Date: 12-3-21
4.
The momentum of a 5-kilogram object moving at
6 meters per second is

Answers

Answer 1

Answer

30 kg . m/sec

Explanation:

mark me as brainliest!

Answer 2
30 kg•m/s

p = mv
p = 5kg • 6m/s
p = 30 kg•m/s

Related Questions

A 1.50 × 10^-6-meter-long segment of an electromagnetic wave is represented below. Which type of electromagnetic wave does the segment in the diagram represent?

1) ultraviolet
2) x-rays
3) visible light
4) infrared

A 1.50 10^-6-meter-long segment of an electromagnetic wave is represented below. Which type of electromagnetic

Answers

The electromagnetic radiation with a wavelength of 1.5 x 10⁻⁶ m corresponds to infrared radiation.

option D.

What is an electromagnetic wave?

Electromagnetic waves are a form of radiation that travel though the universe.

So electromagnetic radiation consists of waves of the electromagnetic field, which propagate through space and carry momentum and electromagnetic radiant energy.

Examples of electromagnetic radiations include;

ultravioletx-raysvisible lightinfrared

The electromagnetic radiation with a wavelength of 1.5 x 10⁻⁶ m corresponds to infrared radiation.

Thus, option D is the correct answer.

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what do rx, ry, , and |r| represent in terms of the force of the current, and what do they represent in terms of the forces moving the boat?

Answers

Rx and Ry represent the x- and y-components of the force of the current, respectively.

The magnitude of the force of the current, or the strength of the current, is represented by |r|. In terms of the forces moving the boat, the x- and y-components of the force of the current represent the horizontal and vertical forces that the current exerts on the boat.

|r| represents the magnitude of this force, which can be thought of as the intensity of the current. The stronger the current, the greater the force it will exert on the boat and the greater impact it will have on its movement.

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A coffee maker has a power rating of 1.4 kW. How much energy will this coffee maker transfer every second?

Answers

Answer:

The power rating of the coffee maker is 1.4 kW, which means that it uses 1.4 kilowatts of power when it is in operation. To find out how much energy it will transfer every second, we can use the formula:

Energy transferred = Power × Time

Since we want to know the energy transferred every second, we can set the time to 1 second. Therefore:

Energy transferred per second = Power × 1 second

Energy transferred per second = 1.4 kW × 1 second

We can simplify this by converting the unit of power from kilowatts to watts:

Energy transferred per second = 1,400 watts × 1 second

Energy transferred per second = 1,400 joules

Therefore, the coffee maker will transfer 1,400 joules of energy every second.

assume all pulleys are massless and frictionless, and the systems are in equilibrium. find the tension t. the acceleration due to gravity is 9.8 m/s 2

Answers

The tension in each pulley would be is 74.96 N.

What is pulley system?

A pulley system is a type of mechanical device that uses pulleys to lift or move heavy objects. It consists of two or more pulleys, a belt or cable, and a motor or hand-operated force. The pulleys are connected with a belt or cable that passes over them, creating a loop.

The tension in a pulley system can be found using the equation:
T = m * g * (sin θ1 + sin θ2)
where m is the mass of the hanging object, g is the acceleration due to gravity (9.8 m/s2 in this case), and θ1 and θ2 are the angles of the pulleys.
So to find the tension, we need to know the mass of the object and the angles of the pulleys. If the system is in equilibrium, then the tension in the two pulleys must be equal, so we can set the tension to be equal to the same value in each pulley.
Once we know the mass of the object and the angles of the pulleys, we can solve for the tension in each pulley using the equation above.
For example, if the mass of the object is 10 kg, and the angles of the pulleys are 30° and 45°, then the tension in each pulley would be:
T = 10 kg * 9.8 m/s2 * (sin 30° + sin 45°)
T = 74.96 N

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In 2D motion, which of the following variables is not split into x and y components?

Answers

Any variable that is scalar cannot be split into x and y components. Travelled distance, speed, distance and mass are some examples of scalars.

In two-dimensional motion, any variable that is scalar cannot be split into x and y components, some of which we are going to list:

Travelled distance.Speed. (Magnitude of the velocity, a vector)Distance. (Magnitude of the displacement or position, a vector)Mass.

Any variable that is scalar cannot be split into x and y components. Travelled distance, speed, distance and mass are some examples of scalars.

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Calcula la fuerza que tiene que realizar el brazo sobre el punto medio del mango de la pala para levantar la tierra situada en la cuchara que pesa 8kg

Answers

Explanation:

1- El primer paso para calcular la fuerza del brazo en el punto medio de la excavadora para levantar la tierra, es averiguar dónde está el fulcro, que en este caso está en las manos.

2- El segundo paso es calcular el brazo de potencia, al que llamaremos Bp, y el brazo de resistencia, que estará representado por Br.

Si Bp es igual a la distancia de la potencia al fulcro, Bp = 60cm

y si Br es igual a la distancia desde la resistencia al fulcro, entonces

Br = 40 + 60 = 100cm

3- Ahora aplicamos la fórmula de la ley de la palanca. Nosotros

piden que se aplique la fuerza en manos de

en el medio, es decir, la potencia P. La fórmula sería:

Y en el tercer paso, aplicaremos la fórmula de la ley de la palanca, que es:

P = R x Br / Bp

P = 8 x 100/60

P = 13,33 Kgf

Entonces la respuesta final es:

P = 13,33 Kgf

Refer to the following series circuit: + R R, = 17.2 V R, = 52 1:11 V = 15V R, 1 I Calculate the total power developed in the circuit. P= Choose... watts Choose... 15 120 98 Submit Answer Skip C Notes​

Refer to the following series circuit: + R R, = 17.2 V R, = 52 1:11 V = 15V R, 1 I Calculate the total

Answers

Series connection

R=R1+R2=10+5=15\(\Omega\)V=15V

Now

\(\\ \rm\Rrightarrow P=\dfrac{V^2}{R}\)

\(\\ \rm\Rrightarrow P=\dfrac{15^2}{15}\)

\(\\ \rm\Rrightarrow P=15W\)

Which of the following facts demonstrates how women's symbolic representation has translated into substantive representation?

Answers

Substantive representation refers to the ways in which elected representatives advocate for and enact policies that benefit a particular group. One example of how women's symbolic representation has translated into substantive representation is the increase in policies aimed at promoting gender equality.

For instance, the passage of the Violence Against Women Act, which provides funding for programs to prevent domestic violence and support victims, was spearheaded by a coalition of female lawmakers. Additionally, the number of women in elected office has increased over time, leading to more policies and initiatives that address issues affecting women, such as paid family leave, reproductive rights, and affordable childcare. The mere presence of women in positions of power also sends a message that their perspectives and experiences are valued, which can encourage other women to pursue leadership roles. However, there is still much work to be done to ensure that women's symbolic representation is fully realized in substantive representation.

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7. Our state of mind affects how we observe our surroundings. What
mental state is the best for observing?
I
a) happy
c) nervous
b) relaxed d) excited

Answers

It has to be C Nervous

How much electrical energy is used by a 75 W laptop that is operating for 12
minutes?
O A. 27,000 J
B. 108,000 J
C. 900 J
O D. 54,000 J

Answers

Answer:

54,000 J

Explanation:

Given,

Power ( P ) = 75 W

Time ( t ) = 12 minutes

To find : Electrical energy ( E ) = ?

t = 12 minutes

= 12 x 60

t = 720 seconds

Formula : -

E = Pt

E = 75 x 720

E = 54,000 J

Therefore,

54,000 J is the electrical energy is used by a 75 W laptop that is operating for 12 minutes.

NEPTUNE

•Number of days to orbit the sun:
•Distance around the sun:​

Answers

Answer:

1. 165 years

2. 2.781 billion mi

Explanation:

if the volume of a cube is 100cm3. what's the measurement of one of its length​

Answers

Answer:

100 cm

Explanation:

Answer:

4.64

Explanation:

The cube root of 100 is 4.64.

A highway curves to the left with radius of curvature of 44 m and is banked at 16 ◦ so that cars can take this curve at higher speeds. Consider a car of mass 1563 kg whose tires have a static friction coefficient 0.72 against the pavement. How fast can the car take this curve without skidding to the outside of the curve?

Answers

The car can take this curve without skidding to the outside of the curve with a speed of 23.47 m/s.

Given that,

Radius of the track r = 44 m

Inclination θ = 16°

Mass of car m = 1563 kg

Coefficient of kinetic friction μ = 0.72

By analysing the free body diagram, we get,

N cos θ - fr - m g = 0  ----(1)

where, N is normal reaction

fr is friction

N cos θ + fr cos θ = mv²/r  ----(2)

fr = μ N ----(3)

From (1), (2) and (3) we get maximum velocity without skidding as,

v = √(g r ) × √( tanθ +μ )/(1 - μ tanθ) = √(9.8× 44 ) ×√( tan 16°+ 0.72)/(1 - 0.72 tan 16°) = 20.77 × √1.007/0.79 = 20.77 × 1.13 = 23.47 m/s

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What type of matter is 10 grams of calcium?

plz help me begging

Answers

Answer:

A pure element.

Explanation:

Calcium, being whatever weight, is a pure element.

Hope this helped! Have a good day.

Answer:

the answer is

Explanation: Calcium is a chemical element with symbol Ca and atomic number 20. Classified as an alkaline earth metal, Calcium is a solid at room temperature.

A disc of moment of inertia 45kgm^2 is rotating with an angular velocity of 12rad/s.what will be its rotational kinetic energy?​

Answers

Answer:

3240 J

Explanation:

here moment of inertia (I)= 45kgm²

angular velocity (ω) = 12 rad/s

now KE = 1/2(Iω²)=1/2(45×12²)= 3240J

A cylindrical metal wire W1, of length l and cross-sectional area A, has a resistance of 16Ω. A second cylindrical wire W2 having length l 2 and cross-sectional area 2A, is made from the same metal. Determine (i) the resistance of W2,

Answers

The resistance of wire W2 can be determined by using the formula for resistance, which depends on the resistivity, length, and cross-sectional area of the wire.

Since wire W1 and W2 are made from the same metal, their resistivity is the same. Considering the given length and cross-sectional area, the resistance of W2 is 8Ω.

The resistance of a wire can be calculated using the formula:

R = (ρ * l) / A

where R is the resistance, ρ is the resistivity of the material, l is the length of the wire, and A is the cross-sectional area of the wire.

Since wire W1 and W2 are made from the same metal, they have the same resistivity, denoted as ρ. Therefore, the resistivity is constant for both wires.

For wire W2, the length is given as l2 and the cross-sectional area is 2A. Substituting these values into the resistance formula:

R2 = (ρ * l2) / (2A) = (1/2) * [(ρ * l2) / A]

Since we know the resistance of W1 is 16Ω, we can substitute this value into the resistance formula for W1:

16Ω = (ρ * l) / A

Simplifying, we have:

ρ * l = 16Ω * A

Substituting this into the expression for R2:

R2 = (1/2) * [(ρ * l2) / A] = (1/2) * [(16Ω * A) / A] = 8Ω

Therefore, the resistance of wire W2 is 8Ω.

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A train traveling at 108 kmph crosses another train traveling in the same direction at 72 kmph in 60 seconds. What is the combined length (in km) of both the trains?

Answers

The requried combined length of the trains are 1.8 kilometers.

What is velocity?

Velocity is defined as the rate of change in the position of an object with respect to time.

Here,

Let's first convert the speeds from km/h to m/s to make our calculations easier,

The first train travels at 108 km/h = 30 m/s.

The second train travels at 72 km/h = 20 m/s.

Now, we can calculate the relative speed of the trains:

The relative speed between the two trains is 30 m/s - 20 m/s = 10 m/s.

We know that the first train overtakes the second train in 60 seconds. During this time, the first train will cover a distance equal to the combined length of both trains.

Let's denote the length of the first train as L₁ and the length of the second train as L₂. Then, we can write,

Distance covered by the first train in 60 seconds = L₁

Distance covered by the second train in 60 seconds = L₂ + L₁ (because the second train is L₂ behind the first train when it is overtaken)

The speed of the first train is 30 m/s, so its distance covered in 60 seconds is:

Distance covered by the first train in 60 seconds = 30 m/s x 60 s = 1800 m

Similarly, the speed of the second train is 20 m/s, so its distance covered in 60 seconds is,

Distance covered by the second train in 60 seconds = 20 m/s x 60 s = 1200 m

L₁ = 1800 m - 1200 m = 600 m

L₁ + L₂ = 1800 m

So the combined length of both trains is:,
L₁ + L₂ = 1800 m

L₁ + L₂ = 1.8 km

Therefore, the combined length of both trains is 1.8 km.

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In a ______ solar system, the planets orbit around the sun.

A. Geocentric
B. Monolithic
C. Heliocentric
D. Pericentric

Answers

Geocentric
Have a good day!
Geocentric is the answer have a very nice day

What is the energy of the He electron with n = 4? (k = 2.18 x 10-18 J) • Your answer should have three significant figures.

Answers

The energy of the He electron with n = 4 is -1.36 × 10^-18 J or we can say that it's 1.36 × 10^-18 J (since energy is always positive but can have a negative sign if it is being released).

The energy of He electron with n = 4 (k = 2.18 x 10-18 J) can be found using the formula below:\($$E_{n} = \frac{-Z^{2} k^{2} \cdot m_{e}}{2 \cdot h^{2} \cdot n^{2}}$$\) where \($E_{n}$\) is the energy, k is Coulomb's constant, \($m_{e}$\) is the mass of an electron, h is Planck's constant, and Z is the atomic number of the element. Using the given value of k = 2.18 × 10⁻¹⁸ J, and atomic number of He which is Z = 2, m_{e} = 9.11 x 10^-31 kg, h = 6.626 × 10⁻³⁴ J s, and n = 4, we can find the energy of the He electron. Substituting these values in the formula above, we have;\($$E_{4} = \frac{-2^{2} \cdot (2.18 × 10^{-18} J)^{2} \cdot 9.11 × 10^{-31} kg}{2 \cdot (6.626 × 10^{-34} J s)^{2} \cdot 4^{2}}$$\). Solving for the above expression;\($$E_{4} = -1.36 *10^{-18} J$$\).

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Jared is experimenting with a force that is attractive only and the weakest of the fundamental forces. He is experimenting with which force?

electromagnetic
strong
gravitational
weak

Answers

Answer is gravitational !

Answer:

C. gravitational

Explanation:

Took  the test!

Michael has a constant elasticity of substitution (CES) utility function, U(q 1

,q 2

)=(q 1
rho

+q 2
rho

) rho
1

, where rho

=0 and rho≤11 14
Given that Michael's rho<1, what are his optimal values of q 1

and q 2

in terms of his income and the prices of the two goods? Answer 1. Substitute the income constraint into Michael's utility function to eliminate one control variable. Michael's constrained utility maximization problem is max q 1

,q 2


U(q 1

,q 2

)=(q 1
rho

+q 2
rho

) rho
1

s.t. Y=p 1

q 1

+p 2

q 2


We can rewrite Michael's budget constraint as q 2

=(Y−p 1

q 1

)/p 2

. Substituting this expression into his utility function, we can express Michael's utility maximization problem as: max q 1


U(q 1

, p 2

Y−p 1

q 1


)=(q 1
rho

+[ p 2

Y−p 1

q 1


] rho
) 1/rho
. By making this substitution, we have converted a constrained maximization problem with two control variables into an unconstrained problem with one control variable, q 1

2. Use the standard, unconstrained maximization approach to determine the optimal value for q 1

. To obtain the first-order condition, we use the chain rule and set the derivative of the utility function with respect to q 1

equal to zero: rho
1

(q 1
rho

+[ p 2

Y−p 1

q 1


] rho
) rho
1−rho

(rhoq 1
rho−1

+rho[ p 2

Y−p 1

q 1


] rho−1
[−− p 2

p 1


])=0 Using algebra, we can solve this equation for Michael's optimal q 1

as a function of his income and the prices: 15 (3.18) q 1

= p 1
1−σ

+p 2
1−σ

Yp 1
−σ


where σ=1/[1−rho]. By repeating this analysis, substituting for q 1

instead of for q 2

, we derive a similar expression for his optimal q 2

: (3.19) q 2

= p 1
1−σ

+p 2
1−σ

Yp 2
−σ


Thus, the utility-maximizing q 1

and q 2

are functions of his income and the prices.

Answers

The optimal values of \(q_1\) and \(q_2\) are determined by these equations, which are functions of Michael's income and the prices of the goods.

The given problem describes Michael's utility maximization problem with a constant elasticity of substitution (CES) utility function. The objective is to find the optimal values of \(q_1\) and \(q_2\) in terms of Michael's income (Y) and the prices of the two goods (\(p_1\) and \(p_2\)).

1. Substitute the income constraint into Michael's utility function:

\(U(q_1, q_2) = (q_1^\rho + q_2^\rho)^(1/\rho)\)

  s.t. \(Y = p_1q_1 + p_2q_2\)

  We can rewrite Michael's budget constraint as \(q_2 = (Y - p_1q_1)/p_2\). Substituting this expression into his utility function, we have:

 \(U(q_1, p_2, Y) = (q_1^\rho + [p_2(Y - p_1q_1)/p_2]^\rho)^{(1/\rho)\)

  By making this substitution, we have converted the constrained maximization problem with two control variables (\(q_1\) and \(q_2\)) into an unconstrained problem with one control variable \((q_1)\).

2. Use the standard unconstrained maximization approach to determine the optimal value for \(q_1\). To obtain the first-order condition, we differentiate the utility function with respect to \(q_1\) and set it equal to zero:

\(\delta U / \delta q_1 = \rho(q_1^{(\rho-1)} + \rho[p_2(Y - p_1q_1)/p_2]^{(\rho-1)}(-p_1/p_2)) = 0\)

Simplifying and solving for \(q_1\):

\(\rho q_1^{(\rho-1)} - \rho(p_1/p_2)[p_2(Y - p_1q_1)/p_2]^{(\rho-1)} = 0\)

\(\rho q_1^{(\rho-1)} - \rho(p_1/p_2)[Y - p_1q_1]^{(\rho-1)} = 0\)

\(\rho q_1^{(\rho-1)} = \rho(p_1/p_2)[Y - p_1q_1]^{(\rho-1)}\)

\(q_1^{(\rho-1)} = (p_1/p_2)[Y - p_1q_1]^{(\rho-1)\)

\(q_1^{(\rho-1)} = (p_1/p_2)^{(1-\rho)}[Y - p_1q_1]^{(\rho-1)}\)

\(q_1^{(\rho-1)} = (p_1/p_2)^{(1-\rho)}(Y - p_1q_1)^{(\rho-1)}\)

\(q_1^{(\rho-1)} = (p_1/p_2)^{(1-\rho)}(Y^{(\rho-1)} - (\rho-1)p_1q_1(Y - p_1q_1)^{(\rho-2)})\)

  This equation represents Michael's optimal \(q_1\) as a function of his income (Y) and the prices (\(p_1\) and \(p_2\)).

3. Similarly, we can derive a similar expression for his optimal \(q_2\):

\(q_2^{(\rho-1)} = (p_2/p_1)^(1-\rho)(Y^{(\rho-1)} - (\rho-1)p_2q_2(Y - p_1q_2)^{(\rho-2)})\)

  This equation represents Michael's optimal \(q_2\) as a function of his income (Y) and the prices (\(p_1\) and \(p_2\)).

Therefore, these equations, which depend on Michael's income and the prices of the commodities, determine the ideal values of \(q_1\) and \(q_2\).

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A spring with spring constant 58N/cm is stretched 4cm. How much force is it applying

Answers

Answer:

232 N

Explanation:

By Hooke's law, the force applied to a spring is proportional to the stretch of the spring, so

F = kx

Where F is the force, k is the spring constant and x is how much it is stretched.

So, replacing k by 58N/cm and x by 4 cm, we get

F = (58 N/cm)(4 cm)

F = 232 N

Therefore, the force applied is 232 N

A 200 -W point source emits monochromatic light of wavelength 500 nm equally in all directions. At a light detector situated 1.5 m away from the source:

Answers

A point source of 200-W emits monochromatic light of wavelength 500 nm equally in all directions. At a light detector situated 1.5 m away from the source, what is the total energy detected per second? The energy detected per second= 5654 J/s≈ 5.7 kJ/s.

Solution:

The total energy detected per second can be found using the equation,

Energy per second = Energy per unit time × Surface area of the sphere on which the energy is distributed.

The energy emitted by a 200 W point source of light is given by

Energy emitted per second = 200 J/s.

Using the formula,

Energy per second = Energy per unit time × Surface area of the sphere on which the energy is distributed.

The surface area of the sphere is given by

Surface area of sphere= 4πr2

Where r is the radius of the sphere i.e., distance between the light source and the detector.

It is given as 1.5 m.

Surface area of sphere = 4π(1.5)2= 28.27 m2

Therefore,

The energy detected per second = Energy emitted per second × Surface area of sphere

The energy detected per second= 200 J/s × 28.27 m2

The energy detected per second= 5654 J/s≈ 5.7 kJ/s.

Answer: Total energy detected per second is 5.7 kJ/s.

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a radio station has a frequency of 88.7 megahertz. what is the wavelength of the radio waves the station emits (you will have to convert units)

Answers

The wavelength of the radio waves emitted by the radio station is approximately 3.38 meters. This means that the radio waves have a relatively long wavelength and can travel long distances, which is why radio waves are commonly used for broadcasting signals.

To determine the wavelength of the radio waves emitted by the radio station, we can use the formula:

wavelength = speed of light / frequency

The speed of light is approximately 299,792,458 meters per second. However, the frequency of the radio station is given in megahertz, which is a unit of frequency equal to one million hertz. To convert megahertz to hertz, we need to multiply by one million.

Therefore, the frequency of the radio station in hertz is:

88.7 MHz x 1,000,000 = 88,700,000 Hz

Now, we can substitute the values into the formula:

wavelength = 299,792,458 m/s / 88,700,000 Hz = 3.38 meters

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Part A: Explain why x = 5 makes 4x − 1 ≤ 19 true but not 4x − 1 < 19. (5 points) Part B: What value from the set {6, 7, 8, 9, 10} makes the equation 5x + 2 = 47 true? Show your work. (5 points)

Answers

Answer:

A: ≤ means less than OR equal to. < only means less than

B: 9

Explanation:

A: Because it would equal 19, and 19 is EQUAL than 19. 4(5) - 1 would equal 19, which is equal to 19, and not less than. ≤ means less than or equal to. < means less than. So its not true.

B: 47 - 2, 45. Then 5 x 9 equals 45. So 5 x 9 equals 45, then add 2 would equal 47.

Hope this helps <3

The inequality 4x − 1 ≤ 19 has less than or equal sign but the inequality 4x − 1 < 19 has only less than sign. The equation 5x + 2 = 47 is satisfied, for x = 9.

What is inequality?

Inequality is simply a type of equation that does not have an equal sign in it. Inequality is defined as a statement about the relative size as well as is used to compare two statements.

Part A: Explain why x = 5 makes 4x − 1 ≤ 19 true but not 4x − 1 < 19.

The inequality 4x − 1 ≤ 19 is satisfied by 5 because the inequality has less than or equal sign but the inequality 4x − 1 < 19 has only less than sign so for x = 5, the value is equal to 19 which is not true.

Part B: The value from the set {6, 7, 8, 9, 10} makes the equation 5x + 2 = 47 true.

By simplifying the equation, then we have

5x + 2 = 47

     5x = 45

       x = 9

The equation is satisfied, for x = 9.

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Two trains sound identical horns of frequency 410 Hz. One train is stationary. The other is moving away from an observer, who heats a beat frequency of 35 Hz. How fast is the moving train going?

Answers

The speed of the moving train is approximately 33.5 m/s.

The beat frequency is given by the difference in frequency between the two horns, which is equal to the Doppler shift in frequency due to the motion of the moving train. Using the formula for the Doppler effect, we can solve for the speed of the train:

\(f_b = f_s\dfrac{(v + v_o)}{(v + v_s)}\)

where \(f_b\) is the beat frequency, \(f_s\) is the horn frequency, v is the speed of sound, \(v_o\) is the observer's speed, and \(v_s\) is the speed of the source.

We know that \(f_s\) = 410 Hz and \(f_b\) = 35 Hz. The speed of sound in air at standard temperature and pressure is approximately 343 m/s. Since the observer is stationary, \(v_o\) = 0.

Solving for \(v_s\), we get:

\(v_s = \dfrac{(f_s + f_b)}{f_s - 1} \times v\)

\(v_s\) = ((410 Hz + 35 Hz) / 410 Hz - 1) * 343 m/s

\(v_s\) = 33.5 m/s

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What is the weight, on Earth, of a book with a mass of 1. 5 kg? 1. 5 N 6. 5 N 11. 3 N 14. 7 N.

Answers

Answer:

The weight, on Earth, of a book with a mass of 1.5kg is 14.7N.

Explanation:

Hi there!

Weight of an object = mass (kg) × acceleration due to gravity (N/kg)

Plug in the given values using the g constant g = 9.8 N/kg:

W = 1.5 × 9.8 = 14.7 N

A 0.149-kg baseball, initially moving at 15 m/s is brought to rest in 0.050 seconds by a baseball glove on a catcher’s hand. The magnitude of the average force exerted on the ball by the glove is

Answers

The magnitude of the average force exerted on the ball by the glove is

What is the magnitude of the average force exerted on the ball by the glove?

The magnitude of the average force exerted on the ball by the glove is calculated as follows:

Force = Mass × acceleration

Data given:

Mass, m = 0.149 kg

Velocity, v = 15 m/s

Time, t = 0.050 seconds

However,

Acceleration = Δv / t

where;

Δv is the change in velocityt is the time taken

Hence;

Force = Mass ×  Δv / t

Force = 0.149 × (15 - 0) / 0.050

Force = 44.7 N

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3. a stone thrown up is caught by the thrower after 6 seconds how high did it go and where was it 4 seconds after start (g = 9.8m/s2)??​

Answers

Answer:

here, v = 0, a = - 9.8 m/sec^2, t = 3 sec

v = u + at

0 = u + (-9.8) * 3

0 = u - 29.4

u = 29.4 m/sec

here, u = 29.4m/s, t = 3sec, a= -9.8m/s^2

s = ut + 1/2 a t^2

s = 29.4 * 3 + 1/2 * - 9.8 * 3^2

s = 88.2 - 4.9 * 9

s = 88.2 - 44.1

s = 44.1 m

here, u = 0, a = 9.8m/s^2, t = 1 sec, s = ?

position after 4sec :

s = ut+ 1/2 at^2

s = 0 * 1 + 1/2 * 9.8 * 1^2

s = 4.9m

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A sheet of steel 5.0 mm thick has nitrogen atmospheres on both sides at 900∘C and is permitted to achieve a steady-state diffusion condition. The diffusion coefficient for nitrogen in steel at this temperature is 46.70 m2/s and the diffusion flux is found to be 53.81 kg/m2.s. Also, it is known that the concentration of nitrogen in the steel at the high-pressure surface is 39.52 kg/m3. How far into the sheet (in mm ) from this highpressure side will the concentration be 29.12 kg/m3 ? Assume a linear concentration profile.

Answers

The concentration of nitrogen will be 29.12 kg/m³.

The thickness of the steel sheet, l = 5.0 mm

The diffusion coefficient of nitrogen in steel, D = 46.70 m²/s

The diffusion flux, J = 53.81 kg/m²s

The initial concentration of nitrogen in steel, C1 = 39.52 kg/m³

The final concentration of nitrogen in steel, C2 = 29.12 kg/m³

The required distance, x = ?

The concentration profile is linear. The formula for diffusion flux is J = -D * (dC/dx), where dC/dx is the concentration gradient in the x direction. Here, the negative sign represents the diffusion of nitrogen in the direction of decreasing concentration.

Since the concentration profile is linear, we can use the following equation: dC/dx = (C2 - C1) / x

We can now substitute the given values in the diffusion flux formula:

J = -D * (dC/dx) = -D * (C2 - C1) / x

Solving the above formula for x, we get

x = -D * l / (J * (C2 - C1)) = -46.70 * 5.0 / (53.81 * (29.12 - 39.52))

≈ 1.53 mm

Therefore, the concentration of nitrogen will be 29.12 kg/m³ at a distance of approximately 1.53 mm from the high-pressure surface.

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