cual es la motaña más alta del mundo​

\(a(1) = 240 \\ a(2) = a(1) + d = 240 + 24 = 264 \\ a(3) = a(2) + d = 264 + 24 = 288 \\ a(4) = a(3) + d = 288 + 24 = 312 \\ a(5) = a(4) + d = 312 + 24 = 336 \\ a(6) = a(5) + d = 336 + 24 = 360\)

Answer:

C. 31 units

Step-by-step explanation:

Circumference of a circle is the distance around the circle and is given by C = pi•d

Your circle with a point and center given has a radius of 5 because from (2,1) to (7,1) is 5 units. Radius 5 means the diameter is 10.

C = pi•10

= 3.14•10

= 31.4 using 3.14 as an approximation for pi.

Circumference is approximately 31 units.

a) The probability that we both lose when you bet on red and I bet on black is 0.463.
b) The probability that at least one of us wins is 0.537.
c) The probability that at least one of us loses is 1.


a) When you bet on red, the probability of losing is 18/38 because the roulette wheel has 18 red spaces out of 38 total spaces. Similarly, the probability of losing when I bet on black is 18/38. Since these are independent events, the probability of both losing is (18/38) × (18/38) = 0.221 or 0.22 (rounded to two decimal places).

Therefore, the probability that we both lose is 0.22 or 22%.

b) The probability that at least one of us wins is equal to the complement of the probability that we both lose. The complement rule states that if P(A) is the probability of event A, then P(not A) = 1 – P(A). In this case, P(both lose) = 0.22, so P(at least one wins) = 1 – P(both lose) = 1 – 0.22 = 0.78 or 78%.

c) The probability that at least one of us loses is 1 because it is impossible for both of us to win at the same time. In other words, the events "you lose" and "I lose" are complementary and exhaustive, which means that their probabilities add up to 1.

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In the table, the relation (x,y) is not a function if the missing value of x is of x = 3.

A relation represents a function if each value of the input is mapped to only one value of the output, that is, one input cannot be mapped to multiple outputs.

For a point in the standard format (x,y), we have that:

In the table, we have that when x = 3, y = 10, hence, if when y = 20 x also equals 3, then the relation would not represent a function.

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Answer:

B. 11

Step-by-step explanation:

3  7  11  14  16  16  18  21  22  23  27

Given:

The inequality is:

\(4x+1<5x\leq 3(x+2)\)

To find:

The integer solutions to the given inequality.

Solution:

We have,

\(4x+1<5x\leq 3(x+2)\)

This compound inequality can be written as two separate inequalities \(4x+1<5x\) and \(5x\leq 3(x+2)\).

Now,

\(1<5x-4x\)

\(1<x\)                 ...(i)

And,

\(5x\leq 3(x+2)\)

\(5x\leq 3(x)+3(2)\)

\(5x-3x\leq 6\)

\(2x\leq 6\)

Divide both sides by 2.

\(x\leq \dfrac{6}{2}\)

\(x\leq 3\)               ...(ii)

From (i) and (ii), we get

\(1<x\leq 3\)

Here, 1 is excluded and 3 is included in the solution set. There two integer values 2 and 3 in \(1<x\leq 3\).

Therefore, the integer solution for the given inequality are 2 and 3.

Answer:

Substitute x = 4 into the equation.

f(4) = 2(4)² - 6

= 2(16) - 6

= 32 - 6

= 26

Answer:

x (distance) = 10, max height = .75

Step-by-step explanation:

y=-.03x(x-10)

The distance are the x intercepts: 0 and 10, where 0 is time started and 10 is time ended.

Expand the equation:

y=-.03x^2 +.3x

To find max height you find the vertex

x = -b/2a

x = -.3/-.06 = 5

Plug the x into the equation

y=.-03(5)^2 +.3(5)

y=.75

The values of r and s is -1 and -4 respectively.

Given that:-

coordinates of j are (-8,-5)

coordinates of l are (6,-11)

coordinates of k are (r-4,2s)

Also, k is the mid-point of jl.

We have to find the values of r and s.

We know that, for  (x,y) and (z,w), the mid-point is ((x+z)/2, (y+w)/2).

Here,

(x,y) = (-8.-5)

(z,w) = (6,-11)

(r-4,2s) = ((x+z)/2,(y+w)/2)

Hence,

(r-4,2s) = ((-8+6)/2,(-5-11)/2)

(r-4,2s) = (-1,-8)

Comparing the coordinates, we get:-

r - 4 = -1

r = -1+4 =3

2s = -8

s =-8/2 = -4

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The provided options (x = -2, x = -1, x = 3, x = 2) are not asymptotes for the given function.

An asymptote of a function is a line that the graph of the function approaches but never touches. In the given function Y = (4x - 2)/(x^2 - 3x). The vertical asymptotes occur when the denominator of the fraction equals zero, so we set x^2 - 3x = 0 and solve for x:
x(x - 3) = 0
x = 0 or x = 3
The vertical asymptotes occur at x = 0 and x = 3.
The horizontal asymptote occurs when the degree of the numerator is less than or equal to the degree of the denominator. In this case, the degree of the numerator is 1 and the degree of the denominator is 2, so the horizontal asymptote occurs at y = 0.
   4x - 2
x^2 - 3x | 4x - 2

- 4x + 12
-14x - 2
To determine the asymptote of the given function Y = (2/cos(y-20)), we need to identify the values of y for which the denominator (cos(y-20)) becomes zero. For cosine, this occurs when its argument is an odd multiple of π/2.

The equation y - 20 = (2n+1)π/2, where n is an integer. Adding 20 to both sides gives y = (2n+1)π/2 + 20. Since there is no specific value of x involved in this function, we can conclude that there are no vertical asymptotes in the form x = some constant value.

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The domain and the range of the function are (-∝, ∝) and (0, ∝), respectively

From the question, we have the following parameters that can be used in our computation:

The graph

The above graph is an exponential function

The rule of an function is that

The domain is the set of all real values

In this case, the domain is (-∝, ∝)

For the range, we have

Range = (0, ∝)

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If you have samples of two groups and are performing the pooled-variance t-test, the degrees of freedom can be calculated using the formula df = n1 + n2 - 2. I explained the importance of having larger sample sizes to increase the degrees of freedom and improve the accuracy of the t-test results.

If you have samples of two groups and are performing the pooled-variance t-test, the degrees of freedom can be calculated using the formula df = n1 + n2 - 2, where n1 and n2 are the sample sizes of the two groups. This formula takes into account that two degrees of freedom are lost due to the estimation of the population variances from the sample variances.
For example, if you have a sample of 30 from group A and a sample of 40 from group B, the degrees of freedom for the t-test would be 30 + 40 - 2 = 68. This means that you have 68 degrees of freedom to estimate the t-value and perform the hypothesis test.
It is important to note that having a higher number of degrees of freedom increases the accuracy and reliability of the t-test results, as there is more information available from the samples to estimate the population parameters. Therefore, it is generally recommended to have larger sample sizes to increase the degrees of freedom and improve the statistical power of the t-test.
In summary, if you have samples of two groups and are performing the pooled-variance t-test, the degrees of freedom can be calculated using the formula df = n1 + n2 - 2. I explained the importance of having larger sample sizes to increase the degrees of freedom and improve the accuracy of the t-test results.

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Answer:

multiplycation by 10,000

Step-by-step explanation:

70,000/7=10,000

Answer:

Given function f(x) = x + 2

The co-ordinates of ( -2 , 0) , (1 ,3 ),( 2,4)

Step-by-step explanation:

Given function

               \(f(x) = \frac{x^{2}- 3 x -10 }{x -5}\)

let       \(y = f(x) = \frac{x^{2}- 3 x -10 }{x -5}\)

    The Factor \(x^{2} - 3 x - 10\)

                     x ² - 5 x + 2 x - 10

                  x ( x -5) + 2 (x-5)

         \(f(x) = \frac{x^{2}- 3 x -10 }{x -5} = \frac{(x-5)(x+2)}{x-5} = x +2\)

              y = x +2

The co-ordinates of ( -2 , 0) , (1 ,3 ),( 2,4)

Answer:

C is the answer ,got it right on EDG 2020

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

Answer:

on the math and reading test, 240 (reading) and 250 (math) are typical top scores.

Step-by-step explanation:

To find the correct equations for the missing boxes, we need more information about the relationships between the different activities in Jake's Gems. However, based on the given context, we can make some assumptions and suggest potential equations:

Mining and Cutting activities produce diamonds, rubies, and other gems. Let's assume that the production of each gem type is represented by a variable: D (diamonds), R (rubies), and G (other gems).

Maintenance supports the Mining and Cutting activities. We can assume that the maintenance effort required for each activity is represented by the variable M (maintenance).Since the question mentions five missing boxes, we can suggest additional equations to represent relationships between these variables, such as:

Mining + Cutting = D + R + G (the sum of all gem types produced equals the total production from Mining and Cutting activities).

Maintenance = M (maintenance effort required).

The relationships between these variables might include equations like D = f(M), R = g(M), G = h(M), where f, g, and h represent some functions or formulas that relate gem production to maintenance effort.

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We need to evaluate the double integral ∫∫R 3y dA, where R is the region in the first quadrant bounded by the x-axis, the line 3x + y = 6, and the line y = 3x.The value of the double integral ∫∫R 3y dA is 9/2

To evaluate the double integral, we first need to find the limits of integration for x and y. From the given equations, we can find the intersection points of the lines.

Setting y = 3x in the equation 3x + y = 6, we get 3x + 3x = 6, which simplifies to 6x = 6. Solving for x, we find x = 1.

Next, substituting x = 1 into y = 3x, we get y = 3(1) = 3.

Therefore, the limits of integration for x are 0 to 1, and the limits of integration for y are 0 to 3.

The double integral can now be written as:

∫∫R 3y dA = ∫[0 to 1] ∫[0 to 3] 3y dy dx

Integrating with respect to y first, we get:

∫∫R 3y dA = ∫[0 to 1] [(3/2)y^2] [0 to 3] dx

            = ∫[0 to 1] (9/2) dx

            = (9/2) [x] [0 to 1]

            = (9/2) (1 - 0)

            = 9/2

Therefore, the value of the double integral ∫∫R 3y dA is 9/2.

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Answer:

  27 square units

Step-by-step explanation:

To use Heron's formula, you need to know that "s" represents half the perimeter.

  s = (11 +6 +9)/2 = 13

Then the area is given by the formula as ...

  A = √(13(13 -11)(13 -6)(13 -9)) = √(13·2·7·4) = √728

  A ≈ 26.98 ≈ 27 . . . square units

Answer:

27 units

Step-by-step explanation:

correct answer on edge

EXPLANATION

The division is equal to:

First we need to write the problem in long division format:

8.0 /_ 9.92

Divide 9 by 8 to get 1:

1

8.0 /_ 9.92

Multiply the quotient digit (1) by the divisor 8:

1

8.0 /_ 9.92

8

Subtract 8 from 9:

1

8.0 /_ 9.92

8

1

Add a decimal point to the solution

Bring down the next number of the dividend

1.

8.0 /_ 9.92

8

19

The radian measure of Angle E should be labeled π/3 or 60 degrees, and F should be labeled 2(π/3) or 120 degrees.

A full circle in radian measures is 2π and half π

If we divide π into 3 equal parts it should be π/3 radian.

Angle EAP would be π/3 radians because E is one-third of the way from A to P.

In degrees, π/3 radians is equal to (180/π) × π/3 = 60°

Angle FAP would be 2×(π/3) radians givn that F is 2/3 of the way from A to P.

In degrees, 2×(π/3) radians is equal to (180/π) × 2(π/3) = 120°.

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To determine if a function has a vertical asymptote, you need to consider its behavior as the input approaches certain values.

A vertical asymptote occurs when the function approaches positive or negative infinity as the input approaches a specific value. Here's how you can determine if a function has a vertical asymptote:

Check for restrictions in the domain: Look for values of the input variable where the function is undefined or has a division by zero. These can indicate potential vertical asymptotes.

Evaluate the limit as the input approaches the suspected values: Calculate the limit of the function as the input approaches the suspected values from both sides (approaching from the left and right). If the limit approaches positive or negative infinity, a vertical asymptote exists at that value.

For example, if a rational function has a denominator that becomes zero at a certain value, such as x = 2, evaluate the limits of the function as x approaches 2 from the left and right. If the limits are positive or negative infinity, then there is a vertical asymptote at x = 2.

In summary, to determine if a function has a vertical asymptote, check for restrictions in the domain and evaluate the limits as the input approaches suspected values. If the limits approach positive or negative infinity, there is a vertical asymptote at that value.

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Answer:

972π m³

Step-by-step explanation:

given

in a sphere

radius (r) = 9 m

Volume (V ) = ?

so we know

The formula for the volume of a sphere is V = 4/3 πr³.

now

V = 4/ 3 * π * 9³

V = 972π m³

hope it helps :)

Answer:

972pi

Step-by-step explanation:

4/3(pi)r^3

4/3(pi)(9)^3

972(pi)

hope this helps!

Answer:

3z < -4.8

* be sure to use the less than or equal to sign

Step-by-step explanation:

The inequality for the A number z times 3 is at most -4.8 is 3x < -4.8

Mathematical expressions with inequalities are those in which the two sides are not equal. Contrary to equations, we compare two values in inequality. Less than (or less than or equal to), greater than (or greater than or equal to), or not equal to signs are used in place of the equal sign.

Given:

A number z times 3 is at most -4.8

Now, the mathematical expression is

3z < -4.8

and, z< -1.6

Hence, the inequality is 3x < -4.8

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Step-by-step explanation:

A function is an equation that has only one answer for y for every x. A function assigns exactly one output to each input of a specified type. It is common to name a function either f(x) or g(x) instead of y. f(2) means that we should find the value of our function when x equals 2.

The domain restrictions of the expression q²−7q−8/q²+3q−4 are q ≠ -4 and q ≠ 1. (option c)

The denominator of the expression is q²+3q−4. To determine the values that would make the denominator equal to zero, we can set it equal to zero and solve for q:

q² + 3q - 4 = 0

Now, we can factorize the quadratic equation:

(q + 4)(q - 1) = 0

To find the values of q, we set each factor equal to zero and solve for q:

q + 4 = 0 or q - 1 = 0

Solving these equations, we get:

q = -4 or q = 1

So, the values of q that would make the denominator equal to zero are q = -4 and q = 1. These are the values we need to exclude from the domain of the expression to avoid division by zero.

Therefore, the correct answer is option c) q ≠ 1 and q ≠ -4.

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Complete Question:

What are the domain restrictions of q²−7q−8/q²+3q−4?

a) q≠1 and q≠−8

b) q≠−1 and q≠4

c) q≠1 and q≠−4

d) q≠−1 and q≠8

Answer:

y= 6x-8

Step-by-step explanation:

you pick two y values and subtract them. then take two x values and subtract them. divide those two awnsers with y on top. the -8 is the y intercept because when x is 0, the y is -8.

Answer:

Step-by-step explanation:

recall slope m is:

slope = m

m = (y2-y1) / (x2-x1)

point P1 (0,-8)  in the form (x1,y1)

point P2(1,-2)  in the form (x2,y2)

m = { -2-(-8) } / { 1-0 }

m = { -2+8 } / 1

m = 6 /1

m = 6

then plug in any point, I'll use P1

y - y1 = m(x -x1) (point-slope formula)

y - (-8) = 6*(x-0)

y+8 = 6x

y= 6x -8  (slope-intercept formula)  :)

Answer:

95 degrees

Step-by-step explanation:

in a triangle angles add up to 180 degrees.

a + b + c = 180

30 + 45 + c = 180

85 + c = 180

c= 180 - 85

c= 95 degrees

Answer:

I think it is D.

Step-by-step explanation: