Consider a single slit that produces a first-order minimum at 16.5° when illuminated with monochromatic light. show answer No Attempt 50% Part (a) At what angle, in degrees, is the second-order minimum?

a. Nyquist rate = 30 kHz is the Nyquist rate.

compact disc (CD) records audio signals digitally by means of a binary code. Assume an audio signal bandwidth of 15 kHz.

⇒ According to the Nyquist criteria, the sampling frequency must be at least 2 times the bandwidth.

⇒Nyquist rate = 2 x 15 kHz

⇒Nyquist rate = 30 kHz

So that means we need to take at least 30,000 sample/s to meet Nyquist criteria.  

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Answer:

1 N

Explanation:

First the equation is momentum = Force / distance

20 cm = 0.2 m

5 N/m = F / 0.2 m

F = 1 N

Given that,Two point charges, Q1 =7μC and Q2 =−3μC, are located at the two nonadjacent vertices of a square contour a=15 cm on a side.

Let the charges Q1 = 7 μC be located at the origin of the coordinate system, while the charges Q2 = −3 μC will be at the coordinates x = a and y = a, respectively, where a is the side of the square, i.e. a = 15 cm.Let us consider a square ABCD.

Let the coordinates of the center O of the square be (7.5, 7.5) cm. Let us take the vertex A opposite to the vertex C for which we have to find the potential difference. Let A (x, y) be the coordinates of the vertex A.Let V1 be the potential at A due to the charge Q1.

Let V2 be the potential at A due to the charge Q2.Let V be the potential difference between the point A and the point O.The distance of A from Q1 and Q2 areOA=√x²+y² and OC=√(a-x)²+(a-y)² respectively.

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Answer:

The magnetic field through the wire must be changing

Explanation:

According to Faraday's law, the induced emf, ε in a metallic conductor is directly proportional to the rate of change of magnetic flux,Φ  through it. This is stated mathematically as ε = dΦ/dt.

Now for the wire, the magnetic flux through it is given by Φ = ABcosθ where A = cross-sectional area of wire, B = magnetic field and θ = angle between A and B.

So, dΦ/dt = dABcosθ/dt

Since A and B are constant,

dΦ/dt = ABdcosθ/dt = -(dθ/dt)ABsinθ

Since dθ/dt implies a change in the angle between A and B, since A is constant, it implies that B must be rotating.

So, for an electric current (or voltage) to be produced in the wire, the magnetic field must be rotating or changing.

The Horizontal motion of a kickball involves a constant speed and zero acceleration, as there are no external forces acting on it. The position-time graph shows a straight line with a constant slope, while the velocity-time graph displays a horizontal line at the constant velocity value.

The horizontal motion of a kickball can be described using the concepts of distance, displacement, speed, and velocity. When the kickball is kicked, it follows a parabolic trajectory with its horizontal motion being constant, assuming no external forces like air resistance act upon it.

On a position-time graph, the horizontal motion can be represented as a straight line with a constant slope, indicating a constant speed. The slope of this line represents the horizontal speed of the kickball. The greater the slope, the faster the kickball's horizontal speed.

On a velocity-time graph, the horizontal velocity remains constant, as there is no acceleration in the horizontal direction. This is depicted as a straight horizontal line at the constant velocity value.

In summary, the horizontal motion of a kickball involves a constant speed and zero acceleration, as there are no external forces acting on it. The position-time graph shows a straight line with a constant slope, while the velocity-time graph displays a horizontal line at the constant velocity value.

These features on the graphs support the understanding of the kickball's horizontal motion.

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Answer:Answer: Pressure is directly proportional to force and inversely proportional to area. Explanation: As from above it is visible that pressure is directly proportional to the force applied which means that if force increases, pressure increases. It is also inversely proportional to the area of cross-section.

Explanation: welcome

45° × π/180 = 0,7854 rad

ω = θ /t

ω = 0.7854 / 0.75 = 1.0472 rad/s

A) The altitude at apogee is 552.7 km, b) its period is 8876.2 seconds, c)  the velocity at perigee is 7223.4 m/s.

Altitude is the height of an object or point in relation to sea level or ground level. It is usually measured in meters or feet. Altitude is generally used when referring to points on the Earth's surface, while elevation is used for points above the surface, such as the summit of a mountain or hill.

a) Calculate its altitude at apogee: The orbital eccentricity of a satellite can be used to calculate its altitude at apogee by using the following equation: Apogee = Perigee / (1 - eccentricity)

Using the given information, we can calculate the altitude at apogee as follows: Apogee = 550km / (1 - 0.00187)

Apogee = 552.7 km (rounded to the nearest whole number)

b) Calculate its period: The orbital period of a satellite can be calculated using the following equation: Period = 2π √(a³ / μ)

where a is the semi-major axis of the orbit and μ is the gravitational parameter of the central body.

In this case, the semi-major axis of the orbit is given by:

a = (Perigee + Apogee) / 2

a = (550km + 552.7km) / 2

a = 551.35km

The gravitational parameter of the Earth is given by: μ = 3.986004418 x 10¹⁴ m³/s²

We can now calculate the period of the orbit as follows:

Period = 2π √(551.35km³ / 3.986004418 x 10¹⁴ m³/s²)

Period = 8876.2 seconds (rounded to the nearest whole number)

c) Calculate the velocity at perigee: The velocity of a satellite at perigee can be calculated using the following equation: V = √(μ (2/r - 1/a)), where a is the semi-major axis of the orbit, r is the radius of the orbit at perigee, and μ is the gravitational parameter of the central body.

Using the given information, we can calculate the orbital velocity at perigee as follows:

V = √(3.986004418 x 10¹⁴ m³/s² (2/550km - 1/551.35km))

V = 7223.4 m/s (rounded to the nearest whole number)

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A. Electrical energy  B. Elastic energy  are the forms of potential energy.

Potential energy is the energy possess by an object because due to its position relative to other objects, stresses within itself, its electric charge, or other factors.

Types of Potential energy:

Therefore,

Electrical energy , Elastic energy are the forms of potential energy.

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Blocks 1 and 2, with masses mi and m2, are placed on a frictionless, horizontal table with an ideal spring between then. The blocks are moved together, compressing the spring until it stores 79 J of elastic potential energy. When released from rest, the blocks move in opposite directions. Find the maximum speed v of block 2 if mı =7.84 kg and m2 =3.5 kg. V= 10.72 m/s

The maximum speed of block 2 in the given scenario is 10.72 m/s.

This was calculated by first finding the total initial potential energy stored in the spring when it was compressed, which was 79 J.

This energy is then divided equally between the two blocks as they move in opposite directions after the spring is released. The kinetic energy of block 2 at its maximum speed is calculated by equating the initial potential energy to the final kinetic energy of the block.

The mass of block 2 and the velocity are then substituted into the equation to solve for the maximum velocity.

Therefore, the maximum speed is obtained as 10.72 m/s.

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The wave if you replaced the string with one that has two times the mass density is 415 gm

What is density?
density is the mass of a material substance per unit volume. d = M/V, where d is density, M is mass, as well as V is volume, is the formula for density. Grams per cubic centimetre are a common unit of measurement for density. For instance, while Earth has a density of 5.51 grammes per cubic centimetre, water has a density of 1 grammes per cubic centimetre. Another way to state density is in kilogrammes per cubic metre (in metre-kilogram-second or SI units). For instance, air weighs 1.2 kilogrammes per cubic metre. In textbooks and manuals, the densities of typical solids, liquids, as well as gases are listed.

density given= 7.87 gm/cm^3

Let a = 3.75 cm

Find mass of sample

Volume= a^3

             =(3.75)^3 cm^3

Volume = 52.73 cm^3

d=7.87

v=52.7

d =mass/volume

mass = d×v

          =7.87×52.7

          =415 gm

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The statement "recognize that he is experiencing a complex psychiatric crisis, quickly load him into the ambulance, and transport without delay" is true.

In a general sense, recognizing that someone is experiencing a complex psychiatric crisis and providing appropriate medical attention and transportation is often a recommended course of action. However, it is important to consider that every situation is unique, and the specific response may vary based on factors such as the severity of the crisis, the individual's condition, and available resources.

In cases of psychiatric crises, it is crucial to prioritize the individual's safety and well-being. Prompt medical attention and transportation may be necessary to ensure they receive appropriate care and support.

However, it is essential to involve qualified professionals, such as mental health providers or emergency medical services, to assess the situation and determine the most appropriate course of action.

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Answer:

High current flow

Explanation:

Generally , the measuring instruments used by technician also have some resistance, though its value is very low  . So when high current is present in the circuit , that current also passes through the instrument which creates a good potential drop across the instrument . So the external voltage used in the circuit measures less voltage .

Answer:

D) 42.87 m/s

Explanation:

First, find the time it takes him to land.  Given in the y direction:

Δy = 60 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

60 m = (0 m/s) t + ½ (9.8 m/s²) t²

t = 3.5 s

Next, find the speed needed to travel the horizontal distance in that time.  Given in the x direction:

Δx = 60 m

a = 0 m/s²

t = 3.5 s

Find: v₀

Δy = v₀ t + ½ at²

150 m = v₀ (3.5 s) + ½ (0 m/s²) (3.5 s)²

v₀ = 42.87 m/s

The age of the universe in a flat universe, based on the given values, is approximately 3.454 × 10^16 seconds or approximately 1.094 billion years.

To calculate the age of the universe based on the observed recession velocity and assuming a flat universe, we can use the Hubble's Law equation:
v = H₀ × d
where:
v is the recession velocity of the galaxy,
H₀ is the Hubble constant, and
d is the distance to the galaxy.
The Hubble constant is the rate at which the universe is expanding and is typically expressed in units of km/s per megaparsec (km/s/Mpc).
Rearranging the equation, we can solve for time (t), which represents the age of the universe:
t = 1 / H₀
Given that the recession velocity (v) is 894 km/s and the distance (d) is 12 Mpc, we can substitute these values into the equation:
t = 1 / (894 km/s / 12 Mpc)
Converting the units to consistent values:
t = 1 / (894 km/s / 3.09 × 10^19 km/Mpc)
Evaluating the expression:
t = 1 / (2.897 × 10^−17 s^−1)

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The final pressure of the gas will be 26.8 kPa when has a final volume of 78.0L.

Boyle's law, also known as the Boyle-Mariotte law, is an experimental gas law that explains the connection between a confined gas's pressure and volume. The pressure of a gas is inversely related to its volume at constant temperature, as well as its number of moles, according to Boyle's law.

P ∝ 1/V

\(PV=k\) or \(P_{1} V_{1} =P_{2} V_{2}\)

\(P_{1}\)= initial gas pressure is 209 kPa

\(P_{2}\)= final pressure which is unknown.

\(V_{1\)= 10.0 L, which is the gas's initial volume.

\(V_{2}\)= 78.0 L, which is the gas's final volume.

We can now use this formula to obtain the final gas pressure by entering all the specified variables.

\((209kPa)(10.0L)=P_{2}(78.0L)\\P_{2}=26.8kPa\)

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The main difference between Kinetic energy and Potential energy is that kinetic energy refers to movement while potential energy refers to storage.

Kinetic energy is a type of energy in motion or energy in movement such as a turbine (mechanical energy), while Potential energy refers to the energy that is stored to be used when required (e.g. chemical bonds of foods).

Therefore, with this data, we can see that  Kinetic energy is used as movement, while Potential energy is stored to be used in the future.

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The diameter of the X-ray source, calculated based on a flickering frequency of 200 cycles per second, is approximately 2.53 × 10⁻¹⁷ kilometers.

To calculate the diameter of the X-ray source, we need to utilize the concept of the diffraction limit. The diffraction limit states that the smallest resolvable detail in an image is determined by the wavelength of the radiation and the aperture size of the instrument.

In this case, since we are dealing with X-rays, which have a very short wavelength, we can assume that the diffraction limit is governed by the size of the X-ray source itself. The formula for the diffraction limit is given by:

θ = λ / D

Where θ is the angular resolution, λ is the wavelength of the radiation, and D is the diameter of the source.

To calculate the diameter, we rearrange the formula:

D = λ / θ

Since the flickering frequency is given as 200 cycles per second, which corresponds to 200 oscillations in one second, we can determine the angular resolution as:

θ = 2πf

Where f is the frequency. Substituting the values into the equation, we have:

θ = 2π * 200 = 400π radians per second

Assuming an X-ray wavelength of approximately 0.01 nm, or 10⁻¹¹ meters, we can calculate the diameter as:

D = (10⁻¹¹ m) / (400π rad/s) ≈ 2.53 × 10⁻¹⁴ meters

Converting this to kilometers, we find that the diameter of the X-ray source is approximately 2.53 × 10⁻¹⁷ kilometers.

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Answer:

Force / mass

Explanation:

Divide mass on both sides to get acceleration by itself leaving you with mass below force hence divide force by mass

Answer: 40.311 m

Explanation:

Given

Ant walks 15 m east

then 40 m North and finally 20 m west

from the figure, ant is 40 m North and 5 m west

Using Pythagoras, we can write

\(\Rightarrow d=\sqrt{40^2+5^2}\\\Rightarrow d=\sqrt{1625}=40.311\ m\)

Answer:

The distance covered is 40 m and the displacement is 31,6m.

Explanation:

The distance covered is the sum of the two distances (10+30). The displacement is equal to the distance of the hipotenusa of the triangle that the two distances (10 m to north and 30m to east) create. Using the Pythagoras theorem the displacent is equal to the Square root of (30^2 +10^2) .

Explanation:

7a) The work function (ϕ) is the minimum energy required to remove an electron from the metal surface. It is related to the threshold frequency (fo) by the equation:

ϕ = hfo

where h is Planck's constant (6.626 x 10^-34 J s).

The threshold wavelength (Ao) can be calculated from the threshold frequency using the equation:

c = λf

where c is the speed of light (3.00 x 10^8 m/s).

Given that the work function of the metal surface is 3.0 eV, we have:

ϕ = 3.0 eV = (3.0 x 1.6 x 10^-19) J fo = ϕ/h = (3.0 x 1.6 x 10^-19) J / (6.626 x 10^-34 J s) ≈ 4.53 x 10^14 Hz Ao = c/fo = (3.00 x 10^8 m/s) / (4.53 x 10^14 Hz) ≈ 661 nm

Therefore, the threshold frequency is 4.53 x 10^14 Hz and the threshold wavelength is approximately 661 nm.

7b) The maximum kinetic energy of the emitted photoelectrons can be calculated using the equation:

KEmax = hf - ϕ

where h is Planck's constant, f is the frequency of the incident radiation, and ϕ is the work function of the metal surface.

The energy of a photon can be calculated from its wavelength using the equation:

E = hc/λ

where h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon.

Given that the wavelength of the incident radiation is 350 nm, we have:

f = c/λ = (3.00 x 10^8 m/s) / (350 x 10^-9 m) ≈ 8.57 x 10^14 Hz E = hc/λ = (6.626 x 10^-34 J s) x (3.00 x 10^8 m/s) / (350 x 10^-9 m) ≈ 1.79 eV

Therefore, the maximum kinetic energy of the emitted photoelectrons is:

KEmax = hf - ϕ = (6.626 x 10^-34 J s) x (8.57 x 10^14 Hz) - (3.0 x 1.6 x 10^-19) J ≈ 1.17 eV

a) The minimum frequency required to cause photoemission is equal to the threshold frequency:

fo = 8.9 x 10^14 Hz

Using the same equation as in part 7a), we can calculate the work function:

ϕ = hf0 = (6.626 x 10^-34 J s) x (8.9 x 10^14 Hz) ≈ 5.90 x 10^-19 J = 3.68 eV

b) i. The maximum kinetic energy of the emitted photoelectrons can be calculated using the same equation as in part 7b):

KEmax = hf - ϕ

The energy of a photon with wavelength 250 nm is:

E = hc/λ = (6.626 x 10^-34 J s) x (3.00 x 10^8 m/s) / (250 x 10^-9 m) ≈ 4.97 eV

Therefore, the maximum kinetic energy of the emitted photoelectrons is:

KEmax = hf -

the answer for number 2 is B

¿Cuál es la diferencia entre ciencia y tecnología?

La ciencia se refiere al proceso de explorar nuevos conocimientos metódicamente a través de la observación y los experimentos.

La tecnología se refiere al proceso de aplicar el conocimiento científico en aplicaciones prácticas para varios propósitos.

What is the difference between science and technology?

Science refers to the process of exploring new knowledge methodically through observation and experiments.

Technology refers to the process of applying scientific knowledge in practical applications for various purposes.

none of the above. According to Newton's third law of motion, for every action, there is an equal and opposite reaction.

In this case, if Joshua is attracted toward Earth by a 500 N gravitational force, then by Newton's third law, Earth is also attracted toward Joshua with an equal and opposite force of 500 N. The gravitational force between two objects is always mutual and equal in magnitude but opposite in direction.

Newton's third law of motion states that for every action, there is an equal and opposite reaction. This means that when an object exerts a force on another object, the second object exerts an equal and opposite force on the first object. The forces always occur in pairs and act on two different objects.

For example, if you push against a wall with a certain amount of force, the wall pushes back on you with an equal amount of force in the opposite direction. Another example is the propulsion of a rocket. The rocket pushes exhaust gases backward, and in response, the gases push the rocket forward with an equal force.

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You could pursue a career in oceanography, aircraft safety, energy conservation, air quality control, space exploration, or education. The most thorough and economical method for remotely monitoring these systems is via satellite.

Weather forecasting, remote sensing, geo-positioning, navigation, television, and telephony are a few of the services that satellites may offer for disaster risk management and emergency response.

For the purpose of taking pictures, atmospheric sounding, satellite communication, geo-positioning, and navigation, equipment onboard the satellites circling the Earth is created to cover a range of wavelengths in the electromagnetic spectrum.

Depending on the use or instrumentation, satellites orbit the Earth in a variety of ways: A satellite in a geostationary orbit revolves around the planet simultaneously with the rotation of the planet above the equator (0° latitude).

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When a force is applied to an object, it can cause a change in the object's motion or state of rest.

If the force is unbalanced, it can cause the object to accelerate or decelerate, resulting in a change in speed or direction. The effect of the applied force depends on the mass and nature of the object, as well as the magnitude and direction of the force. Additionally, the object may experience other effects, such as deformation or compression, depending on the type and direction of the force applied. Understanding the effects of applied forces is crucial in fields such as engineering, physics, and mechanics.

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--The complete question is, When force is Applied  on an object describe effect of action applied. --

Answer:

Actual Mechanical Advantage

Explanation:

AMA=mg/F(applied)