Can you please help me with the 1st law of thermodynamics (What does the variables in the formula mean) and a example of the first law

The moment of a couple is significant in various applications, such as analyzing the equilibrium and rotational motion of objects, understanding the behavior of rotating systems, and studying the effects of torques in mechanics and engineering.

In physics, the moment of a couple, also known as torque, refers to the rotational effect produced by two equal and opposite forces acting on an object but not along the same line of action.

A couple consists of two forces that have the same magnitude, act in parallel lines, and are opposite in direction. These forces create a rotational moment or torque around a particular point, known as the pivot or axis of rotation. The moment of a couple is a measure of the tendency of the couple to rotate an object.

The magnitude of the moment of a couple is given by the product of one of the forces and the perpendicular distance between the lines of action of the two forces. Mathematically, it can be expressed as:

Moment of couple = Force × Perpendicular distance

The SI unit of moment of a couple is the newton-meter (Nm). It is also important to note that the moment of a couple is a vector quantity and follows the right-hand rule for determining its direction.

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Answer:depends on the masses of the objects and the distance between them

Explanation:

According to Newton's law of universal gravitation,the force of attraction between two objects depends on the masses of the objects and the distance between them

Answer:

15,505 N

Explanation:

Using the principle of conservation of energy, the potential energy loss of the student equals the kinetic energy gain of the student

-ΔU = ΔK

-(U₂ - U₁) = K₂ - K₁ where U₁ = initial potential energy = mgh , U₂ = final potential energy = 0, K₁ = initial kinetic energy = 0 and K₂ = final kinetic energy = 1/2mv²

-(0 - mgh) = 1/2mv² - 0

mgh = 1/2mv² where m = mass of student = 70kg, h = height of platform  = 1 m, g = acceleration due to gravity = 9.8 m/s² and v = final velocity of student as he hits the ground.

mgh = 1/2mv²

gh = 1/2v²

v² = 2gh

v = √(2gh)

v = √(2 × 9.8 m/s² × 1 m)

v = √(19.6 m²/s²)

v = 4.43 m/s

Upon impact on the ground and stopping, impulse I = Ft = m(v' - v) where F = force, t = time = 0.02 s, m =mass of student = 70 kg, v = initial velocity on impact = 4.43 m/s and v'= final velocity at stopping = 0 m/s

So Ft = m(v' - v)

F = m(v' - v)/t

substituting the values of the variables, we have

F = 70 kg(0 m/s - 4.43 m/s)/0.02 s

= 70 kg(- 4.43 m/s)/0.02 s

= -310.1 kgm/s ÷ 0.02 s

= -15,505 N

So, the force transmitted to her bones is 15,505 N

Answer:True. The number of calories in a food is a measure of how much potential energy that food possesses.

Explanation:

The break shot speed of the player is determined as 96.5 ft/s.

use the following kinematic equation to determine the time of motion of the player.

h = vt + ¹/₂gt²

h = 0 + ¹/₂gt²

h = ¹/₂gt²

t = √(2h/g)

t = √(2 x 2.75/32.17)

t = 0.171 s

vx = x/t

vx = 16.5 ft / 0.171 s

vx = 96.5 ft/s

Thus, the break shot speed of the player is determined as 96.5 ft/s.

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The vector product of A=2.00i+3.00j+1.00k and B=1.00i-3.00j-2.00k is C=9.00i+4.00j-9.00k.

To find the vector product (also known as the cross product) of two vectors, A and B, we can use the following formula:

C = A × B

Where C is the resultant vector, A and B are the given vectors, and × denotes the cross product.

Given A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k, we can substitute these values into the formula to find the vector product:

C = (2.00i + 3.00j + 1.00k) × (1.00i - 3.00j - 2.00k)

Now, let's expand the cross product using the properties of vector products:

C = (2.00i × 1.00i) + (2.00i × -3.00j) + (2.00i × -2.00k) +

   (3.00j × 1.00i) + (3.00j × -3.00j) + (3.00j × -2.00k) +

   (1.00k × 1.00i) + (1.00k × -3.00j) + (1.00k × -2.00k)

Now, let's calculate each of these cross products:

C = (2.00 × 1.00) \(i^2\) + (2.00 × -3.00) i × j + (2.00 × -2.00) i × k +

   (3.00 × 1.00) j × i + (3.00 × -3.00) \(j^2\) + (3.00 × -2.00) j × k +

   (1.00 × 1.00) k × i + (1.00 × -3.00) k × j + (1.00 × -2.00) \(k^2\)

Since i × j = k, j × k = i, and k × i = j, we can simplify the expression further:

C = 2.00k - 6.00i + 4.00i - 9.00j + k - 3.00j - 2.00j - 2.00k

Combining like terms, we get:

C = (2.00i + 4.00i) + (-6.00i - 9.00j - 3.00j) + (2.00k + k - 2.00k)

Simplifying further:

C = 6.00i - 12.00j + k

Therefore, the vector product of A and B is C = 6.00i - 12.00j + k, which can be written as C = 9.00i + 4.00j - 9.00k in terms of i, j, and k.

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The vector product of A and B is -3i - 5j - 9k.

The vector product, also known as the cross product, of two vectors A and B is denoted as A x B. It is a vector that is perpendicular to both A and B. To calculate the vector product, you can use the formula A x B = (Ay * Bz - Az * By)i + (Az * Bx - Ax * Bz)j + (Ax * By - Ay * Bx)k.

In this case, we have A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k. Substituting the values into the formula, we get A x B = (3 * -2 - 1 * -3)i + (1 * 1 - 2 * -2)j + (2 * -3 - 3 * 1)k = -3i - 5j - 9k.

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Answer:

This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.

The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.

The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).

The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:

R(n) = √(X² + Y²)

Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.

However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:

<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2

<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2

Because <X²> = <Y²>, we can write:

<R²> = <X²> + <Y²> = n A²

So, the root mean square distance (the square root of the mean square displacement) after n steps is:

R(n) = √(<R²>) = √(n) * A

Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.

Answer:

Explanation:

As warm air comes in contact with the glass, the air becomes cooler. When that happens the cool air can't hold as much water vapor which condenses on the glass.

The answer is C.

Answer:

1. No

2. A = Cool. B = Room Temp

3. Unknown

Explanation:

1. No because by definition convection is within a fluid.

2. The colder something is it'll keep getting colder. Hotter one should get to room temperature due to diversion of temps.

By supplying the fundamental knowledge required to create new instruments and techniques for medical use, physics enhances our quality of life

From can openers, light bulbs, and mobile phones to muscles, lungs, and brains; from paintings, piccolos, and pirouettes to cameras, vehicles, and cathedrals; from earthquakes, tsunamis, and storms to quarks, DNA, and black holes, physics aids us in understanding the workings of the world around us.

The science of physics is the most fundamental and has many applications in contemporary technology. Because it makes it possible for smartphones, computers, televisions, watches, and many other modern technologies to function automatically, physics is crucial to modern technology.

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If you know the apparent and intrinsic brightness of a star, you can find the distance to the star by using the inverse square law of brightness.

The apparent brightness of a star is the amount of light received from the star at a given distance from Earth, while the intrinsic brightness is the actual amount of light the star emits. By comparing the apparent and intrinsic brightness of a star, we can calculate the distance to the star using the inverse square law of brightness, which states that the intensity of light decreases as the square of the distance from the source increases. Therefore, the distance to a star can be determined by using the equation: distance = square root (intrinsic brightness / apparent brightness).

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The velocity of the electron after moving a distance of 1cm in the electric field is 5.95×10⁶m.

Electric field is the physical field that surrounds a charge.

a=F/m=qE/m

E= electric field

m= mass of electron

=(−1.60×10^−19C)(3×10³N/C)/(9.11×10^-31kg)

=10¹⁵×0.526m/s²

v0=initial velocity of the electron =5×10⁶m/s

a=acceleration of the electron =10¹⁵×0.526m/s²

Δx=distance moved by the electron in east direction =1cm=10^-2m

=25×10¹²+10.52×10¹²

=35.52×10¹²

Thus , we can conclude that the velocity of the electron after moving a distance of 1cm in the electric field is 5.95×10⁶m.

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Therefore, the power of the porter is 441,450 J/s, or approximately 441.5 watts.

The work done by the porter in lifting the 50 kg bag up the stairs can be calculated as the product of the force applied and the distance moved.

The force applied is the weight of the bag, which is given by:

F = m * g

where m is the mass of the bag and g is the acceleration due to gravity, which is approximately 9.81 m/s². Substituting the given values, we get:

F = 50 kg * 9.81 m/s²

F = 490.5 N

The distance moved by the porter in lifting the bag up one staircase is 30 cm, and the porter climbs 10 staircases in 10 seconds, which gives a speed of:

v = (10 * 30 cm) / 10 s

v = 30 cm/s

The power of the porter is the rate at which work is done, which can be calculated as:

P = W / t

where W is the work done and t is the time taken. Substituting the values, we get:

P = F * d * v / t

P = 490.5 N * 10 * 30 cm * 30 cm/s / 10 s

P = 441,450 J/s

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Answer:

D

I hope these is correct

A matter may exist as a solid, liquid, or gas. Matter is made up of atoms. The correct options are A and C.

In physical laws and general chemistry, matter is any material that has mass and occupies space by having volume.

It has something to do with weight. Atoms, which are made up of subatomic particles, make up the vast majority of matter in the universe.

Even all organisms is made up of matter, whether they are living or non living.

Matter is significant as though it build up all the things present in person's environment. Matter can neither be generated or be destroyed as it can only be transmuted into some another form.

The quantity of matter in a physical existence is renowned as mass. When a net force is exerted, it also characterize the body's inertia, or resistance to acceleration.

A substance can exist as a solid, liquid, or gas. Atoms are the building blocks of matter.

Thus, the correct options are A and C.

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1.Unit vector in the direction BA: BA/|BA| = (2/3, 2/3, 1/3)

2.The angular velocity (ω) of the body is given as 3 radians per second.

3.Without the position of point P given, it is not possible to write the position vector of P.

4.Left-handed rotation refers to the direction of rotation where the rotation follows the left-hand rule.

5.Position vector of point A: (4, 1, 1)

Position vector of point B: (2, -1, 0)

The direction vector BA = (-2, -2, -1)

1.To determine the unit vector pointing in the direction BA, we subtract the coordinates of point B from the coordinates of point A and normalize the resulting vector.

The direction vector BA is given by:

BA = (4 - 2, 1 - (-1), 1 - 0) = (2, 2, 1)

To obtain the unit vector in the direction of BA, we divide the direction vector by its magnitude:

|BA| = √(2^2 + 2^2 + 1^2) = √(4 + 4 + 1) = √9 = 3

Unit vector in the direction BA: BA/|BA| = (2/3, 2/3, 1/3)

2.The angular velocity (ω) of the body is given as 3 radians per second.

3.Without the position of point P given, it is not possible to write the position vector of P. Please provide the position of point P to proceed with the calculation.

4.Left-handed rotation refers to the direction of rotation where the rotation follows the left-hand rule. In a left-handed coordinate system, if you curl the fingers of your left hand in the direction of rotation, your thumb will point in the direction of the rotation axis. It is the opposite direction to a right-handed rotation.

5.The position vectors of points A and B are:

Position vector of point A: (4, 1, 1)

Position vector of point B: (2, -1, 0)

The direction vector BA can be obtained by subtracting the coordinates of point A from the coordinates of point B:

BA = (2 - 4, -1 - 1, 0 - 1) = (-2, -2, -1)

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Answer:

Fault is the correct answer

Explanation:

The rest are incorrect.

Answer:

The meaning of the name “Birendra” is: “Great warrior”.

Explanation:

The meaning of the name "Birendra" is "Great warrior"

Explanation:

Categories: Hindi names, Hindu names, Indian names, Sanskirt names.

Answer:

a)  F₃ = 109.5 N ,     θ₃ = 38.35,  b)   m = 0.429 kg

Explanation:

For this force addition exercise, let's decompose the forces into a coordinate system

strength 1

          cos 70 = F₁ₓ / F₁

          sin 70 = \(F_{1y}\) / F₁

          F₁ₓ = F₁ cos 70

         F_{1y} = F₁ sin 70

          F₁ₓ = 45 cos 70 = 15.39 N

          F_{1y} = 45 sin70 = 42.29 N

Strength 2

         cos 20 = F₂ₓ / F₂

         sin 20 = F_{2y} / F₂

         F₂ₓ = F₂ cos 20

         F_{2y} = F₂ sin20

         F₂ₓ = 75 cos 20 = 70.48 N

         F_{2y} = 75 sin 20 = 25.65 N

a) in the first part we are asked to find the magnitude of force 3 so that the body is in equilibrium

X axis

         ∑ Fₓ = 0

          F₁ₓ + F₂ₓ + F₃ₓ = 0

          F₃ₓ = - F₁ₓ - F₂ₓ

          F₃ₓ = - 15.39 - 70.48

          F₃ₓ = - 85.87 N

Y Axis

         ∑ F_{y}  = 0

         F_{1y} + F_{2y} +F_{3y}  = 0

         F_{3y} = - F_{1y} -F_{2y}

         F_{3y} = - 42.29 - 25.65

         F_{3y} = - 67.94 N

the magnitude of this force can be found using the Pythagorean theorem

         F₃ = √ (F₃ₓ² + F_{3y}^2)

         F₃ = √ (85.87² + 67.94²)

         F₃ = 109.5 N

The direction of this force can be found using trigonometry

          tan θ =  F₃ = \(F_{3y}\) / F₃ₓ

          θ₃ = Tan⁻¹ (67.94 / (85.87))

          θ₃ = 38.35º

since the two vectors are negative this angle is in the third quadrant, measured from the positive side of the x axis is

          θ₃ = 180 + 38.53

          θ₃ = 218.35º

b) I think you have an error in your statement, we have two possibilities:

1) If we eliminate the third force, what is the mass

it should say: "if we apply the third force force ...", they ask that we find the masses of the vehicle, let's use Newton's second law

X axis

       F₁ₓ + F₂ₓ = m a

       15.39 + 70.48 = m 200

        m = 85.87 / 200

        m = 0.429 kg

2) If the force F3 is in the first quadrant

        F1x + F2x + F3x = m a

        m = (15.39 + 70.48 + 85.87) / 200

        m = 0.8587 kg

The current that flows through the 75 ohm resistor in the circuit shown below is 0.12A.

The current flowing through a circuit can be calculated using the Ohm's law equation as follows;

V = IR

Where;

According to this question, a circuit is shown in the above image. A 75 ohm resistor is given alongside a voltage of 9V. The current can be calculated as follows;

9 = I × 75

I = 0.12A

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Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

Normal force is an equal but opposite force to weight.

Weight = Normal force

weight=m×g

= 65×10

=650N

Explanation:

HOPE THAT THIS IS HELPFUL.

HAVE A GREAT DAY.

Answer:

v₃ = 1.25[m/s]

Explanation:

In order to solve this problem, we must use the principle of conservation of the amount of movement and momentum.

That is, the amount of movement is preserved before and after the collision. Let's propose an equation, in which the elements to the left of the equal sign represent the moment before the collision and to the right the moment after the collision.

\(P=m*v\)

P = lineal momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

\((m_{1}*v_{1})+(m_{2}*v_{2})=(m_{1}+m_{2})*v_{3}\)

m₁ = mass of the first railroad = 2096 [kg]

m₂ = mass of the second railroad = 6280 [kg]

v₁ = velocity of the first railroad before the collision = 5 [m/s]

v₂ = velocity of the second railroad before the collision = 0 (initially at rest)

v₃ = velocity of the group after the collision [m/s]

Now replacing:

\((2096*5)+(6280*0)=(2096+6280)*v_{3}\\10480=8376*v_{3}\\v_{3}=1.25[m/s]\)

Across

2. opaque

4. hard

5. metal(s)

6. translucent

8. luster

Down

1. wood

3. transparent

7. soluble?

Happy to help, have a great day! :)

Answer:

3*10^8 ÷ 475*10^-9

= 6.3 x 10^14

Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.

To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.

In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.

To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.

Total cost covered by the five friends = Total cost - Cost of one person's meal

= (£12 x 6) - £12

= £72 - £12

= £60

Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).

Amount each friend needs to pay = Total cost covered by the five friends / Number of friends

= £60 / 5

= £12

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Answer:

B

Explanation:

Electric charges and magnetic dipoles

The magnitude of the magnetic field's torque on the loop is 0.034 Nm.

When a current-carrying conductor is put in a magnetic field, it experiences a force known as the Lorentz force, which is proportional to the magnetic field's strength and the current running through the conductor. As a result of this force, a torque is imparted to the conductor, which tends to turn it around an axis perpendicular to the conductor's plane.

The following formula can be used to calculate the torque operating on the conductor:

= NIABsin

where is the torque, N is the number of turns, I is the current, A is the area of the loop, B is the strength of the magnetic field, and is the angle between the magnetic field and the plane of the loop.

If the magnetic field is parallel to the plane of the loop, then θ is equal to 0°, and sinθ is equal to 0.

As a result, the torque formula can be shortened to: = NIAB.

When the numbers for N, I, A, and B are entered into this formula, the magnetic field's torque on the loop is found to be:

= (1)(0.017 A)(π(1 m)²)(0.80 T)τ = 0.034 Nm.

As a result, the magnitude of the magnetic field's torque on the loop is 0.034 Nm.

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Scientifically painting finished components might be given as, W = F * d. In this example, the pressure exerted at the block is regular, however, the path of force and the direction of displacement encouraged by using this pressure is one-of-a-kind. right here, force F reacts at an attitude θ to the displacement d.

The work accomplished through pressure is defined to be the product of the aspect of the force in the path of the displacement and the importance of this displacement. formulation. work may be calculated by multiplying force and Distance inside the route of force as follows. W = F × d.

The work W is equal to the pressure f instances the distance d, or W = fd. If the force is being exerted at a perspective θ to the displacement, the work accomplished is W = FD cos θ.

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