compare the times of all sunsets during the same period what do you observe​

The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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The vectors can be expressed using unit vectors as follows:

Vector A = 96N i + 96N j + 0N k

Vector B = 76.6N i + 64.3N j + 0N k

Vector C = 64N i + 48N j + 0N k.

In the given diagram, let's consider the vectors as follows:

Vector A with magnitude 120N, Vector B with magnitude 100N, and Vector C with magnitude 80N.

To express these vectors using unit vectors i, j, and k, we need to determine their respective components in the x, y, and z directions.

For Vector A (120N), we have the following information:

Magnitude = 120N

Direction: X-axis (cosine component) with an angle of 37° and Y-axis (sine component) with an angle of 53°.

Using the trigonometric values provided:

cos37° = 0.8 and sin53° = 0.8

Therefore, the components of Vector A are:

Ax = 120N * 0.8 = 96N (in the X-direction)

Ay = 120N * 0.8 = 96N (in the Y-direction)

Az = 0N (no component in the Z-direction)

Thus, Vector A can be written as 96N i + 96N j + 0N k.

Similarly, using the trigonometric values for Vector B and Vector C, we can calculate their components:

For Vector B (100N):

Bx = 100N * cos40° = 100N * 0.766 = 76.6N

By = 100N * sin40° = 100N * 0.643 = 64.3N

Bz = 0N

Vector B can be expressed as 76.6N i + 64.3N j + 0N k.

For Vector C (80N):

Cx = 80N * cos37° = 80N * 0.8 = 64N

Cy = 80N * sin37° = 80N * 0.6 = 48N

Cz = 0N

Vector C can be written as 64N i + 48N j + 0N k.

In summary, the vectors can be expressed using unit vectors as follows:

Vector A = 96N i + 96N j + 0N k

Vector B = 76.6N i + 64.3N j + 0N k

Vector C = 64N i + 48N j + 0N k.

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Answer:

Diffrent

Explanation:

Electrical energy is electrical charges moving. When you play soccer kinetic energy is used. Kinetic energy is the movement of atoms, objects, and electrons.

The airplane change in velocity be 120 m/sec

The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.

The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose strength or magnitude is determined by the norm and whose direction correlates with a plumb bob.

acceleration = velocity/time

Velocity = acceleration * time

Velocity = 60*2

Velocity = 120 m/sec

The airplane change in velocity be 120 m/sec

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Answer:

The Earth's major plates are the African plate, the Antarctic plate, the Eurasian plate, the North American plate, the South American plate, and the Pacific plate.

Explanation:

The expression "velocity as a function of time" refers to the change in an object's velocity over time, which can be observed by graphing the velocity against time on a graph.

Speed and time are related in the first equation of motion. V = u + at represents the first motion equation. Here, u denotes the starting velocity, a the acceleration, and t the duration, whereas v denotes the end velocity. The derivative of x with respect to time, or v(t)=ddtx, represents the instantaneous velocity of an object. It is the limit of average velocity as the time approaches zero (t). V (t) equals d d t x (t). Instantaneous velocity has a dimension of length per time, just like average velocity does.

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Answer:

Jumping battle slams - just move the rope up and down

Alternating jump wave - jump and move the rope side to side

Alternating wide circles - move the rope in a circle position

Jumping jacks

Squat to sholder

Explanation:

The guy above me is correct give him Brainliest

Answer:

80 sec

Explanation:

Answer:

4161 J/kg·°C

Explanation:

We can use the principle of conservation of energy to solve this problem, which states that the total heat energy in a closed system is constant. The heat lost by the tea is equal to the heat gained by the milk.

Let's first calculate the heat lost by the tea:

Q(tea) = mcΔT

Q(tea) = (0.27 kg)(3910 J/kg·°C)(90.0°C - 85.0°C)

Q(tea) = 6555 J

where m is the mass of tea, c is the specific heat of tea, and ΔT is the change in temperature.

Next, let's calculate the heat gained by the milk:

Q(milk) = mcΔT

Q(milk) = (0.02 kg)(c)(85.0°C - 6.0°C)

Now we can equate the two expressions:

Q(tea) = Q(milk)

6555 J = (0.02 kg)(c)(79.0°C)

Solving for c, we get:

c = 4161 J/kg·°C

Therefore, the specific heat of milk is approximately 4161 J/kg·°C.

The orbital radius of the satellite above Webb13's equator is around 11,360 kilometres.

There are several rotating periods (of an astronomic object) the length of time needed for it to revolve in relation to the nearby stars. (of an object revolving on Earth) the duration of its axis rotation in relation to the earth (assumed fixed).

Since 1 hour equals 60 minutes x 60 seconds, or 3600 seconds, the orbital period of the satellite is the same as the planet's rotational period, which is 22.9 hours, or 82,440 seconds. The following formula may be used to determine the radius of the satellite's orbit:

\(r = (G * M * T^2 / 4π^2)^(1/3)\)

where r is the orbit's radius, G is the gravitational constant, M is the planet's mass, and T is the satellite's orbital period.

Using the specified values:

\(G = 6.67 × 10^-11 m^3 kg^-1 s^-2 (gravitational constant)\)

\(M = 2.75 × 10^25 kg (mass of Webb13)\)

T = 82,440 s (orbital period of satellite)

The units can be changed to kilometres and then entered into the formula as follows:

\(r = (6.67 × 10^-11 m^3 kg^-1 s^-2 * 2.75 × 10^25 kg * (82,440 s)^2 / (4π^2))^(1/3)\)

\(r = 1.136 × 10^7 m\)

\(r = 11,360 km\)

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Answer:

i think B is the answer of the question

Answer: The answer is B and A

Explanation:

Answer:

a) V = 0.24 m/s

b) v = 1.53 m/s

Explanation:

In this case, we are asked to find two values that are pretty similar and use the same units, however, there are differences between them.

The average velocity is often referred to a vector quantity, therefore, if time is a scalar magnitude, we need to find the vector quantity of distance. In this case, is the displacement, which is also referred as a vector.

So, to calculate the average velocity we need to determine first the displacement of the person. As the person heads east and then west, his total displacement (D) is:

D = 55 - 40 = 15 m

Now the total time would be the time taken to go to the windmill and then, to a bench:

t = 25 + 37 = 62 s

Finally, the average speed is:

V = D/t

V = 15 / 62

The average speed is a scalar magnitude, so we use the covered distance by the person (d) and the total time:

d = 40 + 55 = 95 m

Then, the speed:

v = 95/62

Hope this helps

Answer:

Yes, because you would weigh differently on the moon, than on earth,

Explanation:

Can I have brainliest? It would help me out, if not thanks anyways! Hope this helped and have a nice day :)

Answer:

yes

Explanation:

the wight of an object is determined by the pull of gravity on it

Answer:

-T

Explanation:

Hope it helps!

Cancer cells are cells that divide relentlessly, forming solid tumors or flooding the blood with abnormal cells. Cell division is a normal process used by the body for growth and repair.

The dot used to represent the Sun’s location in the picture is too large to represent the size of the Sun on the picture.

1 cm = 10000 light-years

1 mm = 1000 light-years

Dot = 0.5 to 1 mm

Diameter of the Sun = 1.5 * \(10^{-7}\) light-years = 1.5 * \(10^{-10}\) mm

On comparing, the Sun should not be visible to a human eye in that picture. Even using an Electron microscope, we cannot spot the Sun according to the given scale.

A light-year is a measurement of distance. It is the distance travelled by light in one year.

Light speed = 300000 km / s = 9.46 * \(10^{12}\) km / yr

1 light year = 9.46 * \(10^{12}\) km

Diameter of sun = 1.39 * \(10^{6}\) km

Therefore, the dot used to represent the Sun’s location in the picture is too large to represent the size of the Sun on the picture.

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To find the mass in kilograms, you need to know the object's weight in newtons and the acceleration due to gravity. The formula for finding mass is mass = weight / acceleration due to gravity. So if you have an object with a weight of 100 N and the acceleration due to gravity is 9.8 m/s^2, the mass would be 10.204 kg.

The mass of the block is 0.025 kg or 25 g, when the spring has k = 28 N/m, and compresses 0.11 m before bringing the block to rest.

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Answer:

A. Waves bend as they pass through an opening.

Explanation:

important word here is "opening"

diffraction example is a CD reflecting rainbow colors

A. Waves bend as they pass through an opening best describes diffraction.

Diffraction is the spreading out or bending of waves as they pass through an aperture or around an object. If we talk about light waves, diffraction of light occurs when a light wave passes by a corner or through a slit or opening. The slit or opening can be physically approximately the size of, or even smaller than that light's physical wavelength. An example of diffraction is the diffraction of sunlight by the clouds.

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The attached picture shows the diffraction of light through a single slit.

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The answer is D.

...................................

Answer:

d lol why did he put ................. like what did he get from that D)

amount of fertilizer

Answer:

The drift speed of the electrons in the wire is 2.12x10⁻⁴ m/s.

Explanation:

We can find the drift speed by using the following equation:

\( v = \frac{I}{nqA} \)

Where:

I: is the current = 4.50 A

n: is the number of electrons

q: is the modulus of the electron's charge = 1.6x10⁻¹⁹ C

A: is the cross-sectional area = 2.20x10⁻⁶ m²

We need to find the number of electrons:

\( n = \frac{6.022\cdot 10^{23} atoms}{1 mol}*\frac{1 mol}{26.982 g}*\frac{2.70 g}{1 cm^{3}}*\frac{(100 cm)^{3}}{1 m^{3}} = 6.03 \cdot 10^{28} atom/m^{3} \)                  

Now, we can find the drift speed:

\(v = \frac{I}{nqA} = \frac{4.50 A}{6.03 \cdot 10^{28} atom/m^{3}*1.6 \cdot 10^{-19} C*2.20 \cdot 10^{-6} m^{2}} = 2.12 \cdot 10^{-4} m/s\)              

Therefore, the drift speed of the electrons in the wire is 2.12x10⁻⁴ m/s.

I hope it helps you!      

Given:

To be calculated:

Calculate the acceleration of given object ?

Formula used:

Acceleration = v - u / t

Solution:

We know that,

Acceleration = v - u / t

☆ Substituting the values in the above formula,we get

Acceleration ⇒ 300 - 200 / 20

⇒ 100/20

⇒ 5 m/s²

Stochastic impacts of radiation allude to those that happen arbitrarily and are not reliant upon the portion got. These impacts are related to the likelihood of events and incorporate disease and hereditary changes. Non-stochastic impacts, then again, have a limit, and their seriousness increments with expanding portions.

Models incorporate radiation consumption and intense radiation conditions. Understanding the qualification among stochastic and non-stochastic impacts of radiation is significant in fields like radiation security, atomic medication, and radiobiology.

It assists in setting radiation with dosing limits, creating well-being rules, and carrying out suitable radiation safeguarding measures. By separating these impacts, experts can evaluate and deal with the dangers related to openness to ionizing radiation all the more successfully.

This information guides choices in regard to radiation wellbeing conventions, word-related openness limits, and the improvement of radiation therapy systems in medication.

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Answer: We have vf = 7.57 m/s, which is the speed of the car (and the truck) after the collision.

Explanation:

p (auto) = 2200 kg * 12 m/s = 26,400 kg m/s p (truck) = 3800 kg * 5 m/s = 19,000 kg m/s After the collision, we have p = (2200+3800)*vf = 26400+19000 p = 6000*vf = 45,640 Therefore, we have vf = 7.57 m/s, which is the speed of the car (and the truck) after the collision.

Angular velocity of the platform with its load is 0.94 rad/s.

Since, there is no external torque acting on the system, the momentum is conserved.

So, Initial momentum, L₁ = Final momentum, L₂

I₀ω₁ = (I₀ + m₁r₁² + m₂r₂²)ω₂

I₀ω₁ = [1/2 x 80.7 x (1.91)²] (1.57)

I₀ω₁ = 147.2 x 1.57 = 231.1 kgm²/s

So,

231.1 = [147.2 + 9.57(4/5 x 1.91)² + 21.1(1.91)²]ω₂

Therefore, the final angular velocity,

ω₂ = 231.1/246.5

ω₂ = 0.94 rad/s

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the force the woman exerts to do a push-up at constant speed is 333 N.

the work the woman does is 152 J.

her useful power output is 76 W.

(a) To calculate the force the woman exerts to do a push-up, we need to use torque methods. The woman is doing a push-up at constant speed, which means that the net torque on her body is zero. The only torque acting on her body is due to her weight W, which acts at the center of mass of her body. The distance between her center of mass and her hands is 0.76 m, and the angle between her body and the horizontal is 45 degrees.

The torque due to her weight about her hands is given by:

τ = r x W = (0.76 m) x (cos 45°)(W)

where r is the distance between her hands and her center of mass and cos 45° is the component of the distance perpendicular to the weight vector. Since the woman is at constant speed, the torque she exerts about her hands must be equal and opposite to the torque due to her weight. Therefore:

τ = (0.76 m)(cos 45°)(W) = (1/2)(W)(0.76 m)

Solving for W, we get:

W = 2(τ/0.76 m) = 2[(0.5)(mg)(0.76 m)/(0.76 m cos 45°)] = 333 N

Therefore, the force the woman exerts to do a push-up at constant speed is 333 N.

(b) The work the woman does is equal to the change in her potential energy as her center of mass rises. The woman's mass is not given, so we will assume a value of 60 kg. The gravitational potential energy of the woman is given by:

U = mgh

where m is the mass of the woman, g is the acceleration due to gravity (9.81 m/s^2), and h is the height her center of mass rises (0.26 m). Therefore:

U = (60 kg)(9.81 m/s^2)(0.26 m) = 152 J

Therefore, the work the woman does is 152 J.

(c) The useful power output of the woman is the work she does per unit time, taking into account the work done in lowering her body. Each push-up involves two phases: lifting her body and lowering her body. When she lowers her body, the work done is negative, as the force she exerts is in the opposite direction to the displacement. The work done in lowering her body is equal to the work done in lifting her body, so the total work done in one push-up is zero.

The woman does 30 push-ups in 1 minute, which means she does one push-up every 2 seconds. Therefore, the useful power output of the woman is:

P = (152 J)/(2 s) = 76 W

Therefore, her useful power output is 76 W.

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The part of a road vehicle which must be tested to ensure that there is sufficient friction to stop the vehicle in an emergency is the tyre.

This is referred to as a force that resists the motion of one object against another when they roll or slide against each other.

When dealing with braking, the main factor is to have sufficient friction between the road surface and tyre to bring the vehicle to a standstill. If the tyres are wornout there won't be enough friction to make the vehicle stop during emergencies which is therefore the reason why it was chosen as the correct choice.

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Answer:

where u put it last time or retrace ur steps to where u last put it