Consider a single slit that produces its first minimum at 59° for 620 nm light.

Answers

Answer 1

The width of the slit is 482 nm. The first minimum in a single slit diffraction pattern occurs at an angle given by the equation sinθ = λ/b,

where θ is the angle between the center of the diffraction pattern and the location of the minimum, λ is the wavelength of the light, and b is the width of the slit.

In this case, we are given that the first minimum occurs at 59° for 620 nm light.

Using the equation, we can solve for the width of the slit as b = λ/sinθ. Plugging in the values, we get b = (620 nm)/(sin(59°)) = 482 nm. Therefore, the width of the slit is 482 nm.

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Related Questions

Calculate the number of years it would take New Horizons space satellite to travel to the closest star to our Sun, Proxima Centauri, which is 4.3 light years away. New Horizons is the fastest space satellite ever launched with a speed of 53,000 kilometers per hour.

Answers

It would take approximately 716,943 years for the New Horizons space satellite to travel to Proxima Centauri at its current speed.

To calculate the number of years it would take for the New Horizons space satellite to travel to Proxima Centauri, we need to convert the speed of the satellite to the appropriate units and then use the formula for time:

Distance = Speed × Time

Given:

Distance to Proxima Centauri = 4.3 light years

Speed of New Horizons = 53,000 kilometers per hour

First, we need to convert the speed of New Horizons from kilometers per hour to light years per year. To do this, we'll use the conversion factor:

1 light year ≈ 9.461 × \(10^{12\) kilometers

Speed of New Horizons in light years per year:

Speed in light years per year = (53,000 kilometers per hour) × (1 year / 8766 hours) × (1 light year / 9.461 × \(10^{12\) kilometers)

Speed in light years per year ≈ 0.000006003

Now, we can calculate the time it takes to travel to Proxima Centauri:

Time = Distance / Speed

Time = 4.3 light years / 0.000006003 light years per year

Time ≈ 716,943 years

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PLEASE HELP !!!
Which types of decay cannot result in transmutation of the parent nucleus

A) gamma only

B) alpha and beta

C) alpha only

D) alpha and gamma

Answers

Gamma decay cannot result in the transmutation of the parent nucleus. Therefore, option (A) is correct.

What is Gamma Decay?

Gamma decay can be described as the emission of electromagnetic radiation of a high frequency that is a high energy, giving out excess energy to stabilize the unstable nucleus. Gamma rays can be defined as a stream of high-energy radiation given off by a nucleus undergoing radioactive decay.

Gamma decay can be described as the nucleus dropping from a higher energy level to a lower energy level through the emission of high-energy photons.

Therefore, the gamma-ray emitted is also of very high energy, just like x-rays. Due to their high energy of gamma rays, they are penetrating and thereby dangerous to biological life forms.

In the transmutation of an element, one element is converted into another element. In gamma decay, the transmutation of the parent nucleus does not take place. As the gamma-ray high-energy particles are represented as ⁰γ₀.

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An object was initially electrically neutral. After being rubbed, the object acquires a positive charge Q= 320 microcoulomb. Then, the object ________.
1.loses 2 X 10 15 electrons
2.gains 2 X 10 21 electrons
3.gains 2 X 10 15 electrons
4.loses 2 X 10 21 electrons

Answers

Correct Option A : The object has lost 2 x \(10^15\) electrons, which corresponds to a negative charge of -320 microcoulombs.

When an object is rubbed, it can transfer charge from one object to another. In this case, the object acquires a positive charge of 320 microcoulombs, which means that it has gained 320 microcoulombs of positive charge from somewhere else. Since the object was initially electrically neutral, this means that it must have lost an equivalent amount of negative charge in order to become positively charged.

The charge on an electron is\(-1.6 x 10^-19\) Coulombs. Therefore, to determine how many electrons the object has lost or gained, we can use the formula Q = Ne, where Q is the total charge in Coulombs, N is the number of electrons, and e is the charge of one electron.

In this case, we know that the object has gained 320 microcoulombs of positive charge. Therefore, we can set up the equation as follows:

320 x \(10^-6\) C = Ne

Solving for N, we get:

N = (320 x\(10^-6\) C) / (1.6 x \(10^-19\) C)

N = 2 x \(10^15\)

This means that the object has lost 2 x \(10^15\) electrons, which corresponds to a negative charge of -320 microcoulombs. Therefore, the correct answer is A, the object loses 2 x \(10^15\) electrons.

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An object was initially electrically neutral. After being rubbed, the object acquires a positive charge Q= 320 microcoulomb. Then, the object ________.

A. loses 2 X 10 15 electrons

B. gains 2 X 10 21 electrons

C. gains 2 X 10 15 electrons

D. loses 2 X 10 21 electrons

Compare and contrast what happens to matter when thermal energy is added to a
substance at its melting and boiling point to any temperature other than its melting
and boiling point.
Can anyone please give me a answer for this pls!

Answers

Answer:

When thermal energy is added to a substance at its melting or boiling point, the temperature of the substance remains constant as the added energy is used to break intermolecular bonds and cause a phase change from solid to liquid or from liquid to gas. In contrast, adding thermal energy at any temperature other than the melting or boiling point will cause the temperature of the substance to increase, as the added energy increases the kinetic energy of the particles, causing them to move faster and collide more frequently. At other temperatures, the intermolecular forces between the particles are not strong enough to cause a phase change until the substance reaches its melting or boiling point.

please help 30 points. write definition and examples of each. (give atleast 2 examples).
a) luminous objects.
b) non- luminous objects.
c) opaque objects.
d) translucent objects.
e) transparent objects.​

Answers

objects that generate light are called as luminous objects

objects that do not generate light are called as luminous objects

objects in which light cannot pass through it is known as opaque

objects in which light pass partially through it is known as translucent

objects in which light can pass through it in known as transparent

Answer:

a) luminous objects.

= If light is emitted by object,the object is called Luminous Object.

Examples: Torch, Candle, etc.

b) non- luminous objects.

= Objects that cannot emit light energy by themselves are known as non-luminous objects.

Examples: Moon, wood, etc.

c) opaque objects.

= The object which do not allow the light to pass through are called opaque object.

Examples: stone, wood etc.

d) translucent objects.

= Those objects through which light can pass partially are called translucent objects.

Examples: paper, plastic, etc.

e) transparent objects.

= Those object through which light can pass easily are called transparent.

Examples: water, glass, etc.

Hope it helps !

please help 30 points. write definition and examples of each. (give atleast 2 examples).a) luminous objects.b)
please help 30 points. write definition and examples of each. (give atleast 2 examples).a) luminous objects.b)

How do astronomers find asteroids heading toward Earth?

Answers

Astronomers use a variety of techniques to find asteroids that may be on a collision course with Earth. Some of them are by using optical telescopes and infrared telescopes, and radio telescopes. Once an asteroid is detected, astronomers use its position and velocity data to calculate its orbit and determine if it poses a threat to Earth.

Optical telescopes are equipped with cameras that can take images of a large area of the sky at once. The images are then compared over time to identify asteroids that are moving in relation to the stars.

Infrared telescopes are useful for finding asteroids that are in the inner solar system, where they are closer to the sun and therefore warmer. This is particularly useful for finding asteroids that are difficult to detect using traditional optical telescopes, as many asteroids are dark and therefore do not reflect much light.

Radio telescopes involve bouncing radar waves off asteroids and measuring the time it takes for the waves to return. By analyzing the radar data, astronomers can determine the asteroid's distance and speed, as well as its size and shape.

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the velocity of a car changes from 5 m/s to 20 m/s in 30 sec the acceleration?​

Answers

Answer:

0.5m/s2

..............

the velocity of a car changes from 5 m/s to 20 m/s in 30 sec the acceleration?
a = vf -vi/t
Velocity final - velocity initial/ time
(20 m/s - 5 m/s)/ 30s
15 m/s/ 30s = 0.5 m/s^2

During a ______ Moon phase, the side of the Moon facing Earth isn't reflecting any sunlight from the Sun.
A: Full

B: New

Answers

Answer:

B) New

During a new Moon phase, the side of the Moon facing Earth isn't reflecting any sunlight from the Sun.

light rays that are near and parallel to the principal axis of a concave mirror converge to a point 18 cm in front of the mirror. what is the radius of curvature of the mirror?

Answers

Light rays that are near and parallel to the principal axis of a concave mirror converge to a point 18 cm in front of the mirror. The radius of curvature of a concave mirror can be calculated as -36 cm.

According to the mirror equation, 1/f = 1/do + 1/di, where f is the focal length of the mirror, do is the object distance, and di is the image distance. For a concave mirror, the focal length is negative and is equal to half the radius of curvature .

f = -R/2

In this case, the image distance is positive because the light rays converge to a point in front of the mirror. The object distance  is taken as negative because the object is located in front of the mirror. Substituting the given values, we get

1/f = 1/-18 + 1/di,

which simplifies to f = -36 cm.

Since the focal length is equal to half the radius of curvature, we can conclude that the radius of curvature of the mirror is -2f = 72 cm (negative because it is a concave mirror). Therefore, the radius of curvature of the mirror is 72 cm.

In conclusion, the radius of curvature of the concave mirror can be calculated as -36 cm based on the given information about the point where the light rays converge. This corresponds to a focal length of -18 cm and a radius of curvature of -72 cm.

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What percentage of maximum heart rate should be the target in doing vigorous-intensity workout?
A. 77% and 93% C. 75% and 90%
B. 77% and 95% D. 77% and 100%​

Answers

Your ideal heart rate for vigorous intensity physical activity should be between 77% and 93% of your maximum heart rate. here option A is correct.

You should feel like you can do the activity for a longer period of time while the intensity is still low. You can educate your body to exercise for extended periods of time in this zone, which is all about increasing your endurance. Active Intensity. In general, you won't be able to speak for more than a few words without pausing to take a breath if you're engaging in vigorous-intensity activities. Running, jogging, or race walking. The American Heart Association recommends working at 70 to 85 percent of your maximal heart rate for a vigorous activity. Running is an example of a rigorous workout. at least 10 mph when cycling. carrying a large bag while moving quickly uphill.

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What event most likely created the atoms of gold found in your jewellery or electronics?
a) the big bang
b) two black holes merging
c) two neutron stars merging
d) a supernova

Answers

The most likely event that created the atoms of gold found in your jewellery or electronics is d) a supernova.

Gold is a heavy element that is not formed during the Big Bang, which primarily produced lighter elements like hydrogen and helium. Instead, gold is produced through a process called nucleosynthesis, which occurs in the cores of massive stars. When a massive star explodes as a supernova, it releases a tremendous amount of energy and heat, causing the fusion of elements such as hydrogen and helium into heavier elements like gold. These elements are then dispersed into space and eventually become part of the materials that make up our planet and the objects we use. Therefore, the most likely event that created the atoms of gold found in jewelry or electronics is a supernova.

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Do electromagnetic waves require matter to travel?

Answers

Answer:

No.

Explanation:

Electromagnetic waves do not require a medium of matter to move through, electromagnetic waves are used in things like your cell phone and telecommunications.

1. A car starts from the rest on a circular track with a radius of 300 m. It accelerates with a constant tangential acceleration of a = 0.75 m/s?. Determine the distance traveled and the time elapsed"

Answers

Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.

To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.

The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).

Using the equation:

v = v₀ + at

where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:

v = 0 + (0.75 m/s²) * t

v = 0.75t m/s

The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:

v = ωr

Substituting the values:

0.75t = ω * 300

Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:

ω = ω₀ + αt

ω = 0 + (0.75 m/s²) * t

ω = 0.75t rad/s

We can now substitute the value of ω into the equation:

0.75t = (0.75t) * 300

Simplifying the equation gives:

0.75t = 225t

t = 0.75 seconds

The time elapsed is 0.75 seconds.

To calculate the distance traveled (s), we can use the equation:

s = v₀t + (1/2)at²

Since the initial velocity (v₀) is zero, the equation becomes:

s = (1/2)at²

s = (1/2)(0.75 m/s²)(0.75 s)²

s = (1/2)(0.75 m/s²)(0.5625 s²)

s = 0.2119 meters or approximately 21.19 centimeters

Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.

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the phase angle of an rlc series circuit with a capacitive reactance of 40 ω, a resistor of 100 ω and a certain inductor at 1000 hz is 40.0°. what is the value of the inductance in this circuit?

Answers

The value of the inductance in this RLC series circuit is approximately 0.01336 H (or 13.36 mH).

To calculate the value of the inductance in an RLC series circuit with a given phase angle, capacitive reactance, and resistor, we can use the following formula:

tan(θ) = Xc / R

where:

- θ is the phase angle (given as 40.0°)

- Xc is the capacitive reactance (given as 40 Ω)

- R is the resistance (given as 100 Ω)

Let's substitute the given values into the formula and solve for Xc:

tan(40.0°) = 40 Ω / 100 Ω

Using a scientific calculator, we can find the value of tan(40.0°) to be approximately 0.8391.

0.8391 = 40 Ω / 100 Ω

Now, let's solve for the inductive reactance (XL):

XL = tan(40.0°) * R

  = 0.8391 * 100 Ω

  ≈ 83.91 Ω

Since the inductive reactance is given by the formula XL = 2πfL, where f is the frequency and L is the inductance, we can rearrange the formula to solve for L:

L = XL / (2πf)

Given that the frequency (f) is 1000 Hz, let's substitute the values and calculate the inductance (L):

L = 83.91 Ω / (2π * 1000 Hz)

 ≈ 0.01336 H

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When calculating residential service load, ___ is allowed for each branch circuit serving laundry receptacles.

Answers

When calculating residential service load, 1,500 VA is allowed for each branch circuit serving laundry receptacles.

In residential electrical systems, branch circuits are used to supply power to various areas or appliances within a home. When determining the residential service load, specific allowances are made for different circuits based on their intended purpose and expected usage. For laundry receptacles, a standard allowance of 1,500 VA (volt-amperes) is typically allocated per branch circuit. This allowance takes into account the electrical demands of typical laundry equipment such as washing machines and dryers.

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Wind energy is increasingly relied upon to help meet global energy needs. Wind energy can be used to generate electricity using wind turbines. What correctly identifies the sequence of energy conversions that occur in a wind turbine?

Answers

The sequence of energy conversions that occur in a wind turbine can be identified as follows: Kinetic Energy -> Mechanical Energy -> Electric Energy

What is the sequence of energy conversions that occurs in a wind turbine?

The kinetic energy of the wind is converted into mechanical energy as the blades of wind turbine turn.

Mechanical energy of the spinning blades is then converted into electrical energy by generator that is connected to the turbine.

And then finally,  electrical energy produced by the generator is transmitted to power grid or to a battery for storage and later use.

So, the sequence of energy conversions in a wind turbine is from kinetic energy to mechanical energy to electrical energy.

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Note: The question given on the portal is incomplete. Here is the complete question.

Question: Wind energy is increasingly relied upon to help meet global energy needs. Wind energy can be used to generate electricity using wind turbines. What correctly identifies the sequence of energy conversions that occur in a wind turbine?

Kinetic Energy -> Mechanical Energy -> Electric Energy

Mechanical Energy -> Kinetic Energy -> Electric Energy

Kinetic Energy ->Electric Energy ->  Mechanical  Energy

If a 779.29 kg object traveling at 969.39 m/s to the right
experiences a force of 48.4 newton's to the right for 9
seconds, what is its change in momentum?

Answers

The change  in momentum is 435.6 Kgm/s

What is the change in momentum from Newton's law?

Newton's second law of motion states that the rate of change of momentum of an object is directly proportional to the force applied, and the change in momentum takes place in the direction of the applied force.

The mathematical expression of Newton's second law is as follows:

F = dp/dt

where F is the force applied on the object, p is the momentum of the object, and t is time. dp/dt represents the rate of change of momentum over time.

From this equation, we can see that the change in momentum (Δp) of an object due to a force is equal to the product of the force (F) and the time (Δt) over which the force is applied:

Δp = F Δt

From Newton's law;

Ft = mv - mu

Where mv - mu = Δp or change in momentum

Then;

Ft = 48.4 * 9 = 435.6 Kgm/s

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Why was Roemer's measurement of the speed of light inaccurate?

a) because man's reaction time was much slower than the speed of light
b) because the eclipses of Jupiter's were not regular enough
c) he did not know the accurate diameter of the Earth's orbit

Answers

C bc you have to have the accurate diameter of earths orbit

For the following elementary reaction 2br• -> br2-. The rate of consumption of the reaction and the rate of formation of product is given by which set of expression? ​

For the following elementary reaction 2br -> br2-. The rate of consumption of the reaction and the

Answers

Answer: \(-\frac{1}{2}\times \frac{d[Br^.]}{dt}=+\frac{d[Br_2]}{dt}\)

Explanation:

Rate of a reaction is defined as the rate of change of concentration per unit time.

Thus for reaction:

\(2Br^.\rightarrow Br_2\)

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

\(Rate=-\frac{d[Br^.]}{2dt}\)

or \(Rate=+\frac{d[Br_2]}{dt}\)

Thus \(-\frac{d[Br^.]}{2dt}=+\frac{d[Br_2]}{dt}\)

What is the symbol for Pressure ? Help

Answers

Answer:

The answer is Pascal or Pa.

Answer:

Pa or small p

Explanation:

Force over Area. The SI unit is Pascal

What percentage of college graduates believe their education was useful for helping them grow personally and intellectually, but not useful for helping them develop specific skills and knowledge for the workplace? Write your answer as a percentage but do not include the % symbol.

Answers

Percentage of college graduates believing their education was useful for helping them grow personally and intellectually, but not useful for helping them develop specific skills and knowledge for the workplace is 70%.

According to a 2018 study by the Association of American Colleges and Universities, approximately 70% of college graduates believe that their education was very or somewhat effective in helping them grow personally and intellectually, but not very effective in helping them develop specific skills and knowledge for the workplace.

This suggests that many college graduates may feel that their education did not adequately prepare them for the demands of the labor market, despite being beneficial for personal and intellectual growth. This finding highlights the importance of considering the alignment between higher education and workforce development, as well as the need for continued learning and skill development beyond formal education.

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Rainfall from a slow-moving thunderstorm was over 5 inches. This storm led to
the erosion of about 0.2 mm of soil from a field. Express this soil loss in Mg ha-1 (Ton/ha) if the bulk density
of the soil is 1.01 Mg m-3.

Please show your work!
a. 0.202 Mg/ha
b. 2.02 Mg/ha
c. 20.2 Mg/ha

Answers

The soil loss in  \(Mg ha^{-1}\) (Ton/ha) if the bulk density of the soil is 1.01  \(Mg m^{-3}\)  is option a. 0.202 Mg/ha.

For expressing the soil loss in \(Mg ha^{-1}\), need to convert the units appropriately. First, convert the soil loss from millimetres (mm) to meters (m) by dividing it by 1,000 (1 mm = 0.001 m). Thus, the soil loss is 0.0002 m.

Next, calculate the volume of soil lost per unit area (ha). The volume can be obtained by multiplying the soil loss (0.0002 m) by the area (ha). Since the bulk density of the soil is given as 1.01 \(Mg m^{-3}\), can convert the volume to mass by multiplying it by the bulk density.

Using the formula:

Soil loss (Mg ha-1) = Soil loss (m) × Bulk density (\(Mg m^{-3}\)) × Area (ha)

Substituting the values:

Soil loss (\(Mg ha-1\)) = 0.0002 m × 1.01 \(Mg m^{-3}\) × 1 ha

Calculating the result:

Soil loss (\(Mg ha-1\)) = 0.0002 × 1.01 = 0.000202 \(Mg ha-1\)

Therefore, the correct answer is option a. 0.202 Mg/ha.

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Sumin runs 50 meters from her house to the park down the street. She then keeps running in the same direction to her friend's house 150 Meters from the park. She then turns around and goes back to the park. What is Sumin's average velocity during her run if it takes her 2 minutes to complete?
A. 25 m/s
B.2.92 m/s
C.3.33 m/s
D.0.417 m/s​

Answers

Answer:

d. 0.417 m/s

Explanation:

v= ▲x/t

(350-150)/120 s

= .417 m/s

what is the angular-momentum quantum number, ℓ, for the orbital shown here?

Answers

The orbital form of an electron is generally described by the angular momentum quantum number, denoted by the letter l. The value of the main quantum number, n, determines the value of l.

How can the orbital angular momentum L be determined?

The sum of the orbital angular momenta from each electron creates the total orbital angular momentum, which has a magnitude of square root of L(L + 1) (L), where L is an integer.

How is the angular quantum number L calculated?

Therefore, using the equation l=n1 l = n 1 and knowing the main quantum number, it is easy to determine the angular momentum quantum number. According to this statement, the primary quantum number will never be greater than the azimuthal quantum number.

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Some comparisons between Earth and a heavenly body are as follows: Mass of Earth= 10 times the mass of heavenly body Radius of Earth=- 2 times radius of heavenly body If the weight of 1kg of water is 10 N on Earth, Calculate the weight of 10 kg of water on heavenly body.​

Answers

We can use the formula for gravitational force to calculate the weight of 10 kg of water on the heavenly body:

F = G (m1m2)/r^2

where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between their centers.

First, let's find the mass and radius of the heavenly body in terms of Earth's values:

Mass of heavenly body = (1/10) * Mass of Earth
Radius of heavenly body = (1/2) * Radius of Earth

Now we can substitute these values into the gravitational force formula and solve for the weight of 10 kg of water on the heavenly body:

F = G [(10 kg) * (1/10) * (Mass of Earth)] / [(1/2 * Radius of Earth)^2]

F = G [(10 kg) * (1/10) * (10 * weight of 1kg of water)] / [(1/2 * radius of Earth)^2]

F = G * weight of 1kg of water * 50

F = (6.674 × 10^-11 N m^2/kg^2) * (10 N) * 50

F = 3.337 × 10^-8 N

So the weight of 10 kg of water on the heavenly body is 3.337 × 10^-8 N.

Answer:

Let's assume that the heavenly body has a mass of m and a radius of r. According to the given information:

Mass of Earth = 10 times the mass of heavenly body

Therefore, the mass of the heavenly body = 1/10 times the mass of Earth

m = (1/10) * M

Radius of Earth = -2 times radius of heavenly body

Therefore, the radius of the heavenly body = -1/2 times the radius of Earth

r = (-1/2) * R

Weight of 1 kg of water on Earth = 10 N

This means that the gravitational acceleration on Earth is g = 10 m/s^2

To calculate the weight of 10 kg of water on the heavenly body, we can use the formula for weight:

weight = mass * gravitational acceleration

The mass of 10 kg of water is 10 kg, and the gravitational acceleration on the heavenly body can be calculated using the formula:

g' = G * m / r^2

where G is the gravitational constant (6.67 x 10^-11 N*m^2/kg^2).

Substituting the values, we get:

g' = G * m / r^2

g' = 6.67 x 10^-11 * (1/10) * M / ((-1/2) * R)^2

g' = 2.688*10^-11  * M / R^2

Now, we can calculate the weight of 10 kg of water on the heavenly body:

weight = mass * gravitational acceleration

weight = 10 * (2.688*10^-11   * M / R^2)

weight = 2.668 x 10^-10* M / R^2

Therefore, the weight of 10 kg of water on the heavenly body is 2.668 x 10^-10 times the mass of the heavenly body divided by the square of its radius.

a small nail may Pierce an inflated car tyre and remain there without pressure reduction in the tyre ..explain the observation ​

Answers

The rubber is stretched and firmly gripped by the nail due to the pressure inside the tire, which prevents air leakage.

What is the pressure ?

The force of all gas particle/wall collisions divided by the surface area of the wall is the definition of pressure (P): One of the fundamental measurable quantities of this phase of matter, pressure is a property shared by all gases. The amount of force applied to a given area is referred to as pressure.

For instance, the weight of the snow divided by the area of the roof would represent the pressure from snow on a roof. Gases are typically where pressure in chemistry comes from. Gas is added to a balloon before it is inflated. Gas molecules collide with one another and the balloon's walls.

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Mountain goats can easily scale slopes angled at 60° from horizontal. What are the normal force and the static friction force acting on a mountain goat that weighs 900 N and is standing on such a slope?

Answers

The normal force on the mountain goat is equal in magnitude to the force of gravity acting on it, which is 900 N.

The normal force is perpendicular to the slope and prevents the mountain goat from falling into the slope. The static friction force acts parallel to the slope and in the opposite direction of motion. When the mountain goat is stationary, the force of static friction balances the component of the force of gravity that is acting parallel to the slope. Therefore, the static friction force has a magnitude of 900 N times the sine of the slope angle, which is sin(60°) = 0.866. So the static friction force is 900 N × 0.866 = 781.4 N.

As long as the force of gravity acting parallel to the slope does not exceed the maximum static friction force, the mountain goat will remain stationary on the slope. If the force of gravity does exceed the maximum static friction force, the mountain goat will slide down the slope.

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Two trains sound identical horns of frequency 410 Hz. One train is stationary. The other is moving away from an observer, who heats a beat frequency of 35 Hz. How fast is the moving train going?

Answers

The speed of the moving train is approximately 33.5 m/s.

The beat frequency is given by the difference in frequency between the two horns, which is equal to the Doppler shift in frequency due to the motion of the moving train. Using the formula for the Doppler effect, we can solve for the speed of the train:

\(f_b = f_s\dfrac{(v + v_o)}{(v + v_s)}\)

where \(f_b\) is the beat frequency, \(f_s\) is the horn frequency, v is the speed of sound, \(v_o\) is the observer's speed, and \(v_s\) is the speed of the source.

We know that \(f_s\) = 410 Hz and \(f_b\) = 35 Hz. The speed of sound in air at standard temperature and pressure is approximately 343 m/s. Since the observer is stationary, \(v_o\) = 0.

Solving for \(v_s\), we get:

\(v_s = \dfrac{(f_s + f_b)}{f_s - 1} \times v\)

\(v_s\) = ((410 Hz + 35 Hz) / 410 Hz - 1) * 343 m/s

\(v_s\) = 33.5 m/s

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a 1.6 m diameter solid spgere rotates about an axis through its center by torque of 30.0 m.n which accelerates it uniformly from rest through a total of 400 revolutions in 12.0 secod. what is the mass of the sphere?

Answers

Using the moment of inertia, the mass (m) of the sphere is found to be approximately 6.513 kg.

To find the mass of the sphere, we need to use the formulas for torque and rotational motion.

The formula for torque (τ) is given by:

τ = I × α

Where:

τ = Torque

I = Moment of inertia

α = Angular acceleration

The moment of inertia (I) for a solid sphere rotating about its center is given by:

I = (2/5) × m × r²

Where:

m = Mass of the sphere

r = Radius of the sphere

The formula for angular acceleration (α) is:

α = (ω - ω0) / t

Where:

ω = Final angular velocity

ω0 = Initial angular velocity

t = Time

First, we need to find the final angular velocity (ω) using the given information. We know that the sphere rotates through a total of 400 revolutions in 12.0 seconds. One revolution is equal to 2π radians, so the total angular displacement (θ) is:

θ = 400 revolutions × 2π radians/revolution

θ = 800π radians

The time (t) is given as 12.0 seconds. We can now calculate the final angular velocity:

ω = θ / t

ω = (800π radians) / (12.0 s)

ω ≈ 209.4395 rad/s

Since the sphere starts from rest, the initial angular velocity (ω0) is 0 rad/s. Plugging the values into the formula for angular acceleration:

α = (ω - ω0) / t

α = (209.4395 rad/s - 0 rad/s) / (12.0 s)

α ≈ 17.4533 rad/s²

Now, we can use the formula for torque to find the moment of inertia (I):

τ = I × α

30.0 m·N = I × 17.4533 rad/s²

Since the torque (τ) and angular acceleration (α) are given, we can solve for the moment of inertia (I). Rearranging the equation:

I = τ / α

I = 30.0 m·N / 17.4533 rad/s²

I ≈ 1.7204 kg·m²

Finally, we can use the moment of inertia to find the mass (m) of the sphere:

I = (2/5) × m × r²

1.7204 kg·m² = (2/5) × m × (0.8 m)²

Simplifying the equation:

m = (1.7204 kg·m²) / [(2/5) × (0.8 m)²]

m ≈ 6.513 kg

Therefore, the mass of the sphere is approximately 6.513 kg.

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Analyze What could you do to change the
volume of a gas?

Answers

You can change the volume, pressure, or temperature of a gas.

Change the volume of a gas to raise or lower the temperature. As the temperature increases, the gas expands and increases in volume. Conversely, as the temperature decreases, the volume of the gas decreases. As the temperature increases, the volume of the gas increases. Conversely increasing the pressure will decrease the volume of the gas.

Reducing the gas volume increases the gas pressure. An example of this is when gas is trapped inside a cylinder by a piston. When the piston is pushed in, the volume occupied by the gas decreases, so there is less room for gas particles to move. The relationship between pressure and volume Boyle's Law. As the pressure of a gas increases the gas particles are pushed together thus decreasing the volume of the gas.

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