can you describe your own perspective whats Physical Science all about? PLS GUYS HELP​

Answer:

   v_s = 34.269 m / s

Explanation:

This is a Doppler effect exercise, in this case the observer is fixed and the sound source is moving.

         f ’= f  \(\frac{v}{v \mp v_s }\)

where the negative sign is used for when the source approaches the observer and the positive sign for when the source moves away from the observer

In this case when f ’= 5500 Hz approaches and when f’ = 4500 Hz moves away, let's write the two expressions together

          5500 = f (\(\frac{v}{v - v_s }\))

          4500 = f ( \(\frac{v}{v + vs}\))

let's solve these two equations

           \(\frac{5500}{4500} = \frac{v+v_s}{v-v_s}\)

           1.222 (v-v_s) = v + v_s

            v_s (1+ 1.22) = v (1.222 -1)

            v_s = v   \(\frac{0.222}{2.223}\)

the speed of sound in air is v = 343 m / s

            v_s = 343 0.09990

             v_s = 34.269 m / s

Answer:

192.6N

Explanation:

Let's consider the forces acting on the beam:

Weight of the beam (W): It acts vertically downward and has a magnitude of W = mass * gravitational acceleration = 39.4 kg * 9.8 m/s^2.

Force exerted by the link on the beam (F_link): It acts at an angle of 90 degrees with respect to the beam and has two components: the vertical component and the horizontal component.

Tension in the cable (T): It supports the far end of the beam and acts at an angle of 90 degrees with respect to the beam. Since the angle between the beam and the cable is 90 degrees, the tension in the cable only has a vertical component.

Let's break down the forces acting on the beam:

Vertical forces:

W (weight of the beam) - T (vertical component of tension) = 0

T = W

Horizontal forces:

F_link (horizontal component of the force exerted by the link) = ?

To find the magnitude of the horizontal component of the force exerted by the link on the beam (F_link), we need to consider the equilibrium of forces in the horizontal direction.

Since the beam is inclined at an angle of θ = 33.1 degrees with respect to the horizontal, the horizontal equilibrium equation can be written as:

F_link = W * sin(θ)

Let's substitute the given values:

W = 39.4 kg * 9.8 m/s^2

θ = 33.1 degrees

F_link ≈ (39.4 kg * 9.8 m/s^2) * sin(33.1 degrees)

Using a calculator, we find that the magnitude of the horizontal component of the force exerted by the link on the beam (F_link) is approximately 192.6 N.

From the darkest part of the object's shadow, you would be able to see a small amount of the light source. There would be a small amount of light that is visible, but it would be faint. On the other hand, from the lightest part of the shadow, you would be able to see much more of the light source. The light source would be far brighter and more visible, and you would be able to identify the source of the light.

"The distance above the surface of the Earth at which the acceleration due to gravity is 0.980  is approximately 12 million meters or 12,000 kilometers."

To solve this problem, we need to use the formula for gravitational acceleration, which is: g =\(GM/r^2\) Where g is the acceleration due to gravity, G is the gravitational constant, M is the mass of the Earth, and r is the distance between the center of the Earth and the object. At the surface of the Earth, g = 9.80 \(m/s^2\), so we can set up the equation as: 9.80 = \((6.67 x 10^-11) * M / (6,371,000)^2\)

Where we use the radius of the Earth, 6,371,000 meters. Solving for M, we get: M = (\(9.80 * 6,371,000^2)\) / (\(6.67 x 10^-11\)) = 5.97 x \(10^24\)kg, Now we can use this value of M to find the distance at which the acceleration due to gravity is 0.980\(m/s^2\).

Setting up the equation again, we have: 0.980 = (\(6.67 x 10^-11\)) * (\(5.97 x 10^24\)) /\(r^2\) Solving for r, we get: r = sqrt((\(6.67 x 10^-11\)) * (\(5.97 x 10^24\)) / 0.980) = 1.20 x \(10^7\)meters

Therefore, the distance above the surface of the Earth at which the acceleration due to gravity is 0.980 \(m/s^2\) is approximately 12 million meters or 12,000 kilometers.

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Time of flight = 1.6 s

Horizontal distance = 64 m

Projectile motion is the form of motion experienced by an object or particle projected into a gravitational field, such as from the surface of the Earth, and moves along a curvilinear path only under the action of gravity.

For the given case,

h = vt + ¹/₂gt²

h = height of tower

v = initial velocity

t = time of flight

55 = 50sin30t + ¹/₂9.8t²

55 = 25t + 4.9t²

4.9t² + 25t - 55 = 0

t = 1.6 s

X = vₓt

X = horizontal distance

vₓ = horizontal velocity

t = time of flight

X =  (50 x cos30) x 1.6

X =  64 m

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The amplitude of the electric field will be =

According to the given question,

The given power rating of the bulb = 60 W

The given efficiency = 50%

The distance given = 2.0 m

Now if we consider a bulb we can see a spherical area of the same which is radiating electromagnetic energy,

The area could be written as,

⇒ A = 4\(\pi r^{2}\)

In the formula, r represents the distance that is = 2.0 m

⇒ A = 4 x \(\pi\) x r x r

⇒A = 4 x \(\pi\) x 2 x 2

⇒ A = 50.26 \(m^{2}\)

Now we will calculate the intensity at a distance of 2.0 m

⇒  \(\frac{POWER}{AREA}\)

⇒  \(\frac{100 * 0.50}{50.26}\)

⇒ 0.99

⇒ 1

We can now consider the formula containing permeability,

\(E_{rms} = \sqrt{\frac{I}{\alpha C} }\)

α = permeability = 8.85 x \(10^{-12}\)

C = speed of light in air = 3 x \(10^{8}\)

\(E_{rms} = \sqrt{\frac{1 * 10^{4} }{8.85 * 3} }\)

\(E_{rms} =\) \(\sqrt{37.66}\)

\(E_{rms} =\) 6.14 ( As the amplitude \(A^{2}\) = E )

Therefore, The amplitude of the electric field will be = 6.14

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The statement" The direction of the force on the charge placed in the electric field is upward" is false because the direction of the force on a negative charge (-6 C) placed in an upward-directed uniform electric field of magnitude 24 N/C would be downward.

The direction of the force on a charged particle placed in an electric field is determined by the charge of the particle and the direction of the electric field. In this case, a charge of -6 C is placed in an electric field directed upward with a magnitude of 24 N/C.

The force on a charged particle in an electric field can be calculated using the formula:

F = q * E

Where F is the force, q is the charge of the particle, and E is the electric field.

Since the charge q in this case is negative (-6 C) and the electric field E is directed upward, we can substitute the values into the formula:

F = (-6 C) * (24 N/C)

F = -144 N

The negative sign in the force value indicates that the force is in the opposite direction to the electric field. Therefore, the force on the charge placed in the electric field is downward, not upward.

The force on a negative charge is always opposite to the direction of the electric field. This is because negative charges experience an attractive force towards positive charges, and electric fields are directed from positive charges to negative charges.

Therefore, the statement "The direction of the force on the charge placed in the electric field is upward." is false.

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To find:

The direction of the magnetic force.

Explanation:

The direction of the magnetic field or a magnetic force on a charged particle is given by the right-hand rule. It states that when the thumb, middle finger, and index finger are held in such a way that they are perpendicular to each other if the thumb is pointing in the direction of the positive charge and the middle finger is pointing in the direction of the magnetic force then the index finger will point in the direction of the magnetic field.

Thus applying this rule we find that the index finger will be pointing to the east.

Final answer:

Thus the direction of the magnetic field is east.

Answer:

32.7 m

Explanation:

If it is in the air for 5.16 s    the highest point is at one-half of this time

  =   5.16/2 = 2.58 s    <====== at this point velocity = zero

vf = vi + at

0 = vi - 9.8 (2.58)      shows vi = 25.3 m/s

d = vi t  + 1/2 at^2

 = 25.3 (2.58) - 1/2 (9.8) (2.58^2 )   = max height = 32.7 meters

Answer:

The electric field inside the conductor is zero.

Explanation:

In electrostatic equilibrium charges are assumed to be in rest. Therefore no current.

I = 0

From the ohm's law

ΔV= IR = 0

⇒ΔV =0

Therefore, potential V is same through the conductor.

Also, E = -ΔV d = 0

Hence, The electric field inside the conductor is zero.

1.Unit vector in the direction BA: BA/|BA| = (2/3, 2/3, 1/3)

2.The angular velocity (ω) of the body is given as 3 radians per second.

3.Without the position of point P given, it is not possible to write the position vector of P.

4.Left-handed rotation refers to the direction of rotation where the rotation follows the left-hand rule.

5.Position vector of point A: (4, 1, 1)

Position vector of point B: (2, -1, 0)

The direction vector BA = (-2, -2, -1)

1.To determine the unit vector pointing in the direction BA, we subtract the coordinates of point B from the coordinates of point A and normalize the resulting vector.

The direction vector BA is given by:

BA = (4 - 2, 1 - (-1), 1 - 0) = (2, 2, 1)

To obtain the unit vector in the direction of BA, we divide the direction vector by its magnitude:

|BA| = √(2^2 + 2^2 + 1^2) = √(4 + 4 + 1) = √9 = 3

Unit vector in the direction BA: BA/|BA| = (2/3, 2/3, 1/3)

2.The angular velocity (ω) of the body is given as 3 radians per second.

3.Without the position of point P given, it is not possible to write the position vector of P. Please provide the position of point P to proceed with the calculation.

4.Left-handed rotation refers to the direction of rotation where the rotation follows the left-hand rule. In a left-handed coordinate system, if you curl the fingers of your left hand in the direction of rotation, your thumb will point in the direction of the rotation axis. It is the opposite direction to a right-handed rotation.

5.The position vectors of points A and B are:

Position vector of point A: (4, 1, 1)

Position vector of point B: (2, -1, 0)

The direction vector BA can be obtained by subtracting the coordinates of point A from the coordinates of point B:

BA = (2 - 4, -1 - 1, 0 - 1) = (-2, -2, -1)

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The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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A set of values for a variable arranged by magnitude from lowest to highest. A ranked distribution is represented by the elements in a cumulative frequency table.

The distribution of players among the various levels in ranked League of Legends is referred to as rank distribution. There are nine tiers, each divided into four sections. Iron, Bronze, Silver, Gold, Platinum, Diamond, Master, Grandmaster, and Challenger are the tiers in ascending order.

Ranked distribution means values put in order from lowest to highest. In other words, ascending order of values.

1. 123, 129, 234, 234, 236, 283, 358, 438, 444, 567

2. 10, 22, 23, 24, 25, 36, 43, 56, 67, 67, 76, 78, 92, 98

3. 10, 10, 23, 28, 30, 32, 42, 44, 56, 66, 67, 98, 98

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The 10/90 principle can be a powerful tool for taking control of your situation and improving your life. By taking responsibility for what you can change and focusing on your reaction to the situation, you can make positive changes in your life and become the master of your own destiny.

The 10/90 principle refers to the idea that life is made up of 10% of what happens to you and 90% of how you respond to it. In other words, you may not be able to control what happens to you, but you can control your reaction to it. By taking responsibility for what you can change rather than being a victim of what you cannot change, you can take control of your situation and improve your life.One example of a situation where the 10/90 principle could be applied is losing a job. Losing a job can be a devastating experience, and it can be easy to feel like a victim in this situation. However, by applying the 10/90 principle, you can take control of your situation and make positive changes in your life.The first step in applying the 10/90 principle in this situation would be to take responsibility for what you can change. This could mean updating your resume, networking with others in your field, and applying for new jobs. By taking action and doing what you can to find a new job, you are taking control of your situation and improving your chances of finding a new job.
The second step would be to focus on your reaction to the situation. Instead of dwelling on the negative aspects of losing your job, try to focus on the positive aspects. This could mean using the extra time to pursue a new hobby or spend more time with family and friends. By focusing on the positive aspects of the situation, you are taking control of your reaction and improving your overall well-being.
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Answer:

First, we can find the velocity of the rock just before it hits the ground using the equation:

v^2 = 2gh

where v is the final velocity, g is the acceleration due to gravity (9.81 m/s^2), and h is the height the rock falls from (7.0 m).

v^2 = 2(9.81 m/s^2)(7.0 m) = 136.89 m^2/s^2

v = √136.89 m^2/s^2 = 11.7 m/s

The momentum change of the rock caused by its fall is:

Δp = mv = (18 kg)(11.7 m/s) = 211.2 kg m/s

The resulting change in the magnitude of earth's velocity can be found using the conservation of momentum equation:

m1v1 + m2v2 = (m1 + m2)v'

where m1 and v1 are the mass and velocity of the rock before it falls, m2 and v2 are the mass and velocity of the earth before the rock falls (which we can assume is negligible), and v' is the velocity of the rock-earth system after the rock falls.

We can rearrange this equation to solve for v':

v' = (m1v1)/(m1 + m2)

v' = (18 kg)(11.7 m/s)/(18 kg + 6.0 × 10^24 kg)

v' = 1.95 × 10^-24 m/s

This means that the change in the magnitude of earth's velocity is essentially zero (which makes sense, since the mass of the earth is so much greater than the mass of the rock).

The momentum change of the rock caused by its fall is 211.2 kg·m/s, and the resulting change in the magnitude of earth’s velocity is 3.5 × 10⁻²³ m/s.

What is Momentum?

Momentum is a physics concept that describes the amount of motion an object has.  The units of momentum are kg m/s. In a closed system, the total momentum before an event or interaction is equal to the total momentum after the event or interaction.

To solve this problem, we need to use the law of conservation of momentum, which states that the momentum of an isolated system remains constant.

The momentum change of the rock is given by the formula:

Δp = mv

where m is the mass of the rock, and v is the change in velocity.

First, we need to find the final velocity of the rock. We can use the formula for the velocity of a falling object:

v² = 2gh

where g is the acceleration due to gravity, and h is the height of the fall.

Plugging in the given values, we get:

v² = 2 × 9.8 m/s² × 7.0 m

v² = 137.2

v = √137.2

v = 11.7 m/s

The change in the magnitude of Earth's Velocity  can be found using the formula:

Δv = Δp / M

where M is the mass of the earth.

The mass of the earth is given as 6.0 × 10²⁴ kg.

Δp = mΔv

Δp = 18 kg × 11.7 m/s

Δp = 211.2 kg·m/s

Δv = Δp / M

Δv = 211.2 kg·m/s / 6.0 × 10²⁴ kg

Δv = 3.5 × 10⁻²³ m/s

Therefore, the momentum change of the rock caused by its fall is 211.2 kg·m/s, and the resulting change in the magnitude of earth’s velocity is 3.5 × 10⁻²³ m/s.

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Answer:

In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

Mitosis is an essential mechanism for life, according to a National Human Genome Research Institute publication. A single cell divides into two genetically identical daughter cells during mitosis.

Multicellular organisms require this mechanism for growth, repair, and reproduction.

Because it doesn't use gametes or fertilization to create genetically identical daughter cells, mitosis is a type of asexual reproduction.

"Mitosis is a type of asexual reproduction that is essential for the growth and development of multicellular organisms," the National Center for Biotechnology Information explains.

Because it is essential for tissue growth and repair, mitosis is a vital process for all living things. The growth and repair of tissues as well as some organisms' asexual reproduction depend on mitosis, according to the American Society of Hematology.

Mitosis enables the expansion of tissues throughout development as well as the generation of new cells that can replace harmed or dying cells in the body.

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Answer:

Angular displacement  ≈  54 rad

Explanation:

Given:

φ₀ = 0

ω₀ = 15 rad/s

ω = 0

t = 7.2 s

___________

φ - ?

Rotational motion equation:

φ = φ₀ + ω₀·t + ε·t² / 2

Angular acceleration:

ε = (ω - ω₀) / t = ( 0 - 15 ) / 7.2 ≈ - 2.08 rad/s²

Angular displacement :

φ = φ₀ + ω₀·t + ε·t² / 2 = 0 + 15·7.2+ (-2.08)·7.2² / 2 ≈  54 rad

Answer:

2.25 Liters

Explanation:

The magnitude of the acceleration of the car before the collision is  4.23\(\frac{m}{ (s ^ 2)}\) and the magnitude of the average acceleration of the car during the collision is -16 \(\frac{m}{ (s ^ 2)}\) and the magnitude of the average acceleration of the car during the entire test, from when the car first begins moving until the collision is over is 2.46\(\frac{m}{ (s ^ 2)}\).

Velocity of car before collision is \(v_{1}\) = 120km / h

Velocity of car after collision is, \(v_{2}\) = 76.5km / h .

Time taken by a car before collision is, t =7.88:

Acceleration of car before collision is calculated as;

a = \(\frac{v-u}{t}\)

a =\(\frac{120\times \frac{5}{18}-0 }{7.88}\)

a = 4.23\(\frac{m}{ (s ^ 2)}\)

Therefore magnitude of acceleration of a car before collision a = 4.23  \(\frac{m}{ (s ^ 2)}\)

The average vehicle acceleration at the time of impact is computed as;

\(a_{avg}\) = \(\frac{v-u}{t}\)

\(a_{avg}\) =\((120-76.5)\times \frac{5}{18}\)

\(a_{avg}\) =0.755 s

\(a_{avg}\) =-16 \(\frac{m}{ (s ^ 2)}\)

Here, a negative sign shows that the average acceleration is moving in the opposite direction from where the car is travelling.

\(a_{avg}\) = \(\frac{v-u}{t}\)

\(a_{avg}\) =\(\frac{ (120-76.5)\times \frac{5}{18}}{0.755}\)

\(a_{avg}\) =-16\(\frac{m}{ (s ^ 2)}\)

Here, the negative sign denotes that the average acceleration is occurring in the opposite direction to the motion of the car.

Therefore, the average acceleration of a car during collision is \(a_{avg}\) =16 \(\frac{m}{ (s ^ 2)}\)

and in direction opposite to the direction of car.

The average acceleration of the car during the test is calculated.

as,

\(a_{2}\)=\(\frac{v-u}{t}\) =\(76.5\times a_{2}\)= \(\frac{76.5\times\frac{5}{18} }{7.88-0.75}\)

\(a_{2}\)=2.46\(\frac{m}{ (s ^ 2)}\)

Therefore, the average acceleration of a car during entire test is a_{2} = 2.46\(\frac{m}{ (s ^ 2)}\)

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Answer:

C

Explanation:

it is C because science is an acquiring and defining of knowledge.

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\( \large\green{\overline{\underline{\rm{\red{•••••••••••••••••••••••••}}}}} \)

what is the name of the scientist that discovered gravity?

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The scientist named Isaac Newton discovered the gravity. But before that Aristotle was discovered the gravity first but the calculations were poor and not enough for knowing what it is.

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The medium in which electromagnetic waves and mechanical waves travel is one of their primary distinctions. Light and other electromagnetic waves, including radio waves, can move through void space without the aid of a physical medium.

They may move through vacuum, air, or other materials and are made up of oscillating electric and magnetic fields. The propagation of mechanical waves, such as sound or water waves, on the other hand, depends on a physical medium.

To transport energy, they rely on particle interactions and displacements in the medium. Since mechanical waves need a physical medium to carry their energy, they cannot move through a vacuum.

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The distance between the glass to have the given heat loss is 2.54 m.

The given parameters:

The area of the glass window is calculated as follows;

\(A = 0.6 \times 0.9\\\\A = 0.54 \ m^2\)

The distance between the glass is calculated as follows;

\(Q = \frac{KA \Delta T}{\Delta x} \\\\\Delta x = \frac{kA \Delta T}{Q} \\\\\Delta x = \frac{0.8 \times 0.54 \times 24 }{4.09} \\\\\Delta x = 2.54 \ m\)

Thus, the distance between the glass to have the given heat loss is 2.54 m.

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According to the information we can infer that the forces are PULLING forces, OPPOSITE FORCES, EQUAL, forces DO balance each other, the resultant force is ZERO, and there IS NO motion.

According to the information of the image, we can conclude that the forces shown above are PULLING forces because they involve pulling a rope on each side. Also, the forces shown above are OPPOSITE FORCES because they act in opposite directions, pulling the rope towards different sides.

On the other hand, the forces are EQUAL in magnitude because each side exerts a force of 1000 Newtons. Additionally, the forces DO balance each other because they have the same magnitude and act in opposite directions. The individuals on each side are exerting equal forces, resulting in a balanced system.

Finally, the resultant force is ZERO because the forces are equal in magnitude and act in opposite directions. The combined effect of the forces is no net force or resultant force and there IS NO motion because the forces are balanced, resulting in a net force of zero. In a balanced system, the objects will remain at rest or in a state of uniform motion.

Note: This question is incomplete. Here is the complete information:
Attached image

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The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).

The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.

In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²

(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:

Electric flux = Electric field strength × Area

Electric flux = 18 N C⁻¹ × 0.450 m²

Electric flux = 8.1 N m² C⁻¹

In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.

The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).

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Answer:

Let's start by calculating how much of a head start Car A has in distance before Car B starts.

In 3 minutes, Car A will have travelled:

d = r * t = (60 km/h) * (3/60) h = 3 km

So when Car B starts, Car A is 3 km ahead.

Now let's consider the time it takes for both cars to meet. Let's call the time it takes for both cars to meet t.

During that time, Car A will travel at a speed of 60 km/h, and Car B will travel at a speed of 70 km/h.

The distance that Car A will travel during that time is:

dA = 60 km/h * t

The distance that Car B will travel during that time is:

dB = 70 km/h * t

The total distance between the two cars when they meet is:

d = dA + dB

We want to find the value of t that makes dA + dB = 3 km (the distance that Car A is ahead of Car B when Car B starts).

Substituting the expressions for dA and dB, we get:

60 km/h * t + 70 km/h * t = 3 km

Simplifying, we get:

130 km/h * t = 3 km

t = 3 km / 130 km/h

t = 0.0231 h

Now we can calculate the distance that both cars will have travelled when they meet:

dA = 60 km/h * 0.0231 h = 1.38 km

dB = 70 km/h * 0.0231 h = 1.61 km

d = dA + dB = 1.38 km + 1.61 km = 2.99 km

Therefore, the two cars will draw level after travelling approximately 2.99 km from the starting point.