Answer:
Q1_new = 515.68 µC
Q2_new = 246.82 µC
Explanation:
Since the capacitors are charged in parallel and not in series, then both are at 250 V when they are disconnected from the battery.
Then it is only necessary to calculate the charge on each capacitor:
Q1 = 5.85 µF * 250 V = 1462.5 µC
Q2 = 2.8 µF * 250 V = 700 µC
Now, we will look at 1462.5 µC as excess negative charges on one plate, and 1462.5 µC as excess positive charges on the other plate. Now, we will use this same logic for the smaller capacitor.
When there is a connection of positive plate of C1 to the negative plate of C2, and also a connection of the negative plate of C1 to the positive plate of C2, some of these excess opposite charges will combine and cancel each other. The result is that of a net charge:
1462.5 µC - 700 µC = 762.5 µC
Thus,762.5 µC of net charge will remain in the 'new' positive and negative plates of the resulting capacitor system.
This 762.5 µC will be divided proportionately between the two capacitors.
Q1_new = 762.5 µC * (5.85/(5.85 + 2.8)) = 515.68 µC
Q2_new = 762.5 µC * (2.8/(5.85 + 2.8) = 246.82 µC
An aeroplane is circling above an airport in a horizontal circle at a speed of 400 kmh-1.The banking angle of the wings is 20.What is the radius of the circular path?
Answer: the radius of the circular path is approximately 1637.58 meters.
Explanation:
The centripetal force acting on the airplane is provided by the component of the gravitational force that acts towards the center of the circular path. This component is given by:
F_c = m * g * tan(banking angle)
Where:
F_c is the centripetal force
m is the mass of the airplane
g is the acceleration due to gravity
tan(banking angle) is the tangent of the banking angle
Now, the centripetal force is also given by the formula:
F_c = (m * v^2) / r
Where:
v is the speed of the airplane
r is the radius of the circular path
Equating the two expressions for F_c, we get:
(m * g * tan(banking angle)) = (m * v^2) / r
Canceling out the mass (m) on both sides of the equation, we have:
g * tan(banking angle) = v^2 / r
Solving for r, we get:
r = (v^2) / (g * tan(banking angle))
Substituting the given values:
v = 400 km/h = 400,000 m/h
g = 9.8 m/s^2
banking angle = 20°
Converting the speed to m/s:
v = 400,000 m/h * (1/3600) h/s = 111.11 m/s
Converting the banking angle to radians:
banking angle = 20° * (π/180) rad/° = 0.3491 rad
Now, substituting the values into the formula:
r = (111.11^2) / (9.8 * tan(0.3491))
r ≈ 1637.58 meters
Therefore, the radius of the circular path is approximately 1637.58 meters.
What is the minimum amount ( in kg) of liquid water at 26 degrees that would be required to completely melt 41 grams of ice? The specific heat capacity of liquid water is 4180 J/kg/°C and the specific heat of fusion of ice is 3.33×105 J/kg.
Approximately 0.123 kg of liquid water at 26 degrees Celsius would be needed to melt 41 grams of ice.
To calculate the minimum amount of liquid water required to melt 41 grams of ice at 0°C, we need to consider the energy required for the phase change from solid to liquid, which is known as the specific heat of fusion of ice.
The energy required to melt 1 kg of ice is 3.33×105 J/kg.
Therefore, the energy required to melt 41 grams of ice is (3.33×105 J/kg) × (41/1000) kg = 13653 J.
To calculate the amount of liquid water required, we use the specific heat capacity of water, which is 4180 J/kg/°C.
Assuming the initial temperature of water is 26°C, the amount of water needed can be calculated as (13653 J) ÷ (4180 J/kg/°C) ÷ (26°C) = 0.123 kg or approximately 123 ml of water.
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A student takes the temperature of a bottle of liquid water and a tub filled with ice. The student then places the bottle of liquid water into the tub of ice. After 15 minutes, which of the following best describes what happens to the temperature of each?
There will be exchange of heat in the system, the tub filled with ice will gain heat, while the bottle of liquid will lose heat.
The flow is made possible by means of convection which implies heat flow from region of higher concentration to region of low concentration
by actual movement of material particles
There are basically three modes of heat transfer
RadiationConvectionConductionLearn more:
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Explanation:
if you go to connexus and are doing the science
Thermal Energy Unit Test 10 qestions 8th grd unit 5 test lesson 12 here are the correct answers
1. A. metal is heated from room temperature to 200'C.
2. B. The particles will have more space between them as steam, but they will be moving at the same speed in both states.
3. C. The potential energy decreases due to the tighter arrangement of the particles.
4. B. an increase in heat and an increase in kinetic energy until a phase change occurs.
5. C. thermometer
6. B. 4.
7. D. convection
8. C. Air moves from the areas of higher temperature to areas of lower temperature.
9. C. The temperature of the ice increases, while the temperature of the water decreases
10. A. heat transfer by radiation.
i hope this helps and please let me know if it does! = ) <3
An objects weight w is equal to the product of its mass and the acceleration due
to gravity. On Earth, this value is g = 9.8 m/s^2. If something weighs 400 N,
what is its mass?
Answer:hinwjdheiohuddwrr
87u7t
A 68 kg
man's arm, including the hand, can be modeled as a 79-cm
-long uniform cylinder with a mass of 3.3 kg. In raising both his arms, from hanging down to straight up, by how much does he raise his center of gravity?
Answer:
Explanation:
We can calculate the change in the man's center of gravity by considering the initial and final positions of the center of gravity of his arms.
Assuming the man's arms are initially hanging down by his sides, the center of gravity of his arms is located at the midpoint of the cylinder, which is at a distance of L/2 = 79/2 = 39.5 cm from the shoulder joint.
When the man raises his arms straight up, the center of gravity of his arms is located at the top of the cylinder, which is at a distance of L = 79 cm from the shoulder joint.
The change in the man's center of gravity is therefore:
Δh = h_final - h_initial
= L - L/2
= 79 cm - 39.5 cm
= 39.5 cm
Therefore, the man raises his center of gravity by 39.5 cm when he raises both his arms from hanging down to straight up.
A charge of 87.6 pC is uniformly distributed on the surface of a thin sheet of insulating material that has a total area of 65.2 cm^2. A Gaussian surface encloses a portion of the sheet of charge. If the flux through the Gaussian surface is 9.20 N⋅m^2/C, what area of the sheet is enclosed by the Gaussian surface?
Answer:
60.8 cm²
Explanation:
The charge density, σ on the surface is σ = Q/A where q = charge = 87.6 pC = 87.6 × 10⁻¹² C and A = area = 65.2 cm² = 65.2 × 10⁻⁴ m².
σ = Q/A = 87.6 × 10⁻¹² C/65.2 × 10⁻⁴ m² = 1.34 × 10⁻⁸ C/m²
Now, the charge through the Gaussian surface is q = σA' where A' is the charge in the Gaussian surface.
Since the flux, Ф = 9.20 Nm²/C and Ф = q/ε₀ for a closed Gaussian surface
So, q = ε₀Ф = σA'
ε₀Ф = σA'
making A' the area of the Gaussian surface the subject of the formula, we have
A' = ε₀Ф/σ
A' = 8.854 × 10⁻¹² F/m × 9.20 Nm²/C ÷ 1.34 × 10⁻⁸ C/m²
A' = 81.4568/1.34 × 10⁻⁴ m²
A' = 60.79 × 10⁻⁴ m²
A' ≅ 60.8 cm²
The flux through the Gaussian surface is 9.20 N⋅m^2/C then the surface area of the Gaussian Sheet is 60.76 square cm.
Charge and Charge DensityA certain amount of electrons in excess or defect is called a charge. Charge density is the amount of charge distributed over per unit of volume.
Given that, for a thin sheet of insulating material, the charge Q is 87.6 pC and surface area A is 65.2 square cm. Then the charge density for a thin sheet is given below.
\(\sigma = \dfrac {Q}{A}\)
\(\sigma = \dfrac {87.6\times 10^{-12}}{65;.2\times 10^{-4}}\)
\(\sigma = 1.34\times 10^{-8} \;\rm C/m^2\)
Thus the charge density for a thin sheet of insulating material is \(1.34\times 10^{-8} \;\rm C/m^2\).
Now, the flux through the Gaussian surface is 9.20 N⋅m^2/C. The charge over the Gaussian Surface is given as below.
\(Q' = \sigma A'\)
Where Q' is the charge at the Gaussian Surface, A' is the surface area of the Gaussian surface and \(\sigma\) is the charge density.
For the closed Gaussian Surface, Flux is given below.
\(\phi = \dfrac {Q'}{\epsilon_\circ}\)
Hence the charge can be written as,
\(Q' = \phi\epsilon_\circ\)
So the charge can be given as below.
\(Q' = \phi\epsilon_\circ = \sigma A'\)
Then the surface area of the Gaussian surface is given below.
\(A' = \dfrac {\phi\epsilon_\circ}{\sigma}\)
Substituting the values in the above equation,
\(A' = \dfrac {9.20 \times 8.85\times 10^{-12}}{1.38\times 10^{-8}}\)
\(A' =0.006076\;\rm m^2\)
\(A' = 60.76 \;\rm cm^2\)
Hence we can conclude that the area of the Gaussian Surface is 60.76 square cm.
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Kyle lays a mirror flat on the floor and aims a laser at the mirror. The laser beam reflects off the mirror and strikes an adjacent wall. The plane of the incident and reflected beams is perpendicular to the wall. The beam from the laser strikes the mirror at a distance a=60.1 cm from the wall. The reflected beam strikes the wall at a height b=31.3 cmabove the surface of the mirror.Find the angle of incidence θiat which the laser beam strikes the mirror.
Answer:
62.5 °
Explanation:
✓From law of reflection, angle of incidence equals angles of reflection .
✓the angle between the reflected ray can be determined using trigonometry, we know that
horizontal distance x =60.1 cm
the vertical distance is y =31.3
Then
tan( θ) =( y / x)
If we substitute the values we have,
tan θ = 31.3 / 60.1
θ = tan⁻¹ (0.5208)
θ = 27.5°
This angle is been measured using x-axis (horizontal)BBut in optics we can measured with respect to y-axis then angle becomes
θ = 90 - 27.5
θr = 62.5 °
θr = θi= 62.5°
the angle of incidence θiat which the laser beam strikes the mirror is 62.5°
A rubber balloon has become negatively charged from being rubbed with a wool cloth, and the charge is measured as 6 * 10 ^ - 14 C According to this charge, the balloon contains an excess of how many electrons?
Answer:
1.60 x 10-10 C
Explanation:
A fifty-car train going 25 meters per second takes 150 seconds to stop. What is the acceleration?
( show work please )
Answer:
6
Explanation:
150 seconds divided by 25 meters per seconds = 6
You are walking down a straight path in a park and notice there is another person walking some distance ahead of you. The distance between the two of you remains the same, so you deduce that you are walking at the same speed of 1.17 m/s. Suddenly, you notice a wallet on the ground. You pick it up and realize it belongs to the person in front of you. To catch up, you start running at a speed of 2.75 m/s. It takes you 14.5 s to catch up and deliver the lost wallet. How far ahead of you was this person when you started running
Answer:
Δx = 23.0 m
Explanation:
Since we know the time passed from the moment you picked up the wallet till you catch the other person up, and assuming that he continued moving at 1.17 m/s, we can find the distance traveled by him during this time, applying the definition of average speed, and rearrranging terms as follows:\(x_{2} = v_{2} * t = 1.17m/s * 14.5 s = 17.0 m (1)\)
Now, as we know the speed at which you started to run, assuming that the speed kept constant during all the time since you picked the wallet up, we can find the total distance till you got to deliver the wallet, as follows:\(x_{1} = v_{1} * t = 2.75 m/s * 14.5 s = 40.0 m (2)\)
the distance that you were behind the other person when you started running, is just the difference between (2) and (1):Δx = x₂ - x₁ = 40.0 m - 17.0 m = 23.0 m (3)Fill in the magnitude of net force for each case. Including the solution plss
Net forces in all above cases will be
A) F net = 0
B) F net = 1 N
C) F net = 5 N
D) F net = 5N
E) F net = 5 N
F) F net = 5 N
G) F net = 9.9 N
H) F net = 9.9 N
A) net force = upward force - downward force
= 4 - 4 = 0
B) net force = rightward force - leftward force = 4 - 3 = 1 N
C) net force
using Pythagoras theorem
F net = \(\sqrt{4^{2} + 3^{2} }\) = \(\sqrt{25}\) = 5 N
D) F net = \(\sqrt{-4^{2} + (-3)^{2} }\) = 5 N
E) balancing horizontal forces
rightward force - leftward force = 5 - 2 = 3 N
using Pythagoras theorem
F net = \(\sqrt{4^{2} + 3^{2} }\) = 5 N
F) balancing vertical forces
-5 + 2 = -3 N
using Pythagoras theorem
\(\sqrt{(-4)^{2} +(-3) ^{2} }\) = 5 N
G) using Pythagoras theorem
F net = \(\sqrt{7^{2} + 7^{2} }\) = 9.9 N
H ) balancing horizontal forces
10 - 3 = 7 N
\(\sqrt{7^{2} + 7^{2} }\) = 9.9 N
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Please help I don’t get it tell me where to draw the lines (if correct I’ll give brainliest) 10 POINTS
Answer:
bulb, battery, switch
Explanation:
conect the battery and the bulb with switch .on the switch to light the bulb.
6° with the horizontal) at a steady speed of 4.0 m/s. Assuming a total mass of 75 kg (bicycle and Kasek), what must be Kasek's power output to climb the same hill at the same speed?
Answer:
Power, P = 307.31 W
Explanation:
It is given that,
Kasek climb at an angle of 6° with the horizontal at a steady speed of 4.0 m/s.
The total mass of bicycle and Kasek is 75 kg
We need to find the Kasek's power output to climb the same hill at the same speed. The angle is made with the horizontal. It means that,
F = F sinθ
So,
Power output is given by :
\(P=mg\sin\theta\times v\\\\P=75\times 9.8\times \sin(6)\times 4\\\\P=307.31\ W\)
So, Kasek's power output to climb the same hill is 307.31 W.
According to the principal of superposition,
Answer:
the resultant wave is the algebraic sum of all the waves reaching that particular point at a given time.
Explanation:
imagine two or three waves reaching a particular particle x at the same time. The particle will vibrate those waves and give out or transmit a resultant wave which is the algebraic sum of the incoming two waves. If both the waves have the same amplitude and phase, the resultant wave will be amplified. However if the waves have the same amplitude and equal but opposite phase then the resultant wave will be a straight line
forces applied to the collision
Answer: I think this is the answer, In a collision, there is a force on both objects that causes an acceleration of both objects; the forces are equal in magnitude and opposite in direction. For collisions between equal-mass objects, each object experiences the same acceleration.
Explanation: I had a question similar to this, Hope this helps!
WILL GIVE BRAINIEST PLZ HEP!!!!!!
Which is a component of skill-related fitness?
Flexibility
Reaction time
Muscular strength
Body Composition
Answer:
B. Reaction Time
Explanation:
Reaction Time is the amount of time it takes to respond to anything.
4. Maryanne is driving directly south for a distance of 100 km. Her
trip takes 1 hour. During the drive, a police officer measures her
speed at 125 kilometers per hour. Which of the statements are
accurate about her drive? (Choose all that apply)
Her average velocity was 125 kilometers per hour south.
Her instantaneous velocity was always 125 kilometers per hour
south.
Her instantaneous velocity was always 100 kilometers per hour
south.
Her average velocity was 100 kilometers per hour south
At one point, her instantaneous velocity was 125 kilometers per
hour south.
The accurate statements are:Her average velocity was 100 kilometers per hour south.At one point, her instantaneous velocity was 125 kilometers per hour south.
The accurate statements about Maryanne's drive are:
Her average velocity was 100 kilometers per hour south. Average velocity is calculated by dividing the total displacement by the total time taken. In this case, since she drove directly south for a distance of 100 km in 1 hour, her average velocity is indeed 100 km/h south.
At one point, her instantaneous velocity was 125 kilometers per hour south. Instantaneous velocity refers to the velocity at a specific moment in time. Although her average velocity was 100 km/h south, there could have been moments during her drive where her speed reached 125 km/h south, indicating her instantaneous velocity.
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Stefan pushes a cart with three books so it just reaches the end of a track. He puts six books onto the cart. What must he use next time so the cart reaches the end of the track?
Answer:
if its adding its 9 if its multiplying its 18 if its division its 2
Nicki rides her bike at a constant speed for 6 km. That part of her ride takes her 1 hour. She then rides her bike at a constant speed for another 9 km. That part of her trip takes her 2 hours. What is her average speed?
The average speed of the Nicki would be 5 km/hr
What is speed?The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is meter/second. The generally considered unit for speed is a meter per second.
The mathematical expression for speed is given by
average speed = total distance /Total time
As given in the problem Nicki rides her bike at a constant speed for 6 km. That part of her ride takes her 1 hour. She then rides her bike at a constant speed for another 9 km. That part of her trip takes her 2 hours,
Total distance traveled by the Nicki = 6+9
=15 km
The total time = 1 + 2
=3 hours
Average speed = 15/3
=5 km/hr
Thus, her average speed comes out to be 5 km/hr.
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an ideal gas at 20centigree In a press 1.5×10pa and compress,a.isothamally,b.adaibatically until it volume in 1/3 in each case reversible.calculate in each case the final pressure and temperature of d gas (the ratio all specific capacity=Cp/Cv=1.4
a) The final pressure and temperature for the isothermal compression are \(4.5*10^5 Pa\) and 293 K, respectively, while b) the final pressure and temperature for the adiabatic compression are\(5.58*10^5 Pa\) and 515 K, respectively.
a. Isothermal compression:
For an isothermal process, the temperature remains constant. Therefore, we can use the ideal gas law:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature.
Since the process is isothermal, we can write:
\(P_1V_1 = P_2V_2\)
where P1 and V1 are the initial pressure and volume, and\(P_2\)and\(V_2\)are the final pressure and volume.
We are given that the volume is compressed to 1/3 of its original volume, so\(V_2 = (1/3)V_1\). Substituting this into the equation above gives:
\(P_2 = (V_1/V_2)P_1 = 3P_1\) = \(4.5*10^5 Pa\)
To find the final temperature, we can use the ideal gas law again:
PV = nRT
Rearranging, we get:
T = PV/(nR)
Substituting the values we know, we get:
T = (\(1.5*10^5\)Pa)(V1)/(nR)
Since the process is isothermal, the temperature remains constant, so the final temperature is the same as the initial temperature:
T2 = T1 = 293 K
b. Adiabatic compression:
For an adiabatic process, there is no heat transfer between the gas and its surroundings. Therefore, we can use the adiabatic equation:
PV^γ = constant
where γ = Cp/Cv is the ratio of specific heats.
Since the process is adiabatic and reversible, we can write:
\(P_1V_1\)^γ = \(P_2V_2\)^γ
We are given that the volume is compressed to 1/3 of its original volume, so V2 = (1/3)V1. Substituting this into the equation above gives:
\(P_2 = P_1(V_1/V_2)\)^γ = \(P_1\)\((3)^{(1.4)\) = \(5.58*10^5 Pa\)
To find the final temperature, we can use the adiabatic equation again:
\(T_2 = T_1(P_2/P_1)\)^((γ-1)/γ) = T1(5.58/1.5)^(0.4) = 515 K
Therefore, the final pressure and temperature for the isothermal compression are \(4.5*10^5 Pa\)and 293 K, respectively, while the final pressure and temperature for the adiabatic compression are \(5.58*10^5\) Pa and 515 K, respectively.
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A box puts a pressure of 50 N/m2 on an area of 0.25 m2. Find the force of the box on the floor.
A box puts a pressure of 50 N/\(m^{2}\) on an area of 0.25 \(m^{2}\). The force of the box on the floor is 12.5 Newton (N)
What is pressure and types?Pressure is defined as the physical force exerted on an object. The force applied is perpendicular to the surface of objects per unit area. The basic formula for pressure is \(\frac{F}{A}\) (Force per unit area). Unit of pressure is Pascals (Pa). Types of Pressures are Absolute, Atmospheric, Differential, and Gauge Pressure.
Using the formula Force = Pressure × Area
given Pressure = 50 N/\(m^{2}\)
area = 0.25 \(m^{2}\)
Substituting the values ,
Force = 12.5 Newton
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Look at the attached photo:
Answer:
C) Mass of the ball
Explanation:
Independent variable is the variable the researcher changes.
Since Martin is testing the mass of the ball, he'll be using different balls and that is the only thing he changes.
The distance traveled by the ball is the dependent variable since it depends on the mass of the ball.
The height and length of the ramp are the constant variables since that's the only ones that remain the same throughout this experiment.
What can happen when untreated sewage water contaminates water?
Answer:
Health Effects ↯Life-threatening human pathogens carried by sewage include cholera, typhoid and dysentery. Other diseases resulting from sewage contamination of water include schistosomiasis, hepatitis A, intestinal nematode infections, and numerous others.
Explanation:
BRAINLIEST PLEASE • •︴︴
____
The amount of work required for a
dump truck to move a mound of dirt 0
meters using a foree of 70 Newtons is
what?
Answer:
if I'm not wrong, 0 Joules
Explanation:
If it is not being moved at all, then no work is being done
A car starts from rest and accelerates to a speed of 30 m/s in a time of
3 seconds. The average acceleration of the car is ___m/s2
average acceleration is 10m/s2
Explanation:
average acceleration= final velocity- starting velocity/time
x=30-0/3
x=30/3
x=10
The velocity of a bob on a simple pendulum at the lowest position is 10.56 m/s. What is the maximum vertical height it is able to rise to?
um I do not know sorry
Explanation:
ummmmmmjjhfgfffff
The most common complaint among patients about their doctors is the time spent waiting in the doctor's office. Patients claim that doctors overbook appointments. Doctors claim that a significant number of patients fail to show or are late for their appointments. Doctors also note that as medical professionals they must tend to anyone who has need of their service. The medical profession is also uncertain because doctors never know when an emergency will occur. Considering the economic concepts of scarcity and economic resources, why must doctors book as many patients as necessary during office hours?
A doctor has the time and resources to choose how many patients to treat
A doctor, by law, must treat every patient who shows up in a medical facility
A doctor must make as much money as possible during normal business hours
A doctor's time is scarce and must be used effectively to see the most patients
Answer: B- a doctor, by law, must treat every patient who shows up in a medical facility
Explanation:
What type of image can be larger or smaller than the object?
A. An expansion
B. A magnification
C. A reduction
D. An enlargement
A pendulum consists of a weight tied by a string that is attached to the ceiling. The diagram models the motion of the pendulum as it swings from the left to the right, then back to the left. Points A-G show the different locations of the weight as it moves. ceiling Which answer correctly states the energy transformation between two points? O Kinetic energy is transformed to potential energy from points G to E. O Kinetic energy is transformed to potential energy from points B to D. O Potential energy is transformed to kinetic energy from points A to C. O Potential energy is transformed to kinetic energy from points D to C.
Pendulum under goes energy conversions from potential to kinetic and back to potential.
A pendulum consists of a long string to which a bulb is attached. The string is fastened to a point from which it can oscillate freely when displaced through a small angle.
The pendulum is an example of a system in which energy conversion takes place. The energy is converted from potential to kinetic and back to potential. Since the image was not shown in the question, we can not locate the specific points where the energy conversions occur.
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the use of solar energy should be increase in the context of Nepal.justify the statement
Answer:
The solar potential in Nepal is 50,000 terawatt-hours per year, which is 100 times larger than Nepal's hydro resource and 7,000 times larger than Nepal's current electricity consumption. Solar can easily meet all future energy needs in Nepal. Solar energy is cheaper than fossil fuels, nuclear and hydro.