Circuit breakers and fuses are important safety features of circuits because _____.Select one:a.they decrease the voltage of the circuit b.they decrease the resistance of the circuit c.they interrupt the flow of excess currentd.all of the above

a) The total surface area of tin G in terms of π is 170π cm².

b) The mass of tin H is 336 g.

To solve the given problem, we need to determine the total surface area of tin G in terms of π and the mass of tin H. Since the mass of an empty cylindrical tin is proportional to its surface area, we can use the given information to find the solutions.

a) Total surface area of tin G in terms of π:

The surface area of a cylinder consists of two circular bases and the lateral surface area. The formula for the lateral surface area of a cylinder is given by:

Lateral surface area = 2πrh

where r is the radius of the base and h is the height of the cylinder.

In the case of tin G, the given dimensions are a radius of 5 cm and a height of 12 cm. Substituting these values into the formula, we can calculate the lateral surface area:

Lateral surface area = 2π(5 cm)(12 cm)

Lateral surface area = 120π cm²

Since the total surface area of the cylinder includes the two circular bases as well, we need to add their areas. The area of a circle is given by:

Area of a circle = πr²

The radius of the circular base of tin G is 5 cm, so the area of each circular base is:

Area of each circular base = π(5 cm)²

Area of each circular base = 25π cm²

To find the total surface area of tin G, we sum the lateral surface area and the areas of the two circular bases:

Total surface area of tin G = Lateral surface area + 2 × Area of each circular base

Total surface area of tin G = 120π cm² + 2 × 25π cm²

Total surface area of tin G = 120π cm² + 50π cm²

Total surface area of tin G = 170π cm²

Therefore, the total surface area of tin G in terms of π is 170π cm².

b) Mass of tin H:

We are given that the surface area of tin H is 792π cm². We can assume that the same proportionality factor applies as in tin G, so we can set up the following proportion:

(surface area of tin G) / (mass of tin G) = (surface area of tin H) / (mass of tin H)

Using the given values, we have:

(170π cm²) / (72 g) = (792π cm²) / (mass of tin H)

Cross-multiplying and solving for the mass of tin H, we get:

(170π cm²) × (mass of tin H) = (72 g) × (792π cm²)

mass of tin H = (72 g) × (792π cm²) / (170π cm²)

mass of tin H = 336 g

Therefore, the mass of tin H is 336 g.

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The models provide important tools for understanding the strong force interactions within a proton.

The strong force interactions between quarks and gluons within a proton are described by Quantum Chromodynamics (QCD), which is a fundamental theory of the strong nuclear force in particle physics. QCD is a non-Abelian gauge theory, meaning that the interactions between the quarks and gluons are highly nonlinear and non-perturbative.

One of the most promising theoretical models for describing the strong force interactions within a proton is lattice QCD, which is a numerical approach that uses a discrete grid to represent the space-time continuum. Lattice QCD allows for the calculation of QCD observables from first principles, without resorting to perturbative expansions. This method can handle non-perturbative effects such as confinement and chiral symmetry breaking by allowing for the simulation of the strong interactions on a discrete space-time grid

Another promising model is effective field theory, which provides a way to describe the low-energy behavior of QCD by constructing an effective Lagrangian that contains only the degrees of freedom relevant to a particular energy scale. This allows for the calculation of QCD observables in a systematic expansion in powers of a small parameter, such as the ratio of the quark mass to the QCD energy scale.

Chiral perturbation theory is another effective field theory that focuses on the dynamics of light quarks, which are the building blocks of pions, the lightest hadrons. Chiral perturbation theory provides a systematic expansion for the interactions between pions and nucleons, and can be used to calculate the properties of these particles at low energies.

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Answer:

For the first one, its B) cities B and C

I'm not so sure, but I hope this helps.

Answer:

θ = 90º

Explanation:

The velocity is given by

          v = \(\frac{dr}{dt}\)

calculate

          v = 3 i ^ + √2 j ^ + 2t k ^

acceleration is defined by

         a = dv / dt

         a = 2 k ^

one way to find the angle is with the dot product

         v. a = | v | | a | cos θ

         cos θ= v.a / | v | | a |

Let's look for the value of each term

       v. a = 4 t

        | v | = \(\sqrt{3^2 + 2 + (2t)^2 }\) = \(\sqrt{ 11 + 4t^2}\)

        | a | = 2

they ask us for the angle for time t = 0

         v. a = 0

        | v | = √11 = 3.317

we substitute

        cos θ = 0 /√11

        cos θ = 0

therefore the angles must be θ = 90º

Answer:

current I = 38 mA

Explanation:

given data

distance r = 7.2 cm

repel each other force per unit length \frac{F}{l} = 4.2 nN/m

solution

we know 2  wire is parallel and when current flow through these wire they exert force each other due to magnetic field

and current I(1) = I(2)   ................1

so

\(\frac{F}{l} = \frac{\mu _o}{2\pi } \times \frac{I(1) \times I(2)}{r}\)     ..................2

put here value

4.2 × \(10^{-9}\) = \(\frac{4\pi \times 10^{-7}}{2\pi } \times \frac{I^2}{7.2\times 10^{-2}}\)    

solve it we get

I = 0.038884 A

current I = 38 mA

The current flow in the wires will be:

"38 mA".

According to the question,

Distance, r = 7.2 cm

Force per unit length, \(\frac{F}{l}\) = 4.2 nN/m

Current passes, when wire is parallel:

→ I₁ = i₂

We know the relation,

→           \(\frac{F}{l}\) = \(\frac{\mu_0}{2 \pi}\times \frac{I_1\times I_2}{r}\)

By substituting the values, we get

4.2 × 10⁻⁹ = \(\frac{4 \pi\times 10^{-7}}{2 \pi}\times \frac{I^2}{7.2\times 10^{-2}}\)

hence,

The current will be:

              I = 0.038884 A or,

                = 38 mA

Thus the above answer is appropriate.

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The speed of the ball rebounding from the plate is approximately 13.2 m/s.

According to the graph, the greatest force exerted by the football on the force plate during impact is around 1900 N. The ball comes to a halt on the force plate before rebounding.

The kinetic energy of the ball before impact equals the kinetic energy of the ball after the rebound, according to the law of conservation of energy.

The speed of the ball rebounding can be calculated using the formula:

(1/2)mv²= (1/2)mv_0²

where m is the mass of the ball (0.43 kg), v is the speed of the ball rebounding, and v_0 is the initial speed of the ball (15 m/s).

Solving for v, we get:

v = sqrt(v_0² - (2F/m))

where F is the maximum force exerted on the force plate (1900 N).

Plugging in the values, we get:

v = sqrt(15² - (2*1900/0.43)) ≈ 13.2 m/s

Therefore, the speed of the ball rebounding from the plate is approximately 13.2 m/s.

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The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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The density of water being approximately 1000 kg/m³ and acceleration due to gravity being approximately 9.8 m/s², the depth is calculated to be approximately 10.2 meters, while assuming Atmospheric pressure at sea level.

The pressure at any point in a fluid (like water) is given by:

pressure = density x gravity x depth

where density is the density of the fluid, gravity is the acceleration due to gravity, and depth is the depth of the point below the surface.

At sea level, the atmospheric pressure is 10⁵ N/m². This means that the pressure at any point below sea level in water will be higher than 10⁵ N/m².

To find the depth at which the pressure is equal to 10⁵ N/m², we can rearrange the above equation as:

depth = pressure / (density x gravity)

The density of water is approximately 1000 kg/m³, and the acceleration due to gravity is approximately 9.8 m/s². Substituting these values and the given pressure of 10⁵ N/m², we get:

depth = 10⁵ N/m² / (1000 kg/m³ x 9.8 m/s²)

depth = 10.2 meters

Therefore, the depth at which the pressure is equal to atmospheric pressure at sea level (10⁵ N/m²) in water is approximately 10.2 meters.

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Answer:

KE=1/2 mv² = FD

where FD =umgd , thus,

1/2mv²= umgd

1/2v² =ugd

v² = 2 ugd

v =√2ugd

v=√2(0.3)(9.81)(78)

v=21.4m/s

Vehicles need to be serviced for several reasons such as preventing costly repairs and improving fuel economy.

First, regular maintenance can help to prevent costly repairs down the road. Second, maintenance can help to improve fuel economy and emissions. Third, maintenance can help to keep your vehicle safe and reliable.

The servicing requirements for petrol/diesel and electric vehicles differ in a number of ways. Petrol/diesel vehicles require oil changes more frequently than electric vehicles. This is because petrol/diesel engines use oil to lubricate the moving parts, while electric motors do not. Petrol/diesel vehicles also require tune-ups more frequently than electric vehicles.

This is because petrol/diesel engines have more moving parts that need to be synchronized, while electric motors have fewer moving parts.

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Given Information:

Power = P = 100 Watts

Voltage = V = 220 Volts

Required Information:

a) Current = I = ?

b) Resistance = R = ?

Answer:

a) Current = I = 0.4545 A

b) Resistance = R = 484 Ω

Explanation:

According to the Ohm’s law, the power dissipated in the light bulb is given by

\(P = VI\)

Where V is the voltage across the light bulb, I is the current flowing through the light bulb and P is the power dissipated in the light bulb.

Re-arranging the above equation for current I yields,

\(I = \frac{P}{V} \\\\I = \frac{100}{220} \\\\I = 0.4545 \: A \\\\\)

Therefore, 0.4545 A current is flowing through the light bulb.

According to the Ohm’s law, the voltage across the light bulb is given by

\(V = IR\)

Where V is the voltage across the light bulb, I is the current flowing through the light bulb and R is the resistance of the light bulb.

Re-arranging the above equation for resistance R yields,

\(R = \frac{V}{I} \\\\R = \frac{220}{0.4545} \\\\R = 484 \: \Omega\)

Therefore, the resistance of the bulb is 484 Ω

Answer:

bulb will burn out!

Explanation:

Answer:

Explanation:

Force of friction

F = μ mg

μ is coefficient of friction , m is mass and g is acceleration due to gravity .

If f be the force applied to pull the sled , the horizontal component of force should be equal to frictional  force

The vertical component of applied force will reduce the normal force or reaction force from the ground

Reaction force R = mg - f sin28.3

frictional force = μ R where μ is coefficient of friction

frictional force = μ x (mg - f sin28.3 )

This force should be equal to horizontal component of f

μ x (mg - f sin28.3 ) = f cos 28.3

μ x mg = f μsin28.3 + f cos 28.3

f = μ x mg / (μsin28.3 + cos 28.3 )

a )

work done by pulling force  = force x displacement

f cos28.3 x d

μ x mg d cos28.3  / (μsin28.3 + cos 28.3 )

b ) Putting the given values

= .155 x 53.1 x 9.8 x 25.3 cos28.3 / ( .155 x sin28.3 + cos 28.3 )

= 1796.76 / (.073 + .88 )

= 1885.37  J

c )

Work done by frictional force

= frictional force x displacement

=  -  μ x (mg - f sin28.3 ) x d  

= -  μ x mgd + f μsin28.3  x d

= -  μ x mgd + μsin28.3  x d x μ x mg / (μsin28.3 + cos 28.3 )

d )

Putting the values in the equation above

- .155 x 53.1 x 9.8 x 25.3 +

.155 x .474 x 25.3 x .155 x 53.1 x 9.8 /( .155 x .474 + .88)

= -2040.67 + 149.92 / .95347

= -2040.67 + 157.23

= -1883.44 J .

Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe.

Galileo Galilei played a crucial role in challenging the prevailing geocentric model of the universe proposed by Aristotle and supported by Ptolemy. He provided several lines of evidence that effectively disproved their theories and supported the heliocentric model proposed by Nicolaus Copernicus. Some of the key evidence used by Galileo includes:

1. Observations through a telescope: Galileo was one of the first astronomers to use a telescope to observe the heavens. His telescopic observations revealed several important discoveries that contradicted the Aristotelian-Ptolemaic worldview. He observed the phases of Venus, which demonstrated that Venus orbits the Sun and not Earth. He also observed the four largest moons of Jupiter, now known as the Galilean moons, which provided evidence for celestial bodies orbiting a planet other than Earth.

2. Sunspots: Galileo's observations of sunspots provided evidence that the Sun is not a perfect celestial body, as suggested by Aristotle. Sunspots indicated that the Sun has imperfections and undergoes changes, challenging the notion of celestial perfection.

3. Mountains on the Moon: Galileo observed the rugged and uneven surface of the Moon, which contradicted Aristotle's belief in celestial spheres made of perfect, unchanging material. The presence of mountains on the Moon suggested that celestial bodies are subject to the same physical laws as Earth.

4. Phases of Venus: Galileo's observations of the phases of Venus provided direct evidence for the heliocentric model. As Venus orbits the Sun, it goes through phases similar to the Moon, ranging from crescent to full. This observation strongly supported the idea that Venus revolves around the Sun.

These lines of evidence presented by Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe. His work marked a significant turning point in the history of science and laid the foundation for modern astronomy.

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Answer:

\(E=4.5*10^-^9J\)

Explanation:

From the question we are told that:

Capacitor \(C=1.0nf\)

Induction \(I=3.0mH\)

Voltage \(V=3.0\)

Generally the equation for Max charge on Capacitor  is mathematically given by

\(Q_{max}=C*V\)

\(Q_{max}=1*10^{-9}*3\)

\(Q_{max}=3*10^{-9}C\)

Generally the equation for Energy in  magnetic field of the coil  is mathematically given by

Since

Energy stored in capacitor = Energy in magnetic field of the coil

Therefore

 \(E = (1/2)* C * V^2\)

 \(E= 0.5 * 1*10^{-9} *3^2\)

 \(E=4.5*10^-^9J\)

Answer:

-0.209 kg.m/s

Explanation:

The mass of the ball, m = 275g or 0.275 kg

Speed or velocity, v = 2.60 m/s

Momentum, P = mv

Momentum when velocity is 2.60 = 0.275 x 2.60 = 0.715 kg.m/s

Speed or velocity, v = 1.84 m/s

Momentum, P = mv

Momentum when velocity is 1.84= 0.275 x 1.84 = 0.506 kg.m/s

Change in magnitude =  0.506 - 0.715 = -0.209 kg.m/s

Potential energy is a form of accumulated energy that an item or set of objects may have depending on their size, shape, location, or even substance.

Potential energy is the energy retained by an object as a result of its location relative to other objects, internal stresses, electric charge, or other variables. Although it has ties to the old Greek philosopher Aristotle's idea of potentiality, the word potential energy was coined by the 19th-century Scottish engineer and physicist William Rankine.

The gravitational potential energy of an object, the elastic potential energy of a stretched spring, and the electric potential energy of an electric charge in an electric field are all examples of common kinds of potential energy.

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Answer:

Explanation:

This depends on the height.

Using the formula mgh + 1/2mv^2 = total mechanical energy, we can determine the amount of kinetic and potential energy. I'm assuming your talking about if the marble goes all the down, then all of the energy is converted.

Answer:

The second one says cant open file............

A beaver runs at a speed of 2.0 m/s with 45 J of kinetic energy, then the mass is approximately 1.74 kg, and this can be calculated by using the  kinetic energy (KE) of an object that is KE = (1/2) ×m × \(v^2\).

KE = (1/2) ×m × \(v^2\).

where m= mass of the object, v=its velocity.

The beaver runs at a speed of 2.0 m/s with 45 J of kinetic energy. Substituting these values into the above equation

45 J = (1/2) ×m × \((2.0 m/s)^2\)

Simplifying this equation:

45 J = (1/2) × m × 4.0\(m^2/s^2\)

45 J = 2 m × 2 \(m^2/s^2\)

45 J = 4 \(m^3/s^2\)

\(m^3\) = 45 J / 4 \(s^2\)

\(m^3\) = 11.25 kg×\(m^2/s^2\)

Taking the cube root of both sides to solve for mass,

m = (11.25 kg×\(m^2/s^2)^(^1^/^3^)\)

m = 1.74 kg (rounded to two decimal places)

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Answer:

a) V = 0.24 m/s

b) v = 1.53 m/s

Explanation:

In this case, we are asked to find two values that are pretty similar and use the same units, however, there are differences between them.

The average velocity is often referred to a vector quantity, therefore, if time is a scalar magnitude, we need to find the vector quantity of distance. In this case, is the displacement, which is also referred as a vector.

So, to calculate the average velocity we need to determine first the displacement of the person. As the person heads east and then west, his total displacement (D) is:

D = 55 - 40 = 15 m

Now the total time would be the time taken to go to the windmill and then, to a bench:

t = 25 + 37 = 62 s

Finally, the average speed is:

V = D/t

V = 15 / 62

The average speed is a scalar magnitude, so we use the covered distance by the person (d) and the total time:

d = 40 + 55 = 95 m

Then, the speed:

v = 95/62

Hope this helps

The buoyant force on the cannon stays the same as long as it is fully under water because the buoyant force is determined by the volume of fluid that the cannon displaces and not by the weight or mass of the cannon itself.

Archimedes' Principle states that the buoyant force on an object in a fluid is equal to the weight of the fluid that the object displaces. This means that as long as the cannon remains fully submerged in the water and does not change its volume, the amount of water it displaces and thus the buoyant force on the cannon will also remain the same.

In other words, the buoyant force is dependent on the fluid's density and the volume of the object, not its weight. So, as long as the volume of the cannon and the density of the fluid surrounding it remain constant, the buoyant force will also stay constant.

The buoyant force on the cannon will stay the same as long as it is fully under water.

The buoyant force on an object is equal to the weight of the fluid displaced by the object. The buoyant force is always directed upwards, and it opposes the force of gravity. As long as the cannon is fully under water, the amount of water displaced by the cannon will stay the same. This means that the buoyant force on the cannon will also stay the same.

The buoyant force on an object depends on the density of the fluid, the volume of the object, and the acceleration due to gravity. The density of water is constant, so the buoyant force on the cannon will only change if the volume of the cannon changes or if the acceleration due to gravity changes.

Neither of these factors change. The volume of the cannon does not change as it is being recovered from the shipwreck. The acceleration due to gravity also does not change, as it is the same on Earth's surface as it is underwater.

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The angular velocity in radians per second, given that Microwave ovens rotate at a rate of about 5 revolutions per minute (rpm) is 0.50 radians per second

The angular velocity (in radians per second) can be obtained by simply converting 0.08 revolution per second to radians per second. This is obtained as illustrated below:

1 revolution per second = 2π radians per second

Therefore,

0.08 revolution per second = 0.08 × 2π

Recall

Pi (π) = 3.14

Thus,

0.08 revolution per second = 0.08 × 2 × 3.14

0.08 revolution per second = 0.50 radians per second

Thus, we can conclude that the angular velocity (in radians per second) is 0.50 radians per second

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The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

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Answer:

Efficiency of the system = 100%

Explanation:

Given:

Input energy = 100 J

Potential energy load = 60 J

Find:

Efficiency of the system

Computation:

Efficiency of the system = [Potential energy load/Input energy]100

Efficiency of the system = [60/100]100

Efficiency of the system = 100%

Answer:

Its the last one.

Explanation:

Massive objects such as earth generate gravity, and the moon orbits the earth as it is smaller and close enough.

Answer: The dependent Variables include: Size and Types of trees.

The independent Variables include:

geographic elevations that is, valleys and the higher elevations.

Explanation:

The dependent variable simply refers to the variable a researcher tests or measures during an experiment. On the other hand, the independent variable simply refers to the variable that's controlled during an experiment.

Based on the definition above, the dependent variables include the size and the types of trees while the independent variables include the

geographic elevations that is, the valleys and the higher elevations.

If a person walks 1km north, 5 km West, 3km south, and 7km east, then the resultant displacement vector would be 2.82 km toward the south east direction

What is displacement?

When an object moves in connection to a reference frame, such as when a passenger travels to the back of an airliner or a professor walks to the right in relation to a whiteboard, its position changes. This movement in position is described as displacement.

as stated in the issue If a person goes one kilometre north, five kilometres west, three kilometres south, and seven kilometres east,

The resulting displacement vector, as we know, is the shortest feasible distance between the beginning and ending points

In the horizontal direction, the outcome is

7-5 pointing east

2 kilometres to the eas

In the vertical direction, the outcome is

3–1 km to the south

2 kilometres to the south

\($\begin{aligned} \text { Resultant displacement } &=\sqrt{ }\left(2^{2}+2^{2}\right) \\ &=2 \cdot \sqrt{2} \\ &=2.82 \end{aligned}$\)

As a result, the resulting displacement vector is 2.82 kilometres to the southeast.

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Answer:

74.0 meters

Explanation:

We can use the kinematic equation for displacement with constant acceleration to solve this problem:

Δy = v0t + 1/2at^2

where Δy is the displacement (i.e., the change in height), v0 is the initial velocity (which is 0), a is the constant acceleration, and t is the time taken.

Plugging in the given values, we get:

Δy = 0 + 1/2(71.0 m/s^2)(1.45 s)^2

Δy = 74.0 m

Therefore, the maximum altitude achieved by the rocket is 74.0 meters above the ground.

The energy required by the heating process is 0.042 candy bars.

We'll begin by calculating the mass of the water.

Mass = Density × Volume

Mass of water = 1000 × 5×10¯⁴

Mass of water = 0.5 Kg

Next, we shall determine the heat required

Q = MCΔT

Q = 0.5 × 1 × 25

Finally, we shall convert 12.5 Kcal to candy bar.

300 Kcal = 1 candy bar

Therefore,

12.5 Kcal = 12.5/300

12.5 Kcal = 0.042 candy bars

Therefore, the energy required in candy bar is 0.042 candy bars

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Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.

To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.

In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.

To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.

Total cost covered by the five friends = Total cost - Cost of one person's meal

= (£12 x 6) - £12

= £72 - £12

= £60

Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).

Amount each friend needs to pay = Total cost covered by the five friends / Number of friends

= £60 / 5

= £12

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