The distance among the two slits is 1.73 x 10⁻³ cm.
The third black fringe will appear 0.627 cm from the center of the dazzling fringe.
(a) The distance between the central bright fringe and the third bright fringe is given by:
Δy = (nλD) / d
where Δy is the distance between the central fringe and the nth bright fringe, λ is the wavelength of the light, D is the distance between the slits and the screen, and d is the distance between the slits.
Substituting the given values, we get:
3.11 cm = (1 x 632.8 nm x 85.0 cm) / d
Solving for d, we get:
d = (1 x 632.8 nm x 85.0 cm) / 3.11 cm = 1.73 x 10⁻³ cm
Therefore, the distance between the two slits is 1.73 x 10⁻³ cm.
(b) The distance between the central bright fringe and the nth dark fringe is given by:
Δy = [(2n - 1)λD] / (2d)
where Δy is the distance between the central fringe and the nth dark fringe, λ is the wavelength of the light, D is the distance between the slits and the screen, and d is the distance between the slits.
Substituting the given values and n=3, we get:
Δy = [(2 x 3 - 1) x 632.8 nm x 85.0 cm] / (2 x 1.73 x 10⁻³ cm) = 0.627 cm
Therefore, the third dark fringe will occur 0.627 cm away from the central bright fringe.
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A. the distance between the two slits is approximately 12.8 micrometers. B. the third dark fringe will occur at a distance of approximately 0.557 cm from the central bright fringe.
What is slit?Slit is a term used to refer to a long, narrow opening or gap. It is most commonly used to describe a thin cut in a piece of material or a surface. Slits are used in a variety of fields, including engineering, manufacturing, and architecture.
A. The distance between the two slits can be calculated using the equation:
d sinθ = mλ
First, we need to calculate the wavelength of the light using the frequency:
\(\lambda = c/f = (3.00 \times 10^8 m/s) / (6.32 \times 10^{14} Hz) = 4.74 \times 10^{-7} m\)
\(tan \theta = (3.11 cm) / (85.0 cm)\)
\(\theta = tan^{-1} (3.11 cm / 85.0 cm) = 2.10^{\circ}\)
Finally, we can substitute the values into the equation and solve for d:
\(d = m\lambda / sin\theta = (3)(4.74 \times 10^{-7} m) / sin(2.10^{\circ}) \approx 1.28 \times 10^-5 m = 12.8 \mu m\)
Therefore, the distance between the two slits is approximately 12.8 micrometers.
B. The distance from the central bright fringe to the third dark fringe can be calculated using the equation:
\(y = (m + 1/2) (\lambda d)\\y = (m + 1/2) (\lambda D/d) = (3 + 1/2) (4.74 \times 10^{-7} m) (85.0 cm) / (12.8 \times 10^{-6} m) \approx 0.557 cm\)
Therefore, the third dark fringe will occur at a distance of approximately 0.557 cm from the central bright fringe.
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Eugene works at a carpet factory. Which natural polymer does he most likely work with to make the carpets?
wool
rubber
nylon
silk
Answer:wool not nylon
Explanation:
Answer:
A. Wool
Explanation:
How far can a mother push a 20.0 kg baby carriage, using a force of 62.0 N if she can do 2920 J of work
The mother can push the 20.0 kg baby carriage a distance of approximately 47.1 meters using a force of 62.0 N.
To determine the distance the mother can push the baby carriage, we need to use the work-energy principle, which states that the work done on an object is equal to the change in its kinetic energy. In this case, the work done by the mother is given as 2920 J.
The work done can be calculated using the formula: work = force × distance. Rearranging the formula to solve for distance, we have distance = work / force.
Substituting the given values, distance = 2920 J / 62.0 N = 47.1 meters (rounded to one decimal place).
Therefore, the mother can push the 20.0 kg baby carriage a distance of approximately 47.1 meters using a force of 62.0 N.
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Nearsight Company manufactures glasses. The actual costs for 2019 and 2020 were as follows: 2019 2020 Direct materials: Plastic frames $ 4.00 $ 3.80 Lens set 17.00 17.20 Direct labor 32.00 (1.6 hours) 30.00 (1.5 hours) Indirect manufacturing costs: Variable 8.00 7.10 Fixed 2.00 (50,000 units) 1.60 (60,000 units) Beginning in 2020, Nearsight implemented a continuous improvement program that required a first-year cost reduction target of a 5 percent reduction of the 2019 base. Nearsight's continuous improvement target for plastic frames in 2020 was:
The continuous improvement target for plastic frames in 2020 was set at $3.80.
How much was the continuous improvement target for plastic frames in 2020?This target was determined as a result of Nearsight Company's efforts to reduce costs through their continuous improvement program. The program aimed to achieve a 5% reduction from the 2019 base costs. In the case of plastic frames, which had a cost of $4.00 in 2019, the target cost was calculated by subtracting the reduction amount of $0.20 from the 2019 cost.
By setting this target, Nearsight Company aimed to streamline their manufacturing processes, identify cost-saving opportunities, and enhance the overall efficiency of producing plastic frames. This would contribute to improved profitability and competitiveness in the eyeglass manufacturing industry.
Therefore, the continuous improvement target for plastic frames in 2020 was $3.80.
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how would the europa clipper mission deal with the special hazard that faces any spacecraft that tries to study europa close-up?
NASA's Europa Clipper will conduct detailed reconnaissance of Jupiter's moon Europa and investigate whether the icy moon could have conditions suitable for life.
The magnetometer investigation aims to confirm that Europa's ocean exists, measure its depth and salinity, and measure the moon's ice shell thickness. It will also study Europa's ionized atmosphere and how it interacts with Jupiter's ionized atmosphere. On February 10, 2021, it was announced that the mission would use a 5.5-year trajectory to the Jovian system, with gravity-assist maneuvers involving Mars (February 2025) and Earth (December 2026). Europa Clipper's main science goal is to determine whether there are places below Europa's surface that could support life. Jupiter's moon Europa shows strong evidence for an ocean of liquid water beneath its icy crust.
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If the temperature of a fixed amount of an ideal gas is increased, it NECESSARILY follows that a. the volume of the gas will increase. b. the pressure of the gas will increase. c. its entropy decreases. d. the speed of the gas molecules will increase. e. All of these statements are correct.
The correct statements is (e) all of the above statements.
What is ideal gas?A theoretical gas called an ideal gas is one that has plenty of point particles flying around arbitrarily and without being affected by other particles.
The ideal gas notion is advantageous because it complies with the ideal gas law, a condensed equation of state, and is amenable to statistical mechanics analysis.
According to the Ideal Gas Law, the product of the pressure, volume, and temperature of an ideal gas is constant ( PV = nRT) when the number of moles, n, is held constant.
This means that if the temperature of a fixed amount of an ideal gas is increased, the volume and the pressure of the gas will also increase, and the speed of the gas molecules will increase. However, the entropy will increase, not decrease.
So, the correct answer is a. the volume of the gas will increase. b. the pressure of the gas will increase. d. the speed of the gas molecules will increase.
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A ball is dropped from a window and bounces three times. The first bounce is 60 centimeters high. The second bounce is 40 centimeters high. The third bounce is 15 centimeters high.The ball then rolls and comes to a stop.What has happened to the energy of the ball when it has come to a stop?answer choicesThe potential energy of the ball has decreased.The kinetic energy of the ball has increased.The potential energy has been transformed into kinetic energy.The potential energy of the ball has increased during energy transfer.
The potential energy of the ball has increased during energy transfer.
If the ball rolls and stops, the kinetic energy from rolling and friction turns into potential energy.
Potential energy is relative position, kinetic energy is relative to motion.
The main relationship between the two is their ability to transform into each other. That is, potential energy turns into kinetic energy, kinetic energy turns into potential energy, and back again. It's an endless cycle.
Let's look at another example. Suppose there is a book on the table.
When the book is at rest, it has potential energy. However, if you accidentally drop it off the table, that potential energy is converted into kinetic energy, causing the book to move and fall. However, as soon as the book hits the ground, this kinetic energy is converted into potential energy.
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A bicycle travels 22 km in 0.50 hr. What is its average speed?
Answer:
22/0.50=44
Explanation:
average speed= distance / time
Which statement best explains why there could be a force of attraction
between two electrically charged objects?'
because they have like charges
because they have unlike charges
because they have the same number of protons
because they have the same number of electrons
used to accurately measure the volume of solutions when adding a solid to be dissolved
To make the solute dissolve, thoroughly mix and add a little quantity of solvent after transferring the solute to a container
What is a solute?A solute is a material dissolved in another substance known as a solvent in a homogeneous mixture made of two or more components.
A solute's concentration in a solution is a measure of how much of that solute is dissolved in the solvent and the amount of solvent present, such as salt. Solutes are the best cleaning agents and additives.
Add a little quantity of solvent after transferring the solute to a container ideally a volumetric flask,
Which most precisely measures the volume of the solution indicated on the flask. To make the solute dissolve, thoroughly mix.
Hence the above process should be followed to dissolve, and thoroughly mix.
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When a 4-kg ball is thrown upwards at 40 m/s, at what
height is the potential energy equal to the kinetic
energy
Answer:
the height of the potential energy is 3,200 J
Explanation:
The computation of the kinetic energy is shown below:
Kinetic energy = 1 ÷ 2 × mass × velocity^2
= 1 ÷ 2 × 4 kg × 40 m/s^2
= 3,200 J
Hence the height of the potential energy is 3,200 J
* Question Completion Status: Moving to another question will save this response. Question 29 Which one of the following statements is not true? (choose all apply) O UV radiation is a type of ionizing
One statement that is not true is that UV radiation is a type of electromagnetic radiation. It is also a type of ionizing radiation. UV radiation is actually a form of non-ionizing radiation.
UV radiation, or ultraviolet radiation, is a type of electromagnetic radiation that falls between visible light and X-rays on the electromagnetic spectrum. It is often categorized into three types: UVA, UVB, and UVC. Unlike ionizing radiation, such as X-rays and gamma rays, which have enough energy to remove tightly bound electrons from atoms or molecules, UV radiation lacks the necessary energy to ionize atoms or molecules. Instead, it primarily interacts with the outermost electrons of atoms or molecules, leading to chemical reactions and causing biological effects.
UV radiation is commonly associated with sunlight and has various effects on living organisms and materials. It can cause sunburn, premature aging of the skin, and an increased risk of skin cancer. Exposure to excessive UV radiation can also damage the eyes and impair the immune system. It is important to protect oneself from excessive UV exposure by wearing sunscreen, protective clothing, and sunglasses.
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When 0. 7521 g of benzoic acid was burned in a calorimeter containing 1,000. G of water, a temperature rise of 3. 60°c was observed. What is the heat capacity of the bomb calorimeter, excluding the water? the heat of combustion of benzoic acid is –26. 42 kj/g.
The heat capacity of the bomb calorimeter, excluding the water is 1.3 ×\(10^{3}\)
Given data
mass of water ( Mwater ) = 1000 g
Specific heat of water ( (water ) = 4.184 3 / g. oc
Change in temperature ( T ) = 3. 60 C
mass of benzoic acid ( m ) = 0.7521 9
Heat of combustion of benzoic acid ( q ) =- 26.42 k3/g
Heat capacity of bomb calorimeter ( Ccal ) = ?
First , we will find out how much heat released in the reaction .
q rn = m x a
Now , we will calculate the heat capacity of bomb
calorimeter C ( cal )
q rn = ( ( mwater ) X ( Cwater ) * ΔT ) + ( Ccal * ΔT )
- 19870 J = - (1000 g ) x ( 4. 18 4 3 x ( 3.60 ) ) + ( Ccal x 3.60 )
( 1000g ) * ( 4:284 3 /8 9 ) x ( 3.60 " c ) ) + ( Ceal * 3.60 ( ) = 198 70 ]
15062 + Ccal 3. 60 = 19870 j
Ccal 3.60 = 4807. 6 j
Ccal = 4807. 6 J/ 3.60 = 1335.43 j/degree Celsius
Ccal = 1. 3 x \(10^{3}\) kj /degree Celsius
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Friction is a ____________ force
a. Artificial
b. Natural
c. Pessimistic
d. Negative
Answer:
natural is the answer
Friction is a natural force which exist
will give brain list plz help
Which is not a feature common to all electric circuits?
an electrochemical cell
a resistant device
conducting wires
an energy source
Answer:
An electric chemical cell is not always needed to have a power circuit. But every other part is.
2) Which type of bond will form between these elements?
WHICH BOND?
Which mathematically describes the wave properties of electrons?.
Answer:
On Waves. Quantum mechanically, an electron can be described by a wave function oscillating in space and time that has mean values equal to the expectation values of observables corresponding to given operators. ... Electrons are fermions. They are charged particles. in short the quantum theory
i hope its helpful !
Calculate the density of the football. Use the formula D = m/V where D is the density, m is the mass, and V is the volume. Record your calculations in Table B of your Student Guide. What is the density of the football?
Answer:
0.10
Explanation:
I know because I got it right
Answer:
0.10 cm3
Explanation:
PLEASE HELP MY WHOLE GRADE-DEPENDS ON THIS
A motorboat whose speed in water is 5.00 m/s must aim upstream at an angle of 47.5° above the
horizontal in order to travel directly across the river. A. Diagram the physical scenario and add the triangle (2 pt). B. What
is the speed of the river (1 pt)? C. What is the resultant speed of the boat with respect to the shore (1 pt)? D. If the opposite
shore is 191 meters away, how long will it take to get across (1 pt)?
Answer:
C.
Explanation:
Because the speed pf the boat will depends of the driver.
Pleeeease help! I'll give brainliest if possible!! :)))
Use the scenario to answer the question.
An astronomer discovers a new galaxy using a telescope. The astronomer wants to investigate how the galaxy is moving relative to the Milky Way galaxy.
In one or two sentences, make a hypothesis about the movement of the galaxy and explain at least one way to test the hypothesis.
The most scientific guess (hypothesis) based on what is known about the behavior of galaxies is that Galaxies are continuously moving away from each other. This hypothesis can be tested using Hubble's Law.
What does Hubble's Law Say?Hubble's law indicates that almost all galaxies are moving apart from one another because the universe as a whole is expanding. Choose any two galaxies at arbitrarily, and they're most likely traveling apart from each other.
Hubble discovered that galaxies move away from us at a rate proportionate to their distance: more distant galaxies move away faster than closer ones. The accompanying graphic shows Hubble's classic graph of measured velocity vs. distance for neighboring galaxies.
The graph shows a linear relationship between galaxy velocity (v) and distance (d).
The equation for the above linear relationship is:
v = H₀ x d
Where:
H₀ is the expansion rate
v = velocity of the galaxy; and
d = distance.
Using the above formula, the astronomer can measure or test to know whether indeed the new galaxy is moving relative to the Milky Way galaxy and at what rate.
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What are three things you already know about the game of baseball?
Answer:
You only have 12 Seconds to Pitch
A baseball game usually lasts 3 hours long
The record of most home runs in a baseball match by one person is 4
Explanation:
I hope this helps u
Gravitational force between two masses m, and m, is represented as F Gm₂ m₂ 7 where = xi+yj + zk and Irl=√√x² + y² + z² G,m,, m₂ are nonzero constants and let's assume that I 0 a) Calculate curl of and divergence of F (4 points) b) Show the integral ffdf is path independent and calculate following (4 points) (11) 우리가 일반물리 시간에 중력장을 이용한 포텐셜은 위치의 함수라는 걸 배운게 기억이 날겁니다. 이 문제는 사실 vector function 에 대한 문제인데 (9.10.11 단원), 우리가 배운 수학적 도구를 가지고 한번쯤 생각해볼 필요가 있어서 넣었습니다.
Gravitational force between two masses m, and m, is represented as F = Gm₂ m₂ / r^2 where r = xi+yj + zkG, m, m₂ are nonzero constants and let's assume that I = 0
a) Calculation:For F = Gm₂ m₂ / r^2.
Using r = xi+yj + zk and let r^2 = x^2 + y^2 + z^2∴ F = Gm₂ m₂ / (x^2 + y^2 + z^2), Where G, m, m₂ are nonzero constants. Divergence of F = ∇ · F= 1/r^2(d/dx(r^2Fx) + d/dy(r^2Fy) + d/dz(r^2Fz))= 1/r^2(d/dx(r^2Gm₂ m₂ x/(x^2+y^2+z^2)^(3/2)) + d/dy(r^2Gm₂ m₂ y/(x^2+y^2+z^2)^(3/2)) + d/dz(r^2Gm₂ m₂ z/(x^2+y^2+z^2)^(3/2)))= 1/r^2(d/dx(r^2Gm₂ m₂ x/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2) + d/dy(r^2Gm₂ m₂ y/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2) + d/dz(r^2Gm₂ m₂ z/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2))= 1/r^2(Gm₂ m₂ [2x(x^2+y^2+z^2)-3x^2]/(x^2+y^2+z^2)^(5/2) + Gm₂ m₂ [2y(x^2+y^2+z^2)-3y^2]/(x^2+y^2+z^2)^(5/2) + Gm₂ m₂ [2z(x^2+y^2+z^2)-3z^2]/(x^2+y^2+z^2)^(5/2))= 1/r^2(Gm₂ m₂ [(2x^2+2y^2+2z^2-3x^2)/(x^2+y^2+z^2)^(3/2)] + [2x^2+2y^2+2z^2-3y^2]/(x^2+y^2+z^2)^(3/2)] + [2x^2+2y^2+2z^2-3z^2]/(x^2+y^2+z^2)^(3/2)])= 1/r^2(Gm₂ m₂ [x^2+y^2+z^2]/(x^2+y^2+z^2)^(3/2))= 0.
Curl of F = ∇ × F= i(d/dy(Fz) - d/dz(Fy)) - j(d/dx(Fz) - d/dz(Fx)) + k(d/dx(Fy) - d/dy(Fx))= i(d/dy(Gm₂ m₂ z/(x^2+y^2+z^2)) - d/dz(Gm₂ m₂ y/(x^2+y^2+z^2))) - j(d/dx(Gm₂ m₂ z/(x^2+y^2+z^2)) - d/dz(Gm₂ m₂ x/(x^2+y^2+z^2))) + k(d/dx(Gm₂ m₂ y/(x^2+y^2+z^2)) - d/dy(Gm₂ m₂ x/(x^2+y^2+z^2)))= i(Gm₂ m₂ [-2xz]/(x^2+y^2+z^2)^(5/2)) - j(Gm₂ m₂ [-2yz]/(x^2+y^2+z^2)^(5/2)) + k(Gm₂ m₂ [(x^2+y^2-2z^2)]/(x^2+y^2+z^2)^(5/2))
b) Calculation:The line integral of F along a curve C can be evaluated by the following formula∫C F.dr = ∫∫ ( ∇ x F) ds, Where r is the position vector of the curve, s is the scalar parameter representing the curve, and the integral is evaluated from the initial point to the final point.
Using the curl of F obtained in part a) and for the surface with ∂S as C∫C F.dr = ∫∫ ( ∇ x F) ds= ∫∫ curl(F) ds= ∫∫ (-2xz i -2yz j + (x^2+y^2-2z^2)k) ds...[1]
Let's consider the surface S as a plane perpendicular to the z-axis of the form ax+by+c=0 and the curve C as the intersection of the plane and the cylinder x^2 + y^2 = a^2.
Let's choose the unit normal to the surface S as k (along the z-axis).
The curl of F is a vector field perpendicular to the plane and along the direction of k.
Thus the integral can be written as∫C F.dr = ∫∫ ( ∇ x F) . k ds= ∫∫ (x^2+y^2-2z^2) ds...[2]
Now let's evaluate the integral over the given plane ax+by+c=0. We can write x = t, y = (c-at)/b and z = 0, where t is the scalar parameter along the line of intersection of the plane and the cylinder (x^2 + y^2 = a^2).
Since the curve C is on the cylinder of radius a, we have x^2+y^2 = a^2 ⇒ t^2+(c-at)^2/b^2 = a^2On solving for t, we have t = (bc±ab √(a^2-b^2-c^2))/[a^2+b^2].
Substituting t in x and y, we get the curve C in the x-y plane as a function of the scalar parameter s asx = (bc±ab √(a^2-b^2-c^2))/[a^2+b^2]y = (c-at)/b= (c-(bc±ab √(a^2-b^2-c^2))/[a^2+b^2])/b.
Now we can evaluate the integral over the curve C, which is along the intersection of the plane and the cylinder.
Integral over C (x^2+y^2-2z^2) ds= ∫t₁^t₂ [(t^2 + [(c-at)^2]/b^2 - 2(0)^2)^(1/2)] dt= ∫t₁^t₂ [(a^2-b^2-c^2)t^2+2bc(c-at)+b^2c^2-a^2b^2]^(1/2) dt.
Now we can choose the value of t₁ and t₂ such that the square root in the integrand is minimized (so that the integral is path-independent).
This can be done by choosing the value of t that gives the minimum value of (a^2-b^2-c^2)t^2+2bc(c-at)+b^2c^2-a^2b^2 over the range of t from t₁ to t₂.
On differentiation with respect to t and equating to 0, we get the value of t = bc/(a^2+b^2).
Substituting this value of t in the integrand, we get the minimum value of the square root in the integrand to be |c| √(a^2+b^2)/|b|.
Thus the integral over C is given by∫C F.dr = ∫∫ (-2xz i -2yz j + (x^2+y^2-2z^2)k) ds= ∫∫ (x^2+y^2-2z^2) ds= ∫t₁^t₂ |c| √(a^2+b^2)/|b| dt= |c| √(a^2+b^2)/|b| (t₂-t₁).
Now we can see that the integral is path-independent as it depends only on the end points t₁ and t₂ and not on the path taken to reach them.
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A bicycle has a mass of 10kg and an acceleration of 2m/s². What is the net force of the bicycle?
20 m/s
20 m/s
5 N
5 N
0.2 m/s
0.2 m/s
20 N
Answer:
The answer is 20 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
Force = mass × accelerationFrom the question
mass = 10 kg
acceleration = 2 m/s²
We have
Force = 10 × 2
We have the final answer as
20 NHope this helps you
Pls help!
sponge
sandworm
crab
sea star
flatworm
Which characteristic do these animals have in common
Answer:
they havve to stay in water to survive
Explanation:
So their are sea animals
b) A shopkeeper sold a watch for Rs 810 at 10% loss. How much did he pay to
buy the watch?
indir
Answer:
rs 900
Explanation:
the process is given
A 2100 lb (1 kg=2.2 lbs) car is using 4500 N of traction in order to move with a constant
velocity of 67 mph (29.8 m/s). What is the acceleration of this 9300 N vehicle?
Answer:
\(a = 0\ m/s^2\)
Explanation:
The acceleration of a body is defined as the change in velocity of an object, with respect to time. So, in order to produce and acceleration in any object, the velocity of that object must change. And, if the velocity of the object is not changing with respect to time, then the object is said to have a uniform motion. The acceleration of the object in such uniform motion is always zero. Because the change in velocity is zero.
\(acceleration = change in velocity/time\\acceleration = 0 / time\\acceleration = 0 m/s^2\)
Since, the car in this case is moving with a constant speed. Therefore, its acceleration will also be zero.
a = 0 m/s²
A person holds an 80-N weight 2 m above the floor for 30 seconds. The power required to do this is: a. none of these b. 40 W c. 80 W d. 5.3 W
30 seconds are spent holding an 80-N weight 2 meters off the ground. This will demand 5.3 W of power. Hence the correct option is (d).
The power required to hold an object can be calculated using the formula: Power = Force x Distance / Time.
Given:
Force = 80 N
Distance = 2 m (vertical displacement)
Time = 30 seconds
Putting the values in the formula:
Power = 80 N x 2 m / 30 sec
Power = 160 J/30 sec
Power = 5.3 W
Therefore, the answer is d. 5.3 W.
In physics, power is a measure of the rate at which energy is being transferred or transformed. It is defined as the amount of work done per unit time, and is usually measured in Watts (W).Power is an important physical concept that appears in many areas of physics, including mechanics, thermodynamics, electromagnetism, and many others. In mechanics, for example, power is used to calculate the rate at which work is being done, which is essential for understanding the behavior of objects in motion. In thermodynamics, power is used to describe the rate at which heat is being transferred between two systems, which is essential for understanding the behavior of thermodynamic systems.
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Find the area of the surface.the part of the plane x 2y 3z = 1 that lies inside the cylinder x2 y2 = 6
I assume you mean the plane \(x+2y+3z=1\). Its area over the region
\(R = \left\{(x,y) ~:~ x^2 + y^2 \le 6\right\}\)
is given by the integral
\(\displaystyle \iint_R dA = \iint_R \sqrt{1 + \left(\frac{\partial f}{\partial x}\right)^2 + \left(\frac{\partial f}{\partial y}\right)^2} \, dx \, dy\)
where \(z=f(x,y) = \frac{1 - x - 2y}3\).
We have
\(\dfrac{\partial f}{\partial x} = -\dfrac13\)
\(\dfrac{\partial f}{\partial y} = -\dfrac23\)
so that the area element is
\(dA = \sqrt{1 + \left(-\dfrac13\right)^2 + \left(-\dfrac23\right)^2} \,dx\,dy = \dfrac{\sqrt{14}}3\,dx\,dy\)
Then we have
\(\displaystyle \iint_R dA = \frac{\sqrt{14}}3 \iint_R dx \, dy\)
and the remaining integral is exactly the area of the disk \(x^2+y^2\le6\). Its radius is √6, so its area is π (√6)² = 6π. So the area of the surface is
\(\displaystyle \iint_R dA = \frac{\sqrt{14}}3 \cdot 6\pi = \boxed{2\sqrt{14}\pi}\)
Imagine that you are sitting on a couch watching TV and that you will continue sitting on the couch watching TV until someone changes the channel. This situation is a metaphor for which of Newton's laws of motion?
-The law of inertia
-The law of action-reaction
-The law of acceleration
-None of the above
Answer:
I think the law of inertia
Marlene loves astronomy and has enrolled in an online course to learn more about space. The course gives Marlene access to a digital classroom.
What does this enable her to do? Check all that apply.
discuss the solar system with others in the class
attend a field trip to a planetarium at a local college
upload an amateur video of a shooting star
make a presentation about her favorite planet
take notes, tests, and quizzes
watch instructional videos made by a teacher
Answer:
A E and F are the correct answers
Explanation:
Answer:
A E F are correct
Explanation:
what two elements are highlighted on group 3 of the periodic table
Answer:
hello! Jaesuk~Sakai here!
Explanation:
The four group 3 elements are scandium, yttrium, lanthanum and actinium. “lanthanide” refers to the elements between lanthanum and lutetium. That term does not encompass scandium and yttrium. Scandium and yttrium act pretty much identically to lanthanides.
happy to help!!
Remember to always stay happy no matter what happens! ^^