause of the anomalous result would be a reading that was  too low from the ammeter.

What is an ammeter?

An ammeter is described as an instrument used to measure the current in a circuit.

The cause of the anomalous result is most likely an experimental error, arising from  faulty or misread measurement from ammeter.

It is less possible that the wire itself was damaged or flawed because there were consistent values for the adjacent lengths of wire.

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You throw a ball into the air. Which two forces cause the ball to gradually stop moving upward and then fall back to Earth?


A.

Balanced forces

B.

Friction

C.

Normal force

D.

Gravitational force


will mark brainliest

Answers

Answer: Gravitational Forces

Explanation:

A motorcycle, travelling cast, starts from rest, moves in a straight line with a constant acceleration and covers a distance of 64 m in 4 s.Calculate a) Its acceleration b) Its final velocity c) At what time the motorcycle had covered half the total distance d) What distance the motorcycle had covered in half the total time.​

Answers

The motorcycle had covered a distance of 16 meters in half the total time.

a) To calculate the acceleration, we can use the formula:

a = (v - u) / t

where a is the acceleration, v is the final velocity, u is the initial velocity (which is 0 since the motorcycle starts from rest), and t is the time.

Given:

u = 0 m/s (initial velocity)

v = ? (final velocity)

t = 4 s (time)

s = 64 m (distance)

Using the equation of motion:

s = ut + 1/2at^2

We can rearrange the equation to solve for acceleration:

a = 2s / t^2

a = 2(64) / (4)^2

a = 128 / 16

a = 8 m/s^2

Therefore, the acceleration of the motorcycle is 8 m/s^2.

b) To find the final velocity, we can use the formula:

v = u + at

v = 0 + (8)(4)

v = 32 m/s

Therefore, the final velocity of the motorcycle is 32 m/s.

c) To determine the time at which the motorcycle had covered half the total distance, we divide the total distance by 2 and use the formula:

s = ut + 1/2at^2

32 = 0 + 1/2(8)t^2

16 = 4t^2

t^2 = 4

t = 2 s

Therefore, the motorcycle had covered half the total distance at 2 seconds.

d) To calculate the distance covered in half the total time, we use the formula:

s = ut + 1/2at^2

s = 0 + 1/2(8)(2)^2

s = 0 + 1/2(8)(4)

s = 0 + 16

s = 16 m

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Which of the following best describes electromagnetic waves?
• A. Electromagnetic waves cause particles in a medium to vibrate
parallel to the direction of wave travel.
• B. Electromagnetic waves are produced by a disturbance in a
medium.
• C. Electromagnetic waves cause particles in a medium to vibrate
perpendicular to the direction of wave travel.

D. Electromagnetic waves are produced by a disturbance in electric a
and magnetic fields.

Answers

Electromagnetic waves are waves characterized by oscillating coupled electric and magnetic fields (electromagnetic fields). Because these are waves, they are shown to exhibit wave phenomena such as diffraction, reflection, and transmission, much like other types of waves.

The best description looks like option D

When a 2.50 - kg object is hung vertically on a certain light spring described by Hooke’s law, the

spring stretches 2.76 cm. (a) What is the force constant of the spring? (b) If the 2.50 - kg object is

removed, how far will the spring stretch if a 1.25 - kg block is hung on it? (c) How much work must

an external agent do to stretch the same spring 8.00 cm from its unstretched position?​

Answers

The work done in the spring is calculated to be 2.8 J

What is Hooke's law?

Hooke's law states that, the extension of a given material is directly proportional to the applied force as long as the elastic limit is not exceeded . First, we must bear in mind that the material must remain within the elastic limit for us to apply the Hooke's law in solving the problem.

Now;

From Hooke's law;

F = Ke

F = force applied

K = force constant

e = extension

F = W = mg =  2.50 - kg * 9.8 m/s^2 = 24.5 N

K = 24.5 N/ 2.76 * 10^-2

K = 888 N/m

e = F/K

F = W =  1.25 - kg * 9.8 m/s^2 = 12.25 N

e = 12.25 N/ 888 N/m = 0.014 m or 1.4 cm

Work done by an external agent = 1/2 Kx^2

= 0.5 * 888 * (8 * 10^-2)^2

= 2.8 J

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Must physics always be explained by math?

Answers

Answer:

Because Physics is mainly composited of math

Explanation:

If you really think about it the only way any science works is off maths, whether that be measuring the amount of NaOH to put into a solution or determening the amount of sugar you want in a cake it all relys on maths

If it requires 3 J of work to move a charge of 0.5 C through an unknown voltage, what is the magnitude of the voltage?

If it requires 3 J of work to move a charge of 0.5 C through an unknown voltage, what is the magnitude

Answers

Given that the work done is W = 3 J.

The charge given is q = 0.5 C

We have to find the voltage.

The voltage can be calculated by the formula

\(V\text{ = }\frac{W}{q}\)

Substituting the values, the voltage will be

\(\begin{gathered} V=\text{ }\frac{3}{0.5} \\ \text{ = }6\text{ V} \end{gathered}\)

Thus, the magnitude of voltage is 6 V

Other Questions
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