Consider an automobile moving at v mph that skids d feet after its brakes lock. Calculate how far it would skid if it was moving at 2v and the brakes were locked.

Answers

Answer 1

Answer:

KE1 = 1/2 M V^2

KE2 = 1/2 M (2*V)^2

KE2 = 4 KE1

If stopping distance is proportional to the original KE then the stopping distance is 4 times great for the car moving at 2 * V


Related Questions

The map shows faults located near the Pacific and North American tectonic plates, including the San Andreas Fault. Arrows indicate direction of motion on either side of the faults.

Identify a natural hazard commonly associated with the geologic features shown on the map. Describe the relationship between these features and the hazard.

The map shows faults located near the Pacific and North American tectonic plates, including the San Andreas

Answers

That Pacific Plate the Northern American Plate are separated from one another by San Andreas Fault. While a Northern American Plate is migrating the southwest and east, it Pacific Plate moves a north west.

What is the name of San Andreas line?

A transform fault, the 1,200-kilometer-long the San Andreas fault zone forms a section of the boundary between both the Pacific or North American plates. It links the Mendocino fissure zone or the Cascade subduction junction to the north with the Pacific Plate Rise inside the Gulf of California.

What is the San Andreas Line?

Southwestern North America is home to the San Andreas Fault, a significant Earth's crustal fissure. From the northern end of a Gulf of California across western California in the United States, the fissure trends northwestward for further than 800 miles (1,300 km), heading out to sea into the Pacific Ocean not far from San Francirsco.

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A 35.30-kg box is attached to a light string that is wrapped around a cylindrical frictionless spool of radius 10.0 cm and moment of inertia 4.00 kg * m^2. The spool is suspended from the ceiling, and the box is then released from rest a distance from rest a distance 3.50 m above the floor. How long does it take for the box to reach the floor?

Answers

Answer:

The velocity of the box is related to the angular velocity of the spool, which is given by the equation:

v = r * ω

where r is the radius of the spool and ω is the angular velocity of the spool. The angular velocity of the spool, in turn, is related to the torque applied to the spool by the tension in the string, which is given by the equation:

τ = I * α

where τ is the torque, I is the moment of inertia of the spool, and α is the angular acceleration of the spool.

The tension in the string is equal to the weight of the box, which is given by:

T = m * g

Putting all of these equations together, we can solve for the time it takes for the box to reach the floor. Here's how:

First, we can find the angular acceleration of the spool using the torque equation:

τ = I * α

T = m * g = τ

m * g = I * α

α = (m * g) / I

α = (35.30 kg * 9.81 m/s^2) / 4.00 kg*m^2

α = 86.53 rad/s^2

Next, we can find the angular velocity of the spool using the kinematic equation:

ω^2 = ω_0^2 + 2 * α * θ

where ω_0 is the initial angular velocity (which is zero), θ is the angle through which the spool has turned (which is equal to the distance the box has fallen divided by the radius of the spool), and ω is the final angular velocity (which is what we want to find). Solving for ω, we get:

ω^2 = 2 * α * θ

ω = sqrt(2 * α * θ)

ω = sqrt(2 * 86.53 rad/s^2 * (3.50 m / 0.10 m))

ω = 166.6 rad/s

Finally, we can find the time it takes for the box to reach the floor using the equation:

v = r * ω

v = 0.10 m * 166.6 rad/s

v = 16.66 m/s

t = d / v

t = 3.50 m / 16.66 m/s

t = 0.21 s

What was Gan De's contribution to astronomy?
A.
He developed the world's first star catalogue.
B.
He was the first to record a lunar eclipse.
C.
He was the first to observe planets.
D.
He invented the telescope.

Answers

Answer:  A. He developed the world's first star catalogue.

Explanation: Gan De's contribution to astronomy was the development of the world's first star catalogue , along with his colleague Shi Shen. He also made observations of the planets, particularly Jupiter, and may have been the first to describe one of Jupiter's moons. Unfortunately, all of Gan De's writings have been lost, but fragments of his works' titles and quoted fragments are known from later texts.

a particle weighing 250N accelerates from 8.5m/s when a force of 125N acts on it. Find the velocity after 5.5sec​

Answers

The velocity of the particle after 5.5 seconds is 11.25 m/s.

To find the velocity of the particle after 5.5 seconds, we can use the equation of motion:

v = u + at

Where:

v = final velocity

u = initial velocity

a = acceleration

t = time

Given:

u = 8.5 m/s (initial velocity)

a = F/m = 125 N / 250 N = 0.5 m/\(s^2\) (acceleration)

t = 5.5 sec (time)

substitute the values:

v = 8.5 m/s + (0.5 m/\(s^2\))(5.5 sec)

v = 8.5 m/s + 2.75 m/s

v = 11.25 m/s

Therefore, the velocity of the particle after 5.5 seconds is 11.25 m/s.

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When a skater pulls her arms in, it
reduces her moment of inertia from
2.12 kg m² to 0.699 kg-m². If she was
initially spinning 3.25 rad/s, what is
her final angular velocity?

Answers

The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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why do astronauts weigh less on the moon than on earth

Answers

Answer:

Explanation: The moon of the Earth is much lighter in mass than the planet itself. In addition to being smaller than Earth, the Moon is also only approximately 60% as dense. A human weighs less on the Moon because there is less gravitational attraction there than there is on Earth.

Moon has lesser mass as conpared to earth, therefore gravitational force exerted by moon on any object is lesser than that of gravitational force exerted by earth on the same object, hence we can say that astronauts weight less on moon, i.e approximately 1/6 th of their weight on earth.

Heather and Jerry are standing on a bridge 46 m
above a river. Heather throws a rock straight down with a speed of 14 m/s
. Jerry, at exactly the same instant of time, throws a rock straight up with the same speed. Ignore air resistance. How much time elapses between the first splash and the second splash?

Answers

The time elapsed between the first splash and the second splash is approximately 0.69 seconds.

To calculate this, we consider the motion of two rocks thrown simultaneously from a bridge. Heather throws a rock straight down with a speed of 14 m/s, while Jerry throws a rock straight up with the same speed.

We use the equation for displacement in uniformly accelerated motion: s = ut + (1/2)at^2.

For Heather's rock, which is thrown downwards, the initial velocity (u) is positive and the acceleration (a) due to gravity is negative (-9.8 m/s^2). The displacement (s) is the height of the bridge (46 m).

Solving the equation, we find two possible values for the time (t): t ≈ -4.91 s and t ≈ 1.91 s.

Since time cannot be negative in this context, we discard the negative value and consider t ≈ 1.91 s as the time it takes for Heather's rock to hit the water.

For Jerry's rock, thrown upwards, we use the same equation with the same initial velocity and acceleration. The displacement is also the height of the bridge, but negative.

Solving the equation, we find t ≈ -5.68 s and t ≈ 1.22 s. Again, we discard the negative value and consider t ≈ 1.22 s as the time it takes for Jerry's rock to reach its maximum height before falling back down.

To find the time difference between the first and second splash, we subtract t ≈ 1.91 s (Heather's rock) from t ≈ 1.22 s (Jerry's rock). This gives us a time difference of approximately 0.69 seconds.

Therefore, the time elapsed between the first splash and the second splash is approximately 0.69 seconds.

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A similar device includes a transformer so that an MP3 player can also be charged. The primary coil has 300 turns.

(a) How many turns are needed in the secondary winding if the voltage is stepped up from 6.2 V to 15.5 V?

(b) Given that the current in the primary winding is 10 mA, what power is transmitted to the secondary windings if the transformer is 77% efficient?​

Answers

The secondary coil needs 120 turns.The power transmitted to the secondary winding is 0.155 W.

How does the voltage change between the primary and secondary coil in a transformer?

A transformer works by using electromagnetic induction to transfer electrical energy between two circuits. The voltage changes between the primary and secondary coil based on the ratio of the number of turns in each coil. In a step-up transformer, the voltage is increased from the primary to the secondary coil, while in a step-down transformer, the voltage is decreased.

What are some common uses for transformers in electronic devices?

Transformers are commonly used in electronic devices to convert voltage levels, isolate circuits, and match impedances. They are often used in power supplies to step down the voltage from the wall outlet to a level that can be used by the device. They are also used in audio amplifiers to match the impedance of the output to the speaker, and in radio and television receivers to tune in to different frequencies.

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Helppp!!

Research indicates that teenagers tend to become impaired by alcohol
adults.
A. faster than
B. slower than
C. at the same rate as

Answers

Answer:

A faster because teens what to drink it more when. they see there parents do it

Research indicates that teenagers have a faster tendency compared to adults in these case.

What are the process to encourage good behavior in pre-teens and teenagers?

Good behavior in pre-teens and teenagers starts with positive communication and warm relationships. This lays the foundation for guiding your child’s behavior in a positive way.

Here are some practical tips for putting this positive approach into action.

Active listening entails paying close attention to your child's words and body language while they are being said. This enables you to pay attention to your child's feelings and thoughts. Additionally, it demonstrates to your child your concern and interest in them.Clear expectations concerning behaviour are outlined in family rules. Include every member of the family in the rule-setting talks, if you can. Maintaining good rules is important. For instance, you might say, "We treat each other with respect," rather than, "Don't be disrespectful."

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1. A 15.0 kΩ resistor is hooked up to a 45.0 V battery in a circuit with a switch.
(a) Draw a circuit diagram for the circuit described. Label all parts and values.
(b) What is the current flowing through the resistor?
(c) What is the power dissipated by the resistor?

Answers

(a) The circuit diagram is in the image attached.

(b) The current flowing through the resistor is 0.003 A.

(c) The power dissipated by the resistor is  0.135 W.

What is current flowing through the resistor?

(b) The current flowing through the resistor is calculated by applying Ohm's law as follows;

V = IR

I = V/R

where;

V is the voltageR is resistance

I = 45 V / 15,000Ω

I = 0.003 A

(c) The power dissipated by the resistor is calculated as follows;

P = IV

where;

I is the current V is the voltage

P = 0.003 x 45 V

P = 0.135 W

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1. A 15.0 k resistor is hooked up to a 45.0 V battery in a circuit with a switch.(a) Draw a circuit diagram

. When a longitudinal wave passes through air, the instantaneous acceleration of the particle is proportional to its A. velocity B. displacement C. time period D. frequency ​

Answers

Answer:a i think

Explanation:

When a longitudinal wave passes through air, the instantaneous acceleration of the particle is proportional to its displacement. Hence, option (B) is correct.

What is simple harmonic motion?

Simple harmonic motion is a specific sort of periodic motion of a body that arises from a dynamic equilibrium between an inertial force in mechanics and physics (often referred to as SHM).

It operates as a restoring force on the moving object that is directly proportional to the size of the object's displacement and acts in the direction of the object's equilibrium position. It is proportional to the acceleration of the body away from the static equilibrium position.

When a longitudinal wave passes through air, the particles of the air posses simple harmonic motion. Hence,  the instantaneous acceleration of the particle is proportional to its displacement.

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How did earth change about 2.5 billion years ago when many organisms began using photosynthesis to make food

A. The amount of oxygen in the atmosphere increased

B. Mass extinctions occurred

C. The oceans became larger

D. Rainfall increased

Answers

The amount of oxygen in the air was increased

A non-conducting spherical thick shell, of inner radius a and outer radius 2a, carries a charge per unit volume density. Calculate the electrostatic potential energy of this system g

Answers

Answer: Electrostatic potential energy of the given system is

U=1/4π∈*(96/5)*Q²/a

Explanation:

consider spherical shell of inner radius a  (taken as x) and outer radius 2a ,carrying charge Q and volume charge density ρ=Q/4π(2a)³...........................(1)

then voume of the shell=4πx²dx

charge on the shell inner part of the shell.q1=4πx²dx ρ

charge on this ,in case of sphereical type,q2=4/3*πx³ ρ

then electrostatic energy of sperical charge of radius a (which we taken as x) and sperical shell of radius x and thickness dx is,

dU=1/4π∈ *(q1q2)/x

by placing value of q1 and q2 from above , we will get a equation

    dU=1/4π∈*(16/3*π²ρ²x \(x^{4}\)dx

then total electrostatic energy of sperical charge by integrating from limit a to 2a and putting value of ρ then we will get

U=1/4π∈*(96/5)Q²/a

fertilization that takes place when the union of the sex cells happens outside the body​

Answers

Answer:external

Explanation:EDGE 2021

An oil droplet is sprayed into a uniform electric field of adjustable magnitude. The 0.11 g droplet hovers
motionless (gravity force equalling electrostatic force) when the electric field is set to 370 N/C and directed
downward.
a) Determine the sign and magnitude of the charge on the oil droplet.
b) Determine the approximate number of excess electrons that are on the oil droplet.

Answers

Answer:

The direction of the field is downward, and negatively charged particles will experience an upwards force due to the field.

F = N e E     where E is the value of the field and N e the charge Q

M g = N e E      and M g is the weight of the drop

N = M g / (e E)

N = 1.1E-4 * 9.8 / (1.6E-19 * 370) = 1.1 * 9.8 / (1.6 * 370) * E15 = 1.82E13

.00011 kg is a very large drop

Q = N e = M g / E = .00011 * 9.8 / 370 = 2.91E-6 Coulombs

Check:     N = Q / e = 2.91E-6 / 1.6E-19 = 1.82E13   electrons

Which is a similar theme in both "The Stag at the Pool" and "Hans in Luck"? O A. The things we think are valuable sometimes turn out not to be valuable after all. 0 B. It is important to know whom we can trust and whom we cannot O C. By working hard, we will end up with possessions that will make us feel successful. 0 D. The best things come in small packages.​

Answers

A similar theme in both "The Stag at the Pool" and "Hans in Luck" is A. The things we think are valuable sometimes turn out not to be valuable after all.

In "The stag at the pool", a thirsty stag went to the pool to drink. As he bent over, he admired his antlers but despised his legs. He saw a lion and ran but his antlers got stuck in a tree and he was caught by the lion.

The theme in "Hans in Luck" shows that one doesn't need possessions to be happy. The character in the story had several possessions but was still unhappy. Both themes showed that the things we think are valuable sometimes turn out not to be valuable after all.

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difference between fuse wire and MCB​

Answers

Answer:

Explanation:

"fuse wire" typically refers to a thin, single-use wire that is used to protect an electrical circuit from overloading or short circuiting. The wire is designed to melt and break the circuit if the current flowing through it exceeds a certain level, which helps to prevent damage to the electrical equipment or a potential fire hazard. Once the fuse wire has melted, it must be replaced with a new one.

an "MCB" (miniature circuit breaker) is a type of switch that automatically trips and breaks the circuit when there is an overcurrent or short circuit.

Unlike a fuse wire, an MCB can be reset after it has tripped, making it more convenient for protecting electrical circuits. MCBs are typically more expensive than fuse wires, but they offer greater protection and are often used in modern electrical systems.

difference between fuse wire and MCB
difference between fuse wire and MCB

Question 1:
A ball rolls down a 1.0-meter long incline from rest to 2.0 m/s. The ball has a 5.0
cm radius. Find the angular acceleration of the ball.

Question 2:
A soccer ball is rolling at 15 rev /s. It stops rolling after traveling 25.0 m.
Calculate the time it was rolling. Also find its angular acceleration. The ball has
20 cm diameter.

Answers

The angular acceleration of the ball is approximately 800 rad/s².  the angular acceleration of the soccer ball is approximately -35.89 rad/s².

Question 1:

To find the angular acceleration of the ball rolling down the incline, we can use the following formula:

v = ω * r

where:

v is the linear velocity (2.0 m/s),

ω is the angular velocity, and

r is the radius of the ball (0.05 m).

We can also use the formula to relate linear and angular acceleration:

a = α * r

where:

a is the linear acceleration,

α is the angular acceleration, and

r is the radius of the ball (0.05 m).

Given that the ball rolls down the incline from rest, the initial angular velocity (ω0) is zero.

Using the equations above, we have:

2.0 m/s = ω * 0.05 m

ω = 2.0 m/s / 0.05 m

ω = 40 rad/s

Since the initial angular velocity is zero, the change in angular velocity (Δω) is equal to the final angular velocity (ω).

Using the equation a = α * r, we can rewrite it as α = a / r:

α = ω / r

α = 40 rad/s / 0.05 m

α ≈ 800 rad/s²

Question 2:

To calculate the time the soccer ball was rolling, we can use the formula:

t = d / v

where:

t is the time,

d is the distance traveled (25.0 m), and

v is the linear velocity (circumference of the ball times the angular velocity).

The circumference of the ball (C) can be calculated using the formula:

C = π * d

where:

d is the diameter of the ball (0.20 m).

Given that the ball has a diameter of 20 cm, the circumference is:

C = π * 0.20 m

C ≈ 0.628 m

Using the formula v = C * ω, we have:

v = 0.628 m * 15 rev/s

v ≈ 9.42 m/s

Substituting the values into the equation t = d / v, we find:

t = 25.0 m / 9.42 m/s

t ≈ 2.66 s

Therefore, the soccer ball was rolling for approximately 2.66 seconds.

To find the angular acceleration, we can use the formula:

α = Δω / t

Given that the initial angular velocity (ω0) is 15 rev/s and the final angular velocity (ω) is zero, the change in angular velocity (Δω) is:

Δω = ω - ω0

Δω = 0 - 15 rev/s

Δω = -15 rev/s

Converting the change in angular velocity to radians per second (rad/s):

Δω = -15 rev/s * (2π rad/rev)

Δω = -30π rad/s

Substituting the values into the formula α = Δω / t, we find:

α = (-30π rad/s) / 2.66 s

α ≈ -35.89 rad/s²

Note that the negative sign indicates a deceleration or slowing down of the rotation.

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1. What is the frame of reference for a plane moving at 500 km/h?
O A the clouds
O B the other planes in the sky
O C the ground
O d the passengers

Answers

Answer:

A: the clouds

Explanation: none

The answer is C, The ground

Explanation: Gradpoint

A race car accelerates from rest to a velocity of +90 m/s over a distance of 423m. Determine the acceleration of the race car.

Answers

Answer:

9.57m/s²

Explanation:

Given parameters:

Initial velocity  = 0m/s

Final velocity  = 90m/s

Distance  = 423m

Unknown:

Acceleration of the race car  = ?

Solution:

To solve this problem, we should apply one of the appropriate motion equations;

      V²  = U²   + 2as

Where V is the final velocity

           U is the initial velocity

           a is the acceleration

           s is the distance

  90²  = 0²  + 2 x a x 423

  8100 = 846a

      a  = 9.57m/s²

The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?

Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.

Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!

Answers

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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An airbys A380 airliner lands at 30 m/s. Partially loaded, its mass is 480000 kg. The engines apply reverse thrust for 12s to slow the plane to 25 m/s.How much thrust did the engines apply?

Answers

To determine the thrust applied by the engines, we can use Newton's second law of motion, which states that force (thrust) is equal to mass times acceleration. In this case, we need to calculate the force required to decelerate the plane from 30 m/s to 25 m/s in 12 seconds.

First, we calculate the change in velocity (∆v):

\(\displaystyle\sf \Delta v=25\,m/s-30\,m/s=-5\,m/s\)

Next, we calculate the acceleration (∆a) using the formula:

\(\displaystyle\sf \Delta a=\frac{\Delta v}{\Delta t}\)

where ∆t is the change in time, which is 12 seconds in this case.

\(\displaystyle\sf \Delta a=\frac{-5\,m/s}{12\,s}\)

Now, we can determine the force (thrust) applied by the engines using Newton's second law:

\(\displaystyle\sf F=m\cdot a\)

where m is the mass of the airplane, which is 480000 kg.

\(\displaystyle\sf F=480000\,kg\cdot \left(\frac{-5\,m/s}{12\,s}\right)\)

Calculating the result:

\(\displaystyle\sf F=-200000\,N\)

Therefore, the engines applied a thrust of -200000 Newtons (N) to decelerate the plane. The negative sign indicates that the thrust is in the opposite direction of the motion.

The epidermis is the top layer of skin compared to the underlying dermis of the
-kin. Using directional terms, where is the epidermis located in relation to the
dermis?
Do
Lateral
Proximal
Superficial
Superior

Answers

Answer:

just as rea was situated at a distance in picture and a half dozen years old in his first comment in picture the actor was the first thing he had ever heard about it he reati was the only person who has

Explanation:

plz help you get the best in your house but muje has been in a relationship since the last

Answer:

Although you may not typically think of the skin as an organ, it is in fact made of tissues that work together as a single structure to perform unique and critical functions. The skin and its accessory structures make up the integumentary system, which provides the body with overall protection. The skin is made of multiple layers of cells and tissues, which are held to underlying structures by connective tissue (Figure 5.1.1). The most superficial layer of the skin is the epidermis which is attached to the deeper dermis. Accessory structures, hair, glands, and nails, are found associated with the skin. The deeper layer of skin is well vascularized (has numerous blood vessels) and is superficial to the hypodermics. It also has numerous sensory, and autonomic and sympathetic nerve fibers ensuring communication to and from the brain.

Explanation:

Describe the layers of the skin and the functions of each layer

-Identify the components of the integumentary system

-Describe the layers of the skin and the functions of each layer

-Describe the layers of the epidermis and dermis

-Identify and describe the hypodermis and fascia

-Describe the role of keratinocytes and their life cycle

-Describe the role of melanocytes in skin pigmentation

Which of the the following quantities has the same unit as kilowatt - hour?
(a) Force × time
(b) Force × distance
(c) Force × acceleration
(d) Force × velocity

Answers

Answer:

I think (d) is your answer...

Force × velocity is the quantities has the same unit as kilowatt - hour. hence option D is correct.

What is Force ?

A force in physics is an effect that changes the velocity of a mass-moving object, causing it to accelerate from rest, for example. It is a vector quantity since it can be a push or a pull and always has magnitude and direction. It is denoted by the letter F (formerly P) and is measured in newtons (N), the SI unit of force.

The net force exerted on an object is equal to the rate at which its momentum varies over time, according to Newton's second law in its original formulation. According to this equation, an object's acceleration is precisely proportional to the net force applied on it if its mass remains constant.

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5. A 1500-kg car makes a u-turn with a radius of 25m. If the coefficient of static friction between the tires and the road μs = 0.42, what is the greatest speed the car can have without skidding (m/s)?

Answers

The maximum speed of the car was found to be 10.14 ms-1.

Define coefficient of static friction ?

A number that expresses how sticky an object is to its contact surface while it is stationary is known as the coefficient of static friction.

It is the ratio of the normal force imposed on the body to the static friction present between two contact surfaces.

Consider the three categories of dry friction: rolling friction, kinetic friction, and static friction.

Generally speaking, rolling friction and kinetic friction coefficients are lower than the coefficient of static friction.

Because static friction is greater than kinetic friction and rolling friction, this is the case.

This suggests that if an item is immobile, it will take greater effort to start it moving.

Rolling friction often has the least friction since it is greater in kinetic friction than rolling friction.

Fr=μs|n|

g=9.81

Fc=mv^2max/R

mv^2max/R=μsmg

v^2max=μsgR

vmax=√(0.42)(9.81)(25)

=√103.005

vmax =10.14 ms-1

The maximum speed of the car was found to be 10.14 ms-1.

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Imagine a baseball pitcher and a batter. The baseball has a mass of 0.14 kg. The ball is
pitched to the right with a velocity of 41.26 m/s.

Answers

The momentum of the baseball with a mass of 0.14 kg and velocity of 41.26 m/s is determined as 5.78 kgm/s.

What is the momentum of the baseball?

The momentum of the baseball is calculated by applying the following formula as shown below;

P = mv

where;

m is the mass of the baseballv is the speed of the baseball

The momentum of the baseball is calculated as follows;

mass of the baseball = 0.14 kg

velocity of the baseball = 41.26 m/s

momentum, P = mv

P = 0.14 kg  x  41.26 m/s

P = 5.78 kgm/s.

Thus, the momentum of the baseball with a mass of 0.14 kg and velocity of 41.26 m/s is determined as 5.78 kgm/s by applying the formula for linear momentum.

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The complete question is below:

Imagine a baseball pitcher and a batter. The baseball has a mass of 0.14 kg. The ball is pitched to the right with a velocity of 41.26 m/s. What is the momentum of the baseball?

What is MOST likely to be TRUE about asynchronous communication?
It is rarely used in businesses in today's society.
It offers many opportunities to ask clarifying questions in real time.
It is helpful when employees work across multiple time zones.
It only works when all employees work in the same time zone.

Answers

The most likely true statement about asynchronous communication is that it is helpful when employees work across multiple time zones.

Asynchronous communication refers to a mode of communication where participants do not need to be present or engaged simultaneously. Instead, they can send and receive messages at their convenience.In today's globalized society, businesses often have teams distributed across different geographical locations and time zones. Asynchronous communication becomes invaluable in such scenarios as it allows team members to collaborate effectively without the constraints of real-time interactions. By utilizing tools like email, project management platforms, or messaging apps, individuals can communicate and exchange information regardless of their location or the time differences.

Asynchronous communication also offers benefits such as flexibility and increased productivity. Team members have the freedom to work at their own pace and prioritize tasks accordingly. It provides opportunities for thoughtful and well-crafted responses, as individuals can take time to gather information or reflect on complex matters before replying.While asynchronous communication is advantageous for teams operating across multiple time zones, it does not rely on all employees working in the same time zone. In fact, it is designed to accommodate diverse schedules and allow individuals to collaborate efficiently despite their varying work hours.

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A box with a mass of 5.8 kg is lifted from the garage floor and placed on a shelf. If the box gains 145 J of
potential energy, how high is the self?

Answers

Answer:

2.27

Explanation:

Potential energy =mgh so from there u can substitute the values

PLEASE ANSWER FASG I WILL MARK BRAINELIST PLEASEEEEE
The number of protons in the nucleus of an atom determines the species of the atom, i.e., the element to which the atom belongs. An atom has the same number of protons and neutrons. But the electron number cannot be used instead because (5 points)
a. electrons are not within the nucleus
b. electrons are negatively charged
c. electrons can be removed from or added to an atom
d. electrons are lighter than protons

Answers

The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

Why the electron number cannot be used instead?

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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Very Important, I need the answer

Very Important, I need the answer

Answers

Answer:

A

Explanation:

A constant velocity means the position graph has a constant slope. It's a straight line sloping up.

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