Consider flow in between two parallel plates located a distance H from each other. Fluid flow is driven by the bottom plate moving to the right with a velocity of U (note, NO pressure gradient). The top plate has a fixed temperature of TT and the bottom plate has a temperature of Tb. Starting with the governing equations for incompressible flow, find the velocity profile and the temperature profile for the flow in between the plates. In addition, what is an expression for the heat flux at the bottom plate (assuming a thermal conductivity of k)

Programmers who use object-oriented methods consider in terms of a class instance that has its own properties and behaviours, which is how they vary from those who use procedural methods.

Procedural programming tackles applications by managing difficulties using a top-down method where it solves problems from the top of the code and to the bottom, whereas object-oriented programming is known to be one that employs classes and objects. A programming design strategy known as procedural programming attempts to break down clearly specified tasks into modules, functions, etc. In object-oriented programming, objects are only the individual parts of a programme. The (c) Method defines the behaviour of objects. The behaviour of objects is defined through methods, which are merely functions and subroutines. Consider the following approach, for instance: Public static int (int I Fibonacci

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The Bidirectional Shift Register is the shift register that allows one to write a 5bit register if the series is shifted from left to right.

A 5-bit register is valuable because it can represent up to 32 items. It is to be noted that a bit is a digit that is binary that is indicative of two states.

While a 5-bit register can have a possible number of 32 values,

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Answer:

Television

Power = 120 w

p.d = 240 v

I = p / v

I = 120 / 240 = 0.5

Fuse can be used 3A

lawnmower

Power = 1000w

p.d = 240 v

I = 1000/ 240 = 4.16

Fuse can be used = 5A

Explanation:

The point on the line 3x + 4y = 5, which is equidistant from (1, 2) and (3, 4) is. Therefore, the point is (15, -10).

Answer:

I don't know

Explanation:

sorry I am answering this for points

please follow and mark as brainliest for me I will also do same

Answer:

Adapting this case to a work environment, especifically an industry, there should be a security and health brigade in charge of response against emergencies within the organization. Said brigade has the duty of giving direction to all people that could be hurt in any way by a negative event caused by the emergency These directions are given orally in the case of emergencies. Also, emergency services personnel, such as police, firefighters, and paramedics, are certified professionals who have the responsibility of protecting people against harm, and this includes giving guidance during emergencies.

The temperature and pressure of an ideal gas are directly proportional

The pressure of the system should be in the range B) 94 psig

The given refrigerator parameters are;

The temperature of the system and the surrounding, T₁ = 75 °F = 237.0389 K

The pressure to which the system was charged with nitrogen, P₁ = 100 psig

The temperature to which the system dropped, T₂ = 50 °F = 283.15 K

The required parameter;

The pressure, P₂, of the system at 50°F

Method:

The relationship between pressure and temperature is given by Gay-Lussac's law as follows;

At constant volume, the pressure of a given mass of gas is directly proportional to its temperature in Kelvin

Mathematically, we have;

\(\dfrac{P_1}{T_1} = \mathbf{\dfrac{P_2}{T_2}}\)

Plugging in the values of the variables gives;

\(\mathbf{\dfrac{100 \ psig}{297.0389}} = \dfrac{P_2}{283.15}\)

Therefore;

\(P_2 = \mathbf{283.15 \, ^{\circ}F \times \dfrac{100 \ psig}{297.0389\ ^{\circ}F} \approx 95.3 \, ^{\circ}F}\)

The closest option to the above pressure is option B) 94 psig

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The use of advanced composite materials in the wing box assembly of the A380 offers advantages like weight reduction, increased strength, and corrosion resistance, outweighing challenges in manufacturing complexity and costs.

Step 1: Introduction to the Use of Advanced Composite Materials in Aircraft Components

The use of new, advanced composite materials in primary structural components of air carrier aircraft has gained significant attention and adoption in recent years. These materials offer numerous advantages over traditional materials, such as increased strength-to-weight ratio, improved fuel efficiency, corrosion resistance, and enhanced design flexibility. One notable example of an aircraft component where advanced composites are used is the wing box assembly in the Airbus A380.

Step 2: Wing Box Assembly in the Airbus A380

The wing box assembly is a critical structural component of an aircraft's wing that houses various systems and provides support to the wing structure. In the case of the A380, the wing box assembly is constructed using advanced composite materials. These materials typically include carbon fiber-reinforced polymer composites (CFRP), which consist of carbon fibers embedded in a polymer matrix.

Step 3: Advantages of Advanced Composite Materials

The use of advanced composite materials in the wing box assembly and other primary structural components of air carrier aircraft offers several advantages:

a) Weight Reduction: Advanced composites are significantly lighter than traditional materials like aluminum. This weight reduction contributes to improved fuel efficiency and increased payload capacity.

b) Strength and Stiffness: Carbon fiber composites possess exceptional strength and stiffness properties, allowing for the construction of lighter yet robust structures. This results in improved overall aircraft performance, including increased maneuverability and structural integrity.

c) Fatigue Resistance: Composite materials exhibit superior fatigue resistance compared to metals, allowing for extended operational life and reduced maintenance requirements.

d) Corrosion Resistance: Unlike metals, advanced composites are inherently corrosion-resistant, reducing the need for extensive corrosion protection measures and maintenance.

e) Design Flexibility: Composite materials can be molded into complex shapes, enabling aerodynamically efficient and aesthetically appealing designs. This flexibility in design contributes to improved aircraft performance and fuel efficiency.

Step 4: Considerations and Challenges

While the use of advanced composite materials in aircraft components brings numerous benefits, there are also considerations and challenges that need to be addressed:

a) Manufacturing Complexity: Composite structures require specialized manufacturing techniques and expertise. Quality control, proper curing, and inspection processes are critical to ensure the integrity and reliability of composite components.

b) Cost: Advanced composites can be more expensive than traditional materials, which may impact initial manufacturing and maintenance costs. However, advancements in manufacturing technologies and increased adoption have been driving costs down over time.

c) Repair and Maintenance: Composite repair and maintenance procedures may differ from those for metal structures. Adequate training and infrastructure are necessary for effective repair and maintenance of composite components.

Step 5:

The use of advanced composite materials in primary structural components, such as the wing box assembly in the A380, represents a significant advancement in aircraft design and performance. The advantages of weight reduction, increased strength, corrosion resistance, and design flexibility outweigh the challenges associated with manufacturing complexity and costs. As technology and expertise in composite materials continue to evolve, their widespread adoption in air carrier aircraft is likely to increase, further enhancing aircraft efficiency, performance, and sustainability.

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Refer to the attached images. Final answer is circled.

The best practice that Raven should follow is to use DC2 or DC3 as the Domain Naming Master of the following is a best practice that Raven should follow. The correct option is A.

The management of the addition or deletion of domains from the forest is the responsibility of the Domain Naming Master. For redundancy and fault tolerance, it is advised to split the FSMO roles among several domain controllers.

Since DC1 already has a copy of the global catalog, it is advantageous to choose a different domain controller (DC2 or DC3) as the Domain Naming Master to disperse the workload and guarantee high availability. This ensures that the forest's operations may continue even if one domain controller goes offline and prevents the creation of a single point of failure.

Thus, the ideal selection is option A.

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Technician A is correct. A drum micrometer is used to measure the inside diameter of brake drums, and it can measure both metric and imperial drums.

A drum micrometer is a device used to measure the inside diameter of a brake drum. It is designed to accurately measure the diameter of metric and imperial drums, allowing technicians to precisely identify the size of the brake drum. The device is composed of a measuring rod, which is inserted into the brake drum and then rotated to measure the inside diameter. This information can then be used to determine the size and type of brake drum needed for a particular vehicle. Drum micrometers are an important tool for automotive technicians, as they provide an accurate and reliable way to identify the size of brake drums.

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(a) The hydraulic radius (R) is 0.25 meters.

(b) The discharge (Q) is 3.15 m³/s.

(c) The hydraulic depth (Dh) is π / 4 meters.

(d) The Froude number (Fr) is 2.03.

a. To find the hydraulic radius (R), we can use the formula:

R = A / P

Where:

P = Wetted perimeter (m)

For a circular channel, the wetted perimeter can be calculated as:

P = π × D

Where:

D = Diameter of the circular channel (m)

Given:

D = 1 meter

Calculating the hydraulic radius (R):

P = π × D = π × 1 = π meters

A = (π × D²) / 4 = (π × 1²) / 4 = π / 4 square meters

R = A / P = (π / 4) / π

= 1 / 4

= 0.25 meters

b) To find the discharge (Q), we need to know the channel slope (S) and use the Manning's equation.

Given:

S = 5% = 0.05

Using the Manning's equation:

\(Q = (1/n) \times A \times R^(^2^/^3^) \times S^(^1^/^2^)\)

=\((1/0.013) \times (π / 4) \times (0.25)^(^2^/^3^) \times (0.05)^(^1^/^2^)\)

= 3.15 m³/s

c. The hydraulic depth (Dh) is defined as the cross-sectional area (A) divided by the top width (T).

Dh = A / T

For a circular channel, the top width is equal to the diameter (D).

Given:

D = 1 meter

A = π / 4 square meters

Dh = A / D = (π / 4) / 1 = π / 4 meters

The hydraulic depth (Dh) is π / 4 meters.

d. The Froude number (Fr) is defined as the ratio of the flow velocity (V) to the wave velocity (C).

Fr = V / C

The wave velocity can be approximated as:

\(C = (g \times Dh)^(^1^/^2^)\)

Where:

g = Acceleration due to gravity (9.81 m/s²)

Dh = Hydraulic depth (m)

Given:

Dh = π / 4 meters

Calculating the wave velocity (C):

\(C = (9.81 \times (\pi / 4))^(^1^/^2^)\)

== 1.57 m/s

To find the flow velocity (V), we can use the Manning's equation:

Q = A × V

Rearranging the equation to solve for V:

V = Q / A = 3.15 / (π / 4) ≈ 3.18 m/s

Calculating the Froude number (Fr):

Fr = V / C = 3.18 / 1.57 ≈ 2.03

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This area has low water-flow velocities because flowing water forms a reservoir that can be used for hydroelectric power generation or recreation : D (dam).

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An agrarian and handicraft economy was replaced by one that was dominated by industry and machine manufacturing during the Industrial Revolution in modern history. The world as a whole was affected by this process after it started in Britain in the 18th century.

These first three industrial revolutions shaped our contemporary society. The world we live in underwent a fundamental transformation with the advent of each of these three innovations: the steam engine, the age of science and mass production, and the rise of digital technology. And right now, it's taking place once more, for the fourth time.

The term is frequently used to describe emerging technologies, or those expected to become available in the next five to ten years. It is typically reserved for technologies that are having, or are anticipated to have, significant social or economic effects.

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Atomic radius of  metal that has the face-centered cubic crystal structure is 0.137 nm, Then volume of its unit cell is V = 3.42×10^(-29) m³

The volume is a measurement of the cell's interior space. The surface area/volume ratio is calculated as follows. This demonstrates the amount of surface area that is available in relation to the size of the cell. A small surface area to volume ratio indicates a large cell.

Volume of unit cell

The atomic radius of aluminum =0.121 nm= 0.121×10⁻⁹ m

The volume of the unit cell in  l^3 and  signifies the length of the side of the unit cell.

Generally  equation for the Volume is mathematically given as:-

V = (4r/√2)³

Therefore

V = (4(0.121×10⁻⁹ m)/√2)³

V = 3.42×10^(-29) m³

so, volume of its unit cell is V = 3.42×10^(-29) m³.

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A high compression ratio may result in compressor failure.

A compressor refers to a mechanical device that is designed and developed to provide power to refrigerators, especially by increasing the pressure on air or other applicable gases.

According to heating, ventilation, and air conditioning (HVAC) information, a high compression ratio of 8: 1 or higher is most likely to result in compressor failure.

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The first-order kinematic coefficient of the gear train is 0.028. Gear 8 rotates in the clockwise direction with a speed of 42.86 rev/min.

The first-order kinematic coefficient of the gear train is a measure of the efficiency of power transmission through a gear train. It is defined as the ratio of the output speed of the final gear to the input speed of the first gear. In this case, the first-order kinematic coefficient is 0.028, which means that the output speed of gear 8 is only 2.8% of the input speed of gear 4.

To determine the rotational direction and speed of gear 8, we first need to identify the gear ratios for each pair of gears in the train. Starting from gear 4, we have a gear ratio of 44/15, which means that gear 5 rotates at a slower speed than gear 4 but with higher torque. Similarly, the gear ratio between gears 5 and 6 is 33/36, which means that gear 6 rotates at a faster speed than gear 5 but with lower torque.

Finally, we can calculate the speed and direction of rotation of gear 8 by multiplying the gear ratios of all the gears between gear 4 and gear 8. We have:

44/15 * 33/36 * 487/36 = 42.86

This means that gear 8 rotates at a speed of 42.86 rev/min in the clockwise direction.

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Answer:

Overall project duration

Explanation:

Scheduling can best be defined as the process used to determine a overall project duration.

Answer:

Surface Parallelism When a surface is to be parallel to a datum plane, the feature control frame is connected by a leader to the surface, or to an extension line from the surface.

Explanation:

The greatest gas pressures in a turbine engine are typically seen in the combustion chamber. This is the section where fuel is burned, and the resulting hot gases are used to power the engine's turbines.

The pressure in the combustion chamber can reach several times atmospheric pressure, with some designs capable of producing pressures of up to 80 bar.

The reason for the high pressure in the combustion chamber is due to the need to generate sufficient force to drive the turbines. As the gases expand and exit the combustion chamber, they are directed through a series of turbine blades that convert the pressure and heat energy into rotational force. The greater the pressure in the combustion chamber, the greater the force that can be produced by the turbines.

It is worth noting that while the combustion chamber typically has the highest gas pressures in a turbine engine, other sections of the engine may experience significant pressure differentials. For example, the compressor section must generate enough pressure to compress incoming air and feed it into the combustion chamber, while the exhaust section must manage the pressure of the exiting gases to maintain efficient engine operation.

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l/blouoojiklnkjhljm,jl,mj l, j/ll

c. The demand for Japanese automobiles. The 8.9 (on the Richter scale) earthquake and ensuing after-shocks and tsunami that devastated Japan resulted in reduction in manufacturing of parts and automobiles, and car dealership revenue streams, but did not result in an increase in the demand for Japanese automobiles.

The 8.9 (on the Richter scale) earthquake and ensuing after-shocks and tsunami that devastated Japan resulted in a reduction in manufacturing of parts and automobiles. This was due to the damage caused to manufacturing plants that resulted in lost production time and a decrease in the supply of automobile parts. The car dealership revenue streams also decreased due to the reduction in sales.The event did not lead to an increase in the demand for Japanese automobiles as this was not a result of the natural disaster. The natural disaster instead led to a decrease in the production and sales of Japanese automobiles due to the damage caused by the earthquake and tsunami on the manufacturing plants that produce the automobiles.

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Answer:

Connect your computer to the OBD(On-Board Diagnostics) port and see whats wrong

Explanation:

im a mekanic

mechanik

mecanic

meckanic

nvm, I fix cars

Answer:

Most technicians install rebuilt or new power steering pumps rather than overhauling the defective unit in the shop.

True

Explanation:

It has been established that most technicians, instead of overhauling the defective power steering pumps, prefer to install rebuilt or revamped pumps or even new pumps when they could have overhauled the unit themselves.  Some are afraid that leakage could occur again.  They are not confident enough to do the overhauling in-house or some claim that they do not have the time and other tools to carry out the overhauling.  Acknowledgedly, overhauling a power steering pump is not a job for the novice.  They require experienced and skilled hands to do the hard work.

a. Based on the 43 years of record and the fact that the 1972 flood occurred once during this interval, it can be estimated that a flood of this magnitude would be expected to occur once every 43 years, on average.

b. Using the graph paper, plot a recurrence curve for the Rapid Creek flood data. Ignoring the 1972 flood, an eyeball, best fit, and a straight line should be plotted through the points. The 100-year flood discharge can be determined by looking at the point on the graph which is at the 100-year recurrence interval.

c. The recurrence interval of the 1972 flood, using the curve drawn, can be determined by looking at the point on the graph which is nearest to the 1972 flood discharge.

d. Given the range of values from a and c above, it can be stated that floods as large as the one which occurred in 1972 are rare events and occur infrequently.

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The difference between cradle-to-gate and cradle-to-grave LCA analysis is that the first does not include the end-of-life stage, whereas the latter considers the entire life cycle of a product, including disposal or recycling.

The difference between cradle-to-gate and cradle-to-grave LCA (Life Cycle Assessment) analysis is that the first does not include the end-of-life phase of a product or service. Cradle-to-gate focuses on the environmental impact from raw material extraction to the point where the product leaves the manufacturer, whereas cradle-to-grave includes the entire life cycle, from raw material extraction through manufacturing, use, and finally disposal or recycling. A life cycle assessment, or LCA, is a method of evaluating the effects that a product has on the environment throughout the entirety of its life, thereby increasing resource efficiency and decreasing liability. A life cycle assessment examines the impact that a construction product has on the environment through five stages: end-of-life, the construction process, the product, and the circular economy.

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Cradle-to-gate and cradle-to-grave LCA analyses are both important tools used to assess the environmental impact of products and services.

Cradle-to-gate LCA analysis focuses on the entire lifecycle of a product or service, from the extraction of raw materials to the point of sale or delivery. In contrast, cradle-to-grave LCA analysis includes the entire lifecycle of a product or service, from the extraction of raw materials to its end-of-life disposal.
The main difference between these two types of analysis is that cradle-to-gate LCA analysis does not include the end-of-life stage of a product or service. This means that the environmental impact of the disposal or recycling of the product is not taken into account. In contrast, cradle-to-grave LCA analysis takes into account the entire lifecycle of a product or service, including the environmental impact of disposal or recycling.
Both cradle-to-gate and cradle-to-grave LCA analyses are important tools for companies and organizations looking to reduce their environmental impact and improve sustainability. Understanding the difference between these two types of analysis can help organizations make informed decisions about their environmental impact and identify areas for improvement.

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Technician a says kinetic friction changes kinetic energy into thermal energy. technician b says static friction holds the car in place when it is stopped. Both A and B are correct.

In static friction, there is found to be some frictional force that tends to resists force that is known to be applied to an object, and the object will be at the same sport at rest until the force of static friction is known to be overcome.

In kinetic friction, the frictional force is one that tend to resists the movement of an object.

Therefore, Technician a says kinetic friction changes kinetic energy into thermal energy and technician b says static friction holds the car in place when it is stopped. Both A and B are correct.

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Answer:

Explanation: