Compact fluorescent bulbs are much more efficient at producing light than are ordinary incandescent bulbs. They initially cost much more, but last far longer and use much less electricity. According to one study of these bulbs, a compact bulb that produces as much light as a 100 W incandescent bulb uses only 23.0 W of power. The compact bulb lasts 10000 hours, on the average, and costs $ 12.00, whereas the incandescent bulb costs only $ 0.76, but lasts just 750 hours. The study assumed that electricity cost $ 0.090 per kilowatt-hour and that the bulbs were on for 4.0 h per day.
Required:
a. What is the total cost (including the price of the bulbs) to run each bulb for 3.0 years?
b. How much do you save over 3.0 years if you use a compact fluorescent bulb instead of an incandescent bulb?
c. What is the resistance of a "100-W" fluorescent bulb?
Answers
Answer:
a
\(The \ price \ for \ Compact\ fluorescent\ bulbs \ is \ C_T = \$ 21.067\\The \ price \ for \ incandescent\ bulb \ is \ C_t = \$ 43.98\)
b
\(The \ amount \ saved \ is \ C_S = \$ 22.913\)
c
\(The \ resistance \ is \ R = 626.1 \Omega\)
Explanation:
From the question we are told that
The power used by incandescent bulb \(P_r = 23.0 W\)
The power used by Compact fluorescent bulb \(P_p = 100W\)
The life span of Compact fluorescent bulb is \(t = 1000 \ hours\)
The prices of Compact fluorescent bulb is \(C_c = \$ 12 \)
The prices of incandescent bulb is \(C_i = \$ 0.76 \)
The life span of incandescent bulb is \(t_k = 750 \ hours\)
The cost of electricity is \(C_e = \$ 0.090/ kilowatt-hour = \frac{0.090}{1000} = \$0.00009 / W / h\)
The duration of daily bulb usage is \(t_d = 4 \ hours\)
Generally 3 years of bulb usage in hours is mathematically evaluated as
\(t_3 = 3 * 365 * t_d\)
=> \(t_3 = 3 * 365 * 4\)
=> \(t_3 = 4380 \ h \)
Generally the cost to power a 23W bulb for the above duration is mathematically represented as
\(Z = 23 * t_3 * C_e\)
=> \(Z = 23 * 4380 * 0.00009\)
=> \(Z = \$ 9.0667\)
The number of Compact fluorescent bulbs required to achieve this about of time is mathematically represented as
\(N = \frac{t_3}{ t}\)
=> \(N = \frac{4380}{1000}\)
=> \(N = 0.438 \)
=> \(N \approx 1 \)
The total cost of usage for the Compact fluorescent bulb is mathematically represented as
\(C_T = Z +C_c\)
=> \(C_T = 9.0667 +12\)
=> \(C_T = \$ 21.067 \)
The number of incandescent bulbs required to achieve this about of time is mathematically represented as
\(M = \frac{t_3}{ t_k}\)
=> \(M = \frac{4380}{750}\)
=> \(M = 6 \)
Generally the cost to power a 100W bulb for the above duration is mathematically represented as
\(Z = 100 * t_3 * C_e\)
=> \(Z = 100 * 4380 * 0.00009\)
=> \(Z = \$ 39.42\)
The total cost of usage for the incandescent bulbs is mathematically represented as
\(C_t = C_e + [6 *C_i]\)
=> \(C_t = 39.42 + [0.76 * 6]\)
=> \(C_t = \$ 43.98\)
Generally the total amount saved is mathematically represented as
\(C_S = C_t - C_T\)
=> \(C_S = 43.98 - 21.067\)
=> \(C_S = \$ 22.913\)
Generally the resistance of the Compact fluorescent bulb is
\(R = \frac{V^2}{P}\)
\(R = \frac{120^2}{23}\)
\(R = 626.1 \Omega\)
Related Questions
Consider the circuit in Figure 5 with e(t) = 12sin(120pit) V. When S1 and S2 are
open, i leads e by 30°. When SI is closed and S2 is open, i lags e by 30°. When S1 and S2 are closed, i has an amplitude 0.5A. What are R, L, and C?
Answers
Based on the information, it should be noted that the resistance R is 0.5 Ω.
How to calculate the resistanceWhen S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:
Z = jωL - 1/(jωC)
Since i leads e by 30°, we can express the phasor relationship as:
I = k * e^(j(ωt + θ))
Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)
Re(Z) = 0
By equating the real parts, we get:
0 = 0 - 1/(120πC)
Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:
Z = R + jωL - 1/(jωC)
Z = R + jωL
Im(Z) = ωL > 0
Substituting the angular frequency and rearranging the inequality, we have:
120πL > 0
L > 0
This condition implies that the inductance L must be greater than zero.
When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:
Z = R + jωL - 1/(jωC)
Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:
I = 0.5 * e^(j(ωt + θ))
By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:
Re(Z) = R
Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R
Therefore, the resistance R is 0.5 Ω.
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Determine the resistance, in milliOhms, of a metal rod 2.39 m long, 0.47cm diameter and composed of aluminum of resistivity 2.8 x 10-8 Ωm .
Answers
0.965 mililΩ
ExplanationThe resistance of a metal rod depends on resistivy, length and temperature, it can fe found usign the formula
\(\begin{gathered} R=\rho\frac{L}{A} \\ where\rho\text{ is} \\ L\text{ is the length } \\ A\text{ is the seccion of area} \end{gathered}\)sp
Step 1
a) let
\(\begin{gathered} \rho=2.8*10^{-8}m\text{ ^^^^2126} \\ L=2.39\text{ m} \\ d=0.4\text{ cm=0.4 cm\lparen}\frac{1m}{100\text{ cm}}\text{\rparen=0.0047 m} \end{gathered}\)b) find the transversal area (A)
use the area of a circle
\(\begin{gathered} A=\pi r^2 \\ replace \\ A=\pi(0.0047\text{ m\rparen}^2 \\ A=6.93*10^{-5}m^2 \end{gathered}\)c) now, replace in the formula
\(\begin{gathered} R=\rho\frac{L}{A} \\ R=2.8*10^{-8}m\text{ ^^^^2126*}\frac{2.39\text{ m}}{6.93*10^{-5}m^2} \\ R=0.00096565\text{ ^^^^2126} \end{gathered}\)finally, to convert into milliOhms, Multiply by 1000
\(\begin{gathered} R=0.000965365*1000\text{ m^^^^2126} \\ R=0.965\text{ m^^^^2126} \end{gathered}\)therefore, the answer is
0.965 miliΩ
I hope this helps you
how long does it take for light to travel 2.5m in water?
Answers
Speed of light in water = Speed of light in vacuum / Refractive index of water
Speed of light in water = 299,792,458 m/s / 1.33
Speed of light in water = 225,143,995.5 m/s
To calculate how long it takes for light to travel 2.5 meters in water, we can use the formula:
Time = Distance / Speed
Time = 2.5 m / 225,143,995.5 m/s
Time = 1.11 x 10^-8 seconds
Therefore, it takes approximately 1.11 x 10^-8 seconds for light to travel 2.5 meters in water.
HI PLEASE HELP ON QUESTION ASAP USING AVERAGE (MEAN) TO ANSWER QUESTION! IF UR ANSWER AND EXPLAINATION IS CORRECT ILL RATE YOU FIVE STARS, A THANKS AND MAYBE EVEN BRAINLIEST. PLEASE MAKE SURE YOU ANSWER MY QUESTION USING AVERAGES.
1) a meal for 6 cost £12 per person. as it is one of the diners birthday , the other 5 decided to pay for his meal. how much do each of the five friends need to pay?
Answers
Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.
To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.
In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.
To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.
Total cost covered by the five friends = Total cost - Cost of one person's meal
= (£12 x 6) - £12
= £72 - £12
= £60
Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).
Amount each friend needs to pay = Total cost covered by the five friends / Number of friends
= £60 / 5
= £12
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What is the cycle of a breaststroke?
Answers
Answer:
Breaststroke can be divided up into 4 distinct phases, which consists of the out sweep, in sweep, breathing phase, and lunge, extension, or recovery phase.
Explanation:
pa follow po
Two 22.7 kg ice sleds initially at rest, are placed a short distance apart, one directly behind the other, as shown in Fig. 1. A 3.63 kg cat, standing on the left sled, jumps across to the right one and immediately comes back to the first. Both jumps are made horizontally at a speed of 3.05 m/s relative to the ice. Ignore the friction between the sled and ice.
(a) Find the final speeds of the two sleds. [6 marks]
(b) Calculate the impulse on the cat as it lands on the right sled. [2 marks]
(c) Find the average force on the right sled applied by the cat while landing. Consider that the cat takes 12 ms to finish the landing.
Answers
Newton's third law of motion sates that force is directly proportional to the rate of change of momentum produced
(a) The final speeds of the ice sleds is approximately 0.49 m/s each
(b) The impulse on the cat is 11.0715 kg·m/s
(c) The average force on the right sled is 922.625 N
The reason for arriving at the above values is as follows:
The given parameters are;
The masses of the two ice sleds, m₁ = m₂ = 22.7 kg
The initial speed of the ice, v₁ = v₂ = 0
The mass of the cat, m₃ = 3.63 kg
The initial speed of the cat, v₃ = 0
The horizontal speed of the cat, v₃ = 3.05 m/s
(a) The required parameter:
The final speed of the two sleds
For the first jump to the right, we have;
By the law of conservation of momentum
Initial momentum = Final momentum
∴ m₁ × v₁ + m₃ × v₃ = m₁ × v₁' + m₃ × v₃'
Where;
v₁' = The final velocity of the ice sled on the left
v₃' = The final velocity of the cat
Plugging in the values gives;
22.7 kg × 0 + 3.63 × 0 = 22.7 × v₁' + 3.63 × 3.05
∴ 22.7 × v₁' = -3.63 × 3.05
v₁' = -3.63 × 3.05/22.7 ≈ -0.49
The final velocity of the ice sled on the left, v₁' ≈ -0.49 m/s (opposite to the direction to the motion of the cat)
The final speed ≈ 0.49 m/s
For the second jump to the left, we have;
By conservation of momentum law, m₂ × v₂ + m₃ × v₃ = m₂ × v₂' + m₃ × v₃'
Where;
v₂' = The final velocity of the ice sled on the right
v₃' = The final velocity of the cat
Plugging in the values gives;
22.7 kg × 0 + 3.63 × 0 = 22.7 × v₂' + 3.63 × 3.05
∴ 22.7 × v₂' = -3.63 × 3.05
v₂' = -3.63 × 3.05/22.7 ≈ -0.49
The final velocity of the ice sled on the right = -0.49 m/s (opposite to the direction to the motion of the cat)
The final speed ≈ 0.49 m/s
(b) The required parameter;
The impulse of the force
The impulse on the cat = Mass of the cat × Change in velocity
The change in velocity, Δv = Initial velocity - Final velocity
Where;
The initial velocity = The velocity of the cat before it lands = 3.05 m/s
The final velocity = The velocity of the cat after coming to rest =
∴ Δv = 3.05 m/s - 0 = 3.05 m/s
The impulse on the cat = 3.63 kg × 3.05 m/s = 11.0715 kg·m/s
(c) The required information
The average velocity
Impulse = \(F_{average}\) × Δt
Where;
Δt = The time of collision = The time it takes the cat to finish landing = 12 ms
12 ms = 12/1000 s = 0.012 s
We get;
\(F_{average} = \mathbf{\dfrac{Impulse}{\Delta \ t}}\)
∴ \(F_{average} = \dfrac{11.0715 \ kg \cdot m/s}{0.012 \ s} = 922.625 \ kg\cdot m/s^2 = 922.625 \ N\)
The average force on the right sled applied by the cat while landing, \(\mathbf{F_{average}}\) = 922.625 N
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Obiects 1 and 2 attract each other with a electrostatic force of 36.0 units. If the distance separating Objects 1 and 2 is tripled, then the new electrostatic force will be
__ units.
Answers
Objects 1 and 2 attract each other with an electrostatic force of 36.0 units. If the distance separating Objects 1 and 2 is tripled, then the new electrostatic force will be four units.
Coulomb's law can be expressed as:
F = k × (q1 × q2) / r²
In which:
F = electrostatic force
k = electrostatic constant (k = 9 × 10⁹ N·m²/C²)
q1 and q2 = the charges of the objects
r = distance between the objects
Let's consider that the initial electrostatic force in between objects 1 and 2 is 36.0 units.
F1 = 36.0 units
Next, if the distance is considered between the objects is tripled, the new distance (r') changes into three times the initial distance (r):
r' = 3 × r
To determine the new electrostatic force (F'), replacement r' into Coulomb's law:
F' = k × (q1 × q2) / (r')²
Place r' = 3r:
F' = k × (q1 × q2) / (3r)²
= k × (q1 × q2) / 9r²
The new force will be one-ninth (1/9) of the initial force since the electrostatic force (F') is directly proportional to (q1 q2) and inversely proportional to r2.
F' = (1/9) × F1
= (1/9) × 36.0
= 4.0 units
Thus, objects 1 and 2 attract each other with an electrostatic force of 36.0 units. If the distance separating Objects 1 and 2 is tripled, then the new electrostatic force will be 4 units.
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Drag the tiles to the correct boxes. Not all tiles will be used.
Match the molecular shapes to the correct Lewis structures.
trigonal pyramidal
trigonal planar
bent
tetrahedral
linear
Answers
Answer
1) AlH3= trigonal planar
2) CH2F2= tetrahedral
3) PH3= trigonal pyramidal
4) O3= bent
Explanation:
I took the test
What are the similarities and
differences between solids,
liquids and gases?
Answers
Solids: incompressible, solids have a definite shape and volume.
Gasses: Can be compressed easy, gasses have no definite volume.
They all are made up of atoms and molecules.
Hope this helps:)
A 66 kg driver gets into an empty taptap to start the day's work. The springs compress 2.3×10−2 m
. What is the effective spring constant of the spring system in the taptap?
Enter the spring constant numerically in newtons per meter using two significant figures
Answers
Explanation:
You want N/m
N = 66 * 9.81
m = 2.3 x 10^-2 m
66* 9.81 / 2.3 x 10^-2 = 28150 = 28 000 N/m to two S D
76. Two electric charges -6μC and
+6μC are placed respectively in two
points A and B distant of 1m apart. The
electric field is null at the point C:
A.Located in the middle of the
segment AB
B.Located outside segment AB at
1m from A.
C.Located outside segment AB at
1m from B
D.Outside the line AB
E.No answer is right.
Answers
Answer:
D. Located outside line AB
Explanation:
I do not have a Columb table with me, so it could be B. or C., but if I did the math right, then I think the answer is D.
What is the resistance of five 10Ohm resistors in parellel?
Answers
Answer:
The equivalent resistance is 2 ohms.
Explanation:
let the first resistance = R₁ = 10 ohm
let the second resistance = R₂ = 10 ohm
let the third resistance = R₃ = 10 ohm
let the fourth resistance = R₄ = 10 ohm
let the fifth resistance = R₃ = 10 ohm
The equivalent resistance is calculated as;
\(\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \frac{1}{R_4} + \frac{1}{R_5} \\\\\frac{1}{R_T} = \frac{(R_2R_3R_4R_5)+(R_1R_3R_4R_5)+(R_1R_2R_4R_5) +(R_1R_2R_3R_5)+(R_1R_2R_3R_4)}{R_1R_2R_3R_4R_5} \\\\R_T = \frac{R_1R_2R_3R_4R_5}{(R_2R_3R_4R_5)+(R_1R_3R_4R_5)+(R_1R_2R_4R_5) +(R_1R_2R_3R_5)+(R_1R_2R_3R_4)} \\\\R_T = \frac{(10^5)}{(10^4)+(10^4)+(10^4)+(10^4)+(10^4)} \\\\R_T = \frac{10^5}{5(10^4)} \\\\R_T = \frac{10}{5} \\\\R_T = 2 \ ohms\)
Therefore, the equivalent resistance is 2 ohms.
An object is placed at several different distances to the left of the lenses and mirrors (focal length = f). For each case, draw the 3 principal rays to locate the image and then (S.A.L.T.) [Size, Attitude, Location, Type] the image.
Answers
To determine the image characteristics using the 3 principal rays and SALTS (Size, Attitude, Location, Type), we'll consider both lenses and mirrors separately. Here's how you can analyze each case:
Lenses:
Place an object at different distances to the left of a lens with a focal length (f).
a) Object placed beyond 2f:
In this case, the object is placed far beyond twice the focal length of the lens.
Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.
Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.
Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.
The image will be formed on the opposite side of the lens, between the focal point and twice the focal length.
SALTS:
Size: The image will be smaller than the object.
Attitude: The image will be inverted.
Location: The image will be located between the focal point and twice the focal length.
Type: The image will be real.
b) Object placed at 2f:
In this case, the object is placed at twice the focal length of the lens.
Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.
Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.
Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.
The image will be formed on the opposite side of the lens at twice the focal length.
SALTS:
Size: The image will be the same size as the object.
Attitude: The image will be inverted.
Location: The image will be located at twice the focal length.
Type: The image will be real.
c) Object placed between f and 2f:
In this case, the object is placed between the focal point and twice the focal length of the lens.
In this case, the object is placed far beyond twice the focal length of the mirror.
Principal ray 1: A ray parallel to the principal axis will reflect through the focal point on the same side.
Principal ray 2: A ray passing through the focal point on the object side will reflect parallel to the principal axis.
Principal ray 3: A ray passing through the center of curvature will reflect back along the same path.
The image will be formed on the opposite side of the mirror, between the focal point and twice the focal length.
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At 5220J, a temperature increase occurs from 10 degrees Celsius to 60 degrees Celsius. What is the mass of the water?
Answers
The mass of water that undergoes a change in temperature from 10 degrees celsius to 60 degrees celsius is 24.9 g.
What is mass?Mass is the quantity of matter a body contained.
To calculate the mass of the water, we use the formula below
Formula:
m = Q/cΔt................... Equation 1Where:
m = Mass of waterQ = Amount of heatc = Specific heat capacity of waterΔt = Change in temperatureFrom the question,
Given:
Q = 5220 Jc = 4200 J/kg.KΔt = 60-10 = 50 degree celsiusSubstitute these values into equation 1
Q = 5220/(4200×50)Q = 0.0249 kgQ = 24.9 gHence, the mass of water is 24.9 g.
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A rollerskating mom has 10,000 kgm/s of momentum. As she's skating, she picks up her 20kg son, who is at rest. What is the momentum of the mom and son together?
Answers
Momentum is a measure of an object's motion, and is calculated as the product of an object's mass and velocity. When the mom picks up her son, the velocity of the combined system doesn't change, so the momentum of the combined system remains the same as the momentum of the mom alone.
p = m * v
where p is momentum, m is mass, and v is velocity.
For the mom alone:
p = 10000 kgm/s = 10,000 kg * 1 m/s
For the mom and son together:
p = (m_mom + m_son) * v = (10,000 kg + 20 kg) * (1 m/s) = 10,020 kg * 1 m/s = 10,020 kgm/s = 10,020 kgm/s
A fan spins at 6.0 rev/s. You turn it off, and it slows at 1.0 rev/s2. What is the angular displacement before it stops
Answers
Answer:
Angular displacement before it stops = 18 rev
Explanation:
Given:
Speed of fan w(i) = 6 rev/s
Speed of fan (Slow) ∝ = 1 rev/s
Final speed of fan w(f) = 0 rev/s
Find:
Angular displacement before it stops
Computation:
w(f)² = w(i) + 2∝θ
0² = 6² + 2(1)θ
0 = 36 + 2θ
2θ = -36
Angular displacement before it stops = -36 / 2
θ = -18
Angular displacement before it stops = 18 rev
A 3 kg rock is swung in a circular path and in a vertical plane on a 0.25 m length string. At the top of the path, the angular velocity is 11 rad/s. What is the tension in the string at that point
Answers
Answer:
The tension in the string at that point is 90.75 N
Explanation:
Given;
mass of the object, m = 3 kg
length of string, r = 0.25 m
the angular velocity, ω = 11 rad/s
The tension on string can be equated to the centrifugal force on the object;
T = mω²r
Where;
T is the tension in the string
m is mass of the object
ω is the angular velocity
r is the radius of the circular path
T = 3 x (11)² x 0.25
T = 90.75 N
Therefore, the tension in the string at that point is 90.75 N
find the hypotenuse of a right triangle if the perpendicular leg is 12 and the base is 5.
Answers
144+25
=169
169 squared is 13
John's home had 20 pounds of condiments. sugar made up 40% of the condiments. Salt made up the rest. After some sugar was used, sugar made up 25% of the condiments. How many pounds of sugar were used? pounds of sugar
Answers
3 pounds of sugar were used.
What are percentages?Percentage can be calculated by dividing the value by the total value, and then multiplying the result by 100.
How to find the amount of sugar used;
40% of sugar + 60% of salt = 20 pounds of condiments
Therefore 40% of sugar = (40/100) x 20
Sugar = 8 pounds
Therefore;
Salt = 20 - 8 pounds
Salt = 12 pounds
For sugar to make up 25% of the condiments;
Sugar = (25/100) x 20 pounds
Sugar = 5 pounds
The amount of Sugar used;
Sugar = 8 - 5 pounds
Sugar = 3 pounds
The amount of sugar used up is 3 pounds.
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Water flows at a speed of 13 m/s through a pipe that has a diameter of 1.2 m. What is the
diameter of the smaller end of the pipe that the water comes out with a speed of 30 m/s?
Answers
The diameter of the smaller end of the pipe is approximately 0.78 meters.
To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.
The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity
Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2
Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2
Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30
Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30
0.36 * 13 = (diameter2/2)^2 * 30
4.68 = (diameter2/2)^2 * 30
Dividing both sides by 30:
0.156 = (diameter2/2)^2
Taking the square root of both sides:
0.39 = diameter2/2
Multiplying both sides by 2:
0.78 = diameter2
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An owl has a mass of 4 kg. It dives to catch a mouse, losing 800 J of its GPE. What was the starting height of the owl, in meters?
Answers
The owl started out at a height of about 3.2 metres.
What is gravity?Gravity is the force that draws objects toward the center of a planet or other object.
How do you determine this?Gravitational potential energy (GPE) is calculated as follows:
GPE = mass x gravity x height. Since we are aware of the owl's mass (4 kg) and the change in GPE (-800 J) in this case, we can rewrite the formula to account for the height: tallness = GPE / (mass x gravity).
On Earth, the acceleration caused by gravity is roughly 9.8 m/s2.
By entering the known numbers, we obtain the height change as follows: -800 J / (4 kg x 9.8 m/s2) = -0.408 metres.
By combining the ultimate height (which is believed to be 0 metres) with the height change, we may get the initial height as follows: 0 m + (-0.408 m) = -0.408 m = 0.408 m = 3.2m.
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Based on the diagram, why does the lightbulb light when the loop rotates, and what is the energy change involved?
When the wire moves in an electric field, electrons in the wire move and become mechanical energy. The mechanical energy causes the light to glow. Electrical energy used to rotate the loop is converted to light energy.
When the wire moves in an electric field, electrons in the wire move and become mechanical energy. The mechanical energy causes the light to glow. Electrical energy used to rotate the loop is converted to light energy.
When the wire moves in a magnetic field, electrons in the wire move and become an electric current. The current causes the light to glow. Mechanical energy used to rotate the loop is converted to electrical energy.
When the wire moves in a magnetic field, electrons in the wire move and become an electric current. The current causes the light to glow. Mechanical energy used to rotate the loop is converted to electrical energy.
When the wire moves in an electric field, electrons in the wire move and become mechanical energy. The mechanical energy causes the light to glow. Mechanical energy used to rotate the loop is converted to electrical energy.
When the wire moves in an electric field, electrons in the wire move and become mechanical energy. The mechanical energy causes the light to glow. Mechanical energy used to rotate the loop is converted to electrical energy.
When the wire moves in a magnetic field, electrons in the wire move and become an electric current. The current causes the light to glow. Mechanical energy used to rotate the loop is converted to light energy.
Answers
Answer:
Based on the information provided, the lightbulb lights when the loop rotates because the movement of the wire in an electric or magnetic field causes electrons in the wire to move and become either mechanical energy or an electric current. This energy causes the light to glow. The energy change involved is the conversion of electrical or mechanical energy used to rotate the loop into either light or electrical energy
Explanation:
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Answers
Answer:
option A is correct because air friction is greater than gravity
Explanation:
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A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
Answers
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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What is the acceleration of a ball with a mass of 0.40 kg is hit with a force of 16N?
Answers
Answer:
40 m/s^2
Explanation:
Mass= 0.40 kg
Force= 16 N
Therefore the acceleration can be calculated as follows
F = ma
16= 0.40 × a
16= 0.40 a
a= 16/0.40
a= 40 m/s^2
Hence the acceleration is 40 m/s^2
A car sitting at rest begins
accelerating at 2.40 m/s2 for
15.0 seconds. How far has the
car gone?
Answers
The distance covered by the car for the speed of 2.40 m/s² for 15 seconds is 36 meters
To find the distance the given datas are:
Speed = 2.40 m/s²
Time = 15 seconds.
What is distance?Distance is the total movement of an object without any regard to direction.Distance can be evaluated how much an object moves from starting point to the end point.The distance completely depends upon the speed and time, i,e., the object covering some area with some particular time interval with the particular speed.Formula of distance,Distance = Speed × Time.
Distance will be measured in meter, kilometer, etc..Distance is a Scalar quantity.Substituting the given datas in the formula,
Distance = 2.40 × 15
= 36 m
The Car went at the distance of about 36 meters.
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Select ALL the
correct answers.
Which two examples describe ways that corporations can give large donations to presidential candidates?
A corporation leader makes
direct payment to the candidate.
A corporation creates another company to accept candidate contributions
A corporation collects moneys from its employees to contribute to
A corporation contributes to a Super PAC that
a PAC
accepts contributions
for a candidate,
Reset
Next
Answers
Answer: Hope this helps ;) don't forget to rate this answer !
Explanation:
There are two correct answers:
A) A corporation leader makes direct payment to the candidate.
D) A corporation contributes to a Super PAC that a PAC accepts contributions for a candidate.
Option A describes a scenario where a corporation directly donates money to a presidential candidate, which is allowed as long as it is done within the limits set by campaign finance laws.
Option D describes a scenario where a corporation donates money to a Super PAC, which is a type of political action committee that can accept unlimited donations from individuals, corporations, and other organizations. The Super PAC can then use the money to support or oppose a particular candidate, but it is not allowed to coordinate directly with the candidate or the candidate's campaign.
I hope this helps! Let me know if you have any other questions.
A Bicycle is turned upside down the front wheel is running,where will the valve stop
Answers
The valve will stop when the wheel stops.
How can the wheel stops?
It can be done either applying the force manually or let the natural friction force work.The force can be applied manually by pulling up the brakes.The other way by which it stop is :
When we ride on a bicycle, we rotate the pedals, which in turn rotate the chainrings, which rotate the rear sprocket, hence, making the rear wheel to move forward. This rotation brings in angular speed and angular acceleration.The friction is applied from the ground to stop it from slipping. Here, the forces working are the rotational and the frictional along with angular acceleration and speed. When the bicycle is upside down, the frictional force from the ground becomes zero. The chain rings also don’t control the front wheel. The angular acceleration will be opposed by some force. Here, the frictional force that will act will be from the air and the inertia is applied to the rotational motion of the wheel which is now in the air and not on the ground. Once the friction from air is greater than angular motion, the wheel stop automatically.To know more about angular motion, refer : https://brainly.com/question/14723674
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Three vectors are shown in this figure. Their respective moduli are A = 4.00m.B = 3, 20m and C = 2.70mCalculate 2.00 A - B + 1.30 CExpress your answer according toa) Unit vectorsb) The modulus and orientation with respect to the positive part of the x-axis
Answers
Given that,
Modulus of vector A=4.00
The angle made by the vector A with the y axis, θ₁=33.0°
The modulus of vector B=3.20 m
The angle made by the vector B with the x-axis is θ₂=40.0+90.0=130°
The modulus of the vector C=2.70 m
The angle made by the vector C with x-axis θ₃=-90°
The x and y components of the vector can be written as
\(\begin{gathered} x=r\cos \theta \\ y=r\sin \theta \end{gathered}\)Where r is the magnitude (or modulus) of the vector and θ is the angle made by the vector.
Or a vector, in cartesian coordinates, can be written as,
\(R=r\cos \theta\hat{\text{i}}+r\sin \theta\hat{j}\)Therefore, vector A is cartesian coordinates is
\(\begin{gathered} \vec{A}=4.00\cos 33^{\circ}\hat{i}+4.00\sin 33.0^{\circ}\hat{j} \\ =3.35\hat{i}+2.18\hat{j} \end{gathered}\)And the vector B is
\(\begin{gathered} \vec{B}=3.20\cos (130^{\circ})\hat{i}+3.20\sin (130^{\circ})\hat{j} \\ =-2.06\hat{i}+2.45\hat{j} \end{gathered}\)And vector C is given by,
\(\begin{gathered} \vec{C}=2.70\cos (-90^{\circ})\hat{i}+2.70\sin (-90^{\circ})\hat{j} \\ =-2.7\hat{j} \end{gathered}\)The given equation is
\(2.00\vec{A}-\vec{B}+1.30\vec{C}\)Let this represents a vector V
On substituting the known values,
\(\begin{gathered} \vec{V}=2.00\vec{A}-\vec{B}+1.30\vec{C} \\ =2.00\times(3.35\hat{i}+2.18\hat{j})-(-2.06\hat{i}+2.45\hat{j)}+1.30(-2.7\hat{j}) \\ =8.76\hat{i}-1.6\hat{j} \end{gathered}\)(a) This is the representation with the unit vectors, where i and j are the unit vectors along the x-axis and y-axis respectively.
\(\vec{V}=8.76\hat{i}-1.6\hat{j}\)b) The modulus of any vector is the square root of the sum of the squares of its components.
That is, the magnitude of the vector V is
\(\begin{gathered} V=\sqrt[]{8.76^2+(-1.6)^2} \\ =8.90\text{ m} \end{gathered}\)The angle of this vector with the x-axis is given by
\(\begin{gathered} \phi=\tan ^{-1}(\frac{-1.6}{8.75}) \\ =-10.36^{\circ}^{} \end{gathered}\)The negative sign indicates that the vector is below the positive x-axis
Therefore the modulus of the resultant of the above equation is 8.90 m and its angle with the positive x-axis is -10.36°
Define invariant transformations
Answers
Answer:
For a given system, there can be particular transformations for which the explicit equations of motion are the same for both the old and new variables. Transformations for which the equations of motion are invariant, are called invariant transformations. It will be shown that if the Lagrangian does not explicitly contain a particular coordinate of displacement qi, then the corresponding conjugate momentum, pi, is conserved. This relation is called Noether’s theorem which states “For each symmetry of the Lagrangian, there is a conserved quantity".