Can someone help me please What happens as if I spin the magnet several time? Putting the magnet in the loops and click the magnet flip button

Can Someone Help Me Please What Happens As If I Spin The Magnet Several Time? Putting The Magnet In The

Answers

Answer 1

In the given configuration we have a magnet and a loop} of wire connected to a light bulb.

The magnet produces a constant magnetic field which is represented by the field lines.

When the magnet poles are flipped the magnetic field changes accordingly. Now, we need to consider Faraday's law or the Law of Induction. This means that when there is a changing magnetic field in a loop, an electromagnetic force will be induced inside the loop. This electromagnetic force will generate a current that in turn will turn the light bulb on.

Therefore, by flipping the magnet inside the loop the light bulb will turn on.


Related Questions

A girl with a mass of 32 kg is playing on a swing. There are three main forces
acting on her at any time: gravity, force due to centripetal acceleration, and
the tension in the swing's chain (ignore the effects of air resistance). At the
instant shown in the image below, she is at the bottom of the swing and is
traveling at a constant speed of 4 m/s. What is the tension in the swing's
chain at this time? (Recall that g = 9.8 m/s²)
Tension
Weight
A. 333.6 N
OB. 817.8 N
C. 562.8 N
D. 441.6 N
4 m/s

A girl with a mass of 32 kg is playing on a swing. There are three main forcesacting on her at any time:

Answers

The tension in the swing's chain at the instant shown in the image is 441.6 N.

option D

What is the tension at bottom swing?

At the bottom of the swing, the girl is traveling at a constant speed, so her acceleration is zero. Therefore, the net force acting on her is also zero.

Thus, we have:

0 = T - mg - mv²/r

where;

T is the tension in the swing's chain, m is the girl's mass, g is the acceleration due to gravity, v is her speed, and r is the radius of the swing.

At the bottom of the swing, the radius is equal to the length of the chain, so we have:

r = L = 4.0 m

Substituting the values we have:

T = (32 kg)(9.8 m/s²) + (32 kg)(4 m/s)²/4.0 m

Solving for T, we get:

T = (32 kg)(9.8 m/s²) + (32 kg)(4 m/s)²/4.0 m

T = 441.6 N.

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Two objects are interacting but stay stationary. Which best describes what is happening to he action and reaction forces

Answers

Answer: B

Explanation: The forces are equal and opposite each other.

When two objects are interacting but stay stationary, then the forces are equal and opposite each other.

What do you mean by Force?

Force may be defined as the process of pushing and pulling an object with an actual mass that stimulates its velocity to be changed.  It is a type of vector quantity because it has both magnitude and direction.

It is the simple and fundamental concept of physics that when two or more objects are interacting with one another but do stimulate any change in their position, the forces among them are definitely equal and opposite to one another. It is the most plausible explanation of Newton's third law of motion.

Therefore, when two objects are interacting but stay stationary, then the forces are equal and opposite each other.

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Your question seems incomplete. The most probable complete question is as follows:

The forces are equal and opposite each other. The forces are not equal and opposite to each other. The forces are equal but not opposite to each other.The forces are not equal but opposite to each other.

A.005kg bullet going 200m/s, hits a .995kg block of wood, what is the final speed of the bullet and wood as they fly off together? ​

Answers

Answer:

Given :  

m 1 =0.5 kg        

u 1 =0 m/s                    

m 2=0.005 kg      

u 2=200 m/s              

Let the velocity acquired by the block after the collision be V.

Using conservation of linear momentum before and after the collision :    P i =P f

​∴    m1u 1 +m 2u 2=(m 1+m 2 )V

OR    

0.5×0+0.005×200=(0.5+0.005)V              

⟹V≈1.9  m/s

Answer:

V= 1.9  m/s

Explanation:

I did the test

Hope this helps :)

the image below shows how the temperature of 10 g of ice changes as energy is added. which statement is correct?

Answers

The correct statement is the water absorbed energy continuously, but the temperature increased only when all of the water was in one phase.

this is explained by the latent heat of fusion. The melting point of ice ( at which ice melts into water) is 0 degree Celcius. This temperature remains constant till all 10 g of ice melts completely and water comes in the same phase of liquid.

The latent heat of fusion, also known as enthalpy of fusion, is defined as the total amount of heat energy supplied to a solid substance to start a change in its physical state from a solid to a liquid state. Given the pressure of the environment is constant.

The correct option is (b).

The given question is incomplete, the complete question is

The image below shows how the temperature of 10 g of ice changes as energy is added. which statement is correct?

(a) The water absorbed energy continuously and temperature increases while water is changing phase.

(b) The water absorbed energy , but the temperature increased only when all of the water was in one phase.

(c) Temperature of the water remained constant.

(d) Temperature always increases.

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the fact that entropy is always increasing is demonstrated by

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The fact that entropy is always increasing is demonstrated by several everyday examples, such as ice melting, clocks running down, dead organisms decaying, and mountains crumbling.

The second law of thermodynamics, which states that the entropy of an isolated system will always increase over time. Entropy is a measure of disorder or randomness in a system, and the second law states that in any natural process, the entropy of a system will always increase or stay the same. This means that energy will always flow from a higher state of organization to a lower state of organization, and that systems will naturally tend towards a state of maximum disorder.

ThIs is demonstrated by many everyday examples, such as the fact that ice melting will not reassemble itself, clocks running down will not get back itself to the previous time, or dead organisms decaying  will not assemble itself back in the complete form.

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compare and contrast speed and velocity.​

Answers

Speed is the time rate of an object moving from one place to another, while velocity is the rate and direction of the object's movement. They are very similar but they don't mean the same thing.

A child on a tricycle is moving at a speed of 1.40 m/s at the start of a 2.25 m high and 12.4 m long incline. The total mass is 48.0 kg, air resistance and rolling resistance can be modeled as a constant friction force of 41.0 N, and the speed at the lower end of the incline is 6.50 m/s. Determine the work done (in J) by the child as the tricycle travels down the incline.

Answers

Answer:

The work done by the child as the tricycle travels down the incline is 416.96 J

Explanation:

Given;

initial velocity of the child, \(v_i\) = 1.4 m/s

final velocity of the child, \(v_f\) = 6.5 m/s

initial height of the inclined plane, h = 2.25 m

length of the inclined plane, L = 12.4 m

total mass, m = 48 kg

frictional force, \(f_k\) = 41 N

The work done by the child is calculated as;

\(\Delta E_{mech} = W - f_{k} \Delta L\\\\W = \Delta E_{mech} + f_{k} \Delta L\\\\W = (K.E_f - K.E_i) + (P.E_f - P.E_i) + f_{k} \Delta L\\\\W = \frac{1}{2} m(v_f^2 - v_i^2) + mg(h_f - h_i) + f_{k} \Delta L\\\\W = \frac{1}{2} \times 48(6.5^2 - 1.4^2) + 48\times 9.8(0-2.25) + (41\times 12.4)\\\\W = 966.96 \ - \ 1058.4 \ + \ 508.4\\\\W = 416.96 \ J\)

Therefore, the work done by the child as the tricycle travels down the incline is 416.96 J

Why the tyres are in circular shape?

Answers

The circular shape allows the tire to roll easily with the least amount of bumps or jolts

How does the period of a wave change if the frequency increases by a factor of three?

Answers

Answer:

Period becomes 1/3 of the original

Explanation:

Period = 1/f      if f becomes 3f   then period becomes 1/3 of the original

Sone one explain equilibrium to me what is it​

Answers

Answer:

In econ: When supply and Demand are equal

Explanation:

Equilibrium is when something evens out

One statement of the first law of thermodynamics is that:___________.
a. the amount of work done on a system is dependent of pathway.
b. the total work done on a system must equal the heat absorbed by the system.
c. the heat flow in or out of a system is independent of pathway.
d. the total energy flow in or out of a system is equal to the sum of the heat transferred to or from the system and the work done by or on the system.
e. in any chemical process the heat flow must equal the change in enthalpy.

Answers

Answer:

a. the amount of work done on a system is dependent of pathway

Explanation:

The first law of thermodynamics states that the change in internal energy of a system equals the net heat transfer into the system minus the net work done by the system.

ΔU = Q - W

Where;

Q, the net heat transfer into the system depends on the pathway

W, the net work done by the system also depends on the pathway

But, ΔU, the change in internal energy is independent of pathway

Therefore, the correct option is "A"

a. the amount of work done on a system is dependent of pathway

A police car in hot pursuit goes speeding past you. While the siren is approaching, the frequency of the sound you hear is 5500 Hz. When the siren is receding away from you, the frequency of the sound is 4500 Hz. Use the Doppler formula to determine the velocity of the police car. Use vsound=330 m/s.
What is the velocity v of the police car ?

Answers

Vs = 34m/s
I don’t have an explanation my apologies.

When a police car in hot pursuit goes speeding past you, the velocity v of the police car is 33 m/s.

What is the Doppler formula?

The formula is used when there exists a Doppler shift. The Doppler shift is due to the relative motion of sound waves between the source and observer.

The frequency increase by the Doppler effect is represented by the formula

f' = \(\dfrac{v-v_{o} }{v-v_{s} }\)× f

Given the frequency of source f' is 5500 Hz . Velocity of the observer v₀  is 0.

Substituting the value into the equation will give us the velocity of the police car.

\(5500 = \dfrac{330}{330-v} \times f\)...........(1)

When the car is receding, the frequency of the receiving signal f = 4500 Hz.

\(4500 = \dfrac{330}{330+v} \times f\)..........(2)

Solving both equation, we get the velocity of a police car.

v = 33 m/s

Therefore, the velocity v of the police car is 33 m/s.

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Mastering Problems
57. Ranking Task Rank the following objects according
to the magnitude of the acceleration, from least to
greatest. Specifically indicate any ties,
A. A falling acorn accelerates from 0.50 m/s to
10.3 m/s in 1.0 s.
B. A car accelerates from 20 m/s to rest in 1.0 s.
C. A centipede accelerates from 0.40 cm/s to 2.0 cm/s
in 0.50 s.
D. While
being hit, a golf ball accelerates from rest to
4.3 m/s in 0.40 s.
E. A jogger accelerates from 2.0 m/s to 1.0 m/s in 8.3 s.

Answers

Answer:

C , E , A , D , B

Explanation:

We evaluate the accelerations for each case, using the formula: a = (vf - vi) / t

A)  a = (10.3 - 0.5 ) / 1 = 9.8 m/s^2  --> magnitude: 9.8 m/s^2

B)  a = (0 - 20) / 1 = - 20 m/s^2  -->  magnitude : 20 m/s^2

C)  a = (0.02 - 0.004) / 1 = 0.016 m/s^2 -->  magnitude : 0.016  m/s^2

D)  a = (4.3 - 0) / 0.4 = 10.75 m/s^2  -->  magnitude : 10.75 m/s^2

E)  a = (1 - 2) / 8.3 = - 0.12 m/s^2  -->  magnitude: 0.12 m/s^2

Then, comparing magnitudes from least to greatest:

C , E , A , D , B

The order of the magnitude of the acceleration, from least to greatest is:

C < E < A < D < B

In physics, acceleration (a) is the rate at which velocity changes (Δv) with time (t).

We will calculate the acceleration for each scenario using the following expression.

\(a = \frac{v-u}{t}\)

where,

u: initial velocityv: final velocity

A. A falling acorn accelerates from 0.50 m/s to 10.3 m/s in 1.0 s.

Data

u: 0.50 m/sv: 10.3 m/st: 1.0 s

\(a = \frac{10.3m/s-0.50m/s}{1.0s} = 9.8 m/s^{2}\)

B. A car accelerates from 20 m/s to rest in 1.0 s.

Data

u: 20 m/sv: 0 m/s (rest)t: 1.0 s

\(a = \frac{0m/s-20m/s}{1.0s} = -20 m/s^{2}\\\\|a| = 20 m/s^{2}\)

C. A centipede accelerates from 0.40 cm/s to 2.0 cm/s in 0.50 s.

Data

u: 0.40 cm/sv: 2.0 cm/st: 0.50 s

\(a = \frac{2.0cm/s-0.40cm/s}{0.50s} = 3.2cm/s^{2} \times \frac{1m}{100cm} = 0.032 m/s^{2}\)

D. While being hit, a golf ball accelerates from rest to 4.3 m/s in 0.40 s.

Data

u: 0 m/s (rest)v: 4.3 m/st: 0.40 s

\(a = \frac{4.3m/s-0m/s}{0.40s} = 11 m/s^{2}\)

E. A jogger accelerates from 2.0 m/s to 1.0 m/s in 8.3 s.

Data

u: 2.0 m/sv: 1.0 m/st: 8.3 s

\(a = \frac{1.0m/s-2.0m/s}{8.3s} = -0.12 m/s^{2}\\\\|a| = 0.12 m/s^{2}\)

The order of the magnitude of the acceleration, from least to greatest is:

C < E < A < D < B

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A speed skater just finished a race. After she crossed the finish line, she coasted to a complete stop. If her initial speed was 13.0 m/s and her acceleration was -2.9 m/s2, how long did it take her to stop?

Answers

Answer:

5seconds

Explanation:

because she was going through the same time

A 615 N student standing on a scale in an elevator notices that the scale reads 645 N. From this information, the student knows that the elevator must be moving Group of answer choices You cannot tell if it is moving upward or downward. upward. downward.

Answers

Answer:

The elevator must be moving upward.

Explanation:

During the motion of an elevator, the weight of the person deviates from his or her actual weight. This temporary weight during the motion is referred to as "Apparent Weight". So, when the elevator is moving downward, the apparent weight of the person becomes less than his or her actual weight.

On the other hand, for the upward motion of the elevator, the apparent weight of the person becomes more than the actual weight of that person.

Since the apparent weight (645 N) of the student, in this case, is greater than the actual weight (615 N) of the student.

Therefore, the elevator must be moving upward.

Robert, my neighbor, a forty-five-year-old blacksmith is seven feet tall, and eats all day long. What does he weigh?

Answers

The neighbour weighs Iron. As he is a blacksmith, iron is the only thing he weighs the whole day.

What is a riddle?

A riddle is a statement, question or phrase having a double or veiled meaning, put forth as a puzzle to be solved.

If Robert, your neighbor, a forty-five-year-old blacksmith is seven feet tall, and eats all day long, based on these statements, we can explain the riddle as Robert weighs iron for the fact that he  is a blacksmith, iron is the only thing he weighs the whole day.

Thus, the correct explanation for the riddle is " The neighbour weighs Iron. As he is a blacksmith, iron is the only thing he weighs the whole day.

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what does mercaptan smell like?

Answers

Answer:

its been said that is smells like rotten eggs or rotten cabbage.

Explanation:

Depending on the makeup of your olfactory senses, Ethyl Mercaptan most often is reported to smell like rotten eggs or sometimes rotten cabbage. Some also say it has a strong garlic, or skunk-like, smell

Answer: Depending on the makeup of your olfactory senses, Ethyl Mercaptan most often is reported to smell like rotten eggs or sometimes rotten cabbage. Some also say it has a strong garlic, or skunk-like, smell.

Sunlight is composed of wavelengths of light that make up part of the electromagnetic spectrum. Towson University Exam Question. The frequency of a wave is directly proportional to the speed at which the wave is traveling. Do NOT Copy! Calculate the frequency (in Hz) of light at the following wavelength:

Answers

Answer:

\(f= 5.11 * 10^{10}Hz\)

Explanation:

Given

\(\lambda = 0.587cm\)

See comment for complete question

Required

Calculate the frequency

Frequency is calculated using:

\(f = \frac{c}{\lambda}\)

Where

\(c \to\) speed of light

\(c =299792458 ms^{-1}\)

\(\lambda = 0.587cm\)

Convert wave length to meters

\(\lambda = 0.587 * 0.01m\)

\(\lambda = 0.00587m\)

So, we have:

\(f = \frac{c}{\lambda}\)

\(f=\frac{299792458 ms^{-1}}{0.00587m}\)

\(f=\frac{299792458}{0.00587}Hz\)

\(f= 5.11 * 10^{10}Hz\)

A 1420-kg car moving east at 17.0 m/s collides with a 1880-kg car moving south at 15.0 m/s, and the two cars connect together.A. What is the magnitude of the velocity of the cars right after the collision? (m/s )B. What is the direction of the cars right after the collision? Enter the angle in degrees where positive indicates north of east and negative indicates south of east. (°)C. How much kinetic energy was converted to another form during the collision? (kJ)

Answers

Given,

The mass of the car moving east, m=1420 kg

The mass of the car moving south, M=1880 kg

The velocity of the car moving east, u₁=17.0 m/s

The velocity of the car moving south, u₂=-15.0 m/s

Here we assume that the eastward direction is the positive x-direction and the southward direction is the negative y-direction.

From the law of conservation of momentum, the momentum is conserved in both directions simultaneously and independently.

Considering the conservation of momentum in the x-direction,

\(mu_1=(m_{}+M)v_x\)

Where v_x is the x-component of the final velocity of the two cars.

On substituting the known values,

\(\begin{gathered} 1420\times17.0=(1420+1880)v_x \\ v_x=\frac{1420\times17.0}{(1420+1880)} \\ =7.32\text{ m/s} \end{gathered}\)

Considering the conservation of momentum in the y-direction,

\(Mu_2=(m+M_{})v_y\)

Where v_y is the y-component of the final velocity of the cars.

On substituting the known values,

\(\begin{gathered} _{}1880\times-15.0=(1420+1880)v_y \\ v_y=\frac{1880\times-15.0}{(1420+1880)} \\ =-8.55\text{ m/s} \end{gathered}\)

A.

The magnitude of the velocity of the cars tight after the collision is given by,

\(v=\sqrt[]{v^2_x+v^2_y}\)

On substituting the known values,

\(\begin{gathered} v=\sqrt[]{7.32^2+(-8.55)^2} \\ =11.26\text{ m/s} \end{gathered}\)

Thus the magnitude of the velocity of the cars right after the collision is 11.25 m/s

B.

The direction of the cars right after the collision is given by,

\(\theta=\tan ^{-1}(\frac{v_y}{v_x})\)

On substituting the known values,

\(\begin{gathered} \theta=\tan ^{-1}(\frac{-8.55}{7.32}) \\ =-49.4^{\circ} \end{gathered}\)

Thus the direction of the cars right after the collision is -49.4°. That is 49.4° south of the east.

C.

The total kinetic energy of the system is before the collision is

\(K_1=\frac{1}{2}mu^2_1+\frac{1}{2}Mu^2_2\)

On substituting the known values,

\(\begin{gathered} K_1=\frac{1}{2}\times1420\times17.0^2+\frac{1}{2}\times1880\times15.0^2 \\ =205.19\times10^3+211.5\times10^3 \\ =416.69\times10^3\text{ J} \end{gathered}\)

The kinetic energy of the system of two cars after the collision is,

\(\begin{gathered} K_2=\frac{1}{2}(m+M)v^2 \\ =\frac{1}{2}\times(1420+1880)11.26^2 \\ =209.2\times10^3\text{ J} \end{gathered}\)

Thus the kinetic energy lost during the collision is,

\(\Delta K_{}=K_1-K_2\)

On substituting the known values,

\(\begin{gathered} \Delta K=416.69\times10^3-209.2\times10^3 \\ =207.49\times10^3\text{ J} \\ \approx207.5\text{ kJ} \end{gathered}\)

Thus the total kinetic energy lost during the collision is 207.5 kJ

A split highway has a number of lanes for traffic. For traffic going in one direction, the radius for the inside of the curve is half the radius for the outside. One car, car A, travels on the inside while another car, car B, travels at equal speed on the outside of the curve. Which statement about resultant accelerations of the cars is correct

Answers

Answer:

The correct one is that the force on B is half of the force on A

Explanation:

Because radius for the inside of the curve is half the radius for the outside and Car A travels on the inside while car B, travels at equal speed on the outside of the curve. Thus force on B will be half on A

0.030 km
2. The Olympic record for the marathon is 2hr, 1min, 39s. Determine the average velocity in m/s and
miles per hour of the record.

Answers

0.0041m/s and 0.00917 mile/hr. is the average velocity.

If an object moves with an average speed of v for time t, then the distance traveled by this object is s= v.t

Average speed and time are given in the task. So you can use this formula to calculate the marathon distance.

Velocity or speed  is defined as: The rate of change of the object's position in any direction. Velocity is measured as the ratio of distance traveled and time traveled. Velocity is a scalar quantity because it has only direction and not magnitude.

time =2hr, 1min, 39s  s= 0.030km

t= 7299s    s=30m

v=s/t=30/7299

=0.0041m/s.

in mile per hour = 0.00917 mile/hr

So feom the above equations solved the answer is 0.0041m/s and 0.00917 mile/hr.

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An aeroplane left Benin to fly to Yola 600km away on a bearing 110° at an air speed 220km/h. If they is a steady wind of 35km/h from a bearing of 40°. What is the course of the aeroplane and the time taken to fly across?

Answers

(a) The course of the aeroplane is 234.3 km/h at 78⁰.

(b) The time  taken for the aeroplane to fly across is 2.5 hours.

What is the course of the aeroplane?

The course of the aeroplane is calculated as follow;

Total vertical velocity = 220 km/h x sin(110) + 35 km/h x sin (40)

Total vertical velocity = 229.23 km/h

Total horizontal velocity = 220 km/h x cos(110) + 35 km/h x cos (40)

Total horizontal velocity = -48.43 km/h

The resultant velocity of the aeroplane is calculated as;

v = √ ( 229.23² + ( -48.43)² )

v = 234.3 km/h

The direction of the aeroplane

θ = arc tan ( Vy / Vx )

θ = arc tan ( 229.23 / 48.43 )

θ = 78⁰

The time of motion of the aroplane is calculated as follows;

t = ( 600 km ) / ( 234.3 km/h )

t = 2.5 hours

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A ball is Thrown straight up with a speed of 30 M/S, and air resistance is negligible what is its velocity after 4.2s

Answers

Answer:

11.2 m/s

Explanation:

We need to first figure out how long it took to reach the ball's max height:

Vf = 0

Vi = 30 m/s

a = -9.81 m/s^2

t = ?

---------------

Vf = Vi + at

0 = 30 + (-9.81)t  --->  -30 = -9.81t  ---> 3.058 = t

t = 3.058 s

---------------

We can now solve the problem by subtracting the given time (4.2s) by the max height time (3.058s) and plugging that into a kinematic equation for Vf:

Vi = 0

a = 9.81 m/s^2

t = (4.2s - 3.058s) = 1.142 s

Vf = ?

---------------

Vf = Vi + at

Vf = 0 + (9.81)*(1.142)  ---> Vf = 11.203

---------------

The velocity of the ball after 4.2s is 11.2 m/s

what i have learned
complete the statements below. write your answers on a separate sheet of paper
even before the advent of the telescope ancient aastronomers were able to observe the following

Answers

Even before the advent of the telescope, ancient astronomers were able to observe the following:

1. Celestial Bodies: Ancient astronomers could observe celestial bodies such as the Sun, Moon, stars, and planets. They could track their movements across the sky and study their patterns and behaviors.

2. Solar and Lunar Eclipses: By carefully observing the positions of the Sun, Moon, and Earth, ancient astronomers could predict and witness solar and lunar eclipses. They noticed that during a solar eclipse, the Moon blocks the Sun's light, creating a temporary darkness on Earth, while during a lunar eclipse, the Earth casts a shadow on the Moon, causing it to appear reddish or darkened.

3. Stellar Positions: Ancient astronomers mapped and observed the positions of stars in the night sky. They recognized patterns and constellations, which helped them navigate and keep track of time.

4. Seasons and Celestial Movements: By observing the changing positions of the Sun and its daily and yearly motions, ancient astronomers could understand the changing seasons. They could determine solstices, equinoxes, and the length of days and nights.

5. Comet Appearances: Ancient astronomers were able to observe and document the appearance of comets in the night sky. They recognized these celestial objects as distinct from stars and noted their unusual and transient nature.

These observations formed the basis of ancient astronomy and laid the groundwork for the development of more advanced astronomical techniques and instruments, including the telescope.

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What is measurement???
knahi pani nepali ca jasto chaxenw​

Answers

Explanation:

The comparison of an unknown physical quantity with the known standard quantity is called measurement....

Here are some tho.....

A rectangular block of wood has dimensions 240mm×20.5cm×0.040m. calculate its volume in cm³.

Answers

Answer: 1968 cm3

Explanation: You first need to convert all of your dimensions to the same units.

240 mm = 24 cm

20.5 cm = 20.5 cm

0.04 m = 4 cm

Then volume is Length x width x height = 24 cm x 20.5 cm x 4 cm =

While diving in cancun Mexico where the seawater has a density of 1,015 kg/m3 Nana observed that her pressure meter device reading was 3.75 atm. The reading at sea level is standard 1.0 atm. At what depth is she diving when the meter read 3.75 atm g

Answers

Answer:

The depth of the diver is 28.01 m

Explanation:

Given;

density of the seawater, ρ = 1,015 kg/m³

standard sea level pressure, P₀ = 1.0 atm = 101,325 Pa

the final reading of her pressure, P₁ = 3.75 atm = 379968.75 Pa

acceleration due to gravity, g = 9.8 m/s²

Let the depth she was diving at the final pressure = h

This depth is calculated as;

P₁ = P₀  +  ρgh

P₁ - P₀ =  ρgh

\(h = \frac{ P_1 \ - \ P_o}{\rho g} = \frac{379968.75 \ - \ 101325}{1015 \ \times \ 9.8} = 28.01 \ m\)

Therefore, the depth of the diver is 28.01 m

URGENT HELP NEEDED!!!
Two spheres of molten rock, both moving in the positive y-direction, collide in space. One sphere has a mass of 660 kg and is moving at a velocity of 17 m/s. The other sphere has a mass of 970 kg, and is moving at a velocity of 24 m/s. When the two spheres collide, and become one unit, what will be their combined velocity?

21.2 m/s

24.0 m/s

41.0 m/s

20.5 m/s

Answers

Answer:

20.5 m/s

Explanation:

All of the following steps are included in a self-modification program except __________. A. specifying target behavior B. designing a program C. focusing on one goal at a time D. gathering data about target behavior
(Psychology)

Answers

Answer:

C)focusing on one goal at a time

Explanation:

Self-modification programs could be regarded as a program that help individual in managing unwanted as well as dysfunctional behavioral responses whenever they are going through a problem and try to deal with it. For instance the dysfunctional behavioral response for someone with a panic attack is avoidance. Some of the the steps that are involved in in a self-modification program are;

✓ specifying target behavior ✓designing a program

✓ gathering data about target behavior

Answer:

c

Explanation:

on edge 2020

pls help Wilhelm Wundt, the “father of psychology,” studied consciousness using introspection. How was this introspection MOST likely demonstrated?

a.His subjects were hooked up to machines to read their brain waves.

b.His subjects examined and shared their own feelings and thoughts.

c.His subjects lived their day-to-day lives, and Wundt observed their actions.

d.His subjects were watched while they were sleeping to map their REM sleep.

Answers

Wundt studies consciousness using introspection because his subjects examined and shared their own feelings and thoughts. Wundt was the first psychologist.

Introspection refers to the examination of one's own mental and/or emotional mechanisms and processes.

Wilhelm Wundt was a distinguished psychologist who demonstrated that introspection is a highly practiced mechanism of self-examination.

W. Wundt developed the theory of conscious thought by indicating that conscious mental states can be scientifically (empirically) studied by using introspection.

Learn more about Wilhelm Wundt here:

https://brainly.com/question/5286466

Answer: B His subjects examined and shared their own feelings and thoughts.

Explanation: Just took the test

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