Given
677 cm3
Si units are m3 for volume
Procedure
Direct conversion formula: 1 Cubic centimeters * 1000000 = 1 Cubic meters
\(\begin{gathered} 677cm^3\cdot\frac{1m^3}{1000000cm^3} \\ 0.000677m^3 \\ \end{gathered}\)
In Scientific notation
6.77 × 10^(-4) m3
What is the magnitude of the momentum of a motorcycle of a mass of 100 kg at rest What is its momentum if this motorcycle when it travels at 40 m s?
The magnitude of a momentum of a motorcycle of a mass of 100kg at rest stage is 0kg-m/sec and momentum of a motorcycle is 4000kg-m/sec when it travels with 40m/sec speed.
We know very well that momentum is defined as the quantity of the motion of the body.
Momentum is represented by the product of mass and velocity, or in other words p=mass × velocity
Momentum is called as a vector quantity. It means it has proper magnitude and proper direction.
From momentum, impulse is also calculated.
At rest stage velocity of motorcycle is 0m/sec
Therefore, momentum=100×0=0Kg-m/sec
Now, when motorcycle is moving with speed 40m/sec, then momentum is
=>p=100kg×40m/sec
=>p=4000kg-m/sec
There are various laws in physics which are derived by the conservation of momentum.
Hence, magnitude of momentum are 0kg-m/sec and 4000kg-m/sec.
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Which is true about scientific theories?
Group of answer choices
They are the result of a single experiment.
They are proposed by scientists who wish to investigate a new topic.
They are only based on the most recent evidence.
They are the results of many experiments over a long period of time.
Scientific theories are the results of many experiments over a long period of time.
Scientific theories are explanations that have been developed through extensive experimentation and observation over a period of time. They are supported by a large body of evidence from multiple sources and have been subjected to rigorous testing and scrutiny by the scientific community. Scientific theories are not based on a single experiment but rather on a vast accumulation of knowledge and data. They provide a framework for understanding the natural world and can help predict future observations and experiments. Scientific theories are also subject to change or revision if new evidence is discovered that contradicts or expands upon the existing theory. The development of scientific theories is a collaborative effort among scientists from different disciplines, and the peer-review process is used to ensure that scientific theories are reliable and accurate representations of reality. Scientific theories have been used to make significant advancements in fields such as medicine, engineering, and physics, and they continue to play a critical role in advancing our understanding of the world.
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need an answer, please need an answer, please
9514 1404 393
Answer:
moderate low: 82moderate high: 112.75vigorous low: 123vigorous high: 174.25Explanation:
When calculations are repetitive, I find it convenient to use a calculator that can work with tables.
The PMHR is (220 -15) = 205.
Each of the other heart rates is computed as the formula shows. For example, the low moderate heart rate is 205×0.40 = 82 bpm
The other rates are shown in the attached table. They are computed the same way.
please help answering A,B,C in screenshots thank you!
The slope of the graph is 0.5 m/s² and when t = 1.5 s, the predicted displacement (d) of the object is 0.75 meters.
To plot the velocity vs. time graph, we'll use the given data points:
Duration, At (s): 2.0, 4.0, 6.0, 8.0, 10.0, 12.0
Velocity, v (m/s): 6.0, 7.0, 8.0, 9.0, 10.0, 11.0
Let's plot these points on a graph:
Time (s) [x-axis] | Velocity (m/s) [y-axis]
--------------------------------------------
2.0 | 6.0
4.0 | 7.0
6.0 | 8.0
8.0 | 9.0
10.0 | 10.0
12.0 | 11.0
After plotting the points, we can connect them with a straight line to represent the motion of the object. This line represents the velocity vs. time relationship.
Now, let's calculate the slope of this line. The slope of a line represents the rate of change of the dependent variable (velocity) with respect to the independent variable (time). In this case, it gives us the acceleration of the object.
Using the formula for calculating the slope of a line:
Slope (k) = (Change in velocity) / (Change in time)
For the first two points:
Change in velocity = 7.0 - 6.0 = 1.0 m/s
Change in time = 4.0 - 2.0 = 2.0 s
Slope (k) = 1.0 m/s / 2.0 s = 0.5 m/s²
Therefore, the slope of the graph is 0.5 m/s².
Now, to answer part B, the physical significance of the slope value is that it represents the object's acceleration. In this case, the constant acceleration experienced by the object is 0.5 m/s².
Moving on to part C, we are given the equation d = kt, where d represents the displacement and t represents time. Since the object is experiencing constant acceleration, the equation can be rewritten as d = 0.5t, where 0.5 is the acceleration (k).
To predict the value of "d" when t = 1.5 s, we can substitute the value of t into the equation:
d = 0.5 * 1.5 = 0.75 meters
Therefore, when t = 1.5 s, the predicted displacement (d) of the object is 0.75 meters.
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The probable question may be:
An object is subjected to a constant acceleration along a frictionless track. A student measures its velocity (v) after specific durations (At). The student uses a graph to analyze the truck's motion.
Duration, At, (s) :- 2.0,4.0,6.0,8.0,10.0,12.0.
Velocity, v, (m/s) :- 6.0,7.0,8.0,9.0,10.0,11.0
A. Plot the velocity (in meters/sec) vs. time (seconds). The velocity is the y-axis and time is the x-axis. Use any graphing software you like or graph this data in pencil on graph paper. Excel has a nice graphing package. Calculate the slope of this graph. You will
B. What is the physical significance of the slope value computed in part A?
C. Having determined the slope of the line, you can now write d = kt. Use this equation to predict a value of "d" when t = 1.5 s.
Arrange the objects in order from greatst to least of potential energy assume that gravity is constant
Answer:
Water > Box of books > Stone > Ball
Explanation:
We'll begin by calculating the potential energy of each object. This can be obtained as follow:
For stone:
Mass (m) = 15 Kg
Acceleration due to gravity (g) = 10 m/s²
Height (h) = 3 m
Potential energy (PE) =?
PE = mgh
PE = 15 × 10 × 3
PE = 450 J
For water:
Mass (m) = 10 Kg
Acceleration due to gravity (g) = 10 m/s²
Height (h) = 9 m
Potential energy (PE) =?
PE = mgh
PE = 10 × 10 × 9
PE = 900 J
For ball:
Mass (m) = 1 Kg
Acceleration due to gravity (g) = 10 m/s²
Height (h) = 20 m
Potential energy (PE) =?
PE = mgh
PE = 1 × 10 × 20
PE = 200 J
For box of books:
Mass (m) = 25 Kg
Acceleration due to gravity (g) = 10 m/s²
Height (h) = 2 m
Potential energy (PE) =?
PE = mgh
PE = 25 × 10 × 2
PE = 500 J
Summary:
Object >>>>>>>> Potential energy
Stone >>>>>>>>> 450 J
Water >>>>>>>>> 900 J
Ball >>>>>>>>>>> 200 J
Box of books >>> 500 J
Arranging from greatest to least, we have:
Object >>>>>>>> Potential energy
Water >>>>>>>>> 900 J
Box of books >>> 500 J
Stone >>>>>>>>> 450 J
Ball >>>>>>>>>>> 200 J
Water > Box of books > Stone > Ball
A person with a bacterial infection is taking amoxicillin, which is an antibiotic. The bacteria that are causing the infection have mutated and fight off the amoxicillin.
Which best summarizes this mutation?
Answer:
I’m pretty sure it’s B. It is harmful to the person and beneficial to the bacteria.
Explanation:
I’m taking the test right now. But if you think about it the bacteria is fighting off the medicine to which means the bacteria will just keep growing. So I’m 97% sure it’s B. Good luck you can do it don’t stop believing in yourself!!!!!! Hope I helped. And remember at the end of the day all that matters is love and happiness not grades!!!!!!!
Answer:
Answer is B!
Explanation:
I took the cumulative exam and got 100%
A large air-filled 0.221-kg plastic ball is thrown up into the air with an initial speed of 11.9 m/s. At a height of 2.77 m, the ball's speed is 2.85 m/s. What fraction of its original energy has been lost to air friction?
Answer:
Initial energy = (M/2)*Vo^2 = 12.80 J
Total energy at 4.7 m and V = 5 m/s:
= (M/2)*5^2 + M*g*4.7 = 1.25 + 4.61 J
Fraction of ball's energy LOST = (12.80-5.86)/12.80
= 0.542
Explanation:
I know it's not the real answer, but this will help you find the real one
Hope this helps!!!
How long is the runway? And what is the planes take off speed
These relationships are referred to as the equation of motion.
s = ut + ½at². and v = u + at.
length of the Run way = 1350m
Take of speed of the plane is 90 m/s.
How many formulas of motion are there?We will learn how to relate quantities such as velocity, time, acceleration, and displacement as long as the acceleration is constant. These relationships are referred to as the equation of motion.The three equations of motion are as follows:
v = u + a t is the first equation of motion.s = u t + 1 /2 a t^2 is the second equation of motion. Third Element of Motion: v 2 = u 2 + 2 a sfrom equation of motion
s = ut + ½at².
here u =0 a =3 m/s^2 t= 30s
put these values on the above equation
s= 1/2x 3x 30x30= 1350 m
length of the Run way = 1350m
from equation of motion ,
v = u + at.
= 0+ 3x 30 = 90m/s.
Take of speed of the plane is 90 m/s.
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Distance = 1350m, speed = 90m/s
Given:
Initially the Aero plane is at rest. Therefore, initial velocity:
u = 0m/s
Acceleration = 3m/\(s^{2}\)
Time taken = 30 seconds
So according to question, we have to find distance & speed
How to find distance?we know that
s = ut + 1/2a\(t^{2}\)
Putting all the values, we get S = 1350 m
Now to find speed, we know,
\(v^{2} = u^{2} + 2aS\)
Putting all the values,
v = \(\sqrt{8100}\)
v = 90m/s
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2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m
For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:
a. The volume is 24 m³.
b. weight is 240,000 N,
c. mass is 24,490 kg, and
d. pressure is 23,530 Pa.
a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:
Volume = Length x Width x Depth
Given:
Length = 4 m
Width = 3 m
Depth = 2 m
Substituting the values into the formula, we have:
Volume = 4 m x 3 m x 2 m
Volume = 24 m³
Therefore, the volume of paraffin in the tank is 24 cubic meters.
b) The weight of the paraffin can be calculated using the formula:
Weight = Volume x Density x Acceleration due to gravity
The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:
Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²
Weight = 240,000 N
Therefore, the weight of the paraffin in the tank is 240,000 Newtons.
c) The mass of the paraffin can be calculated using the formula:
Mass = Density x Volume
Substituting the given values:
Mass = 10,000 kg/m³ x 24 m³
Mass = 24,490 kg
Therefore, the mass of the paraffin in the tank is 24,490 kilograms.
d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:
Pressure = Weight / Area
The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:
Area = 4 m x 3 m
Area = 12 m²
Pressure = 240,000 N / 12 m²
Pressure = 20,000 Pa
Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).
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3a Define resistivity
\(\huge\color{red}\mathcal{\colorbox{bla}{Define resistivity}}\)
Answer :-a measure of the resisting power of a specified material to the flow of an electric current.
Hope it is Helpful to you
What characteristics determine how easily two substances change temperature? Check all that apply.
volume of the two substances in contact
amount of time the two substances are in contact
Oarea in contact between the two substances
specific heat of the material that makes up the substances
density of the two substances in contact
Answer:
The characteristics that determine how easily two substances change temperature are:
specific heat of the material that makes up the substancesarea in contact between the two substancesThe volume and density of the substances and the amount of time they are in contact do not directly affect how easily they change temperature.
Explanation:
The cross-sectional area of vessel A is 50 cm² and it contains water to a height 30 cm. The vessel B has an area of cross-section of 25 cm². The two vessels are connected with a thin tube as shown in the figure, When the tap is slowly opened, and the water attained an equilibrium in both vessels. The reduction in the potential energy of the water is (Density of water is 1000 kgm-³)
1) 7.5 J
2) 22.5 J
3) 0.75 J
4) 8.5 J
5) 75 J
Please show the working along with a brief explanation.
The reduction in the potential energy of the water is approximately 7.5 J.
option 1
What is the reduction in potential energy?We can use the principle of conservation of energy to determine the reduction in potential energy of the water.
Initially, the water in vessel A has a certain amount of potential energy due to its height above the bottom of the vessel. When the water flows through the tube and reaches vessel B, its height above the bottom of vessel B is lower than that of vessel A, which means that its potential energy has decreased.
The potential energy of the water in vessel A is given by:
PE_A = mgh_A
The mass of the water in vessel A is given by:
m = density x volume
volume = A x h_A
Substituting for m and simplifying, we get:
PE_A = density x A x h_A x g
Similarly, the potential energy of the water in vessel B is:
PE_B = density x A_B x h_B x g
At equilibrium, the height of the water in the two vessels will be the same, so we can set h_A = h_B = h.
Also, since the water is in equilibrium, the pressure at the bottom of both vessels must be the same. This means that the pressure difference between the top and bottom of the water column in vessel A (due to the weight of the water) must be balanced by the pressure difference between the top and bottom of the water column in vessel B.
The pressure difference in vessel A is:
P_A = density x g x h_A
and the pressure difference in vessel B is:
P_B = density x g x h_B
Since the pressure difference must be balanced, we have:
P_A - P_B = density x g x h_A - density x g x h_B = 0
which simplifies to:
h_A = h_B x A_B / A
Substituting for h_A and h_B in the expressions for PE_A and PE_B, we get:
PE_A = density x A x h x g
PE_B = density x A_B x h x g x A / A_B
The reduction in potential energy of the water is:
ΔPE = PE_A - PE_B = density x g x h x (A - A_B x A / A_B)
which simplifies to:
ΔPE = density x g x h x (A - A_B)
Substituting the given values, we get:
ΔPE = 1000 kg/m³ x 9.8 m/s² x 0.3 m x (50 cm² - 25 cm²)
Converting the area units to m², we get:
ΔPE = 1000 kg/m³ x 9.8 m/s² x 0.3 m x (0.005 m² - 0.0025 m²)
Simplifying, we get:
ΔPE = 7.4 J
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f the red block is sitting still on the table and has a weight of 12 Newtons, what is the Magnitude and Direction of the Normal Force exerted on the block by the table?
If the red block is sitting still on the table and has a weight of 12 Newtons, then the magnitude of the normal force would be 12 Newtons and the direction of the normal force would be upwards.
What is Newton's third law of motion?Newton's third law of motion state that" for every action force there exists a complementary reaction force that balances it".
As given in the problem If the red block is sitting still on the table and has a weight of 12 Newtons,
The magnitude of the normal force = 12 Newtons
The direction of the normal force would be upward.
Thus, the normal force would have a magnitude of 12 Newtons and would be directed upwards if the red block were to remain still on the table and weigh 12 Newtons.
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Help?step by step/no need
Answer:
3, 5, and 6, that should be the answer
PLEASE HELP FOR PHYSICS!
All objects exert a gravitational force on all other objects. This force is given by, F = GMm r2 , where the value of G = 6.673 × 10–11 N–m2/kg2 , M is the mass of the heavier object, m is the mass of the lighter object, and r is the distance between the two objects.
What is the force of gravity between two balls of mass 50 kg each if the distance between them is 25 m. Assume that there is no interference from any other gravitational field.
Hi there!
Recall Newton's Law of Universal Gravitation:
\(\large\boxed{F_g = G\frac{m_1m_2}{r^2}}\)
Where:
Fg = Force of gravity (N)
G = Gravitational Constant
m1, m2 = masses of objects (kg)
r = distance between objects (m)
Plug in the given values stated in the problem:
\(F_g = (6.673*10^{-11})\frac{50 * 50}{25^2} = \boxed{2.669 * 10^{-10} N}\)
When you jump, you push down on the earth and it pushes back up against you. The earth pushing up against you is what causes you to go into the air. Why doesn’t your push cause the earth to go down if your push on the earth is equal and opposite of the earth's push on you?
That's a great question !
The answer is: It does !
A push on an object causes the object to accelerate in the direction of the force.
The less mass the object has, the more the force accelerates it.
Now, when you jump, the forces on you and on the Earth are equal forces.
The up force on you causes you to accelerate up by some amount.
The down force on the Earth causes the Earth to accelerate down by some amount.
The Earth's mass is something like 5,972,000,000,000,000,000,000,000 kg, while your mass is something like 50 kg.
The Earth has something like 119,400,000,000,000,000,000,000 times as much mass as you have.
So your acceleration is something like 119,400,000,000,000,000,000,000 times as great as the Earth's acceleration.
==> The Earth's downward acceleration, caused by your jump, is there. It's just too small to notice.
BUT . . . That's the reason why seismometers (instruments to detect and measure the vibrations from distant earthquakes) have to be located as far as possible from cities and busy roads.
In places that are too close to cities and roads, the Earth's surface is always vibrating, wiggling, jiggling, heaving and weaving, in reaction to the forces of people walking around, cars and trucks driving around, even rain falling down. And kids jumping up and down !
In such places, these people-motions are louder and stronger than the vibrations coming from distant earthquakes. Seismometers wouldn't work there.
Gender inequality in Machenical Engeenering
Gender inequality in mechanical engineering can manifest through biased hiring practices, limited opportunities for women to advance to leadership roles, and a lack of representation in the industry.
Despite efforts to promote gender equality, women are still underrepresented in the field of mechanical engineering. This can be due to a variety of factors, including biased hiring practices, limited opportunities for career advancement, and a lack of representation in the industry.
To address these issues, it is important for companies and organizations to promote diversity and inclusion initiatives, such as actively recruiting women and people of diverse backgrounds, providing mentorship and networking opportunities, and advocating for policies that support work-life balance and equal pay. By creating a more inclusive environment, the field of mechanical engineering can attract and retain more talented individuals and foster innovation and growth.
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--The complete question is, How does gender inequality manifest in the field of mechanical engineering, and what are some potential solutions to address this issue?--
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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Vocabulary Matching
The specialized equipment used to conduct research and repair
damaged equipment
Instruments
Space Station
Space Suit
Accomodations
Answer:
instruments
Explanation:
How much energy is needed to change the temperature of 50g of water 15°c
Explanation:
This question is not feasible. There is no way to calculate the energy needed because the question is missing the final temperature
help me get the answer in Physical Science.
Answer:
lithium
Explanation:
I took physical science 2 years ago and passed with an A
Write a hypothesis about the effect of the racetrack’s height on the speed of the car using the format of "if…then…because….” Be sure to answer the lesson question "How can motion be described?”
Answer:
Sample Response: If the starting height of a sloped racetrack is increased, then the speed at which a toy car travels along the track will increase because the toy car will have a greater acceleration.
Explanation:
Sample Response: If the starting height of a sloped racetrack is increased, then the speed at which a toy car travels along the track will increase because the toy car will have a greater acceleration.
just in case ur one of the people who like to double-check ur answer before turning it in or before u go onto the next thing u have to work on for the day(if ur doing online school) here u go the person above is 100% correct but here it is again if u like to double-check like I do
What are the three states of water in Earth's system?
Answer:
Solid state: Water in the form of ice or snow.
Liquid state: Water in the form of liquid, such as oceans, rivers, lakes, and groundwater.
Gas state: Water in the form of water vapor, which is an invisible gas that is present in the atmosphere.
Which of the following examples is NOT an example of energy transfer?bringing water to a boilba boat being accelerated by the force of the enginecrain falling from a clouddwaves in the ocean
Rain falling from a cloud is not an example of energy transfer.
onsider laminar flow of a fluid through a square channel with smooth surfaces. now the average velocity of the fluid is doubled. determine the change in the head loss of the fluid. assume the flow regime remains unchanged
The head loss doubles when the average velocity is doubled.
The velocity formula: why?
The vector quantity velocity (v), denoted by equation v = s/t, quantifies dislocation (or shift in position, s), over change in time (t).
How do velocity and speed differ?Velocity is the pace and direction of the an object's movement, whereas speed is the timekeeping at which an object is travelling along a path.In other words, velocity is a vector, whereas speed is indeed a scalar value.
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which type if energy is used to power your tv?
Answer:
electrical
Explanation:
the TV needs electrical energy to power on
Answer:
electrical energy powers your TV, computer, microwave and toaster.
A 193.4 g sample of water at 13.5°C is heated to steam at 131.1°C. How much heat was absorbed?
A 193.4 g sample of water at 13.5°C is heated to steam at 131.1°C. The amount of heat absorbed will be 96000 KJ.
What is Heat energy?Thermal energy refers to the energy which is contained within a system that is responsible for the temperature. Heat is the flow of thermal energy in the system.
Given that,
Mass, m = 193.4 g
We know that,
Q₁ = mcΔt
Q₁ = 193.4 × 4200 × (131.1 - 13.5)
Q₁ = 193.4 × 4200 × 117.6
Q₁ = 95,524,128 Joules
Now, the latent heat
Q₂ = mL
Q₂ = 193.4 × 2260
Q₂ = 437,084 Joules
Now, the total heat energy required,
Q = Q₁ + Q₂
Q = 95,524,128 + 437,084
Q = 95,961,212 Joules
Therefore, the heat energy is approximately 96000 KJ.
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Your question is incomplete, most probably the complete question is:
Calculate the heat energy required to convert completely a 193.4 g sample of water at 13.5°C is heated to steam at 131.1°C, given that the specific heat capacity of water is 4200 J/(kg°C) and the specific latent heat of vaporization of water is 2260 kJ/kg.
A blue car of length 4.52 m is moving north on a roadway
that intersects another perpendicular roadway. The width of the intersection from near edge to far edge is 28.0 m. The blue car has a constant acceleration of magnitude 2.10 m/s2 directed south. The time interval required for the nose of the blue car to move from the near (south) edge of the intersection to the north edge of the intersection is 3.10 s. (a) How far is the nose of the blue car from the south edge of the intersection when it stops? (b) For what time interval is any part of the blue car within the boundaries of the intersection? (c) A red car is at rest on the perpendicular
intersecting roadway. As the nose of the blue car enters the intersection, the red car starts from rest and accelerates east at 5.60 m/s2. What is the minimum distance
from the near (west) edge of the intersection at which the nose of the red car can begin its motion if it is to enter the intersection after the blue car has entirely left the intersection? (d) If the red car begins its motion at the position given by the answer to part (c), with what speed does it enter the intersection?
The distance of the blue car from the edge of the intersection, when it stops, is 35.9 m, the time interval of the blue car within the boundaries of the intersection is 4.04 s, the minimum distance is 45.8 m, and the speed of the car is 22.6 m/s.
From the given,
A) the distance of the blue car from the south edge of the intersection when it stops =?
The width of the intersection = 28m
Acceleration = -2.10 m/s²
time interval = 3.10 s
By using the equation
x = x₀ + v₀t + 1/2 (at²)
28 = 0 + v₀(3.10) + 1/2 (-2.10 ×(3.10)²)
v₀ = 12.3 m/s
v² = v₀² + 2a (x-x₀)
(x-x₀) = Δx = v²-v₀² / 2a
Δx = 35. 9m
B) the time interval=?
distance covered by the blue car = 4.52 + 28 = 32.52 m
By using the relation,
x = x₀ + v₀t + 1/2 (at²)
32.52 = 0 + (12.3)t + 1/2 (-2.10)t²
-1.05t²+12.3t-32.52 = 0
This is the quadratic equation. By solving it, time t= 4.04s,7.66s. The desired time is t = 4.04 s, and the tail of the blue car leaves the intersection.
C) the minimum distance is=?
x = x₀ + v₀t + 1/2 (at²)
= 0 + 0 + 1/2 (5.60 (4.04)²)
= 45.8 m
The minimum distance of the blue car is 45.8m
D) speed of the car=?
the velocity equation
v = v₀ + at
= 0 + (5.60 ×4.04)
= 22.6 m/s
The velocity of the car is 22.6 m/s.
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The inverse of the mass is referred to as acceleration. The acceleration will be slower the more mass there is.
How does acceleration work?Acceleration is the rate of change in an object's velocity over time in mechanics. One of the vector quantities is speed. The direction of the net force exerted on an object is what determines its acceleration. The change in velocity rate is referred to as acceleration. Usually, but not always, acceleration implies a change in velocity.
A circular object moving at a constant velocity is still accelerating because its velocity is changing in the opposite direction. In physics, acceleration is the rate of change in an object's velocity over time. According to Newton's second law, the sum of all forces acting on an object determines its acceleration. Meters per second (ms²) is the SI unit for acceleration.
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the distance between an object and its real image is 40 cm, if the magnification is 3, calculate the object and image distance if the focal length of the lens is 15 cm
The object distance of the lens is 10 cm and the image distance of the lens is 30 cm.
What is the image and object distance?The object and image distance formed by the lens is calculated by applying the following lens formula.
v + u = 40 ------- (1)
v/u = 3 ------------ (2)
v = 3u
Substitute v into equation (1);
3u + u = 40
4u = 40
u = 40/4
u = 10 cm
The image distance = 3u
= 3 x 10 cm
= 30 cm
Thus, the object distance is 10 cm and the image distance is 30 cm.
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